Answer:
the minimum records to be retrieved by using Chebysher - one sided inequality is 17.
Step-by-step explanation:
Let assume that n should represent the number of the students
SO, [tex]\bar x[/tex] can now be the sample mean of number of students in GPA's
To obtain n such that [tex]P( \bar x \leq 2.3 ) \leq .04[/tex]
⇒ [tex]P( \bar x \geq 2.3 ) \geq .96[/tex]
However ;
[tex]E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D[/tex]
[tex]E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D[/tex]
Similarly;
[tex]D\int\limits^4_2(2+ e^{-x}) dx = 1[/tex]
⇒ [tex]D*(2x-e^{-x} ) |^4_2 = 1[/tex]
⇒ [tex]D*4.117 = 1[/tex]
⇒ [tex]D= \dfrac{1}{4.117}[/tex]
[tex]\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103[/tex]
∴ [tex]Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711[/tex]
Now; [tex]P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)[/tex]
Using Chebysher one sided inequality ; we have:
[tex]P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}[/tex]
So; [tex](\omega = \bar x - \mu)[/tex]
⇒ [tex]E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}[/tex]
∴ [tex]P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}[/tex]
To determine n; such that ;
[tex]\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}[/tex]
⇒ [tex]n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}[/tex]
[tex]n \geq 16.83125[/tex]
Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.
Given the coordinates (0,0) and (4, 1), the distance is:
Answer:
[tex]\sqrt{17}[/tex] or ≈4.12
Step-by-step explanation:
Use the distance formula
d= √(x₂ - x₁) ² + (y₂-y₁) ²
d= √(4-0)² + (1-0)²
d= √16 + 1
d= √17
Suppose I claim that the average monthly income of all students at college is at least $2000. Express H0 and H1 using mathematical notation, and clearly identify the claim and type of testing.
Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): [tex]\mu \geq 2000[/tex]
Alternative hypothesis (H1): [tex]\mu <2000[/tex]
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): [tex]\mu \geq 2000[/tex]
Alternative hypothesis (H1): [tex]\mu <2000[/tex]
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
In a preschool, there are 5 students per teacher. There are 10 teachers in the school. How many students are in the school?
2
5
15
50
Answer: 50 student in the school
Step-by-step explanation: 5x10=50 so that’s the answer.
When the health department tested private wells in a county for two impurities commonly found in drinking water, it found that 10% of the wells had neither impurity, 90% had impurity A, and 20% had impurity B. (Obviously, some had both impurities.) If a well is randomly chosen from those in the county, find the probability distribution for Y, the number of impurities found in the well.
Answer:
P(Y= 0) = 0.1
P(Y= 0) = 0.7
P(Y= 0) = 0.2
Step-by-step explanation:
Let Y be number of impurities that can be found in the well,
Let A denote the event that impurity A is randomly found in the well
Here Y can have three values i.e 0 , 1 and 2
✓It will take take the value of 0 when there is no impurity found in the well
✓It will take the value of 1 when when exactly one impurity vis found in the well
✓It will take the value of 2 when when both impurities vis found in the well
CHECK THE ATTACHMENT FOR DETAILED EXPLATION
Amit found and labeled the areas of each of the faces of the triangle prism as shown which area calculation did Amit calculate incorrectly
Complete Question:
Amit found and labeled the areas of each of the faces of the triangular prism as shown.
Which area calculation did Amit calculate incorrectly?
Rectangular face with area 30 cm2
Rectangular face with area 40 cm2
Rectangular face with area 50 cm2
Triangular faces with areas 48 cm2
Answer:
Triangular faces with areas 48 cm2
Step-by-step Explanation:
To find out which area calculation Amit got wrong, let's calculate each faces of the given triangular prism attached below:
There area of theb5 faces should be as follows:
Area of rectangular face with L = 10 and B = 5 would be ==> 10*5= 50cm²
Area of rectangular face with L = 8 and B = 5 would be 8*5 = 40cm²
Area of rectangular face with L = 6 and B = 5 would 6*5 = 30cm²
Area of each of the triangular faces will be ½*8*6 = 48/2 = 24cm²
From our calculations, we'd observe that Amit didn't calculate the area of the triangular faces correctly. Amit got 48cm² instead of 24cm²
Answer:
Triangular faces with areas 48 cm2
Step-by-step explanation:
Given that y = 1.5 at x = -2. Find the function y = f(x) such that
dy/dx=√(4y+3)/x²
Answer:
[tex]y=\frac{(-\frac{4}{x}+1)^2-3 }{4}[/tex]
Step-by-step explanation:
We are given the following information. y have the point [tex](-2,\frac{3}{2} )[/tex] and [tex]\frac{dy}{dx} =\frac{\sqrt{4y+3} }{x^2}[/tex]
First, we need to separate the variables to their respective sides
[tex]\frac{1}{\sqrt{4y+3} } dy=\frac{1}{x^2} dx[/tex]
Now, we need to integrate each side
[tex]\int \frac{1}{\sqrt{4y+3} } dy=\int\frac{1}{x^2} dx[/tex]
But first, let us rewrite these functions
[tex]\int (4y+3)^{-\frac{1}{2} } dy=\int x^{-2} dx[/tex]
Before we can integrate, we need to have the hook for the first function. When we integrate [tex](4y+3)^{-\frac{1}{2} }[/tex], we must have a lone 4 within the integral as well.
[tex]\frac{1}{4} \int4 (4y+3)^{-\frac{1}{2} } dy=\int x^{-2} dx[/tex]
Now we can integrate each side to get
[tex]\frac{1}{4} \sqrt{4y+3} =-\frac{1}{x} + c[/tex]
Now is the best time to use the given point in order to find the value of c.
[tex]\frac{1}{4} \sqrt{4(\frac{3}{2}) +3} =-\frac{1}{-2} + c\\\\\frac{1}{4}\sqrt{6+3} =\frac{1}{2} +c \\\\\frac{3}{4}=\frac{1}{2} +c\\ \\c=\frac{1}{4}[/tex]
Now we can plug in our value for c and then solve for y
[tex]\frac{1}{4} \sqrt{4y+3} =-\frac{1}{x} + \frac{1}{4} \\\\\sqrt{4y+3}=-\frac{4}{x} +1\\ \\4y+3=(-\frac{4}{x} +1)^2\\\\4y=(-\frac{4}{x} +1)^2-3\\\\y=\frac{(-\frac{4}{x} +1)^2-3}{4}[/tex]
2. The sum of the ages of Denise and Earl is 42
years. Earl is 8 years younger than Denise.
How old is each?
d-Denis
e-Earl
d+e=42
e+8=d
e+8+e=42
2e+8=42
2e=34
e=17
d=17+8=25
Denis is 25 and Earl is 17
Answer
Earl is 17 years old.
Denis is 25 years old.
See? Easy!
Step-by-step explanation:
WILL GIVE BRAINLIEST HELP ASAP
Answer:
x = -3
Step-by-step explanation:
1.8 - 3.7x = -4.2x +.3
Add 4.2x to each side
1.8 - 3.7x +4.2x= -4.2x+4.2x +.3
1.8 +.5x = .3
Subtract 1.8 from each side
1.8 +.5x -1.8 = .3 -1.8
.5x = -1.5
Divide each side by .5
.5x/.5 = -1.5/.5
x = -3
Answer:
x=-3
Step-by-step explanation:
In order to solve this equation, we have to isolate x. Perform the opposite of what is being done to the equation. Remember to perform everything to both sides.
1.8-3.7x= -4.2x +0.3
3.7x is being subtracted from 1.8 (-3.7x). The inverse operation of subtraction is addition. Add 3.7x to both sides.
1.8-3.7x+3.7x= -4.2x+3.7x+0.3
1.8= -4.2x+3.7x+0.3
1.8= -0.5x+0.3
0.3 is being added to -0.5x. The opposite of addition is subtraction. Subtract 0.3 from both sides.
1.8-0.3= -0.5x+0.3-0.3
1.8-0.3 = -0.5x
1.5=-0.5x
-0.5 and x are being multiplied (-0.5*x= -0.5x). The opposite of multiplication is division. Divide both sides by -0.5.
1.5/-0.5=-0.5x/-0.5
1.5/-0.5=x
-3=x
Please answer this correctly
So if we know the perimeter of the circle we can find it's radius using the formula for perimeter:
[tex]p = 2\pi(r)[/tex]
So we can solve for radius:
[tex]r = \frac{10.71}{2\pi} [/tex]
Then we can plug this radius into the formula for the area of a circle:
[tex]a = \pi {r}^{2} [/tex]
[tex]a = \pi( \frac{10.71}{2\pi} ) ^{2} [/tex]
Then it only wants a quarter of that area so we divide that value by 4 which upon simplification becomes the answer:
[tex]2.28 {ft}^{2} [/tex]
Answer:
[tex] \boxed{Area \: of \: quarter \: circle = 7.065 \: square \: feet} [/tex]
Given:
Perimeter of quarter circle = 10.71 feet
To find:
Area of quarter circle
Step-by-step explanation:
First we need to calculate the radius of quarter circle:
Let the radius of quarter circle be 'r'
[tex]Perimeter \: of \: quarter \: circle = \frac{\pi r}{2} + 2r[/tex]
[tex] \implies 10.71 = \frac{\pi r}{2} + 2r \\ \\ \implies 10.71 = \frac{\pi r}{2} +2r \frac{2}{2} \\ \\ \implies 10.71 = \frac{\pi r}{2} + \frac{4r}{2} \\ \\ \implies 10.71 = \frac{\pi r + 4r}{2} \\ \\ \implies 10.71 \times 2 = \pi r + 4r \\ \\ \implies 21.42 = \pi r + 4r \\ \\ \implies 21.42 = (\pi + 4)r \\ \\ \implies 21.42 = (3.14 + 4)r \\ \\ \implies 21.42 = 7.14r \\ \\ \implies 7.14r = 21.42 \\ \\ \implies r = \frac{21.42}{7.14} \\ \\ \implies r = 3 \: ft[/tex]
[tex] Area \: of \: quarter \: circle = \frac{\pi {r}^{2} }{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{\pi \times {(3)}^{2} }{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{\pi \times 9}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{3.14 \times 9}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{28.26}{4} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =7.065 \: {ft}^{2} [/tex]
The correlation between height and weight among men age 18-74 in the U.S. is about 0.40. Say whether each conclusion below follows from the data; explain your answer. a) Taller men tend to be heavier. b) The correlation between weight and height for men age 18-74 is about 0.40. c) Heavier men tend to be taller. d) If someone eats more and puts on 10 pounds, he is likely to get somewhat taller.
Answer:
Options a, b, c are correct.
Step-by-step explanation:
First let's see the equation that governs the statement, which is the following:
[tex]r = \frac{cov (x, y)}{\sqrt{var(x) var (y)} }[/tex]
Therefore, reading options a, b, c are correct.
Since from the formula we have the correlation coefficient of two variables x and y and here it shows us the correlation between x, y and y, x is the same.
This means that the 0.4 correlation implies a moderate but positive relationship between the two variables.
that is, the highest or lowest value of one variable implies a highest or lowest value of the other variable, respectively.
if this net were to be folded into a cube which number would be opposite of the number 1?
Answer:
6
Step-by-step explanation:
When the cube is folded, 6 is the opposite of 1.
2 is the opposite of 4 and 5 is the opposite of 3.
When the given net is folded into a cube, the number that we will find opposite 1 is 6.
What number will be opposite 1?When the net is folded, two will be folded left and up with 3 being the base. 4 will be folded right with 5 being the top of the cube.
We will then observe the following pairs opposite each other:
5 and 3.4 and 2.1 and 6.This means that the number that we will see opposite 1 will be the number 6.
Find out more on folding nets at https://brainly.com/question/16670460.
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Probability allows one to measure effectively the risks in selecting one alternative over the others.
True
False
If the area of a triangle is 36 in.^2in. 2 and the base is 9 in., what is the height of the triangle?
Answer:
Height = 8
Step-by-step explanation:
Area of a triangle = [tex]\frac{Base*Height}{2}[/tex]
Say the height = x
4.5x = 36
x = 8
Plz help me ASAP it’s important
Answer:
14
Step-by-step explanation:
each square is 2 you count across then up or the other way is fine too from point A to B it equals to 14
What value of x is in the solution set of 2x – 3 > 11 – 5x?
Given:
2x -3 > 11 -5x
Simplify both sides:
2x - 3 > -5x + 11
Add 5x to both sides:
2x - 3 +5x > -5x + 11 +5
7x - 3 > 11
Add 3 to both sides:
7x - 3 +3 > 11 + 3
7x > 14
Divided 7 to both sides:
[tex]\frac{7x}{7}[/tex] > [tex]\frac{14}{7}[/tex]
x > 2
Answer:
Any number greater than 2 would be the answer. In Edg, choose 4! Choosing 2 would be incorrect in their system.
Step-by-step explanation:
Based on historical data, your manager believes that 36% of the company's orders come from first-time customers. A random sample of 195 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is between 0.34 and 0.49
Answer:
[tex] P(0.34 <\hat p<0.49)[/tex]
And the distribution for the sample proportion is given by;
[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And we can find the mean and deviation for the sample proportion:
[te]\mu_{\hat p}= 0.36[/tex]
[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]
And we can use the z score formula given by:
[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]
[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]
And we can use the normal distribution table and we got:
[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]
Step-by-step explanation:
For this case we know that the sample size is n =195 and the probability of success is p=0.36.
We want to find the following probability:
[tex] P(0.34 <\hat p<0.49)[/tex]
And the distribution for the sample proportion is given by;
[tex]\hat p \sim N(p, \sqrt{\frac{p(1-p)}{n}})[/tex]
And we can find the mean and deviation for the sample proportion:
[tex]\mu_{\hat p}= 0.36[/tex]
[tex]\sigma_{\hat p} =\sqrt{\frac{0.36(1-0.36)}{195}}= 0.0344[/tex]
And we can use the z score formula given by:
[tex] z = \frac{0.34 -0.36}{0.0344}= -0.582[/tex]
[tex] z = \frac{0.49 -0.36}{0.0344}= 3.782[/tex]
And we can use the normal distribution table and we got:
[tex] P(-0.582 <z< 3.782) =P(z<3.782)-P(z<-0.582)=0.99992-0.2803= 0.71962[/tex]
whats the percentage of 56/100
Answer:
56%
Step-by-step explanation:
Percent means out of 100
56/100
56 out of 100
56%
Answer:
56%
Step-by-step explanation:
How much is 56 out of 100 written as a percentage? Convert fraction (ratio) 56 / 100 Answer: 56%
Fraction - Multiplication : 3/4 x 1/7
Answer:
given
3/4×1/7
=3×1/4×7
=3/28
thus the answer is 3/28
[tex]answer = \frac{3}{28} \\ solution \\ \frac{3}{4} \times \frac{1}{7} \\ = \frac{3 \times 1}{4 \times 7} \\ = \frac{3}{28} \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment[/tex]
normally distributed with an unknown population mean and a population standard deviation of 4.5 points. A random sample of 45 scores is taken and gives a sample mean of 84. Find a 90% confidence interval
Answer:
= ( 82.90, 85.10) points
Therefore at 90% confidence interval (a,b)= ( 82.90, 85.10) points
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 84
Standard deviation r = 4.5
Number of samples n = 45
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
84+/-1.645(4.5/√45)
84+/-1.645(0.670820393249)
84+/-1.10
= ( 82.90, 85.10) points
Therefore at 90% confidence interval (a,b)= ( 82.90, 85.10) points
Please help. I’ll mark you as brainliest if correct!
Answer:
(0. 4)
(-2, 0)
Step-by-step explanation:
The y- coordinates (output) at the highest and lowest points are called the absolute maximum and absolute minimum, respectively.As per given graph,
absolute maximum is 4, point (0, 4)absolute minimum is 0, point (-2, 0)A large western state consist of 4341 million acres of land. Approximately 83% of this land is federally owned. Find the number of acres that are not federally owned
Answer:
737.97 acres
Step-by-step explanation:
Given
Approximately 83% of a large western state land is federally owned.
Total land in percentage will be 100%
% of land not federally owned = Total land in percentage - % of land federally owned = 100% - 83% = 17%
Thus, percentage of land not federally owned = 17% of total land
Also given "A large western state consist of 4341 million acres of land"
Therefore,
number of acres that are not federally owned = 17% of total western state land
number of acres that are not federally owned = 17/100 * 4341 = 737.97
Thus, 737.97 acres of western state land are not federally owned.
Please answer this correctly
Answer:
40 - 59 ⇒ 6
60 - 79 ⇒ 5
Answer:
40-59: 6
60-79: 5
Step-by-step explanation:
If you just added up, you can find all the values.
If A={A,15,E,17,18, B,20} and B={ X,22, F,42, Y,62,72}, then what is n(A∪B)?
Answer:
14
Step-by-step explanation:
There are 7 elements in each set, and no elements are shared. The number of elements in the union of the sets is then ...
n(A∪B) = 7+7 = 14
ASAP! GIVING BRAINLIEST! Please read the question THEN answer CORRECTLY! NO guessing. I say no guessing because people usually guess on my questions.
Answer:
D. Yes; the graph passes the vertical line test.
Step-by-step explanation:
→The vertical line test is when you hold something (like a pencil), straight up/vertically, and you move it from left-to-right to see if any two points repeat.
→The correct answer is "D. Yes; the graph passes the vertical line test," because the x-values can't repeat, not the y-values, if the graph were to show a function. In this case, the graph passes the vertical line test.
An inverted conical tank starts the day with 250 ft^3 of crayon wax in it. As the factory commences work, the tank is filled with an additional 40 ft^3 of wax per minute. The height of the wax is modeled by H(V)=3 piV/25. A. Write a function , V(t) to model the volume of wax in the tank after t minutes. B. Find an expression for the composition (HoV)(t) C. The composition in B (above) can be described as the ________ of the wax in terms of _______
Answer:
A. V(t) = 40t + 250 B. (HoV)(t) = 24πt/5 + 30π C. The composition in B (above) can be described as the height of the wax in terms of time.
Step-by-step explanation:
A. Let the rate of change of volume V with respect to time be dV/dt = 40 ft³/min
Solving this, V = 40t + C. At the start of the day, that is t = 0, V = 250 ft³
Substituting these values, we have
250 ft³ = 40(0) + C
C = 250 ft³
So, V(t) = 40t + 250
B. Since H(V) = 3πV/25
(HoV)(t) = 3π(40t + 250)/25
= 24πt/5 + 30π
C. The composition in B (above) can be described as the height of the wax in terms of time.
Please help meee
Which number line model represents the expression -2/5 + 4/5:
The number line model that represents the expression -2/5 + 4/5 is: Option B
How to solve Inequality on number line?
To plot an inequality, such as x > 2, on a number line, first draw a circle over the number (e.g., 2). Then if the sign includes equal to (≥ or ≤), fill in the circle. If the sign does not include equal to (> or <), leave the circle unfilled in.
Now, in this case, the operation to solve is:
-2/5 + 4/5
Solving this gives 2/5
Now, since the operation shows a negative and positive fraction with the solution being positive, then we can easily say that Option B is the correct answer to the problem
Read more about Inequality on number line at: https://brainly.com/question/24372553
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Sabrina has designed a rectangular painting that measures 65 feet in length and 30 feet in width. Alfred has also designed a rectangular painting, but it measures x feet shorter on each side. When x = 3, what is the area of Alfred's painting?
Answer:
1674 ft²
Step-by-step explanation:
Area S = 65*30
Area A = (65 - x)(30 - x) = (65 - 3)(30 - 3) = 62*27= 1674 ft²
If f(x)=4arctan(7x), find f'(x). Find f'(4).
f'(x) = (4 arctan(7x))'
f'(x) = 4 (arctan(7x))'
By the chain rule,
f'(x) = 4/(1 + (7x)^2) * (7x)'
f'(x) = 28/(1 + 49x^2)
and hence
f'(4) = 28/(1 + 49*16) = 28/785
In case you're not sure about the derivative of arctan: If y = arctan(x), then x = tan(y). Differentiating both sides with respect to x gives
1 = sec^2y y' = (1 + tan^2y) y' = (1 + x^2) y'
==> y' = 1/(1 + x^2)
What is the range of the relation {(2, 4), (3, 4), (4,7), (5,7), (6,5)}?
Answer:
The range is {4,5,7}
Step-by-step explanation:
The range of a relation is the output values The values are 4,7,5 we normally put them in order from smallest to largest
The range is {4,5,7}
What’s the correct answer for this?
Answer:
I think the answer is 282.6 but my answer is 297.33.
Answer:
the answer will be 282.6m^2
but that is not entirely correct
Step-by-step explanation:
