Answer:
M ≈ 180 g/mol
Explanation:
Molar mass (M) = Mass (m) / Number of moles (n)
M = 142 g / 0.789 mol
M = 179.974651485 g/mol
Round to 3 SigFigs
M ≈ 180 g/mol
Please don't confuse Molar Mass (M = g/mol) with Molarity (M = mol/Liter)
Hope this helps!
Colifo bacteria in drinking water will not likely cause illness. However, their presence in drinking water indicates that disease-causing organisms (pathogens) could be in the water system. True / F
Yes, the given statement is true. Coliform bacteria in drinking water are generally not likely to cause illness. However, their presence serves as an indicator that disease-causing organisms (pathogens) could potentially be present in the water system. Most coliform bacteria are harmless and naturally occur in the intestines of animals and humans, as well as in soil, on plants, and in surface water.
However, it is important to note that certain strains of Escherichia coli (E. coli), such as O157:H7, can cause severe illness. While most coliform bacteria are not directly harmful, their presence suggests a possible contamination of the water source with feces or animal waste. This means that pathogenic bacteria, including those that can cause illness, may also be present. The presence of coliforms in water indicates a potential pathway for contamination and raises the risk of disease-causing organisms (pathogens) being present in the water system.
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What is the mass in grams of 1.50×10 12
lead ( Pb ) atoms? Round your answer to 3 significant digits.
The mass in grams of[tex]1.50 x 10^12[/tex] lead (Pb) atoms is `0.000516 g`. Given that the number of lead (Pb) atoms is [tex]1.50 x 10^12.[/tex]
We need to find the mass in grams of these atoms. The molar mass of lead (Pb) is 207.2 g/mol.
This means that 1 mole of lead (Pb) has a mass of 207.2 grams.
Hence, to find the mass of 1.50 x 10^12 lead (Pb) atoms, we need to find the number of moles and then multiply by the molar mass.
Number of moles of lead (Pb) atoms present is:
`number of atoms / Avogadro's number`
= [tex]`1.50 x 10^12 / 6.022 x 10^23`[/tex]
[tex]= 2.491 x 10^-12 mol[/tex]
Now, we can find the mass of lead (Pb) atoms by multiplying the number of moles with molar mass of lead (Pb) atoms.[tex]`mass of 1.50 x 10^12[/tex] lead (Pb) atoms`
[tex]= `2.491 x 10^-12 mol x 207.2 g/mol`[/tex]
=`0.000516 g`
Rounded to three significant figures, the mass in grams of [tex]1.50 x 10^12[/tex]lead (Pb) atoms is `0.000516 g`.
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when we use a scanning probe microscope, do we see atoms directly or do we see them only indirectly?
When we use a scanning probe microscope, we see atoms directly.
The scanning probe microscope is a device used for measuring properties of surfaces such as height, slope, and roughness at a very high resolution. This device uses a probe tip that is attached to a cantilever to scan the surface of the sample that is to be observed. It then records the interaction between the surface of the sample and the probe tip, which is used to form an image of the surface.
The scanning probe microscope has the ability to image individual atoms, which makes it one of the most powerful tools for studying surfaces at the atomic scale. This device has a resolution that is much higher than traditional microscopes, which means that we can see atoms and molecules directly. It has a wide range of applications in fields such as materials science, physics, chemistry, and biology. In conclusion, when we use a scanning probe microscope, we see atoms directly.
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In a container you have 3 gases −X,Y, and Z - each present in the same amount by weight. Their molecular weights are in the order X>Y>Z. The total pressure in the container is 1 atm. The partial pressure contributed by each gas would be in the order: A. X>Y>Z B. Z>Y>X C. X=Y=Z=0.333 atm D. X=Y=Z= latm E. Data insufficient
The partial pressure contributed by each gas would be in the order X=Y=Z= 0.333 atm.
Hence, the correct option is C.
The partial pressure contributed by each gas in the container can be determined using Dalton's Law of Partial Pressures, which states that the total pressure exerted by a mixture of non-reacting gases is equal to the sum of the partial pressures of each gas.
Given that X, Y, and Z are present in the container in equal amounts by weight and X>Y>Z in terms of molecular weights, we can conclude that gas X has the highest molecular weight, followed by gas Y, and then gas Z.
According to Dalton's Law, the partial pressure of each gas is directly proportional to its mole fraction. Since the three gases are present in equal amounts by weight, their mole fractions will also be equal.
Therefore, the partial pressure contributed by each gas will be the same. In other words, X=Y=Z.
Hence, the correct option is:
X=Y=Z=0.333 atm
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PLEASE DON’T GIVE AN EXPLANATION, ANSWER ONLY NEEDED. THANK YOU
Which of the following substances is the most strained? A cis-1,2-di-tert-butylcyclopropane B. trans-1,2-tert-butylcyclopropane c. trans-1,2-dimethylcyclopropane D. cis-1,2-dimethylcyclopropane
Due to steric hindrance caused by the bulky tert-butyl groups in the cis configuration on the cyclopropane ring, the most strained substance is (A) cis-1,2-di-tert-butylcyclopropane
Trans-1,2-tert-butylcyclopropane is less strained compared to the cis isomer since the tert-butyl groups are in a trans configuration, reducing the steric hindrance.
