When the two forces act towards concurrently about an object, then their resultant kind of force will have the largest magnitude so that the angle among the forces is zero. Option (1).
Let θ₁ and θ₂ be two main angles among the the two forces with the direction of motion.
To maintain the motion in indicated direction, the net force will be,
F = cos θ₁ + cos θ₂
= (cos θ₁ + cos θ₂)
= cos [(θ₁+θ₂)/2] cos[(θ₁-θ₂)/2]
The maximum amount of value of the cosine function is always 1, which occurs when its argument will be zero.
Therefore the maximum value of F occurs when
θ₁ + θ₂ = 0
or
θ₁ - θ₂ = 0
Add the two equations to obtain
2 θ₁ = 0 => θ₁ = 0
Also, θ₂ = θ₁ = 0.
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Correct Question:
Two forces act concurrently on an object. their resultant force has the largest magnitude when the angle between the forces is
1. 0
2. 30
3. 90
4. 180
Light of wavelength 550 nm illuminates a double slit, and the interference pattern is observed on a screen behind the slit. The third maximum is measured to be 2.8 cm from the central maximum. The slits are then illuminated with light of wavelength 440 nm.
How far is the fourth maximum from the central maximum?
The fourth maximum is measured to be 2.97 cm from the central maximum when slits are illuminated with light of wavelength 440 nm.
The interference or bending of waves passing through an aperture around the corner of an obstacle or into the geometric shadow area of the obstacle/aperture is defined as diffraction. Secondary sources of propagating waves are diffractive objects or apertures. It is the process by which a ray or other wave system expands as it passes through a narrow aperture or edge. It is usually the result of interference between the generated waveforms.
Given,
[tex]\lambda = 550 nm=550*10^{-9}n[/tex]
[tex]y_3 = 2.8 cm = 2.8 * 10^{-2} m[/tex]
The third maximum from the central maximum can be determined by
[tex]y_3 = \frac{3D \lambda}{d}\\\\2.8*10^{-2}=\frac{3*550*10^{-9}D}{d}\\\\\frac{2.8*10^{-2}}{3*550*10^{-9}}=\frac{D}{d}\\\\0.0169*10^6=\frac{D}{d}[/tex]
Now, the fourth maximum from the central maximum can be determined by,
Now, [tex]\lamda = 440 nm =440 *10^{-91} m[/tex]
[tex]y_4 = \frac{4D \lambda }{d}\\\\y_4=4*0.0169*10^6*440*10^{-9}\\\\y_4=29.744*10^{-3}m=2.97 cm[/tex]
Thus, the fourth maximum is measured to be 2.97 cm from the central maximum
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earth's atmosphere is most transparent to all wavelengths of light. earth's atmosphere is most transparent to all wavelengths of light. infrared visible x-ray ultraviolet both visible and ultraviolet
Earth's atmosphere is transparent for waves like visible light and microwaves is correct statement.
A wave is a planned, systematic transfer of disturbances from one place to another. In addition to the waves that move across the water's surface, which are the most well-known waves, there are also waves in sound, light, and the motion of subatomic particles. In the simplest waves, the disturbance oscillates repeatedly at a fixed frequency and wavelength (see periodic motion). Mechanical waves, like sound, need a medium to move, in contrast to electromagnetic waves, which can do so in a vacuum and do not need one (see electromagnetic radiation). How a wave moves through a medium depends on its properties.
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radio frequencies (rf) can set off electronic initiating devices and some very sensitive explosives in the same manner as static electricity. electronic communication transmissions should not occur within a minimum of of suspected explosives.
Radio frequency (RF) is a unit of measurement used to describe the rate of oscillation of electromagnetic radiation spectrum, or electromagnetic radio waves, with frequencies as high as 300 gigahertz (GHz) and as low as 9 kilohertz (kHz).
What is RF in radio?The electromagnetic "spectrum" refers to all electromagnetic radiation in its collective form. Electromagnetic energy includes, for example, the radio waves and microwaves that transmitting antennas emit. "Radiofrequency" or "RF" energy or radiation is the term used to refer to all of them.The most often used frequencies are those that range from 500 MHz to 3 GHz because they provide a balanced set of benefits in terms of transmission range, capacity to handle large data rates, and antennae size. Most radar systems employ the X bands (8–12 GHz).Furthermore, you must have your radio receiver tuned to a specific frequency in order to pick up the information carried by these waves. It so happens that 2.4 GHz and 5 GHz are the WiFi frequencies. Your microwave's frequency and these waves are extremely comparable.To Learn more About Radio frequency refer To:
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A photon is incident on a Hydrogen atom that is in the ground state, resulting in an ejected electron. Which of the following regions of the electromagnetic spectrum could that photon be associated with? Visible Infrared Radio UV?
UV (Ultraviolet) is the regions in the electromagnetic type of spectrum that could photon must be associated with it. Option (4)
Ultraviolet radiation will reaches the Earth's floor is made of forms of rays, referred to as UVA and UVB. Ultraviolet radiation additionally comes from solar lamps and tanning beds. It can reason pores and skin damage, untimely aging, melanoma, and different forms of pores and skin cancer.
A photon become absorbed via way of means of a hydrogen atom in its floor state, and the electron become precipitated to the 5th orbit. When the excited atom returned. to its floor state, seen and different quanta had been emitted. Absorbed mild is mild that is not visible at the same time as emitted mild is mild this is visible. Emission is while electrons go back to power levels. Absorption is while electrons advantage power and soar to better power levels.
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Correct Question:
A photon is incident on a Hydrogen atom that is in the ground state, resulting in an ejected electron. Which of the following regions of the electromagnetic spectrum could that photon be associated with?
1. Visible
2. Infrared
3. Radio
4. UV (Ultraviolet).
Ultraviolet radiation has frequencies from 3.0×1015 to 3.0×1016 Hz, whereas the frequency region for gamma ray radiation is 3.0×1019 to 3.0×1024 Hz.
We can say that:
1. The speed of ultraviolet radiation is _________ higher than/ lower than/the same as gamma ray radiation.
2. The wavelength of ultraviolet radiation is ________ longer than /shorter than/ the same as gamma ray radiation.
What is the maximum number of orbitals that can be identified with the following quantum numbers: n = 3, ℓ = 0
a. 7
b. 8
c. 18
d. 1
e. 2
1) The same as gamma rays. As we know all electromagnetic radiations travel with speed of light.
2) longer than gamma rays
As we know, higher the frequency lower is the wavelength.as ultraviolet has lower frequency than gamma rays.so it has longer wavelength.
3) n=3 ,l=0 ,hence it is 3s orbital so it has 1 orbital.
(d) is correct.
The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.
By comparing the values of the fields you provide, a straightforward frequency analysis generates a report that shows each value for those fields along with the frequency at which it appears.
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8
Figure 2.24 shows a model of a skyscraper which Omar made
for the school exhibition. It is mounted on a firm plastic base
and has a total weight, W, of 4.0 N. Omar applies a force Fas
shown to test the stability of his model.
Calculate the minimum value of F required to cause the model
to rotate about point P.
Answer:
24-997
Explanation:
which of the following is not a type of electromagnetic wave with lower energy than visible light waves? microwaves| radar waves| the waves that carry AM or FM broadcasts| the sound waves coming from your transistor radio| the waves that carry television transmissions
The sound waves coming from your transistor radio is not a type of electromagnetic wave with lower energy than visible light waves.
What is electromagnetic wave explain?
Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.
How do electromagnetic waves travel?
Electromagnetic waves differ from mechanical waves in that they do not require a medium to propagate. This means that electromagnetic waves can travel not only through the air and solid materials but also through the vacuum of space.
What are the 7 types of electromagnetic waves?
In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. Microwaves (like the ones used in microwave ovens) are a subsection of the radio wave segment of the EM spectrum.
Thus, sound waves coming from your transistor radio are the correct option.
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when striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.0 m/s in 0.14 s .
The acceleration of the predatory fish is 28.57 m/s².
What is the acceleration of predatory fish?
The acceleration of the predatory fish is the rate of change of velocity of the predatory fish with time.
Mathematically, the formula for acceleration is given as;
a = Δv / Δt
where;
Δv is the change in velocity of the predatory fishΔt is the change in time of motion of the predatory fishThe given parameters include the following;
the change in velocity of the predatory fish = 4 m/sthe change in time of motion of the predatory fish = 0.14 sa = (4 m/s) / (0.14 s)
a = 28.57 m/s²
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The complete question is below:
when striking, the pike, a predatory fish, can accelerate from rest to a speed of 4.0 m/s in 0.14 s . find the acceleration?
When forces are balanced they?
Answer:
There is no change in motion it is constant
Explanation:
Balanced forces are equal in size and opposite in direction. When forces are balanced, there is no change in motion. In one of your situations in the last section, you pushed or pulled on an object from opposite directions but with the same force.
A 110 kg running back carries the ball south at 8 m/s. A 130 kg linebacker runs to make the tackle going
north at 5 m/s. In their collision, the linebacker wraps his arms around the runner and makes it an inelastic
collision. How fast are they moving right after the collision (before they fall to the ground)?
The speed of the runners after the inelastic collision is 0.96 m/s towards the south.
What is the final speed of the runners after the collision?
The final speed of the runners after the collision is calculated by applying the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = v(m₁ + m₂)
where;
m₁ is the mass of the running backu₁ is the mass of the running backm₂ is the mass of the linebackeru₂ is the initial speed of the linebackerv is the final speed of the runners after the collision110 (8) + 130(-5) = v (110 + 130 )
880 - 650 = 240v
230 = 240 v
v = 230 / 240
v = 0.96 m/s
Thus, after the collision the runners will be running at lower speed towards the south. The collision of the runners is inelastic meaning they will have the same velocity after the collision.
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Which if the following is an example of good conflict mangament
An example of good conflict management is empathizing with other players. The Option C is correct.
What is a conflict management?Conflict management refers to the process of limiting the negative aspects of conflict while increasing the positive aspects of conflict. Furthermore, a conflict management means the practice of being able to identify and managing conflicts sensibly, fairly and efficiently.
Since conflicts are a natural part of the workplace, it is very important that there are people who understand conflicts and know how to resolve them. As everyone is striving to show how valuable they are, this can lead to disputes with other members of the team.
Some of the aim of conflict management is to enhance learning and group outcomes including an effectiveness or performance in an organizational setting. Properly managed conflict can improve group outcomes.
Missing options " A. Letting an opponent's "trash-talking" break your focus. B. Throwing a baseball bat down in anger. C. Empathizing with other players. D. Yelling at other players.
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when light passes from a material with a high index of refraction into material with a low index of refraction: is the meaning of?
When light passes from a material with a high index of refraction into material with a low index of refraction, it is the meaning of a)incident angle. So, correct option is a.
Refraction of light is quite possibly of the most regularly noticed peculiarity, however different waves like sound waves and water waves additionally experience refraction. Refraction makes it feasible for us to have optical instruments, for example, amplifying glasses, focal points and crystals. It is likewise a direct result of the refraction of light that we can shine light on our retina.
The refractive file, additionally called the record of refraction, depicts how quick light goes through the material.
The refractive index is dimensionless in nature. For a given material, the refractive record is the proportion between the speed of light in a vacuum (c) and the speed of light in the medium (v). On the off chance that the refractive record for a medium is addressed by n, it is given by the accompanying recipe:
n=c/v
where n is refractive index, c is the speed of light in vacuum and v is the speed of light in other medium.
Hence, correct option is a.
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(Complete question) is:
when light passes from a material with a high index of refraction into material with a low index of refraction: it is the meaning of?
a)incident angle
b)speed of light
c)refraction angle
d)all of the above
Two blocks (X and Y) are in contact on a horizontal frictionless surface. A 36-N constant force is applied to X as shown. The force exerted by X on Y is:
D 30 N F = ma yields 36N = 24kga, or a 1.5m/s2 acceleration. Due to the 4kg block's contact force, the 20kg block is accelerating. 20 kg at 1.5 m/s2 contact equals 30 N.
What is accelerating?
In mechanics, acceleration refers to the rate at which an object's velocity with respect to time varies. They are accelerations and vector quantities.
The direction of an object's acceleration is determined by the direction of the net force acting on it.
Due to the 4kg block's contact force, the 20kg block is accelerating. 20 kg at 1.5 m/s2 contact equals 30 N.
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Which of the following best describe a displacement pump? A. Reciprocating pump B. Propeller pump C. Centrifugal D. Jet pump
Emptying trenches, filling tanks, supplying water for boilers, and all of the above tank refuelling
What do you name a drainage trench?An exclusive variety of floor drain with a predominately trough- or channel-shaped body is known as a trench drain (also known as a channel drain, line drain, slot discharge, linear drain, or strip drain). It is utilised to contain utility lines or industrial pollution as well as for the quick evacuation of surface water.
What makes a trench different from a drain?Aside from what we've mentioned here, the distinction between a French dump and a trench drain is that the former French drain is used for water that is underground, whilst a trench drain redirects extra water from a surfac.e
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the forearm in the figure(figure 1) accelerates a 3.2 kg ball at 7.5 m/s2 by means of the triceps muscle, as shown. a) Calculate the torque needed. Ignore the mass of the arm. Answer in m*Nb) Calculate the force that must be exerted by the triceps muscle. Answer in N
The calculated answer for the torque is 7.812 Nm and the force is 25.2 N
In the given question, we have to find the torque needed and the force exerted by the triceps muscle.
We know that, when there is a net torque on the system, it causes angular acceleration and the angular momentum is no more conserved.
Here let be the arm is massless.
The torque can be written as
τ=Iα
Where I is the moment of inertia.
α is the angular acceleration.
So,
τ=mR^2 α
τ=mRa
Here we have used the relationship between angular and tangential acceleration, which is: α=a/R.
The position vector is: R = 0.31
The mass is: m =3.6
The tangential acceleration is: a =7 m/s2
So, the torque will be,
τ=3.6*0.31*7
=7.812
So, the required torque is 7.812 Nm.
And we know that torque is: τ=F.R
So, force is F = τ/r
= 7.812/0.31
=25.2 N
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The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends.Find the frequency of the lowest note a piccolo can play, assuming the speed of sound in air is 340 m/s. Opening holes in the side effectively shortens the length of the resonant column. If the highest note a piccolo can sound is 4000 Hz, find the distance between adjacent antinodes for this mode of vibration.
The lowest note a piccolo can play has a frequency of (f)= 531.25 Hz. and for this mode of vibration, the distance (d) between neighboring antinodes is equal to 4.25 cm.
(a)The formula f = v/2L can be used to determine the frequency of the lowest note a piccolo can play
where v = 340 m/s, the speed of sound in air and
L is length = 32 cm is equal to 0.32 meters as given ,
therefore f = 340/(2 * 0.32)
f = 531.25 Hz
(b) The wavelength formula is λ = v/f.
Thus; λ = 340/4000 \s
λ = 0.085 m
Now, for the specified mode of vibration,
the distance between consecutive antinodes is given by (d )= λ/2 = 0.085/2
d = 0.0425 m.
As a result, d = 4.25cm
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Miguel (m=72) and Fernando (89 kg) board the bumper cars at the local carnival. Miguel is moving at a velocity of 4 m/s when he rear-ends Fernando who is at rest in his path. Fernando and his 125-kg car lunge forward at 2 m/s. Determine the post-collision velocity of Miguel and his 125-kg car.
Miguel will be travelling at 1.2 m/s inside the opposite direction following the collision, according to this.
Define collision.
A collision in physics is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.
The conservation of momentum law allows for the calculation of Miguel's post-collision speed.
