The equation of the reflected function across the y-axis is g(x) = -4x - 8.
What is a function?A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.
The function f(x) = 4x - 8 is reflected across the y-axis.
The function g(x) will be given by putting the negative x in place of x. Then the reflected function is obtained.
g(x) = -4x - 8
Then the equation of the reflected function across the y-axis is g(x) = -4x - 8.
The graph of the reflected graph is given below.
More about the function link is given below.
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Find area of shaded region
Answer:
ayyyy i go to RSM too? Which location r u at? ANyways the answer is
If this fish tank is filled halfway, how much water will it hold?
96 cubic inches
768 cubic inches
48 cubic inches
384 cubic inches
Answer:
384 cubic inches
Step-by-step explanation:
first find the volume of the fish tank by multipying the length, width, and height.
v=lwh
=(16in)(4in)(12in)
= 768 cubic inches (This answer is equal to the volume of the entire fish tank, however we need to find how much water half the tank can hold. To figure this out, we need to divide 768 by 2. And you should get 384 cubic inches)
Answer:
384
Step-by-step explanation:
took the quiz
Using the diagram, which of the following choices represent alternate exterior angles
Answer:
A
Step-by-step explanation:
The answer is choice A.
The two angles are alternate exterior angles of lines LG and KH cut by transversal JF.
A number increase by three is two more twice the number.find the number.
Answer:
1
Step-by-step explanation:
1 increased by 3=1+3=4
Twice of 1=1+1=2
4 is two more than 2.
Therefore, the number=1
help with 27 please. thanks
Answer:
See Below.
Step-by-step explanation:
We are given the function:
[tex]\displaystyle y=\sqrt{\sin x}[/tex]
And we want to show that:
[tex]\displaystyle 4y^3\frac{d^2y}{dx^2}+y^4+1=0[/tex]
Find the first derivative of y using the chain rule:
[tex]\displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{\sin x}}\cdot \cos x = \frac{\cos x}{2\sqrt{\sin x}}[/tex]
And find the second derivative using the quotient and chain rules:
[tex]\displaystyle \begin{aligned} \frac{d^2y}{dx^2} &= \frac{1}{2}\left(\frac{(\cos x)'(\sqrt{\sin x})-(\cos x)(\sqrt{\sin x})'}{(\sqrt{\sin x})^2}\right) \\ \\ &=\frac{1}{2}\left(\frac{-\sin x\sqrt{\sin x} - \left(\cos x\right) \left (\dfrac{\cos x}{2\sqrt{\sin x}}\right)}{\sin x}\right) \\ \\ & = \frac{1}{2}\left(\frac{ -\sin x(2\sin x) -\cos x(\cos x) }{\sin x \left(2\sqrt{\sin x}\right) }\right) \\ \\ &= -\frac{1}{2} \left(\frac{2\sin^2 x + \cos^2 x}{2\sin^{{}^{3}\!/\! {}_{2}}x}\right)\end{aligned}[/tex]
Find y³:
[tex]\displaystyle y^3 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right) ^3= \sin^{{}^{3}\! / \! {}_{2} }x[/tex]
And find y⁴:
[tex]\displaystyle y^4 = \left((\sin x)^{{}^{1}\!/\!{}_{2}}\right)^4 = \sin^2 x[/tex]
Substitute:
[tex]\displaystyle 4\left( \sin^{{}^{3}\! / \! {}_{2} }x\right)\left(-\frac{1}{2}\left(\frac{2\sin ^2x + \cos ^2 x}{2\sin^{{}^{3}\!/ \! {}_{2}}x}\right)\right)+\left(\sin ^2 x\right) + 1= 0[/tex]
Simplify:
[tex]-\left(2\sin^2 x + \cos^2 x\right) + \sin ^2 x + 1=0[/tex]
Distribute:
[tex]-2\sin ^2 x - \cos^2 x + \sin ^2 x + 1=0[/tex]
Simplify:
[tex]-\sin ^2 x - \cos^2 x + 1= 0[/tex]
Factor:
[tex]-(\sin ^2 x + \cos^2 x ) + 1=0[/tex]
Pythagorean Identity:
[tex]-(1)+1=0\stackrel{\checkmark}{=}0[/tex]
Q.E.D.
Pls if anyone knows the answer that will be greatly appreciated :)
Answers:
The areas from left to right are: 13 m^2, 49 m^2, 24 m^2, 14 m^2
The largest area occurs when the rectangle is a square
===========================================================
Explanation:
The area rectangle formula is base*height, or length*width, whichever you prefer.
From left to right, we have these areas:
1*13 = 13 m^27*7 = 49 m^212*2 = 24 m^25*9 = 14 m^2We get the largest area (49 m^2) when the figure is a square. This happens with any problem in which we have a fixed amount of fencing and we want to max out the area. So it's not particular to this specific problem only.
Why a square? Well an informal way to think of it would be to consider that as one dimension goes up, the other goes down, and vice versa. Think of it like a see-saw. As the examples show, if one dimension is particularly large, then its area wont be as big compared to when the dimensions are closer together. It's only when all dimensions are equal is when we max the area out entirely.
I am sry but he has don wrong calculation the answer is last one 9*5=45m and its the answer.
and the noticiable thing is the larger the shape is the area increases.
(b) How much the selling price should be fixed for pulse bought for Rs.70 per kg. to earn a profit of Rs.6 after allowing a 5 % discount?
Answer:
Rs. 80
Step-by-step explanation:
Given that :
Purchase price = 70
Profit = 6
Discount = 5%
Let selling price = x
Selling price * (1 - discount) = (purchase price + profit)
x * (1 - 5%) = (70 + 6)
x * (1 - 0.05) = 76
x * 0.95 = 76
0.95x = 76
x = 76 / 0.95
x = 80
Hence, selling price = Rs. 80
The length of a rectangle is 7 inches
more inan its width. the area of
the rectangle is eqaul to 4 inches less
than 4 times the perimeter. Find the
length and width of the rectangle
Answer:
length = 20 inches
width = 13 inches
Step-by-step explanation:
l = length
w = width
area = l×w
perimeter = (2×l) + (2×w)
l = w + 7
l×w = 4×(2×l + 2×w) - 4
(w+7)×w = 4×(2×(w+7) + 2×w) - 4
w² + 7w = 4×(2w + 14 + 2w) - 4
w² + 7w = 8w + 56 + 8w - 4 = 16w + 52
w² - 9w - 52 = 0
the solution for a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/(2a)
here we use now w instead of x.
and a=1
b=-9
c=-52
w = (9 ± sqrt(81 - -208))/2 = (9 ± sqrt(81+208))/2 =
= (9 ± sqrt(289))/2 = (9 ± 17)/2
w1 = (9+17)/2 = 26/2 = 13
w2 = (9-17)/2 = -8/2 = -4
and a negative length does not make any sense for a geometric shape.
so, only w1 = 13 applies.
l = w + 7 = 13 + 7 = 20
Help please!!!
I need this assignment done today
Answer:
x- 1
y-5
z-3
Step-by-step explanation:
all u have to do is calculate the distance, so for example y is 5 because - -4 -3 -2 -1 0 1 and that is a 5 number distance
Ten samples were taken from a plating bath used in an electronics manufacturing process, and the bath pH was determined. The sample pH value are 7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42. Manufacturing engineering believes that pH has a median value of 7.0. Do the sample data indicate that this statement is correct
Answer:
There is no sufficient evidence to support the claim.
Step-by-step explanation:
Given the data:
7.91, 7.85, 6.82, 8.01, 7.46, 6.95, 7.05, 7.35, 7.25, 7.42
Sample size, n = 10
The sample mean, xbar = ΣX/ n = 74.07 / 10 = 7.407
The sample standard deviation, s = 0.41158 ( from calculator)
The hypothesis :
H0 : μ = 7
H0 : μ ≠ 7
The test statistic :
(xbar - μ) ÷ (s/√(n))
(7.047 - 7) ÷ (0.41158/√(10))
0.047 / 0.1301530
Test statistic = 0.361
Testing the hypothesis at α = 0.05
The Pvalue ;
df = n - 1 ; 10 - 1 = 9
Two tailed test
Pvalue(0.361, 9) = 0.7263
Since the Pvalue > α ; we fail to reject the Null and conclude that there isn't sufficient evidence to support the claim.
Two boats are travelling at 30 miles/hr, the first going north and the second going east. The second crosses the path of the first 10 minutes after the first one was there. At what rate is their distance increasing when the second has gone 10 miles beyond the crossing point
Answer:
their distance is increasing at the rate of 41.6 miles/hr
Step-by-step explanation:
Given the data in the question;
first we determine the distance travelled by the first boat in 10 min when the second boat was crossing its path;
⇒ ( 30/60 ) × 10 = 5 miles
so as illustrated in the diagram below;
y² = x² + ( x + 5 )²
2y[tex]\frac{dy}{dt}[/tex] = 2x[tex]\frac{dx}{dt}[/tex] + 2(x+5)[tex]\frac{dx}{dt}[/tex]
y[tex]\frac{dy}{dt}[/tex] = ( 2x + 5 ) ][tex]\frac{dx}{dt}[/tex]
[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex] ------ let this be equation 1
Now, given that, [tex]\frac{dx}{dt}[/tex] = 30 miles/hr, when x = 10
so
y = √( 10² + 15² ) = √325
so from equation 1
[tex]\frac{dy}{dt}[/tex] = [( 2x + 5 )/y ][tex]\frac{dx}{dt}[/tex]
we substitute
[tex]\frac{dy}{dt}[/tex] = [( 2(10) + 5 ) / √325 ]30
[tex]\frac{dy}{dt}[/tex] = [ 25 / √325 ] × 30
[tex]\frac{dy}{dt}[/tex] = 41.6 miles/hr
Therefore, their distance is increasing at the rate of 41.6 miles/hr
What is the solution set of the
equation?
(3x – 5)(2x – 10) = 0
Answer:
Step-by-step explanation:
3x - 5 = 0
3x = 5
x = 5/3
2x - 10 = 0
2x = 10
x = 10/2 = 5
How many mL of a 10% magnesium sulfate solution will contain 14 grams of magnesium sulfate?
Answer:
Upto 40 g or 160 mmols
Step-by-step explanation:
Can you plz mark me as brainliest?
Answer:
140 mL
Step-by-step explanation:
10% of 140 is 14
I need help on this problem
9514 1404 393
Answer:
see attached
Step-by-step explanation:
(a) The graph is scaled by a factor of 2, and shifted up 1 unit. The scaling moves each point away from the x-axis by a factor of 2. The points on the x-axis stay there. The translation moves that scaled figure up 1 unit.
__
(b) The graph is reflected across the x-axis and shifted right 4 units. The point on the x-axis stays on the x-axis.
what’s the formula to find the shaded area?
shaded area = area of outer figure - area of inner figure........
Evaluate.
(n - 1)!, where n = 3
2
5
6
(n-1) where n= 3
Answer is 2
(n - 1)!
n = 3
( 3 - 1)!
2!
= 1 × 2
= 2
n = 2
(2 - 1)!
1!
= 1
n = 5
(5 - 1)!
4!
= 1 × 2 × 3 × 4
= 24
n = 6
(6 - 1)!
5!
= 1 × 2 × 3 × 4 × 5
= 120
Answered by Gauthmath must click thanks and mark brainliest
a train left town at 9:15am it arrived at 2:15 at an average speed of24km/h, how many km does it cover.
Answer:
168 km
Step-by-step explanation:
24*7 is equal to 168 km
Given the numbers 30 and 45, find the common factors of the two numbers.
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30
Factors of 45: 1, 3, 5, 9, 15, 45
The common factors between the two numbers are 1, 3, 5, 15.
Hope this helps!
I need help completing this problem ASAP
4/(√x - √(x - 2)) × (√x + √(x - 2))/(√x + √(x - 2))
= 4 (√x + √(x - 2)) / ((√x)² - (√(x - 2))²)
= 4 (√x + √(x - 2)) / (x - (x - 2))
= 4 (√x + √(x - 2)) / (x - x + 2)
= 4 (√x + √(x - 2)) / 2
= 2 (√x + √(x - 2))
What percentage of area is above the mean on a normal curve?
Group of answer choices
34%
68%
97.35%
50%
Answer:
z=0
50%
Step-by-step explanation:
What is the maximum of f(x)= sin(x)?
-2π
-1
1
2π
Answer:
1
Step-by-step explanation:
the maximum of f(X)=sin(X) is 1
if f(x)=3x²-7 and f(x+n)=3x²+24x+41, what is the value of n?
