Answer:
79.8 cm²
Explanation:
surface area of triangular prism: (a + b + c) × length + base × height
Here given:
a = 3 cm, b = 3 cm, c = 3 cm, length = 8 cm, base = 3 cm, height = 2.6 cm
Inserting the values:
(a + b + c) × length + base × height
(3 + 3 + 3) × 8 + 3 × 2.6
79.8 cm²
More on surface area of triangular prism: https://brainly.com/question/27970162
Please help 15 points each but beware if you use my points for no reason or don't answer all 3 boxes I'll report you
What is the distance between the house and the library?
Answer:
C (√34)
Step-by-step explanation:
Pythagoras' theorem states that: a² + b² = c², where c is the hypotenuse and what we are trying to figure out.
So, 3² + 5² = c²
9 + 25 = 34 = c²
c = √34
:)
Answer:
C (√34)
Step-by-step explanation:
What is the smallest prime divisor of 5^23+7^17?
Answer:
well, both numbers are odd, so their sum will be even.
2 is the smallest prime divisor.
please help!!!!!!!!!!!!!!!!!!!!!!
please answer fast!
If a certain measurement of a polygon is 283 in2, it means:
A. the polygon's measurements are 283 inches by 283 inches.
B. the polygon's volume is 283 in?
C. 283 one-inch by one-inch squares will fit over its surface.
D. none of the above.
Answer: C
Step-by-step explanation:
A says the polygon's measurements are 283 inches by 283 inches. Is it Correct? No. If we multiply these numbers we get 80,089 inches squared, which is not equal to our actual surface of 283 inches squared.
B says the polygon's volume is 283 inches cubed, which is not correct because it says that a certain measurement of a polygon is 283 inches squared, not cubed, which means we got a surface/area, not a volume.
C says that our 283 inches squared area could fit 283 one-inch by one-inch squares, which is correct because one-inch by one-inch is an one inch squared area, if we multiply this one-inch squared by the number 283, we get 283 inch squared area.
And D couldn't be because the answer is C.
Hope I Helped!
how do i find the LCD? ( Lowest Common Denominator )
Answer:
First for example let's say
3 and 15your going to doing what you do normally for gcf but then make an l and times it if that makes sense
Step-by-step explanation: