The work done by the applied force is 21.23 J.
The work done by the gravity is 29.4 J.
The magnitude of the normal force between the block and the wall is 9.8 N.
What is the work done on the block?The work done on the block include the following;
by the applied force, W = Fd cosθby the force of gravity, W = Fn cosθ x dby force of friction , W = Ff cosθ x dwhere;
F is the applied forceFn is the normal forceFf is the force of frictiond is the distance in which the block is moveθ is the angle of inclination of the blockThe applied force on the block is calculated as follows;
Fsinθ - μmgsin(90) = ma
at a constant velocity, the acceleration of the block = 0
Fsinθ - μmg = 0
Fsinθ = μmgsinθ
F = μmg/sinθ
F = (0.4 x 1 x 9.8)/sin(29)
F = 8.09 N
The work done by the applied force is calculated as;
W = Fcosθ x d
W = (8.09 x cos29) x 3
W = 21.23 J
The work done by the gravity is calculated as follows;
W = Fn cosθ x d
where;
θ is the angle between the normal force and the block = 0W = mg cosθ x d
W = 1 x 9.8 x cos(0) x 3
W = 29.4 J
The magnitude of the normal force between the block and the wall is calculated as follows;
Fn = mg cosθ
where;
θ is the angle between the normal force and the block = 0Fn = 1 x 9.8 x cos(0)
Fn = 9.8 N
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a hydraulic press in a garage is attached to a platform that is used to lift cars. the press includes a small piston that is attached to a fluid-filled pipe, which opens into a larger chamber under the platform (see image below). if the platform has a radius of 3 m and the piston has a radius of 3 cm, how much force (in n) must be applied to the piston in order to raise a 1200 kg car?
Answer:
.12 kg
Explanation:
Area under car = pi 3^2 = 9 pi m^2
Area of piston = pi (.03)^2 = .0009 pi m^2
As a ratio:
.0009 / 9 = x / 1200
x = 1200 ( .0009/9) = .12 kg
An athlete is running a circular track of radius 50m after he completed 2 revolution, what will be.
A, displacement B, distance
Answer:
displacement=√50^2+50^2=70.71m
Explanation:
Distance traveled by the athlete=length of the arc
=d(theta)r
Here the athlete runs 3\4of a circle whose radius is 50 m
here, d(theta)=3(pi)/2rad
hence distance=3(pi)/2 x 50
=235.61 m
displacement=the chord between the initial point and the final point. it subtends an angle of 90degrees at the centre of the circle.
it forms a right angled triangle.
hence by Pythagoras theorem,
displacement=√50^2+50^2=70.71m
if at a given time the magnitude of acceleration of a mass is 9 m/s2 when its position is 4 meters from equilibrium, what is the period of oscillation?
The period of oscillation, if at a given time the magnitude of acceleration of a mass is 9 m/s² when its position is 4 meters from equilibrium is 4.188 s
Acceleration can be expressed as,
a ( t ) = - ω² x ( t )
ω² = a ( t ) / - x ( t )
ω² = 9 / - ( - 4 )
ω² = 9 / 4
ω = 3 / 2
ω = 1.5 rad / s
T = 2 π / ω
T = Time period
ω = Angular velocity
T = 2 * 3.14 / 1.5
T = 4.188 s
Therefore, the period of oscillation is 4.188 s
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a motorcycle is traveling up one side of a hill and down the other side. the crest of the hill is a circular arc with a radius of 45.0 m. determine the maximum speed that the cycle c
The maximum speed of the cycle is 21 m/s.
When the motorcyclist takes the curve on the hill, a net frictional force acts on it towards the center and acts as the centripetal force.
The radius of the hill is = 45 m
Also , the weight of the motorcycle acts downwards and the normal reaction acts upwards. As the motorcycle is on the curve so , a component of the weight acts towards the center.
weight is given by , W = mg
So the net F(friction) = mg - N = [tex]\frac{mv^{2} }{r}[/tex]
For loosing contact, N=0
[tex]v^{2}[/tex] = rg
v = [tex]\sqrt{rg}[/tex]
v = [tex]\sqrt{(45)(9.80)}[/tex]
v = 21 m/s
So the maximum speed of the motorcycle can be 21 m/s.
