25 people gathered to watch a baseball game while talking they realized that 5 of them were New York Mets fans what is the probability that the favorite team of a randomly selected person in the group is the New York mets

The answer to the problem is: row

Answer:

[tex]\frac{-29}{72}[/tex]

Step-by-step explanation:

use a calculator

The linear functions for each situation are given as follows:

The interval of hours for which Company A is cheaper than Company B is given as follows:

x > 5.

The linear functions are modeled in slope-intercept format, as follows:

y = mx + b.

In which:

Hence the functions are defined as follows:

Company A will be cheaper when:

45x + 250 < 55x + 200

10x > 50

x > 5.

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Convenience sampling represents the sub-population of the sample strategies.

Convenience sampling is defined as a type of non-probability sampling that involves the sample being drawn from that part of the population that is close to hand and is a type of sampling that is most useful for pilot testing.

Convenience sampling can be used by almost anyone and has been around for generations. One of the reasons that it is most often used is due to the numerous advantages it provides

Expedited data collection, Ease of research, Ready availability, Cost-effectiveness.

Bias, Power is the disadvantages of convenience sampling.

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The numbers that have been omitted from the given series of a number with comparable discrepancies between them are known as missing numbers.

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The value of  [tex]tan^{-1}(0.2)[/tex] = -0.19739 + ... i.e. [tex]tan^{-1} (0.2)= (0.2) - \frac{(0.2)^{3} }{3} +\frac{(0.2)^{5} }{5} -\frac{(0.2)^{7} }{7}+...[/tex]

The power series of  [tex]tan^{-1}(x)[/tex] obtained in example 6 is called the Gregory's series. The Gregory series is an infinite series of fractions or rational numbers

After the Scottish mathematician James Gregory (1638-1675) who had anticipated some of Newton's discoveries we have shown that  the Gregory's series is valid when -1 < x < 1.

But it turns out (although it isn't easy to prove) that it is also valid when:

x = 1 or ≠ 1.

According to Example 6, The radius of convergence of the series for

[tex]1/(1 +x^{2} )[/tex]  is 1, the radius of convergence of this series for [tex]tan^{-1}(x)[/tex] is also 1.

                          [tex]tan^{-1} x = x - \frac{x^{3} }{3} +\frac{x^{5} }{y} -\frac{x^{7} }{y} +....[/tex]  

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The area above x axis is 12.6 sq units while the area under the y-axis is 42.443 sq units. The change in the average phone bill is 29.843 units.

a) Here we see that the graph is in the shape of a right-angled triangle above the x-axis

The area of a triangle = 1/2 X Base X Height

Here the base will be the measure of the distance of co-ordinates on the x-axis

The height is the distance between the coordinates on the axis for that triangle

= 1/2 X (16 - 8) X (3.15 - 0)

= 1/2 X 8 X 3.15

= 12.60 sq units

b)

Below the x-axis, the graph is a rectangle and a triangle

The area of the rectangle = length X width

Here length is the distance of the co-ordinates of the y-axis and width is the distance between the coordinates for the x-axis

Hence we get

(0 - (-5.14))(8 - 0)

= 5.14 X 8

= 41.12 sq units for the rectangle.

The area of the triangle will be

1/2 X (18 - 15.48) X (0 - (-1.05))

1/2 X 2.52 X 1.05

= 1.323 sq unit

Hence, the total area is

41.12 + 1.323

= 42.443 sq unit

c)

Since the area under the graph represents change,

Here we see that the change in the average cell phone bill will be

42.443 + 12.6

= 55.043

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Complete Question

(Image Attached)

The correct answer is option D, extraversion, neuroticism, and psychoticism

Eysenck's theory of personality is based on three logical attributes namely:  

a) introversion vs. extroversion – Extroversion leads to sociable life , while introversion causes need of being alone and limited interactions

b) neuroticism vs. stability – Neuroticism leads to anxiousness and overactive sympathetic nervous system while  stability leads to emotional stability

c) psychoticism vs. socialization. - psychoticism  leads to independent thinking, and hostility. While socialization leads to co-operative and conventional behaviour.  

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Answer:

A polynomial’s degree is the highest or the greatest power of a variable in a polynomial equation. The degree indicates the highest exponential power in the polynomial (ignoring the coefficients).

For example: 6x4 + 2x3+ 3 is a polynomial. Here 6x4, 2x3, 3 are the terms where 6x4 is a leading term and 3 is a constant term. The coefficients of the polynomial are 6 and 2.

The degree of the polynomial 6x4 + 2x3+ 3 is 4.

If the dealership decided to use a 20% markup instead, then they earn $700 more.

percentage, a relative value indicating hundredth parts of any quantity.

Given that A car dealership pays a wholesale price of $14,000 to purchase a vehicle.

They sell the car for $16,100

If the dealership decided to use a 20% markup instead, we have to find the hu=ow much more would they make.

Let us find 20% of 14000

20/100×14000

0.2×14000

2800

So with 20% the price will become $16800.

As they sell the car for $16100.

The difference between $16800-$16100 is $700

Hence, If the dealership decided to use a 20% markup instead, then they earn $700 more.

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The graph of the given equation is given at end.

A graph is a graphic depiction or diagram that displays data in an organized manner. The points on a graph are typically used to depict the relationships between two or more things.

Determine the slope and y-intercept first, then put the equation in y-intercept (y=mx+b) form to get the equation of a graphed line. The y-to-x change ratio is known as the slope. The two locations you locate on the line should be connected by a sloping triangle.

Common graph types include line graphs, bar graphs, pie charts, scatter plots, and histograms. Graphs are an excellent tool for visualizing data and presenting statistics. An example of displaying numerical data is with a bar graph or chart.

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The difference (Dogs – Cats) in the sample proportions of those that get their teeth cleaned typically varies about 0.054 from the true difference in proportions.

The third option is correct.

What is the standard deviation?

Standard deviation is a statistical measure of the spread of a dataset, defined as the square root of its variance. It is a way to quantify the amount of variation or dispersion of a set of data values.

Percentage of Dogs getting their teeth cleaned = 48% = pD

Percentage of Cats getting their teeth cleaned = 35% = pC

Number of Dogs selected = nD = 25

Number of Cats selected = nc = 32

As the sample sizes are large enough, we can apply Central Limit Theorem

According to Central Limit Theorem for proportions –

pD-hat ~ Normal(pD, {pD*(1-pD)}/nD)

Thus, pD-hat ~ Normal(0.48, 0.009984)

Similarly,

pC-hat ~ Normal(pC, {pC*(1-pC)}/nC)

Thus, pC-hat ~ Normal(0.35, 0.0071094)

Now if X ~ N(E(X), Var(X)) and Y ~ N(E(Y), Var(Y))

then X -Y ~ N(E(X)-E(Y), Var(X)-Var(Y)) (If X and Y are Independent)

Thus,

pD-hat - pC-hat ~ Normal(0.48-0.35, 0.009984 – 0.0071094)

pD-hat - pC-hat ~ Normal(0.13, 0.0028746)

Thus, Standard Deviation of pD-hat - pC-hat = (0.0028746^0.5) = 0.0536 that is 0.054 approximately

Hence, the difference (Dogs – Cats) in the sample proportions of those that get their teeth cleaned typically varies about 0.054 from the true difference in proportions.

Third Option is correct.

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The odd_sum method accepts an array of numbers and returns the total sum of all odd numbers found in the array.

def odd_sum(numbers)

 sum = 0

 numbers.each do |num|

   if num.odd?

     sum += num

   end

 end

 sum

end

1. We define a method called odd_sum that accepts an array of numbers as an argument.

2. We set a variable called sum and set it to 0.

3. We iterate through the array using the each method.

4. We check if the number is odd using the odd? method.

5. If the number is odd we add it to the sum variable.

6. We return the sum variable at the end of the method.

The odd_sum method accepts an array of numbers and returns the total sum of all odd numbers found in the array

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.

The solution to the differential equation (x^3 + y^3) dx − xy^2 dy = 0 is y/x^3 = Ce^(−(y/x)^3), where C is an arbitrary constant.

Substituting y = vx and dy = x dv + v dx, we get:

(x^3 + (vx)^3)dx − x(vx)^2(x dv + v dx) = 0

Simplifying and rearranging, we get:

x^2v dx + (x^3 + 3xv^2 − v^3x^2)dv = 0

Dividing both sides by x^2v and rearranging, we get:

dx/x + (1/v)dv + (3/xv - v^2)dv = 0

Integrating both sides, we get:

ln|x| + ln|v| + 3ln|v/x| − v^3 = C

Where C is an arbitrary constant. Simplifying, we get:

ln|vx/x^3| = C − v^3

Rearranging, we get:

vx/x^3 = Ce^(−v^3)

Finally, we can express this in terms of x and y as:

y/x^3 = Ce^(−(y/x)^3)

The solution to the differential equation (x^3 + y^3) dx − xy^2 dy = 0 is y/x^3 = Ce^(−(y/x)^3), where C is an arbitrary constant.

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Answer:

(100/500) *200 =40%

Step-by-step explanation:

Answer:129.7

Step-by-step explanation:

Literally just used a calculator but if you need explanation lmk

Answer:28

Step-by-step explanation:

Trick: just check if it's divisible by both numbers

The picture explains it all. We use tangent rule to find out the measure of angle A.

The measure of angle unknown angle is 30°.

Use the concept of the triangle defined as:

A triangle is a three-sided polygon, which has three vertices and three angles which has a sum of 180 degrees.

Given that,

Side AC = 6 units

Side BC = 3 units

Let ∠BAC = θ

Since we know that,

Sin θ = opposite/Hypotenuse

Sin θ = BC/AC

Put the values,

Sin θ = 3/6

Sin θ = 1/2

Since we know that,

sin(π/6) = 1/2

Therefore,

Sin θ = sin(π/6)

Take the inverse of sin on both sides we get,

θ = π/6 or 30°

Hence,

The measure of angle unknown angle is 30°.

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Answer:

1,576,800 minutes

Weight of the 13 male eleventh graders is 157.23  pounds. Median is the number in the middle, ranked from least to greatest.

Median weight = 148+140+159+141+151+156+173+167+160+159+146+174+170

                                              = 2044/13

                                                 = 157.23

The value that separates the upper half of a population, a data sample, or a probability distribution from the lower half is known as the median. It could be referred to as "the middle" value for a data set. The value in the middle of a data set is called the median. This means that 50% of the data points have values that are smaller than or equal to the median, and 50% of the data points have values that are higher than or equal to the median. First, you count the number of data points (n) and arrange them in ascending order for a small data set.

The middle value in a set of data is called the median. First, arrange the data in ascending order from smallest to largest. Divide the total number of observations by two to get the midpoint value. Round that number up if there are an odd number of observations, and the value in that position is the median. Take the average of the values found above and below that position if the number of observations is even.

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To calculate the mcg/kg/minute, first divide 800 mg by 500 ml to get 1.6 mg/ml. Then, multiply 1.6 mg/ml by 5 ml/hour to get 8 mg/hour. Finally, divide 8 mg/hour by 70 kg to get 0.114 mcg/kg/minute.

To calculate the mcg/kg/minute, first divide 800 mg by 500 ml to get 1.6 mg/ml, which is the concentration of dopamine in the solution. Next, multiply 1.6 mg/ml by 5 ml/hour to get 8 mg/hour, which is the rate of infusion. Finally, divide 8 mg/hour by 70 kg to get 0.114 mcg/kg/minute, which is the mcg/kg/minute the client is receiving. This calculation can also be done by dividing 800 mg by 500 ml to get 1.6 mg/ml, then multiplying 1.6 mg/ml by 5 ml/hour to get 8 mg/hour, and finally dividing 8 mg/hour by 70 kg to get 0.114 mcg/kg/minute. By doing this calculation, the client is receiving 0.114 mcg/kg/minute of dopamine solution.

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Answer:

2. <

Step-by-step explanation:

To compare these two fractions we can first find them a common denominator. A common denominator between 4 and 16 is 16.

To get from 16 from 4 we multiply by 4 so we do the same to the numerator, changing 1/4 to 4/16.

5/16 already has a denominator of 16 so we can leave that one as is.

4/16___5/16

In this form it is obvious that 5/16 is the larger fraction because 5 is larger than 4, meaning that 5/16 is larger than 1/4.

By using Triangles ABC and ADC given in image, Ladders will cross at 10/3 m above the ground.

What are triangles?

Triangles are polygons in geometry that have three sides and three vertices. This figure is two-dimensional and has three straight sides. A triangle is a three-sided polygon. A triangle's three angles added together equals 180°. A single plane contains the triangle. The triangle is classified into six forms based on its sides and angles.

A triangle is categorized into three categories based on its sides, namely:

Scalene Triangle - Each side has a distinct length.

Isosceles Triangle - A triangle with two sides of equal length and one side of a different length.

Equilateral Triangle - A triangle has three sides that are of the same length.

A triangle is categorized into three categories based on its angles, namely:

Acute Angle Triangle - A triangle with all of its angles smaller than 90°.

Obtuse Angle Triangle - A triangle with one of its angles larger than 90°.

Triangle with a Right Angle - A triangle with one of its angles equal to 90°.

Now,

As shown in image  that the angles ∠BAD and ∠ADC are alternate angles, and therefore equal. Likewise, angles ∠ABC and BCD are also alternate and therefore equal.

∠BEA and ∠CED are opposite, which means that they are equal. You can see these equal angles in the image.

This means that the triangles ABE and DCE have the same angles as each other, and are therefore similar.

This means:

AE/ED=AB/DC=5m/10m=1/2

Therefore AE=1/3AD

This means E is 1/3 of the way up from the floor to D, so is at a height of 10/3m=3 1/3m

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Cotangent is the inverse of tangent:

cotΘ = 1/tanΘ

cotΘ = [tex]1/\frac{\sqrt{6} }{2}[/tex]

         =[tex]\frac{2}{\sqrt{6}}[/tex]

         =[tex]\frac{2}{\sqrt{6}}*\frac{\sqrt{6}}{\sqrt{6}}=\frac{2\sqrt{6}}{6}[/tex] Rationalize the denominator

cotΘ = [tex]\frac{\sqrt{6}}{3}[/tex]

Plug and solve.

[tex]\frac{\frac{\sqrt{6}}{2}+\frac{\sqrt{6}}{3} }{\frac{\sqrt{6}}{2}-\frac{\sqrt{6}}{3}}[/tex]

We'll break the problem into 2, simplify the denominator, then simplify the numerator.

Simplify the denominator with the common denominator 6, of 2 and 3:

[tex]{\frac{\sqrt{6}}{2}-\frac{\sqrt{6}}{3} = {\frac{3\sqrt{6}}{6}-\frac{2\sqrt{6}}{6} = {\frac{3\sqrt{6}-2\sqrt{6}}{6} = {\frac{\sqrt{6}}{6}[/tex]

Simplify the Numerator with the common denominator 6, of 2 and 3:

[tex]{\frac{\sqrt{6}}{2}+\frac{\sqrt{6}}{3} = {\frac{3\sqrt{6}}{6}+\frac{2\sqrt{6}}{6} = {\frac{3\sqrt{6}+2\sqrt{6}}{6} = {\frac{5\sqrt{6}}{6}[/tex]

Back in original equation with simplified numerator and denominator:

[tex]\frac{\frac{5\sqrt{6}}{6}}{\frac{\sqrt{6}}{6}}[/tex]

Multiply by reciprocal and simplify:

[tex]\frac{5\sqrt{6}}{6}*\frac{6}{\sqrt{6}} = \frac{5\sqrt{6} * 6}{6\sqrt{6}} = 5*\frac{6\sqrt{6}}{6\sqrt{6}} = 5*1 = 5[/tex]

Answer: A scale factor is defined as the ratio between the scale of a given original object and a new object, which is its representation but of a different size (bigger or smaller). Therefore, The scale factor would be 1/2

The proof of the circumcenter theorem states that given three points A, B and C, drawing lines AB and AC or AB and BC and finding the perpendicular bisector of the corresponding segment will intersect at the circumcenter of triangle ABC.

Column 1:

1. Given three points A, B and C, draw lines AB and AC.

2. A bisector of angle BAC is the perpendicular bisector of segment AC.

3. The perpendicular bisector of segment AC intersects line AB at the circumcenter of triangle ABC.

Column 2:

1. Given three points A, B and C, draw lines AB and BC.

2. A bisector of angle ABC is the perpendicular bisector of segment BC.

3. The perpendicular bisector of segment BC intersects line AB at the circumcenter of triangle ABC.

The proof of the circumcenter theorem states that given three points A, B and C, drawing lines AB and AC or AB and BC and finding the perpendicular bisector of the corresponding segment will intersect at the circumcenter of triangle ABC. Therefore, it is enough to work on two edges to find the circumcenter.

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The general solution with the initial condition y(-1)=C is y=-(1+x)/(6+x)=-2/7.

The general solution to the differential equation -6y = 1+x+y+xy is y = -(1+x)/(6+x). To apply the initial condition, we can substitute x=-1 and y=C into the above equation and solve for C. We get C=-(2/7). Therefore, the general solution to the differential equation with the initial condition y(-1)=C is y=-(1+x)/(6+x)=-2/7.

Substituting x=-1 and y=C into the equation:

-6C = 1-1+C+(-1)C

-7C = 1

C = -1/7

Therefore, the general solution with the initial condition y(-1)=C is y=-(1+x)/(6+x)=-2/7.

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An ellipse is defined as the set of all points such that the sum of the distances between the point and the two foci is constant. The equation of an ellipse can be represented in the standard form as:

(x-h)^2/a^2 + (y-k)^2/b^2 = 1

where (h, k) is the center of the ellipse, a is the distance from the center to a vertex, and b is the distance from the center to the focus.

Given that the center of the ellipse is at (2, 1), one vertex is at (2, -4), and one focus is at (2, -2), we can use this information to find the values of a and b, and represent the equation of the ellipse:

a = distance from center to vertex = |1 - (-4)|/2 = 2.5

b = distance from center to focus = |1 - (-2)|/2 = 1.5

The equation of the ellipse is:

(x-2)^2/2.5^2 + (y-1)^2/1.5^2 = 1

which can also be written as:

(x-2)^2/6.25 + (y-1)^2/2.25 = 1

This equation represents the ellipse with center at (2, 1), one vertex at (2, -4), and one focus at (2, -2)

The slope of the secant line between x = 3 and x = 8 for the function [tex]f(x) = \sqrt{16x - 47}[/tex] is given as follows:

8/5.

The secant line intersects the function f(x) at the coordinates x = 3 and x = 8.

The numeric value for the function at each of these points is given as follows:

Given two points, the slope of a line is calculated as the change in y divided by the change in x, hence:

m = (9 - 1)/(8 - 3)

m = 8/5.

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To have the determinant negative, at least one Eigenvalue has to be negative but the reverse of this statement may or may not be true.

If we add all the diagonal elements of the square matrix, we get the trace of the given matrix.

Eigenvalues is a scalar that associates with a set linear equation described as -

(A - λ I) X = 0

If we take the product of all the eigenvalues of a matrix, we'll get the determinant of the matrix. If we consider a case in which the trace of the matrix is +ve, and its determinant is -ve, then at least one or an odd no. of Eigenvalues must be negative, since their product has to be positive when we solve for the determinant of the matrix

Therefore, to have the determinant negative, at least one Eigenvalue has to be negative but reverse may or may not be true.

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