3. e ssm a battery charger is connected to a dead battery and delivers a current of 6.0 a for 5.0 hours, keeping the voltage across the battery terminals at 12 v in the process. how much energy is delivered to the battery?

Answer:

The distance between the two objects

The force is directly proportional to the product of the masses of the two objects and inversely proportional to the square of the distance between them

Explanation:

The waves created by the boat have a speed of 25.3 km/h, a period of approximately 0.37 hours, and a frequency of approximately 0.027 h⁻¹

When a boat travels at a certain speed across the surface of a still lake, it creates a series of waves that spread outwards from the boat. The speed of these waves depends on the properties of the water, such as its depth and temperature.

In this case, the boat is traveling at a speed of 43.0 km/h across the surface of a still lake, and the waves it creates in the water have a speed of 25.3 km/h.

The speed of the waves created by the boat can be calculated using the formula:

v = sqrt(gλ/2π)

where v is the speed of the waves, g is the acceleration due to gravity (9.81 m/s^2), λ is the wavelength of the waves, and π is the mathematical constant pi (approximately equal to 3.14).

Assuming that the wavelength of the waves is proportional to the speed of the boat, we can use the following formula to relate the wavelength of the waves (λ) to the speed of the boat (vb) and the speed of the waves (v):

λ = (v + vb) T

where T is the period of the waves, which is the time it takes for one complete wavelength to pass a fixed point.

We can rearrange this formula to solve for the period:

T = λ / (v + vb)

Substituting the given values, we get:

T = λ / (v + vb) = (25.3 km/h) / (43.0 km/h + 25.3 km/h)

T ≈ 0.37 hours

Finally, we can use the period of the waves to calculate their frequency (f), which is the number of waves that pass a fixed point in one second:

f = 1 / T

f = 1 / 0.37 hours ≈ 0.027 h⁻¹

Therefore, the waves created by the boat have a speed of 25.3 km/h, a period of approximately 0.37 hours, and a frequency of approximately 0.027 h⁻¹.

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1. The z-component of the magnetic field due to charge one at the origin of the coordinate system, in teslas is (4π x [tex]10^{-7}[/tex] T m/A).

2. The z-component of the magnetic field due to charge two at the origin of the coordinate system, in teslas is 6.06 x [tex]10^{-5}[/tex] T.

3. The total magnetic field, in the z-direction, at the origin, due to the two charges, in teslas is 6.05 x [tex]10^{-5}[/tex] T.

1. To calculate the magnetic field at the origin of the coordinate system due to the two moving charges, we can use the Biot-Savart law, which relates the magnetic field at a point to the current or the moving charges producing it.

Let's first calculate the magnetic field at the origin due to charge one:

The magnitude of the magnetic field at a point due to a moving charge can be calculated using the equation:

B = (μ0/4π) x (q v sinθ / r²).

2. In this case, charge one has a charge of 0.15 C and is moving at a speed of 18.5 x [tex]10^6[/tex] m/s. The distance between charge one and the origin is 0.65 m.

B1 = (μ0/4π) x (0.15 x 18.5 x [tex]10^6[/tex] / 0.65²) = 6.06 x [tex]10^{-5}[/tex] T

The z-component of this magnetic field is zero since the field is perpendicular to the z-axis.

3. Next, let's calculate the magnetic field at the origin due to charge two:

B2 = (μ0/4π) x (5.50 x 2.5 x 10 / 0.65²) = -1.26 x [tex]10^{-7}[/tex] T

The negative sign indicates that the magnetic field due to charge two is directed along the negative z-axis.

Finally, let's calculate the total magnetic field at the origin due to both charges:

Since the magnetic fields due to the two charges are perpendicular to each other, we can simply add their magnitudes to obtain the total magnetic field in the z-direction:

Btot = B1 + B2 = 6.06 x [tex]10^{-5}[/tex] - 1.26 x [tex]10^{-7}[/tex] = 6.05 x [tex]10^{-5}[/tex] T

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The question is -

Consider the two charges, which are moving in opposite directions and located at a distance of 0.65 m on either side of the origin of the given coordinate system. Charge one is 0.15 C and is moving at a speed of 18.5 x 106 m/s, and charge two is 5.50 and is moving at a speed of 2.5 x 10 m/s.

The maximum angle (with respect to the horizontal) of a smooth rock that can be walked on without slipping is 50°.

Friction is a force that acts between two rough shells, whenever one tries to move one face against the other. When a force F pushes an object in one direction, there appears a disunion force in the contrary direction. Before stir thresholds, we're in the governance of static disunion.

Once the applied force is increased, the static disunion increases at the same rate, until it's reached a outside, denoted by maximum static disunion, and defined by the formula

[tex]f_s = \mu_s N[/tex]

The static measure between the shoe and the smooth gemstone is μs= 1.2

and hence the maximum static disunion is given by,

[tex]f_s = \mu_s N[/tex]

where N is the magnitude of the normal force. The forces acting on the shoe are

The gravitational force wielded by the Earth, of magnitude

F = mg

The normal force N wielded by the face of the gemstone, directed typically outwards from the gemstone.

The( static) disunion, wielded by the gemstone, in the direction overhead the gemstone( opposed to the tendency of slipping).

N - Fcosθ

N = Fcosθ

f = μFcosθ,

μFcosθ = Fsinθ

μ = sinθ/cosθ

Given by is the maximum (or critical) angle.

[tex]\theta_m_a_x = arctan\mu_s = arctan(1.2) = 50^0[/tex]

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Complete question:

Shoes made for the sports of bouldering and rock climbing are designed to provide a great deal of friction between the foot and the surface of the ground. Such shoes on smooth rock have a coefficient of static friction of 1.2 and a coefficient of kinetic friction of 0.90. For a person wearing these shoes, what is the maximum angle (with respect to the horizontal) of a smooth rock that can be walked on without slipping?

The value of n for the electron emissions will be refer in each of the photoelectric effect, radioactivity. electron microscopy.

Photoelectric effect: In this process, electrons are emitted from a metal surface when light is shone on it. The energy of the incident light is absorbed by electrons in the metal, causing them to be ejected from the surface. "n" could refer to the energy level of the electron in the metal before it is ejected, which would determine the kinetic energy of the emitted electron.

Radioactive decay: Some radioactive isotopes undergo a process called beta decay, in which a neutron in the nucleus decays into a proton, emitting an electron in the process. "n" could refer to the energy level of the electron in the nucleus before it is emitted.

Electron microscopy: In electron microscopy, a beam of electrons is used to image a sample at high resolution. "n" could refer to the number of electrons emitted from the source, which would determine the intensity of the electron beam.

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The electric field follows vector superposition while the voltage follows scalar superposition, which is the difference between the two superpositions (i.e., The net electric field at any point is the vector sum of the electric field due to the individual charges).

What is Electric field?

The term "electric field" refers to the physical field that surrounds electrically charged particles and acts to either attract or repel all other charged particles in the field (or E-field). One of the four fundamental interactions, or forces, of nature is the electromagnetic field, which manifests in both electric and magnetic fields. Electric fields, which are significant in many parts of physics, are used in electrical technology.

For instance, in atomic physics and chemistry, the electric field serves as the attractive force that holds the atomic nucleus and electrons of an atom together.

Moreover, it is the force that causes molecules to form when atoms bind chemically.

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On light snow and hard snow, the coulomb friction coefficients were estimated to be 0.03 and 0.05, respectively. In this investigation, the intermediate and final phases of the coulomb friction coefficient were between 0.03 and 0.04. Thus, option B is correct.

The snow exerts kinetic frictional force on the sled's runners, slowing down and ultimately stopping the sled from moving. The coefficient of kinetic friction is 0.050.

Determine the value of the friction force.

[tex]F=uN = [0.05] [5000N] = 250N[/tex]

Here, N is the sledge's normal reaction force.

Write the expression for the work done.

[tex]F = f *d[/tex]

Here, d represents the horizontal distance.

[tex]W= (250)N (1000m) = 2.5 * 10^5 J[/tex]

Therefore, 2.5 * 10^5 The dog team pulls the sledge 1000 meters at a consistent speed to complete the task.

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The given question is incomplete. The complete question is given below:

A sledge (including load) weighs 5000 N. It is pulled on level snow by a dog team exerting a horizontal force on it. The coe�cient of kinetic friction between sledge and snow is 0.05. How much work is done by the dog team pulling the sledge 1000 m at constant speed?

A. 2.5×10^4J

B. 2.5×10^5J

C. 5.0×10^5J

D. 2.5×10^6J

E. 5.0×10^6J

The capacitor is used to store charge.

We have to know that the capacitor is the kind of device that can be used to store the electrical charges. As such, the capacitor can be able to be charged from a battery.

This question is incomplete and the mathematical details of the problem are missing. However, we should know that the efficiency of the charging would depend on the kind of battery that has been used and the nature of the capacitor as we have in the question above here.

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at the velocity of 60 degree angle above the horizontal should the ball be thrown so that the runner will catch it just before it hits the ground

For the person to be able to catch the ball, the horizontal component of velocity of the ball should be same as the speed of the person, i.e.,

v 0 cosθ= 2v 0

​  or cosθ= 21

​  or θ=60 ∘ .

Velocity is the directional speed of an object in motion as an indication of its rate of change in position as observed from a particular frame of reference and as measured by a particular standard of time.

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According to the laws of thermodynamics, all energy transformations are inefficient because every reaction loses some energy to the surroundings as heat

The second law of thermodynamics states that entropy in a system always has a tendency to rise. It claims that because some energy is constantly lost as heat with each energy transfer, no energy transfer mechanism is ideal. The system's entropy rises as a result of the energy wasted. Due to this, only 10% of the energy from one tropic level gets transferred to the next, with the remaining 90% being wasted as heat.

According to the second rule of thermodynamics, some energy is transferred as heat. Numerous biological processes include this ineffective energy transfer.

This indicates that part of the input energy gets transformed into a highly disordered form of energy when energy is transformed into a different form.

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By the help of potential energy of the spring, so option A) 0.21 m/s is the correct answer.

There is no energy in the spring in its normal state, which is when it is not stretched. However, the spring can store energy when it is in a position that is different from its normal position because of the position. Potential energy is the name for this accumulated energy. The accumulated potential energy as a result of a specific elastic item, such as a spring, deforming is known as the potential energy of the spring. It reflects the labor involved in stretching the spring and is dependent on both the length of the stretch and the spring constant, k.

the energy of the spring = [tex]\frac{1}{2} kx^2[/tex]

so it depends on spring's constant

and change  in length

so it is independent of mass

so, A) remains the same is the correct answer

B) total energy =[tex]0.5mv^2= 0.5\times0.2\times0.3^2[/tex]

total energy =  [tex]9\times10^-3 J[/tex]

v = 0.21 m/s

so 0.21 m/s is the correct answer

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The magnitude of the acceleration experienced by an electron in an electric field of 750 N/C is approximately 1.318 × 10¹⁴ m/s².  

If the electric field is in the direction of positive x-axis, the electron will be accelerated in the negative x-axis direction. If the electric field is in the direction of positive y-axis, the electron will be accelerated in the negative y-axis direction, and so on.

The magnitude of the acceleration experienced by an electron in an electric field can be calculated using the formula:

a = F/m

where F is the force experienced by the electron in the electric field, and m is the mass of the electron.

The force experienced by an electron in an electric field is given by:

F = qE

where q is the charge of the electron, and E is the electric field strength.

The mass of an electron is approximately 9.11 × 10⁻³¹ kg, and the charge of an electron is -1.602 × 10⁻¹⁹ C.