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Why should diameter of double walled tube must be big for a ice box
The diameter should of the double-walled tube be big for an ice box is increase the thermal temperature.
Double wall pipes are an important safety tool when storing liquids such as those used in the chemical wastewater food and beverage industries. The majority of jacketed piping applications are for chemical wastewater-contaminated groundwater and chemical process safety.
Tube wall thickness in excess of that required for internal stresses and known loads not only provides a margin of safety against unexpected loads but also increases survival time when corrosion or fatigue mechanisms are in action. increase. Single-layer tubing is lightweight, flexible, and can be installed quickly with less personnel and equipment. The double wall is a smooth inner double wall with a corrugated outer tube.
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if one ball's initial speed was 1.50 m/s , and the other's was 2.20 m/s in the opposite direction, what will be their velocities after the collision?
If one ball's initial speed was 1.50 m/s , and the other's was 2.20 m/s in the opposite direction, There velocities after collision will be - 2.2 m/s and - 2.9 m/s
given :
masses of both the balls are same
using conservation of momentum
m1u1 + m2u2 = m1v1 + m2v2
m1 ( 1.50 ) + m2 * (-2.20) = m1v1 + m2v2
m (1.50) + m ( -2.20) = mv1 + mv2
-0.7 = v1 + v2 equation 1
since
u1 + v1 = u2 + v2
1.50 + v1 = (-2.20) + v2
v1 - v2 = - 3.7 equation 2
solving equation 1 and 2 we get
v1 = - 2.2 m/s
v2 = - 2.9 m/s
There velocities after collision will be - 2.2 m/s and - 2.9 m/s
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Your friend conducted an experiment in which they drop four objects from 5 meters above the
ground, and record their position every 0.1 seconds as they fall.
One object was an eight pound medicine ball, one was a golf ball, one was a frisbee, and one was a
feather.
b. Describe how would this data change, If this student had an access to the vacuum chamer and
performed this test in a vacuum?
c. The next experiment was conducted in the normal conditions (in the air). Predict whether a
feather or a golf ball would land first
a ) The slowest and fastest object are object 2 and object 1 respectively
b ) In a vacuum chamber all objects will fall at the same time
c ) In normal conditions, a golf ball would land first.
a ) From the data taken from the table,
Object 1 lands after 1.1 s
Object 2 lands after 1.8 s
Object 3 lands after 1.3 s
Object 4 lands after 1.1 s
Eventhough object 1 and 4 land at same time, at 1 s mark object 4 has more height than object 1. So object 1 would land first
b ) If conducted in a vacuum chamber, there will be no air resistance,. So all the objects will fall at the same time.
c ) In normal conditions, there will be air resistance. So air resistance will be larger in the object with larger surface area. Feather has a larger surface area than a golf ball. So feather will fall slower than the golf ball.
Therefore,
a ) The slowest and fastest object are object 2 and object 1 respectively
b ) In a vacuum chamber all objects will fall at the same time
c ) In normal conditions, a golf ball would land first.
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write the differential equation of the system by the 2nd law of newton mechanics or theorem of momentum moment g
The instantaneous change in momentum brought on by something like a hammer strike is equal to the applied impulse, however the second law of newton did not state that F=ma (i.e., d2xdt2=1mF) in the Principial.
What is the second law of Newton in plain English?The modifications that a force can cause to a body's motion are quantitatively described by Newton's second law. According to this, the force acting on a body has an equal and opposite magnitude and rate of change in its momentum over time.
The third law of Newton is what?The formal formulation of Newton's third law is: There is an opposite and equal to every action. According to the statement, each interaction involves two forces acting on the interacting objects. The first object's force is equal to the size of the second object's force.
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both the gravitational and electric force between objects are considered ____ .
A) pushing forces
B) contact forces
C) field forces
D) applied forces
Answer:
C) field forces
Explanation:
A) pushing forces (wrong option)
---> gravitational force: an invisible force that pulls objects towards the earth
---> electric force: a contact force that pushes or pulls objects without making any contact, making it a technically non-pushing force
B) contact forces (wrong option)
---> gravitational force: since it is an invisible force (as stated in the explanation for option A), it is a non-contact force
---> electric force: as stated in the explanation for option A, it is also a non-contact force
C) field forces (correct option)
---> gravitational force: is a type of force field since it is a non-contact force
---> electric force: is also a type of force field that cause the attraction or repulsion of forces without actual contact between the charges
D) applied forces (wrong option)
---> not applicable for both forces as supported by all the above information
Explanation:
A huge variety of physical phenomena during interaction is determined by only four types of interactions: electromagnetic, weak, strong and gravitational.
Answer:
C) Field forces
During which type of radioactive decay is the mass of the emitted particle the smallest?.
Answer:
Explanation:
The mass of the emitted particle is the smallest in beta decay.
Beta decay is the flow of electrons, alpha decay is the flow of helium nuclei
During alpha decay, the mass of the emitted particle is the smallest compared to other types of radioactive decay.
In alpha decay, an unstable atomic nucleus emits an alpha particle, which consists of two protons and two neutrons bound together, effectively forming a helium-4 nucleus. This means that the alpha particle has a mass of approximately 4 atomic mass units (AMU).
In contrast, beta decay involves the emission of beta particles, which can be either beta-minus particles (electrons) or beta-plus particles (positrons). These particles have much smaller masses compared to alpha particles. For example, a beta-minus particle (electron) has a mass of approximately 0.00055 AMU, and a beta-plus particle (positron) has the same mass but opposite charge.
Gamma decay, on the other hand, does not involve the emission of particles with mass but instead releases high-energy photons (gamma rays) to stabilize the nucleus.
Hence, the alpha particle emitted during alpha decay has the smallest mass among the particles emitted during radioactive decay processes.
During alpha decay, the mass of the emitted particle is the smallest compared to other types of radioactive decay.
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a block sits at a ramp with a 35 degree angle to the ground. friction has a magnitude of 41 n as it slides down the ramp with a mass of 13.2 kg. what acceleration does the block have on the ramp?
The Net acceleration of the block is 5.62104907 m/s².
Given -A block is positioned at the bottom of a ramp at a 35-degree angle. With a mass of 13.2 kg, it slides down the ramp with a coefficient of friction of 41 n.
Principle-The resistance that surfaces in contact provide to motion when they pass one another is referred to as friction. The two surfaces in contact are causing friction because of their irregularities. Therefore, these surface irregularities become entangled when one object moves over the other, creating friction. The friction will increase in significance as the roughness increases, creating more irregularities.
Mathematical concept-[tex]F=ma-----[1]\\\\F=mgsinx----[2]\\\\\\ma=mgsinx[/tex]
cancelling m both sides and finally the equation reduces to [tex]a=gsinx[/tex]
Calculations-g=9.8m/s² , x= 35
a=9.8 sin 35
a=9.8 x 0.57357
=5.62104907 m/s²
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which of the pathways below are in the correct order for the flow of electrons from glucose to oxygen in aerobic respiration? select one: a. glycolysis, citric acid cycle (tca), ets g
Glycolysis, a pathways for the flow of electrons from glucose to oxygen in aerobic respiration.
The process of obtaining chemical energy for the body in the form of ATP is called respiration. In the process, chemical bond energy stored in various molecules is reduced or oxidized. The most commonly used substrate in this pathway is glucose.
Glucose is first converted to two molecules of pyruvate by a pathway known as glycolysis. The pyruvate produced is converted to acetyl-CoA and enters the Krebs cycle. In the Krebs cycle, acetyl-CoA is oxidized to form CO2, ATP, NADH and FADH2. NADH and FADH2 are used as reducing forces within the electron transport chain or ETC, oxidizing various enzymes and coenzymes within the ETC to synthesize ATP.
Therefore, the correct sequence of processes involved in aerobic cellular respiration is glycolysis, the Krebs cycle, and the electron transport chain.
So the correct answer is "glycolysis, Krebs cycle, electron transport system".
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12) pi2: why does the oscilloscope register a non-zero voltage for the small coil? there are no wires between the two circuits, so how can energy can transfer from one coil to the other?
The oscilloscope is also known as scope CRO or DSO the latter is the modern one.
An oscilloscope is used to observe the continuously varying voltage signal. It helps us to measure the varying voltage signal apart from voltage it is also used to measure other signals like sound, vibration also observation but this signal is first converted into voltage and then displayed on an oscilloscope. However this drawback has been covered in the DRO which directly Shows you the result without any conversion.
The oscilloscope shows the voltage with respect to the time which means it captures the voltage signal for a particular time and then shows up the result it means for large where the voltage signal is frequently changing within a second oscilloscope is unable to read and that's why show as a non zero voltage. The energy transfer between the coil without any electrical connection is done by the principle of mutual induction.
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A spherical balloon is increasing in volume at 3 24 cm s π. How fast is the radius of the balloon increasing when the surface area of the balloon is 2 30π cm ?.
The rate of increase in balloon radius is 0.12 cm/s.
Solution:
r^3 = 24×3/4
r^3= 18
r= √18
r= 2.62cm
∴ the rate of change in radius here is 2.62cm/s since π is constant.
The surface area of the sphere= 4πr^2
the surface area of the balloon is 30πcm^2
therefore 30π= 4πr^2
divide both sides by 4π
r^2= 30/4
r^2= 7.5
r=√7.5
r= 2.74cm
The rate of change in radius here is 2.74cm/s
As altitude increases atmospheric pressure decreases. The pressure on the outside of the balloon then drops. In order to balance the external pressure, the gas inside expands and lowers the pressure. Therefore, the size of the balloon increases. Gas particles exert pressure on the walls of the gas-filled container. When you inflate a balloon the air inside expands and exerts pressure on the walls of the balloon. This will increase the size of the balloon.
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A vibrating structural beam in a spacecraft can cause problems ifthe frequency of vibration is fairly high. Even if the amplitude ofvibration is only a fraction of a millimeter, theacceleration of the beam can be several times greater than theacceleration due to gravity. As an example, find the maximumacceleration of a beam that vibrates with an amplitude of 0.25 mmat the rate of 110 vibrations per second. Give your answer as amultiple of g.
The maximum acceleration of the beam is 12.18 g.
What is the maximum acceleration of the beam?Centripetal acceleration is defined as the property of the motion of an object, traversing a circular path. The maximum centripetal acceleration is the rate at which the maximum angular velocity changes with time.
The centripetal acceleration is obtained by multiplying the radial acceleration by amplitude of the motion.
The maximum acceleration of the beam is calculated as follows;
a = ω²r
where;
ω is the angular speed of the vibrating objectr is the radius of the pathmaximum acceleration = ω²A
where;
A is the amplitude of the motionThe given parameters;
angular speed of the vibrating beam = 110 rev/s = (110 x 2π rad)/s = 691.1 rad/sthe amplitude of the vibration, A = 0.25 mma(max) = (691.1²) x (0.25 x 10⁻³)
a(max) = 119.4 m/s²
In multiple of acceleration due to gravity (g) = 119.4 / 9.8 = 12.18 g
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A grapefruit has a weight on Earth of 4.9 newtons. What is the grapefruit’s mass?
Answer:
0.5 kg
Explanation:
W = mg
4.9 = m(9.8)
4.9 = 9.8m
4.9/9.8 = m
m = 0.5 kg
An object of mass 30 kg is in free fall in a vacuum where there is no air resistance. Determine the acceleration of the object.
a 0.650-kg object is swung in a circular path and in a vertical plane on a 0.500-m-length string. if the angular speed at the bottom is 8.00 rad/s, what is the tension in the string when the object is at the bottom of the circle?
The tension in the string = 83.2 N
What is tension?Tension is defined as the pulling force transmitted axially by using a string, a rope, chain, or similar object, or by each end of a rod, truss member, or similar 3-D object; tension might also be expressed as the action-reaction pair of forces acting at each end of said elements. Tension is the opposite of compression. All objects in contact with each other exert forces on each other. The best example of pulling force is seen when pulling on a rope. When a pulling force is applied to a rope, it creates considerable tension.
Given,
Mass of object (m) = 0.650kg
Radius of object (r) = 0.5 m
Angular speed (ω) = 8.00 rad/s
T = mω²/r
T = 0.65 × 8²/0.5
T = 83.2 N
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Physics: Please Help
Answer:
6a.
7c.
8c.
9a.
10b.
11d.
