1. The range of the given function y = 3x² for the given domain: {- 2, - 1, and 0} is {12, 3, 0}.
2. The range of the given function y = 8x + 1, where x > 2 is (17, ∞).
3. The range of the given function y = 5x + 2, where x > -2 is (- 8, ∞).
We know that the range of a function is the entire set of all possible values for the dependent variable (typically y), after substituting the domain.
1. For the function y = 3x²,
Here the domain is {- 2, - 1, and 0}. So, we have to find the y values for the x values - 2, - 1, and 0 to find the range of the function.
Now, at x = - 2,
y = 3(- 2)² = 3 × 4 = 12
At x = - 1,
y = 3(- 1)² = 3 × 1 = 3
At x = 0,
y = 3(0)² = 3 × 0 = 0
So, the range of this function is {12, 3, 0}.
2. Now, for the function y = 8x + 1,
At x = 2,
y = 8 × 2 + 1 = 16 + 1 = 17
Since the domain is x > 2, we can say that the range set will contain values greater than 17.
So, the range of this function is (17, ∞).
3. For the function y = 5x + 2,
Now, at x = - 2,
y = 5 × (- 2) + 2 = - 10 + 2 = - 8
Since the domain is x > - 2, we can say that the range set will contain values greater than - 8.
So, the range of this function is (-8, ∞).
1. Therefore, the range of the given function y = 3x² for the given domain: {- 2, - 1, and 0} is {12, 3, 0}.
2. The range of the given function y = 8x + 1, where x > 2 is (17, ∞).
3. The range of the given function y = 5x + 2, where x > -2 is (- 8, ∞).
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HELP HELP HELP HELP
HELP HELP HELP HELP
HELP HELP HELP HELP
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Step-by-step explanation:
just breathe and read it carefully. no need for panic. all you need is common sense, nothing fancy.
the tools and definitions to use are given in the description. we only need to use them.
the height of the point of view is 44 + 6 = 50 ft (because the eyes are again 6 ft above the top of the hill, and we are dealing with what the eyes can see).
so, the seeable distance D in miles is then
D = sqrt(2×50) = sqrt(100) = 10 miles
she will be able to see approximately 10 miles to the horizon.
can someone please help me with this problem?
q(t)= Q_0 e^-kt where Q represents the quantity remaining after t years and k is the decay constant 0.00043. How long will it take for 500g of radium to decay to 5g?
It takes 16,064 years for the 500g of radium to decay to 5g.
How long will it take for 500g of radium to decay to 5g?
Here we have the decay equation:
[tex]Q(t) = Q_0*e^{-k*t}[/tex]
Where Q₀ is the initial amount, and k is the decay constant.
We know that:
Q₀ = 500g
k = 0.00043
And we want to find the value of t such that Q(t) = 5g, so we need to solve:
[tex]5 = 500*e^{-0.00043*t}\\\\5/500 = e^{-0.00043*t}\\\\0.001 = e^{-0.00043*t}[/tex]
Now we can apply the natural logarithm in both sides:
[tex]ln(0.001) = ln(e^{-0.00043*t})\\\\ln(0.001) = -0.00043*t\\\\\frac{ln(0.001)}{-0.00043} = t = 16,064.5[/tex]
So it takes 16,064 years for the 500g of radium to decay to 5g.
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What are the domain and range of an exponential parent function?
Help please
The domain and the range of an exponential parent function, that is, y = eˣ are equal to all real numbers and non-negative numbers, respectively. (Correct choice: C)
How to determine the domain and range of an exponential function
In this problem we should determine what an exponential parent function is. The most common exponential functions have the following form:
[tex]y = A\cdot e^{B\cdot x} + C[/tex] (1)
(1) is an exponential parent function for A = 1, B = 1 and C = 0.
