24. Show and explain clearly, how you would solve the following problem using John Mason's Model for problem solving: A lady rears goats and fowls in her backyard. She observed that there were 42 eyes and 66 legs in her backyard. How many fowls and how many goats are in the yard?

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The average rate of change for this function for the interval from x = 2

to x = 4 is 20

The function is given as:

x   y

0  18

2   32

3    50

4   72

The average rate of change at the interval from x = 2 to x = 4 is calculated using:

m = (f(4) - f(2))/(4 - 2)

Using the table values, we have:

m = (72 - 32)/(4 - 2)

Evaluate

m = 20

Hence, the average rate of change is 20

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Answer:

-10 and -2

Step-by-step explanation:

First, divide both sides by 4 to get |x+6| = 4
Then, Take the absolute vaule on both sides
x+6= 4 or -4
So, x could be 2 vaules
Your welcome!

4 | x + 6 | = 16

Divide both sides by 4.

[tex]\bf{\dfrac{4|x+6|}{4}=\dfrac{16}{4} }[/tex]

[tex]\bf{|x+6|=4 }[/tex]

Absolute value is solved.

[tex]\bf{|x+6|=4 }[/tex]

We know either x + 6 = 4 or x + 6 = -4.

x + 6 = 4 (Possibility 1)

x + 6 - 6 = 4 - 6 (Subtract 6 from both sides)

x=−2

x + 6 = -4 (Possibility 2)

x + 6 - 6 = -4 - 6 (Subtract 6 from both sides)

x=-10

Solution:

x=−2 or x=−10

[tex]\red{\boxed{\green{\boxed{\boldsymbol{\purple{Pisces04}}}}}}[/tex]

Answer:  Choice D)  All rhombuses are squares

=============================================================

Explanation:

Let's go through the answer choices to see which are true and which are false.

Check out the venn diagram below showing the connection between the geometric shapes mentioned. The large outer rectangle represents the set of all quadrilaterals. Inside this is the oval representing all parallelograms. Then inside the oval is the set of rectangles and the set of rhombuses. The overlapping region of the rectangles and rhombuses is the set of squares, marked in blue.

As you can see, picking any square will get us a rhombus and a rectangle automatically. However, picking any rhombus will not guarantee it's a square.

Using conditional probability, it is found that there is a 0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

Conditional probability is the probability of one event happening, considering a previous event. The formula is:

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which:

In this problem, we have that the probabilities are given as follows:

[tex]P(A) = 0.433, P(A \cap B) = 0.29 \times 0.50 = 0.145[/tex]

Hence the conditional probability is:

[tex]P(B|A) = \frac{0.145}{0.433} = 0.3349[/tex]

0.3349 = 33.49% probability that a student is a 9th grader, given that fishing is their favorite leisure activity.

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Answer:

please mark me brainlist

Step-by-step explanation:

i need it

Answer:

3^1 multiplied by 3^2 = 3^(1 + 2) = 3^3

162

Simplify ——————

(2•3^3)

Canceling out 2 as it appears on both sides of the fraction line

3^4 divided by 3^3 = 3^(4 - 3) = 3^1 = 3

Step-by-step explanation:

hope this helps you ♡

Another way to write the equation is 7x + 54 = 0

Given the equation;

[tex]\frac{7}{8}x + \frac{3}{4} = -6[/tex]

Find the LCM on the left side, which is 8

[tex]\frac{7x + 6}{8} = -6[/tex]

Cross multiply

[tex]7x + 6 = -6[/tex] × [tex]8[/tex]

[tex]7x + 6 = -48[/tex]

Collect like terms

[tex]7x = -48 - 6[/tex]

[tex]7x = -54[/tex]

Take all to one side

[tex]7x + 54 = 0[/tex]

Thus, another way to write the equation is 7x + 54 = 0

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Answer:

-3 is a zero of the function  False

-1 is a zero of the function  True

1 is a zero of the function   False

2 is a zero of the function  True

4 is a zero of the function   False

Answer:

please help me find em ah and I will be able to do what I can

The estimated cost of the ending inventory, assuming the gross profit rate is 35% is; $11250

Let us first calculate the gross profit;

Gross Profit = Sales * Profit%

Gross Profit = 395000 * 35%

Gross Profit = $138250

Cost of goods sold = Sales - Gross Profit

Cost of goods sold = 395000 - 138250

Cost of goods sold = $256750

Cost of ending inventory = Cost of goods available for sale - Cost of goods sold

Cost of ending inventory = 268000 - 256750

Cost of ending inventory = $11250

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Answer:

200 cans.

Step-by-step explanation:

f(c)=10r + 120

Put t=8 into it

T(c) = 10 x 8 + 120

=200 cans

(Use substitution method)

Answer:

64 degrees

Step-by-step explanation:

90-32=58

180-58-58=64

Answer:

x = 64°

Step-by-step explanation:

supplementary angles is two angles whose sum is 180° (straight line)

90 + 32 = 122°

To find angle A,

A + 122 = 180

subtract 122 from both sides,

A + 122 - 122 = 180 - 122

A = 58°

This is an isosceles triangle, two angles are equal in measure (A and B). These angles lie opposite to the equal sides.

A triangles angles add up to 180°

58° + 58° + x° = 180°

116° + x = 180°

116 - 116 + x = 180 - 116

x = 64°

Answer:

[tex]31[/tex]

Step-by-step explanation:

It's 31 degrees, I hope it is the right answer

The value of the probability P(x > 2) is 0.8369

The given parameters are:

n = 5

p =0.7

The probability is calculated as:

[tex]P(x) = ^nC_x *p^x * (1 - p)^x[/tex]

Using the complement rule, we have:

P(x > 2) = 1 - P(0) - P(1) - P(2)

Where:

[tex]P(0) = ^5C_0 *0.7^0 * (1 - 0.7)^5[/tex]

P(0) = 1 *1 * (1 - 0.7)^5 = 0.00243

[tex]P(1) = ^5C_1 *0.7^1 * (1 - 0.7)^4[/tex]

P(1) = 5 *0.7^1 * (1 - 0.7)^4 = 0.02835

[tex]P(2) = ^5C_2 *0.7^2 * (1 - 0.7)^3[/tex]

P(2) = 10 *0.7^2 * (1 - 0.7)^3 = 0.1323

Recall that:

P(x > 2) = 1 - P(0) - P(1) - P(2)

So, we have:

P(x > 2) = 1 - 0.00243 - 0.02835 - 0.1323

Evaluate

P(x > 2) = 0.83692

Approximate

P(x > 2) = 0.8369

Hence, the value of the probability P(x > 2) is 0.8369

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Answer:

a. b = 2A/a

b. 30

Step-by-step explanation:

a. to solve for b:

[tex]A = 1/2 ab[/tex]

multiply both sides by 2

[tex]2A = ab[/tex]

divide both sides by a

[tex]2A/a=b[/tex]

so b = 2A/a

b. using the equation b = 2A/a

[tex]b = 2*18/(6/5)\\= 36/(6/5)\\= 30[/tex]

Answer:

They could make at most 5 teams and its not possible to make everyone on team.

Step-by-step explanation:

If there are 4 players on a team, then we use 23 ÷ 4 = 5.75, 0.75 is not enough for 1, so there are 3 players remaining after making 5 teams.

Answer:

The equation of a parallel line is y = x

Step-by-step explanation:

Parallel lines have the same slope

hence the new lines slope is = 1

The equation of the line is written in the slope-intercept form,

y = mx + b

where m represents the slope

          b represents the y-intercept

where the format of a point is (x, y)

Given:

we need to find b, y = 1x + b

we can plug in the point (2, 2)

2 = 1(2) + b

2 = 2 + b

0 = b

Hence, the equation of the line through point

(2, 2) and parallel to y = x+4 is y = x

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Answer:

Slope-intercept form: y = 3x - 1

Step-by-step explanation:

We are given that a line passes through the point (-5, -16) and has a slope of 3

We want to write the equation in point-slope form, and simplify it to slope-intercept form (if it is possible to do so).

First, point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1, y_1)[/tex] is a point

We have both the slope and a point, but let's label the values of everything to avoid confusion + mistakes:

m = 3

[tex]x_1=-5\\y_1=-16[/tex]

Now substitute into the formula (remember: we have NEGATIVE numbers, and the formula uses SUBTRACTION):

[tex]y--16=3(x--5)[/tex]

The equation can be simplified

[tex]y+16=3(x+5)[/tex]

We can also write this in slope-intercept form

Start by distributing 3 to both x and 5 (multiply both x and 5 by 3)

[tex]y+16=3x + 15[/tex]

Subtract 16 from both sides

y = 3x - 1

Answer:

Step-by-step explanation:

Write the number as [tex]abc[/tex] and use the divisibility rules for 10 and 3. From the rule for 10, we know that the last digit of [tex]abc+cba[/tex] is [tex]o[/tex], hence [tex]a+c=10[/tex]. Thus the options are [tex]a=1[/tex] & [tex]c=9[/tex], [tex]a=2[/tex], & [tex]c=8[/tex], etc.

From the rule for 3, namely that the digit sum must be divisible by 3, we find that [tex]2a+2b+2c=20+2b[/tex]  is divisible by [tex]3[/tex]. By hand it's easy to check that [tex]b=2,5,8[/tex] are the only options that work.

So there are 9 choices for [tex]a[/tex] and [tex]c[/tex] and [tex]3[/tex] for [tex]b[/tex] , giving 27 total.

Answer:

Step-by-step explanation:

a cuboid has length 18.5 cm, width 9.4 cm a height 6.2 cm. Work out the area of the cuboid​

assuming you are looking for thr surface area

Surface Area of a Cuboid ·

TSA = 2 (lw + wh + hl)

2*( 18.5 * 9.4 + 9.4 * 6.2 + 6.2 * 18.5) =         (remember PEMDAS)

2 * 346.88 =

693.76 cm²

Answer:

y=-x^2-4x-1

Step-by-step explanation:

when it is an arch like an upside down U then its

-x^2

it passes through the y axis at -1

its vertex or high point is -2,3 so its

-4x

Answer:

See below

Step-by-step explanation:

Dome shaped parabola      so   'a'  is negative

'c' is determined where x = 0

    this value is -1

Axis of symmetry is the x value of the vertex (which is the high point of the dome)

   x = -2

The following statements accurately compare the three functions on the graph: option A and C.

In Geometry, the following statements are true about the graph of a function:

By critically observing the graph of a function, we can logically deduce that the following statements accurately compare the three functions on the graph:

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Answer:

1/4 or 0.25

Step-by-step explanation:

The total possibilities of any 7 digit number using 0-9 is :

9×10×10×10×10×10×10=9000000

To work out the total possibilities in this question :

We look at the conditions :

The first digit can only be 5 numbers :

1 , 3 , 5 , 7 , 9

Now we subtract 5 from 9 :

9-5 = 4

Since no repeats for 2 , 3 , 4, 5, 6:

9 , 8 , 7 , 6 , 5,  

5 possibilities for the last digit :

Total possibilities for this code :

4 × 9 × 8 × 7 × 6 × 5 × 5 = 302400

If it begins with 5 that is only 1 possibility for the first digit

1 × 9 × 8 × 7 × 6 × 5 × 5 = 75600

Now we make a fraction :

75600÷302400

Dividing top and bottom by 75600 gives you 1/4 or 0.25

Hope this helped and have a good day

Answer:

Step-by-step explanation:

Comment

The first digit and the last digit are both odd. That tells you that so far what you have is one of 5 digits for the first digit and and one of 4 for the last digit. 4 because you can't repeat the first digit.

5, , , , , ,4

2 digits are gone 8 remain.

5* 8 * 7* 6* 5* 4* 4 = 134400

Part 2

Only one number can go at the beginning, and that is a 5. Everything else remains the same.

1 * 8 * 7 * 6 *5 * 4 * 4 = 26880

P(picking a number beginning with a 5 is  25880 /13440) = 0.2

Step-by-step explanation:

(4²-x²)³/²

or,(4+X) (4-X)

Substitute [tex]x = 4 \sin(y)[/tex], so that [tex]dx = 4\cos(y)\,dy[/tex]. Part of the integrand reduces to

[tex]16 - x^2 = 16 - (4\sin(y))^2 = 16 - 16 \sin^2(y) = 16 (1 - \sin^2(y)) = 16 \cos^2(y)[/tex]

Note that we want this substitution to be reversible, so we tacitly assume [tex]-\frac\pi2\le y\le \frac\pi2[/tex]. Then [tex]\cos(y)\ge0[/tex], and

[tex](16-x^2)^{3/2} = 16^{3/2} \left(\cos^2(y)\right)^{3/2} = 64 |\cos(y)|^3 = 64 \cos^3(y)[/tex]

(since [tex]\sqrt{x^2} = |x|[/tex] for all real [tex]x[/tex])

So, the integral we want transforms to

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 64 \int \cos^3(y) \times 4\cos(y) \, dy = 256 \int \cos^4(y) \, dy[/tex]

Expand the integrand using the identity

[tex]\cos^2(x) = \dfrac{1+\cos(2x)}2[/tex]

to write

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx = 256 \int \left(\frac{1 + \cos(2y)}2\right)^2 \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \cos^2(2y)) \, dy \\\\ = 64 \int (1 + 2 \cos(2y) + \frac{1 + \cos(4y)}2\right) \, dy \\\\ = 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy[/tex]

Now integrate to get

[tex]\displaystyle 32 \int (3 + 4 \cos(2y) + \cos(4y)) \, dy = 32 \left(3y + 2 \sin(2y) + \frac14 \sin(4y)\right) + C \\\\ = 96 y + 64 \sin(2y) + 8 \sin(4y) + C[/tex]

Recall the double angle identity,

[tex]\sin(2y) = 2 \sin(y) \cos(y)[/tex]

[tex]\implies \sin(4y) = 2 \sin(2y) \cos(2y) = 4 \sin(y) \cos(y) (\cos^2(y) - \sin^2(y))[/tex]

By the Pythagorean identity,

[tex]\cos(y) = \sqrt{1 - \sin^2(y)} = \sqrt{1 - \dfrac{x^2}{16}} = \dfrac{\sqrt{16-x^2}}4[/tex]

Finally, put the result back in terms of [tex]x[/tex].

[tex]\displaystyle \int (16 - x^2)^{3/2} \, dx \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 128 \frac x4 \frac{\sqrt{16-x^2}}4 + 32 \frac x4 \frac{\sqrt{16-x^2}}4 \left(\frac{16-x^2}{16} - \frac{x^2}{16}\right) + C \\\\ = 96 \sin^{-1}\left(\frac x4\right) + 8 x \sqrt{16 - x^2} + \frac14 x \sqrt{16 - x^2} (8 - x^2) + C \\\\ = \boxed{96 \sin^{-1}\left(\frac x4\right) + \frac14 x \sqrt{16 - x^2} \left(40 - x^2\right) + C}[/tex]