Electrical inspector authority enforces the requirements set by the NEC.
The NEC specifies the minimum requirements for secure electrical installations.
The letters "UL" signify an electrical product satisfies the safety requirements of Underwriters Laboratories
Section 110.3 (B) Installation and Use of OSHA and NEC 1999. Equipment that is listed or labelled must be installed and used in accordance with any guidelines mentioned in the listing or labelling.
the word "shall" appears in a NEC reference, it means that it (must)(may) be done.
"The goal of this Code is the practical safeguarding of persons and property from hazards deriving from the usage of electricity," the NEC reads in 90.1(A). *
A collection of guidelines for the secure installation of electrical wiring in the US called the National Electrical Code (NEC) is revised on a regular basis. The NEC has been modified three times since it was first published in 1897.
In order to avoid fires and other electrical catastrophes, the NEC offers recommendations for electrical installation. For installations to be secure, legitimate, and compliant, electricians and contractors must be knowledgeable of the NEC when applicable. The National Fire Protection Organization, a private commercial association, is responsible for maintaining the codes.
The National Electrical Code (NEC) is a national designation, but it is not a federal statute. Local government either adopts NEC standards or writes and enforces its own electrical code in place of this.
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Help me in this question it is science
Answer:
13=c
14=a
other question=d
the light passing through the grating slits seems to be creating patterns of bright and dark fringes. in terms of light in the real world, what is happening to create the fringes?
When a light passes through a grating, it split the light to multiple light of different wavelength and which we can see as fringes. It is essentially separate the wavelength of incoming light.
Whilst light goes through a slit, diffraction reasons it to bend and unfold across the display, creating a predictable banded pattern. whilst mild is going thru two slits, new darkish regions seem. The dark and mild areas are produced with the aid of interference of the mild passing via the slits.
White mild can be separated into all seven most important hues of the entire spectrum or rainbow by using a diffraction grating or a prism. The diffraction grating separates mild into colors because the mild passes through the numerous exceptional slits of the grating. this is a transmission grating.
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exitance is defined as the power per unit area that is emitted from the surface of an object. for a blackbody radiator, the exitance emitted is dependent upon its temperature. calculate the exitance in w/cm2 for a blackbody radiator at 46 k and 335 k. exitance at 46 k
The exitance in W/cm² for a blackbody radiator at 335 K is 232 W/cm².
The exitance of a blackbody radiator is given by the Stefan-Boltzmann law: exitance = sigma × [tex]T^4[/tex]
where exitance is the power per unit area emitted from the surface of the object, sigma is the Stefan-Boltzmann constant (5.67 x [tex]10^{-8}[/tex] W/m² K^4), and T is the temperature of the blackbody radiator in Kelvin.
To calculate the exitance in W/cm² for a blackbody radiator at 46 K, we can substitute this temperature into the equation:
exitance = 5.67 x [tex]10^{-8}[/tex] W/m² [tex]K^4[/tex] × [tex](46 K)^4[/tex] = 0.000715 W/m²
Converting this to W/cm², we get:
exitance (W/cm²) = 0.000715 W/m² × (100 cm/m)² = 0.0715 W/cm²
To calculate the exitance in W/cm² for a blackbody radiator at 335 K, we can substitute this temperature into the equation:
exitance = 5.67 x [tex]10^{-8}[/tex] W/m² [tex]K^4[/tex] × [tex](335 K)^4[/tex] = 2.32 W/m²
Converting this to W/cm², we get:
exitance (W/cm²) = 2.32 W/m² × (100 cm/m)² = 232 W/cm²
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the right edge of the circuit in the figure extends into a 50 mt uniform magnetic field.
The magnitude of the circuit is 2.5*10^-2. Since the circuit's right edge in the illustration extends into a 50 mt uniform magnetic field, Rightward is the direction of the magnetic force.
According to the left hand rule, the thumb of the left hand points in the direction of force when the middle finger and index finger point in the direction of current and magnetic field, respectively. The magnetic field and the downward direction are indicated by the way the current in this circuit flows, which is from top to bottom. The thumb points to the right if the index finger points into the page and the middle finger points downward. Thus, the direction of the magnetic force is towards right.
F = (5.0)(10)(50mT)(10^-3/1)(sin90)
F = 2.5*10^-2N
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The complete question is -
The Right Edge Of The Circuit In The Figure Extends Into A 50 MT Uniform Magnetic Field. What Are The Magnitude of the circuit.
Can someone help with this
To solve this problem, you can use the equation for the conservation of energy, which states that the initial potential energy of the spring plus the work done by friction is equal to the final kinetic energy of the block.
The initial potential energy of the spring is given by 0.5kx1^2, where k is the force constant of the spring and x1 is the initial compression of the spring.
The work done by friction is equal to the force of friction times the distance over which it acts, which is given by µkmg*x1, where µk is the coefficient of kinetic friction, m is the mass of the block, g is the acceleration due to gravity, and x1 is the distance the block moves before coming to rest.
The final kinetic energy of the block is given by 0.5mv^2, where m is the mass of the block and v is the final velocity of the block.
You can set up the equation as follows:
0.5kx1^2 + µkmgx1 = 0.5m*v^2
Substituting the given values, we have:
0.5400.3^2 + µk29.810.3 = 0.52*v^2
Solving for µk, we find that:
µk = (0.5400.3^2 - 0.52v^2)/(29.810.3)
The maximum extension x2 of the spring is equal to the distance the block travels, so we can substitute x2 for v:
µk = (0.5400.3^2 - 0.52x2^2)/(29.810.3)
Substituting the value of x2, we find that:
µk = (0.5400.3^2 - 0.520.2^2)/(29.810.3)
Simplifying, we find that:
µk = 0.2
Therefore, the answer is 0.2, letter B.
Light rays from the sun make a 300 angle to the vertical when seen from below the surface of a body of water. At what angle above the horizon is the sun? The indices of refraction of glass, water, and air are 1.50, 1.333, and 1.000293, respectively.
The light rays from the sun is making an angle of 30° then the angle above the horizon of the sun is 48.32°.
What is an angle?When two lines converge at a point, they produce an angle. The word "angle" refers to the length of the "gap" between these two rays. The symbol is used to denote it.
Radians, a unit of roundness or rotation, and degrees are the 2 most common units used to measure angles. In daily life, angles are present.
As per the information given in the question,
Use the equation of snell's law,
(sin i)/(sin r) = n₂/n₁
r = sin⁻¹ (n₁ sin i)/n₂
Put n₁ = 1.33 and n₂ = 1 also substitute i = 30°
r = sin⁻¹ (1.33) (sin 30)/1
r = sin⁻¹(0.665)
r = 41.68°
The formula for the angle above the horizon,
θ = 90° - r
θ = 90° - 41.68°
θ = 48.32°.
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____a form of energy caused by the movement of molecules from warmer substances or objects to cooler ones. a. Conductor
b. Convection
c. Conduction
d. Heat
The right answer is D. Heat is a type of energy that results from molecules moving from warmer kinds of particles to cooler ones.
Why is energy so crucial?Computers, vehicles, communications, state-of-the-art medical technology, and many other things are all powered by energy. The demand for dependable and economical energy is especially pressing for emerging countries. It might even save a person's life.
How does energy originate?When electrons transfer by one atom to another, energy is produced. Heat and light are other examples of energy. It is also possible to convert one type of energy into another. Chemical energy that has been stored converts to electric energy using a battery.
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