0.4p – 5 = 0.08p + 3
Solve pls

Answer:

26) Let the first number be x.

Sum of three consecutive even numbers:

[tex]x+(x+2)+(x+4)=-84[/tex]

[tex]x+x+2+x+4=-84\\[/tex]

[tex]3x+6=-84[/tex]

Subtract 6 from both sides:

[tex]3x+6-6=-84-6[/tex]

[tex]3x=-90[/tex]

Divide both sides by 3:

[tex]\frac{3x}{3}=\frac{-90}{3}[/tex]

[tex]x=-30[/tex]

To find the other two numbers, add 2 and 4 respectively:

[tex](-30+2=-28)(-30+4=-26)[/tex]

27) Let the first number be x.

Sum of three consecutive odd integers:

[tex]x+(x+2)+(x+4)=141[/tex]

[tex]3x+6=141[/tex]

Subtract 6 from both sides:

[tex]3x+6-6=141-6\\3x=135[/tex]

Divide both sides by 3:

[tex]\frac{3x}{3}=\frac{135}{3}\\x=45[/tex]

To find the other two numbers, add 2 and 4 respectively:

[tex](45+2=47)(45+4=49)[/tex]

28) Let the first number be x.

Sum of four consecutive integers:

[tex]x+(x+1)+(x+2)+(x+3)=54[/tex]

[tex]4x+6=54[/tex]

Subtract 6 from both sides:

[tex]4x+6-6=54-6\\4x=48[/tex]

Divide both sides by 4:

[tex]\frac{4x}{4}=\frac{48}{4}\\x=12[/tex]

To find the other three numbers, add 1, 2 and 3 respectively:

[tex](12+1=13)(12+2=14)(12+3=15)[/tex]

29) Let the first number be x.

Sum of four consecutive integers:

[tex]x+(x+1)+(x+2)+(x+3)=-142[/tex]

[tex]4x+6=-142\\[/tex]

Subtract 6 from both sides:

[tex]4x+6-6=-142-6[/tex]

[tex]4x=-148[/tex]

Divide both sides by 4:

[tex]\frac{4x}{4}=\frac{-148}{4}\\x=-37[/tex]

To find the other three numbers, add 1, 2 and 3 respectively:

[tex](-37+1=-36)(-37+2=-35)(-37+3=-34)[/tex]

Answer:

23

Step-by-step explanation:

Answer: First step would be doing the () first. The third step would be 4 times 0. I think so, forgive me if I’m wrong.

Step-by-step explanation:

Answer: Four hundred and thirty two point nine - eight.

Step-by-step explanation:

Hey there! I'm happy to help!

With the numbers before the decimal, you just say it normally. After the decimal, you just name the digits.

So, you would call this number four hundred thirty-two point nine eight.

Have a wonderful day! :D

16 avocados costs = $8, 20 avocados costs = $10 and 9 avocados costs = $4.5

The amount of money that a company spends on the creation or production of goods or services.

Given that, Eight avocados cost $4.

Therefore, each of them costs = 4/8 = 1/2

So, 16 avocados = 16*1/2 =$8

20 avocados = 20*1/2 =$10

9 avocados = 9*1/2 =$4.5

Hence, 16 avocados costs = $8, 20 avocados costs = $10 and 9 avocados costs = $4.5

For more references on Cost, click;

https://brainly.com/question/15135554

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Answer:

D. 3

Step-by-step explanation:

We can see from the graph that there are 3 lines. All 3 lines look linear, and if a line is linear, x and y are proportional. Therefore, if all 3 lines are linear, then we have 3 proportional relationships.

Answer:

[tex]a=2K-b[/tex]

Step-by-step explanation:

[tex]K=\frac{a+b}{2}[/tex]

Switch sides:

[tex]\frac{a+b}{2}=K[/tex]

Multiply both sides by 2:

[tex]\frac{2\left(a+b\right)}{2}=2K[/tex]

[tex]a+b=2K[/tex]

Subtract b from both sides:

[tex]a+b-b=2K-b[/tex]

[tex]a=2K-b[/tex]

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{234}}}}}[/tex]

Step-by-step explanation:

Total seats in a theatre = 450

Finding the total occupied seats

[tex] \dashrightarrow{ \sf{48\% \: of \: 450}}[/tex]

[tex] \dashrightarrow{ \sf{ \frac{48}{100} \times 450}} [/tex]

[tex] \dashrightarrow{ \sf{216}}[/tex]

Finding the seats that are not occupied

[tex] \longrightarrow{ \sf{450 - 216 = 234}}[/tex]

Hope I helped!

Best regards! :D

Answer:

  k = 5

Step-by-step explanation:

The value of k is added to each y-coordinate, so represents the amount of up-shift. If the shift up is 5 units, then k=5.

Answer:

k = 5

Step-by-step explanation:

I got it right on the quiz

This should be your equation - (y/-6) + 5 = 9

Answer:  

y/-6 = 4 <y = -24 <

Answer:

[tex]y=-24\\[/tex]

Step-by-step explanation:

Write the equation

[tex]\frac{y}{-6} +5=9[/tex]

Subtract 5 from both sides

[tex]\frac{y}{-6} =4[/tex]

Multiply both sides by -6

[tex]y=-24\\[/tex]

Hope this helps! : )

Answer:

[tex]\displaystyle \frac{\cos x}{1 + \sin x} = \tan\left(\frac{\pi}{4} - \frac{x}{2}\right)[/tex].

Overview of the steps:

Step-by-step explanation:

Double-angle identity of sines and cosines:

Pythagorean identity for the sine and cosine of the same angle:

[tex]1 = \cos^2\alpha + \sin^2\alpha[/tex].

Angle sum and difference identity of sines and cosines:

[tex]\sin(\alpha - \beta) = \sin\alpha\, \cos\beta - \cos\alpha \, \sin\beta[/tex].

[tex]\cos(\alpha - \beta) = \cos\alpha\, \cos\beta + \sin\alpha \, \sin\beta[/tex].

Consider [tex]x[/tex] as the sum of two angles of size [tex](x/2)[/tex]. Start by applying the double-angle identity to the left-hand side.

[tex]\begin{aligned} \text{L.H.S.}&= \frac{\cos(x)}{1 + \sin(x)} \\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{1 + 2\, \sin(x / 2)\, \cos(x / 2)}\end{aligned}[/tex].

Apply the Pythagorean identity to rewrite the "1" in the denominator as [tex]\left(\cos^2(x / 2) + \sin^2(x / 2)\right)[/tex].

[tex]\begin{aligned} \text{L.H.S.}&= \frac{\cos(x)}{1 + \sin(x)} \\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{1 + 2\, \sin(x / 2)\, \cos(x / 2)}\\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{\sin^2(x/2) + 2\,\sin(x/2)\, \cos(x/2) + \cos^2 (x/2)}\end{aligned}[/tex].

Note that the denominator is now a perfect square. On the other hand, the numerator is in the form [tex](x^2 - y^2)[/tex], which is equal to [tex](x + y)\, (x - y)[/tex]. Rewrite and simplify this expression:

[tex]\begin{aligned} \text{L.H.S.}&= \frac{\cos(x)}{1 + \sin(x)} \\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{1 + 2\, \sin(x / 2)\, \cos(x / 2)}\\ &= \frac{\cos^2(x / 2) - \sin^2(x / 2)}{\sin^2(x/2) + 2\,\sin(x/2)\, \cos(x/2) + \cos^2 (x/2)} \\[1em] &= \frac{(\cos(x/2) + \sin(x/2))\, (\cos(x/2) - \sin(x/2))}{\left(\sin(x/2) + \cos(x/2)\right)^2} \\ &= \frac{\cos(x/2) - \sin(x/2)}{\sin(x/2) + \cos(x/2)}\end{aligned}[/tex].

The tangent of an angle is equal to the ratio between its sine and its cosine. Apply the angle sum and difference identity of sine and cosine to the right-hand side.

Note, that the sine and cosine of [tex](\pi/4)[/tex] are both equal to [tex]\left(\sqrt{2}/2\right)[/tex].

[tex]\begin{aligned}\text{R.H.S.} &= \tan\left(\frac{\pi}{4} - \frac{x}{2}\right) \\ &= \frac{\sin((\pi/4) - (x/2))}{\cos((\pi/4) - (x/2))}\\ &= \frac{\left(\sqrt{2}/2\right)\, \cos(x/2) - \left(\sqrt{2}/2\right)\, \sin(x/2)}{\left(\sqrt{2}/2\right)\, \cos(x/2) + \left(\sqrt{2}/2\right)\, \sin(x/2)} \\ &= \frac{\cos(x/2) - \sin(x/2)}{\cos(x/2) + \sin(x/2)}\end{aligned}[/tex].

