1. Fill in the missing Statement/Reason for the following proof:
Given: LN bisects ZMLO and LM = LO
Prove: ALMN = ALON
M
STATEMENT
1.
2.
3.
4. LN = LN
5.
ALMN a ALON
REASON
N
1.
2.
3. def of Angle Bisector
4.
5.
| I

1. Fill In The Missing Statement/Reason For The Following Proof:Given: LN Bisects ZMLO And LM = LOProve:

Answers

Answer 1

The completed proof that demonstrates that: ΔLMN ≅ ΔLON is:

LN Bisects ∠MLO; and LM ≅ LO [Given]∠MNL ≈ ∠ONL = 90° [Definition of Angle Bisector]LN ≅ LN [Definition of Reflexive Property]; ThusΔLMN ≅ ΔLON [AAS Postulate]

What is the Angle-Angle-Side Postulate (AAS)?

The Angle-Angle-Side Postulate (AAS) is a rule used in geometry to prove that two triangles are congruent. It states that if two angles and the side between them in one triangle are congruent to two angles and the side between them in another triangle, then the two triangles are congruent.

The reflexive property of equality in algebra asserts that a number is always equal to itself. Equality has a reflexive attribute. If x positive integer, then x = x.

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Related Questions

PLSSS HELP ME DUE TODAY!!!

Meg is heading back to her car after a hike to Misty Falls. The waterfall is at an elevation of 4,000 feet, and the trail descends an average of 500 feet for every 1 mile she hikes. You can use a function to approximate Meg's elevation after she hikes x miles.
Write an equation for the function. If it is linear, write it in the form h(x)=mx+b. If it is exponential, write it in the form h(x)=a(b)x.

Answers

Step-by-step explanation:

Since every single mile it descends the same amount (which is 500ft), that means it's linear, so we'll use that they gave us, the h(x) = mx+b

To find m, we use the following equation

[tex] \frac{y2 - y1}{x2 - x1} [/tex]

to find b, we have to find out the starting point. luckily they gave it to us, which is 4,000ft. B = 4000

Now every 500 feet, we go down 1 mile

Which means at 1000 feet, we go down 2 miles

500 and 1000 can be our y1 and y2

1 and 2 can be our x1 and x2

[tex] \frac{1000 - 500}{2 - 1} = \frac{500}{1} = 500 = m[/tex]

Now that we have our m and b, we just put it together

[tex]h(x) = - 500x + 4000[/tex]

A negative was placed before the 500 because they are descending, not ascending.

13. Interpret the IQR and median in the context of the data set.

Answers

The interquartile range is 4 and the median is 27.

What is the interquartile range?

The interquartile range is the difference between the third quartile and the first quartile. On a box plot, the interquartile range is the difference between the first line and the third line on the box.

Interquartile range = 28 - 24 =4

Median is the central value of a data set. On a box plot, the median is the second line on the box.

The median is 27.

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Points B and D are on the perpendicular bisector of ^ABC. The measure of

Answers

The measure of angle ABC in the figure of triangle attached is

< ABC = 46 degrees

What are perpendicular bisectors?

In geometry, a perpendicular bisector is a line or line segment that divides another line segment into two equal parts and is perpendicular to it.

From the definition of perpendicular bisector, we have that

< A = < C

and using triangle ABD

< A + < ABD = 90

< A + 28 = 90

< A = 90 - 28

< A = 62

Using triangle ABC

< A + < ABC + < C = 180

62 + < ABC + 62 = 180

< ABC = 180 - 62 - 62

< ABC = 56

OR

< ABD = < DBC = 28 degrees

and < ABC = < ABD + < DBC adjacent angles

< ABC = < ABD + < DBC

< ABC = 28 + 28

< ABC = 56 degrees

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complete question

The perpendicular bisector of side AB of triangle ABC intersects the extension of side AC at D. Find the measure of angle ABC if measurement of angle CBD=16 degrees and measurement of angle ACB=118 degrees

our jobs are to be done on four different machines. The cost in rupees of

producing ith on the jth machine is given below. Assign the jobs to different machines

so as to minimise the total cost.