All functions are relations with a domain and range, the domain is an input set related to the range, that is, an output set. In the case of an exponential parent function, the domain and the range of the expression are [tex]\mathbb{R}[/tex] and y ≥ 0, respectively. (Correct choice: C)
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A graph is shown below
what is the equation of the line in slope intercept form HELP ASAP
Answer:
y = -2x + 16
the y intercept is the y value at x = 0. On the graph there is a dot at 16 on x= 0, so the y intercept would be 16.
the only answer choice adding 16 sis y = -2x + 16
Round the number to the nearest ten-thousands:
388,725
a. 400,000
b.390,000
c. 388,800
d. 389,000
Answer:
B is the correct answer
Step-by-Step:
Weiming receives a weekly pocket money of $28. If he decides to save 20% of it, find his saving in a year and spendings in a year
Welming's spending is $1164.8 and his savings is $291.2
How to determine the savings and the spending?The given parameters are:
Weekly pocket = $28
Save = 20%
There are 52 weeks in a year.
So, the yearly pocket is:
Yearly pocket = $28 * 52
Evaluate
Yearly pocket = $1456
He saves 20%.
So, we have:
Savings = 20% * $1456
Evaluate
Savings = $291.2
His spending is then calculated as:
Spending = $1456 - $291.2
Evaluate
Spending = $1164.8
Hence, Welming's spending is $1164.8 and his savings is $291.2
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Which of the following could be the equation of the function below?
y = -3 sin (2 (x + pi)) + 2
y = -3 sine (x + pi) + 2
y = 3 sin (4 (x - pi)) + 4
y = 3 sin (2 (x + pi)) + 2
The equation of the sine function will be y = -3 sin [2(x + π)] + 2. Then the correct option is A.
What is a sinusoidal Function?It is a function that repeats itself in a particular time interval.
The equation is given as
y = A sin (ωx + Ф) + C
Where A is the amplitude, ω is the frequency, Ф is the phase difference, and C is the constant.
From the graph, we have
A = -3
ω = 2
Ф = 2π
C = 2
Then we have the equation will be
y = -3 sin [2(x + π)] + 2
Then the correct option is A.
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Write the equation of the line in slope-intercept form Slope=5/3 Y-Intercept=4
Answer:
y=5/3x+4
Step-by-step explanation:
Slope intercept formula: y=mx+b
m=slope
b=Y-Intercept
Answer:
[tex]\sf y=\dfrac{5}{3}x+4[/tex]
Step-by-step explanation:
Given:
[tex]\textsf{slope of $\dfrac{5}{3}$, and a y-intercept of $4$}[/tex]
⇒ Slope-Intercept Form: y = mx + b
where:
m is the slopeb is the y-intercept (when x = 0)Substitute the given values:
[tex]\sf\\ \implies y=mx+b\\\\\implies y=\dfrac{5}{3}x+4[/tex]
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PLEASE HELP PLEASEEEE!! 100 PTS!
Answer:
R
H
S
= cos
2
x
Step-by-step explanation:
Hope this helped!
AD and CD are tangents to the circle below
Calculate the size of angle 0
Answer: [tex]59^{\circ}[/tex]
Step-by-step explanation:
In triangle ABC, we know that [tex]\angle ABC=130^{\circ}-\theta[/tex]. So, by the inscribed angle theorem, minor arc AC is equal to [tex]260^{\circ}-2\theta[/tex].
Thus, major arc AC is equal to [tex]100^{\circ}+2\theta[/tex].
Using the fact that the angle formed by the two tangents is 38 degrees,
[tex]\frac{(100^{\circ}+2\theta)-(260^{\circ}-2\theta)}{2}=38^{\circ}\\\\100^{\circ}+2\theta-260^{\circ}+2\theta=76^{\circ}\\\\4\theta-160^{\circ}=76^{\circ}\\\\4\theta=236^{\circ}\\\\\theta=\boxed{59^{\circ}}[/tex]
In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then do the calculation.