Mass times velocity (p=mv), a vector quantity, equals momentum.
Before the collision, Miguel and Fernando's car had a momentum of 782 kg*m/s (m1=72 kg) (v1=4 m/s) + (m2=125 kg) (v2=0 m/s).
The momentum of the system following the collision is equivalent to (m1=72kg)(v1=?m/s) + (m2=125kg)(v2=2m/s) = 782 kg*m/s.
Miguel's comment velocity is -1.2 m/s, as determined by solving for v1. Miguel will be travelling at 1.2 m/s inside the opposite direction following the collision, according to this.
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find the mass in [g] of the quantity of ice required at 0oc that 10 grams of 100oc steam will melt completely. the heat of vaporization of water at standard temperature and pressure is 2256 kj/kg. the heat of fusion of ice is 334 kj/kg. incorrect answer:
The mass of ice required at 0oc that 10 grams of 100oc steam will melt completely is 80.07 g.
The amount of energy that must be supplied to a solid substance (typically in the form of heat) in order to cause a change in its physical state and convert it to a liquid is known as latent heat of fusion (when the pressure of the environment is kept constant). The latent heat of fusion of one kilogramme of water, for example, is 333.55 kilojoules, which is the amount of heat energy that must be supplied to convert one kilogramme of ice without changing the temperature of the environment (which is kept at zero degrees Celsius).
Given,
mass of steam, [tex]m_s[/tex] = 10g = 0.01 kg
Latent heat of fusion of ice ,[tex]L_f= 334kj/kg[/tex]
Latent heat of vaporization of water, [tex]L_v=2256kj/kg[/tex]
change of temperature, [tex]\delta T=100-0=100\textdegree\ C[/tex]
The amount of heat cooling can be determined by.
[tex]m_{ice}L_f=m_sL_v+m_sS \delta T[/tex]
Here, S= specific heat constant i.e [tex]4.184 kj/kg[/tex]
[tex]m_{ice}L_f=(0.01*2256)+(0.01*4.184*100)\\\\m_{ice}*334=22.56+4.184\\\\m_{ice}*334=26.744\\\\m_{ice}=\frac{26.744}{334}=0.0807kg=80.07 g[/tex]
Thus, the mass of quantity of ice is 80.07 g.
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A person places a cup of coffee on the roof of her car while she dashes back into the house for a forgotten item. When she returns to the car, she hops in and takes off with the coffee cup still on the roof. A) If the coefficient of static friction between the coffee cup and the roof of the car is 0.20, what is the maximum acceleration the car can have without causing the cup to slide? Ignore the effects of air resistance. B) What is the smallest amount of time in which the person can accelerate the car from rest to 24 m/s and still keep the coffee cup on the roof?
(a) The maximum acceleration the car can have without causing the cup to slide is 1.96 m/s².
(b) The smallest amount of time in which the person can accelerate the car from rest to the final speed is 12.25 seconds.
What is the maximum acceleration of the car?
The maximum acceleration the car can have without causing the cup to slide is calculated as follows;
For the car not to slide, the applied force must equal the force of friction, so the that the acceleration of the car is zero.
F - Ff = ma
F - Ff = 0
F = Ff
ma = μmg
a = μg
where;
μ is the coefficient of static frictiong is acceleration due to gravitya = 0.2 x 9.8 m/s²
a = 1.96 m/s²
The smallest amount of time in which the person can accelerate the car from rest to the final speed is calculated as follows;
v = u + at
v = 0 + at
t = v/a
t = (24 m/s) / (1.96)
t = 12.25 s
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How do you calculate the rotation speed for a rotating living quarters on a spaceship for 1 g?
To produce the equal of 1 G, you would require a superstructure with a diameter of around 900m and a leisurely 1rpm.
For artificial gravity, how so many rotations per minute are required?Solution:The orbiter must rotate at a rate of 0.04 revolutions per second, or 2.4 revolutions per minute, to imitate Earth's gravity.
