1. Write an application that throws and catches an ArithmeticException when you attempt to take the square root of a negative value. Prompt the user for an input value and try the Math.sqrt() method on it. The application either displays the square root or catches the thrown Exception and displays an appropriate message. Save the file as SqrtException.java.
2. Create a ProductException class whose constructor receives a String that
consists of a product number and price. Save the file as ProductException.java.
Create a Product class with two fields, productNum and price. The Product
constructor requires values for both fields. Upon construction, throw a
ProductException if the product number does not consist of three digits, if the
price is less than $0.01, or if the price is over $1,000. Save the class as Product.java.
Write an application that establishes at least four Product objects with valid and invalid values. Display an appropriate message when a Product object is created
successfully and when one is not. Save the file as ThrowProductException.java.

Answer:

Explanation:

The following program was written in Java. It asks the user to first enter the target sum. Then it creates a while loop that continues asking the user to either roll dice or quit. If they decide to roll, it rolls the dice and prints out both values. If the target sum was hit, it prints that out and exits the program otherwise it loops again. The code has been tested and can be seen in the attached image below.

import java.util.Random;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       Random rand = new Random();

       Scanner in = new Scanner(System.in);

       System.out.print("Enter Target Sum: ");

       int targetSum = in.nextInt();

       while (true) {

           System.out.println("r: Roll Again");

           System.out.println("q: Quit");

           String choice = in.next();

           char choiceModified = choice.toLowerCase().charAt(0);

           if (choiceModified == 'r') {

               int roll1 = rand.nextInt(6) + 1;

               int roll2 = rand.nextInt(6) + 1;

               int total = roll1 + roll2;

               System.out.println("Dice 1: " + roll1);

               System.out.println("Dice 2: " + roll2);

               if (total == targetSum) {

                   System.out.println("Target Sum of " + targetSum + " hit.");

                   break;

               }

           } else if (choiceModified =='q') {

               break;

           } else {

               System.out.println("Wrong choice");

           }

       }

   }

}

Answer:

3

Explanation:

int(x)=3

int(x) rounds to the smallest whole number

For example,

if you say int(3.99) it is also 3

Following are the responses to this question:

Creating users:

We will use the useradd command to achieve this. Using that same command, you can create users who would log in or customers who would log in (in the case of creating a user for a software installation).

In its basic form, the command is as follows:

Take this user olivia, for instance. Assuming that you had been to issue the command prompt:

Users are added to the system without the need for a home directory and are unable to log on. It if we were using this rather than running the command without arguments?

Using the command above, a new user would be created, including a home directory that corresponded to the username. That means that you might now see the name "olivia" in the directory "/home".

But what about the lockout concern that was raised earlier? Both these methods are possible. After creating the user, you can enter the following command:

You'll be requested to enter & verify your new password once you've completed the process. This unlocks the user profile, allowing them to log in.

This command might look like if you wanted to accomplish it in one go:

You should be using Passcodes as the login for the user olivia.

As soon as the user logs in, he or she can update their account password by using the password command to input their current password, and afterward entering/verifying their new one.

To create a user that has no personal account and cannot log in, execute the following instructions:

The user to be added is identified by USERNAME.

It establishes a user with really no root folder and prevents them from signing in with a second operation.

To add an existing user to a group on Linux, follow the instructions:

Another way to add a user to a group under Linux would be to use the following syntax:

The following operations are performed when a new login is added to the system.

.bash_logout

.bash_profile

.bashrc

Learn more:

Linux system: brainly.com/question/13843535

Answer:

The open() operation notifies the system that the named file is about to become active. The close() operation notifies the system that the named file is no longer in active use by the user who issued the close operation.

Answer:

Explanation:

The following program is written in Java. It is a function that takes in the two parameters, combines them as a String, turns the combined String back into an integer, and uses a series of IF statements to check the parameters and determine which season it belongs to. Then it prints the season to the screen. The code has been tested with the example provided in the question and the output can be seen in the attached image below.

class Brainly {

   public static void main(String[] args) {

       getSeason(4, 65);

       getSeason(4, 11);

   }

   public static void getSeason(int month, int day) {

       String combined = String.valueOf(month) + String.valueOf(day);

       int combinedInt = Integer.parseInt(combined);

       if ((month > 0 && month < 12) && (day > 0 && day < 31)) {

           if ((combinedInt >= 320) && (combinedInt <= 620)) {

               System.out.println("The Season is Spring");

           } else if ((combinedInt >= 621) && (combinedInt <= 921)) {

               System.out.println("The Season is Summer");

           } else if ((combinedInt >= 922) && (combinedInt <= 1220)) {

               System.out.println("The season is Autumn");

           } else {

               System.out.println("The Season is Winter");

           }

       } else {

           System.out.println("Invalid date");

       }

   }

}

Answer:

Error reports

Explanation:

Answer: 121, 2222, 2202, 999

Explanation:

Answer:

a. 121

b. 2222

c. 2202

c. 999

Answer:

Quả lê Quả lê là một loại trái cây phổ biến vừa ngon vừa bổ dưỡng. ...

Quả dâu tây. Dâu tây là loại quả cực kỳ ngon. ...

Quả bơ Quả bơ khác hơn so với hầu hết các loại trái cây. ...

Quả táo. ...

Quả mâm xôi. ...

Quả chuối. ...

Cà rốt. ...

Củ cải đường.

Answer:

ae

Explanation:

The pseudo-code that corresponds to the given assembly code is:

b) if (c < 0)

print (yes);

else

print (maybe);

In assembly code, the command cmp AH, c checks if the high byte of the EAX register (AH) has the same value as the variable c. Then, if the value in AH is more than the value in c, the instruction jg option1 will move to option1.

Therefore, In the pseudo-code, one can check if c is smaller than 0. If it happens, we say "yes". If not, we say "maybe"

Read more about   pseudo-code here:

https://brainly.com/question/24953880

#SPJ2

Answer and Explanation:

In C programming language:

char fun(int*a, int*b){

printf("enter two integers: ");

scanf("%d%d",a,b);

int e;

printf("please enter a character: ");

e=getchar();

return e;

}

int main(int argc, char *argv[]) {

int d;

int f;

int g;

fun();

printf("%d%d%d", d, f, g);

}

We have declared a function fun type char above and called it in main. Note how he use the getchar function in c which reads the next available character(after the user inputs with printf()) and returns it as an integer. We then return the variable e holding the integer value as char fun() return value.

Answer:

The answer is "Spending the money can improve the company's reputation and attract new personnel with the necessary abilities".

Explanation:

In many cases, companies engage in activities tangential to their principal service or brand. As more than just a result, the purpose is to boost the company's reputation and at the same time raising societal awareness.

To strengthen its very own business reputation and to create future employees by teaching necessary skills, a technology organization may be established throughout the given case.

Every one of these initiatives helps to boost the brand's reputation & image, as well as the customer's confidence.

Answer:

A

Explanation:

b/c the round of 'A' is less than ruond of'B'

Answer:

The answer is "True".

Explanation:

Answer:

Ensures all database elements are known and secured through inventory and security protocols. Catalogs databases, backups, users, and accesses as well as checks permissioning, data sovereignty, encryption, and security rules. 

Security Risk Scoring

Proprietary Risk Assessment relays the security posture of an organization's databases at-a-glance through risk scores.

 Operational Security

Discovers and mitigates internal and external threats in real time through Database Activity Monitoring plus alerting and reporting. Identifies and tracks behavior while looking for anomalous activity internally and externally.

Database Activity Monitoring

Monitors 1 to 1,000+ databases simultaneously, synthesizing internal and external activity into a unified console.

Only by covering both of these areas can organizations have defense in depth and effectively control risk.

Answer:

Explanation:

// C++ Program to Find Grade of Student

// -------codescracker.com-------

#include<iostream>

using namespace std;

int main()

{

   int i;

   float mark, sum=0, avg;

   cout<<"Enter Marks obtained in 5 Subjects: ";

   for(i=0; i<5; i++)

   {

       cin>>mark;

       sum = sum+mark;

   }

   avg = sum/5;

   cout<<"\nGrade = ";

   if(avg>=91 && avg<=100)

       cout<<"A1";

   else if(avg>=81 && avg<91)

       cout<<"A2";

   else if(avg>=71 && avg<81)

       cout<<"B1";

   else if(avg>=61 && avg<71)

       cout<<"B2";

   else if(avg>=51 && avg<61)

       cout<<"C1";

   else if(avg>=41 && avg<51)

       cout<<"C2";

   else if(avg>=33 && avg<41)

       cout<<"D";

   else if(avg>=21 && avg<33)

       cout<<"E1";

   else if(avg>=0 && avg<21)

       cout<<"E2";

   else

       cout<<"Invalid!";

   cout<<endl;

   return 0;

}

Answer:

Managed devices

Explanation:

hope it helps u

Answer:

1.similarity:

3.ergonomics are designed keying devices that alleviates wrist strain experienced when using ordinary keyboard for long hours

4.

Answer:

Right click anywhere on your taskbar, and then click Properties. Step 2: Find and click the Notification Area tab on the top bar, and then find the section labeled with System icons, check the checkbox for Network. Last, click OK to finish it.

Answer:

c

Explanation:

Answer:

computers system may be classified according to their size.

four types of computers are;

some examples of the computer are;

2. mini computers- mini computers are sometimes called mid-range computers which are more powerful than microcomputers and can support a number of users performing different tasks, they were originally developed to perform specific tasks such as engineering calculations.

3. Mainframe computers- Mainframe computers are larger systems that can handle numberous users, store large amounts of data and process transaction at a high rate. these computers are expensive and powerful.

4. super computers- super computers are the most largest, fastest and most powerful computer. this systems are able to process hundreds of million of instructions per second they are used for job requiring and long complex calculation.

Answer:

4

Explanation:

4 is the ans as weather;timtable and price list display information

Answer:

The algorithm is as follows:

Input x

sum_a = 0

sum_b = 0

sum_c = 0

for i = 0 to 20

   sum_a = sum_a + x^i

   sum_b = sum_b + (-x)^i

   sum_c = sum_c + x^i/(i+1)

print sum_a, sum_b, sum_c

Explanation:

Required

An algorithm to solve (a), (b) and (c)

For Series (a):

This series is a geometric progression and the common ratio is x

i.e.

[tex]r = x/1 = x^2/x = ...... = x^{n+1}/x^n =x[/tex]

So, the sum of the series is:

Sum = Previous Sums + x^i --- where i is between 0 and 20 (inclusive)

For Series (b):

This series is a geometric progression and the common ratio is -x

i.e.

[tex]r = -x/1 = -x^2/x = ...... = -(x^{n+1}/x^n) = -x[/tex]

So, the sum of the series is:

Sum = Previous Sums + (-x^i) --- where i is between 0 and 20 (inclusive)

For Series (c):

This series is a neither arithmetic nor geometric progression.

It obeys the following rule:

[tex]\frac{x^i}{1+i}[/tex]  --- where i is between 0 and 20 (inclusive)

So, the sum of the series is:

Sum = Previous Sums + [tex]\frac{x^i}{1+i}[/tex]

Answer:

#include <stdio.h>

int main()  

{

int x;

float y;

printf("Input total distance in km: ");

scanf("%d",&x);

printf("Input total fuel spent in liters: ");

scanf("%f", &y);

printf("Average consumption (km/lt) %.3f ",x/y);

printf("\n");

return 0;

}

Answer:

Omg what is this

soooo long questionn

i am fainted

what rubbish you written how long the question is of which subject

what's your name

Answer:

Explanation:

Absconding

Answer:

Power point is a good software to use for slides

Answer:

i don't know the answer please tell me

Answer:

Advantages of hardware:

Physical existence

Multitasking

Speedy

Disadvantages:

Costly as different equipment cost differently

Time consuming

requires space

Privacy issues

Explanation:

Advantages of Software:

Less costly

Improved privacy controls

Requires no space

Disadvantages:

Does not have physical existence

hacking and cyber attacks may steal important information

Regular updates required