40 points
Examine the table and write down what should be in each row below.
Write your answers on different lines for each row and place a common in
between each answer in that same row.*
Name
Symbol
Atomic
number
Mass
Number
Number of
neutrons
Number of
Electrons
Charge
Lithium-5
su
3
SB
1601
ISN
7
25Na
187
Your answer

atomic number tells us how many neutrons an element has

Answer:

[tex]7.27[/tex] x [tex]10^{2}[/tex]

[tex]1.72[/tex] x [tex]10^{5}[/tex]

[tex]9.84[/tex] x [tex]10^{-4}[/tex]

[tex]2[/tex] x [tex]10^{4}[/tex]

[tex]1.4[/tex] x [tex]10^{0}[/tex]

[tex]2.560[/tex] x [tex]10^{33}[/tex]

Answer:

The total heat required is 691,026.36 J

Explanation:

Latent heat is the amount of heat that a body receives or gives to produce a phase change. It is calculated as: Q = m. L

Where Q: amount of heat, m: mass and L: latent heat

On the other hand, sensible heat is the amount of heat that a body can receive or give up due to a change in temperature. Its calculation is through the expression:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, constituted by a substance of specific heat c and where ΔT is the change in temperature (Tfinal - Tinitial).

In this case, the total heat required is calculated as:

Q= c*m*ΔT

[tex]Q=4.184\frac{J}{g*C} *248 g* (100 -0 )C[/tex]

Q=103,763.2 J

Q= m*L

[tex]Q=13.78moles*40.79 \frac{kJ}{mol}[/tex]

Q=562.0862 kJ= 562,086.2 J (being 1 kJ=1,000 J)

Q= c*m*ΔT

[tex]Q=1.99\frac{J}{g*C} *248 g* (154 - 100 )C[/tex]

Q=25,176.96 J

So, total heat= 103,763.2 J + 562,086.2 J + 25,176.96 J= 691,026.36 J

The total heat required is 691,026.36 J

The specific heat can be defined as the amount of heat required to raise the temperature of one gram of substance by one degree Celsius. The total heat of the reaction has been 691.029 kJ.

The heat of vaporization is the amount of heat required to convert  the liquid to the vapor state.

The water at 0 degree Celsius has been converted to the water at 100 degree Celsius. The 100 degree Celsius water vaporized to 100 degree steam. The 100 degree steam will be converted to the 154 degree Celsius.

The conversion of 0 degree Celsius water to 100 degree Celsius

[tex]Q_1=mc\Delta T[/tex]

Substituting the values of mass ([tex]m[/tex]), specific heat ([tex]c[/tex]), and change in temperature ([tex]\Delta T[/tex]):

[tex]Q_1=248\;\times\;4.184\;\times\;(100-0)\\Q_1=103,763.2\;\text J\\Q_1=103.7632\;\rm k\text J[/tex]

The amount of heat required to convert 100 degree Celsius water to 100 degree Celsius steam has been:

[tex]Q_2=mL[/tex]

Substituting the values of mass ([tex]m[/tex]), and heat of vaporization ([tex]L[/tex]):

[tex]Q_2=248\;\times\;40.79\\Q_2-562.0862\;\rm kJ[/tex]

The amount of heat required to convert 100 degree Celsius steam to 154 degree Celsius steam has been:

[tex]Q_3=mc\Delta T[/tex]

Substituting the values of mass ([tex]m[/tex]), heat of steam ([tex]c[/tex]), and change in temperature ([tex]\Delta T[/tex]):

[tex]Q_3=248\;\times\;1.99\;\times\;(154-100)\\Q_3=25,176.96 \;\text J\\Q_3=25.1796\;\rm kJ[/tex]

The total amount of heat in the reaction has been:

[tex]Q=Q_1+Q_2+Q_3[/tex]

Substituting the values for the total heat of the reaction:

[tex]Q=103.7632+562.0862+25.1796\;\rm kJ\\\textit Q=691.029\;kJ[/tex]

The total heat of the reaction for the conversion of water from 0 degree Celsius to 100 degree Celsius is 691.029 kJ.

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To solve this we must be knowing each and every concept related to isotope and its example. Therefore, the corresponding isotope is ₁₇Cl³⁷.

Each atom contains the exact same quantity of electrons like protons, but isotopes differ somewhat; they contain the very same amount of electrons as well as protons but differing quantities of neutrons.