Therefore:

[tex]\displaystyle \text{L.H.S.} = \frac{\cos(x/2) - \sin(x/2)}{\sin(x/2) + \cos(x/2)} =\text{R.H.S.}[/tex].

[tex]\displaystyle \frac{\cos x}{1 + \sin x} = \tan\left(\frac{\pi}{4} - \frac{x}{2}\right)[/tex].

Answer:

40 smoothies

Step-by-step explanation:

if a 1/2 is one then times it by two

Answer:

40 smoothies

Step-by-step explanation:

Answer:

A 524.5 in^3

Step-by-step explanation:

Answer:

see below

Step-by-step explanation:

The question is not clear but I will provide info based on given

Translation of

means sliding by a points to left/right and by b points to up/down

Answer:

A graph of the data that was collected is shown: A line graph with Number of Months on the x axis and Number of Users, in thousands, on the y axis. The x axis has a scale from 0 to 36 with an increment of 4. The y axis has a scale of 0 to 60 with increments of 6. A straight line connecting 0, 0 and approximately 36, 54 is drawn. What can be interpreted from the range of this graph? v .

Answer:

c

Step-by-step explanation:

Answer:

123201

Step-by-step explanation:

This is an arithmetic sequence of common difference 2 and starting value 1,

So we can use the formula for an arithmetic sequence  if we know what is the order of the last term.

Then first use the formula for the nth term to find "n":

[tex]a_n=a_1+(n-1)d[/tex]

where d = 2, first term = 1 and last term = 701

[tex]a_n=a_1+(n-1)d\\701=1+(n-1)*2\\700=(n-1)*2\\350=n-1\\n = 351[/tex]

Knowing this, we can estimate the partial sum:

[tex]S=n\,\frac{a_1+a_n}{2} \\S=351\,\frac{1+701}{2} \\S=351\,*\,351\\S = 123201[/tex]

Answer:

  13.25 ft

Step-by-step explanation:

Let w represent the width of the window. Then w-5 represents the length, and the perimeter is ...

  P = 2(L+W)

  43 = 2((w-5) +w) = 4w -10

  53/4 = w = 13.25 . . . feet

The width of the window is 13.25 ft.

Answer: D

Step-by-step explanation:

i just had this question on a quiz and it said the correct answer was /89

Answer:

[tex]8x+9<4[/tex] and [tex]8x+9>-4[/tex].

Step-by-step explanation:

The given inequality is

[tex]|8x+9|<4[/tex]

We need to rewrite the given inequality as two linear inequalities.

We know that |8x+9|>0 but (8x+9) can be positive or negative.

For [tex]|8x+9|<4[/tex],  the value of (8x+9) must be lies between -4 and 4.

i.e., [tex]-4<8x+9<4[/tex]

If 8x+9 positive, then

[tex]8x+9<4[/tex]      ...(1)

If 8x+9 negative, then

[tex]8x+9>-4[/tex]      ...(2)

Therefore, the two inequalities are [tex]8x+9<4[/tex] and [tex]8x+9>-4[/tex].

Answer:

S = { (4), (5), (1,4), (1,5), (2,4), (2,5), (3,4), (3,5), (1,2,3,4), (1,2,3,5), (2,1,3,4) (2,1,3,5), (3,1,2,4), (3,1,2,5) }

A ={(4), (5)}

Step-by-step explanation:

Given that:

Among the three copies, (1,2,3) are the first printings, and (4,5) are the second printings.

A student who examines these books in random order stops when a second printing has been selected.

Thus, we can compute the sample space associated with these experiments as:

S = { (4), (5), (1,4), (1,5), (2,4), (2,5), (3,4), (3,5), (1,2,3,4), (1,2,3,5), (2,1,3,4) (2,1,3,5), (3,1,2,4), (3,1,2,5) }

Suppose A represents the event that we must examine exactly one book.