How many ways are there to distribute 8 different books among 21 children if no child gets more than one book?
a.) Combination; Subscript 13 Baseline C Subscript 8 Baseline = 1287
b.) Combination; Subscript 21 Baseline C Subscript 8 Baseline = 203,490
c.) Permutation; Subscript 21 Baseline P Subscript 8 Baseline = 8,204,716,800
d.) Permutation; Subscript 13 Baseline P Subscript 8 Baseline = 51,891,840
Using the permutation formula, it is found that the number of ways to distribute the books is given by:
c. 8,204,716,800
The order is important, as the books are different, hence the permutation formula is used to solve this question.
What is the permutation formula?The number of possible permutations of x elements from a set of n elements is given by:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
In this problem, 8 books are distributed among 21 children, hence the number of ways is given by:
[tex]P_{21,8} = \frac{21!}{13!} = 8,204,716,800[/tex]
Which means that option c is correct.
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What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12
Answer:
x≥20
Step-by-step explanation:
-3(6-2x)≥4x+12
or, -18+6x≥4x+12
or, -18-12≥4x-6x
or, -40≥-2x
or, -40/2≥-x
or, -20≥-x
or, 20≥x
= x≥20
What are the domain and range of the function represented by the set of
ordered pairs?
{(-7, 1), (-3, 2), (0, -2), (5,5)}
Answer:
see explanation
Step-by-step explanation:
the domain is the set of x- coordinates from the ordered pairs , that is
domain : { - 7, - 3, 0, 5 }
the range is the set of y- coordinates from the ordered pairs, that is
range : { - 2, 1, 2, 5 }
In a certain region of space, the potential is given by v=2x−5x2y 3yz2. How much is the magnitude of the electric field at point (-2, 2, 0)?
The magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m
How to calculate the electric field?Since in a certain region of space, the potential is given by v = 2x − 5x²y 3yz²,
The electric field, E = -grad(V) where grad(V) = (dV/dx)i + (dV/dy)j + (dV/dz)k
Since V = 2x − 5x²y + 3yz²
dV/dx = d(2x − 5x²y + 3yz²)/dx
= d2x/dx - d5x²y/dx + d3yz²/dx
= 2 - 10xy + 0
= 2 - 10xy
dV/dy = d(2x − 5x²y + 3yz²)/dy
= d2x/dy - d5x²y/dy + d3yz²/dy
= 0 - 5x² + 3z²
= - 5x² + 3z²
dV/dz = d(2x − 5x²y + 3yz²)/dz
= d2x/dz - d5x²y/dz + d3yz²/dz
= 0 - 0 + 6z
= 6z
The electric field
So, E = -grad(V)
= -[(dV/dx)i + (dV/dy)j + (dV/dz)k]
= -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]
So, the electric field at (-2, 2, 0) is
E = -[(2 - 10xy)i + (- 5x² + 3z²)j + (6z)k]
E = -[(2 - 10(-2)(2))i + (- 5(2)² + 3(0)²)j + (6(0))k]
E = -[(2 + 40)i + (- 5(4) + 0)j + (0)k]
E = -[42i + (-20 + 0)j + (0)k]
E = -[42i - 20j + 0k]
E = -42i + 20j - 0k
The magnitude of the electric field
So, the magnitude of E at (-2, 2, 0) is
|E| = √[(-42)² + 20² + 0²]
= √[1764 + 400 + 0]
= √2164
= 46.52 V/m
So, the magnitude of the electric field at the point (-2, 2, 0) is 46.52 V/m
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A road is 450 metres long . It takes a woman 5 minutes to walk along the road . Work out the average speed of the woman . Give your answer in metres per second .
A point P is 45km from Q in a bearing of 75⁰ how far is P north of Q
Answer:
11.65
Step-by-step explanation:
45 cos 75 (in degrees not radians) =
11.6468570296
jiskha
raka
Match the function with the graph.
a. y = |x+ 5|
b. y= |x-5| + 2
c. y= |x-5|
d. y=|x| -5
i did a and it was wrong. i don’t understand lol please help
C. y= |x-5|
you have the right idea, it's being shifted horizontally so the shift would be shown inside of the brackets. However, it would be |x-5| not |x+5| because the graph is shifting to the right.
6 numbers that have a median of 8 a mean of 9 and a range of 13?
Answer:
5,6,8,8,9,18
Step-by-step explanation:
...................
7. Miguel draws a square on a coordinate plane. One vertex is located at (5, 4). The
length of each side is 3 units. Circle the letter by all the ordered pairs that could be
another vertex.
A. (5, 1)
B. (5, 7)
C. (7, 8)
D. (2, 6)
E. (2, 1)
Answer:
A, B and E
Step-by-step explanation:
Answer: A,B and E i did the test
Step-by-step explanation:
Let (-7, 2) be a point on the terminal side of 0.
Find the exact values of sin0, sec 0, and tan 0.
By applying the definitions of trigonometric functions, the exact values of the sine, secant and tangent of the point on the terminal side are [tex]\sin \theta = \frac{2}{\sqrt{53}}[/tex], [tex]\sec \theta = -\frac{\sqrt{53}}{7}[/tex] and [tex]\tan \theta = -\frac{2}{7}[/tex].
How to determine the exact values
In this question we need to find the exact values of three trigonometric functions associated with the terminal side of an angle. The following definitions are used:
Sine
[tex]\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}[/tex] (1)
Secant
[tex]\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}[/tex] (2)
Tangent
[tex]\tan \theta = \frac{y}{x}[/tex] (3)
If we know that x = - 7 and y = 2, then the exact values of the three trigonometric functions:
Sine
[tex]\sin \theta = \frac{2}{\sqrt{53}}[/tex]
Secant
[tex]\sec \theta = -\frac{\sqrt{53}}{7}[/tex]
Tangent
[tex]\tan \theta = -\frac{2}{7}[/tex]
By applying the definitions of trigonometric functions, the exact values of the sine, secant and tangent of the point on the terminal side are [tex]\sin \theta = \frac{2}{\sqrt{53}}[/tex], [tex]\sec \theta = -\frac{\sqrt{53}}{7}[/tex] and [tex]\tan \theta = -\frac{2}{7}[/tex].
Remark
The statement reports typing errors, correct form is shown below:
Let (x, y) = (- 7, 2) be a point on the terminal side of θ. Find the exact value of sin θ, sec θ and tan θ.
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Select the correct answer. The function g(x) = x2 is transformed to obtain function h: h(x) = g(x) − 5. Which statement describes how the graph of h is different from the graph of g? A. The graph of h is the graph of g vertically shifted up 5 units. B. The graph of h is the graph of g horizontally shifted left 5 units. C. The graph of h is the graph of g vertically shifted down 5 units. D. The graph of h is the graph of g horizontally shifted right 5 units.
The graph of h(x) is the graph of g vertically shifted down 5 units. Then the correct option is C.
What is a function?Functions are found all across mathematics and are required for the creation of complex relationships.
The function g(x) = x² is transformed to obtain function h:
h(x) = g(x) − 5
h(x) = x² − 5
The graph h(x) get shifted downward by 5 units.
Then the correct option is C.
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Triangle is reflected across the y-axis and then dilated by a factor of centered at the origin. Which statement correctly describes the resulting image, triangle ? Image of right triangle ABC in a graph with vertices A (minus 4, minus 2), B (4, minus 2), and C (4, 4) A. Both the reflection and dilation preserve the side lengths and angles of triangle . B. The reflection preserves the side lengths and angles of triangle . The dilation preserves angles but not side lengths. C. The dilation preserves the side lengths and angles of triangle . The reflection does not preserve side lengths and angles. D. Neither the reflection nor the dilation preserves the side lengths and angles of triangle .
Answer: B. The reflection preserves the side lengths and angles of the triangle. The dilation preserves angles but not side lengths.
Step-by-step explanation:
Reflections are congruency transformations, but dilations are similarity transformations.
If f(x) = 2x² + 3x and g(x) = x - 2, what is (f+ g)(2) ?
[tex](f+g)(x)=f(x)+g(x)\\\\f(x)=2x^2+3x\\g(x)=x-2\\\\(f+g)(2)=2\cdot2^2+3\cdot2+2-2=8+6=14[/tex]
Jamie is walking her neighbors’ dog while they are away. She is keeping track of the total number of blocks she walks over time.
A 2-column table with 3 rows. Column 1 is labeled Minutes with entries 6, 14, 20. Column 2 is labeled Blocks with entries 3, 7, 10.
Does the table represent a proportional relationship?
Yes, because both columns are written in ascending order.
Yes, because the values in the second column are less than the values in the first column.
Yes, because the ratios are equivalent between each pair of values.
No, because the values in the table do not increase by the same amount in each row.
Answer:
Yes, the relation is proportional because the ratios are equivalent between each pair of values
Step-by-step explanation:
Proportional relationships are relationships with equal ratios.
Entries in the respective columns are:
column 1 (Minutes) column 2 (Blocks) Ratios
6 3 1/2
14 7 1/2
20 10 1/2
As the ratio of Blocks and Minutes is same for every row,
the given table represent a proportional relationship.
hence, option c is correct.
Yes, because the ratios are equivalent between each pair of values.
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Answer: Yes, the relation is proportional because the ratios are equivalent between each pair of values :)
Which expression is equivalent to √48x5, if x>0?
OA. 12x³√3x
OB. 4x³√3
OC. 4x²√3x
D. 12x²√x
Answer: C
Step-by-step explanation:
[tex]\sqrt{48x^{5}}=\sqrt{16x^{4}}\sqrt{3x}=\boxed{4x^{2}\sqrt{3x}}[/tex]
How many cubes are needed to build this figure?
4
6
5
3
Answer:
3
Step-by-step explanation:
because I sense three and You need
A river flows at 2m/s. Juan’s boat can travel twice as fast down the river as it can go up the river. How fast can the boat go in still water?
Answer: 2m/s
Step-by-step explanation:
The boat goes twice as fast down the river, which means it goes twice as slow up the river.
Because the river flows at 2m/s, I think the answer is 2m/s
evaluate 2x^2-1 when x=3
[tex] \sf{\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Let's evaluate ~
[tex]\qquad \sf \dashrightarrow \: 2 {x}^{2} - 1[/tex]
plug in the value of x :
[tex]\qquad \sf \dashrightarrow \: 2(3) {}^{2} - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 2(9) - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 18 - 1[/tex]
[tex]\qquad \sf \dashrightarrow \: 17[/tex]
The required value is 17
-------------------------------------------------------------------------------------------------------------
Answer: [tex]\textsf{Option B, 17}[/tex]
-------------------------------------------------------------------------------------------------------------
Given: [tex]\textsf{2x}^2\textsf{ - 1}[/tex]
Find: [tex]\textsf{When x = 3}[/tex]
Solution: In order to find the value when x is equal to 3 we just need to equate any x to the value of 3 and simplify.
Plug in the values
[tex]\textsf{2x}^2\textsf{ - 1}[/tex][tex]\textsf{2(3)}^2\textsf{ - 1}[/tex]Simplify the expression
[tex]\textsf{2(3 * 3) - 1}[/tex][tex]\textsf{2(9) - 1}[/tex][tex]\textsf{18 - 1}[/tex][tex]\textsf{17}[/tex]Therefore, the answer that would make most sense would be option B, 17.
What is the length of the hypotenuse? If necessary, round to the nearest tenth.
By the Pythagorean theorem,
[tex]a^{2}+12^{2}=13^{2}\\\\a^{2}+144=169\\\\a^{2}=25\\ \\ a=\boxed{5}[/tex]
