2018 poll of 2232 randomly selected U.S. adults found that 40.86% planned to watch at least a "fair amount" of a particular sporting event in 2018.
In 2014, 47% of U.S, adults reported planning to watch at least a "fair amount."
a. Does this sample give evidence that the proportion of U.S. adults who planned to watch the 2018 sporting event was less than the proportion who planned to do so in 2014? Use a 0.05 significance level.
b. After conducting the hypothesis test, a further question one might ask is what proportion of all U.S. adults planned to watch at least a "fair amount" of the sporting event in 2018. Use the sample data to construct a 90% confidence interval for the population proportion. How does your confidence interval support your hypothesis test conclusion?

Answers

Answer 1

a. Let p

1

 be the proportion of U.S. adults who planned to watch at least a "fair amount" of the 2018 sporting event and p

2

 be the proportion of U.S. adults who planned to do so in 2014. We want to test the following hypotheses:

H

0

:p

1

=p

2

H

a

:p

1

<p

2

We will use a significance level of α=0.05.

Our sample size is n=2232 and our sample proportion is  

p

^

=0.4086. The standard error of the sample proportion is:

SE(

p

^

)=

n

p(1−p)

=

2232

0.4086(1−0.4086)

=0.0097

Our test statistic is:

z=

SE(

p

^

)

p

^

−p

0

=

0.0097

0.4086−0.47

=−6.38

Our p-value is P(z<−6.38)=0.000000000002.

Since our p-value is less than our significance level of α=0.05, we reject the null hypothesis. There is evidence to suggest that the proportion of U.S. adults who planned to watch the 2018 sporting event was less than the proportion who planned to do so in 2014.

b. A 90% confidence interval for the population proportion is:

CI=(

p

^

−z

1−α/2

⋅SE(

p

^

),

p

^

+z

1−α/2

⋅SE(

p

^

))

CI=(0.4086−1.645⋅0.0097,0.4086+1.645⋅0.0097)

CI=(0.4002,0.4170)

We are 90% confident that the true proportion of U.S. adults who planned to watch at least a "fair amount" of the 2018 sporting event is between 0.4002 and 0.4170.

Our confidence interval does not include 0.47, the proportion of U.S. adults who planned to watch at least a "fair amount" of the sporting event in 2014. This supports our hypothesis test conclusion that the proportion of U.S. adults who planned to watch the 2018 sporting event was less than the proportion who planned to do so in 2014.


Related Questions

4.The first orange I drew from my bag is red. All oranges in my bag are red. Therefore, the second orange I drawn from my bag will be red, too.

Write the kind of argument?

Answers

Answer:

The first orange I drew from my bag is red. All oranges in my bag are red. Therefore, the second orange I drawn from my bag will be red, too. And so will the third but how many oranges do i have I DON'T KNOW

Explanation:

Question:how old am i

Peter earned 40% more money than Albert. Albert earned 20% less than Michael. Petre earned more than michael by
Select one:
a. 25%
b. 20%
c. 12%
d. 10%

Answers

Let's assume Michael earned $100.

Albert earned 20% less than Michael, which is $80.

Peter earned 40% more than Albert, which is $80 + 0.4($80) = $112.

So, Peter earned $112 - $100 = $12 more than Michael.

Therefore, the percentage that Peter earned more than Michael is (12/100) x 100% = 12%.

The answer is c. 12%.

Activity 1: Let's Value Directions: Complete the matrix by providing the advantages and disadvantages of the following concepts, then give a brief explanation. Deepen SUBJECT
1. Cloud Computing
2. Mobile Applications
3. Communication Technology
4. World Wide Web
5. E-commerce

write the (POSITIVE IMPACT)( NEGATIVE IMPACT ) (EXPLANATION)​

Answers

Cloud computing is a technology that allows users to access computing resources such as storage, processing power, and applications over the Internet.

How to explain the information

A mobile application or mobile app is a software application designed to run on a mobile device such as a smartphone or tablet.

Tools and systems used to facilitate communication between individuals or groups are called communication technologies.

The World Wide Web, also known as the Web, is an interconnected network of publications and resources accessible via the Internet.  

E-commerce, which stands for electronic commerce, is the purchasing and selling of goods and services on the internet.

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5
Select the correct answer from each drop-down menu.
AB
CD is perpendicular to
and passes through point C(5, 12).
If the coordinates of A and B are (-10, -3) and (7, 14), respectively, the x-intercept of CD
is
Reset
Next
The point
lies on
CD

Answers

CD is perpendicular to AB and passes through point C (5,12). If the coordinates of A and B are (-10, -3) and (7, 14), respectively, the x- intercept of CD is: (17, 0)

The point: (-2, 19) lies on CD.

How to explain the information

Since CD is perpendicular to AB and passes through C, we know that CD is parallel to the vector AB and passes through point C. The vector AB is:

AB = <7 - (-10), 14 - (-3)> = <17, 17>

A vector perpendicular to AB is:

n = <-17, 17>

The x- intercept of CD is: (17, 0) and the point: (-2, 19) lies on CD.

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CD is perpendicular to AB and passes through point C (5,12).

If the coordinates of A and B are (-10, -3) and (7, 14), respectively, the x- intercept of CD is:

(12, 0)

(15, 0)

(17, 0)

or (19,0).

The point:

(-5, 24)

(-2, 19)

(7, -10)

or (8, 11)

lies on CD.

The newly elected president need to decide the remaining eight spots available for cabinet here she is appointing there are 12 eligible candidate for this position where rink matters how many different ways can the member of the cabinet be appointed

Answers

Answer: There are 495 different ways the members of the cabinet can be appointed.

Explanation:

nCr+n! / (r! * (n-r)!)

Where n is the total number of items, and r is the number of items to choose.

In this case, there are 12 eligible candidates for 8 spots. So, we need to find the humber of ways to choose 8 candidates from 12, which is:

12C8 = 12!/ (8! * (12-8)!)+495

Posttest
Chiku has a poor track record of completing work assignments. She has been placed on a project with other
co-workers. Her team members will likely view Chiku as:
A) Combative
B) Unreliable
C) Trustworthy
D) Confident

Answers

Answer:

B) Unreliable

Explanation:

Based on the given information, Chiku has a poor track record of completing work assignments. Therefore, her team members are likely to view her as "unreliable".

When a plant is not strong enough to support its own weight, what is most likely the problem? O A. The plant is producing too many polysaccharides. B. The plant is not producing enough cellulose. C. The plant needs more monosaccharides to add strength. D. The plant does not have enough starch. ✔ Correct




(D) The plant is not producing enough cellulose​

Answers

Yes, you are correct. When a plant is not strong enough to support its own weight, the most likely problem is that the plant is not producing enough cellulose. Cellulose is a complex carbohydrate that provides structural support to plant cell walls. It forms strong fibers that help plants maintain their shape and rigidity. If a plant does not produce enough cellulose, its cell walls may be weak, leading to a lack of structural support and an inability to withstand the weight of the plant.[tex][/tex]

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