1. Which of the following numbers is
rational?
A. 0.78
B. 0.303003000
C. √6
D. 0.3841697

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = -2[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: 2 {x}^{2} - 3y = 6[/tex]

[tex]\qquad \tt \rightarrow \: 3y + 6 = 2 {x}^{2} [/tex]

[tex]\qquad \tt \rightarrow \: 3y = 2 {x}^{2} - 6[/tex]

[tex]\qquad \tt \rightarrow \: y = \cfrac{2 {x}^{2} - 6 }{3} [/tex]

[tex]\qquad \tt \rightarrow \: y = \cfrac{2 {}^{} }{3} {x}^{2} - 2[/tex]

[ here, y can be replaced with f(x) because y is a function of x ]

[tex]\qquad \tt \rightarrow \: f(x) = \cfrac{2 {}^{} }{3} {x}^{2} - 2[/tex]

[tex] \large\textsf{Find f(0):} [/tex]

[tex]\qquad \tt \rightarrow \: f(0) = \cfrac{2 {}^{} }{3} {(0)}^{2} - 2[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = 0 - 2[/tex]

[tex]\qquad \tt \rightarrow \: f(0) = - 2[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:576

Step-by-step explanation:

24 squared is 576

The simplification form of the provided expression is 6/5x¹⁰ option first is correct.

It is defined as the combination of constants and variables with mathematical operators.

We have an expression:

[tex]\rm = \sqrt{\dfrac{72x^{16}}{50x^{36}}}[/tex]

[tex]\rm = \sqrt{\dfrac{72}{50}} \sqrt{\dfrac{x^{36}}{x^{16}}}[/tex]

[tex]\rm = \sqrt{\dfrac{36\times2}{25\times2}} \sqrt{\dfrac{x^{36}}{x^{16}}}[/tex]

[tex]\rm ={\dfrac{6x^{8}}{5x^{18}}}[/tex]

[tex]\rm ={\dfrac{6}{5x^{10}}}[/tex]

Thus, the simplification form of the provided expression is 6/5x¹⁰ option first is correct.

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Answer:

6x3

Step-by-step explanation:

Edge 2023

Answer:

  m∠K = 37° and n = 31

Step-by-step explanation:

A lot of math is about matching patterns. Here, the two patterns we want to match are different versions of the same Law of Cosines relation:

Comparing the two equations, we note these correspondences:

Comparing these values to the given information, we see that ...

Abby apparently knew that ∠K = 37° and n = 31.

__

Additional comment

Side and angle naming for the Law of Sines and the Law of Cosines are as follows. The vertices of the triangle are labeled with single upper-case letters. The side opposite is labeled with the same lower-case letter, or with the two vertices at either end.

Vertex and angle K are opposite side k, also called side NM in this triangle.

For the regions bounded by y = 6cosx and y = one-fourth x squared minus 7, the limits of integration, the expression representing the total area, and the total area are mathematically given as

A=27.03squnit

What are the limits of integration, the expression representing the total area, and the total area.?

Generally, the equation for expression is mathematically given as

y = 6cosx

y=(1/4)x^2-7

therefore

[tex]A=\int^{b}_a (f(x)-g(x))dx[/tex]

The limits are

a=0 b=2\pi

Hence

[tex]A=\int ^{2\pi}_0 (6cosx -((1/4)x^2-7))dx\\\\solving\\\\A=\int^{2\pi}_0 (6cosx -((1/4)x^2-7))dx[/tex]

A=27.03squnit

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Answer:

A) d [tex]\geq[/tex] 5s + 9

Answer:

A. d ≥ 5s + 9

Step-by-step explanation:

Hence, equation will be :

The measure of the angles are Z = 90, X = 90, V = 90, Y = ∠20, W = ∠8 and W = ∠20

The sum of angles on a straight line is 180 degrees.

This means that:

Z + 90 = 180

X + 90 = 180

V + 90 = 180

Solve for the variables

Z = 90;

X = 90

V = 90

Also, alternate angles are equal.

This means that:

Y = ∠20

W = ∠8

This is so because the above angles are alternate angles.

Lastly, corresponding angles are equal.

So, we have:

W = ∠20

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The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

Parameters

[tex]$x^{2}=4 p y$[/tex]

[tex]$y=h$[/tex]

[tex]\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\[/tex]

Generally, the equation for the Area is mathematically given as

[tex]& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\[/tex]

[tex]&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

In conclusion,  the equation for the Area is

[tex]A=\frac{8}{3} \sqrt{p h} \cdot h[/tex]

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The range of the required function f(x)  = -√-x is all real values less than or equal to 0.

The nature of the function is imaginary because of the negative sign present inside the root. Hence the range of the function exists only and only if the function gives real  values in each of its outcomes.