Trans-1,2-dimethylcyclopropane has less strain compared to the tert-butyl-substituted cyclopropanes since the methyl groups are smaller and cause less steric hindrance.
Cis-1,2-dimethylcyclopropane has the least strain among the given options since it has smaller methyl groups and they are cis to each other, minimizing steric hindrance.
Therefore, A cis-1,2-di-tert-butylcyclopropane is the correct answer.
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select all that are true about buffers and buffer regions. group of answer choices drastic changes in ph will be observed when adding acid or base to a buffer buffers consist of high concentrations of a weak conjugate acid-base pairs in a weak acid-strong base titration the buffer region is identified as the relatively horizontal area after the equivalence point in a weak acid-strong base titration the buffer region is identified as the relatively horizontal area before the equivalence point drastic changes in ph will not be observed when adding acid or base to a buffer
Buffers consist of weak acid-base pairs in high concentrations and prevent drastic changes in pH when acid or base is added.
The true statements about buffers and buffer regions are as follows:
Buffers consist of high concentrations of a weak conjugate acid-base pair.Buffers are solutions that resist changes in pH when small amounts of acid or base are added to them.They are composed of a weak acid and its conjugate base or a weak base and its conjugate acid, both present in relatively high concentrations.
Drastic changes in pH will not be observed when adding acid or base to a buffer.Buffers are designed to maintain a relatively constant pH. When small amounts of acid or base are added to a buffer, the buffer components can react with them and minimize the change in pH. As a result, buffers exhibit resistance to drastic changes in pH.The following statements are false:
Drastic changes in pH will be observed when adding acid or base to a buffer.This statement is false. Buffers are specifically designed to resist drastic changes in pH. When acid or base is added to a buffer, the buffer components react with them to maintain the pH within a relatively narrow range.In a weak acid-strong base titration, the buffer region is identified as the relatively horizontal area after the equivalence point.
This statement is false. In a weak acid-strong base titration, the buffer region is actually identified as the relatively horizontal area before the equivalence point.
In this region, the weak acid and its conjugate base are present in the buffer, and their concentrations help maintain the pH relatively stable.
In summary, the true statements are: Buffers consist of high concentrations of a weak conjugate acid-base pair, and drastic changes in pH will not be observed when adding acid or base to a buffer.
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A experiment calls for 45 gallons of a saline solution. You only have a saline solution and a saline solution. Let x represent the amount of saline solution and y represent the amount of saline solution, what is the
equation that describes the total amount of pure saline in the solution?
The equation that describes the total amount of pure saline in the solution is: x + y = 45.
In the given scenario, x represents the amount of saline solution and y represents the amount of saline solution. The experiment calls for a total of 45 gallons of the saline solution. Since the total amount of saline in the solution is the sum of the amounts in each component, the equation x + y = 45 represents the total amount of pure saline in the solution.
The equation simply states that the combined amounts of saline solution (x) and saline solution (y) should add up to 45 gallons, fulfilling the requirement of the experiment. It provides a straightforward mathematical representation of the relationship between the two components in terms of their total quantity.
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complete the noncovalent force table in all the molecular foula
Completing the noncovalent force table for all the molecular formulas:
Noncovalent forces, also known as intermolecular forces, play a crucial role in determining the physical and chemical properties of molecules. The table below outlines the common noncovalent forces for each molecular formula:
Molecular Formula: Noncovalent Forces:
C5H8O London dispersion forces, dipole-dipole interactions, hydrogen bonding
(Note: The specific arrangement of atoms in the molecule will determine the strength and presence of these forces.)
1. London dispersion forces: Present in all molecules, these forces arise due to temporary fluctuations in electron distribution, creating temporary dipoles. They are the weakest intermolecular forces.
2. Dipole-dipole interactions: Present in polar molecules, these forces occur when the positive end of one molecule is attracted to the negative end of another molecule due to permanent dipoles.
3. Hydrogen bonding: A special type of dipole-dipole interaction that occurs when a hydrogen atom is bonded to a highly electronegative atom (such as nitrogen, oxygen, or fluorine) and is attracted to a lone pair of electrons on another electronegative atom.
The noncovalent force table provides an overview of the common intermolecular forces present in molecules with different molecular formulas. Understanding these forces is essential in predicting the behavior, physical properties, and interactions of molecules. The specific arrangement and functional groups in each molecule influence the presence and strength of noncovalent forces.
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Part A Use Kepler's third law to find the collapse time, astuming the star has the same mass as the Sun. Express your answer in years to two significant figures.
The collapse time would be 1,263 years (to two significant figures).
Kepler's third law states that the square of the orbital period of a planet is proportional to the cube of the semi-major axis of its orbit. Mathematically, it can be expressed as:
T^2 = (4π^2/GM)R^3
where T is the period of the planet's orbit, G is the gravitational constant, M is the mass of the central object (in this case, the star), and R is the semi-major axis of the planet's orbit.