How do you determine the g-force in a turn?Just use following formula to translate rotations per minute (RPM) into relative centrifugal (RCF), also known as g force:RCF = (RPM)2 × 1.118 × 10-5 × r.The length of the particle from the rotating center and the rotational speed, measured in RPM, both affect the relative centrifugal force.
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A copper rod has a length of 60 cm at room temperature (220C). The coefficient of expansion of copper is 17 x 10-6 /Co, its specific heat is 386 J/(kg K), its melting point is 1356 K and its heat of fusion is 207 kJ/kg. The copper rod is heated so that its length increases to 60.3 cm a. What is the new temperature of the copper rod? T 316 b. If the mass of the rod is 0.52 kg, how much thermal energy was added to the rod? Q 5.9 x104 J c. If the mass of the rod is 0.52 kg, how much total thermal energy will need to be added to the copper if we want to completely melt the copper rod starting at room temperature? Qー ? x105 J
There are 3 questions here that need to be solved.
a. The new temperature of the copper rod is 316°C (rounded)
b. If the mass of the rod is 0.52kg, the thermal energy that was added to the rod is 5.9 * 10^4J
c. If the mass of the rod is 0.52kg, the total thermal energy will need to be added to the copper if we want to completely melt the copper rod starting at room temperature by using coefficient of thermal expansion of copper at 17 * 10^-6 / C° is 3.21 * 10^5J
What is coefficient of thermal expansion?It refers to the rate at which material expands with increase in temperature. More specifically, this coefficient is determined at constant pressure and without a phase change, such as the material is expected to still be in its solid or fluid form.
Now, moving to the question.
a. What is the new temperature of the copper rod?
L₂ = L₁ + L₁ * α * (t₂ - t₁)
Where
L2 is length of the rod that already increased
L1 is the original length of the rod
α is coefficient of expansion of copper
t2 is the new temperature
t1 is the original temperature
60.3cm = 60cm + 60cm * 17 * 10^-6 * (t₂ - 22°C)60.3
= 60 + 0.00102 * (t₂ - 22)0.3 = 0.00102 * (t₂ - 22)t₂ - 22
= 0.3 / 0.00102 t₂ - 22 = 294.12
t₂ = 316°C (rounded)
b. If the mass of the rod is 0.52kg, how much thermal energy was added to the rod?
Q = m * c * Δt
m = mass
c = coefficient
= 0.52 * 386 * (316 - 22)
= 59011.68
= 5.9 * 10^4 J (rounded)
c. If the mass of the rod is 0.52kg, how much total thermal energy will need to be added to the copper if we want to completely melt the copper rod starting at room temperature?
Q = m * c * Δt + m * L fusion
= m * c * (t melt - t₁) + m * L fusion
= 0.52 * 386 * (1356 - (22 + 273)) + 0.52 * 207 * 10^3Q
= 320603.92
Q = 3.21 * 10^5 J
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A 75 kg person stands on a metric bathroom scale that reads in Newtons while in an elevator. The
elevator accelerates upward at 3 m/s/s. Determine the person's actual weight and the reading of the
scale under these conditions.
Answer: 735 N (actual), 960 N (accelerating up)
Explanation:
Actual weight = W = mg = (75 kg)(9.8 m/s²) = 735 N
Scale reading = N (normal force acting on the person by the elevator) = mg + ma = 735 N + (75 kg)(3.0 m/s²) = 735 N + 225 N = 960 N
That's why you feel heavier when you are accelerating up in an elevator
a cube of mass m sliding without frictionat speed v0. It undergoes a perfectly elastic collision with the bottom tip of a rod of length d and mass M = 2m. The rod is pivoted about a frictionless axle through its center, and initially it hangs straight down and is at rest. What is the cube's velocity - both speed and direction - after the collision?
The cube's velocity - both speed and direction - after the collision is [tex]v=\frac{v_0}{5}[/tex].
What is kinetic energy conservation?
Kinetic energy, which may be seen in the movement of an object, particle, or group of particles, is the energy of motion. Any moving item uses kinetic energy, such as a person walking, a baseball being thrown, a piece of food falling off a table, or a charged particle in an electric field.