Substituting these values, we get:

F = (-1.602 × 10⁻¹⁹ C) × (750 N/C) = -1.2015 × 10⁻¹⁶ N

a = F/m = (-1.2015 × 10⁻¹⁶ N) / (9.11 × 10⁻³¹ kg) ≈ -1.318 × 10¹⁴ m/s²

Therefore, the magnitude of the acceleration experienced by an electron in an electric field of 750 N/C is approximately 1.318 × 10¹⁴m/s².

The direction of the acceleration of the electron depends on the direction of the electric field at that point. By convention, the direction of the electric field is the direction in which a positive charge would experience a force. Since the charge of an electron is negative, the force experienced by an electron in an electric field is opposite in direction to the electric field.

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The acceleration of the car is [tex]11.63 m/s^2.[/tex] The force produced by the car is 4,876.4 Newtons.

To find the acceleration of the car, we can use the formula:

acceleration = (final velocity - initial velocity) / time

In this case, the initial velocity is 0 m/s, the final velocity is 50 m/s, and the time is 4.3 s. Substituting these values into the formula, we get:

acceleration = (50 m/s - 0 m/s) / 4.3 s =[tex]11.63 m/s^2[/tex]

Therefore, the acceleration of the car is[tex]11.63 m/s^2.[/tex]

To find the force produced by the car, we can use Newton's second law of motion, which states that force is equal to mass times acceleration:

force = mass x acceleration

In this case, the mass of the car is 420 kg, and the acceleration is 11.63 m/s^2. Substituting these values into the formula, we get:

[tex]force = 420 kg \times 11.63 m/s^2 = 4,876.4 N[/tex]

Therefore, the force produced by the car is 4,876.4 Newtons.

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A circuit in which two light bulbs with equal resistance values are connected in parallel. if one of the light bulbs burns out, By factor (2) is the brightness of the other bulb multiplied.

When two identical light bulbs are connected in parallel, the total resistance of the circuit is half of the resistance of each individual bulb. If one of the bulbs burns out, the total resistance of the circuit doubles, which means that the current through the remaining bulb is halved. The brightness of a light bulb is directly proportional to the current passing through it, so the brightness of the remaining bulb will be reduced by a factor of 2.

I = V/R

If both bulbs have the same resistance R and the same voltage V is applied to each, then the current passing through each bulb is:

I = V/R

When both bulbs are connected in parallel, the total current in the circuit is the sum of the currents through each bulb:

[tex]I_t_o_t_a_l = I_1 + I_2[/tex]

here,

[tex]I_1[/tex] & [tex]I_2[/tex] are currents passing by each bulb.

Reserving Ohm's law:-

[tex]I_t_o_t_a_l = V/R + V/R[/tex]

Simplifying:-

[tex]I_t_o_t_a_l = 2V/R[/tex]

The power P dissipated by each bulb is given by:

[tex]P = IV = V^2/R[/tex]

So the brightness of each bulb is proportional to [tex]V^2[/tex]. If one bulb burns out, the voltage across the remaining bulb remains the same, but the resistance of the circuit doubles, so the current passing through the remaining bulb is halved. This means that the power dissipated by the remaining bulb is reduced by a factor of 2, which corresponds to a reduction in brightness by the same factor. Therefore, the brightness of the remaining bulb is reduced by a factor of 2.

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If uniform beam with a mass of 120 kg and a length of 5.0 m rests on two supports, one at the left edge and one 3.0 m from the left edge then 1.6 m close to the right edge can a 68-kg person walk along the beam without causing it to tip over.

What is mass?

A body's mass is an innate characteristic. Prior to the discovery of the atom and particle physics, it was widely considered to be connected to the amount of matter in a physical body. It was found that different atoms and elementary particles had varying masses even if they theoretically contain the same quantity of stuff. In modern physics, there are a number of theoretically distinct but physically equal theories of mass. Experimentally, the mass of a body can be used to quantify its resistance to acceleration (change in velocity) in the presence of a net force.

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Both caesium-137 and iodine-131 emit ionizing radiation, which can damage living tissue and increase the risk of cancer.

Isotopes are members of the same element's family but have variable numbers of neutrons despite having the same number of protons.