Using Kepler's third law to find the collapse time, assuming the star has the same mass as the Sun can be done as follows:
T^2 = (4π^2/GM)R^3T^2 = (4π^2/[(6.67 x 10^-11 N(m^2/kg^2))(1.99 x 10^30 kg)])(1.5 x 10^11 m)^3T^2 = 1.58 x 10^20T = sqrt(1.58 x 10^20)T = 3.98 x 10^10 seconds
Since we want the answer in years with two significant figures, we need to convert seconds to years and round to two significant figures.1 year = 31,536,000 seconds
Therefore, T = (3.98 x 10^10 seconds)/(31,536,000 seconds/year)
T = 1,263 years (to two significant figures)
Therefore, the collapse time is 1,263 years (to two significant figures).
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parts c and d please
1. Chlorine, bromine, and iodine are all diatomic molecules as a result of covalent bonding. However, due to differences in the strength of the inteolecular forces, they exist in three different sta
Chlorine, bromine, and iodine are all diatomic molecules due to covalent bonding. However, they exist in three different states because of differences in the strength of the intermolecular forces.
The three different states are solid, liquid, and gas. The three elements are at room temperature (approximately 25 °C): Chlorine is a gas, bromine is a liquid, and iodine is a solid. The different states of these three elements at the same temperature can be explained in terms of the strength of their intermolecular forces. Chlorine molecules are held together by weak intermolecular forces; as a result, it is a gas at room temperature. Bromine molecules are kept together by intermolecular forces that are a little stronger than chlorine's; therefore, it is a liquid at room temperature. Iodine molecules are held together by intermolecular forces that are much stronger than chlorine's and bromine's; as a result, it is a solid at room temperature. Part C: The statement that describes how the difference in intermolecular forces between chlorine, bromine, and iodine is responsible for their different states is, "However, due to differences in the strength of the intermolecular forces, they exist in three different states."Part D: Chlorine is a gas at room temperature, bromine is a liquid, and iodine is a solid. This is due to differences in intermolecular forces. Chlorine molecules are held together by weak intermolecular forces, so they are a gas at room temperature. Bromine molecules are held together by intermolecular forces that are slightly stronger than those of chlorine, so they are liquid at room temperature. Finally, iodine molecules are held together by intermolecular forces that are significantly stronger than those of chlorine and bromine, so they are solid at room temperature.
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Perform the following conversion:
83 grams = _________ megagrams
(Do not use scientific notation.)
The given value is 83 grams. So, 83 grams is equal to 0.000083 megagrams.
Converting grams to megagrams we get,1 megagram = 1,000,000 grams
So, 1 gram = 1/1,000,000 megagrams
Converting 83 grams to megagrams:
83 grams = 83/1,000,000 megagrams = 0.000083 megagrams
We can convert from grams to megagrams using the following formula:
1 megagram = 1,000,000 grams
Hence, 1 gram = 1/1,000,000 megagrams
To convert 83 grams to megagrams, we can use this formula and substitute the given value of 83 grams.
83 grams = 83/1,000,000 megagrams= 0.000083 megagrams
Therefore, 83 grams is equal to 0.000083 megagrams.
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a. Draw a Newman projection of the staggered gauche confoation of pentane sighting down the C2 −C3
bond. b. What kind(s) of strain exists in this confoation? c. Draw a Newman projection of the most unstable confoation of pentane sighting down the C2 −C3 bond
a. Newman projection of staggered gauche conformation of pentane is given below:
The staggered gauche conformation of pentane can be drawn using Newman projection as follows:
Newman projection is used to represent the 3D structure of the molecule in a 2D plane. In Newman projection, the front carbon is represented by a dot and the back carbon is represented by a circle. The carbon-carbon bond is represented by a line. The angle between the carbon-carbon bond and the substituents is 60° for the gauche conformation. Thus, in the Newman projection of staggered gauche conformation of pentane, the angle between C1–C2 and C2–C3 bond is 60° and 300° respectively.
b. The strain exists in this conformation is torsional strain. Torsional strain arises from the eclipsing interactions between the substituents on adjacent atoms. In staggered gauche conformation of pentane, there are no eclipsing interactions between the substituents on adjacent atoms. Therefore, no torsional strain exists in this conformation.
c. Newman's projection of the most unstable conformation of pentane is given below: The most unstable conformation of pentane is the eclipsed conformation. In the eclipsed conformation, the angle between C1–C2 and C2–C3 bond is 0°. Thus, in the Newman projection of the most unstable conformation of pentane, the front carbon and back carbon overlap each other.
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A hot air balloon is filled to a volume of 44. 5 l at 758 torr. What will be the volume of the balloon if the pressure decreases to 748 torr under constant temperature?.
The volume of the balloon will be approximately 45 liters when the pressure decreases to 748 torr.
According to Boyle's Law, at constant temperature, the pressure and volume of a gas are inversely proportional. This means that as the pressure decreases, the volume increases, and vice versa.
The relationship between pressure and volume is given by the equation P1V1 = P2V2, where P1 and V1 represent the initial pressure and volume, and P2 and V2 represent the final pressure and volume.
In this case, the initial volume of the balloon is given as 44.5 L, and the initial pressure is 758 torr. The final pressure is given as 748 torr, and we need to find the final volume.
Using the formula P1V1 = P2V2, we can rearrange it to solve for V2:
V2 = (P1 * V1) / P2
Plugging in the values, we get:
V2 = (758 torr * 44.5 L) / 748 torr
Simplifying the equation, we find:
V2 = 45 L
Therefore, the volume of the balloon will be 45 liters when the pressure decreases to 748 torr under constant temperature.