Functions is the relationship between sets of values. e g y=f(x), for every value of x there is its exists in set of y. x is independent variable while Y is dependent variable.

As per question
f(x) = -√-x
clearly, for each positive real number the function becomes imaginary.
So the domain of the given function lies  (-∞, 0).
and for every x in its domain function has its exists in range of all real values less than and equal to zero.

Thus, the range of the function f(x) ≤ 0.

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Answer:

Step-by-step explanation:

Comment

The angle supplementary to x and 3x are equal.

Supplementary angles = 180

Solution

x + 3x = 180

4x = 180                  Divide by 4

4x/4 = 180/4

x = 45

The angle supplementary to x is 3x

3x = 3*45

3x = 135

This angle is vertically opposite y. Vertically opposite angles are equal. So  y = 135

Answer

x = 45

y = 135

Answer: 1

Step-by-step explanation:

Substituting in the given values,

3a-5b=3(-3)-5(-2)=-9+10=

The speed of the wind and the speed of the dragon in still air are respectively;  142.5 mph and 7.5 mph

The dragon flew 300 miles with the wind in two hours.

After flying against the wind for two hours, he had made 270 miles of the return trip.

Let s be the speed in still air

Let w be the speed of the wind

Thus;

(s - w) = effective speed against the wind

and

(s + w) = effective speed with the wind

We know that;

distance = time * effective speed

Thus;

2(s + w) = 300

2(s - w) = 270

This can be simplified to get;

s + w = 150   -----(1)

s - w = 135   -----(2)

Add both equations to get;

2s = 285

s = 285/2

s = 142.5 mph.

Then, plane speed in still air is;

142.5 + w = 150

w = 150 - 142.5

w = 7.5 mph is the speed of the wind

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C and A

X = at least 45 and more

This means we need to have a full closed dot.

It's A because the question says more than 75 ft meaning only open dots.

Answer:

power of a power

Step-by-step explanation:

the power of a power law says that, "if a base raised to a power is being raised to another power, the exponents are multiplied and the base remains the same."

for example, for this problem, you would do:

[tex](x^4)^9\\= x^4^*^9\\= x^3^6[/tex]

The question was incomplete. Below you will find the missing parts of the question.

The company actually loses money on their first few products as it costs them more to make them, but once they hit  ?   they break even again. The worst case scenerio is that they produce  ?   items, as they will have a profit of  ?   dollars. The first root tells us that the profit will be 0 when  ?   products are sold.

Answer: The company actually loses money on their first few products as it costs them more to make them, but once they hit  150   they break even again. The worst case scenerio is that they produce  75   items, as they will have a profit of  10000   dollars. The first root tells us that the profit will be 0 when  0   products are sold.

Because the roots are x = 0 and 150, the vertex is (75, 10000).

So, the function is y = [tex]-\frac{10000}{5625}(x-75)^{2} +10000[/tex]

When, y = 0,

[tex]0=-\frac{10000}{5625} (x-75)^{2} +10000[/tex]

⇒ [tex]\frac{10000}{5625} (x-75)^{2}=10000[/tex]

⇒ [tex](x-75)^{2} = 10000(\frac{5625}{10000})[/tex]

⇒ [tex](x-75)^{2} = 5625[/tex]

⇒ [tex]x-75=75[/tex]

⇒ x = 150

When y=0, then x =150, their income was in balance.

When x = 75, then y=10000, they will have a profit of 10000 dollars.

The first root tells us that the profit will be 0 when 0 products are sold.

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[tex]\tan x+\frac{\cos x}{1+\sin x}\\\\ =\frac{\sin x}{\cos x}+\frac{\cos x}{1+\sin x}\\\\=\frac{\sin x(1+\sin x)+\cos^{2} x}{\cos x(1+\sin x)}\\\\=\frac{\sin^{2} x+\cos^{2} x+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1+\sin x}{\cos x(1+\sin x)}\\\\=\frac{1}{\cos x}\\\\=\sec x[/tex]

Answer:

GFC = 4

Step-by-step explanation:

Factors of 20     1   2   4   5   10  20

Factors of 36     1   2  3 4  6  9 12 18 36

Answer:4

Step-by-step explanation:nice and simple

Answer:

A. b+2(b+2b)

b + 2b + 4b = 7b

B. 3b + b = 4b

C. 2(2b) = 4b

None of them are equal to 9b

Answer:

[tex]\fbox {None}[/tex]

Step-by-step explanation:

A

B

C

Using the binomial distribution, it is found that there is a 0.9842 = 98.42% probability that 3 or fewer experienced insomnia as a side effect, which means that it is a highly likely event.

The formula is:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

The values of the parameters are given as follows:

n = 20, p = 0.05.

The probability that 3 or fewer experienced insomnia as a side effect is given by:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)[/tex]

Hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{20,0}.(0.05)^{0}.(0.95)^{20} = 0.3585[/tex]

[tex]P(X = 1) = C_{20,1}.(0.05)^{1}.(0.95)^{19} = 0.3774[/tex]

[tex]P(X = 2) = C_{20,2}.(0.05)^{2}.(0.95)^{18} = 0.1887[/tex]

[tex]P(X = 3) = C_{20,3}.(0.05)^{3}.(0.95)^{17} = 0.0596[/tex]

Then:

[tex]P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.3585 + 0.3774 + 0.1887 + 0.0596 = 0.9842[/tex]

0.9842 = 98.42% probability that 3 or fewer experienced insomnia as a side effect.

Since this probability is greater than 95%, this is a highly likely event.

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Answer:

See below

Step-by-step explanation:

x = amount of 6% milk....   amount of fat = .06x

45-x = amount of 3% milk ...amount of fat = .03 (45-x)

Amount of fat in final mix of 45 quarts = .04 (45)

Inputs = output

.06x     +   .03(45-x)     =    .04(45)

.06x   +    1.35 - .03x     =  1.8

.03x = .45

x = 15   quarts of 6%      then  30  quarts of 3%

Answer:

7,500

Step-by-step explanation:

When you round you automatically round up unless told otherwise
so find the hundredth, which is 485 and you round that to 500
then put the 7 back → 7,500

Using the probability concept, we have that:

a) It would not be unusual to observe one component​ fail, since the probability that one component​ fails is greater than 0.05.

b) It would be unusual to observe two components​ fail, since the probability that two components​ fail is less than 0.05.

A probability is given by the number of desired outcomes divided by the number of total outcomes. If a probability is less than 0.05, the event is considered unusual.

In this problem, the probabilities are given as follows:

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Answer:

19 liters 800 milliliters

Step-by-step explanation:

0.33 * 12 * 5 = 19.8 liters

Since everything to the right of the line is shaded, the linear inequality which represents the graph is equal to: A. y ≥ 1/3x - 4.

In order to determine the linear inequality which represents the graph, we would find the slope of the given points.

Mathematically, the slope of a straight line can be calculated by using this formula;

[tex]Slope = \frac{Change\;in\;y\;axis}{Change\;in\;x\;axis}\\\\Slope = \frac{y_2\;-\;y_1}{x_2\;-\;x_1}[/tex]

Substituting the given points into the formula, we have;

[tex]Slope = \frac{-4\;-\;(-5)}{0\;-\;(-3)}\\\\Slope = \frac{1}{3}[/tex]

Slope = 1/3.

From the standard equation, we have:

y - y₁ = m(x - x₁)

y - (-5) = 1/3(x - (-3))

y + 5 = 1/3x + 1

y = 1/3x + 1 - 5

y = 1/3x - 4

y ≥ 1/3x - 4.

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Answer:

etrf4f3dvef3rf3rfr2wrgwrf2rg3rf3rgerferferfef I'm

[tex]a - 4 = ( \sqrt{a} - 2)( \sqrt{a} + 2)[/tex]

[tex] \frac{ \sqrt{a} - 2}{a - 4} = \frac{ \sqrt{a} - 2}{( \sqrt{a} - 2)( \sqrt{a} + 2) } = \frac{1}{ \sqrt{a} + 2 } [/tex]

Answer:

[tex]y=\dfrac{5}{4}x^3+10[/tex]

Step-by-step explanation:

Given information:

Create two equations by substituting the given points into the given equation:

Equation 1:  point (0, 10)

[tex]\implies a(0)^3+d=10[/tex]

[tex]\implies 0+d=10[/tex]

[tex]\implies d=10[/tex]

Equation 2:  point (2, 20)

[tex]\implies a(2)^3+d=20[/tex]

[tex]\implies 8a+d=20[/tex]

Substitute Equation 1 into Equation 2 and solve for a:

[tex]\implies 8a+d=20[/tex]

[tex]\implies 8a+10=20[/tex]

[tex]\implies 8a+10-10=20-10[/tex]

[tex]\implies 8a=10[/tex]

[tex]\implies \dfrac{8a}{8}=\dfrac{10}{8}[/tex]

[tex]\implies a=\dfrac{10}{8}[/tex]

[tex]\implies a=\dfrac{5}{4}[/tex]

Finally, substitute the found values of a and d into the original formula:

[tex]\implies y=\dfrac{5}{4}x^3+10[/tex]

Check by substituting the x-values of the two given points into the found equation:

[tex]x=0 \implies y=\dfrac{5}{4}(0)^3+10=10 \leftarrow \textsf{correct}[/tex]

[tex]x=2 \implies y=\dfrac{5}{4}(2)^3+10=20 \leftarrow \textsf{correct}[/tex]

Put(0,10)

Now

Put again (2,20) this time