Jobs

M1

M2

M3

M4

J1

15

11

13

15

J2

17

12

12

13
J3

14

15

10

14

J4

16

13

11

17

Answers

nbvggghhjjjjjhgfdddrttyyyyyy

Ramesh ran at a speed of 7 km/h for 3 h. He then 2 He took 6 h altogether to complete the whole journe (a) Find the total distance that Ramesh ran. (b) Find his average running speed for the whole j a mixed number in its simplest form.​

Answers

Find the total distance that Ramesh ran is 23km. His average running speed for the whole journey is 3 5/6 km/h.

How to calculate Ramesh Total distance and average running speed

To find the average speed,

We find the total distance and divide it by the total time.

During the first part of the run, she ran 3 hours at a speed of 7 km/h.  

To find the the distance she ran, multiply the speed times the time:  3 x 7 = 21 km.

From the second part of the run, she ran 2km.

So the total distance he ran is 21 + 2 = 23km.

The total time was 6 hours.

To find the the average speed;  

Divide 23 by 6 to get the average speed, which comes to 3 5/6 km/h.

hence, the average speed is 3 5/6 km/h.

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Find x round to the nearest whole number

Answers

Answer:

Below

Step-by-step explanation:

Instead of x , I assume you want the angle For RIGHT triangles, remember

cos (angle ) = adjacent leg / hypotenuse

cos ( angle ) = 5 /12    

      angle = arccos( 5/12) = 65 °

You could also use pythagorean theorem to calculate the misssing side....then use cos law to calculate the angle.

Find the number of ways to arrange the letters in HEDGEHOG.
There are blank ways to arrange the letters in HEDGEHOG.

Answers

Answer:

Step-by-step explanation:

The number of ways to arrange the letters in "HEDGEHOG" is 8!/(2!3!). The exclamation mark (!) means factorial, which is the product of all positive integers up to that number. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.

In this case, we have two H's and three E's, so we have to divide the total number of arrangements by the number of arrangements of H's and the number of arrangements of E's to avoid overcounting.

The total number of arrangements of the eight letters is 8!:

8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40320

The number of arrangements of H's is 2!:

2! = 2 x 1 = 2

The number of arrangements of E's is 3!:

3! = 3 x 2 x 1 = 6

So the number of arrangements of the letters in "HEDGEHOG" that avoid overcounting is:

40320 / (2 x 6) = 40320 / 12 = 3360.

Therefore, there are 3360 ways to arrange the letters in "HEDGEHOG".

An account that earned 23% annual interest compounded quarterly for 3 years and currently has a balance of $6258.

Answers

The initial balance of the account was approximately $3541.83.

What is interest is compounded?

This can be illustrated by using basic math: if you have $100 and it earns 5% interest each year, you'll have $105 at the end of the first year. You will wind up with $110.25 at the conclusion of the second year.

We can utilise the compound interest formula to find a solution to this issue:

A = P(1 + r/n)ⁿⁿ

In this case, we have P = the initial balance of the account, r = 0.23 (23% expressed as a decimal), n = 4 (since interest is compounded quarterly), t = 3 years, and A = $6258. We can solve for P by rearranging the formula:

P = A / (1 + r/n)ⁿⁿ

Substituting the values we know, we get:

P = 6258 / (1 + 0.23/4)⁴ˣ³

Simplifying this expression gives:

P = 6258 / 1.76757

P ≈ $3541.83

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Can someone help me with the step by step solutions to these? Thanks​

Answers

Answer:

  c. √2/30

  f. 13√3/14

  i. -11√10/24

Step-by-step explanation:

You want the sums of the fractions shown.

Sum of fractions

Two fractions can be added like this:

  [tex]\dfrac{a}{b}+\dfrac{c}{d}=\dfrac{ad+bc}{bd}[/tex]

If the denominators have a common factor (k), then this can be reduced to ...

  [tex]\dfrac{a}{bk}+\dfrac{c}{dk}=\dfrac{ad+bc}{bdk}[/tex]

The product bdk is the least common denominator when k is the greatest common factor.

