(3) construct a quadratic equation
For -1/3 and -2/3

Therefore , Mrs. Garcia needs 280 grams of gluten-free flour.

Equations are classified by identity equations or conditional equations. There is an identity for each possible value of the variables. A conditional equation can only have a certain set of variable values. Equation is represented by equals ("="), which divides two expressions.

Here,

Mrs. Garcia  needs 70% of the flour to be almond flour

Thus ,

70% of 400 is

=> 70/100*400 =  280

Therefore , Mrs. Garcia needs 280 grams of gluten-free flour.

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Answer: Answer would be -65

It should be that?

the difference between Group B and Group C (-0.3) is less than the other differences, we can conclude that Group B and Group C are the means that are different.

The ANOVA test has determined that there is a difference between the means, and the Tukey's results can help to determine which mean is different. In this case, Group B (4.0) and Group C (4.3) are significantly different, meaning that one of those means is different from the other groups.

An ANOVA test has been conducted and it has been determined that there is a difference between the means. The Tukey's results can be used to identify which mean is different. In this case, Group B (4.0) and Group C (4.3) are significantly different, meaning that one of those means is different from the means of the other groups (A: 2.2 and D: 4.5). Therefore, Group B and Group C are the means that are different.

Tukey's Test

Group A vs B: 2.2 - 4.0 = -1.8

Group B vs C: 4.0 - 4.3 = -0.3

Group C vs D: 4.3 - 4.5 = -0.2

Since the difference between Group B and Group C (-0.3) is less than the other differences, we can conclude that Group B and Group C are the means that are different.

The complete question is :

suppose an analysis of variance (anova) has determined that there is a difference between means and the following tukey's results are shown. determine which mean is different.

Group A: 2.2

Group B: 4.0

Group C: 4.3

Group D: 4.5

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Let V be a finite-dimensional vector space and let B ={α 1…,α n } be a basis for V . Let ( | ) be the inner product of V. If c 1,...,c n , are n is a scalar, then show that there exist one vector α∈ V such that (α∣αj)=cj, j=1 ,…,n.

We have given that V is a finite dimensional vector space.

Consider α∈ V defined as

α = α₁β₁ + α₂β₂ + -----+ αₙβₙ where,

β₁ = α₁

β₂= α₂ - (α₁ |β₁)/β₁/β₂ |(β₁)

similarly, __

βⱼ = αⱼ - ( ∑ (αⱼ|βⱼ) / βᵢ|(βᵢ) βᵢ ) , j = 2,n bar

As defined aᵢ, i = 1, j bar

α₁ = c₁/ (β₁ )|β₁

___

α₂ = c₁/ (β₁ )|β₁ - a₁ ( α₂|β₂/β₁|β₂)

proceeding like as we get

_______

αⱼ = 1/β₁|(β₁) (cⱼ - ∑ αⱼ ( αⱼ |βⱼ)

then conider

(α|αⱼ )= ( α₁β₁ + α₂β₂ + -- + αₙβₙ |αⱼ )

= α₁β₁ + α₂β₂ + -- + αₙβₙ |βⱼ ) + ∑ α₁β₁+ α₂β₂ +---+αⱼβᵢ /βᵢβᵢ)

______

(α|αⱼ) =αⱼ(βⱼ |βⱼ) + (cⱼ - ∑ αⱼ ( αⱼ |βⱼ) βⱼ |βⱼ

__ ___

= (cⱼ - ∑ αᵢ ( αⱼ |βᵢ) + ∑αⱼ |βᵢ

(α|αⱼ) = cj, j = 1,n

Hence proved.

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Answer:

Step-by-step explanation:

.17(100)=17

17 meters

Answer:

The Venn diagram below shows information

about the number of items in sets A and B.[asy]

label("A",(0,75));

label("B",(100,75));

label("C",(50,0));

label("D",(0,45));

label("E",(100,45));

draw(Circle((50,60), 40));

draw(Circle((50,30), 40));

draw(Circle((20,60), 20));

draw(Circle((80,60), 20));

[/asy]To find P(A'|B), we can use the formula:P(A'|B) = P(A' and B) / P(B)We can find P(A' and B) by looking at the Venn diagram. It is the number of items in the intersection of sets A' and B, which is represented by the region labeled "D" in the Venn diagram. This region contains 10 items.To find P(B), we can look at the Venn diagram and add up the number of items in both sets B and the intersection of A and B. This is represented by the regions labeled "D" and "E" in the Venn diagram, and contains a total of 20 items.Plugging these values into the formula above, we get:P(A'|B) = (10 items) / (20 items) = 1/2So, the probability that an item chosen at random belongs to A' given that it belongs to B is 1/2. This fraction is already in its simplest form.

Step-by-step explanation:

After evaluating f(x) = 3x - 5, the answer is f(x-2) = 3x - 11

What do you mean by functions?

A mathematical phrase, rule, or law that establishes the link between an independent variable and a dependent variable (the dependent variable). Expressions of well-known functions can be found in many frequently used mathematical formulas. A function in mathematics from a set X to a set Y allocates exactly one element of Y to each element of X.

The set X is called the domain of the function and the set Y is called the codomain of the function.

Given function:

f(x) = 3x - 5

For f(x-2) substitute x as (x-2) in given function

f(x-2) = 3(x - 2) - 5 = 3x - 6 - 5 = 3x - 11

therefore, f(x-2) = 3x - 11

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Answer:

The correct answer is D

Step-by-step explanation:

In order for a relation to be a function, every input for x can only have one output. Therefore, D is the correct answer.

Answer:

D

Step-by-step explanation:

A function is a relation where every input has only 1 output.

Inputs are the x's and outputs are the y's.

Answer a is missing an input.  You have (,0)  The first number is missing.

B is not a function because the input -2 has to outputs 2 and 4.

C is not a function because the input 0 has two outputs 5 and 4

Define the function [tex]R^{+}[/tex]: N ⇒ N where R+(x) = x + [tex]x^{R}[/tex]

(a) Let A₂ = {(x,y) | [tex]R^{+}[/tex] (x) = y} language A₂ ∈L.

(b) Let A₃ = {(x,y) | [tex]R^{+}[/tex] ([tex]R^{+}[/tex] (x)) = y} language A₃ ∈L.

Given that,

For any positive integer x, let [tex]x^{R}[/tex] be the integer with the opposite of x's binary representation in terms of representation. (Assume that x's binary form has no leading 0s.) Specify the function [tex]R^{+}[/tex]: N ⇒ N where R+(x) = x + [tex]x^{R}[/tex]

(a) Let A₂ = {(x,y) | [tex]R^{+}[/tex] (x) = y}. Show A₂ ∈L.

(b) Let A₃ = {(x,y) | [tex]R^{+}[/tex] ([tex]R^{+}[/tex] (x)) = y}. Show A₃ ∈L.

We know that,

Consider the Turing machine M, which computes the inverse of x for every positive inter. The result will also be x if the computation is done using both the integer x and its inverse.

This is because the result of adding a binary number 1 to 0 is always 1. The criterion is that the binary representation of x must not contain 0. In this case, a positive integer x is converted into binary representation.

Only x values with a binary representation of 1 will be accepted by the Turing machine. Even the Turing machine will accept inverse-of-x values with binary representations of 0.

Therefore, It is proved that language A₃ ∈L.

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The statement that servers that exist within a data center that is publicly accessible on the internet are referred to as on-premises servers is False.

HTML5

HTML5 is a markup language used for structuring and presenting content on the World Wide Web. It is the fifth and final major HTML version that is a World Wide Web Consortium recommendation. The current specification is known as the HTML Living Standard.

On-premises servers

On-premises servers refer to the group of servers that are under the control of a private entity. This is not like the traditional cloud computing method where resources can be leased to third-party service providers.

The use of the term, on-premises refers to the local installation of these resources as against the cloud type where the resource is on the vendor's server and a client can reach the software via their internet browsers.

