2. En la ciudad de Quito, en la temporada fría, se registran temperaturas que van desde los 5 °C hasta los 18 °C. En la temporada cálida, el registro de la temperatura va desde los 4 °C hasta los 30 °C.
a. Representamos estas temperaturas en forma de intervalo y como conjunto.
b. ¿A qué intervalo pertenece la temperatura de la ciudad de Quito?
c. ¿Qué temperaturas son comunes en las temporadas fría y cálida?
d. ¿Qué temperaturas son posibles solo en la temporada fría?
e. ¿Qué temperaturas son posibles solo en la temporada cálida?

Answers

Answer 1

Answer:

(See explanation below for further detail/Véase la explicación abajo para mayores detalles)

Step-by-step explanation:

(This exercise is written in Spanish and explanations will be held in such language)

a) Las temperaturas quedan representadas a continuación:

Quito - Temporada Fría

Intervalo

[tex]5 ^{\circ}C \leq t \leq 18^{\circ}C[/tex] (Este intervalo indica si el dato puede pertenecer a la temporada fría)

Conjunto

[tex]C = \{\forall t \in \mathbb {R}| 5 \leq t \leq 18\}[/tex] (Este conjunto acumula todo el registro de las temperaturas de la temporada fría)

Quito - Temporada Cálida

Intervalo

[tex]4 ^{\circ}C \leq t \leq 30^{\circ}C[/tex] (Este intervalo indica si el dato puede pertenecer a la temporada cálida)

Conjunto

[tex]H = \{\forall t \in \mathbb {R}| 4 \leq t \leq 30\}[/tex] (Este conjunto acumula todo el registro de las temperaturas de la temporada cálida)

b) La temperatura de la ciudad de Quito pertenece esencialmente a dos intervalos:

Intervalo de Temporada Fría:

[tex]5 ^{\circ}C \leq t \leq 18^{\circ}C[/tex]

Intervalo de Temporada Cálida:

[tex]4 ^{\circ}C \leq t \leq 30^{\circ}C[/tex]

c) Toda temperatura mayor o igual que 4 °C y menor o igual que 30 °C.

d) Temperaturas mayores o iguales a 5 °C y menores o iguales a 18 °C.

e) Temperaturas mayores o iguales a 4 °C y menores o iguales a 30 °C.


Related Questions

The sum is type answer as integer proper fraction or mixed number simplify answer

Answers

Answer:

[tex]9\dfrac{5}{6}[/tex]

Step-by-step explanation:

[tex]5\dfrac{1}{6}+4\dfrac{2}{3}=\\\\5\dfrac{1}{6}+4\dfrac{4}{6}=\\\\9\dfrac{5}{6}[/tex]

Hope this helps!

Please help me extra points for 1 math question. Please help before my time is up. Five times a number, added to -3, is 37. Find that number.

Answers

Answer:

your number should be 8

Step-by-step explanation:

5x+(-3)=37

5x-3=37

+3       +3

5x=40

÷5  ÷5

x=8

hope this helps

Answer:

The answer is 8.

5x-3=37

5x=37+3

5x=40

x=40/5

x=8

HOPE IT HELPS!!

If you found that the 95% confidence interval to estimate the true proportion of visitors to Niagara Falls that are from the United States was (0.5216, 0.6784), does this provide evidence that a majority of visitors to Niagara Falls are from the United States

Answers

Answer:

The lower end of the interval is above 0.5, which means that it provides evidence that a majority of visitors to Niagara Falls are from the United States

Step-by-step explanation:

We want to see if the majority of Niagara Falls visitors are from the United States.

Looking at the confidence interval

We have to see if the lower end of the interval is higher than 0.5.

In this question:

The 95% confidence interval to estimate the true proportion of visitors to Niagara Falls that are from the United States was (0.5216, 0.6784).

The lower end of the interval is above 0.5, which means that it provides evidence that a majority of visitors to Niagara Falls are from the United States

Please answer this correctly

Answers

Answer:

10-19 ⇒ 3

50-59 ⇒ 4

Answer:

# of ties    # of racks

 10-19               3

50-59              4

Step-by-step explanation:

Using the Stem and Leaf plot, our data is:

11, 12, 16

21

32, 34, 36, 37, 39

41, 45

51, 52, 53, 56

# of ties    # of racks

 10-19               3 (11, 12, 16)

50-59              4 (51, 52, 53, 56)

Find the missing side. Round to
the nearest tenth.
x
9
28°
x = [?]

Answers

Answer:

19.2

Step-by-step explanation:

It's right on Acellus.

The required value of x nearest to tenth is 19.17

What is hypotenuse?

The longest side of the right angled triangle is called hypotenuse

By the Pythagoras theorem in the right angled triangle

h^2 = b^2 + p^2

where h = hypotenuse, b = base, p = perpendicular

How to calculate hypotenuse?

Here we have given perpendicular p = 9

and an angle = 28°

Using sin for the given angle we have

sin 28° = [tex]\frac{perpendicular}{hypotenuse}[/tex]

0.46947 = [tex]\frac{9}{x}[/tex]

x = [tex]\frac{9}{0.46947}[/tex]

x =  19.17

Hence the required length of the side hypotenuse = x = 19.17

This is the conclusion to the answer.

Learn more about hypotenuse here-

https://brainly.com/question/2217700

#SPJ2

Solve for x. 6−x3=3 x=9 x=−9 x=27 x=−27

Answers

6-x3=3
6-3x=3
-3x=3-6
-3x=-3
X=1

Zareen has 24 minutes to work on her math homework in each problem is taking her 2/3 of a minute on average to complete which expression can be used to determine the number of my problem she will be able to complete in the time she has

Answers

Answer:

Hey mate , here is your answer. Hope it helps you

Step-by-step explanation:

Given Zareen has 24min to work on her math homework, and each problem is taking her 2/3 of a minute

As give one problem takes

24*(2/3) minutes = 16

Hence

2/3 divided by 24

The body temperatures of a group of healthy adults have a​ bell-shaped distribution with a mean of 98.19degreesF and a standard deviation of 0.61degreesF. Using the empirical​ rule, find each approximate percentage below. a. What is the approximate percentage of healthy adults with body temperatures within 3 standard deviations of the​ mean, or between 96.36degreesF and 100.02degrees​F? b. What is the approximate percentage of healthy adults with body temperatures between 96.97degreesF and 99.41degrees​F?

Answers

Answer:

a) From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data so then that would be the answer for this case.

b) [tex] z=\frac{96.97-98.19}{0.61}=-2[/tex]

[tex] z=\frac{99.41-98.19}{0.61}=2[/tex]

And within 2 deviations from the mean we have 95% of the values.

Step-by-step explanation:

For this case we know that the distribution of the temperatures have the following parameters:

[tex] \mu = 98.19, \sigma =0.61[/tex]

Part a

From the empirical rule we know that within 3 deviations from the mean we have 99.7% of the data so then that would be the answer for this case.

Part b

We can calculate the number of deviations from the mean with the z score with this formula:

[tex]z=\frac{X -\mu}{\sigma}[/tex]

And using this formula we got:

[tex] z=\frac{96.97-98.19}{0.61}=-2[/tex]

[tex] z=\frac{99.41-98.19}{0.61}=2[/tex]

And within 2 deviations from the mean we have 95% of the values.

What’s the correct answer for this?

Answers

Answer:

D.

Step-by-step explanation:

Since a quadrilateral inscribed in a circle has its opposite angles adding up to 180°

So,

<MNO + <OLM = 180

82 + <OLM = 180

<OLM = 180-82

<OLM = 98°

A commuter uses a bus and a train to get to work. The train is more than 5 minutes late 1/6 of the times they use it The bus is more than 5 minutes late 3/5 of the times they use it. What is the probability that both the bus and train will be more than 5 minutes late?

Answers

Answer:

10% probability that both the bus and train will be more than 5 minutes late

Step-by-step explanation:

Independent events:

If two events, A and B, are independent, we have that:

[tex]P(A \cap B) = P(A)*P(B)[/tex]

What is the probability that both the bus and train will be more than 5 minutes late?

The bus being more than 5 minutes late is independent of the train, and vice versa. So

Event A: Bus more than 5 minutes late

Event B: Train more than 5 minutes late

The train is more than 5 minutes late 1/6 of the times they use it

This means that [tex]P(B) = \frac{1}{6}[/tex]

The bus is more than 5 minutes late 3/5 of the times they use it.

This means that [tex]P(A) = \frac{3}{5}[/tex]

Then

[tex]P(A \cap B) = \frac{3}{5}*\frac{1}{6} = \frac{3}{30} = 0.1[/tex]

10% probability that both the bus and train will be more than 5 minutes late

What is the product?
(45+2)(5s2+ 10s+3)

Answers

Answer:

your answer is 127596 because you would take (45+2) first then you would take (55^2+10s+3) then you multiply them

Step-by-step explanation:

Estimate and then solve the equation. X - 17 4/5=-13 1/5

Answers

Answer: 5 (estimate)

Step-by-step explanation:

x - 17 4/5 = -13 1/5

Estimate:  x - 18 = -13

x - 18 + 18 = -13 + 18

x = 5

actual answer without estimating using exact numbers is 4 3/5 (so estimate is reasonable)

What is the next number in the sequence: 3, 8, 12, 48, 29, __

Answers

Answer:

144

Step-by-step explanation:

Answer:

116

Step-by-step explanation:

3x4=12

12x4=48

8x4=32

32-3=29

29x4=116

Hope it's clear

Very confused, need help quick! (see attachment) Simplify and show your work.