Explanation:
Let me know if I made any mistakes or if you want clarification :)
Determine the acceleration that results when a 10-N net force is applied to a 5.1 kg object.
Answer:
1.96 m^2
Explanation:
F = m * a
10 = 5.1 * a
a = 1.96 m/s^2
photons of ulltraviolet radiation with wavelengths that are shorter than those of visible light will have what kind of energy in relation to visible light?
Ultraviolet radiation has shorter waves than blue or violet light, and thus oscillates more rapidly and carries more energy per photon than visible light does.
Infrared and ultraviolet radiation are the neighbors of visible light in the electromagnetic spectrum.Red light contains shorter waves than infrared radiation, which causes it to oscillate at a lower frequency and carry less energy.
One way energy travels is as visible light.Light waves are an example of electromagnetic (EM) radiation because they are produced by the vibration of electric and magnetic fields.
Although visible light is only one of many different types of electromagnetic radiation and only makes up a very small portion of the entire electromagnetic spectrum, it holds unique relevance for us because we can see it with our eyes.
The wavelength of light is between 400 and 700 nanometers (4,000 to 7,000 angstroms).Our eyes interpret the various light wavelengths as the hues of the rainbow.
Around 700 nm length, the waves of red light are comparatively long.The wavelength of blue and purple light is only 400 nm.
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an object of mass 2.9 kg is attached to a spring that has a spring constant of 69 n/m. suppose the spring is stretched a maximum distance of 0.136 m before the object starts to move. what is mu s, the coefficient of static friction?
The static friction value is the value from zero to the minimum force required to initiate motion. The formula for calculating static friction is:
Static Friction = Normal Force x Static Friction Coefficient.
The maximum or limit of friction between two surfaces is FMAX=μR F MAX = μR. where μ is the coefficient of friction and R is the normal reaction between two surfaces. The coefficient of friction is a measure of surface roughness, with rougher surfaces having higher values. Therefore, as the car makes a circular motion, the necessary centripetal force is provided by the frictional force. Therefore, the coefficient of static friction between a car tire and the road surface is 0.53.
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A force of 15 newtons is applied to an object with a mass of 5kilograms what will be the objects final velocity after 10 seconds
Answer:
See below
Explanation:
First, find acceleration from
F = m * a
then vf = a * t for the final velocity ...... Plug and chug
Suppose two equal mass cars traveling with equal speeds in opposite directions collide head on and stick together. What fraction of the energy is dissipated?.
A collision which is inelastic is one in which the internal energy changes. The entire kinetic energy is lost. The parameters listed are.
When two cars collide, one car's mass equals the second car's mass, or m.
Inelastic collision is the collision type. Each car's speed before the incident was v and -v. The final velocity following the contact is zero, making the collision a perfect example of an inelastic collision.
The negative symbol represents energy that is given out or provided. The energy lost is equal to mv2 (The total initial kinetic energy). As a result, all of the kinetic energy is lost.
When particles, collections of particles, or solid entities travel in the same direction and get close enough to one other, they collide and exert mutual force.
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If an object is moving in the negative direction, but its velocity is getting more positive, does that mean it has a positive acceleration? Does that mean it is slowing down?
Yes. it means the object is slowing down.
What is acceleration?Acceleration is a vector quantity that is defined as the rate at which an object changes its velocity. An object is accelerating if it is changing its velocity. Acceleration has to do with changing how fast an object is moving. Since acceleration is a vector quantity, it has a direction associated with it.
The direction of the acceleration vector depends on two things:
whether the object is speeding up or slowing downwhether the object is moving in the + or - directionIf an object is slowing down, then its acceleration is in the opposite direction of its motion.
In conclusion, If an object is not changing its velocity, then the object is not accelerating.
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) if the elevator's acceleration had a magnitude of g in the upward direction, what would the normal force fn2 be in newtons?
The reaction force applied by the floor of the elevator on the cardboard box is 93.1N.
The mass of the cardboard box is 4.75 kg.
The elevator is moving in the upward direction with an acceleration of g.
According to Newton's law of motion, each and every action has an equal and opposite reaction.
Now, the reaction force that is going to be applied on the box by the floor of the accelerating elevator will be equal to that of the weight of the box felt by the floor of the elevator.