Iodine-131 and caesium-137 both produce ionizing radiation, which can harm living things and raise the risk of cancer.

Due to their varied half-lives and processes of decay, each isotope's danger has changed between 1986 and 2018 despite this.

Caesium-137 degrades gradually over time since it has a longer half-life of roughly 30 years. Iodine-131, on the other hand, degrades swiftly because of its significantly lower half-life of only around 8 days.

Thus, the risk has diminished over time as a result of radioactive decay.

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The block gains 4.49 J of kinetic energy as it moves a distance of 2 m

The increase in kinetic energy of an object can be calculated using the equation:

ΔKE = 1/2 (m)(Δv^2)

where;

To find the change in velocity, we can use the equation of motion, which states that the net force on an object is equal to its mass times its acceleration:

F = ma

Rearranging this equation, we can find the acceleration:

a = F / m

The acceleration is the same before and after the force increases, so we can equate the two and solve for Δv:

F1 / m = F2 / m

F1 / m = (F1 + ΔF) / m

ΔF / m = F2 / m - F1 / m

ΔF / m = (12 N) / (2 kg) - (5 N) / (2 kg)

ΔF / m = 4.5 m/s^2

Δv = √(2 * ΔF / m)

Now that we have Δv, we can plug this value into the equation for ΔKE:

ΔKE = 1/2 * m * Δv^2

ΔKE = 1/2 * 2 kg * (2.12 m/s)^2

ΔKE = 4.49 J

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The distance between two pool balls are separated by 0.0424 m.

The gravitational pull draws any two mass-containing things together. It mentions the gravitational force. The force will always be applied along the line joining the two masses in the direction of the other mass, according to the formula F=Gm1m2r2.

The following formula can be used to determine the gravitational force between two objects:

F = G * (m1 * m2) / r²

where F is the gravitational force's strength, G is the gravitational constant (6.67 x 10-11 N×m2/kg), m1 and m2 are the objects' masses, and r is the separation between them.

To determine the separation between the two pool cues To account for r, we can rearrange this expression as follows:

Represents the objects' masses, while r denotes the separation between their mass centres.

Rearranging this formula to solve for r will allow us to get the distance between the two pool balls:

r = √(G × m1 × m2 / F)

Substituting the given values, we get:

r = √(6.67 x 10⁻¹¹ N*m²/kg² × 0.300 kg × 0.400 kg / 8.92 x 10⁻¹¹ N)

r = 0.0424 m

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Answer:

Advantages of being firstborn:

Disadvantages of being firstborn:

Explanation:

Answer:

Advantages and disadvantages of being firstborn

Explanation:

Advantages of being a firstborn include having higher self-esteem and academic achievements, being seen as more responsible, and receiving extra attention from parents.

Disadvantages of being a firstborn include the pressure to live up to high expectations and the possibility of feeling resentful that their younger siblings get more freedom.

Addition work required to move spring by extra 10cm is 12J.

Define sprint constant.

A restoring force that is proportional to the spring's displacement is stored in a spring when it is compressed or relaxed. The force needed to extend or compress a spring by a unit length is specified by the spring constant. The stiffness constant is another name for it.

According to Hooke's Law, the force required to compress or lengthen a spring is inversely related to the length of the spring. By deducting the initial work from the overall job or the completed work, additional work can be computed.

Work done = 1/2 kx^2

x1 = 10cm = 0.1m

x2 = 10+10 = 20cm = 0.2m

W1 = 4J

W1 = 4 = 1/2 k *0.1*0.1

k = 4*2 /0.01 = 800N/m

W2 = 1/2 *800*0.2*'0.2

W2 = 400*0.04 = 16J

So required work is W = W2-W1

W 16-4 = 12J

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The shopping cart moves a distance of 4.57 meters in 3.00 seconds.

Using Newton's second law, which relates force, mass, and acceleration we can solve this problem

F = ma

where F is the net force acting on the object, m is its mass, and a is its acceleration.