Answers

Answer:

27/(4x^6y^8)

Step-by-step explanation:

Target the variables first. (x^a)^b is the same as x^(a x b).

In the numerator, it is x^(2 x 3) , which is x^6, and y^(4 x 3), which is y^12.

Same principle on the bottom. the denominator is x^12 and y^20.

In the numerator, the number 4 is alone so don't do anything to it. Cube 3. The coefficient of the numerator is 4 x 3^3 . The coefficient of the denominator is 2^4. Cancel like terms. when you divide same terms' exponents, you subtract the exponent on top by the exponent on the bottom. Remember that you can only simplify LIKE terms. (x with x, y with y, number with number.)

Can a Math expert please solve this and explain their answers. Thanks

Answers

Answer:

B152°BA

Step-by-step explanation:

The measure of an arc is twice the measure of the inscribed angle that subtends that arc. A tangent is a special case where the chord that is one leg of the inscribed angle has a length of zero.

1. Short arc LJ is 2a°. Short arc LK is 2b°. Then arc JLK is 2(a+b)°, and short arc JK is ...

  arc JK = 360° -2(a +b)° . . . . . matches choice B

__

2. Long arc WY is twice the measure of "inscribed" angle WYZ, so is ...

  long ard WY = 2(104°) = 208°

Then short arc WY is ...

  arc WXY = 360° -208° = 152°

__

3. The arc measures are double those of the corresponding inscribed angles. We can add up the arcs around the circle:

  (arc AB +arc BC) = 2×70° = 140° . . . inscribed angle relation

  (arc BC +arc CD) = 2×98° = 196° . . . inscribed angle relation

  arc AB + arc BC +arc CD +arc DA = 360° . . . . sum around the circle

Adding the first two equations with arc DA, we have ...

  (arc AB + arc BC) +(arc BC +arc CD) +arc DA = 360° +arc BC

  140° +196° +80° = 360° +arc BC

  416° -360° = arc BC = 56° . . . . . matches choice B

__

4. Angle C and angle A are supplementary in this inscribed quadrilateral.

  angle C = 180° -98° = 82° . . . . . matches choice A

A laptop has a listed price of $875.98 before tax. If the sales tax rate is 6.5%, find the total cost of the laptop with sales tax included.
Round your answer to the nearest cent, as necessary.
please!

Answers

Answer:

$932.92

Step-by-step explanation:

6.5% = 0.065

(875.98) + (875.98)(0065)

(875.98) + (56.9387)

932.9187

$932.92

Answer:

$[tex]932.92[/tex]

Step-by-step explanation:

[tex]6.5/100=0.65[/tex]

Next, multiply the price by the sales tax.

[tex]875.98*0.65=56.94[/tex]

Then, add.

[tex]875.98+ 56.94=932.92[/tex]

$[tex]932.92[/tex] is the total cost of the laptop.

ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.

Answers

Answer:

its b I belive

Step-by-step explanation:

Answer:

The answer is B.

Step-by-step explanation:

In order to find (f-g)(x), you have to subtract g(x) from f(x) :

[tex]f(x) = {3}^{x} + 10[/tex]

[tex]g(x) = 2x - 4[/tex]

[tex](f - g)(x) = {3}^{x} + 10 - 2x - ( - 4)[/tex]

[tex](f - g)(x) = {3}^{x} + 10 - 2x + 4[/tex]

[tex](f - g)(x) = {3}^{x} - 2x + 14[/tex]

Find the value of the logarithm.
log 110
Round your answer to the nearest thousandth.

Answers

Answer:

Log 110 = 2.041

Step-by-step explanation:

Log 110 can be simplified and reduced to

Log 110 = log (10*11)

Log 110 = log10 + log11

But log10 = 1

Log 11= unknown = x

10^x= 11

X= 1.0413926

Log 110 = 1+1.0413926

Log110 = 2.0413926

Log 110 = 2.041

The probability that a member of a certain class of homeowners with liability and property coverage will file a liability claim is 0.04, and the probability that a member of this class will file a property claim is 0.10. The probability that a member of this class will file a liability claim but not a property claim is 0.01. Calculate the probability that a randomly selected member of this class of homeowners will not file a claim of either type.

