Al2(CO3)3
5. How many atoms of oxygen are in the compound above?
6. How many total atoms in this compound?
3Fe(OH)2
, Fe
7. How many atoms? H
Total atoms?
Answer:
7. 6 atoms po
Explanation:
sana makatulong po
What is a ternary ionic compound?
Answer:
In inorganic chemistry, a ternary compound is a compound containing three different elements. An example is sodium phosphate, Na3PO4. The sodium ion has a charge of 1+ and the phosphate ion has a charge of 3-. Therefore, three sodium ions are needed to balance the charge of one phosphate ion
Explanation:
Answer:
Not all ionic compound are composed of only monatomic ionic a ternary ionic compound is an ionic compound composed of three element in a typical ternary ionic compound there is still one type of cation and one type of anion involved the cation the anion or both is a polyatomic ion
The validity of scientific theories and laws depends on evidence. Which of the following statements of evidence supports a law rather than a theory?
Electrons orbit the nucleus of an atom within a certain radius.
DNA analysis reveals that a modern species is related to an extinct species.
Seafloor spreading occurs at a rate of three centimeters per year in the mid-Atlantic.
The amount of matter in a closed system is the same at the start of a reaction as at the end of the reaction.
Answer:
d the amount of matter in a closed system is the same at the start of a reaction as at the end of the reaction
Answer:
D
Explanation:
i am doing the test rn and i found the answer in other places
Which of these describes the role of gelada baboons in their ecosystem?
Answer:
Gelada baboons plays a significant role.
Explanation:
The role of gelada baboons in their ecosystem is very important because they aerate the soil for plants which is necessary for good plant growth. These gelada baboons also helps in controlling the population of predator in their ecosystem which is very essential for the stability and equilibrium of the ecosystem so gelada baboons has a good effect on both plants and animals in their ecosystem.
Answer: Primary Consumer
Explanation: Gelada Baboons are herbivores, :D
If 25 g of AlBr3 was produced whenCsBr was added to the reaction vessel, what quantity (grams) of CsBr was added?
The question is incomplete, the complete question is;
3CsBr + Al(OH)3 → AlBr3 + 3CsOH
If 25 g of AlBr3 was produced when 125 mL of a CsBr solution was added, what was the molarity of the CsBr solution?
Answer:
2.25 M
Explanation:
Number of moles of AlBr3 produced = 25g/266.69 g/mol = 0.0937 moles of AlBr3 .
Now, from the reaction equation;
3 moles of CsBr yields 1 mole of AlBr3
Therefore, x moles of CsBr will yield 0.0937 moles of AlBr3
x = 3 * 0.0937 = 0.2811 moles
If 125 mL of a CsBr solution was added
And;
n =CV
where;
n = number of moles
C = concentration of solution
V = volume of solution
C = n/V
C = 0.2811 moles * 1000/125
C= 2.25 M
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial chemist studying this reaction fills a 200. mL flask with 3.9 atm of sulfur dioxide gas and 3.2 atm of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of sulfur trioxide gas to be 1.6 atm. Calculate the pressure equilibrium constant for the reaction of sulfur dioxide and oxygen at the final temperature of the mixture. Round your answer to 2 significant digits.
Answer:
0.20
Explanation:
Step 1: Write the balanced equation
2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)
Step 2: Make an ICE chart
2 SO₂(g) + O₂(g) ⇄ 2 SO₃(g)
I 3.9 3.2 0
C -2x -x +2x
E 3.9-2x 3.2-x 2x
Step 3: Find the value of x
The partial pressure at equilbrium of SO₃ is 1.6 atm. Then,
2x = 1.6 atm
x = 0.80 atm
Step 4: Calculate the partial pressures at equilibrium
pSO₂ = 3.9-2(0.80) = 2.3 atm
pO₂ = 3.2-0.80 = 2.4 atm
pSO₃ = 1.6 atm
Step 5: Calculate the pressure equilibrium constant
Kp = pSO₃² / pSO₂² × pO₂
Kp = 1.6² / 2.3² × 2.4
Kp = 0.20
a beaker of benzene is at room temperature. what is its vapor pressure. Is this vapor pressure large enough to cause the benzene to boil at sea level answers
Answer:
(1). The vapor pressure is 91 mmHg at 20°C.
(2). No, benzene will not boil at sea level.
Explanation:
Benzene, C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mol and Melting point of 5.5 °C. One of the importance or the uses of benzene is in the making of fibres and plastics.
The vapour pressure of benzene can be gotten from the table showing the vapor pressure of different liquids.
Boiling point can simply be defined as the point or the temperature in which the vapor pressure is the same with the atmospheric pressure.
The atmospheric pressure is 760mmHg, while the vapor pressure at sea level is at the temperature of 15°C which is equal to 71 mmHg( from the table showing the vapor pressure of different liquids).
71 mmHg is not equal to 760 mmHg, thus, at sea level Benzene will not boil.
A benzene is chemical that is color less or light to the eyes and is liquid at the rom temperature. It has a sweaty odor and is highly flammable.
Benzene, that is C6H6 is an aromatic, liquid compound with with molar mass of 78.11 g/mole and a Melting point of 5.5 °C. The atmospheric pressure is at the 760mmHg, while the vapor pressure at the sea level is at the temperature of about 15°C which is equal to 71 mmHg. 71 mmHg is not the equal to 760 mmHg, thus, at sea level Benzene will not boil.Thus the vapor pressure is 91 mmHg at 20°C, and No, benzene will not boil at the sea level.
Learn more about the is at room temperature. what is its vapor.
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Students were shown models of two atoms and asked to make a list of similarities and differences between the models.
Which of the statements about the atomic models shown is correct?
A) Both models represent atoms with the same atomic number.
B) Both models represent atoms with the same atomic mass.
C) The model on the left is an ion and the model on the right is an isotope.
D) The model on the left is an isotope and the model on the right is an ion.
Answer:
A: Both models represent atoms with the same atomic number.
Explanation:
The atomic number equals the number of protons.
The correct statement is that both models represent atoms with the same atomic number.
What are isotopes?Isotopes are those molecules which are having the same atomic numbers but different atomic masses.
In the given model both they have the same number of electrons and protons it means they are not ions, but are having different atomic masses as number of neutrons are different.
Hence both models represent atoms with the same atomic number.
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I have 4 oribitals and 6 valence electrons
Which element am i?
answer choices
a. Lead (Pb) I’m a metal
b. Selenium (Se) i’m metal
c. Lead (Pb) I’m a nonmetal
d. selenium (Se) I’m a non metal
Answer:
d. selenium (Se) I’m a non metal
Explanation:
What we know about the element in view is that it has:
4 orbitals
6 valence electrons
The orbitals are the energy levels in the element.
Valence electrons are the outermost shell electrons.
The orbitals tells us the periods in which an element belongs. Since we have 4 orbitals, this suggests that our element belongs to the 4th period.
The number of valence electrons tells us the group in which the element could be found. Since we have 6 valence electrons, the group number is 6.
Therefore, the element is period 4 and group 6 is selenium. Selenium is a non-metal.
did the mixture boil faster
A 20.0 ml sample of glycerol has a mass of 25.2 grams. What is the mass of 63 ml sample of glycerol?
The mass of 63 ml sample : 79.38 g
Further explanationGiven
20 ml and 25.2 g of glycerol
Required
The mass of 63 ml sample
Solution
Density is the ratio of mass per unit volume
Density formula:
[tex]\large{\boxed {\bold {\rho~=~ \frac {m} {V}}}}[/tex]
Density of glycerol :
= m : V
= 25.2 g : 20 ml
= 1.26 g/ml
Mass of 63 ml sample :
= density x volume
= 1.26 g/ml x 63 ml
= 79.38 g
A student sets up the following equation...
Answer:
The answer to your question is given below
Explanation:
From the question given above, the following data were obtained:
Concentration (g/mL) = 0.04 g/mL
Concentration (g/L) =?
We can convert g/mL to g/L by doing the following:
1 g/mL = 1000 g/L
Therefore,
0.04 g/mL = 0.04 g/mL × 1000 g/L / 1 g/mL
0.04 g/mL = 40 g/L
0.04 g/mL is equivalent to 40 g/L.
Thus, the concentration (g/L) is 40 g/L
What is the correct name for: C3S5?
Answer: calcium ion
Explanation:
reen plants absorb sunlight to power photosynthesis, the chemical synthesis of food from water and carbon dioxide. The compound responsible for light absorption and the color of plants, chlorophyll, strongly absorbs light with a wavelength of 453.nm. Calculate the frequency of this light. Round your answer to 3 significant digits.
Answer:
The frequency of the light is 6.62 * 10¹⁴ Hz
Explanation:
The frequency of a wave is defined as the number of complete oscillations made by the wave per second. Its unit is Hertz. The frequency of light as well as the velocity of the light and wavelength of the light are all related.
The velocity of light is the distance the light wave travels per second.
Wavelength is defined as the distance between successive crests and troughs of the wave. It is inversely related to the frequency of the wave.
The velocity of light, c is related to frequency, f, and wavelength, λ, by the formula, c = λf
where the velocity of light, c is a constant = 3 * 10⁸ m/s
λ is wavelength of light = 453 nm = 4.53 * 10⁻⁷ m
Frequency, f = ?
Making f subject of formula in the equation above, f = c/λ
f = 3 * 10⁸ m/s / 4.53 * 10⁻⁷ m
f = 6.62 * 10¹⁴ Hz
Therefore, the frequency of the light is 6.62 * 10¹⁴ Hz
draw the resonance struture of the three possible carbocation intermediates to show how a methoxyl ( -OCH3) directs bromination toward ortho and para positions
Answer:
See explanation
Explanation:
It is clear that certain substituted benzene compounds reacts faster than benzene during electrophillic substitution reactions. This owes to the activation of the benzene ring towards electrophillic substitution by resonance.
The -OCH3 group is ortho- para directing hence it directs an incoming electrophile (such as during bromination) to the ortho or para position as shown in the image attached. This occurs due to resonance (mesomeric) effect as shown in the image attached to this answer.
Image credit: pinterest
An unknown Group 1 metal carbonate, M2CO3, was reacted with excess 2 M HClThe initial mass was 2.002 g of M2CO3and the mass of CO2released was 1.206 g.a) Write a balanced chemical equation for this reaction.
Answer:
The balanced equation of the reaction is given as follows:
M₂CO₃ + 2HCl ---> 2MCl + H₂O + CO₂
The mole ratio of the metallic carbonate to carbon (iv) oxide is 1:1
The metal is Lithium
Explanation:
The balanced equation of the reaction is given below:
M₂CO₃ + 2HCl ---> 2MCl + H₂O + CO₂
From the equation of reaction, 1 ,mole of the metal carbonate reacts with 2 moles of excess HCl to produce 2 moles of the metallic salt, 1 mole of water and 1 mole of CO₂.
The mole ratio of the metallic carbonate to carbon (iv) oxide is 1:1
Molar mass of CO₂ = 44 g/mol
Number of moles of CO₂ in 1.206 g of CO₂ = 1.206 g / 44 g/mol = 0.0274 moles
Therefore, 2.002 g of M₂CO₃ = 0.0274 moles since all the metallic carbonate was reacted with excess HCl
mass of 1 mole of M₂CO₃ = 2.002/0.0274 = 73.06 g
M₂CO₃ =73.06
2 * M + 12 + 3 *16 = 73.06
2M = 73.06 - 60
M = 13.06/2
M = 6.53 g
Since, the metal belongs to group 1, the metal is most likely Lithium as the molar mass of M is closest to Lithium.
The balanced equation of the reaction is defined as the number of atoms present equally in the reactant and products.
[tex]M_2CO_3 + 2HCl ---> 2MCl + H_2O + CO_2[/tex]
The metal "M" in the reaction is Lithium.
The steps for the balanced reaction is as follows:-
Balance the center metal firstAfter balancing the central atom, then balanced the hydrogen and the oxygen.
After doing all the steps in the reactions the balanced equation of the reaction is given below:
[tex]Li_2CO_3 + 2HCl ---> 2liCl + H_2O + CO_2[/tex]
This is the balanced reaction.
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A sample of nitrogen gas expands in volume from 16 L to 5.4 L at constant
temperature. Calculate the work done in joules if the gas expands (a) against
a vacuum, (b) against a constant pressure of 0.80 atm.
Please answer if yk
a. W = 0 J
b. W = - 308.028 J
Further explanationGiven
Nitrogen gas expands in volume from 1.6 L to 5.4 L
Required
The work done
Solution
Isothermal :
W = -P . ΔV
Input the value :
a. At a vacuum, P = 0
So W = 0
b. At pressure = 0.8 atm
W = - 0.8 x ( 5.4 - 1.6)
W = -3.04 L.atm ( 1 L.atm = 101.325 J)
W = - 3.04 x 101.325
W = - 308.028 J
a solution is 5.00% potassium chloride by mass. how much potassium chloride would you expect to collect by evaporating 150.0 g of the solution
Answer:
When 150.0g of the solution are evaporated, 7.50g of KCl must be collected
Explanation:
A solution 5% of potassium chloride means that there are 5g of KCl per 100g of solution.
When all the solution is evaporated, the solute KCl will be collected as a solid.
In 150g of solution there are:
150g * (5.00gKCl / 100g solution) = 7.50g of KCl are present in 150g of solution.
That means:
When 150.0g of the solution are evaporated, 7.50g of KCl must be collectedAriel drew the cladogram shown.
Which best describes species C?
It has jaws, but no hollow bones.
It has hollow bones, but no jaws.
It has neither hollow bones nor jaws.
It has hollow bones and jaws.
Answer:
It has hollow bones and jaws.
Explanation:
The cladogram shows that Species C has both hollow bones and Jaws. Species A has hollow bones while species B has Jaws. The cladograms shows that species C has both the characteristics.
Answer:
C. It has neither hollow bones nor jaws.
Explanation:
Calculate the second volumes 980L at 71C and 107.2atm to 13C and 59.3atm
Answer:
V₂ = 1473.03 L
Explanation:
Given data:
Initial volume = 980 L
Initial pressure = 107.2 atm
Initial temperature = 71 °C (71 +273.15 = 344.15 K)
Final temperature = 13°C (13+273.15 = 286.15K)
Final volume = ?
Final pressure = 59.3 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 107.2 atm × 980L × 286.15 K / 344.15 K× 59.3 atm
V₂ = 30061774.4 atm .L. K / 20408.095 atm. K
V₂ = 1473.03 L
An element crystallizes in a face-centered cubic lattice. If the length of an edge of the unit cell is 0.408 nm, and the density of the element is 19.3 g/cm3 , what is the identity of the element?
Answer:
Au
Explanation:
For the density of a face-centered cubic:
[tex]Density = \dfrac{4 \times M_w}{N_A \times a^3}[/tex]
where
[tex]M_w[/tex] = molar mass of the compound
[tex]N_A=[/tex] avogadro's constant
[tex]a^3 =[/tex] the volume of a unit cell
Given that:
Density [tex](\rho)[/tex] = 19.30 g/cm³
a = 0.408 nm
a = [tex]0.408 \times 10^{-9} \times 10^{2} \ cm[/tex]
a = [tex]4.08 \times 10^ {-8} \ cm[/tex]
∴
[tex]19.3 = \dfrac{4 \times M_w}{(6.023 \tmes 10^{23})\times (4.08 \times 10^{-8})^3}[/tex]
[tex]M_w= \dfrac{19.3\times (6.023 \times 10^{23})\times (4.08 \times 10^{-8})^3}{4}[/tex]
[tex]M_w=197.37 \ g/mol[/tex]
Thus, the molar mass of 197.37 g/mol element is Gold (Au).
how many moles is 52.16 g of AIN
Answer:
Number of moles = 1.3 mol
Explanation:
Given data:
Number of moles of AlN = ?
Mass of AlN = 52.16 g
Solution:
Formula:
Number of moles = mass/molar mass
Molar mass of AlN = 40 g/mol
By putting values,
Number of moles = 52.16 g/ 40 g/mol
Number of moles = 1.3 mol
Someone help will give brainiest if best and reasonable answer
5.
Solid Phase (Ice)
Unlike most other substances, water's solid form (ice) is less dense than its liquid form, as a result of the nature of its hexagonal packing within its crystalline structure. ... However, a block of ice floats in liquid water because ice is less dense than liquid water.
Unlike most other substances, water's solid form (ice) is less dense than its liquid form, as a result of the nature of its hexagonal packing within its crystalline structure. This lattice contains more space than when the molecules are in the liquid state. ... Liquid water is most dense at 4 degrees Celsius.
6.Evaporation is a phase transition from the liquid phase to the gas phase that occurs at temperatures below the boiling point at a given pressure.
Consider the reaction 3O2(g) 2O3(g) At 298 K, the equilibrium concentration of O2 is 1.6 x 10^-2 M, What is the equilibrium constant of the reaction at this temperature?
Answer:
Kc = 105062.5 at 298K
Explanation:
First of all, we state the equilibrium:
3O₂(g) ⇄ 2O₃(g)
We know data about equilibrium concentration of oxygen. We suppose 1 mol of oxygen at the begining. During the reaction, x moles have reacted.
As ratio is 2:3, we can determine how many moles of ozone have been produced.
(x . 2)/3
So we have the final concentration of oxygen, so, let's find out x
1 - x = 0.016 moles
x = 0.984 moles
Then, the [O₃] in equilibrium will be (0.984 . 2) /3 = 0.656.
We supose a volume of 1 L, so we have molar concentration to determine Kc. Let's state the expression for it:
Kc = [O₃]² / [O₂]³
Kc = 0.656² / 0.016³ → 105062.5
Answer: A. 2.0 x 10^-50
Explanation: That’s what I got on Edge.
Enter the electron configuration for the ion most likely formed by phosphorus. Express your answer in the order of orbital filling as a string without blank space between orbitals. For example, the electron configuration of Li could be entered as 1s^22s^1 or [He]2s^1.
Answer:
1s2 2s2 2p6 3s2 3p6
Explanation:
Phosphorus is a non metal. It gains electrons to form ions. The most likely ion formed is the phosphide, where it gains three extra electrons.
Total number of electrons in Phosphide = 15 + 3 =18
The electronic configuration is given as;
1s2 2s2 2p6 3s2 3p6
Electronic Configuration can be defined as the electron distribution of an atom or molecule in an atomic or molecular orbit. The atomic orbit consists of the s, p and d orbitals.
The Atomic number of Phosphorus is 15.
Thus, the Electronic configuration of Phosphorus is 1s² 2s² 2p6 3s² 3p³.
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A reaction of 100mL of 1.35 M HCl and 100mL of 1.76 M NaOH is monitored and the following
temperatures were recorded: starting temperature = 24.6 C; and final temperature = 38.8 C.
Calculate the AH of this reaction.
A) -92142
J/Mole
B) -12439.2
J/Mole
C) 876
J/Mole
Answer: [tex]\Delta H[/tex] for the reaction is 87935 J
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.
[tex]Molarity=\frac{moles}{\text {Volume in L}}[/tex]
[tex]moles of HCl[/tex]=[tex]Molarity\times {\text {Volume in L}}=1.35\times 0.01=0.135moles[/tex]
[tex]moles of NaOH[/tex]= [tex]Molarity\times {\text {Volume in L}}=1.76\times 0.01=0.176moles[/tex]
As 1 mole of HCl neutralizes 1 mole of NaOH
0.135 moles of HCl will neutralize = 0.135 mole of NaOH
Thus HCl is the limiting reagent.
[tex]Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})[/tex]
Q = Heat absorbed by water = ?
m = mass of water = 200 g (volume of water=200ml, density of wtaer = 1 g/ml)
c = specific heat capacity = [tex]4.18 J/g^0C[/tex]
Initial temperature of water = = 24.6°C
Final temperature of water= = 38.8 °C
[tex]Q=200\times 4.18\times (38.8-24.6)[/tex]
[tex]Q=11871.2J[/tex]
Thus heat released by 0.135 moles is = -11871.2 J
heat released by 1 mole is =[tex]\frac{-11871.2 J}{0.135}\times 1=-87935J[/tex]
The heat of reaction, ΔH is 87935 J
Molarity and Heat of Reaction ΔHMolarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.The heat of reaction ΔH, is the amount of heat evolved or absorbed when a chemical reaction occurs between molar quantities of the reactants as represented in the equation of reaction.Equation of reaction between HCl and NaOH is given below:
HCl + NaOH ----> NaCl + H₂OMolarity = number of mole/volume
Number of moles = molarity * volume
Number of moles of HCl = 1.35 M * 0.1 L = 0.135 moles
Moles of NaOH = 1.76 M * 0.1 L = 0.176 moles
1 mole of HCl neutralizes 1 mole of NaOH
Therefore, 0.135 moles of HCl will neutralize 0.135 mole of NaOHTherefore, NaOH is in excess and HCl is the limiting reagent.Calculating the quantity of heat evolved:
Q = mcΔTwhere m is mass, c is specific heat capacity, ΔT is temperature change
Quantity of heat evolved by reaction = Heat absorbed by waterHeat absorbed by water, Q = mcΔT
mass of water = density * volume
density of water = 1 g/mL
volume of water = 200 mL
mass of water = 1 g/mL * 200 mL
mass of water = 200 g
specific heat capacity of water, c = 4.18 J/g°C
ΔT = final temperature of water - initial temperature of waterInitial temperature of water = = 24.6°C
Final temperature of water= = 38.8 °C
ΔT = 38.8 - 24.6 = 13.7°C
Q = 200 g * 4.18 J/g°C * 14.2°c
Q = 11871.2 J
Therefore, heat released by 0.135 moles is = -11871.2 J
Heat released by 1 mole = 11871.2 * 1/0.135
Heat released by 1 mole = 87935 J
Therefore, the heat of reaction, ΔH is 87935 J
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How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
__NaOH + __CuSO4 à __Na2SO4 + __Cu(OH)2
Answer:
5.0 × 10²⁴ molecules
Explanation:
Step 1: Write the balanced double displacement reaction
2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂
Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄
We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.
5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol
Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄
The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.
Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄
We will use Avogadro's number.
8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule
CzHs + __02-> __CO2+ _H20 *
I need help ASAP PLSSS
Answer:
2,7,4,6
Explanation:
atoms at the left side should be equal to that of right for an equation to be balanced. so the answer is the final one
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Place these features in the order they would probably form:
sea stack, sea cave, headland, cliff, and sea arch
If something has an actual yield of 2.5 grams and a theoretical yield of 10 grams, what is the percent yield?
A)30%
B)25%
C)45%
D)10%