Hypertext Markup Language revision 5 (HTML5) is markup language for the structure and presentation of World Wide Web contents. HTML5 supports the traditional HTML and XHTML-style syntax and other new features in its markup, New APIs, XHTML and error handling.

The statement that servers that exist within a data center that is publicly accessible on the internet are referred to as on-premises servers is False.

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Answer:

  a.  False

  b.  True

  c.  True

  d.  True

  e.  False

Step-by-step explanation:

You want to know the truth value of various logical expressions when b = False, and x = 0.

An And (&&) expression is true if and only if all parts are true. An OR (||) expression is true if any part is true.

When 'b' is false, b&&__ will be false, and !b||__ will be true. This makes (a) and (e) false, and (d) true.

When x = 0, __||x==0 will be true, so (b) is true.

The And (&&) of expression (c) will only be true when both parts are true. For b = False and x = 0, both parts are true, so (c) is true.

   {a, b, c, d, e} = {False, True, True, True, False}

Answer:

48

Step-by-step explanation:

0.8 * 60 = 48

Answer:

y = 57,5°

z = 57,5°

n = 65°

Step-by-step explanation:

Answer:

Your answer is x = 65° , y = 57.5° , z = 57.5°

Step-by-step explanation:

There is a triangle isoscocles so two angles are the same. There is a parallel line where two lines are the same.

<x = 65° and <y° = <z°

so

<x + <y + <z = 180

Plug in angle x.

65° + <y° + <z° = 180°

Subtract 65 to both sides.

<y° + <z° = 180° - 65°

<y° + <z° = 115°

Since <y° = <z° we substitute one of them

<y° + <z° = 115°

<y° + <y° = 115°

Add the <y° together

2y = 115°

Divide 2 to both sides to get y by itself.

<y° = 57.5°

So <y° = <z° = 57.5°

The probability that if I select 10 people, I will get 2 seniors and 8 freshmen is 0.00000901

From the question, we have the following parameters that can be used in our computation:

Also from the question, we have

Number of people selected = 10

To get 2 seniors and 8 freshmen, the probability equation is

Probability = (Seniors)² * (Freshman)⁸

Substitute the known values in the above equation, so, we have the following representation

Probability = (20%)² * (35%)⁸

Evaluate

Probability = 0.0000090075

Approximate

Probability = 0.00000901

Hence, the probability is 0.00000901

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Answer:

20(-2x+5)

10(-4x+10)

Step-by-step explanation:

20(-2x+5) = -40x+100

10(-4x+10) = -40x+100

You just need to expand the brackets

Answer: 19 new bears

Step-by-step explanation: To find the percentage of something, let's recall the formula:

Whole number x part % / 100

So, let's plug in the numbers to the formula:

95 x 20 / 100

95 x 20 = 1900

So, 1900 / 100 = 19; our answer

I hope this helped!

x is the independent variable in the linear equation  ax + by + c = 0

and y is the dependent variable in the linear equation.

Given, an independent variable in a linear function,

we have to define the independent and dependent variables.

Let suppose a linear equation be,

ax + by + c = 0

now, in the above linear equation,

by  = -ax - c

y = -(ax + c)/b

So, the value of variable x in the above linear equation, is independent and don't depend on any other variable whereas the value of variable y in the above linear equation, is dependent as it depends on the value of the variable x.

Therefore, x is the independent variable in the linear equation and y is the dependent variable in the linear equation.

The value of independent variables can be changed by us whereas the value of dependent variables changes on the basis of the value of independent variables.

Hence, the value of independent variables can be changed by us whereas the value of dependent variables changes on the basis of the value of independent variables.

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The total cost of the crafting supplies is $25.5. This can be find using percentage and rate concepts.

What is tax rate and percentage?

A percentage is a portion of a whole expressed as a number between 0 and 100 rather than as a fraction. All of something is 100 percent , half of it is 50 percent , none of something is 0 percent.

Tax is the money that govt collects based on income, sales and other activities.

A tax rate is the percentage at which an individual or corporation is taxed.

