*1. The internal energy with a system associated with the motion of particles and that can be added to a substance is called_____.


A. Thermal energy


B. Electrostatic forces


C. Temperature


D. Kinetic energy


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*2. Which statement describes the effect of adding more energy to a system, assuming a phase change does not occur?


A. The particles within the system will have greater motion, and the temperature will decrease.


B. The particles within the system will have greater motion, and the temperature will increase.


C. The particles within the system will have less motion, and the temperature will increase.


D. The particles within the system will have less motion, and the temperature will decrease.


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*3. Which statement correctly describes how attractions that hold particles break?


A. Attractions due to electrostatic forces. When particles have low enough energy, these forces can no longer keep particles together.


B. Attractions due to gravitational forces. When particles have low enough energy, these forces can no longer keep particles together.


C. Attractions due to gravitational forces. When particles move fast enough, these forces can no longer keep particles together.


D. Attractions due to electrostatic forces. When particles move fast enough, these forces can no longer keep particles together.


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*4. Which statement explains why a rubber band analogy is not a perfect comparison for bonds in a substance when considering phase changes?


A. For a phase change from liquid to gas, the bonds break completely and particles can move independently of each other.


B. For a phase change from liquid to gas, the bonds do not break completely and the particles can still slide past each other.


C. For a phase change from solid to liquid, the bonds break completely and particles can move independently of each other.


D. For a phase change from solid to liquid, the bonds do not break completely in the particles can still slide past each other.


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*5. The boiling point of benzene is 80°C. Which pair of samples will have the same average kinetic energy as benzene molecules?


A. Two samples of liquid benzene, one at 70°C in the other at 80°C.


B. A sample of liquid benzene at 70°C and a sample of gaseous benzene at 90°C.


C. Two samples of gaseous benzene, one at 80°C in the other at 90°C.


D. A sample of liquid benzene at 80°C and a sample of gaseous benzene at 80°C.

Iodine is much more easily polarizable than fluorine therefore temporary dipoles in the molecule are strengthened.

The halogens are members of group 17 in the periodic table. They are highly electronegative and seldom occur free in nature owing to their high level of reactivity.

We know that larger molecules are more easily polarized than smaller ones. Therefore, from Fluorine to lodine, the molecular mass increases. The  electron polarizability increases with the mass increase. In turn,  this strengthens the temporary dipole (dispersion) forces  between particles. Hence the properties of halogens change smoothly down the group.

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Answer:one mole of gold

Answer:

HCl (hydrochloric acid) and H2SO4 (sulphuric acid)

I hope it helps.

Answer:

The number by which we divide is called the divisor. The result obtained is called the quotient. The number left over is called the remainder.

Explanation:

Answer:

Explanation:

Firstly, let us calculate the molar mass of the glucose. To find the molar mass we need to add the masses of individual elements which constitute one glucose molecule.

Now, we know that

Molar mass of Carbon C=12gmol−1

Molar mass of Hydrogen H=1gmol−1

Molar mass of oxygen O=16gmol−1

Therefore, Molar Mass of glucose (C6H12O6) can be calculated as shown below

⇒ 6×12+12×1+6×16

⇒72+12+96⇒180gmol−1

Given mass of glucose = 300g

Now, we can calculate the number of moles in given mass of glucose, using the below formula,

Using the Formula numberofmoles=givenmassmolarmass we get

numberofmoles=300180 = 1.7 moles or 2 moles (approx.)

Hence the number of moles present in 300 g of glucose is 1.7 moles or 2 moles approximately.

Answer:

a.2.55e-7

b.6830

Explanation:

Iodine (I) is oxidized, and bromine (Br) is reduced. The correct option is the last option - lodine (I) is oxidized, and bromine (Br) is reduced.

To determine which elements are oxidized and reduced,

First, we will define the terms Oxidation and Reduction

Oxidation is simply defined as the loss of electrons. It can also be defined as increase in oxidation number.

Reduction is defined as the gain of electrons. It can also be defined as decrease in oxidation number.

The given chemical equation is

Br₂(l) + 2NaI(aq) → I₂(s) + 2NaBr(aq)

Oxidation number of Bromine decreased from 0 to -1.

Therefore, Bromine is reduced.

Oxidation number of Iodine increased from -1 to 0.

Therefore, Iodine is oxidized.

Oxidation number of sodium did not change.

Therefore, Sodium is neither oxidized nor reduced.

Hence, Iodine (I) is oxidized, and bromine (Br) is reduced. The correct option is the last option - lodine (I) is oxidized, and bromine (Br) is reduced.

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Answer:  251 K

Explanation: hope this helps :)

Answer:

The process by which food is broken down to release energy is called respiration

I hope it helps.

Answer:

Respiration

Explanation:

hope this helps.

Answer:

The partial pressure of water is much less than 1atm, so the free energy change for the process must be negative with ΔGrxn<0.

