26.6 00
Fig. E26.6 both meters are ide-
alized, the battery has no appre-
ciable internal resistance, and the
ammeter reads 1.15 A. (a) What
does the voltmeter read? (b) What
is the emf & of the battery?
26.7 For the circuit shown
For the circuit shown in Figure E26.6
V
45.0 Ω
25.0 Ω
ww(A)
|15.0 Ω
www
|15.0 Ω
W
www
ww
4+
35.0 = ?
10.0 Ω

During arm elevation, the motion of the scapula moves is an upward rotation motion.

The scapula otherwise known as the shoulder blade is a bone found in the upper limb and forms part of the shoulder and the back.

They are triangular in shape.

The scapula enables movement of the shoulder and the arm in about six ways.

During arm elevation, the motion of the scapula moves is an upward rotation motion: protraction, retraction, elevation, depression, upward rotation, and downward rotation.

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When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

Newton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.

The mathematical interpretation of the above law is

Removing the proportionality sign,

Where:

From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

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Because of wave refraction, erosion along an irregular coastline is greatest in headlands.

This is referred to as the bending of light as it passes from one medium to another with its speed being changed.

Refraction causes erosion along an irregular coastline to be greatest in headlands which is the area of land projected out toward the sea.

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Answer:

Asteroids and comets have a few things in common. They are both celestial bodies orbiting our Sun, and they both can have unusual orbits, sometimes straying close to Earth or the other planets. They are both “leftovers” — made from materials from the formation of our Solar System 4.5 billion years ago. But there are a few notable differences between these two objects, as well. The biggest difference between comets and asteroids, however, is what they are made of.

While asteroids consist of metals and rocky material, comets are made up of ice, dust, rocky materials and organic compounds. When comets get closer to the Sun, they lose material with each orbit because some of their ice melts and vaporizes. Asteroids typically remain solid, even when near the Sun.

Right now, the majority of asteroids reside in the asteroid belt, a region between the orbits of Mars and Jupiter which may hold millions of space rocks of varying sizes. On the other hand, the majority of comets are in the farthest reaches of our Solar System: either 1. in the Kuiper Belt — a region just outside the orbit of the dwarf planet Pluto that may have millions of icy comets (as well as many icy dwarf planets like Pluto and Eris); or 2. the Oort Cloud, a region where trillions of comets may circle the Sun at huge distances of up to 20 trillion kilometers (13 trillion miles).

Answer:

they are both leftovers materials

Explanation:

think about how the solar system is made the comets and asteroids are both rocks and remains of the solar system

In permanent waving, the size of the curl should be determined based on the size of the rod.

Permanent waving can be defined as a hairstyle that is typically made by setting a person's hair in waves or curls while treating it with chemical solutions such as thio, so as to make it last for a long period of time.

In permanent waving, the size of the curl should be determined based on the size of the rod that would be used for the hairstyle.

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The point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.

The electric field strength is defined as the ratio of electric force and charge. The field's direction is determined by the direction of the force acting on the positive charge.

The megnitude of the electric field for charge 1 is;

[tex]\rm E_1 = (9 \times 10^9 )\times \frac{0.700 \times 10^{-9}}{x^2}[/tex]

The megnitude of the electric field for charge 1 is;

[tex]\rm E_2 = 9.0 \times 10^9 \times \frac{9.00 \times 10^{-9}}{(1.80-x)^2}[/tex]

The net electric field at point p is;

[tex]\rm \frac{0.700}{x^2} = \frac{9.00}{(1.40-x)^2} \\\\( \frac{1.40-x}{x} )^2 = \frac{9.00}{0.700} \\\\\ \frac{1.40-x}{x}=3.58 \\\\ \frac{140}{x} -1=3.58\\\\\ \frac{140}{x}=3.58+1\\\\ x=0.3056 \ m[/tex]

Hence, the point along the line connecting the two charges is the total electric field due to the two charges equal to zero will be 0.3056.

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The change in the momentum of the cart,given the data is 0.06 Kgm/s (Option D)

Momentum is defined as the product of mass and velocity. It is expressed as

Momentum = mass × velocity

Change in momentum = mass (final velocity - initial velocity)

From the data given above, the following data were obtained:

Change in momentum = m(v + u) (renounce)

Change in momentum = 0.5 (-0.24 + 0.36)

Change in momentum = 0.5 × 0.12

Change in momentum = 0.06 Kgm/s

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Answer:

A

Explanation:

ASA was found in the bark of willow trees.

scalars: distance, speed, time

vectors: displacement, velocity, acceleration

In the image below, the focus lines are shown. The step can be done to bring the apple into focus is make the lens rounder. The correct option is A.

The lens is in spherical shape may be diverging or converging.

As light enters the eye, it is focused on the retina. Changing the pupil diameter, regulates the amount of light entering the eye. Changing lens shape will focus the light.

The changes in lens shape needed to maintain focus as the object distance changes.

Thus, the correct option is A.

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Answer:

Weaker, stronger

Explanation:

hope this helped!

Answer:

[tex]\fbox {weaker, stronger}[/tex]

Explanation:

The farther you bring charged objects from each other, the weaker the electrical force between them, and the bigger the charges on the objects, the stronger the electrical force between them.

Proving

Here we need the formula for Coulomb's Law, which is :

[tex]\boxed {F = \frac{1}{4\pi\epsilon_{0}}\times\frac{q_{1}q_{2}}{r^{2}}}[/tex]

As we can see, when the distance increases, the overall force will decrease as they are inversely proportional.

Similarly, as the product of charges is directly proportional to the electrical force produced, as the charges increase, the force increases.

An eclipse is an event in which the sun or moon is blocked from view due to the presence of another celestial body, whereas lunar phases are caused by the reflection of the sunlight.

An eclipse is an astronomical phenomenon where one celestial body (e.g., sun, moon) cannot be observed because another is interposed between the Earth and the first one.

Eclipses can be divided into moon eclipses (we cannot see the moon) and sun eclipses (we cannot see the sun).

On the other hand, moon phases occur due to how sunlight reflects the near side of the Moon.  

Moon phases can be divided into:

In conclusion, an eclipse is an event in which the sun or moon is blocked from view due to the presence of another celestial body, whereas lunar phases are caused by the reflection of the sunlight.

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Answer: the other person explained it all

Explanation:

Answer:

no way to tell since the ocean surface is moving too violently it's not possible to determine the reflected angle

Explanation:

vertical force = 460,000 * sin(70) - 300,000

Fv = 187,717.75N

If all the wires have the same diameter, they will all stretch by the same percent. The elasticity does not depend upon the length.

Distance is a numerical representation of the distance between two locations. The distance can refer to a physical length or an estimate based on other factors in physics or common use.

|AB| is a symbol for the distance between two points A and B.

A physiological method for identifying far-off or unseen items using sound waves that the objects reflect back to the source, such as a bat. Each one will enlarge by the same percentage.

Hence, they will all stretch by the same percentage.

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Answer:

its Q

Explanation:

Answer:

3 meters

Explanation:

Velocity = displacement/time

Displacement=velocity×time

As, time from 7 to 8 is 1 sec. And velocity increases from 0 to 3 m/s

So, Displacement = 3×1

=3m

Please give me brainlist.

The potential energy of a rocket increases when its escapes from the influence of the earth. It increases when it escapes the earth's boundary.

Escape velocity or escape speed is the minimum speed required for a free, non-propelled object to escape from the gravitational pull of the main body and reach an infinite distance from it in celestial physics.

It is commonly expressed as an ideal speed, neglecting atmospheric friction.

If a spacecraft is launched from the moon at the escape speed of the earth then the value of escape speed will be the difference in both the velocities.

An object's height above the zero position directly relates to its gravitational potential energy.

The kinetic energy of motion is converted into gravitational potential power as your rocket ascends.

The rocket possesses gravitational potential energy as it climbs because it is becoming farther away from the Earth's surface, much as a positive and negative charge moving apart.

The potential energy of a rocket increases when its escapes from the influence of the earth. It increases when it escapes the earth's boundary.

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Answer:

4 m/s²

Explanation:

v = v₀ + at

80 = 0 + 20a

80 = 20a

a = 4 m/s²

Last one!

Perpendicular to the wave's energy

Hope this helps!

Answer:

[tex]2.5m/s^{2}[/tex]

Explanation:

Since the distance ,s = 500m

Initial velocity, u = 0m/s

Final velocity, v = 50m/s

We can one of the kinematics equations to find the acceleration.

[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]

Answer:

S=D÷T

Explanation:

50=0.5÷T

T= 100

Home heating systems work through negative feedback by regulating the temperature through thermostat.

In thermostat, when the temperature of the room environment increases by the negative feedback system the furnace gets turn off, allowing the room to get to its normal temperature and when the temperature lower down it turns on again and maintain the temperature in equilibrium state.

So we can conclude that home heating systems work through negative feedback by regulating the temperature through thermostat.

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Answer:

Forces do not have a specific direction.

Taking into account the Newton's second law, the amount of force required to keep the object in motion if you ignore the surface friction is 0 N.

In first place, acceleration in a body occurs when a force acts on a body. There are two factors that influence the acceleration of an object: the net force acting on it and the mass of the body.