Here, the numerators have a common factor, so we can factor that out, perform the sum, then multiply the result by that numerator factor.

c

  [tex]\dfrac{\sqrt{2}}{5}-\dfrac{\sqrt{2}}{6}=\sqrt{2}\left(\dfrac{1}{5}-\dfrac{1}{6}\right)=\sqrt{2}\cdot\dfrac{6-5}{5\cdot6}=\boxed{\dfrac{\sqrt{2}}{30}}[/tex]

f

  [tex]\dfrac{3\sqrt{3}}{7}+\dfrac{\sqrt{3}}{2}=\sqrt{3}\left(\dfrac{3}{7}+\dfrac{1}{2}\right)=\sqrt{3}\cdot\dfrac{3\cdot2+7}{7\cdot2}=\boxed{\dfrac{13\sqrt{3}}{14}}[/tex]

i

The denominators have a common factor of 2: 6=3·2, 8=4·2.

  [tex]\dfrac{-5\sqrt{10}}{6}+\dfrac{3\sqrt{10}}{8}=\sqrt{10}\left(\dfrac{-5}{6}+\dfrac{3}{8}\right)=\sqrt{10}\cdot\dfrac{-5\cdot4+3\cdot3}{3\cdot4\cdot2}=\boxed{-\dfrac{11\sqrt{10}}{24}}[/tex]

Write a story that could represent this math problem. (2 points)

Answers

If John has 3 of 4 slices of pie, and Tom has 2 of 6 slices of pie, how many do they have all together?

I believe that is what type of story you needed, if wrong let me know.

Answer: Suppose Rita is trying to find the area of the carpet of 3/4 and 2/6 for a room of 4/4 sq to 6/6 sq with balcony of 1/4 and 4/6

Explanation: In the given rectangle fig. length is given 3/4 and breadth is given 2/6 for the whole rectangle is 4/4 to 6/6.

for each block length is given 1/4 and breadth is given 1/6. The darker shaded area represents the carpet of the above story.

The answer after multiplying it is 6/24 or 1/4.  

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Which descriptions from the list below accurately describe the relationship
between AXYZ and AUVW? Check all that apply.
857-10
LSM
X62
16
37
← PREVIOUS
20
53M
12 W
A. Same size
B. Same shape
C. Similar
D. Congruent
SUBMIT

Answers

The same shape and similar are relationship between ΔXYZ and ΔUVW options (A) and (D) are correct.

What is the similarity law for triangles?

It is defined as the law to prove that two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the complementary angles are congruent.

We have given two triangles with dimensions.

Take the ratio of the corresponding sides:

12/24 = 5/10 = 13/26 = 1/2

The ratios of the corresponding sides are same which means the triangle are similar and having same shape.

Hence, the same shape and similar are relationship between ΔXYZ and ΔUVW option (A) and (D) are correct.

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The complete question is in the attached image.

Yang Bai is investing $10,000 and wants a portfolio that is 80% stocks and 20% bonds. She has decided to accomplish this using just 2 exchange-traded funds (ETFs): a stock ETF trading for $50 per share and a bond ETF trading for $100 for share. What should she do to meet her asset allocation goal?

Answers

In order to meet her asset allocation goal of 80% stocks and 20% bonds, Yang Bai should purchase 800 shares of the stock ETF ($50 per share) and 200 shares of the bond ETF ($100 per share). This will give her a total of $40,000 worth of stocks and $20,000 worth of bonds, which adds up to the $60,000 she is investing.

One cubic foot holds 7.48 gallons of​ water, and 1 gallon of water weighs 8.33 pounds. How much does 4.3 cubic feet of water weigh in​ pounds? In​ tons?

Answers

Answer:

268 pounds

Step-by-step explanation:

Two unit multipliers to be used for this unit conversion:

[tex]\frac{7.48 gallons}{1ft^{3}}[/tex] and [tex]\frac{8.33 pounds}{1 gallon}[/tex]


4.3 cubic feet = [tex](4.3ft^{3})[/tex]×[tex](\frac{7.48 gallons}{1ft^{3}})[/tex] ×[tex](\frac{8.33 pounds}{1ft^{3}})[/tex]

                     
The cubic feet units in the numerator and denominator will cancel each other out. The gallons units in the numerator and denominator will cancel each other out.
             = 268  pounds of water (Rounded to 3 significant figures)

A bank is offering 2.5% simple interest on a savings account. If you deposit $5000, how much interest will you earn in 4 years?
• $50,000
• $500
• $125
• $12,500

Answers

[tex] \large \blue{ \large\tt{C ) \$500}}[/tex]

_____________

[tex] \: [/tex]

Given:-

[tex] \rm{Principal= \bold {5000}}[/tex]

[tex] \rm{Time= \bold 4}[/tex]

[tex] \rm{Intrest Rate= \bold { 2.5}}[/tex]

[tex] \: [/tex]

By using formula:-

[tex] \boxed{ \rm{ \pink{Simple \: interest= \frac{Principal × Time × Rate}{100}}}}[/tex]

[tex] \: [/tex]

Solution:-

[tex] \rm{SI = \frac{PTR}{100} }[/tex]

[tex] \: [/tex]

[tex] \rm{SI= \frac{50 \cancel{00}×4×2.5}{1 \cancel{00}} }[/tex]

[tex] \: [/tex]

[tex] \rm{SI=50×4×2.5}[/tex]

[tex] \: [/tex]

[tex] \underline{\boxed{ \rm{ \red{SI= 500}}}}[/tex]

[tex] \: [/tex]

hope it helps!:)

Answer: the answer is c.$500 hope that helps !

Step-by-step explanation: I took the test

Convert 1,2kg to g to two decimal places where applicable

Answers

Answer: 1200g

Step-by-step explanation:

1 kilogram is equal to 1000 grams, so since you want 1.2, simply multiply by that quantity. So the answer is 1200 grams.

Find the total area of the shaded region. Ay 1.5- 14 x=5y3 (5,1) * = 5y? 0.5- х 07 0 2.5 5 7.5 Find the area of the region enclosed by the curves x= x = 7y?, x=0, and y=1. The area of the region enclosed by the curves is (Type a simplified fraction.)

Answers

The total area of the shaded region for the region x = 5y³ , x = 5y² in the interval ( 5, 1 ) is equal to ( 5 / 12 ).

From the attached graph :

The area of the shaded region :

x = 5y³ , x = 5y² for the interval ( 5, 1 ) is equal to :

= [tex]\int\limits^1_0 {( 5y^{2 } - 5y^{3 }}) \, dy[/tex]

=  [ ( 5y³/3 ) - ( 5y⁴ / 4 ) ][tex]| \limits^1_0[/tex]

Substitute the lower limit and upper limit we get,

= (5 /3 )( 1 )³ - 0  - ( 5 / 4 )( 1⁴) + 0

= ( 5 / 3 ) - ( 5 / 4 )

= ( 20 - 15 ) / 12

= 5 / 12

Therefore, the total area of the shaded region in the given graph for the lower and upper limit is equal to ( 5 / 12 ) .

The given question is incomplete, I answer the question in general according to my knowledge:

Find the total area of the shaded region x = 5y³ , x = 5y² for the interval

( 5, 1 ).

Graph is attached.

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Over the last 3 evenings, Laura received a total of 68 phone calls at the call center. The third evening, she received 2 times as many calls as the first evening. The first evening, she received 8 more calls than the second evening. How many phone calls did she receive each evening?

Answers

On first evening she receives 19 calls and on second evening  she receives 11 calls while on 3rd evening she receives 38 calls.

What is equation?

A mathematical equation is a fοrmula that joins two statements and uses the equal symbol (=) tο indicate equality. A mathematical statement that establishes the equality of twο mathematical expressions is knοwn as an equation in algebra. Fοr instance, in the equatiοn 3x + 5 = 14, the equal sign places the variables 3x + 5 and 14 apart. The relationship between the twο sentences oοn either side of a letter is described by a mathematical formula. Often, there is οnly one variable, which alsο serves as the symbol, fοr instance, 2x – 4 = 2.

X, Y, and Z represents the 1st , 2nd, and 3rd evenings

X + Y + Z = 68

⇒ X = Y + 8

⇒ Z = 2(Y + 8)

⇒ Y + Y + 8 + 2(Y + 8) = 68

Y = 11 calls

And

X = (11)+ 8 = 19 calls

Z = 2((11) + 8) = 38 calls

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2. Sam spent $15 at an art store on paints, brushes, and paper. The paints cost $7.75 and the
brushes cost $3. Write and solve an equation you could use to find how much Sam spent on
paper.

Answers

subtract the variables from the original number and you’ll be left with the remaining number AKA the cost of paper
15
-7.75
-3
=4.25

In the diagram, RSTU~ ABCD. Find the ratio of their perimeters.
U
R
18 S
36
T
D
A
24
The ratio of their perimeters is
B
C

Answers

Answer: Let's call the ratio of the perimeters of the two similar figures "k". That means that for every unit of length in RSTU, there are k units of length in ABCD.

Since UR = 18 and DA = 24, k = 24/18 = 4/3.

So for every length in RSTU, there are 4/3 times that length in ABCD. We can use this ratio to find the corresponding lengths in ABCD. For example, SR = 36, so BS = 36 * (4/3) = 48.

Now that we have the lengths of all sides of ABCD, we can find its perimeter:

Perimeter of ABCD = 24 + 48 + BC + 24 = 120 + BC

Perimeter of RSTU = 18 + 36 + 18 + 36 = 108

So the ratio of their perimeters is:

Perimeter of ABCD / Perimeter of RSTU = (120 + BC) / 108 = (120 / 108) + (BC / 108) = 20/18 + BC/108

Since the perimeters of the two figures are similar, the ratio of their perimeters is equal to the ratio of their corresponding side lengths:

20/18 + BC/108 = 4/3

Solving for BC:

BC = (4/3 - 20/18) * 108 = 36

Step-by-step explanation:

Kara earns 9.75 per hour plus 15.50 in tips each night. If she works for 5 2/5 hours four nights this week how much money will she earn

Answers

Answer: $272.60

Step-by-step explanation:

9.75x5.4= 52.65

52.65+15.50=68.15

68.15x4=272.6

What is the location of point G, which partitions the directed line segment from F to D into an 8:5 ratio?

A number line goes from negative 5 to 10. Point D is at negative 4 and point F is at 9. A line is drawn from point D to point F.

Answers

The position of G in the given line segment is at point 1, which is between points F and D and the line segment between F and D in the ratio 8:5.

What is meant by line segment?

Two unique points on a line define the boundaries of a line segment. A line segment is a section of the path a line takes to join two locations. The difference between a line and a line segment is that a line has no endpoints and can go on forever in either direction.

Given, the locations of D  and F on the line segment.

D = -4

F = 9

Number of units between F and D = 9 - (-4) = 13

Point G partitions the line segment from F to D in the ratio 8:5.

So distance of G from F = [8/(8+5)] * 13 = 8

Distance of G from D =  [5/(8+5)] * 13 = 5

So from F, it is 8 units behind F = 9 - 8 = 1

from D, it is 5 units in front of D = -4 + 5 = 1

Therefore the position of G in the given line segment is at point 1.

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Which of the following tables of x- and y-values represents a function?

Answers

The tables of x- and y-values that represents a function include the following: C. table C.

What is a function?

In Mathematics, a function is a mathematical expression which is typically used for defining and representing the relationship that exists between two or more variables such as an ordered pair in tables or relations.

This ultimately implies that, a function is typically used in mathematics for uniquely mapping an input variable (domain) to an output variable (range) representing a given scenario or situation such as the following:

x  1   3   7   5   2  4

y  6  6   6   6   6  6

In conclusion, we can reasonably infer and logically deduce that only table C represent a function.

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I need the first one

Answers

Answer:

∠1 = ∠2 = 135

Step-by-step explanation:

We know that the sum of the interior angles of a polygon of n sides = (n – 2) × 180° = 3 x 180°= 540°. Hence, the sum of interior angles of a pentagon is 540°.

so ∠1 + ∠2 + 3(90°) = 540°

since ∠1 = ∠2

∠1 + ∠1 + 3(90) = 540

2∠1 + 270 = 540

2∠1 = 540 - 270

2∠1 = 270

∠1 = 270/2 = 135

As modeled, a movie is projected into a large outdoor screen. The bottom of the 60 foot-tall

Answers

Answer:

-

Step-by-step explanation:

the question isn't clear enough to answer it

There are 15 students in an art class. Mr Popplewell has 300 colored pencils to distribute equally among the students. How many colored pencils will each student receive?