Explanation:

Water vapor will condense into liquid water when the water vapor is in its standard state, with a pressure of 1atm. Under normal circumstances, the partial pressure of water vapor is much less that 1atm. It is in a nonstandard state. The free energy change of this reaction has to be negative in order to make the reaction spontaneous.

The criteria of the spontaneous process are the change in the Gibbs free energy should be negative. Above the normal boiling point, the TΔS will be greater than ΔH and ΔG<0.

Gibbs free energy can be described as a state function therefore it doesn’t depend on the path. The change in free energy is equal to the change in enthalpy minus the product of entropy change and temperature of the system.

ΔG = ΔH - Δ (TS)

If the process is carried out at constant temperature, ΔT = 0:

ΔG = ΔH – TΔS

ΔG > 0 for the reaction is non-spontaneous, ΔG < 0 for the reaction is spontaneous, exergonic and ΔG = 0 for the reaction is at equilibrium.

Spontaneous can be described as a reaction that occurs by itself without any external action towards it. The non-spontaneous process needs constant external energy applied to continue and as the external action, the process will cease.

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Answer:

I will give you hints, as follows:

Explanation:

- two words: climate change

- methane smells funny

- the number of electric cars sold each year is increasing

- there´s a reason they´re call "renewable"

- GEOmetry, GEOlogy, GEOthermal

Hope this helps!

Answer:Nothing

Explanation:

The answer is nothing the tempatature isnt matched with the degrees this is false

Answer:

Because oil have apolar molecules, while water have polar molecules

This question is describing the following chemical reaction at equilibrium:

[tex]A\rightleftharpoons B[/tex]

And provides the relative amounts of both A and B at 25 °C and 75 °C, this means the equilibrium expressions and equilibrium constants can be written as:

[tex]K_1=\frac{90\%}{10\%}=9\\\\K_2=\frac{20\%}{80\%} =0.25[/tex]

Thus, by recalling the Van't Hoff's equation, we can write:

[tex]ln(K_2/K_1)=-\frac{\Delta H}{R}(\frac{1}{T_2} -\frac{1}{T_1} )[/tex]

Hence, we solve for the enthalpy change as follows:

[tex]\Delta H=\frac{-R*ln(K_2/K_1)}{(\frac{1}{T_2} -\frac{1}{T_1} ) }[/tex]

Finally, we plug in the numbers to obtain:

[tex]\Delta H=\frac{-8.314\frac{J}{mol*K} *ln(0.25/9)}{[\frac{1}{(75+273.15)K} -\frac{1}{(25+273.15)K} ] } \\\\\\\Delta H=4,785.1\frac{J}{mol}[/tex]

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Answer:

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The rate of a chymotrypsin-catalyzed reaction will increase by using more

enzyme in the reaction mixture.

The rate of a chemical reaction and the enzyme concentration have a direct

relationship. As concentration increases, the rate of a chemical reaction  

also increases and vice versa.

In this scenario, we were told more enzyme was used in the reaction mixture

which signifies an increase in the concentration and a corresponding

increase in the rate of reaction.

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Answer:

12 kilograms is larger.

Explanation:

Of the three units, the kilogram is the largest and the milligram is the smallest. The prefix “kilo” means a thousand and “milli” means one-thousandths. A gram is the basic unit of mass.

3HCl + Al(OH)3 > AlCl3 + 3H20

mol = conc × v

= 0.367 × 0.216

= 0.0792 mol HCl

3 mol HCl = 1 mol Al(OH)3

0.0792 mol HCl = x

x = 0.0792/3 × 1

= 0.0264 mol Al(OH)3

Al(OH)3 = 27 + 3(16 +1) = 78 g/mol

mass = mol x molar mass

= 0.0264 × 78

= 2.0592 g

I don't know if it's correct

Answer:

atom

Explanation:

The sodium atom has a single valence electron that it can easily lose. (If the sodium atom loses its valence electron, it achieves the stable electron configuration of neon.) The chlorine atom has seven valence electrons and can easily gain one electron.

Answer:

KNO2, KBr

Explanation:

Chemical compounds are any substance composed of identical molecules consisting of atoms of two or more chemical elements. So NO2 and KBr are compounds, Br2 and Fe are not.

Answer:

if you drop a water balloon onto the ground, its kinetic energy is converted mostly to thermal energy. If the balloon weighs 1 kilogram and you drop it from about 2 meters, it will heat up by less.

Explanation:

As you say, kinetic energy of large objects can be converted into this thermal energy. For example, if you drop a water balloon onto the ground, its kinetic energy is converted mostly to thermal energy. If the balloon weighs 1 kilogram and you drop it from about 2 meters, it will heat up by less than.

Explanation:

BaF2(s) <------> Ba2+(aq) + 2F-(aq)

Ksp BaF2 =  1.0 x 10^-6.

Ksp BaF2 = [Ba2+(aq)]×[F-(aq)]^2 at equilibrium

When Qsp >Ksp, BaF2 will precipitate

Qsp = [Ba2+(aq)]×[F-(aq)]^2

[Ba2+(aq)]×[F-(aq)]^2 > 1.0 x 10^-6.

0.0122 moldm-3 × [F-(aq)]^2 > 1.0 x 10^-6

[F-(aq)]^2 > 1×10^-6 / 0.0122 mol2dm-6

[F-(aq)]^2 > 81.96 × 10^-6 mol2dm-6

[F- (aq)] > 9.05 × 10^-3 moldm-3

So F- concentration should be more than 9.05 × 10^-3 moldm-3

A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.

A cylindrical weight with a mass (m) of 3 kg is dropped, that is, its initial velocity (u) is 0 m/s and travels 10 m (s). Assuming the acceleration (a) is that of gravity (9.8 m/s²). We can calculate the velocity (v) of the weight in the instant prior to the collision with the piston using the following kinematic equation.

[tex]v^{2} = u^{2} + 2as = 2 (9.8 m/s^{2} ) (10m) \\\\v = 14 m/s[/tex]

The object with a mass of 3 kg collides with the piston at 14 m/s, The kinetic energy (K) of the object at that moment is:

[tex]K = \frac{1}{2} m v^{2} = \frac{1}{2} (3kg) (14m/s)^{2} = 294 J[/tex]

The kinetic energy of the weight is completely converted into heat transferred into the gas cylinder. Thus, Q = 294 J.

Given all the process is at 250 K (T), we can calculate the change of entropy of the gas using the following expression.

[tex]\Delta S_{gas} = \frac{Q}{T} = \frac{294 J}{250K} = 1.18 J/K[/tex]

The change in the entropy of the environment, has the same value but opposite sign than the change in the entropy of the gas. Thus, [tex]\Delta S_{env} = -1.18 J/K[/tex]

A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.

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Answer:

The Nucleus...

it perform many activities and stores DNA in a cell.

Answer:

HowHow many moles of KOH are in 21.0g of KOH?

Answer:

0.374 moles

Explanation:

I have included the dimensional analysis below, and by MM I mean Molar Mass of the atom.

Hope this helps!

Using melting and boiling temperature, hardness and electric current passing testing.

Ionic solids are materials that have a strong bond between their ions, thus producing well-defined shapes.

In addition, due to this strong attraction, the boiling and melting temperatures of these materials are very high, in addition to the resistance to breakage presented by them.

Finally, ionic solids are also excellent conductors of electricity.

So, their properties used to determine whether or not they are ionic solids are  melting and boiling temperature, hardness and electric current passing testing.

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Halogens combine with alkanes to yield halogenoalkanes. It is a chain reaction.

Alkanes are a group of organic molecules whose functional group is the carbon - carbon single bond. The halogenation of alkanes refers to the process by which alkanes reacts with halogen molecules to yield halogenoalkanes.

The following are true statements regarding the halogenation of alkanes;

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The sample of white powder contains 47.1% K2CO3 and 0.39% Na2CO3.

Molar mass of sodium carbonate = 106 g/mol

Molar mass of potassium carbonate = 138 g/mol

Number of moles of HNO3 = 10/1000 L × 0.8903 M = 0.008903 moles

Mass of HNO3 =  0.008903 moles × 63 g/mol = 0.56 g

Mass of sample added = 1.091 g

Mass of sample left over = 0.573 g

Mass of sample reacted = 1.091 g - 0.573 g = 0.518 g

The reacted sample contains xg of Na2CO3 and (0.518 - x) g K2CO3.

Na2CO3 + 2HNO3 --> 2NaNO3 + CO2 + H2O

106g of Na2CO3 reacts with 126g of HNO3

x g of Na2CO3 reacts with (126 × x/106)g of HNO3

K2CO3 + 2HNO3 --> 2KNO3 + CO2 + H2O

138 g of K2CO3 reacts with 126 g of HNO3

(0.518 - x) g of K2CO3 reacts with [(0.518 - x) × 126/138] g

Total mass of HNO3 used;

1.19x + 0.47 + 0.91x = 0.56

2.1x + 0.47 = 0.56

2.1x = 0.56 - 0.47

2.1x = 0.09

x =  0.09/2.1

x = 0.0043 g

Mass of K2CO3 = (0.518 - x) g = 0.518 - 0.0043 = 0.5137 g

Mass percent of K2CO3  = 0.5137 g/ 1.091 g × 100/1 = 47.1%

Mass percent of Na2CO3 = 0.0043/1.091 g × 100/1 = 0.39%

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Answer:

It depends on how much the calories and fat there is in the meals and if you don't get enough physical activity of the same amount of food that you eat it can lead to weight gain

Explanation: