2) An algorithm that takes in as input an array with n rows and m columns has a run time of O(nlgm). The algorithm takes 173 ms to run in an input array with 1000 rows and 512 columns. How long will the algorithm take to run on an input array with 1500 rows and 4096 columns? (Note: For ease of calculation, please use a base of 2 for your logarithm.)

Answer:

Numeric Addition

Explanation:

Literally, the + sign is an arithmetic operator used to perform addition operation between numeric datatypes (integer, float, decimal, double, long integer, etc...)

Its default built in function of the plus is sign is to add variables, constants and/or expressions.

The plus sign is used as follows;

a = 5;

b = 3;

c = a + b

-------------

a + b = 5 + 3 = 8

8 will be saved in variable c. This is only possible using the plus sign.

The plus sign also has other function such as string concatenation but this function is language dependent (i.e. some programming languages do not use + for string concatenation).

Conclusively, the built in function of the plus sign is for numeric addition

Answer:

The database can include the fields related to the Author such as name and address, related to Publisher such as publisher's name and address, related to book such as title and ISBN of the book and related to contract such as payment schedule, contract start and end.

Explanation:

The following fields can be needed for this database:

Answer:

The step by step explanation

Explanation:

Before doing anything, the first thing to do is to select the 100BaseTX network adapter and reconnect the Cat5e cable. The 100BaseTX network adapter supports Fast

Ethernet which is all that is required.

Now do the following steps:

Step one

In Office 2, switch to the motherboard view of the computer (turning off the workstation as necessary).

Step two

On the Shelf, expand the Network Adapters category.

Step three

Identify the network adapter that supports Fast Ethernet 100BaseTX. Drag the network adapter from the Shelf to a

free PCI slot on the computer.

Step four

To connect the computer to the network, switch to the back view of the computer.

Step five

Drag the Cat5 cable connector from the motherboard's NIC to the port of the 100BaseTX network adapter.

Step six

To verify the connection to the local network and the Internet, switch to the front view of the computer.

Step seven

Click the power button on the computer case.

Step eight

After the workstation's operating system is loaded, click the networking icon in the notification area and click

Open Network and Sharing Center. The diagram should indicate an active connection to the network and the

Internet.

For one to be able to confirm the speed of the connection, it can be done by clicking the Local Area Connection link in the Network and

Sharing Center.

Answer:

B. Aside element

Explanation:

The options for this question are missing, the options are:

A. ​article element

B. ​aside element

C. ​section element

D. ​content element

An aside element is defined as a section of a page that has content that is tangentially related to the content around the element. In other words, the aside element represents content that is indirectly related to the main content of the page. Therefore, we can say that the correct answer to this question is B. Aside element.

Answer:

Explanation:

The vertices of a square is one such set of points. Either diagonal will bring the degree of the points involved to 3 = 4-1.

The vertices of a regular pentagon is another such set of points. After joining the points in a convex hull, any interior connection will create a triangle and a quadrilateral. The diagonal of the quadrilateral will bring the degree of at least one of the points to 4 = 5-1.

Answer:

The cpp program for the given scenario is as follows.

#include <iostream>

#include <iterator>

using namespace std;

int main()

{

   //boolean variable declared and initialized  

   bool sorted=true;

   //integer array declared and initialized

   int arr[] = {1, 2, 3, 4, 5};

   //integer variables declared and initialized to length of the array, arr

   int len = std::end(arr) - std::begin(arr);

       //array tested for being sorted

    for(int idx=0; idx<len-1; idx++)

    {

        if(arr[idx] < arr[idx+1])

           {

               sorted=false;

            break;

           }

    }

    //message displayed  

    if(sorted == false)

     cout<< "UNSORTED" <<endl;

 else

    cout<< "UNSORTED" <<endl;

return 0;

}

OUTPUT

UNSORTED

Explanation:

1. An integer array, arr, is declared and initialized as shown.

int arr[] = {1, 2, 3, 4, 5};

2. An integer variable, len, is declared and initialized to the size of the array created above.

int len = std::end(arr) - std::begin(arr);

3. A Boolean variable, sorted, is declared and initialized to true.

bool sorted=true;  

4. All the variables and array are declared inside main().

5. Inside for loop, the array, arr, is tested for being sorted or unsorted.  The for loop executes over an integer variable, idx, which ranges from 0 till the length of the array, arr.

6. The array is assumed to be sorted if all the elements of the array are in descending order.

7. If the elements of the array are in ascending order, the Boolean variable, sorted, is assigned the value false and for loop is exited using break keyword. The testing is done using if statement.

8. Based on the value of the Boolean variable, sorted, a message is displayed to the user.

9. The program can be tested for any size of the array and for any order of the elements, ascending or descending. The program can also be tested for array of other numeric data type including float and double.

10. All the code is written inside the main().

11. The length of the array is found using begin() and end() methods as shown previously. For this, the iterator header file is included in the program.

Answer:

The pseudocode is as given below while the flowchart is attached.

Explanation:

The pseudocode is as follows

input customer name, number of texts  

Set Basic bill=5 $;

if the number of texts is less than or equal to 60

Extra Charge=0;

If the number of texts is greater than 60 and less than 200

number of texts b/w 60 and 200 =number of texts-60;

Extra Charge=0.1*(number of texts b/w 60 and 200);

else If the number of texts is greater than 200

number of texts beyond 200 =number of texts-200;

Extra Charge=0.25*(number of texts beyond 200)+0.1*(200-60);

Display Customer Name

Total Bill=Basic bill+Extra Charge;

Total Bill after Tax=Total Bill*1.12;

Answer:

Following are the code to this question:

import java.util.*; //importing package for user input

public class Main //defining class

{

public static void main(String []ar) //defining main method

{

double investment_amount,interest_rate,future_investment_value; //defining double variables

int years; //defining integer variable

Scanner obx=new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter invest value: "); //print message

investment_amount=obx.nextDouble(); //input value

System.out.print("Enter interest rate: ");//print message

interest_rate=obx.nextDouble();//input value

System.out.print("Enter number of years: ");//print message

years=obx.nextInt();//input value

future_investment_value=investment_amount*Math.pow((1+interest_rate/1200.),years*12); //calculating value by apply formula

System.out.println("you enter amount: $"+investment_amount); //print calculated value

System.out.println("annual interest rate:"+interest_rate+"%");//print calculated value

System.out.printf("Number of years: "+years+" the future investment value is :$%.2f\n",future_investment_value);//print calculated value

}

}

output:

please find the attachment.

Explanation:

Program Description:

Answer:

Explanation:

The objective of this question and what we are meant to do is to compute a short program in C++ that will display the information given in the question.

Let get started!.

C ++ Program Code.

#include <iostream>

#include<string>

using namespace std;

int main()

{

string name,email,hometown,highschool,previousColleges,mathOrCSCource,lastMathOrCSCource,CompType,ExtraCur,FavBook

,planAfterGrad,phone;

//Reading Data

cout<<"Name:";

getline(cin,name);

cout<<"Phone:";

getline(cin,phone);

cout<<"Email:";

getline(cin,email);

cout<<"HomeTown:";

getline(cin,hometown);

cout<<"High School(s):";

getline(cin,highschool);

cout<<"Previous Colleges:";

getline(cin,previousColleges);

cout<<"List of math/CS Cources:";

getline(cin,mathOrCSCource);

cout<<"When,Where and what was your last math or CS course:";

getline(cin,lastMathOrCSCource);

cout<<"Type(s) of computer you are confident working with:";

getline(cin,CompType);

cout<<"ExtraCurricular Activities (job,club,sports,etc.):";

getline(cin,ExtraCur);

cout<<"Favourite books,movies,music:";

getline(cin,FavBook);

cout<<"What you plan to do after Graduation:";

getline(cin,planAfterGrad);

//Printing data

cout<<"--------------------Printing Data---------------------------"<<endl;

cout<<"Name:"<<name<<endl;

cout<<"Phone:"<<phone<<endl;

cout<<"Email:"<<email<<endl;

cout<<"HomeTown:"<<hometown<<endl;

cout<<"High School(s):"<<highschool<<endl;

cout<<"Previous Colleges:"<<previousColleges<<endl;

cout<<"List of math/CS Cources:"<<mathOrCSCource<<endl;

cout<<"When,Where and what was your last math or CS course:"<<lastMathOrCSCource<<endl;

cout<<"Type(s) of computer you are confident working with:"<<CompType<<endl;

cout<<"ExtraCurricular Activities (job,club,sports,etc.):"<<ExtraCur<<endl;

cout<<"Favourite books,movies,music:"<<FavBook<<endl;

cout<<"What you plan to do after Graduation:"<<planAfterGrad<<endl;

return 0;

}

Answer:

C. improve data quality and reduce redundancies, reduce increased and staggering storage management costs

Explanation:

Excess data retention can lead to retention of redundant and irrelevant data, which can reduce data handling and processing efficiency, while at the same time increasing the cost of data storage and management. This can be curbed be reducing data to the right size by using data governance techniques like data cleansing and de-duplication

Answer:

Given

The above lines of code

Required

Rearrange.

The code is re-arrange d as follows;.

#include<iostream>

int main()

{

int userNum;

scanf("%d", &userNum);

if (userNum > 0)

{

printf("Positive.\n");

}

else

{

printf("Non-positive, converting to 1.\n");

userNum = 1;

printf("Final: %d\n", userNum);

}

return 0;

}

When rearranging lines of codes. one has to be mindful of the programming language, the syntax of the language and control structures in the code;

One should take note of the variable declarations and usage

See attachment for .cpp file

Answer: provided in the explanation section

Explanation:

// code to copy

Car.java

public class Car {

  public void m1()

  {

  System.out.println("car 1");

}

  public void m2() {

      System.out.println("car 2");

}

  public String toString()

  {

  return "vroom";

}

}

Truck.java

public class Truck extends Car{

  public void m1()

  {

  System.out.println("truck 1");

  }

  public void m2()

  {

  super.m1();

  }

  public String toString()

  {

      return super.toString() + super.toString();

  }

}

MonsterTruck​​​​​​​.java

public class MonsterTruck extends Truck

{

  public void m1() {

System.out.println("monster 1");

}

public void m2() {

super.m1();

super.m2();

}

public String toString() {

return "monster " + super.toString();

}

public static void main(String[] args) {

  MonsterTruck mt=new MonsterTruck();

  mt.m1();

  mt.m2();

  System.out.println(mt);

}

}

cheers i hope this helped !!!

Answer:

Following are the algorithm to this question:

Find_Heavier_Coins(Coin[9]):

   i) Let Coin[] Array represent all Coins.  

   ii) Divide coin[] into 3 parallel bundles and each has three coins, example 0-2, 3-5, 6-8 indicate a1 a2 a3

   iii) Randomly select any two bundles and place them in balance [say a1 and a2]

   iv) If Weigh of a1 and a2 has same:

           // checking that if a3 has heavier coin

           Choose any two 6-8 coins and place them onto balance [say 6 and 8]

           If those who weigh has the same weight:

               Third coin is coin heavier [say 7]

           else:  

               The coin [6 or 8] is the one which is heavier on the balance

       else:

           //The coin has the package which would be heavier on the balance [say a1]

           Select any two coins on balance from of the heavier package [say 0 and 1]

   If they weigh the same weight:

       Third coin is coin heavier [say 2]

   else:

       The coin that is heavier on the balance is the [or 0]

Explanation:

In the above-given algorithm code, a method Find_Heavier_Coins is declared which passes a coin[] array variable in its parameters. In the next step, if conditional block is used that checks the values which can be described as follows:

Answer:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

   print(w[i].upper())

Explanation:

every element needs to be upper cased

A loop that prints the words in uppercase letters is written below with the help of Python.

Simply said, a function is a "chunk" of code that you may reuse repeatedly so instead of having to write it out several times. Software developers can divide an issue into smaller, more manageable parts, which can each carry out a specific task, using functions.

A function, according to a technical definition, is a relationship between an amount of parameters and a set of potential outputs, where every other input is connected to precisely one output.

All the functions are to be written in uppercase:

w = ["Algorithm", "Logic", "Filter", "Software", "Network", "Parameters", "Analyze", "Algorithm", "Functionality", "Viruses"]

for i in range (len(w)):

  print(w[i].upper())

Learn more about function, Here:

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Answer:

import java.util.Scanner;

public class UnitTesting {

   // Function returns origNum cubed

   public static int cubeNum(int origNum) {

       return origNum * origNum * origNum;

   }

   public static void main (String [] args) {

       System.out.println("Testing started");

       System.out.println("2, expecting 8, got: " + cubeNum(2));

       System.out.println("3, expecting 27, got: " + cubeNum(3));

       System.out.println("-1, expecting -1, got: " + cubeNum(-1));

       System.out.println("Testing completed");

       return;

   }

}

Explanation:

Added statements are highlighted.

Since the cubeNum function calculates the cube of the given number and we are asked to write two statements to test inputs 3 and -1, pass the parameters 3 and -1 to the function called cubeNum and print the results using print statements

Answer:

The correct answer is option (c) 4950 cipher keys

Explanation:

Solution

Given that:

From the given question we have that if there are 100 computers in a LAN, then each computer should have how many keys.

Now,

The number of computers available = 100

The number of keys used in  symmetric key cipher for N parties is given as follows:

= N(N-1)/2

= 100 * (100 -1)/2

= 50 * 99

= 4950 cipher keys

Answer:

def output_ints_less_than_or_equal_to_threshold(user_values, upper_threshold):

  for value in user_values:

      if value < upper_threshold:

          print(value)  

def get_user_values():

  n = int(input())

  lst = []

  for i in range(n):

      lst.append(int(input()))

  return lst  

if __name__ == '__main__':

  userValues = get_user_values()

  upperThreshold = int(input())

  output_ints_less_than_or_equal_to_threshold(userValues, upperThreshold)

Explanation:

Find the given attachments

Answer:

Sorted Array A { } = { 1, 4, 23, 32, 34, 34, 67, 78, 89, 100 }

Explanation:

Binary tree is drawn given that the binary tree do not follow both minimum heap and maximum heap property, therefore, it is not a heap.

See attached picture.

Answer:

cyberspace

Explanation:

It is the notional environment in which communication over computer networks occurs.

It is imperative that we safeguard this domain known as cyberspace.

The meaning of the cyberspace is the climate of the Internet.

There is large network of computers connected together in offices or organizations to explore the internet. The cyberspace has formed the first important needed thing in this century without which nothing can be done in personal space or in any companies.

The U.S. continues to become more dependent on the global domain within the information environment consisting of the interdependent network of information technology infrastructures, including the Internet, telecommunications networks, computer systems, and embedded processors and controllers.

So, we safeguard this domain known a cyberspace.

Learn more about cyberspace.

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Answer:

Explanation:

The objective of this program we are to develop is to compute a C++ program and a flowchart that calculates a cost to replace all tablets and desktop computers in a business.

C++ Program

#include<iostream>

#include<iomanip>

using namespace std;

/*

⦁ // Name:

⦁ // Date:

⦁ // Program Name:

⦁ // Description:

*/

int main()

{

const double SalesTaxRate = .075, DiscountPercent = .10, FinanceCharge = .15;

const double TABLET = 320.00, DESKTOP = 800.00;

double total = 0.0, subTotal = 0.0,avg=0.0;

int numberOfTablets, numberOfDesktop;

cout << "-------------- Welcome to Computer Selling Company ------------------ ";

cout << "Enter number of tablets: ";

cin >> numberOfTablets;

cout << "Enter number of desktops: ";

cin >> numberOfDesktop;

subTotal = TABLET * numberOfTablets + numberOfDesktop * DESKTOP;

char choice;

cout << "Paying cash or financing: (c/f): ";

cin >> choice;

cout << fixed << setprecision(2);

if (choice == 'c' || choice == 'C')

{

cout << "You have choosen paying cash." << endl;

total = subTotal - subTotal * DiscountPercent;

cout << "Discount you get $" << subTotal * DiscountPercent<<endl;

cout << "Sales Tax: $" << SalesTaxRate * total << endl;

total = total + total * SalesTaxRate;

cout << "Total computers' Cost: $" << total << endl;

avg = total / (numberOfDesktop + numberOfTablets);

cout << "Average computer cost: $ " << avg << endl;

}

else if (choice == 'f' || choice == 'F')

{

cout << "You have choosen Finance option." << endl;

total = subTotal + subTotal * FinanceCharge;

cout << "Finance Charge $" << subTotal * FinanceCharge << endl;

cout << "Sales Tax: $" << SalesTaxRate * total << endl;

total = total + total * SalesTaxRate;

cout << "Total computers' Cost: $" << total << endl;

avg = total / (numberOfDesktop + numberOfTablets);

cout << "Average computer cost: $ " << avg << endl;

}

else

{

cout << "Wrong choice.......Existing.... ";

system("pause");

}

//to hold the output screen

system("pause");

} }

OUTPUT:

The Output of the program is shown in the first data file attached below:

FLOWCHART:

See the second diagram attached for the designed flowchart.

Answer: you want to list all LC structers

Explanation:

Answer:

C

Explanation:

Accessories are in Microsoft windows, a set of programs and applications that help users with some basic tasks

Answer:

dependability

Explanation:

devon keeps his commitment

The personal skill that's demonstrated by Devin is dependability.

Dependability simply means when an individual is trustworthy and reliable. Dependability simply means when a person can be counted on and relied upon.

In this case, since Devon keeps his commitments, submits work when it's due, and shows up when scheduled, it shows that he's dependable.

It should be noted that employers love the people that are dependable as they can be trusted to have a positive impact on an organization.

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Answer:

This program is written in python programming language

Comments are used for explanatory purpose;

Take note of indentations(See Attachment)

Program starts here

#Initialize Sum to 0

sum = 0

#Prompt user for start value

start= int(input("Start Value: "))

#Prompt user for stop value

stop= int(input("Stop Value: "))

#Check if start is less than stop

if(start<=stop):

       #Iterate from start to stop

       for i in range(start, stop+1, 1):

              sum+=i**3

else:

print("Start must be less than or equal to Stop")

#Display Result

print("Expected Output: ",sum)

#End of Program

Answer:

None

Explanation:

These are all stereotypes. Sure, there are definitely some people who fit their stereotypes, but not all. It's just a generalization at the end of the day. I can't really agree with any of them due to the fact that it's all stereotyping.

Perhaps you feel differently, and believe that some of these example are true. I can't though, sorry. Hope this take helps.

Answer: Provided in the explanation section

Explanation:

Code to use;

# Define the main() function.

def main():

   # Declare the required variables.

   stack_cars = []

   move_time = 1

   retrieve_time = 2

   # Start the loop to display the menu.

   while True:

       # Display the choices to the user.

       print("\n\t\t\t Car Stack Menu")

       print("\n1. Add a car")

       print("2. Retrieve a car")

       print("3. Show the car stack")

       print("4. Exit")

       # Prompt the user to enter the input.

       choice = input("\nEnter your choice: ")

       # Append the car in the stack if the choice is 1.

       if choice == '1':

           car = input("Enter the car name to add: ")

           stack_cars.append(car)

       # Remove the car from the stack if the choice is 2.

       elif choice == '2':

           car = input("Enter the car name to retrieve: ")

           # Display the error message if the car is not present.

           if car not in stack_cars:

               print(car + " is not present in the stack.")

           # Otherwise, compute the time to retrieve a car.

           else:

               # Declare a temp stack to move the cars.

               temp = []

               x = stack_cars.pop()

               count = 0

               # Start the loop to pop the cars from the stack

               # until the car to be retrieved is found.

               while x != car:

                   count += 1

                   # Store the car in the temp stack.

                   temp.append(x)

                   x = stack_cars.pop()

               # Start the loop to move the cars back in the

               # original stack.

               while len(temp) != 0:

                   stack_cars.append(temp.pop())

               # Compute and display the total time.

               total_time = move_time * count + retrieve_time

               print("Total time to retrieve", car, "=", total_time)

       # Display the stack if the choice is 3.

       elif choice == '3':

           print("Car stack =", stack_cars)

       # Return from the funtion if the choice is 4.

       elif choice == '4':

           print("Exiting from the program...")

           return

       # Display the message for invalid input.

       else:

           print("Error: Invalid choice!")

# Call the main() function.

if __name__ == "__main__":

   main()

Answer:

Network Operating System (NOS)

Explanation:

A network operating system (NOS) is an operating system that makes different computer devices connect to a common network in order to communicate and share resources with each other using a server. A network operating system can be used by printers, computers, file sever among others, and they are connected together using a local area network. This local area network which they are connected to works as the server.

The NOS also acts as a network security because it could be used as an access control or even user authentication.

There are two types of NOS

1) Peer to peer network operating system.

2) Client/server network operating system

A network operating system (NOS) is a server-based operating system oriented to computer networking and may include directory services, network management, network monitoring, network policies, user group management, network security, and other network-related functions.

Answer: provided in the explanation section

Explanation:

The question says:

Write a short assembly language program in either our 8088 SCO DOSBox or 80386+ MASM Visual Studio 2017 environment that demonstrates data storage and retrieval from memory. As an example consider some value which is either 16 or 32 bits, after instantiating as an immediate value transfer to and retrieve from memory using assembly language instructions.

The Answer:

multi-segment executable file template. data segment ; add your data here! pkey db "press any key...$" ends stack segment dw 128 dup(0) ends code segment start: ; set segment registers: mov ax, data mov ds, ax mov es, ax ; add your code here mov cx,4 input: mov ah,1 int 21h push ax loop input mov dx,13d mov ah,2 int 21h mov dx,10d mov ah,2 int 21h mov cx,4 output: pop bx mov dl,bl mov ah,2 int 21h loop output exit: lea dx, pkey mov ah, 9 int 21h ; output string at ds:dx ; wait for any key....

mov ah, 1 int 21h mov ax, 4c00h ; exit to operating system. int 21h ends end start ;

set entry point and stop the assembler.

Cheers I hope this helps!!!

Explanation:

A transaction is a very small system unit that can contain many low-level tasks. A transaction in a database system should maintain, Atomicity, Consistency, Isolation, and Durability − these are commonly known as ACID properties − in order to ensure accuracy, completeness, and integrity of the data.

An example of a simple transaction is as below,  Suppose a bank employee transfers Rs 500 from A's account to B's account.

A’s Account

Open_Account(A)

Old_Balance = A.balance

New_Balance = Old_Balance - 500

A.balance = New_Balance

Close_Account(A)

B’s Account

Open_Account(B)

Old_Balance = B.balance

New_Balance = Old_Balance + 500

B.balance = New_Balance

Close_Account(B)