22. In an experiment to determine the density of a soil using a density bottle, the following measuren were recorded. Mass of empty density bottle = 42.9g Mass of density bottle full of water = 66.1g Mass of density bottle with some soil = 67.2g Mass of density bottle with soil filled up with water = 82.0g Use the above data to determine the a) Mass of water that completely filled the bottle (2 b) Volume of water that completely filled the bottle​

Answer:

vf²=vi²+2a∆x

Explanation:

The third equation of motion gives the final velocity of an object under uniform acceleration given the distance traveled and an initial velocity: v 2 = v 0 2 + 2 a d . v^2=v_0^2+2ad. v2=v02+2ad. The graph of the motion of the object.

Unit is the quantity of a constant magnitude which is used to measure the magnitudes of other quantities of the same nature.

Answer:

The standard known quantity which is used to measure a physical quantities is known as unit.

Answer:

Weight = Mass × Gravitational field strength

Explanation:

The mass of the skydiver = 70 kg

The weight of the skydiver, W, is given as follows;

W = m × g

Where-

g = The gravitational field strength ≈ 9.81 m/s²

Therefore, the equation linking weight mass and gravitational field strength is presented as follows;

Weight = Mass × Gravitational field strength

Answer:

hello

Explanation:

hello dost timi kasto cha

Answer:

334m/s

Explanation:

If you take the data you gave and insert it into the equation f=v/λ the frequency would come out to be 3.34m

334 m/s is  the Velocity of sound in air.

Wave velocity in common usage refers to speed, although, properly, velocity implies both speed and direction.

The velocity of a wave is equal to the product of its wavelength and frequency (number of vibrations per second) and is independent of its intensity.

Mathematically , v=fλ

According to the question,

Sound frequency (f)  = 100Hz

Wavelength (λ)= 3.34m

Computing the values in the formula,

v=fλ

v = 100Hz x 3.34m

v= 334m/s

Therefore,

Velocity of sound in air is 334 m/s.

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Answer:

25 mm = 0 deg C

200 mm = 100 deg C

200 - 25 = 175 = change in thread per 100 deg C

95 - 25 = 70 mm - change in thread from 0 deg C

70 / 175 * 100 = 40 deg C    final temperature at 95 mm

A simulation study that is used to learn about a planet by simulating as many conditions as possible, you can visualize what the planet might be like and learn things about it without actually visiting it. The correct option is c.

A simulation is a method of simulating a process or change in the actual world to forecast future events or to explain past events and their causes. These days, simulations are frequently carried out using computers. Scientists use simulations to find answers and to test complicated systems.

A fire drill is used in this instance to get everyone ready for an impending event. In fire drills, the fire alarm is sounded even when there isn't actually a fire.

Therefore, the correct option is c.

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Answer:

The force from the truck on the car is always equal to the force from the car on the truck.

Explanation:

According to Newton's third law; action and reaction are equal and opposite. Hence, when the big truck and small passenger car are involved in a collision, we expect that the force from the truck on the car is always equal to the force from the car on the truck. The forces on the car and the truck are equal in magnitude but opposite in direction.

This follows directly from Newton's third law of motion hence the answer above.

Answer:

Part 1; The total energy = Constant = 200 J

Part 2; Midway, the potential energy = The kinetic energy = 100 J

Explanation:

Part 1

According to the first law of thermodynamics, energy is neither created nor destroyed but changed from one form to another

The total (mechanical) energy = Potential energy + Kinetic energy = Constant

The kinetic energy given to the ball changed vertically up = 200 J

Potential energy = Mass, m × Gravity, g × Height, h

Given that the mass m of the ball and the acceleration due to gravity, g, remain the same, we have;

Potential energy ∝ The height of the ball

The potential energy at ground level = 0 J (Height , h = 0)

∴ The total (mechanical) energy = 0 J + 200 J = 200 J

At the maximum height, the ball momentarily stops, and the kinetic energy = 0 J

Therefore;

The potential energy of the ball at the maximum height, [tex]h_{max}[/tex], [tex]P.E._{max}[/tex] = 200 J

∴  [tex]P.E._{max}[/tex] = m·g·[tex]h_{max}[/tex] = 200 J

Part 2

At midway we have, the height, h = ([tex]h_{max}[/tex])/2

Therefore, [tex]P.E._{Midway}[/tex] = (m·g·([tex]h_{max}[/tex]))/2 = ([tex]P.E._{max}[/tex])/2 = (200 J)/2 = 100 J

The potential energy midway = 100 J

The  remaining 200 J - 100 J = 100 J is the kinetic energy remaining in the ball

The kinetic energy midway = 100 J

Therefore, the total energy midway = 100 J + 100 J = 200 J

Explanation:

Measurement plays an important role in our daily lives because they are useful to do basic tasks, such as taking the temperature of a child with the help of a thermometer,making time estimations,measure out medicines and find out weights, areas and volumes of different substances

answer is

Let m be the mass of both cubes. If the smaller cube has side length x, then its volume is x ³. The side lengths of the larger cube have length 4x, so the larger cube's volume is (4x)³ = 64x ³, or 64 times as large as the smaller cube.

The first cube has a density of m/x ³, while the larger one has a density of m/(64x ³) = 1/64 m/x ³, so the ratio of densities is (1/64):1, or 1:64 (larger cube to smaller cube).

Answer:

The centripetal acceleration of the stone is 5 m/s²

Explanation:

The length of the string to which the stone is attached, r = 1 m

The speed with which the string is rotated, v = 5 m/s

The centripetal acceleration, [tex]a_c[/tex], is given as follows;

[tex]a_c = \dfrac{v^2}{r}[/tex]

Therefore, the centripetal acceleration of the stone found as follows;

[tex]a_c = \dfrac{(5 \ m/s)^2}{1 \ m} = 5 \ m/s^2[/tex]

The centripetal acceleration of the stone, [tex]a_c[/tex] = 5 m/s².

Answer:

[tex] \green{ \sf \: \: 1.6 \: m {s}^{ - 2} \: \: \: is \: the \: correct \: answer}[/tex]

Explanation:

[tex] \sf \: \huge{g } _{ \small{moon}} = \frac{ {\huge{g}}_{earth}}{6} \\ \\ \sf \implies \: \sf \: \huge{g } _{ \small{moon}} = \frac{ 9.8}{6} = 1.6 \: \: m {s}^{ - 2} [/tex]

Answer:

a. Bar A is a magnet

b. Bar B is a metal or magnetic material

c. Bar D is a non-magnetic material

Explanation:

a. Bar A

Since B attracts both A and C, it shows that A and C are both magnetic. So, it is either B and A are magnets or B and C are magnets or A and C are magnets. Also, since A and C sometime attract one another and sometimes repel one another, it means that they attract when their poles are opposite and repel when their poles are negative. This show that both A and C are magnets. Thus, A is a magnet.

b. Bar B

Since B is attracted to both A and C and we know that both A and C are magnets, it implies that B is a magnetic material. Since it does not repel either A or C.

c. Bar D

Since D does not attract A, B or C, D is a non-magnetic material. Since, only a magnetic material can be attracted to magnets and we have established that both A and C are magnets and that B is magnetic. Since D is not also attracted to B, it implies that D is thus non-magnetic.

Answer:

It was created during the French Revolution in 1799 and has enabled for the international exchange of scientific and technical information. Calculating with SI units is also a lot easier than using the English system.

Explanation:

It was first developed during the French Revolution in 1799 and has allowed for the sharing of scientific and technical information on an international level. Performing computations using SI units is also much easier to use than the English system. Thanks

Answer:

0.48N

Explanation:

according to the second law of motion

force=mass×acceleration

the mass in this question is 0.025,the acceleration 19

therefore f=0.025×19

=0.48N

I hope this helps

Answer:

Explanation:

From your other post, the complete question is:

"You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to the right. The snow exerts a friction force of 30 N on the sled to the left. The mass of the sled is 50 kg.

Find the sum of the force on the sled.

Determine the acceleration of the sled .

If the sled has an initial velocity 2m/s to the right, how fast will it be traveling after 5 seconds?

"

Given the rope exerting a force of 50 N to the right and the snow exerts a friction force of 30 N to the left, the sum of forces

= 50 - 30

= 20N to the right

The mass of sled is 50 kg and force = mass * acceleration.

Acceleration = Force / mass

= 20 / 50 = 0.4 m/s^2 to the right

If the sled has an initial velocity 2m/s to the right, after 5 seconds it will be traveling at initial velocity + acceleration * time

= 2 + 0.4*5

= 4 m/s to the right

Answer:

Explanation:

net force = applied force - friction force

= 50-30

= 20N to right

acceleration = net force/mass

= 20/50

= 2/5m/s tp right

final velocity = initial velocity + acceleration*time

= 2+2/5*5

= 4m/s to right

Answer:

the angle of banking is 33.3 degree.

Explanation:

speed, v = 99 mi/h = 44.26 m/s  

radius, r = 1000 ft = 304.8 m

g = 9.8 m/s^2

Let the angle of banking is A.

[tex]tan A = \frac{v ^2}{r g}\\\\tan A = \frac{44.26^2}{304.8\times 9.8}\\\\tan A = 0.66\\\\A = 33.3^0[/tex]

Answer:

Acceleration, a = 295.36 m/s²

Explanation:

Given the following data;

Final velocity = 41.35 m/s

Initial velocity = 0 m/s

Time = 0.140 seconds

To find the acceleration, we would use the first equation of motion;

V = U + at

Where;

V is the final velocity.

U is the initial velocity.

a is the acceleration.

t is the time measured in seconds.

Substituting into the equation, we have;

41.35 = 0 + a*0.140

41.35 - 0 = 0.140a

41.35 = 0.140a

Acceleration, a = 41.35/0.140

Acceleration, a = 295.36 m/s²

Answer:

i think its 4 or 35

Explanation:

its in the middle of 40 and 30

Answer:

Power = I * V = 2.5 C/s * 5 J/C = 12.5 J/s = 12.5 watts

Regardless of the efficiency the power consumed is that used by the converter.

E = P * t = 12.5 J/s * 4500 s = 4500 J

Answer:

CG gh sure er go b vh pxuh FPI OO c AM h kh

Answer:

accelerating.

Explanation:

A horse is running on a circular path with constant speed but its direction is changing at every point. Thus, it is accelerating.

Answer:The answer is A

Explanation:just did it on a test

Answer:

A. When the independent variable is continuous and shows a causal link to the dependent variable.

Explanation:

A graph can be defined as the graphical representation of data (informations) on horizontal and vertical lines i.e x-axis and y-axis respectively.

In an experiment , the variable being manipulated by an experimenter is known as an independent variable while the dependent variable is the event expected to change when the independent variable is manipulated

Generally, a line graph should be used when the independent variable is continuous and shows a causal link to the dependent variable.

This ultimately implies that, a line graph should be used when the data changes continuously over time and as such there exist a linear relationship between the data (variables).

Answer:

it gravitional pull on earth will increased becauste it is compress to a form of moon which is comperatively smaller so the gravitonal pull on per cm of earth will incrased so we can say that there will be change in acceleration due to gravity

Answer:

Wavelength = 5 * 10^{-11} meters

Explanation:

Given the following data;

Frequency = 6.0 x 10^18 Hz

Speed = 3 * 10⁸ m/s

To find the wavelength of the wave;

Mathematically, the wavelength of a wave is given by the formula;

[tex] Wavelength = \frac {speed}{frequency} [/tex]

Substituting into the formula, we have;

[tex] Wavelength = \frac {3 * 10^{8}}{6.0 x 10^{18}} [/tex]

Wavelength = 5 * 10^{-11} meters

Answer:

The temperature of the gas is 350.02 K.

Explanation:

The average speed is related to the temperature as follows:

[tex] \bar v = \sqrt{\frac{3RT}{M}} [/tex]   (1)

Where:

[tex] \bar v [/tex]: is the average speed = 1477 m/s

R: is the gas constant = 8.31 J/(K*mol)                                                  

T. is the temperature =?

M: is the molar mass

First, let's find the molar mass:

[tex] M = \frac{m}{n} [/tex]

Where:

m: is the mass of the gas = 0.008 kg

n: is the number of moles = 2 mol

[tex] M = \frac{m}{n} = \frac{0.008 kg}{2 mol} = 0.004 kg/mol [/tex]

Hence, by solving equation (1) fot T we have:

[tex] T = \frac{\bar v^{2}*M}{3R} = \frac{(1477 m/s)^{2}*0.004 kg/mol}{3*8.31 J/(K*mol)} = 350.02 K [/tex]

Therefore, the temperature of the gas is 350.02 K.

I hope it helps you!            

(a) The work done by force in lb-ft is 300 lb-ft.

(b) The change in potential energy of the object is 200 lb-ft.

The work done by force in lb-ft is calculated as follows;

W = Fd

W = 30 x 10

W = 300 lb-ft

The change in potential energy of the object is calculated as follows;

ΔP.E = P.Ef - P.Ei

ΔP.E = 20 x 10 - 0 = 200 lb-ft

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