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Which of the following is a special problem because it constitutes such as large proportion of trash, and yet it cannot be recycled indefinitely because the fibers break down?
• Aluminum
• Plastic
• Glass
• Paper
Paper is a special problem because it constitutes such a large proportion of trash, and yet it cannot be recycled indefinitely because the fibers break down.
The material that constitutes such a large proportion of trash and yet cannot be recycled indefinitely due to the breakdown of fibers is paper. The terms mentioned in the question, "150", "fibers", "constitutes," point towards the problem of paper waste.
A large proportion of trash constitutes paper, which is a special problem because paper fibers break down when recycled several times. The fibers, on the other hand, can only be recycled four to six times before they deteriorate, leaving the paper unusable.
Therefore, paper is a special problem because it constitutes such a large proportion of trash, and yet it cannot be recycled indefinitely because the fibers break down. The other options in the question, including aluminum, plastic, and glass, can be recycled indefinitely without losing their quality.\
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How many molecules of water are in a collection of snowflakes with a mass of 0.005 grams?A) 5.43 x 1022B) 3.01 x 1024C) 1.67x 1020D) 2.17 x 1021
The number of molecules of water in a collection of snowflakes with a mass of 0.005 grams is approximately 1.67 x 10^20 molecules.
To determine the number of molecules of water in a collection of snowflakes with a mass of 0.005 grams, we need to use the concept of moles and Avogadro's number.
Calculate the number of moles of water:We know the molar mass of water is approximately 18.015 grams/mol.
Mass (g) = Number of moles × Molar mass (g/mol)
0.005 g = Number of moles × 18.015 g/mol
Number of moles = 0.005 g / 18.015 g/mol ≈ 0.000277 mol
Calculate the number of molecules:Avogadro's number states that there are approximately 6.022 x 10^23 molecules in one mole of a substance.
Number of molecules = Number of moles × Avogadro's number
Number of molecules = 0.000277 mol × 6.022 x 10^23 molecules/mol
Number of molecules ≈ 1.667 x 10^20 molecules
Therefore, the correct answer is C) 1.67 x 10^20 molecules.
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A Lewis structure with placeholder elements is shown below. if the foal charge of the central atom is 0 , choose the possible identity or identities of the central atom.
The Lewis structure with placeholder elements is given below:
As given, the formal charge of the central atom is 0. For finding the identity of the central atom, we need to count the valence electrons of all the atoms and subtract them from the total valence electrons. Then, divide the total number of electrons obtained by 2 to get the total number of bonds formed. Then add the remaining electrons to each atom to complete the octet.
The valence electrons of the elements are given below: -
Valence electrons of A = 6
- Valence electrons of B = 4
- Valence electrons of C = Placeholder element
- Valence electrons of D = 3
Total number of valence electrons of the given compound= (6 × 2) + (4 × 2) + (3 × 2) + 2x = 24 + 2xwhere x = number of valence electrons of the placeholder element.
To find the identity of the central atom, we need to find the value of x as follows: 24 + 2x = 8x + 16 => x = 2
The possible identity of the central atom is an element that has 2 valence electrons. The only element with 2 valence electrons is Helium (He). Therefore, the identity of the central atom is Helium (He).
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1. Only one of the three aromatic amino acids is considered highly hydrophobic. Which one is it? Explain why the other two aromatic amino acids are not. 2. How can you use amino acids to estimate the concentration of a protein? 3. Put the following amino acids in order of most to least soluble in water: E L C 4. All amino acids have at least two dissociable hydrogens, but some have three. Explain and be specific. List the amino acids that have three. 5. Why is methionine considered "highly hydrophobic" and cysteine considered "less hydrophobic" even though they both contain sulfur?
1. Only one of the three aromatic amino acids is considered highly hydrophobic. The one that is highly hydrophobic is tryptophan. The other two, tyrosine and phenylalanine, have polar groups on their side chains which are capable of interacting with water molecules.
This makes them less hydrophobic than tryptophan.2. Amino acids can be used to estimate the concentration of a protein through a process called the Lowry assay. The assay involves a series of chemical reactions in which the amino acids in the protein react with copper ions to form a blue color complex. The intensity of the blue color is proportional to the concentration of the protein in the sample.
3. The amino acids in order of most to least soluble in water are: E (glutamic acid), L (leucine), C (cysteine). Glutamic acid is highly soluble in water due to its charged side chain. Leucine is less soluble than glutamic acid but more soluble than cysteine because it is non-polar and does not form hydrogen bonds with water. Cysteine is the least soluble because it can form disulfide bonds with other cysteine residues, making it more likely to form aggregates and less likely to dissolve in water.
4. All amino acids have at least two dissociable hydrogens because they contain both an amino group and a carboxyl group, both of which can donate a hydrogen ion. Some amino acids have a third dissociable hydrogen because their side chains contain an acidic group that can donate a hydrogen ion. The amino acids that have three dissociable hydrogens are: histidine, lysine, arginine, aspartic acid, and glutamic acid.
