Which of these describes the role of gelada baboons in their ecosystem?
Answer:
Gelada baboons plays a significant role.
Explanation:
The role of gelada baboons in their ecosystem is very important because they aerate the soil for plants which is necessary for good plant growth. These gelada baboons also helps in controlling the population of predator in their ecosystem which is very essential for the stability and equilibrium of the ecosystem so gelada baboons has a good effect on both plants and animals in their ecosystem.
Answer: Primary Consumer
Explanation: Gelada Baboons are herbivores, :D
8.3.2 Test (CST): Chemical Reactions Question 2 of 25 For a certain chemical reaction, the bond energy of the reactants is 68 kJ, and 25 kJ of energy is released. For energy to be conserved, what is the bond energy of the products? O A. 83 kJ O B. 93 kJ C. 43 kJ OD. 33 kJ
Answer:
C. 43 kJ
Explanation:
Bond energy (bond enthalpy (H) or bond strength) is the amount of energy required to break a bond. The bond energy is used to determine the strength of a chemical bond.
The bond energy is the difference between the energy of the reactants and the energy of the products. The bond energy is given by:
[tex]\Delta H=\Sigma Bond\ energy\ reactants-\Sigma Bond\ energy\ products\\\\Where \ \Delta H=bond\ energy\ or\ energy\ released\\\\Given\ that\ \Delta H=25\ kJ,\Sigma Bond\ energy\ reactants=68\ kJ, Hence:\\\\\Delta H=\Sigma Bond\ energy\ reactants-\Sigma Bond\ energy\ products\\\\Substituting:\\\\25\ kJ=68\ kJ- \Sigma Bond\ energy\ products\\\\ \Sigma Bond\ energy\ products=68\ kJ-25\ kJ\\\\ \Sigma Bond\ energy\ products=43\ kJ\\[/tex]
Answer: is simply C.
. A block of wood has a mass of 150 grams and a volume of 550 cm3. What is its density?
Answer:
mass= 150 g
volume= 550 cm3
density= mass/ volume
= 150/550
= 0.27 g/cm3
How many liters of C4H10 are present in 0.25 moles of C4H10 at STP?
Answer:
V = 5.6 L
Explanation:
Given data:
Number of moles of C₄H₁₀ = 0.25 mol
Temperature = standard = 273.15 K
Pressure = standard = 1 atm
Volume of C₄H₁₀ = ?
Solution:
Formula:
PV = nRT
R = general gas constant = 0.0821 atm.L /mol.K
1 atm × V = 0.25 mol × 0.0821 atm.L /mol.K × 273.15 K
V = 5.6 atm.L/ 1 atm
V = 5.6 L
Helppppp
Question 19
The active ingredient in many spices has the empirical formula CsH.O. It's molecular formula could be
Link to Periodic Table of the Elements
o Only C10H1202
Neither C5H.0 nor C10H 1202
Only CsHO
Either C5H.0 or C10H1202
Answer: Either [tex]C_5H_6O[/tex] or [tex]C_{10}H_{12}O_2[/tex]
Explanation:
Molecular formula is the chemical formula which depicts the actual number of atoms of each element present in the compound.
Empirical formula is the simplest chemical formula which depicts the whole number of atoms of each element present in the compound.
The empirical formula is [tex]C_5H_6O[/tex]
Now we have to calculate the molecular formula:
[tex]n=\frac{\text{Molecular weight }}{\text{Equivalent weight}}[/tex]
n is a whole number
The molecular formula could be=[tex]1\times C_5H_6O=C_5H_6O[/tex]
Thus molecular formula could be = [tex]2\times C_5H_6O=C_{10}H_{12}O_2[/tex]
How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
__NaOH + __CuSO4 à __Na2SO4 + __Cu(OH)2
Answer:
5.0 × 10²⁴ molecules
Explanation:
Step 1: Write the balanced double displacement reaction
2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂
Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄
We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.
5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol
Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄
The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.
Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄
We will use Avogadro's number.
8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule
reen plants absorb sunlight to power photosynthesis, the chemical synthesis of food from water and carbon dioxide. The compound responsible for light absorption and the color of plants, chlorophyll, strongly absorbs light with a wavelength of 453.nm. Calculate the frequency of this light. Round your answer to 3 significant digits.
Answer:
The frequency of the light is 6.62 * 10¹⁴ Hz
Explanation:
The frequency of a wave is defined as the number of complete oscillations made by the wave per second. Its unit is Hertz. The frequency of light as well as the velocity of the light and wavelength of the light are all related.
The velocity of light is the distance the light wave travels per second.
Wavelength is defined as the distance between successive crests and troughs of the wave. It is inversely related to the frequency of the wave.
The velocity of light, c is related to frequency, f, and wavelength, λ, by the formula, c = λf
where the velocity of light, c is a constant = 3 * 10⁸ m/s
λ is wavelength of light = 453 nm = 4.53 * 10⁻⁷ m
Frequency, f = ?
Making f subject of formula in the equation above, f = c/λ
f = 3 * 10⁸ m/s / 4.53 * 10⁻⁷ m
f = 6.62 * 10¹⁴ Hz
Therefore, the frequency of the light is 6.62 * 10¹⁴ Hz
A 20.0 ml sample of glycerol has a mass of 25.2 grams. What is the mass of 63 ml sample of glycerol?
The mass of 63 ml sample : 79.38 g
Further explanationGiven
20 ml and 25.2 g of glycerol
Required
The mass of 63 ml sample
Solution
Density is the ratio of mass per unit volume
Density formula:
[tex]\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}[/tex]
Density of glycerol :
= m : V
= 25.2 g : 20 ml
= 1.26 g/ml
Mass of 63 ml sample :
= density x volume
= 1.26 g/ml x 63 ml
= 79.38 g
URGENT!!!!!! Please help I will give brainliest
What is the mole fraction of ions in solution if the vapor pressure of an aqueous solution of NaCl is 2.02 kPa
Answer:
.133
Explanation:
Dissolution of solute lowers the vapor pressure of solvent .
Relative lowering by non -volatile solute is equal to mole fraction of solute dissolved .
Vapor pressure of pure water is 2.33 k Pa
Lowering of vapor pressure = 2.33 - 2.02 = .31 k Pa .
relative lowering = .31 / 2.33 = .133
relative lowering will be equal to mole fraction of non volatile solute like NaCl
so mole fraction of NaCl dissolved = .133
A student sets up the following equation...
Answer:
The answer to your question is given below
Explanation:
From the question given above, the following data were obtained:
Concentration (g/mL) = 0.04 g/mL
Concentration (g/L) =?
We can convert g/mL to g/L by doing the following:
1 g/mL = 1000 g/L
Therefore,
0.04 g/mL = 0.04 g/mL × 1000 g/L / 1 g/mL
0.04 g/mL = 40 g/L
0.04 g/mL is equivalent to 40 g/L.
Thus, the concentration (g/L) is 40 g/L
A reaction of 100mL of 1.35 M HCl and 100mL of 1.76 M NaOH is monitored and the following
temperatures were recorded: starting temperature = 24.6 C; and final temperature = 38.8 C.
Calculate the AH of this reaction.
A) -92142
J/Mole
B) -12439.2
J/Mole
C) 876
J/Mole
Answer: [tex]\Delta H[/tex] for the reaction is 87935 J
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
[tex]Molarity=\frac{moles}{\text {Volume in L}}[/tex]
[tex]moles of HCl[/tex]=[tex]Molarity\times {\text {Volume in L}}=1.35\times 0.01=0.135moles[/tex]
[tex]moles of NaOH[/tex]= [tex]Molarity\times {\text {Volume in L}}=1.76\times 0.01=0.176moles[/tex]
As 1 mole of HCl neutralizes 1 mole of NaOH
0.135 moles of HCl will neutralize = 0.135 mole of NaOH
Thus HCl is the limiting reagent.
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
Q = Heat absorbed by water = ?
m = mass of water = 200 g (volume of water=200ml, density of wtaer = 1 g/ml)
c = specific heat capacity = [tex]4.18 J/g^0C[/tex]
Initial temperature of water = = 24.6°C
Final temperature of water= = 38.8 °C
[tex]Q=200\times 4.18\times (38.8-24.6)[/tex]
[tex]Q=11871.2J[/tex]
Thus heat released by 0.135 moles is = -11871.2 J
heat released by 1 mole is =[tex]\frac{-11871.2 J}{0.135}\times 1=-87935J[/tex]
The heat of reaction, ΔH is 87935 J
Molarity and Heat of Reaction ΔHMolarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.The heat of reaction ΔH, is the amount of heat evolved or absorbed when a chemical reaction occurs between molar quantities of the reactants as represented in the equation of reaction.Equation of reaction between HCl and NaOH is given below:
HCl + NaOH ----> NaCl + H₂OMolarity = number of mole/volume
Number of moles = molarity * volume
Number of moles of HCl = 1.35 M * 0.1 L = 0.135 moles
Moles of NaOH = 1.76 M * 0.1 L = 0.176 moles
1 mole of HCl neutralizes 1 mole of NaOH
Therefore, 0.135 moles of HCl will neutralize 0.135 mole of NaOHTherefore, NaOH is in excess and HCl is the limiting reagent.Calculating the quantity of heat evolved:
Q = mcΔTwhere m is mass, c is specific heat capacity, ΔT is temperature change
Quantity of heat evolved by reaction = Heat absorbed by waterHeat absorbed by water, Q = mcΔT
mass of water = density * volume
density of water = 1 g/mL
volume of water = 200 mL
mass of water = 1 g/mL * 200 mL
mass of water = 200 g
specific heat capacity of water, c = 4.18 J/g°C
ΔT = final temperature of water - initial temperature of waterInitial temperature of water = = 24.6°C
Final temperature of water= = 38.8 °C
ΔT = 38.8 - 24.6 = 13.7°C
Q = 200 g * 4.18 J/g°C * 14.2°c
Q = 11871.2 J
Therefore, heat released by 0.135 moles is = -11871.2 J
Heat released by 1 mole = 11871.2 * 1/0.135
Heat released by 1 mole = 87935 J
Therefore, the heat of reaction, ΔH is 87935 J
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What process caused the accumulation of sand that produce the sand dunes?
A. deposition
B. physical weathering
C.
chemical weathering
D.
erosion
Answer:
Anwser A
Explanation:
Sand dunes are created by wind deposition.
The accumulation of sand that produce the sand dunes is called wind deposition. Therefore, option (A) is correct.
What is the process form sand dunes?Sand dunes are formed when wind deposits the sand on top of each other. It stays until a small mound starts to form. As the first mound forms, sand builds up on the windward side more and more until the edge of the dune breaks due to its own weight.
When the angle of the dune becomes too big to support the weight, the collapse of sand dune begins. This is called the angle of repose usually around 30°-34° also depends upon wind speed, grain size, and roundedness of the individual grains.
As these dunes collapse, the sand starts to move in the same direction as the wind. The sand piles up on multiple sides of the dune by changing wind direction and is unable to get the angle of repose such dune never collapses.
Therefore, the sand dunes produce the accumulation of sand through a process called wind deposition.
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Someone help will give brainiest if best and reasonable answer
5.
Solid Phase (Ice)
Unlike most other substances, water's solid form (ice) is less dense than its liquid form, as a result of the nature of its hexagonal packing within its crystalline structure. ... However, a block of ice floats in liquid water because ice is less dense than liquid water.
Unlike most other substances, water's solid form (ice) is less dense than its liquid form, as a result of the nature of its hexagonal packing within its crystalline structure. This lattice contains more space than when the molecules are in the liquid state. ... Liquid water is most dense at 4 degrees Celsius.
6.Evaporation is a phase transition from the liquid phase to the gas phase that occurs at temperatures below the boiling point at a given pressure.
An element crystallizes in a face-centered cubic lattice. If the length of an edge of the unit cell is 0.408 nm, and the density of the element is 19.3 g/cm3 , what is the identity of the element?
Answer:
Au
Explanation:
For the density of a face-centered cubic:
[tex]Density = \dfrac{4 \times M_w}{N_A \times a^3}[/tex]
where
[tex]M_w[/tex] = molar mass of the compound
[tex]N_A=[/tex] avogadro's constant
[tex]a^3 =[/tex] the volume of a unit cell
Given that:
Density [tex](\rho)[/tex] = 19.30 g/cm³
a = 0.408 nm
a = [tex]0.408 \times 10^{-9} \times 10^{2} \ cm[/tex]
a = [tex]4.08 \times 10^ {-8} \ cm[/tex]
∴
[tex]19.3 = \dfrac{4 \times M_w}{(6.023 \tmes 10^{23})\times (4.08 \times 10^{-8})^3}[/tex]
[tex]M_w= \dfrac{19.3\times (6.023 \times 10^{23})\times (4.08 \times 10^{-8})^3}{4}[/tex]
[tex]M_w=197.37 \ g/mol[/tex]
Thus, the molar mass of 197.37 g/mol element is Gold (Au).
a beaker of benzene is at room temperature. what is its vapor pressure. Is this vapor pressure large enough to cause the benzene to boil at sea level answers
Answer:
(1). The vapor pressure is 91 mmHg at 20°C.
(2). No, benzene will not boil at sea level.
Explanation:
Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics.
The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids.
Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure.
The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids).
71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil.
A benzene is chemical that is color less or light to the eyes and is liquid at the rom temperature. It has a sweaty odor and is highly flammable.
Benzene, that is C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mole and a Melting point of 5.5 °C. The atmospheric pressure is at the 760mmHg, while the vapor pressure at the sea level is at the temperature of about 15°C which is equal to 71 mmHg. 71 mmHg is not the equal to 760 mmHg, thus, at sea level Benzene will not boil.Thus the vapor pressure is 91 mmHg at 20°C, and No, benzene will not boil at the sea level.
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write a skeletal equation for the following reaction: An aqueous solution of barium nitrate and an aqueous solution of sodium sulfate are mixed together. Then balance the completed chemical equation.
Answer:
Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2 NaNO₃(aq)
Explanation:
Let's consider the unbalanced double displacement equation for the reaction of an aqueous solution of barium nitrate and an aqueous solution of sodium sulfate.
Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + NaNO₃(aq)
To get the balanced equation, we will multiply NaNO₃(aq) by 2.
Ba(NO₃)₂(aq) + Na₂SO₄(aq) ⇒ BaSO₄(s) + 2 NaNO₃(aq)
Calculate the volume of 7.28 g of a metal that has a density of 6.28 g/cm
Answer:
1.16 cubic centimeters
Explanation:
Al2(CO3)3
5. How many atoms of oxygen are in the compound above?
6. How many total atoms in this compound?
3Fe(OH)2
, Fe
7. How many atoms? H
Total atoms?
Answer:
7. 6 atoms po
Explanation:
sana makatulong po
Water only gets evaporated from the ocean. True or false?
Answer:
×
Explanation:
FALSE BECAUSE NOT OCEAN IT IS ALL
What is the wavelength of a 2.99 s -1 wave? (provide work plz)
Answer:
Explanation:
λ = [tex]10^8[/tex] meters
Explanation:
f : frequency
c : velocity of light
λ : wavelength
f = c/λ
λ = c /f
c = 2.99 ⋅ [tex]10^8[/tex] m/ s
λ = [tex]\frac{2.99 * 10^8}{2.99 s^-^1}[/tex]λ = [tex]10^8[/tex] meters
Is strontium phosphide a ionic or covalent bond
Answer:
Strontium is a soluble earth metal with the nuclear number 38. Phosphate is a polyatomic particle containing phosphorus and oxygen molecules. Strontium loses electrons to turn out to be emphatically charged, and phosphate is an adversely charged particle.
Explanation:
When strontium phosphide comes into contact with water, it transforms into a solid that emits poisonous and combustible fumes. It is a highly reactive substance utilized in the production of chemically reactive devices as well as a laboratory reagent. Strontium phosphide is ionic.
Two elements combine to form an ionic compound. Sr is the metal while P is the non-metal in the ionic combination. After transferring its two valence electrons to P to create the phosphide ion, which has a net negative charge of -3, strontium becomes a cation.
Ions are charged particles that form when an atom (or group of atoms) receives or loses an electron, and ionic compounds are composed of these charged particles.
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Pentane (CH3CH2CH2CH2CH3) and neopentane (C(CH3)4 both have the C5H12 formula. Which compound has stronger induced dipole, induced dipole forces
Answer:
n-Pentane
Explanation:
All molecules possess dispersion forces. It is possible in non-polar molecules that a temporary distortion in the electron distribution of one molecule can affect the electron distribution in a neighboring molecule. This is known as induced dipole, induced dipole forces.
However, this induced dipole, induced dipole forces depends on the shape of the molecule. Molecules of n-pentane are capable of better interaction via induced dipole, induced dipole forces since the molecules interact over the entire length of the molecule rather than neopentane which is more compact and nearly spherical.
Once the activity of americium in a smoke detector falls below 5 percent of its original activity, it's no longer able to effectively detect smoke and trigger the alarm. If the half-life of americium-241 is approximately 432.2 years, how many years will it take before the americium-241 is unable to detect smoke?
Question 11 options:
A)
10 years
B)
20 years
C)
1,868 years
D)
2 years
Answer:
C 1,868 years
Explanation:
I just took the test - I tried doing the math and was close but couldn't get it exact; so I guessed and I was correct :)
Answer:
1,868 years
Explanation:
PLZZZ HELP
The cooling of water vapor enough to return to a liquid state
A Evaporation
B Condensation
C Precipitation
D Transpiration
I have 4 oribitals and 6 valence electrons
Which element am i?
answer choices
a. Lead (Pb) I’m a metal
b. Selenium (Se) i’m metal
c. Lead (Pb) I’m a nonmetal
d. selenium (Se) I’m a non metal
Answer:
d. selenium (Se) I’m a non metal
Explanation:
What we know about the element in view is that it has:
4 orbitals
6 valence electrons
The orbitals are the energy levels in the element.
Valence electrons are the outermost shell electrons.
The orbitals tells us the periods in which an element belongs. Since we have 4 orbitals, this suggests that our element belongs to the 4th period.
The number of valence electrons tells us the group in which the element could be found. Since we have 6 valence electrons, the group number is 6.
Therefore, the element is period 4 and group 6 is selenium. Selenium is a non-metal.
If 25 g of AlBr3 was produced whenCsBr was added to the reaction vessel, what quantity (grams) of CsBr was added?
The question is incomplete, the complete question is;
3CsBr + Al(OH)3 → AlBr3 + 3CsOH
If 25 g of AlBr3 was produced when 125 mL of a CsBr solution was added, what was the molarity of the CsBr solution?
Answer:
2.25 M
Explanation:
Number of moles of AlBr3 produced = 25g/266.69 g/mol = 0.0937 moles of AlBr3 .
Now, from the reaction equation;
3 moles of CsBr yields 1 mole of AlBr3
Therefore, x moles of CsBr will yield 0.0937 moles of AlBr3
x = 3 * 0.0937 = 0.2811 moles
If 125 mL of a CsBr solution was added
And;
n =CV
where;
n = number of moles
C = concentration of solution
V = volume of solution
C = n/V
C = 0.2811 moles * 1000/125
C= 2.25 M
Enter the electron configuration for the ion most likely formed by phosphorus. Express your answer in the order of orbital filling as a string without blank space between orbitals. For example, the electron configuration of Li could be entered as 1s^22s^1 or [He]2s^1.
Answer:
1s2 2s2 2p6 3s2 3p6
Explanation:
Phosphorus is a non metal. It gains electrons to form ions. The most likely ion formed is the phosphide, where it gains three extra electrons.
Total number of electrons in Phosphide = 15 + 3 =18
The electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6
Electronic Configuration can be defined as the electron distribution of an atom or molecule in an atomic or molecular orbit. The atomic orbit consists of the s, p and d orbitals.
The Atomic number of Phosphorus is 15.
Thus, the Electronic configuration of Phosphorus is 1s² 2s² 2p6 3s² 3p³.
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What is the pH of a 75.0 mL solution that is 0.045 M in weak base and 0.053 M in the conjugate weak acid
Answer:
7.07
Explanation:
HA = weak acid = 0.053
A+ = conjugate base = 0.045
Ka = 7.2x10^-8
Ka = [H+][A-]/HA
7 2x10^-8 = [H+][0.045]/0.053
[H+] = 7.2x10^-8 x 0.053/0.045
= 8.48x10^-8
PH = -log[H+]
= -log[8.48x10^-8]
PH = -[login.48 + log10^-8]
PH = -0.928 - (-8)log10
= 7.07
a solution is 5.00% potassium chloride by mass. how much potassium chloride would you expect to collect by evaporating 150.0 g of the solution
Answer:
When 150.0g of the solution are evaporated, 7.50g of KCl must be collected
Explanation:
A solution 5% of potassium chloride means that there are 5g of KCl per 100g of solution.
When all the solution is evaporated, the solute KCl will be collected as a solid.
In 150g of solution there are:
150g * (5.00gKCl / 100g solution) = 7.50g of KCl are present in 150g of solution.
That means:
When 150.0g of the solution are evaporated, 7.50g of KCl must be collected