Given:
A solution of 60% fertilizer is to be mixed with a solution of 21% fertilizer to form 234 liters of a 43% solution.
To find:
The quantity of the 60% solution in the mixture.
Solution:
Let x be the quantity of the 60% solution and y be the quantity of the 21% solution.
Quantity of mixture is 234. So,
[tex]x+y=234[/tex]
[tex]x=234-y[/tex] ...(i)
The mixture has 43% fertilizer. So,
[tex]\dfrac{60}{100}x+\dfrac{21}{100}y=\dfrac{43}{100}\times 234[/tex]
Multiply both sides by 100.
[tex]60x+21y=10062[/tex] ...(ii)
Using (i) and (ii), we get
[tex]60(234-y)+21y=10062[/tex]
[tex]14040-60y+21y=10062[/tex]
[tex]-39y=10062-14040[/tex]
[tex]-39y=-3978[/tex]
Divide both sides by -39.
[tex]\dfrac{-39y}{-39}=\dfrac{-3978}{-39}[/tex]
[tex]y=102[/tex]
Putting this value in (i), we get
[tex]x=234-102[/tex]
[tex]x=132[/tex]
Therefore, 132 liters of the 60% solution must be used.
What is the total holiday debt (no less than $500) that you are trying to pay off and what did you purchase
to accrue (accumulate) that debt?
What is the change in elevation for
(3)(4)(-3.5)
Hey there!
(3)(4)(-3.5)
= 12(-3.5)
= -42
Therefore, your answer SHOULD be: -42
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Ezra has $10 to spend on a taxi ride. The taxi company charges a flat rate of $4, plus $1.50 per mile. What is the maximum amount of miles Ezra can afford to travel in this taxi?
PLS ANSWER ASAP I WILL GIVE BRAINLIEST AND WILL GIVE 22 POINTS!!!!
88, 89, 86, 90, 83, 81, 89
What is the median number
A 88
B. 89
C 90
D. 86
Please answer this I really need help
Answer:
The answer is 90.
Step-by-step explanation:
90 is in the middle
Answer:
d
Step-by-step explanation:
cause i said so
What is the mass of an object that has 50 newtons of force and is accelerating at the rate of 2 m/s/s
HELP PLEASE!! Do not explain need full answer
Answer:
F= ma
m = F/a
m = 50/2
m = 25
Answer equal 25
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using this equation, find the maximum height reached by the rocket, to the nearest tenth of a foot.
y=−16x^2+160x+150
Answer:
Answer below
Step-by-step explanation:
Time can not be negative from any perspective. Hence, the correct answer is 10.16 seconds.
The equation of the path of a rocket is given that is y= x^2 + 153x + 98
We need to determine the time that the rocket will hit the ground.
Now, if the rocket hits the ground after the launching then the overall displacement at the time of hitting the ground will be zero.
Therefore, the value of y is 0.
Thus, -16x^2 +153x + 98 = 0
Now, the formula for finding the roots of the quadratic equation
ax^2 +bx +c = 0 is given as:
[tex]x^{1} =\frac{-b+\sqrt{b^2 -4ac} }{2a}[/tex]
[tex]x^2 = \frac{-b -\sqrt{b^2 -4ac} }{2a}[/tex]
Comparing the expression with the standard form of the equation.
a = -16b = 153 and c = 98
By applying the formula there are two values are come that is,
x^1 = -0.602555
x^2 = 10.1651
Time can not be negative from any perspective.
Hence, the correct answer is 10.16 seconds.
———————————————————————————————————————-
(Hope this helps can I pls have brainlist (crown)☺️)
What is the least common denominator of this equation
Answer:
LCD = 30
Step-by-step explanation:
[tex]\frac{5}{6}[/tex] x - [tex]\frac{1}{10}[/tex] x = [tex]\frac{2}{15}[/tex]
Multiply through by 30 ( the LCM of 6, 10, 15 ) to clear the fractions
25x - 3x = 4
22x = 4 ( divide both sides by 22 )
x = [tex]\frac{4}{22}[/tex] = [tex]\frac{2}{11}[/tex]
Answer:
5
Step-by-step explanation:
[tex] \frac{5}{6} x - \frac{1}{10} x = \frac{2}{15} \\ \frac{50x - 6x}{60} = \frac{2}{15} (criss \: cross) \\ \frac{44x}{60} = \frac{2}{15 } \\ \frac{11x}{15} = \frac{2}{15} (simplify) \\ 165x = 30(criss \: cross) \\ x = \frac{30}{165} = \frac{6}{33} = \frac{2}{11} \\ x = \frac{2}{11} [/tex]
A-B equals, if A =5x^2-4x-11 and B=-x^2+3x-5
Answer:
A-B = 6x^2-7x-6
Step-by-step explanation:
A = 5x^2-4x-11
B = x^2+3x-5
A-B = (5x^2-4x-11) - (-x^2+3x-5) = 5x^2-4x-11+x^2-3x+5 = 6x^2-7x-6
Someone help?
Find the problem:
-5x - 16 = 8x - 1
Fix the problem:
?
[tex]-5x -16 = 8x -1\\\\\implies 8x +5x = -16 +1 \\\\\implies 13x = -15\\\\\implies x = -\dfrac{15}{13}[/tex]
I was absentee and i dont know how to solve it help plz
Answer:
-1/3 or 1/-3 (it doesn't matter which one you pick because its still the same)
Step-by-step explanation:
You find slope by doing rise over run. Its left to right so you start on the left dot and go down one. This makes it -1 because you're going down, not up. You move 3 to the right which makes it positive. Once you do this itll lead you right the the 2nd point. 1 down= -1
3 right= 3
-1/3
A CD is on sale for $100.00. The sales tax rate is 6%. How much will the total cost be for the CD
Answer: $106.00
Step-by-step explanation:
Which graph corresponds with the inequality x< 10 ?
Answer:
C
Step-by-step explanation:
Work out the area of the shaded shape.
Answer:
61 m²
Step-by-step explanation:
Find the area of the whole rectangle and subtract the part that is cut off
Area = [tex]11 *8 - 9 *(8-5)[/tex]
= [tex]88 - 9*3[/tex]
= [tex]88 - 27[/tex]
= [tex]61[/tex]
Units = m * m or m²
61 m²
-Chetan K
A shed has dimensions of 12m in length and 5 m in width. Both the length and width are increased by the same amount in order to increase the floor area by more than double the original area?
The amount by which the length and width of a shed can be increased to
more than double the area, depends on the initial dimensions.
The amount that can be added to both the length and the width to increase the floor area by more than double the original area is more than 3 meters.Reasons:
The given parameters of the shed are;
The length of the shed = 12 m
Width of the shed = 5 m
The amount by which the length and the width are increased = The same amount
The new area after the increase in the length and width of the shed = More than double the initial area
Required:
The amount of increase in the length.
Solution:
Let the amount by which the length and width are increased = x
We have;
Initial area of the shed = 12 m × 5 m = 60 m²
The new area = (12 + x) × (5 + x) > 2 × 60
By multiplication, we get;
(12 + x) × (5 + x) = x² + 17·x + 60 > 2 × 60 = 120
x² + 17·x + 60 - 120 > 120 - 120 = 0
x² + 17·x - 60 > 0
By factorization, we get;
(x + 20)·(x - 3) > 0
x > -20, or x > 3
The increase (positive) amount of the solution is x > 3
Therefore, the amount by which both the length and the width can be increased to more than double the area is x > 3 meters
Learn more about the area of a rectangle here:
https://brainly.com/question/16410706
HELP PLSSS
Use the commutative
property to make an
equivalent
expression.
4+m=?
A. 4-m
B. m+4
Answer:
B. m+4
Step-by-step explanation:
You are just writing the same equation but backwards so that the numbers still stay the same as well as the answer.
Answer: A
Step-by-step explanation:
Helppppppppppppp helppppppppppppp
Answer: 2
Step-by-step explanation:
Which equation below represents an equation in standard form?
Answer:
C
Step-by-step explanation:
standard form is ax + by = c, which is true for the third option.
5(x-a)=3(x+b)
Solve for x
Answer:
[tex]x=\frac{3b}{2} +\frac{5a}{2}[/tex]
Step-by-step explanation:
Answer:
Step-by-step explanation:
5(x - a) = 3(x + b)
5x - 5a = 3x + 3b
2x = 5a + 3b
x = 2.5a + 1.5b
If x is increasing at a
rate of 2 units per second,
find the rate of change of theta
at the instant when x= 12 units.
Answer:
[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex] at [tex]x=12[/tex]
Step-by-step explanation:
[tex]\frac{dx}{dt}=2[/tex]
[tex]\frac{d\theta}{dt}=?[/tex]
[tex]x=12[/tex]
[tex]cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]
[tex]cos(\theta)=\frac{x}{13}[/tex]
[tex]\frac{d}{dt}cos(\theta)=\frac{d}{dt}\frac{x}{13}[/tex]
[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}\frac{dx}{dt}[/tex]
[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{1}{13}(2)[/tex]
[tex]-sin(\theta)\frac{d\theta}{dt}=\frac{2}{13}[/tex]
[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]
[tex]cos(\theta)=\frac{x}{13}[/tex]
[tex]cos(\theta)=\frac{12}{13}[/tex]
[tex]\theta=cos^{-1}(\frac{12}{13})[/tex]
[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(\theta)}[/tex]
[tex]\frac{d\theta}{dt}=\frac{2}{-13sin(cos^{-1}(\frac{12}{13}))}[/tex]
[tex]\frac{d\theta}{dt}=\frac{2}{-13(\frac{5}{13})}[/tex]
[tex]\frac{d\theta}{dt}=\frac{2}{-5}[/tex]
[tex]\frac{d\theta}{dt}=-\frac{2}{5}[/tex]
The value of θ is given by the inverse sine function, from which the rate of
change of θ with respect to x can be derived.
The rate of change of θ at the instant when x = 12 units is -0.4 rad/sReasons:
[tex]\displaystyle \frac{dx}{dt} = \mathbf{2 \ units \ per \ second}[/tex]
[tex]\displaystyle cos(\theta) = \frac{x}{13}[/tex]
[tex]\displaystyle \theta = arccos \left(\frac{x}{13}\right)[/tex]
[tex]\displaystyle \frac{d}{dx} \theta = \frac{d\left(arccos \left(\frac{x}{13}\right)\right)}{dx} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}}[/tex]
Using chain rule of differentiation, we have;
[tex]\displaystyle \frac{d\theta}{dt} = \mathbf{ \frac{d\theta}{dx} \times \frac{dx}{dt}}[/tex]
Therefore;
[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-x^2} }{x^2-169}\times \frac{dx}{dt} = \mathbf{\frac{\sqrt{169-x^2} }{x^2-169}\times 2}[/tex]
When x = 12, we get;
[tex]\displaystyle \frac{d\theta}{dt} =\frac{\sqrt{169-12^2} }{12^2-169}\times 2 = -\frac{2}{5} = -0.4[/tex]
The rate of change of the angle, θ, with time at the instant when x = 12 is -0.4 rad/s
Learn more about rate of change here:
https://brainly.com/question/24686935
Three segments are chosen at random from six segments having lengths of 2, 3, 5, 6, 7 and 10 units. What is the probability that the three segments chosen could form a triangle? Express your answer as a common fraction
Using the probability concept, it is found that there is a [tex]\frac{7}{20}[/tex] probability that the three segments chosen could form a triangle.
A probability is the number of desired outcomes divided by the number of total outcomes.
In this problem, the order in which the sides of the segments are chosen is not important, hence, the combination formula is used to find the number of total outcomes.Combination formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
Total outcomes:
3 segments from a set of 6 lengths, hence:
[tex]C_{6,3} = \frac{6!}{3!3!} = 20[/tex]
Desired outcomes:
Segments can make a triangle if the sum of the lengths of the smaller segments is greater than the length of the larger segment.Hence, the possible options are: (2,5,6), (3,5,6), (3,5,7), (5,6,7), (5,6,10), (5,7,10), (6,7,10).There are 7 desired outcome, hence [tex]D = 7[/tex]Then:
[tex]p = \frac{D}{T} = \frac{7}{20}[/tex]
[tex]\frac{7}{20}[/tex] probability that the three segments chosen could form a triangle.
To learn more about the probability concept, you can take a look at https://brainly.com/question/24437717
Big Sam, an engineer of the Oval Express says: "We blew off a cylinder head an hour after leaving the station and had to continue the trip at three-fifths of the former speed, which brought us in two hours late. If the accident had occurred fifty miles father on, the train would have arrived forty minutes sooner". Based on Sam's description, how long was the run between the two train stations?
A. 150 miles
B. 200 miles
C. 250 miles
D. 300 miles
Answer:
Ig 200 miles
Step-by-step explanation:
I am guessing
hi so my teacher gave me this and i am not sure if i did it right, this is what i put for the first Question
degree = 3
leading coefficient = 1
and the it is the arrows are going up/down so its a odd degree
and i put that the answer is d i did the rest like this please tell me where i went wrong/if i did
Answer:
First, let's look at some polynomials of even degree (specifically, quadratics in the first row of pictures, and quartics in the second row) with positive and negative leading coefficients:❤
James is observing the population of the fish he put into a pond. He built a pond and
populated it with 700 fish. The population of the fish doubles every year.
The exponential equation is given by y = 700(2)ˣ
An exponential function is given by:
y = abˣ
where y, x are variables, a is the initial value of y and b is the multiplier.
Let y represent the population of fish after x hours.
Given that he starts with 700 fishes, hence
a = 700
The population of the fish doubles every year, hence:
b = 2
The exponential equation becomes:
y = 700(2)ˣ
Find out more at: https://brainly.com/question/12490064
Pls help me I’ll brainlest ASAP
22
23
The Krishna family of 5 spent $12 per person at the golf
range plus an additional $40 for equipment. How much
did they spend?
24
i
Answer:
$100
Step-by-step explanation:
12x5=60
+40= $100
Answer:
$100
Step-by-step explanation:
This is easy
12x5=60
+40=$100
the permiter of one face of cube is 60 cm then its volume :
Step-by-step explanation:
a cube has 6faces.
side = 60/6 = 10cm
volume = 1000cm³.
hope this helps you.
Which item produces the magnetic field in the electromagnet?
A-paperclips
B- a switch
C-paint brushes
D- a magnet
Answer:
Its ethier a switch or magnet
2 times the difference of 5 and 3
Answer:
4
Step-by-step explanation:
Equation:-
2(5-3)
=> 2(2)
=> 4
Help me with this question thanks so much
[tex]\frac{\sqrt{2x} }{\sqrt{} x-1}[/tex]
For which values of x does each expression make sense?
Answer:
The expression is unclear so:
If the denominator is [tex]\sqrt{x}-1[/tex] then your set of existence is given by
[tex]\left \{ {{x\ge0} \atop {x\ne1}} \right.[/tex]
since you want the quantity inside both square roots to be positive (and it happens for both to be simply [tex]x\ge0[/tex] and you don't want a zero at the denominator so you have to rule out 1.
If the square root includes the whole denominator [tex]\sqrt{x-1}[/tex] the condition becomes [tex]\left \{ {{x\ge0} \atop {x>1}} \right.[/tex]
where you don't include the extreme in the second condition since, again, you don't want to divide by 0. The answer in this case is simply [tex]x>1[/tex] since values between 0 and 1 will give a negative root which is not a real number.
