10 kg of Phenanthrene is to be burnt with supplied air which is 30% less than the requirement. Find the
exit gas stream average molecular weight and the leftover Phenanthrene amount in the reactor.

We would need to 1.39 L of the stock solution and then make up to the 2.54 L mark.

The dilution formula is used to calculate the new concentration of a solution after it has been diluted with a solvent. The formula is:

C1V1 = C2V2

where:

C1 = the initial concentration of the solution

V1 = the initial volume of the solution

C2 = the final concentration of the solution

V2 = the final volume of the solution

By the use of the formula;

C1V1 = C2V2

V1 = C2V2/C1

V1 = 2.54 * 6/11

V1 = 1.39 L

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The variable that determines which "R" value to use in a calculation is pressure (P). The ideal gas law equation, PV = nRT, includes the universal gas constant (R), which has different values depending on the units used for pressure. If pressure is measured in atmospheres (atm), the value of R is 0.08206 L·atm/mol·K. If pressure is measured in pascals (Pa), the value of R is 8.314 J/mol·K. Similarly, if pressure is measured in other units such as torr, bar, or psi, a different value of R should be used. Therefore, the choice of "R" value to use in a calculation depends on the units of pressure being used in the problem.

Answer:C. pressure (P)

Explanation:

The correct statement about cytokinesis is that a cell plate forms in plant cells. Option C is correct.

During cytokinesis, the cytoplasm of the parent cell divides into two daughter cells, each with its own nucleus and organelles. In animal cells, a contractile ring made of actin and myosin filaments forms around the cell's equator and contracts, pinching the cell in two.

In contrast, plant cells build a cell plate, which forms from vesicles produced by the Golgi apparatus, at the cell's equator. These vesicles fuse together and form a new cell wall to separate the two daughter cells. The other three options mentioned in the question are related to mitosis, which is the division of the nucleus, whereas cytokinesis is the division of the cytoplasm. Option C is correct.

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We need to fill the acetylene tank to a pressure of 44.29 atm to ensure that we run out of each gas at the same time.

To solve this problem, we need to apply the ideal gas law:

PV = nRT

Applying the ideal gas law for each tank,

PV = NkT

where N is the number of particles, k is Boltzmann's constant, and T is the temperature.

For oxygen:

(155 atm) * (7.00 L)

= N1 * k * T

For acetylene:

(P2) * (2.00 L)

= N2 * k * T

To use up both gases at the same time, we need to use the same number of moles of each gas. So we can set N1 equal to N2:

N1 = N2

Combining the two equations above to solve for P2:

(155 atm) * (7.00 L) = (N1) * k * T

(P2) * (2.00 L) = (N1) * k * T

Dividing the second equation by the first,

P2/P1 = (2.00 L)/(7.00 L)

P2 = (2.00 L)/(7.00 L) * (155 atm)

P2 = 44.29 atm

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The buffer solution has a pH of 5.36.

To find the pH of this buffer solution, use the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

where pKa = dissociation constant of acetic acid, [A⁻] = concentration of acetate ions, and [HA] = concentration of acetic acid.

Calculate the concentrations of acetate ions and acetic acid in the solution.

The initial moles of acetic acid are:

moles of acetic acid = volume of acetic acid x concentration of acetic acid

moles of acetic acid = 0.020 L x 0.10 mol/L

moles of acetic acid = 0.002 mol

After mixing with sodium acetate, the total volume of the solution is 50 mL, so the concentration of acetic acid and acetate ions are:

[HA] = moles of acetic acid / total volume of solution

[HA] = 0.002 mol / 0.050 L

[HA] = 0.040 M

[A⁻] = concentration of sodium acetate

[A⁻] = 0.10 M

The dissociation constant of acetic acid is pKa = 4.76.

Now, substitute these values into the Henderson-Hasselbalch equation:

pH = pKa + log([A⁻]/[HA])

pH = 4.76 + log(0.10/0.040)

pH = 4.76 + 0.60

pH = 5.36

Therefore, the pH of the buffer solution is 5.36.

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Answer:

1. Organized information: Mendeleev's periodic law helped organize the then-disparate information about elements into a system that made sense. This made it easier for chemists to understand the nature of the elements and make predictions about their behavior.

Approximately 63.5% of the compound AgNO3 is made of silver.

The atomic mass of silver (Ag) is 107.87 g/mol, and the atomic mass of nitrogen (N) is 14.01 g/mol, and the atomic mass of oxygen (O) is 16.00 g/mol.

The molecular weight of AgNO3 is:

AgNO3 = (Ag atomic mass) + (N atomic mass) + (3 x O atomic mass)

AgNO3 = (107.87 g/mol) + (14.01 g/mol) + (3 x 16.00 g/mol)

AgNO3 = 169.87 g/mol

The percent by mass of silver in AgNO3 can be calculated as:

Percent by mass of silver = (Mass of silver / Total mass of AgNO3) x 100

Since there is only one silver atom in one AgNO3 molecule, the mass of silver in one mole of AgNO3 is equal to the atomic mass of silver, which is 107.87 g/mol.

Therefore, the percent by mass of silver in AgNO3 is:

Percent by mass of silver = (107.87 g/mol / 169.87 g/mol) x 100

Percent by mass of silver = 63.5%

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