5. Methionine is considered highly hydrophobic because it has a non-polar side chain that cannot form hydrogen bonds with water. Cysteine is considered less hydrophobic than methionine because it has a polar side chain that can form hydrogen bonds with water. The sulfur in cysteine can also participate in disulfide bond formation, which can further reduce its hydrophobicity.
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An aqueous solution is 22.0 % by mass
ethanol,
CH3CH2OH, and has a density
of 0.966 g/mL.
The mole fraction of ethanol in the solution
is
The mole fraction of ethanol in the 22.0% by mass aqueous solution is 0.333.
The mole fraction of ethanol ([tex]CH_3CH_2OH[/tex]) in the solution, we need to calculate the number of moles of ethanol and the number of moles of water in the solution.
Assume we have 100 g of the solution. This means that 22.0 g of the solution is ethanol ([tex]CH_3CH_2OH[/tex]), and the remaining mass is water ([tex]H_2O[/tex]).
Molar mass of ethanol ([tex]CH_3CH_2OH[/tex]):
= (2 * 12.01 g/mol for carbon) + (6 * 1.01 g/mol for hydrogen) + (1 * 16.00 g/mol for oxygen)
= 46.07 g/mol
Number of moles of ethanol = mass of ethanol / molar mass of ethanol
= 22.0 g / 46.07 g/mol
To calculate the number of moles of water, we need to convert the given density to mass per volume. The density is given as 0.966 g/mL, so for 100 g of the solution, the volume of the solution will be:
Volume of the solution = mass of the solution / density
= 100 g / 0.966 g/mL
We need to calculate the mass of water in the solution:
Mass of water = total mass of the solution - mass of ethanol
= 100 g - 22.0 g
Number of moles of water = mass of water / molar mass of water
The molar mass of water (H2O) is 18.02 g/mol.
Number of moles of water = (100 g - 22.0 g) / 18.02 g/mol
We can calculate the mole fraction of ethanol ([tex]CH_3CH_2OH[/tex]) in the solution:
Mole fraction of ethanol = moles of ethanol / (moles of ethanol + moles of water)
Substituting the values we calculated:
Mole fraction of ethanol = (22.0 g / 46.07 g/mol) / [(22.0 g / 46.07 g/mol) + ((100 g - 22.0 g) / 18.02 g/mol)]
Calculating the values:
Mole fraction of ethanol ≈ 0.333
The mole fraction of ethanol in the solution is 0.333.
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consider the below reaction between the acetylide ion and methanol.
The reaction between the acetylide ion and methanol involves the substitution of a hydrogen atom in methanol with the acetylide ion, resulting in the formation of an alkoxide ion.
The reaction between the acetylide ion and methanol involves the formation of an alkyne.
Here is a step-by-step explanation of the reaction:
1. The acetylide ion is a negatively charged carbon atom bonded to two additional carbon atoms. It has a triple bond between the carbon atoms, making it an alkyne.
2. Methanol, on the other hand, is an alcohol with a hydroxyl group (-OH) bonded to a carbon atom.
3. In the reaction, the acetylide ion reacts with methanol, resulting in the substitution of the hydrogen atom in the hydroxyl group (-OH) of methanol with the acetylide ion.
4. This substitution occurs because the acetylide ion is a strong nucleophile, meaning it has a high affinity for positively charged or electron-deficient species.
5. The result of the reaction is the formation of a new compound, which is an alkoxide ion. The alkoxide ion contains the acetylide group (-C≡C-) attached to the carbon atom of the hydroxyl group.
It's important to note that the reaction between the acetylide ion and methanol is just one example of a reaction involving the acetylide ion. The acetylide ion can react with other compounds as well, leading to different products. The conditions of the reaction, such as temperature and solvent, can also influence the outcome.
Overall, the reaction between the acetylide ion and methanol involves the substitution of a hydrogen atom in methanol with the acetylide ion, resulting in the formation of an alkoxide ion.
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Question 1: Calculate [OH−OH−] for a solution where [H3O+]=0.00425 M[H3O+]=0.00425 M.
[OH−]=
Question 2:
Calculate the pH of a solution that has a hydroxide ion concentration, [OH−][OH−], of 1.70×10−4 M.1.70×10−4 M.
pH=
Question 1: The value of [OH−] in the given solution is 2.35 × [tex]10^-12[/tex] M. The relationship between hydronium ion and hydroxide ion concentration is given by this equation: [H3O+][OH−]=1.0×10−14.The value of the product of [H3O+][OH−] at 25°C is 1.0×10−14;
As a result, in any aqueous solution, when one ion concentration rises, the other ion concentration decreases.So, for the given solution [H3O+] = 0.00425 M, we can calculate [OH−] by rearranging the above equation as shown below:[H3O+][OH−]=1.0×10−14[OH−]
=1.0×10−14/[H3O+]
Substituting [H3O+] = 0.00425 M into the above equation, we get:[OH−]=1.0×10−14/0.00425
[OH−]=2.35×[tex]10^-12[/tex] M
Thus, the value of [OH−] in the given solution is 2.35 × [tex]10^-12[/tex] M.
Question 2:The pH scale ranges from 0 to 14. The pH of a solution is equal to the negative logarithm of the hydronium ion concentration in moles per liter (M) of the solution. The pH can be calculated using the following formula:
pH=−log[H3O+]
In this question, the value of [OH−] is given instead of [H3O+].