From kinetic energy conservation:
[tex]\begin{gathered}\frac{m v_0^2}{2}=\frac{m v^2}{2}+\frac{I \omega^2}{2} \\I=\frac{M d^2}{12}=\frac{2 m d^2}{12}=\frac{m d^2}{6} \\\frac{m v_0^2}{2}=\frac{m v^2}{2}+\frac{m d^2 \omega^2}{12} \\v_0^2=v^2+\frac{d^2 \omega^2}{6} \Longrightarrow(1)\end{gathered}[/tex]
From angular momentum conservation:
[tex]\begin{gathered}\frac{m v d}{2}=I \omega \\\frac{m v_0 d}{2}=\frac{m d^2 \omega}{6} \\v_0=\frac{d \omega}{3} \\d^2 \omega^2=9 v_0^2 \Longrightarrow(2)\end{gathered}[/tex]
Substituting (2) into (1):
[tex]\begin{gathered}v^2=v_0^2-\frac{3 v_0^2}{2} \\v^2=-\frac{v_0^2}{2}\end{gathered}[/tex]
The correct answer is: [tex]v=\frac{v_0}{5}[/tex]
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In the figure below, the driver of a car on a horizontal road makes an emergency stop by applying the brakes so that all four wheels lock and skid along the road. The coefficient of kinetic friction between tires and road is 0.42. The separation between the front and rear axles is L = 4.2 m, and the center of mass of the car is located at distance d = 1.8 m behind the front axle and distance h = 0.70 m above the road. The car weighs 11 kN. Find the magnitude of the following. (Hint: Although the car is not in translational equilibrium, it is in rotational equilibrium.)
(a) The braking acceleration of the car.
m/s2
(b) The normal force on each rear wheel.
N
(c) the normal force on each front wheel.
N
(d) the braking force on each rear wheel.
N
(e) the braking force on each front wheel.
N
Equation gives a straight result of 8.2*10^2N for friction on each rear wheel. In a similar way, 1.4*10^2N is the result for friction on the front rear wheel. The acceleration is 4.112m.s^2 in magnitude.
We can apply Equation, as suggested in the problem statement. Taking into account the torques around the Centre of mass of the vehicle and the fact that the friction forces are exerted horizontally at the bottom of the wheels, the total friction force there is 3.92m, located 0.75 metres vertically below the centre of mass.
Equation gives the following results for friction on each rear wheel:
friction = (0.42)(3929/2), which is 8.2*10^2N.
In a similar vein, friction on the front and back wheels
friction is (0.42)(7071/2) = 1.4 * 10^2 N
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figure 21-5b shows the concentration profile of a band of material after it has traveled through a column for 2 min and for 26 min. why is the band broader after 26 min? (b) explain why a chromatographic separation normally has an optimum flow rate that gives the best separation.
The broader band because of mobility of ions and because of peaks developed it has optimum flow rate.
There are two characteristics of the concentration profile that are important in determining the efficiency of a column and its ability to separate or separate subsequent solute zones. The first peak maximum refers to the position of maximum concentration in the peak. To obtain sufficient resolution, the maxima of two adjacent peaks must be separated from each other. Such separations depend on the nature of the solutes and the selectivity of the stationary and mobile phases.
A second characteristic that is important for efficiency and resolution is peak width. Peaks with distant maxima are still broad and may not fully resolve the solutes. For this reason, peak width is very important in chromatography.
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a lunar eclipse occurs when group of answer choices the earth lies directly between the sun and the moon the sun lies directly between the earth and the sun the moon lies directly between the sun and the earth
A lunar eclipse occurs when the earth is directly between the sun and the moon, thus, its shadow creates a lunar eclipse. Correct answer: letter A.
A lunar eclipse occurs when the Earth's shadow is cast on the surface of the Moon. This can only happen if the Sun, Earth, and Moon are all aligned in a straight line. In this configuration, the Earth is directly between the Sun and the Moon, blocking the light from the Sun and casting a shadow onto the Moon.