The net acceleration of the box is (g+g),
Net acceleration = 2g.
Now, the weight W of the boc,
W =4.75(2g)
W = 4.75 x 2 x 9.8
W = 93.1 N.
The reaction force Fₙ₂ on the box is 93.1 N.
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Complete question-A cardboard box rest on the floor of the elevator. The box has a mass m = 4.75 kg and the elevator has an upward acceleration a, if the elevator's acceleration had a magnitude of g in the upward direction, what would the normal force fn2 be in newtons?
a 0.25 m radius grinding wheel is rotating with a constant angular speed of 2.0 rad/s. what is the linear displacement of the wheel after 3.0 s?
The linear displacement of the wheel will be 1.5m.
Linear displacement is the measure of straight path covered by the object .
Rotating angular speed of the wheel = 2.0 rad/s
Radius of the wheel = 0.25 m
According to the angular speed and linear speed relationship, we can say that linear speed is the product of angular speed and the the radius of the object
Mathematically, v = r * ωV = linear velocity
r = radius of the wheel
ω = angular velocity
V = 0.25 * 2
V = 0.5 m/s
Also, speed is equal to distance upon time.
V = d/t
Time at wheel the the wheel's linear distance is to be found = 3 s
therefore d = V * t
d = 0.5 * 3
d = 1.5 m
The linear displacement of the wheel after 3.0 s is 1.5 m.
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8. a sports car accelerates from 0 to 27 m/s, in 6.3 seconds. the car exerts a force of 3106 n. what is the mass of the car?
A sports car accelerates from 0 to 27 m/s. The mass of the car is 732.5kg.
initial speed of a car = 0m/s
final speed of the car = 27m/s
time taken = 6.3 seconds
then acceleration is calculated as:
acceleration = velocity / time
acceleration = (27 - 0)/6.3 = 27/6.3 = 4.24m/s²
The force exerted y a car = 3106 N
as we know
F = ma
where
F = force exerted
m = mass of the body
a = acceleration of a car
F = ma
3106N = m x 4.24m/s²
m = 3106 /4.24
m = 732.5kg
A sports car accelerates from 0 to 27 m/s. The mass of the car is 732.5kg.
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a 1.0-mm-diameter wire made of copper and iron segments carries a 4.00 a current. how much charge accumulates at the boundary between the segments?
The charge accumulated at the boundary between the segments that carries 4 A current along a 1 mm diameter wire is 2.95 * [tex]10^{-18}[/tex] C
η = q / A
η = εo I / A [ 1 / σ1 - 1 / σ2 ]
η = Charge density
q = Charge
A = Area
σ = Conductivity
I = Current
εo = Vacuum permittivity
I = 4 A
εo = 8.85 * [tex]10^{12}[/tex] F / m
σ1 = 1 * [tex]10^{7}[/tex] / Ω m
σ2 = 6 * [tex]10^{7}[/tex] / Ω m
Equating both the formulae of charge density,
q / A = εo I / A [ 1 / σ1 - 1 / σ2 ]
q = 8.85 * [tex]10^{12}[/tex] * 4 ( 1 / [tex]10^{7}[/tex] - 1 / 6 * [tex]10^{7}[/tex] )
q = 8.85 * [tex]10^{12}[/tex] * 4 * [tex]10^{-7}[/tex] ( 1 - 1 / 6 )
q = 2.95 * [tex]10^{-18}[/tex] C
Therefore, the charge accumulated at the boundary between the segments is 2.95 * [tex]10^{-18}[/tex] C
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Think about the ecosystem that you live in. Write a response below describing it in complete sentences. Use each of these terms correctly in your description
An ecosystem is made of different species of animals, plants and the resources for their living. If we observe our surroundings, we can see many more types of living things with their own peculiarities.
What is ecosystem?Ecosystems in earth contains the region where living things and major resources exists. There are different ecosystems namely, forests, aquatic systems, deserts, gralsslands, marshy lands etc.
If we observe around there are various kinds of plants and animals in water bodies as well as in land. They can their characteristic features and adapting powers. They can be of same species or different, social living or isolated living.
We can classify water bodies as one ecosystem and land area and grass lands as other ecosystems.
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