However, the product of [H3O+][OH−] equals 1.0×10−14.
Consequently, we can compute the [H3O+] and then calculate the pH as shown below:
[H3O+][OH−]=1.0×10−14[OH−]=1.0×10−14/[H3O+]
Substituting [OH−] = 1.70×10−4 M into the above equation, we get:
[H3O+]=1.0×10−14/[OH−][H3O+]
=1.0×10−14/(1.70×10−4 )[H3O+]
=5.88×10−11 M
Now that we know the value of [H3O+], we can calculate the pH:
pH=−log[H3O+]
pH=−log(5.88×10−11 )
pH=10.23
Therefore, the pH of the given solution is 10.23.
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While feeding urea, the ruminant animals must be supplied with molasses or other source of highly degradable carbohydrate. Do you agree? Justify your answer?. (2) 5. Why we need to add "Sulphur" when we feed urea for ruminant animals? There are no energy in urear, we add sidphus in teed rumsvant to which can be utilised by rumen microbes to improve ramen function and 6. If by-pass protein is important why can't we feed all protein in the diet as by- pass protein? Approximately how many grams of nitrogen are there in 1 kg of protein? (2) grams of mirogen. 6.25 grams of protein, Write the chemical structure of the ammonia ? NH3
The chemical structure of ammonia is NH3.
Feeding urea is the practice of providing animals with a source of non-protein nitrogen (NPN), which aids in the synthesis of microbial protein by the rumen microbes.
While feeding urea, the ruminant animals must be supplied with molasses or another source of highly degradable carbohydrate. Therefore, it is accurate to agree that when feeding urea, ruminant animals must be provided with molasses or another source of highly degradable carbohydrate to aid in the urea breakdown process.
This is because urea, as a non-protein nitrogen source, must first be broken down to produce ammonia, which then undergoes microbial nitrogen fixation into microbial protein for the ruminant animals to use. Therefore, feeding urea requires a source of highly degradable carbohydrates to provide energy for the microbes to break down the urea and fix the ammonia into microbial protein.
When we feed urea to ruminant animals, we add "sulphur" because there are no energy in urea. The addition of sulphur in feed rumsvant to which can be utilised by rumen microbes to improve rumen function. Therefore, the addition of sulphur is necessary to enable rumen microbes to perform optimally in the process of microbial protein synthesis.
We cannot feed all protein in the diet as by-pass protein because by-pass protein is only a fraction of the total protein. There are approximately 16 grams of nitrogen in 1 kg of protein.
The chemical structure of ammonia is NH3.
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Bomite (Cu3FeS3) is a copper ore used in the production of copper. When heated, the following reaction occurs. 2Cu3FeS3( s)+7O2(g)→6Cu(s)+2FeO(s)+6SO2(g) If 3.54 metric tons of bornite is reacted with excess O2 and the process has an 92.1% yield of copper, what mass of copper is produced? घ⿱日一 x metrictons
The mass of copper produced is [tex]1.2095 x 10^6 g[/tex] or 1209.5 kg or 1209.5 x 1000 g.
We know that, Number of moles of Cu = 2 moles of Cu3FeS3( s)
( From balanced chemical equation )
Let's calculate the number of moles of Bornite (Cu3FeS3).
Moles of Cu3FeS3 = mass / molecular weight
Moles of Cu3FeS3 =[tex](3.54 x 10^6 g) / (342.68 g/mole)[/tex]
Moles of Cu3FeS3 = 10337.5 moles
Now, we can calculate the theoretical yield of copper that is expected to be produced from 10337.5 moles of Bornite.
Cu = 2 moles of Cu3FeS3 ( From balanced chemical equation )
Moles of Cu = 2 x 10337.5 moles of Cu
Moles of Cu = 20675 moles of Cu
Now, let's calculate the mass of copper produced using the molar mass of copper.
Mass of Copper produced = Moles of Copper produced x Molecular weight of Copper
Mass of Copper produced = 20675 moles of Cu x 63.55 g/mole
Mass of Copper produced = [tex]1.3141 x 10^6 g[/tex]
Now, we need to calculate the actual yield of copper that is produced from 3.54 metric tons of Bornite.
The percentage yield of copper = (Actual yield of Cu / Theoretical yield of Cu ) x 10092.1 %
= [tex](Actual yield of Cu / 1.3141 x 10^6 g ) x 100[/tex]
Actual yield of Cu = [tex]1.3141 x 10^6 g x (92.1 / 100)[/tex]
Actual yield of Cu = [tex]1.2095 x 10^6 g[/tex]
Thus, the answer is 1209.5 kg.
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Write a rationale explaining how you deteined which cations are absent and which are present. Rational must explain stepwise how the observations prove the presence
(Two cations include sodium and potassium)
The presence of sodium and potassium cations can be determined based on their characteristic flame colors and the results of confirmatory tests. If the flame test yields the respective colors and the confirmatory tests show the appropriate precipitates, it indicates the presence of sodium and potassium cations in the sample.