Answer:
n=4
Step-by-step explanation:
f(x+n)=3(x+n)^2-7=3x^2+24x+41
3x^2+3n^2+6xn-7=3x^2+24x+41
Comparing and we will get, n=4
9. What is m JKM? A 28° C 90° B 58.5° D 117°
Step-by-step explanation:
her it Go i think it is helpful for u
write your answer as an integer or as a decimal rounded to the nearest tenth
Answer:
Step-by-step explanation:
CE and are the sides making up the sine of an angle.
CE is the side opposite the angle
DE is the side hypotenuse.
<D = 61 degrees
Sin(D) = opposite / hypotenuse
hypotenuse = 8
Sin(61) = 0.8746
CE = ?
sin(61) = CE / 8 multiply both sides by 8
8 sin(61) = CE
CE = 8 * 0.8746
CE = 6.9969
CE = 7.0
That 0 should be included in the answer, but I think it is safe to say that if you enter 7, you will get it right.
Answer:
7.0
Step-by-step explanation:
I need help this is confusing to me
Answer:i think it is b not really sure
Step-by-step explanation:
Which expression is the best estimate of the product of 7/8and 8 1/10?
Answer:
7 7/80 or 7.0875
Step-by-step explanation:
product is the result of multiplication
7/8 * 81/10 = 567/80 = 7 7/80 or 7.0875
It is estimated that t months from now, the population of a certain town will be changing at the rate of 4+ 5t^2/3 people per month. If the current population is 10,000, what will the population be 8 months from now?
Answer:
240000
Step-by-step explanation:
Represent the exponential equation.
[tex]10000 (5 {t}^{ \frac{2}{3} } + 4) = [/tex]
Replace 8 with t
[tex]10000(5(8) {}^{ \frac{2}{3} } + 4)[/tex]
[tex]10000(5 \times 4 + 4) [/tex]
[tex]10000(24) = 240000[/tex]
The population of the town after 8 month will be 2,40,000.
What is exponential growth?
Exponential growth is a pattern of data that shows greater increases with passing time, creating the curve of an exponential function.
Let P be the population of the town after 8 months
According to the given question
The current population of the town = 10,000.
Also, the population of the town is changing at the rate of [tex]4+5t^{\frac{2}{3} }[/tex].
Therefore, the population of the town after 8 month is given by the exponential function
[tex]P = 10000(4+5t^{\frac{2}{3} } )[/tex]
Substitute t =8 in the above equation
⇒[tex]P = 10000(4 + 5(8)^{\frac{2}{3} } )[/tex]
⇒[tex]P = 10000(4 + 5(2^{3}) ^{\frac{2}{3} } )[/tex]
⇒[tex]P = 10000(4+5(4))[/tex]
⇒[tex]P = 10000(24)[/tex]
⇒[tex]P = 240000[/tex]
Hence, the population of the town after 8 month will be 2,40,000.
Find out more information about exponential growth here:
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square root of 12321 by prime factorization
12321-3x3x37x37
(3)^2×(37)^2
square root = 3×37=111
Hope it helps you..!!
Find the missing side lengths. Leave your answers as radicals in simplest form.
Answer:
Step-by-step explanation:
For the question 1:
The given is a special right triangle with angle measures of
90-60-30 and side lengths represented by :
a - a[tex]\sqrt{3}[/tex] and 2a
The side length that sees 90 degrees is represented with a
The side length that sees 60 degrees is represented with a[tex]\sqrt{3}[/tex]
The side length that sees 30 degrees is represented with 2a
Here the side length that sees angle measure 60 is given as [tex]\sqrt{6}[/tex]
so a[tex]\sqrt{3}[/tex] = [tex]\sqrt{6}[/tex] to find the value of a we divide [tex]\sqrt{6}[/tex] with [tex]\sqrt{3}[/tex]
[tex]\frac{\sqrt{6} }{\sqrt{3} }[/tex] = [tex]\sqrt{2}[/tex]
so y = [tex]\sqrt{2}[/tex] and x = 2[tex]\sqrt{2}[/tex]
for second question
the square value of hypotenuse is equal to sum of other two side length's square value
10^2 + 6^2 = x^2
100 + 36 = x^2
136 = x^2
[tex]\sqrt{136}[/tex] = x
find the value of the trigonometric ratio
Answer:
15÷39
Step-by-step explanation:
I hope it will help you
cos x = adjacent÷ hypotenuse
cos x =15÷39
cos x = 5÷13