In the given problem, the net force acting on the shopping cart is 14.0 N, and its mass is 15.5 kg. We can rearrange the equation above to solve for the acceleration of the cart:

a = F/m

a = 14.0 N / 15.5 kg

a = 0.9032 [tex]m/s^2[/tex]

Now we can use the kinematic equation that relates distance, acceleration, and time:

d = 1/2 * a * [tex]t^2[/tex]

where d is the distance traveled, a is the acceleration, and t is the time.

Plugging in the values we have:

d = 1/2 * 0.9032 [tex]m/s^2[/tex] * [tex](3.00 s)^2[/tex]

d = 4.57 meters

Therefore, the shopping cart moves a distance of 4.57 meters in 3.00 seconds.

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The two kinds of balance that keep the Sun shining are thermal equilibrium and hydrostatic equilibrium.

Thermal Equilibrium: The Sun shines by nuclear fusion, a process in which hydrogen atoms combine to form helium and release energy in the form of light and heat.

Hydrostatic Equilibrium: The Sun is also in hydrostatic equilibrium, which is the balance between the inward gravitational force and the outward pressure force.

These two balances are delicately intertwined and any disturbance to them could result in a catastrophic event such as a supernova or a collapse.

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Below are the variables known and unknown of an air-filled pipe that have successive harmonica at 480hz, 800hz, 1120hzKnown. Successive harmonics at 480 Hz, 800 Hz, and 1120 Hz Unknown.

Harmonics are overtones that are multiples of the fundamental frequency of a sound. They are produced when a sound wave is reflected from a surface, such as a wall or floor, and create a pleasant, ringing sound.

They are often used in music to create a fuller, richer sound. Harmonics can also be used to create a variety of effects in sound production, such as reverberation and echo.

For example, if a guitar is plucked, the note being played has a fundamental frequency but also has overtones which are produced by the guitar's body and strings.

To calculate the length of the pipe, it would be necessary to know the frequency of the first harmonic (the fundamental) and the frequency of the last harmonic. Without knowing this, it is not possible to calculate the length of the pipe.

Therefore, These overtones create a richer sound and are known as harmonics. The length of the pipe is unknown because the known harmonics do not provide enough information to calculate it.

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Answer:

12 Kilometers

Explanation:

To find the distance Sarah travels in a given time, we can use the formula:

distance = speed * time

In this case, the speed of the horse is 8 km/h and the time Sarah travels is 1 1/2 hours.

distance = 8 km/h * 1 1/2 hours = 12 km

So, Sarah can travel 12 kilometers in 1 1/2 hours.

Answer:

Work is defined as the product of force and distance in the direction of force because it represents the amount of energy that is transferred from one object to another as a result of a force being applied over a certain distance.

The definition of work as the product of force and distance (W = Fd) is based on the concept of energy transfer. Energy is defined as the ability to do work, and work is defined as the transfer of energy from one object to another. When a force is applied to an object over a certain distance, the energy that is transferred is equal to the amount of work done.

a) initial is 80.12°C and final temperature is 181.28°C b) Initial vapor mass is 2kg and liquid water is 0.7923 kg c) Heat transfer is 324.09 kJ

Law of thermodynamics:

ΔU = Q - W

Find initial state:

Specific volume of the mixture from the tables, which is [tex]0.9505 m^3/kg[/tex].

(a) Water has gone pressure condition (assumption). We can use the steam tables to find the specific volume of the water at the end of the process:

The specific volume of the water:  [tex]0.9505 m^3/kg.[/tex]

Volume increases by 20%, so final: [tex]1.1406 m^3/kg[/tex].

Pressure: 500 kPa.

Saturation temperature: 500 kPa is 153.97°C.

Therefore, water is superheated region.

Specific volume water is: [tex]1.1406 m^3/kg.[/tex]

Temperature 181.28°C.

Initial temperature: 80.12°C

Final temperature: 181.28°C.

(b) Water is in pressure under piston.

The specific volume of water: [tex]0.9505 m^3/kg[/tex].

The pressure increases to 500 kPa: superheated vapor region:

Vapor specific volume: [tex]1.4074 m^3/kg[/tex].

Use ideal gas law:

V = m * v

V = [tex]2 kg * 1.4074 m^3/kg = 2.8148 m^3[/tex]

Since volume increases by 20%, initial volume is[tex]2.3457 m^3[/tex].

Use ideal gas law:

P * V = m * R * T

m = P * V / (R * T)

where R: gas constant

At 500 kPa and 181.28°C, the value of R * T is 298.48 kJ/kg.

Substituting:

m = [tex]500 kPa * 2.3457 m^3 / (0.4615 kJ/kg-K * 298.48 K) = 7.5768 kg[/tex]

Therefore, the mass of liquid water when the piston first starts moving is 3 - 7.5768 = -4.5768 kg.

It cannot be negative so therefore, some liquid water is present.

The specific enthalpy of the liquid water is 334.28 kJ/kg.

For saturated vapor =  2779.2 kJ/kg.

Initial enthalpy: 334.28 kJ.

Final pressure: 500 kPa

Final enthalpy:

[tex]H_final = H_initial + m_evap * (h_vap - h_liq)[/tex]

Substituting:

[tex]334.28 kJ + m_evap * (2779.2 kJ/kg - 334.28 kJ/kg) = H_finalH_final = 334.28 kJ + m_evap * 2444.92 kJ/kg[/tex]

Vapor specific volume: 1.4074 m^3/kg

Total volume:

[tex]V_final = V_initial + m_evap * v_vap[/tex]

Substituting:

[tex]2.3457 m^3 + m_evap * 1.4074 m^3/kg = V_final[/tex]

As 20% increase,

1.2 * V_initial = V_final

Substitute:

[tex]1.2 * 2.3457 m^3 = 2.8148 m^3 + m_evap * 1.4074 m^3/kgm_evap = (1.2 * 2.3457 m^3 - 2.8148 m^3)[/tex]

[tex]m_evap = (1.2 * 2.3457 m^3 - 2.8148 m^3) / 1.4074 m^3/kg = 0.2077 kg[/tex]

Mass of liquid when piston moves: 0.7923 kg.

c) To find work, use Thermodynamics 1st law:

Q = deltaU + W

Assume it is adiabatic process.

[tex]deltaU = m_evap * (u_vap - u_liq)[/tex]

The specific internal energy of the liquid water is 334.28 kJ/kg.

For saturated: 2594.2 kJ/kg.

Substitute:

deltaU = 0.2077 kg * (2594.2 kJ/kg - 334.28 kJ/kg) = 468.69 kJ

Work done is:

W = -P * deltaV

The specific volume of the liquid water is 0.0010441 m^3/kg.

The specific volume is 1.4074 m^3/kg.

Substitute:

deltaV = m_evap * (v_vap - v_liq)

Substituting:

deltaV = [tex]0.2077 kg * (1.4074 m^3/kg - 0.0010441 m^3/kg) = 0.2892 m^3[/tex]

Work done:

W = [tex]-500 kPa * 0.2892 m^3 = -144.6 kJ[/tex]

Heat transfer:

Q = [tex]deltaU + W = 468.69 kJ - 144.6 kJ = 324.09 kJ[/tex]

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(a) For graph A the object is moving at a zero constant speed.

(b) For graph B the object is moving at a constant speed greater than zero.

(c) For graph C the object is moving a uniform speed.

Constant velocity refers to a situation in which an object moves at a constant speed in a straight line. This means that the magnitude of the velocity (i.e. the speed) of the object remains the same over time, while its direction may or may not change.

Uniform velocity refers to a situation in which an object moves with a constant speed, but also changes its direction. In other words, the object has a constant magnitude of velocity (i.e. speed), but its direction is constantly changing. An object moving in a circular path at a constant speed is an example of an object with uniform velocity.

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Answer:

 Kinetic energy plus potential energy equals total mechanical energy. The equation for this is KE + PE = Total Mechanical Energy, where KE is kinetic energy, PE is potential energy, and Total Mechanical Energy is the total amount of energy present.