1. What were the concentrations of samples A and B?

2. What are some possible sources of error in a titration experiment? Share some tips to minimize errors with your classmates.

3. What is an example of a problem that can be solved using titration in the real world?

4. Phenolphthalein was used as the indicator in the experiment. The universal indicator exhibits the rainbow of colors for the entire pH range. Do you think using the universal indicateor would also work for this lab? Justify your answer, and explain why you agree or disagree.

That would be...*drumroll* the structure of DNA!

Answer:

they are metals so they are:-

-malleable

-ductile

because metallic bonding is the same in all direction throughout the solid

Answer:

i think the answer is Continental polar air masses

Explanation:

Answer:

C

Explanation:

The higher the period the higher the activity of an element, therefore, since iodine is in period 6 and bromine is in period 5, the described reaction is not possible due to the fact that bromine is less active

The statement that is correct about the emission spectrum of hydrogen in the visible region is that the line corresponding to the greatest emission of energy is in the ultraviolet region.

Hydrogen spectrum is defined as the dissociation of hydrogen atom upon action of electric current into spectral lines that can be seen in that visible light.

These lines falls under the electromagnetic wave of ultraviolet and infrared regions. But the lines of greatest emission is found in the ultraviolet region.

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Answer:

Its a good conductor because its a metal

Answer:

periodic table

Explanation:

in its magnetic properties and chemical activity it resembles iron and cobalt

Red algae and euglena evolved from a symbiotic relationship of organisms, which resulted in eukaryotic organisms containing chloroplasts

Theory of endosymbiosis:

Early eukaryotes developed by the symbiotic connection of prokaryotes, in accordance with the endosymbiosis idea. Which two protists underwent symbiotic evolution, leading to the development of eukaryotic creatures with chloroplasts.

-Symbiotic relationships between two or more prokaryotic cells led to the evolution of the first eukaryotic cells. Greater prokaryotic cells invaded or devoured smaller prokaryotic cells. The connection provided a secure home and nourishment for the tiny cells. By absorbing part of the organic molecules or energy generated by the endosymbionts, the bigger cells (now referred to as hosts) profited.

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The formula of hydrated copper(II) sulfate is CuSO4.10H2O

The formula of the hydrated copper (ii) sulfate is determined as follows:

Mass of hydrated salt = 12.5 g

Mass of anhydrous salt = 8.0 g

Mass of water = 12.5 - 8 = 4.5 g

mole ratio of water and anhydrous salt is;

4.5/18 : 8.0/159.5

0.562 : 0.05

10 : 1

Water of crystallization (n) = 10.

Therefore, the formula of hydrated copper(II) sulfate is CuSO4.10H2O

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Answer:

the answer is c

Explanation:

A carboxylic acid is an organic compound that contains the carboxyl functional group.

Reduction involves the either the addition of hydrogen and removal of oxygen.

Reduction involves the removal of oxygen.

This implies there is a loss of oxygen in reduction.

This can be represented in the extraction of iron from it ores.

Fe₂O₃ + 3CO →  2Fe + 3CO₂

Reduction is also the addition of hydrogen. This implies it is the gain of hydrogen.

For example

CH₃CHO → CH₃CH₂OH

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M₁V₁=M₂V₂

20 x V₁ = 3.5 x 755

V₁ = 132.125 ml

The balanced equation of the reaction is:

A balanced equation is an equation of a reaction in which the moles of atoms of elements in the reaction are equal on both sides of the equation.

The given equation can be balanced as follows:

2 NH₂(g) + O₂(g) → N₂(g) + 2 H₂O(g) + energy

Therefore, the balanced equation of the reaction is the one in which the moles atoms of reacting elements are equal.

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Answer: The molecules will move more quickly.

Explanation:

As temperature increases, the kinetic energy of the particles increases, causing them to move more quickly.

The work of John Lawrence scientist was most essential to the use of radioactive isotopes in medicine.

John Lawrence was the first scientist that use a radioactive isotope in the treatment of a human disease. He became known as the father of nuclear medicine and his laboratory is considered the birthplace of this field.

So we can conclude that the work of John Lawrence scientist was most essential to the use of radioactive isotopes in medicine.

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Answer:

49 moles of atoms

Explanation:

There are 7 individual atoms in each molecule of H2SO4:  (2 hydrogens + 1 sulfur + 4 oxygens).

Therefore, if 7 moles are decomposed, there would be 7 times that amount of individual atoms:

7 x 7 = 49 moles of atoms

The number of moles of aluminum powder needed to produce 203.7 grams of manganese is 5 moles.

Heat, Mn, and Al2O3 are produced when aluminum powder and manganese dioxide are heated.

[tex]3MnO_{2} + 4Al - > 3Mn + 2Al_{2} O_{3} + Heat[/tex]

The balanced chemical equation in this situation indicates that there are 3 moles of manganese and 4 moles of aluminum involved in the reaction, which results in a 3:4 mole ratio.

You may make use of this mole ratio by calculating how many moles of aluminum are required to react with the 203.7g of Manganese. So,

Firstly, the mass of Aluminium has to be taken out

Let the mass be considered x.

So, the number of moles of Aluminium = x/27

Number of moles of Manganese = 203.7/54

Hence, the mass x will be,

[tex]x = 4 *203.7 * 27 / 3 * 54[/tex]

[tex]x = 135.8g[/tex]

Hence,  the number of moles of Aluminium is = 135.8/27 = 5 moles.

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Answer:

Approximately 11460 Years Old

Explanation:

i looked this up :/

way to much maths for me

The age of the bone given that it contains C-14 and N-14 in ratio of 1:3 is 11460 years

C-14 is usually used for radioactive dating (i.e to determine the aga of substance)

From the question, C-14 and N-14 exist in ratio of 1:3.

thus, the amount of C-14 remaining can be obtained as follow:

Percentage of C-14 remaining = 1/4 × 100

Percentage of C-14 remaining = 25%

2ⁿ = N₀ / N

2ⁿ = 100 / 25

2ⁿ = 4

2ⁿ = 2²

n = 2

t = n × t½

t = 2 × 5730

t = 11460 years

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Among the given mediums, Vaccuum is the best thermal insulator to reduce the transfer of thermal energy by radiation as there will be no air particles which carries heat from one place to other. Hence, Option (D) will be the correct option

Heat Radiation refers to the transfer of heat from a hot body to cold body directly, without heating the medium between two bodies.

Vaccum does not have any particles in it. Thus, there will be no transfer of heat through it.

The best example of it is thermous flask in which vaccuum inside thermous flask reduces the transfer of energy through it.

Hence,Among the given mediums, Vaccuum is the best thermal insulator to reduce the transfer of thermal energy by radiation as there will be no air particles which carries heat from one place to other. Thus, Option (D) will be the correct option

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Answer:

they help becuz they dont use any extra power and the are reneable

Answer: 29.2

Explanation:

From the coefficients of the equation, we know that for every 3 moles of hydrogen consumed, 1 mole of nitrogen is consumed.

This means we would need 6.25/3 = 2.0833333333333 mol of nitrogen.

Nitrogen has an atomic mass of 14.007 g/mol, so 2.0833333333333 moles of nitrogen have a mass of (14.007)(2.0833333333333) = 29.2 g (to 3 sf)

Answer: 0 K

Explanation:

This is a fact - absolute zero is defined as 0 degrees Kelvin.

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The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The term electrolysis has to do with the decomposition of a substance by the passage of a direct current through it.

The ions present in the system are[tex]H^+[/tex], [tex]OH^-[/tex] and [tex]NO_3^-[/tex] ions. The gas given off at the cathode is hydrogen while the gas given off at the anode is oxygen.

The half-reaction equation of the reduction is;

[tex]2H^+(aq) + e[/tex] → [tex]H_2(g)[/tex]

The oxidation half-reaction equation is;

[tex]4OH^- (aq)[/tex] → [tex]2H_2O(l) + 4e[/tex]

The overall equation is;

[tex]4H^+(aq) + 4OH^- (aq)[/tex] → [tex]4H_2(g) + 2H_2O(l) + 4e[/tex]

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Answer:

See Below

Explanation:

'an aerobic ' means it does not use oxygen

Answer:

anaerobic

Explanation:

The alkaline earth metals are also referred to as Group 2A. elements are comparable to one another in terms of their electron configurations and thus, their properties.

From beryllium (Be) through radium, the alkaline-earth metals comprise Group 2 of the periodic table (Ra). The alkaline earth metals are so reactive because each of these elements has two electrons in its lowest energy level that they are rarely encountered alone in nature. However, they don't react as quickly as alkali metals do. Compared to the alkali metals, their chemical reactions normally proceed more slowly and generate less heat.

Be :- [He]2S2

Mg:-[Ne]3S2

Ca :-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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Group 2A is another name for the alkaline earth metals, which are similar to one another in terms of their electron configurations and thus, their properties.

Group 2 of the periodic table is made up of alkaline-earth metals, starting with beryllium (Be) and ending with radium (Ra). The fact that each of these elements possesses two electrons at its lowest energy level makes the alkaline earth metals extremely reactive, which is why they are rarely found by themselves in nature. They don't respond as quickly, though, as alkali metals do. Their chemical reactions often take longer and produce less heat than those of the alkali metals.

Be:- [He]2S2

Mg:-[Ne]3S2

Ca:-[Ar]4S2

Sr:-[Kr]5S2

Ba:-[Xe]6S2

Ra:-[Rn]7S2

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