Then the outcomes of A are:

A ={(4), (5)}

Answer:

3:4

Step-by-step explanation:

Answer:

g = 15/7

Step-by-step explanation:

3g - 9 + 11g - 21

group like terms

3g + 11g = 21 + 9

14g = 30

g = 30/14

g = 15/7

10 cars and 10 trains in 100 hours

it approximately take him 10 hours to build one car and one train how 6+4=10 how many times can 10 go into 100 10 times hope this helps a little

Answer:

200000+800000+0+2000+100+30+6

Step-by-step explanation:

2,000,000

800,000

0

2,000

100

30

+ 6

_________

Answer:

The following are the solution to the given points:

Step-by-step explanation:

Given value:

[tex]1) \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\2) \sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}[/tex]

Solve point 1 that is [tex]\sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\[/tex]:

when,

[tex]k= 1 \to s_1 = \frac{1}{1+1} - \frac{1}{1+2}\\\\[/tex]

                  [tex]= \frac{1}{2} - \frac{1}{3}\\\\[/tex]

[tex]k= 2 \to s_2 = \frac{1}{2+1} - \frac{1}{2+2}\\\\[/tex]

                  [tex]= \frac{1}{3} - \frac{1}{4}\\\\[/tex]

[tex]k= 3 \to s_3 = \frac{1}{3+1} - \frac{1}{3+2}\\\\[/tex]

                  [tex]= \frac{1}{4} - \frac{1}{5}\\\\[/tex]

[tex]k= n^ \to s_n = \frac{1}{n+1} - \frac{1}{n+2}\\\\[/tex]

Calculate the sum [tex](S=s_1+s_2+s_3+......+s_n)[/tex]

[tex]S=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....\frac{1}{n+1}-\frac{1}{n+2}\\\\[/tex]

   [tex]=\frac{1}{2}-\frac{1}{5}+\frac{1}{n+1}-\frac{1}{n+2}\\\\[/tex]

When [tex]s_n \ \ dt_{n \to 0}[/tex]

[tex]=\frac{1}{2}-\frac{1}{5}+\frac{1}{0+1}-\frac{1}{0+2}\\\\=\frac{1}{2}-\frac{1}{5}+\frac{1}{1}-\frac{1}{2}\\\\= 1 -\frac{1}{5}\\\\= \frac{5-1}{5}\\\\= \frac{4}{5}\\\\[/tex]

[tex]\boxed{\text{In point 1:} \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2} =\frac{4}{5}}[/tex]

In point 2: [tex]\sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}[/tex]

when,

[tex]k= 1 \to s_1 = \frac{1}{(1+6)(1+7)}\\\\[/tex]

                  [tex]= \frac{1}{7 \times 8}\\\\= \frac{1}{56}[/tex]

[tex]k= 2 \to s_1 = \frac{1}{(2+6)(2+7)}\\\\[/tex]

                  [tex]= \frac{1}{8 \times 9}\\\\= \frac{1}{72}[/tex]

[tex]k= 3 \to s_1 = \frac{1}{(3+6)(3+7)}\\\\[/tex]

                  [tex]= \frac{1}{9 \times 10} \\\\ = \frac{1}{90}\\\\[/tex]

[tex]k= n^ \to s_n = \frac{1}{(n+6)(n+7)}\\\\[/tex]

calculate the sum:[tex]S= s_1+s_2+s_3+s_n\\[/tex]

[tex]S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(n+6)(n+7)}\\\\[/tex]

when [tex]s_n \ \ dt_{n \to 0}[/tex]

[tex]S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(0+6)(0+7)}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{6 \times 7}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{42}\\\\=\frac{45+35+28+60}{2520}\\\\=\frac{168}{2520}\\\\=0.066[/tex]

[tex]\boxed{\text{In point 2:} \sum ^{\infty}_{k = 1} \frac{1}{(n+6)(n+7)} = 0.066}[/tex]

Answer:

82

Step-by-step explanation:

If you don't know the derivative of the inverse of sine, you can use implicit differentiation. Apply sine to both sides:

[tex]y=\sin^{-1}(6x+1)\implies\sin y=6x+1[/tex]

(true for y between -π/2 and π/2)

Now take the derivative of both sides and solve for it:

[tex]\cos y\dfrac{\mathrm dy}{\mathrm dx}=6[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dx}=6\sec y[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\cos\left(\sin^{-1}(6x+1)\right)}[/tex]

[tex]\dfrac{\mathrm dy}{\mathrm dx}=\dfrac6{\sqrt{1-(6x+1)^2}}[/tex]

Answer:

a

Step-by-step explanation:

A theorem cannot be proven.

Answer:

M= D x V, V= M x D

Step-by-step explanation:

You just do the opposite of division since the original is:

Density= Mass/ Volume