Newton's second law states that this force will change the speed of an object because the speed and / or direction will change. These changes in velocity are called acceleration.

So, Newton's second law defines the relationship between force and acceleration mathematically. This law says that the acceleration of an object is directly proportional to the sum of all the forces acting on it and inversely proportional to the mass of the object.

Mathematically, Newton's second law is expressed as:

F= m×a

where:

In this case, you know:

Replacing in Newton's second law:

F= 5 kg× 0 m/s²

Solving:

F= 0 N

Finally, the amount of force required to keep the object in motion if you ignore the surface friction is 0 N.

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The distance of the point from the axis of rotation of the second hand is 9.1 m.

The point from the axis of rotation of the second hand is the radius of the rotation of the clock.

a = v²/r

v² = ar

v = √ar

V = 2πr/T

√ar = 2πr/T

ar = 4π²r²/T²

a = 4π²r/T²

r = aT²/4π²

r = (0.1 x 60²)/(4π²)

r = 9.1 m

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a) 4.9 m

b) 38.3 m/s

c) 33.4 m

The three equations are,

v = u + at

v² = u² + 2as

s = ut + ½at²

According to the question,

Let hold the y-axis in the direction of gravity.

Initial velocity 0 = 0 /,

Initial height ℎ0 = 0 , and finish height ℎ = 75.0

gravitational acceleration = 9.8 /²

a) Determine the distance traveled during the first second.

By third equation of motion

[tex]S_{0} = v_{0} t +\frac{1}{2} gt^{2}[/tex]  where [tex]v_{0}[/tex] =0

then [tex]S_{0} = \frac{gt^{2}}{2} = \frac{9.8*1^{2} }{2} = 4.9 m[/tex]

b) Determine the final velocity at which the object hits the ground

let – velocity of object, when it falling to the ground

– moment falling to the ground, and obtain from condition:

ℎ = ℎ() = 75.0

[tex]v_{f} = v_{0} +gt = gt[/tex]

[tex]h (t_{f} ) = \frac{gt^{2} }{2} = 75.0 m\\t_{f} =\sqrt{\frac{2h_{f} }{g} } \\v_{f}= gt = g \sqrt{\frac{2h_{f} }{g} } =\sqrt{2hg_{f} }= =\sqrt{2*9.8*75.0} = 38.3 m/s[/tex]

c) Determine the distance traveled during the last second of motion before hitting the ground.

From the above equation we get,

[tex]\sqrt{2*75*9.8*1} - \frac{9.8*1^{2} }{2} = 38.3 -4.9 = 33.4 m[/tex]

Therefore,

a) 4.9 m is the distance traveled during the first second.

b) 38.3 m/s is the final velocity at which the object hits the ground

c) 33.4 is the distance traveled during the last second of motion before hitting the ground.

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Gyroscopic wander can be divided into two categories and these are:

Gyroscopic wander can be defined as a movement of the spin axis (axis of rotation) away from a specific fixed direction.

Based on scientific information and records, there are two main types of gyroscopic wander and these include the following:

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Answer:

B

Explanation:

That is solar energy and the sun will be releasing energy constantly for the rest of its life, meaning renewable

the distance is the first 80m+the second 80m she came back. So the distance is 160m. but the displacement is 0, because she came back by the direction she went.

Since we assume the accelerations are constant, the instantaneous acceleration is the same as the average acceleration, so in the first 6.80 seconds we have

[tex]\alpha_1 = \alpha_{\rm ave} = \dfrac{\Delta \omega}{\Delta t} = \dfrac{8.70\frac{\rm rev}{\rm s}}{6.80\,\rm s} \approx 1.28 \dfrac{\rm rev}{\mathrm s^2}[/tex]

In this time, the tub undergoes an angular displacement of

[tex]\theta_1 = \dfrac12 \alpha_1 (6.80\,\mathrm s)^2 \approx 29.6\,\mathrm{rev}[/tex]

In the next 19.0 seconds the tub has acceleration

[tex]\alpha_2 = \dfrac{-8.70\frac{\rm rev}{\rm s}}{19.0\,\rm s} \approx -0.458 \dfrac{\rm rev}{\mathrm s^2}[/tex]

and in this time, the tube undergoes an additional displacement of

[tex]\theta_2 = \left(8.70\dfrac{\rm m}{\rm s}\right)(19.0\,\mathrm s) + \dfrac12 \alpha_2 (19.0\,\mathrm s)^2 \approx 82.7\,\mathrm{rev}[/tex]

So the tub completes [tex]\theta_1+\theta_2 \approx \boxed{112\,\mathrm{rev}}[/tex].