To determine which cations are present and which are absent, a systematic approach involving specific tests and observations can be followed. In this case, let's consider the cations sodium (Na+) and potassium (K+). Here is a stepwise rationale on how to determine their presence:1. Preliminary observation: Begin by visually inspecting the sample for any obvious signs of sodium or potassium compounds, such as color or distinctive physical characteristics.2. Flame test: Perform a flame test by introducing a small amount of the sample into a flame. Sodium ions emit a bright yellow flame, while potassium ions produce a violet flame. The presence of these distinct flame colors confirms the presence of the respective cations.3. Confirmatory tests: Conduct confirmatory tests to differentiate between sodium and potassium. For example, perform a precipitation reaction using silver nitrate (AgNO3) solution. Silver chloride (AgCl) precipitates in the presence of sodium ions, forming a white precipitate, while silver iodide (AgI) precipitates in the presence of potassium ions, resulting in a yellow precipitate. The appearance of the appropriate precipitate confirms the presence of the respective cation.For more such questions on potassium
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Calculate solution concentration. A solution consists of 64.0 g of silver nitrate, AgNO 3
, and 109.0 g water. (a) Calculate the weight percent, the molality, and the mole fraction of AgNO3
in the solution. weight percent = molality = mole fraction = (b) The solution volume is 121 mL. Calculate the molarity of AgNO3
in the solution. molarity =
The weight percent of [tex]AgNO^{3}[/tex] in solution is 37.0241 %.
The molality of [tex]AgNO^{3}[/tex] is 3.4482 mol/kg.
The mole fraction of [tex]AgNO^{3}[/tex] is 0.0642.
The molarity of [tex]AgNO^{3}[/tex] is 3.1074 M.
Weight of silver nitrate, [tex]AgNO^{3}[/tex] = 64 g
Weight of water = 109 g
Weight of solution = 64 g + 109 g = 173 g
(a) Weight percent: It is the percentage of the weight of the solute to the weight of the solution. It can be given as follows:
Weight percent of [tex]AgNO^{3}[/tex] in solution = Mass of [tex]AgNO^{3}[/tex] / Total mass of solution× 100%
Weight percent of [tex]AgNO^{3}[/tex] = 64 g / (64 g + 109 g) × 100% = 37.0241%
Molality: It is the amount of substance of solute present in 1000g of the solvent. It can be given as follows:
Molality of [tex]AgNO^{3}[/tex]
= moles of solute / mass of solvent in kg
Molecular weight of [tex]AgNO^{3}[/tex] = Ag + N + 3O = 107.87 + 14.01 + (3×16.00) = 169.87 g/mol
Number of moles of [tex]AgNO^{3}[/tex] = 64 g / 169.87 g/mol = 0.3762 mol
Mass of water, m = 109 g/1000 g = 0.109 kg
Molality of [tex]AgNO^{3}[/tex] = 0.3762 mol / 0.109 kg= 3.4482 mol/kg
Mole fraction: It is the ratio of moles of one component to the total moles present in the solution. It can be given as follows:
Mole fraction of [tex]AgNO^{3}[/tex] = moles of [tex]AgNO^{3}[/tex] / total number of moles in solution
Mole fraction of [tex]AgNO^{3}[/tex] = 0.3762 mol / (0.3762 + 5.4235) mol = 0.0642
(b) Molarity: It is the amount of substance of solute present per litre of the solution.
Molarity of [tex]AgNO^{3}[/tex] = moles of [tex]AgNO^{3}[/tex] / volume of solution in litres
Molarity of [tex]AgNO^{3}[/tex] = 0.3762 mol / (121/1000) L= 3.1074 M.
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the element that has a valence configuration of 6s1 is ________. a)k b)rb c)na d)cs e)li
Answer:
The element that has a valence configuration of 6s1 is option (a) K (potassium).
Explanation:
The electron configuration of an element describes how electrons are arranged in its atomic orbitals. The notation used to represent electron configuration follows a specific pattern. The first number represents the principal energy level (n), followed by the letter representing the type of orbital (s, p, d, f), and finally, the superscript denotes the number of electrons in that orbital.
In this case, the valence configuration is described as 6s1. The "6" indicates the principal energy level or shell (n = 6), and the "s" refers to the s orbital. The superscript "1" indicates that there is only one electron in the 6s orbital.
The options given are K (potassium), Rb (rubidium), Na (sodium), Cs (cesium), and Li (lithium). We need to determine which of these elements has an electron configuration that matches 6s1.
Among the options, only potassium (K) has an electron configuration of [Ar] 4s1, which corresponds to 6s1 after considering the previous energy levels. The noble gas abbreviation [Ar] indicates that the electron configuration of potassium is similar to that of argon (Ar) with a completed 3rd energy level. Following argon, the 4th energy level starts with the 4s orbital, and potassium has one electron in that orbital.
Therefore, the element with a valence configuration of 6s1 is potassium (K), option (a).
Please feel free to download and use my periodic table which has the orbital numbers along the sides and in some element blocks.
Oxidation describes the __________ of electrons by an atom, ion, or molecule. Select the correct answer below: movement, gain, loss, transfer
Oxidation describes the loss of electrons by an atom, ion, or molecule.
Oxidation is a chemical reaction that involves the loss of electrons or an increase in oxidation state by a molecule, atom, or ion. The loss of electrons by an atom, ion, or molecule is referred to as oxidation.
Electron Loss: Oxidation occurs when a substance loses electrons during a chemical reaction. Electrons are negatively charged particles that play a crucial role in chemical reactions. When a substance loses electrons, its oxidation state or oxidation number increases.Know more about Oxidation here,
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Upon heating: Potassium dichromate (record your observation here) On heating Ammonium dichromate (record vour observation here)
In this reaction, the oxidation state of chromium changes from +6 in potassium dichromate to +3 in chromium(III) oxide. The reaction can be represented by the equation:
4K2Cr2O7(s) → 4K2CrO4(s) + 2Cr2O3(s) + 3O2(g)
The reaction is highly exothermic, meaning it releases a significant amount of heat. As a visual indicator of the reaction, the orange-colored potassium dichromate crystals turn green due to the formation of chromium(III) oxide.
Similarly, when ammonium dichromate ((NH4)2Cr2O7) is heated, it undergoes a decomposition reaction, resulting in the formation of nitrogen gas (N2), water vapor (H2O), and chromium(III) oxide (Cr2O3). The reaction can be represented by the equation:
(NH4)2Cr2O7(s) → Cr2O3(s) + N2(g) + 4H2O(g)
This reaction is also highly exothermic and produces a substantial amount of heat. Similar to the potassium dichromate reaction, the orange-colored ammonium dichromate crystals turn green due to the formation of chromium(III) oxide.
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A teacher wants to find the average score for a student in his class. The teacher's sample set has seven different test scores: 78,89,93,95,88,78,95. He adds all the scores together and gets a sum of 616 . Use the given dataset to calculate the sample standard deviation.
To calculate the sample standard deviation, we need to follow these steps using the given dataset:
Step 1: Find the mean (average) of the dataset.
Step 2: Subtract the mean from each data point and square the result.
Step 3: Find the sum of all the squared differences.
Step 4: Divide the sum of squared differences by (n-1), where n is the number of data points.
Step 5: Take the square root of the result from step 4.
Now let's calculate the sample standard deviation for the given dataset:
Dataset: 78, 89, 93, 95, 88, 78, 95
Step 1: Find the mean
Mean = (78 + 89 + 93 + 95 + 88 + 78 + 95) / 7
Mean = 616 / 7
Mean ≈ 88
Step 2: Subtract the mean from each data point and square the result
(78 - 88)^2 = 100
(89 - 88)^2 = 1
(93 - 88)^2 = 25
(95 - 88)^2 = 49
(88 - 88)^2 = 0
(78 - 88)^2 = 100
(95 - 88)^2 = 49
Step 3: Find the sum of all the squared differences
Sum = 100 + 1 + 25 + 49 + 0 + 100 + 49
Sum = 324
Step 4: Divide the sum of squared differences by (n-1)
Sample variance = Sum / (n-1)
Sample variance = 324 / (7-1)
Sample variance = 324 / 6
Sample variance = 54
Step 5: Take the square root of the sample variance
Sample standard deviation ≈ √54
Sample standard deviation ≈ 7.35
Therefore, the sample standard deviation for the given dataset is approximately 7.35.
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10. Identify the type of polymer. −A−B−B−A−A−A−B−A− a) Copolymer b) Homopolymer c) Condensation polymer d) none of these Answer:
The given polymer sequence −A−B−B−A−A−A−B−A− can be classified as a (a) copolymer. Copolymers are polymers that are composed of two or more different monomers.
In this case, the polymer sequence consists of two different monomers, A and B, arranged in a specific pattern. The alternating arrangement of A and B monomers indicates that it is an alternating copolymer.
Copolymers can have diverse properties and characteristics depending on the composition and arrangement of the monomers.
They are widely used in various applications, such as in the production of plastics, fibers, coatings, and adhesives, due to their ability to combine the desirable properties of different monomers into a single material.
Therefore, (a) copolymer is the correct answer.
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The water test -kit says that the pH level should be between 7.4 and 7.6 pH units and the chlorine level should be between 1.0 and 1.5 PPM (parts per million ). Let p be the pH level and let c be the chlorine level (in PPM ).
If the chlorine level is too high, it may cause skin and eye irritation, leading to chemical burns in extreme cases. When p is the pH level and c is the chlorine level, the pH level should be between 7.4 and 7.6 pH units, and the chlorine level should be between 1.0 and 1.5 parts per million (PPM).
Pool owners and maintenance professionals must monitor two of the most important water quality indicators in swimming pools: pH and chlorine levels. These two chemicals are crucial to ensuring that the swimming pool remains a safe and healthy place to swim, and that the water is clean and clear. The pH level should be between 7.4 and 7.6 pH units, according to most water test kits.
pH levels outside this range may cause eye and skin irritation, corrosion of the pool’s surface, and an unbalanced pool. If the pH is too low, it will become acidic, causing skin and eye irritation. If the pH is too high, it can cause scaling, resulting in the formation of calcium deposits that are rough on the pool’s surface.
In general, when the pH is too low, the pool’s chlorine level can drop quickly, and when the pH is too high, the chlorine can become less effective. The chlorine level should be between 1.0 and 1.5 parts per million (PPM), according to most water test kits. Chlorine levels outside this range may cause health problems and increase the risk of waterborne illness. When the chlorine level is too low, the pool may become contaminated, resulting in bacterial growth and the spread of disease.
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