What is a lunar eclipse?Is an astronomical event that occurs when the Moon passes directly behind Earth and into its shadow. During a lunar eclipse, the Moon will appear dark as it is illuminated by only the faint, red-orange light of the sun scattered by Earth's atmosphere.
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Problem Statement: Two 8-kg blocks A and B resting on shelves are connected by a rod of negligible mass. Knowing that the magnitude of a horizontal force P applied at C is slowly increased from zero, determine the value of P for which motion occurs, and what that motion is, when the coefficient of static friction between all surfaces is (a) js = 0.40, (b) ps = 0.50. Figure: с P 100 mm B 8 kg -200 mm 25° AO 8 kg
In comparison to protons and neutrons, electrons have a very low mass (9.10938356 10 31 kg). An electron weighs about 1837 times as much as a proton, with a mass of (1.67262191027kg). Atoms' nuclei almost entirely account for their mass. There are only protons and neutrons present inside the nucleus.
In physics, what is insignificant?
Negligible refers to the ability to ignore or neglect. There are occasions when a force in physics is so little that its impact on the overall phenomenon is negligible. When you throw an apple up, for instance, the apple draws the earth, yet the earth does not move because the force the apple exerts is very little or inconsequential.
Why is mass so small?
If object A weighs 1 gram and object B weighs 1 kilogram, then object A is said to have a negligible mass in comparison to object B because it weighs so little. In mathematical problems, we typically neglect trivial values to avoid adding complexity.
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❧ What are the effects of Refraction of Light?
The following are effects of refraction of light: bending of light, change in wavelength of light, splitting of light rays.
What is Refraction?Refraction is the bending of light rays as it passes from one medium into another. Light rays refracts whenever it travels at an angle into a substance with a different refractive index. This change of direction is caused by a change in speed of the light rays. For example, when light travels from air into water, it slows down, causing it to continue to travel at a different angle or direction.
Effects of RefractionBending of lightChange in wavelength of lightSplitting of light rays.Learn more about refraction: https://brainly.com/question/27932095
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for the following surface, what is the minimum number of area vectors would you need to fully describe the area?
Only 1 area type of vector is necessary as the given surface is flat and the area vector must point either +x or -x-direction only. Option(2) is correct.
According to triangle regulation of vector addition minimal 3 coplanar vectors are had to get 0 resultant. We understand that best triangle is closed determine of minimal facet, Sides of triangle constitute vector, So the minimal range of unequal vectors whose vector sum may be 0 is 3.
Two vectors may have most cost while they're in identical direction, i.e. the perspective among them is 0°. And may have minimal cost while they're simply in contrary direction, i.e. perspective among them is 180°. Polygon described as a closed aircraft determine, having 3 or greater immediately aspects. So, the minimal range of the facet in a polygon is 3. So, a polygon with a minimal range of aspects is known as triangle.
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Correct Question:
For the following surface, what is the minimum number of area vectors would you need to fully describe the area?
A series of four direct shear tests were conducted on a dry sand. The initial size of the specimens were 50 mm by 50 mm (in horizontal plane) and 20 mm high. The following test results were reported. Test Number Vertical stress (kPa) 50 100 200 400 Shear Stress at Failure (kPa) 35.5 71 142 284 Plot the test results in normal stress-shear stress space, draw the best-fit Mohr-Coulomb failure envelope, and report the friction angle. [Note: assume that the cohesion intercept is zero.] Friction angle (degrees)
35.375 degrees is the friction angle. Four direct shear tests were performed for on a dry sand. The specimens were 50 mm by 50 mm in size at first.
Angle of internal friction, often known as friction angle, is a parameter indicating how well a unit of rock or soil can sustain a shear force. When failure simply results from a shearing stress, an angle (), measured between the normal force (N) and resultant force (R), is reached ( S ). A shear test is intended to exert stress on a test sample so that it slides out of alignment with the applied forces along a plane.
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