Answers

Answer:

The probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.

Step-by-step explanation:

Denote the events as follows:

X = liability claim will be filled

Y = property claim will be filled

The information provided is:

P (X) = 0.04

P (Y) = 0.10

P (X ∩ Y') = 0.01

The probability that a randomly selected member of the class of homeowners will not file a claim of either type will be given by:

[tex]P[(X\cup Y)']=1-P(X\cup Y)=1-[P(X)+P(Y)-P(X\cap Y)][/tex]

According to the law of total probability:

[tex]P(B)=P(B\cap A)+P(B\cap A')[/tex]

Use the law of total probability to determine the value of P (X ∩ Y) as follows:

[tex]P(X)=P(X\cap Y)+P(X\cap Y')\\\\P(X\cap Y)=P(X)-P(X\cap Y')\\\\=0.04-0.01\\\\=0.03[/tex]

The value of P (X ∩ Y) is 0.03.

Compute the value of P (X ∪ Y) as follows:

[tex]P[(X\cup Y)']=1-P(X\cup Y)[/tex]

                   [tex]=1-[P(X)+P(Y)-P(X\cap Y)]\\\\=1-[0.04+0.10-0.03]\\\\=1-0.11\\\\=0.89[/tex]

Thus, the probability that a randomly selected member of this class of homeowners will not file a claim of either type is 0.89.

Find the value of z Subscript alpha divided by 2 that corresponds to a confidence level of​ 89.48%.

Answers

Answer:

For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]

Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:

[tex] z_{\alpha/2}= \pm 1.62015[/tex]

And we can use the following excel code for example:

"=NORM.INV(0.0526,0,1)"

Step-by-step explanation:

For this case we know that the confidence level is 89.48% or 0.8948 and the significance would be: [tex] \alpha=1-0.8948 = 0.1052[/tex] and the value of [tex]\alpha/2 =0.0526[/tex]

Now we need to find a quantile in the normal standard distribution who accumulate 0.0526 of the area on each tail of the normal standard distribution and we got:

[tex] z_{\alpha/2}= \pm 1.62015[/tex]

And we can use the following excel code for example:

"=NORM.INV(0.0526,0,1)"

Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 12 ft high? (Round your answer to two decimal places.)

Answers

Answer:

0.13 ft/min

Step-by-step explanation:

We are given that

[tex]\frac{dV}{dt}=15ft^3/min[/tex]

We have to find the increasing rate of change of height of pile  when the pile is 12 ft high.

Let d be the diameter of pile

Height of pile=h

d=h

Radius of pile,r=[tex]\frac{d}{2}=\frac{h}{2}[/tex]

Volume of pile=[tex]\frac{1}{3}\pi r^2 h=\frac{1}{12}\pi h^3[/tex]

[tex]\frac{dV}{dt}=\frac{1}{4}\pi h^2\frac{dh}{dt}[/tex]

h=12 ft

Substitute the values

[tex]15=\frac{1}{4}\pi(12)^2\frac{dh}{dt}[/tex]

[tex]\frac{dh}{dt}=\frac{15\times 4}{\pi(12)^2}[/tex]

[tex]\frac{dh}{dt}=0.13ft/min[/tex]

Order the numbers from least to greatest based on their absolute values.

|23|, |−37|, |−6|, |18|, |−24|, |2|

Answers

Answer:

/-37/, /-24/, /-6/, /2/, /18/, /23/

simplify (6^7)^3
will give brainlist

Answers

Answer:

The answer is D.

Step-by-step explanation:

You have to apply Indices Law,

[tex] { ({a}^{m}) }^{n} \: ⇒ \: {a}^{mn} [/tex]

So for this question :

[tex] { ({6}^{7}) }^{3} [/tex]

[tex] = {6}^{7 \times 3} [/tex]

[tex] = {6}^{21} [/tex]

My son and I are stuck on this one. Can anyone give some insight to this problem? Thank you.

Answers

Answer:

I made is clear for you, now you may match each one

Step-by-step explanation:

f(1)= 11, f(n)= 3*f(n-1)

11*3= 33, 33*3= 99, 99*3= 297, ...11, 33, 99, 297...

⊕ middle

f(1)= -18, f(n)= f(n-1)+21

-18+21= 3, 3+21= 24, 24+21= 45, ...-18, 3, 24, 45, ...

f(1)= -18, f(n)= f(n-1) + 22

-18+22= 4, 4+22= 26, 26+22= 48, ...-18, 4, 26, 48, ...

f(1)= -18, f(n)= 2*f(n-1)

-18*2= -36, -36*2= -72, -72*2= -144, ...- 18, -36, -72, -144...