In the given que,

Purchased amount = $24.

Tax rate = 6.25%

Tax paid = 24*(6.25/100)

               = $1.5

So, total amount paid = $1.5 + $24

                                    = $25.5

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If the supplied functions are f(x) = - 3x 2 + x - 9 and g(x) = x 3 + 6x and the value of x is -4, the value of (f + g)(- 4) is -137.

A function is an expression, rule, or law in mathematics that describes a connection between one variable (the independent variable) and another variable (the dependent variable). Functions are typically categorized into four categories. Depending on the Element: One function to one function, many functions to one function, onto function, one function to one and onto function, into function A "vertical line test" can be used to identify whether a relation is a function when looking at a graph. If a vertical line can be drawn anywhere on the graph and cross the relation twice, the relationship is not a function.

Here,

(f+g)(x)=f(x)+g(x)

f(-4)=-3*(-4)²-4-9

f(-4)=-61

g(-4)=(-4)³-3*4

g(-4)=-76

(f+g)(-4)=f(-4)+g(-4)

=-61-76

(f+g)(-4)=-137

If the supplied functions are f(x) = - 3x 2 + x - 9 and g(x) = x 3 + 6x and x is -4, the value of (f + g)(- 4) is -137.

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A Coordinate Plane is a two-dimensional plane formed by the intersection of two number lines. One of these number lines is a horizontal number line called the x-axis and the other number line is a vertical number line called the y-axis.

What is a Coordinate Plane?

A Coordinate Plane is a two-dimensional plane formed by the intersection of two number lines. One of these number lines is a horizontal number line called the x-axis and the other number line is a vertical number line called the y-axis.

Elements of the Coordinate Plane

Quadrants: The two number lines divide the coordinate plane into 4 regions. These regions are called Quadrants. The quadrants are denoted by roman numerals and each of these quadrants have their own properties.

Quadrant I: The upper right Quadrant is the first Quadrant denoted as Quadrant I. In this quadrant, the x-axis and the y-axis both have positive numbers.

Quadrant II: The upper left Quadrant is the second Quadrant denoted as Quadrant II. In this quadrant, the x-axis has its negative numbers and the y-axis has positive numbers.

Quadrant III: The bottom left Quadrant is the third Quadrant denoted as Quadrant III. In this quadrant, both the x-axis and the y-axis have negative numbers.

Quadrant IV: The bottom right Quadrant is the fourth Quadrant denoted as Quadrant IV. In this quadrant, the x-axis has positive numbers and the y-axis has negative numbers.

1.The coordinate plane was created hundreds of years ago. The system is commonly referred to as the Cartesian coordinate system because French mathematician René Descartes invented it.

2.The points on the x-axis have their y-coordinate 0 so the points on x-axis are represented as (x,0) and similarly the points on y-axis have their x-coordinate 0, so they are represented as (0,y).

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Answer:

Definition - The plane containing the "x" axis and "y" axis.

Examples - (4,9), (24,90), etc

Facts - The coordinate plane is a two-dimension surface formed by two number lines. One number line is horizontal and is called the x-axis. The other number line is vertical number line and is called the y-axis. The two axes meet at a point called the origin.

Step-by-step explanation:

Absolute Value: The "unsigned" number that corresponds to the (Positive) distance between a number and zero on the number line. [tex]| - 4| = 4 and | 4| = 4;[/tex]

Positive and negative integers, fractions, rational numbers, including irrational numbers, and negative integers are all examples of real numbers. fictitious numbers,  Real numbers are those that fall between the two extremes,

Absolute Value: The "unsigned" number that corresponds to the (Positive) distance between a number and zero on the number line. | - 4| = 4 and | 4| = 4; The collection of positive numbers used to count items is known as the counting numbers, sometimes known as natural numbers. 1, 2, 3, 4, 5, ...; Fractions and decimals are not integers; rather, integers are the set of all whole numbers, along with their opposites (the positive whole numbers, the negative whole numbers, and zero). -3, -2, -1, 0, 1, 2, 3, ...; Irrational Numbers - The collection of all non-terminating, non-repeating decimal numbers; Natural Integers: The collection of positive numbers utilized in object counting (also called counting numbers). 1, 2, 3, 4, 5, ...; Unfavorable Numbers - the range of numbers on the number line that are less than zero and to the left of zero.; Number Line - a horizontal line with points representing different numbers. In a number line with just whole numbers or integers, the dots are uniformly spaced out according to the value of the number they represent.; Opposite - a number that is on the other side of zero and at the same distance from zero as a given integer. For instance, the opposites of 7 and -7 and 9 and 9 are both 7; positive figures - the group of numbers on the number line that are greater than zero and to the right of zero.

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The additive inverse of 5 + i  is (-5) + (-1)

To get a result equal to 0, add the original number and the additive inverse by simply changing the sign of the integer. On the basis of negation of the original number, the characteristics of additive inverse are listed below. For instance, if x is the starting number, then -x is x's additive inverse.

Given:

5 + I

As, the additive inverse is the opposite sign of the given number.

For example, if the number is -6 and we have to find its additive inverse.

So, the additive inverse will be 6.

Similarly for 5 + i ;

the additive inverse is (-5) + (-1)

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Resources that are available in limited quantities on the earth are called Exhaustible resources.

The resources which are present in limited amounts are referred to as exhaustible resources. These resources can be consumed and end someday and are also termed non-renewable resources.

Exhaustible natural resources are available in a limited quantity and cannot be replaced within a reasonable period of time and have the risk of being exhausted by human activities. Such Resources take millions of years to form.

Exhaustible resources are usually not environmentally friendly since they are improperly and inefficiently used and are generally very expensive.

Coal, petroleum, and Forests are examples of exhaustible natural resources.

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Answer:

47.3 m³

Step-by-step explanation:

The garden shed is made up of a rectangular prism and a pyramid.

[tex]\begin{aligned}\textsf{Volume of a rectangular prism}&=\sf width \times length \times height\\&=4 \times 4 \times 2\\&=16 \times 2\\&=32\;\; \sf m^3\end{aligned}[/tex]

From inspection of the given diagram, the slant height of the pyramid is 3.5 m.  

Calculate the perpendicular height of the pyramid using Pythagoras Theorem:

[tex]\begin{aligned}\implies a^2+b^2&=c^2\\2^2+h^2&=3.5^2\\h^2&=8.25\\h&=\sqrt{8.25}\;\; \sf m\end{aligned}[/tex]

Therefore:

[tex]\begin{aligned}\textsf{Volume of a pyramid}&=\dfrac{\sf length \times width \times height}{3}\\\\&=\dfrac{\sf 4 \times 4 \times \sqrt{8.25}}{3}\\\\& = 15.31883372\;\; \sf m^3\end{aligned}[/tex]

[tex]\begin{aligned}\implies \textsf{Volume of shed}&=\textsf{Volume of rectangular prism}+\textsf{Volume of pyramid}\\&=32+15.31883372\\& = 47.3\;\; \sf m^3\;(nearest\;tenth)\end{aligned}[/tex]

Answer:

F = (9/5)C + 32

Step-by-step explanation:

C = 5/9(F-32)        **you wrote the fraction wrong in your question, it's 5/9, not 5/6

C = (5F)/9 - 160/9

C + 160/9 = (5F)/9

9C + 160 = 5F

(9C + 160)/5 = F

F = (9/5)C + 32

Answer:                   F = (6C/5) + 32

To express F in terms of C, rearrange the equation to isolate 'F'.

To rearrange the equation, we want 'F' to be by itself. To move numbers to the other side, we do the other pair of inverse operation to both sides. This cancels out what we don't need while keeping the left and right sides equal.

Pairs of inverse operations

[tex]\displaystyle { C = \frac{5}{6}*(F-32) }[/tex]                  Start with the equation in the question.

[tex]\displaystyle { C = \frac{5*(F-32)}{6} }[/tex]                  Rewrite. This is the same as the question.