Answers

Answer:

Step-by-step explanation:

15 into 300 is 20

300÷ 15 = 20

Find the volume to each equation
(Directions listed above questions)

Answers

The volume of the cube  is 444.19 in³

The volume of the rectangular prism is 661.2 ft³

The volume of the triangular prism is 30.04 yd³

The volume of the cylinder is 380.57 km³

How to find the volume

Volume of a cube is solved using the formula

= length³

= 7.63³

= 444.19 in³

Volume of a rectangular prism is solved using the formula

= Area of base * height

= 9.5 * 8.7 * 8

= 661.2 ft³

Volume of a triangular prism is solved using the formula

= 1/2 × base × height × length

= 1/2 * 5.84 * 3.08 * 3.34

= 30.04 yd³

Volume of a cylinder is solved using the formula

= π * radius² * height

= π * 3² * 13.46

= 380.57 km³

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1. Items a company has purchased and paid for, but has not used are called

A. advanced
B.purchased
C.prepaid
D. long-term liability
items.

Answers

Items a company purchased and paid for but has not used is called a A. Advanced

Answer:

the ans is advanced

I hope you get your ans

a toy manufacturer needs a piece of plastic in the shape of a right triangle with one leg 5 cm longer than the other and the hypotenuse 10 cm longer than the shorter leg. what is the perimeter of the triangle

Answers

The triangle's perimeter is roughly 25.29 cm.

In arithmetic, what is perimeter?

The area around a form's edge is known as its perimeter. The perimeter of various forms can be calculated by summing the lengths of their sides.

Let's call the right triangle's shorter leg "x" for short.

The longer leg is then 5 cm longer than x, or x + 5, according to the situation.

The hypotenuse measures x + 10 cm longer than x.

By the Pythagorean theorem, we know that:

x² + (x+5)² = (x+10)²

Expanding and simplifying this equation gives:

2x² + 10x - 75 = 0

Dividing both sides by 2 gives:

x² + 5x - 37.5 = 0

We can find the value of x by using the quadratic formula:

x = (-5 ± sqrt(5² - 4(1)(-37.5))) / 2

x = (-5 ± sqrt(175)) / 2

x ≈ -8.68 or x ≈ 3.43

Since x represents a length, we must choose the positive solution x = 3.43 cm.

Therefore, the shorter leg of the triangle is 3.43 cm, the longer leg is 8.43 cm (3.43 + 5), and the hypotenuse is 13.43 cm (3.43 + 10). The perimeter of the triangle is the sum of the three sides, which is:

3.43 + 8.43 + 13.43 = 25.29 cm

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Find the volume V of the solid obtained by rotating the region bounded by the graphs of the given expressions about the specified line. y2 = x, x = 3y; about the y-axis V=

Answers

The volume, V of the solid obtained by rotating the region bounded by the graphs of the expressions, y² = x, x = 3y; about the y-axis is equals to the 162π/5 cubic units.

We have a region bounded by the graphs of two expressions. These expressios are y² = x, x = 3y. We have to calculate the volume of solid obtained by rotating the bounded region about the y-axis. First determine the intersection points of

y² = x, x = 3y.

=> x = 3y --(1)

=> y² = 3y

=> y² - 3y = 0

=> y( y - 3 ) = 0

=> y = 0 or y - 3 = 0

=> y = 0 , y = 3

from (1), x = 3y => x = 0, x = 9

Let the intersection points be O(0,0) and P(3,9). Now, the volume of rotating region or due to shaded region is

[tex]V = π\int_{0}^{3} (R² - r²) dy [/tex]

where R = 3y , r = y²

[tex]V = π\int_{0}^{3} [(3y)² - (y²)²]dy [/tex]

[tex]V = π \int_{0}^{3} (9y² - y⁴)dy [/tex]

[tex]V = π[ \frac{9y³}{3}- \frac{y⁵}{5} ]_{0}^{3} [/tex]

[tex]V = π[ \frac{9(3)³}{3}- \frac{{3}^{5} }{5} - 0- 0 ][/tex]

[tex]V = π(81 - \frac{243}{5} ) = \frac{162π}{5} [/tex]

Hence, the required volume is 162π/5 cubic units.

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need help looking for the anwser

Answers

Answer:

need help looking for the anwser here it's the 2.5

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