⊕ bottom

f(1)= -18, f(n)= 6*f(n-1)

-18*6= -108, -108*6= -648, -648*6= -3888, ...- 18, - 108, - 648, -3888, ...

⊕ top

f(1)= 11, f(n)= f(n-1) + 22

11+22= 33, 33+22= 55, 55+22= 77, ...11, 33, 55, 77, ...

А
What is the measure of ZDAB?
&
B
Enter your answer in the box.
D
96°
C
Next​

Answers

Answer:

  84°

Step-by-step explanation:

Adjacent angles in a parallelogram are supplementary:

  ∠A = 180° -96°

  ∠A = 84°

PLEASE HELP

Compare the number of x intercepts of f(x)=x^2 and g(x)= (x-4)^2. Tell me the transformations involved and how g(x) moves from the parent graph.

Answers

Answer

g(x) moves 4 spaces to the left compared to f(x),  

when g(4)=0  when f(0)=0

when g(3)=1   when f(-1)=1

...

and so on

Account A and Account B both have a principal of $2,000 and an annual interest rate of 5%. No additional deposits or withdrawals are made. Account A earns simple interest. Account B earns interest compounded annually. Compare the amounts in the two accounts after 20 years. Which earns more interest? How much more?

Answers

Answer:

Which earns more interest = Account B

How much more = $1,306.60

Step-by-step explanation:

Given;

Principal P = $2,000

Interest rate r = 5% = 0.05

Time t = 20 years

For account A;

Simple interest = P×r×t

Substituting the values;

Simple interest = 2,000 × 0.05 × 20 = $2000

Interest on account A = $2,000

For account B;

Compound interest

Final amount = P(1 + r)^t

Since it's compounded annually

Substituting the values;

Final amount = 2000(1+0.05)^20

Final amount = $5306.60

Interest = final amount - principal = $5306.60 -$2000

Interest = $3,306.60

Therefore, account B earns more interest.

Difference = account B interest - account A interest

Difference = $3,306.60 - $2,000

Difference = $1,306.60

Mitch opened a retirement account that has an annual yield of 4.2% compounding annually. He is planning on retiring in 13 years. How much must he deposit into that account each year so that he can have a total of $1,000,000 by the time he retires?

Answers

Answer:

P = 4878

Step-by-step explanation:

So we'll use the formula

A = p(1+r/n)^ (nt)

A = 1000000

P is the unknown

R = 4.2

N = 13

T = 13

1000000= p ( 1+ 0.42/13)^ 169

1000000 = p (1.032)^169

1000000= p 205

P = 4878

Please help me with this problem

Answers

Answer:

10

-5

Step-by-step explanation:

5 - -5

Subtracting a negative is like adding

5+5 = 10

-9 - -4

-9+4

-5

Answer:

Step-by-step explanation:

5+5 = 10

-9+4 = -5

At Central High School, 55% of students play a school sport. Also, 24% of the student population is in ninth grade. To ninth graders are allowed to play school sports. If two students are selected at random to receive a gift card, what is the probability that one will go to a student athlete and one will go to a freshman? Write the answer as a percent rounded to the nearest tenth of a percent.

Answers

Answer:

Probability that one of the giftcards will go to a student athlete and one will go to a freshman = 26.4%

Step-by-step explanation:

At Central High School, 55% of students play a school sport. Also, 24% of the student population is in ninth grade. No ninth graders are allowed to play school sports. If two students are selected at random to receive a gift card, what is the probability that one will go to a student athlete and one will go to a freshman? Write the answer as a percent rounded to the nearest tenth of a percent.

Solution

Probability that a student plays a school sport, that is, probability that a student is a student athlete = P(S) = 55% = 0.55

Probability that a student is in the ninth grade, that is, probability that a student is a freshman = P(F) = 24% = 0.24

It was given that no freshman is allowed to play sports, hence, it translates that the event that a student is a student athlete and the event that a student is a freshman are mutually exclusive.

P(S n F) = 0

If two students are then picked at random to receive a gift card, we require the probability that one will go to a student athlete and one will go to a freshman.

Probability that the first one goes to a student athlete = P(S) = 0.55

Probability that the second one goes to a freshman ≈ 0.24

Probability that the first one goes to a freshman = P(F) = 0.24

Probability that the second one goes to a student athlete ≈ 0.55

Probability that one will go to a student athlete and one will go to a freshman

= (0.55 × 24) + (0.24 × 0.55)

= 0.132 + 0.132

= 0.264

= 26.4% in percent to the nearest tenth.

Hope this Helps!!

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