[tex]\displaystyle { 6C = \frac{5*(F-32)}{6}*6 }\\[/tex]           Multiply both sides by 6.

[tex]\displaystyle { 6C = 5*(F-32) }[/tex]                 Cancelled out 6 on the right.

[tex]\\\displaystyle { \frac{6C}{5} = \frac{5*(F-32)}{5} }[/tex]                Divide both sides by 5.

[tex]\displaystyle { \frac{6C}{5} = (F-32) }[/tex]                      Cancelled out 5 on the right.

[tex]\displaystyle { \frac{6C}{5} = F-32 }[/tex]                         We don't need the brackets if 'F - 32' is alone.

[tex]\displaystyle { \frac{6C}{5}+32 = F-32+32 }[/tex]         Add 32 to both sides.

[tex]\displaystyle { \frac{6C}{5}+32 = F }[/tex]                         Cancelled out 32 on the right.

[tex]\displaystyle { F = \frac{6C}{5}+32 }[/tex]                         Keep lone variables on the left side.

Therefore, the equation to convert Celsius to Fahrenheit is:

           [tex]\displaystyle { F = \frac{6C}{5}+32 }[/tex]

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The geometric figure above has been dilated by a scale factor of 4/3 centered at the origin and plotted in the graph attached below.

In Geometry, dilation can be defined as a type of transformation which typically changes the size of a geometric object, but not its shape. This ultimately implies that, the size of the geometric object would be increased or decreased based on the scale factor used.

Next, we would have to dilate the coordinates of the preimage by using a scale factor of 4/3 centered at the origin as follows:

Coordinate X (-3, -6) → Coordinate X' (-3 × 4/3, -6 × 4/3) = Coordinate A' (-4, -8).

Coordinate Y (3, 3) → Coordinate Y' (3 × 4/3, 3 × 4/3) = Coordinate A' (4, 4).

Coordinate Z (-3, 6) → Coordinate Z' (-3 × 4/3, 6 × 4/3) = Coordinate A' (-4, 8).

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The dimensions of the radius is 4/3[tex]\sqrt{2}[/tex] and that of height is 8/3.

Let r be the radius of the cone,  be the radius of the sphere and h be the height of the cone.

Let's put DˆOB=x with limitations 0≤x≤π.

In the right-angled triangle DOB:

r=DB=Rsinx, OD=Rcosx, than

h=CD=OC+OD=R+Rcosx=R(1+cosx).

So the volume of the cone is:

V=1/3πr²h ⇒V=1/3π(Rsinx)²⋅R(1+cosx)

V=1/3πR³sin²x(1+cosx)

V'=1/3πR³⋅[2sinx⋅cosx⋅(1+cosx)+sin2x(−sinx)]

  =1/3πR³sinx[2cosx(1+cosx)−sin2x]

  =1/3πR³sinx(2cosx+2cos2x−sin2x)

  =1/3πR³sinx(2cosx+2cos2x−1+cos2x)

 =1/3πR³sinx(3cos2x+2cosx−1)

Now let's find the signum of the derivative, since sinx≥0 for every x in the limitations, then:

V'≥0⇒3cos²x+2cosx−1≥0

      ⇒Δ/4=(b/2)²−ac =1+3=4

cosx=(−b/2)±√Δ/4 / a

      =−1±2/3,

So:

cosx≤−1∨cosx≥1/3

The first one has only the solution:

x=π

the second:

−arccos(1/3)≤x≤arccos(1/3), but for the limitations:

0≤x≤arccos(1/3).

The function gros from zero to arccos(1/3), and then it decreases.

So x=arccos(1/3) is the maximum requested.

Let's find now r and h:

r=Rsinx

 =R√1−cos2x

 = 2√1−(1/3)²

 = 2√1−1/9

 =2√9−1/9

 =2√8/9

 =2⋅2√2/3

 =4/3√2

h=R(1+cosx)=2(1+1/3)

 =2(3+1/3)

=8/3.

Therefore the radius is 4/3√2 and the height is 8/3.

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