Isotopes, on the other hand, possess the same atomic number as well as the same location in the periodic table, but they have unique atomic weights. These isotopes will deteriorate over time and transform into some other isotope or element. The majority of elements discovered in nature are composed of stable isotopes.

number of proton +number of  neutrons = Mass number = 37

number of proton=atomic number= 17

The corresponding isotope is ₁₇Cl³⁷.

Therefore, the corresponding isotope is ₁₇Cl³⁷.

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Answer:

[tex]\rho =2.6g/mL[/tex]

Explanation:

Hello,

In this case, considering that the density is defined as:

[tex]\rho =\frac{m}{V}[/tex]

Thus, since 1 kg equals 1000 g and 1 L equal 1000 mL, the required density in g/mL turns out:

[tex]\rho =\frac{1.7132kg}{0.65L}*\frac{1000g}{1kg}*\frac{1L}{1000mL} \\\\\rho=2.6g/mL[/tex]

Take into account that since 0.65 L has two significant figures, the result is also shown with two significant figures.

Regards.

Answer:

Explanation:

Entropy change in the system : --

ΔG =   −54 kJ⋅mol−1 (−13 kcal⋅mol−1)  =   −54 kJ⋅mol−1 (−13 x 4.2  kJ⋅mol−1)

= - 108.6  KJ / mol

ΔH =  -251 kJ/mol (-60 kcal/mol) =  -251 kJ/mol (-60 x 4.2  kJ/mol)

= - 503  KJ / mol

ΔG = ΔH - TΔS

ΔS = ( ΔH - ΔG ) / T

=  - 503 + 108.6 / ( 273 + 25 ) KJ / mol k⁻¹

= - 1323.48 J / mol k⁻¹

Entropy change in the surrounding

+ 1323.48 J / mol k⁻¹

Answer:

1. 1.80x10⁻⁵ (w/w %).

2. 1.80x10⁻⁴ parts per thousand

3. 0.18 parts per million

Explanation:

The solution contains 45.1μg / 250mL.

1. Weight percent (100 times mass in grams of solute per gram of solution, as there are 250mL of water = 250g):

45.1x10⁻⁶g / 250g * 100 =

2. Parts per thousand (mg of solute per g of solution).

45.1μg * (1x10⁻³mg / 1μg) = 0.0451mg.

0.0451mg / 250g =

3. Parts per million (μg of solute per g of solution):

45.1μg / 250g =

Answer:

[tex]\%_{Rb-85}=33.9\%[/tex]

[tex]\%_{Rb-87}=66.1\%[/tex]

Explanation:

Hello,

In this case, for the natural occurring isotopes we equal the average atomic mass via:

[tex]86.231=84.911*\%_{Rb-85}+86.909*\%_{Rb-87}[/tex]

Thus, since both percentages of abundance must turn out 100%, we can write:

[tex]\%_{Rb-85}+\%_{Rb-87}=100\%\\\\\%_{Rb-85}=100\%-\%_{Rb-87}[/tex]

So we can write:

[tex]86.231=84.911*(100\%-\%_{Rb-87})+86.909*\%_{Rb-87}[/tex]

Solving for the percentage of abundance of Rb-87:

[tex]86.231=84911.00\%-84.911\%_{Rb-87}+86.909*\%_{Rb-87}\\\\\%_{Rb-87}=\frac{86.231-84.911}{-84.911+86.909}\\ \\\%_{Rb-87}=66.1\%[/tex]

Therefore, the percentage of abundance of Rb-85 turns out:

[tex]\%_{Rb-85}=100\%-66.1\%\\\\\%_{Rb-85}=33.9\%[/tex]

Best regards.

Considering the definition of atomic mass, isotopes and atomic mass of an element, the percentages of the isotopes in this sample are:

First of all, the atomic mass (A) is obtained by adding the number of protons and neutrons in a given nucleus of a chemical element.

The same chemical element can be made up of different atoms, that is, their atomic numbers are the same, but the number of neutrons is different. These atoms are called isotopes of the element.

On the other hand, the atomic mass of an element is the weighted average mass of its natural isotopes. In other words, the atomic masses of chemical elements are usually calculated as the weighted average of the masses of the different isotopes of each element, taking into account the relative abundance of each of them.

In this case, a certain sample of rubidium has just two isotopes, 85Rb (mass = 84.911amu) and 87Rb (mass = 86.909amu).  Then, the average mass of lithium can be calculated as:

84.911× percent of Rb-85 + 86.909× percent of Rb-87= 86.231

Since both abundance percentages must be 100%, you can write:

percent of Rb-85 + percent of Rb-87= 100

Then:

percent of Rb-85 = 100% - percent of Rb-87

So, replacing this expression in the first equation:

84.911× (100% - percent of Rb-87) + 86.909× percent of Rb-87= 86.231

Solving:

84.911×100% - 84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231

8491.1% -84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231

-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 8491.1%

-84.911× percent of Rb-87 + 86.909× percent of Rb-87= 86.231 - 84.911

1.998× percent of Rb-87= 86.231 - 84.911

1.998× percent of Rb-87= 1.32

percent of Rb-87= 1.32÷ 1.998

percent of Rb-87= 0.6607

percent of Rb-87= 66.07%

Therefore, the percentage of abundance of Rb-85 is:

percent of Rb-85 = 100% - percent of Rb-87

percent of Rb-85 = 100% - 66.07%

percent of Rb-85 = 33.93%

Finally, the percentages of the isotopes in this sample are:

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Answer:

crabby patties I'm not good at english probably spelled that wrong

Answer:

a what is the HCO3"/CO2 ratio

Answer : The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars. After an asteroid belt comes the outer planets, Jupiter, Saturn, Uranus and Neptune. The interesting thing is, in some other planetary systems discovered, the gas giants are actually quite close to the sun.

Answer:

Mercury

venus

earth

mars

jupiter

saturn

uranus

Neptune

Explanation:

Answer:

The ice occupies a volume of 1.196 liters at -10 ºC.

Explanation:

We must remember that density ([tex]\rho[/tex]), measured in grams per cubic centimeters, is the ratio of mass ([tex]m[/tex]), measured in grams, to occupied volume ([tex]V[/tex]), measured in cubic centimeters, that is:

[tex]\rho = \frac{m}{V}[/tex]

We clear the mass within the formula:

[tex]m = \rho\cdot V[/tex]

The mass of the water inside the soft-drink bottle is: ([tex]\rho = 0.997\,\frac{g}{cm^{3}}[/tex] and [tex]V = 1100\,cm^{3}[/tex])

[tex]m =\left(0.997\,\frac{g}{cm^{3}} \right)\cdot (1100\,cm^{3})[/tex]

[tex]m = 1096.7\,g[/tex]

There are 1096.7 grams of water filling the soft-drink bottle completely.

Then, the water is frozen to -10 ºC and transformed into ice, the volume occupied by the ice which we can deduct from definition of density. That is:

[tex]V = \frac{m}{\rho}[/tex]

The volume occupied by the ice inside the soft-drink bottle is: ([tex]m = 1096.7\,g[/tex] and [tex]\rho = 0.917\,\frac{g}{cm^{3}}[/tex])

[tex]V = \frac{1096.7\,g}{0.917\,\frac{g}{cm^{3}} }[/tex]

[tex]V = 1195.965\,cm^{3}\,(1.196\,L)[/tex]

The ice occupies a volume of 1.196 liters at -10 ºC.

Answer:

Amount of required rations ≥ 15 g

Other assumptions made:

1. All the energy released from the rations is converted to heat

2. All the rations is completely metabolized to release energy

3. No other heat losses occur in the body except due to wetness of her clothing.

Explanation:

Using H = mcθ

where m is mass of the hiker in Kg,

c is specific heat capacity of water/hiker = 4200 JKg⁻¹K⁻¹

θ is temperature change in K

Note : heat capacity of water = specific heat capacity x molar mass

specific heat capacity = heat capacity / molar mass

c = 75.348 JK⁻¹mol⁻¹/18 x 10⁻³ Kgmol⁻¹ = 4186 JKg⁻¹K⁻¹ ≅ 4200 JKg⁻¹K⁻¹

Heat lost, H = 50.0 Kg x 4200 JKg⁻¹K⁻¹ x 2.5 K

H = 5.25 x 10⁵ J = 525 KJ

To avoid this heat loss, the hiker must consume enough emergency rations that releases heat equal to or greater than the heat loss due to wetness of her clothing.

Energy per gram of rations = 35 KJ

Amount of required rations ≥ 525 KJ / 35 KJ/g

Amount of required rations ≥ 15 g

Therefore, the hiker must consume 15 g or more of her emergency rations.

Other assumptions made:

1. All the energy released from the rations is converted to heat

2. All the rations is completely metabolized to release energy

3. No other heat losses occur in the body except due to wetness of her clothing.

Answer:

a

The value is [tex]b  =  4.61 *10^{-5} \  m^3 /mol[/tex]

b

[tex]Z =  0.66[/tex]

Explanation:

Generally the pressure of the gas  is mathematically represented as

     [tex]P  =  \frac{RT}{V_m -b}  - \frac{a}{(V_m)^2}[/tex]

Substituting [tex]8.314 \  m^3\cdot Pa\cdot K^{-1}\cdot mol^{-1}[/tex] for R , 273K for  T  , [tex]5.00 * 10^{-4} m^3[/tex] for  [tex]V_m[/tex] ,  [tex]0.50 \ m^6 \cdot Pa\cdot  mol^{-2}[/tex] for a  and  [tex]3.0 MPa =  3.0*10^{9} \ Pa[/tex] for P

We have

     [tex]3*10^6 =  \frac{8.314 * 273}{5.00*10^{-4} - b}  - \frac{0.50}{(5.00*10^{-4})^2 }[/tex]

=>  [tex]b  =  4.61 *10^{-5} \  m^3 /mol[/tex]

Generally the compression factor is mathematically represented as

       [tex]Z =  \frac{P* V_m }{RT}[/tex]

=>   [tex]Z =  \frac{3.0 *10^{6}* 5.0 *10^{-4} }{8.314 *273}[/tex]

=>     [tex]Z =  0.66[/tex]

The stability of an atom is affected by the balance between the electrons, protons, and neutrons in an atom.

A particle less than an atom is referred to as a subatomic particle. A subatomic particle can either be an elementary particle, which is not made of other particles, or a composite particle, which is composed of other particles, according to the Standard Model of particle physics.

Particles smaller than an atom are referred to as subatomic particles. The three primary subatomic particles present in an atom are protons, neutrons, and electrons.

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Answer:

The answer is digital divide.

Explanation:

Digital divide is the answer because if there is only one-fifth of the world that has computers then the United Nations cannot communicate with everyone ,so there is a digital divide and that is your answer. Also, I took the test and I got the question right.

Answer:

The answer is digital divide.

Explanation:

Digital divide is the answer because if there is only one-fifth of the world that has computers then the United Nations cannot communicate with everyone ,so there is a digital divide and that is your answer. Also, I took the test and I got the question right.

Answer:

d. 0.25.

Explanation:

Hello,

In this case, since the equilibrium repression for the considered chemical reaction is:

[tex]Ksp=[Ag^+]^2[CrO_4^{2-}][/tex]

For a concentration of silver of 6.0x10⁻⁶ we need a concentration of chromate anion that makes the reaction quotient greater than the solubility product, thus, we write:

[tex][CrO_4^{2-}]=\frac{Ksp}{[Ag^+]^2} =\frac{9.0x10^{-12}}{(6.0x10^{-6})^2}[/tex]

[tex][CrO_4^{2-}]=0.25M[/tex]

It means that at concentrations of chromate anion of 0.25 M or more, the reaction quotient Q becomes greater than the solubility product which means that precipitation will begin occurring, therefore, answer is d. 0.25.

Best regards.

Answer:

Matthias Schleiden and Theodor Schwann. However, many other scientists like Rudolf Virchow contributed to the theory.

Explanation:

Answer:Theodor Shwann

Explanation:

Answer:

The value  is   [tex]L  =  0.985 \pm 0.00801 \ g[/tex]

Explanation:

From the question we are told that

  The  molar mass of [tex]CaCO_3[/tex] is  [tex]MW  =  100.085 \  g/mol[/tex]

   The  total mass is  [tex]m_g  = 12.3 \ g[/tex]

   The uncertainty of the total mass is [tex]\Delta g  = 0.1[/tex]

Generally the molar weight of calcium is [tex]M_c  =  40 g/mol[/tex]

 The percentage of calcium in calcite is mathematically represented as

          [tex]C =  \frac{40.07}{100.085} * 100[/tex]

          [tex]C =  40.03 \% [/tex]

Generally the mass of each sample is mathematically represented as

     [tex]m=  \frac{m_g}{5}[/tex]

     [tex]m=  \frac{12.3}{5}[/tex]

     [tex]m= 2.46 \  g [/tex]

Generally mass of calcium present in a single sample is mathematically represented as

        [tex]m_c = 2.46 *  \frac{40.04}{100}[/tex]

       [tex]m_c = 0.985 \  g [/tex]

The  uncertainty of  mass of a single sample is mathematically represented as

      [tex]k  =  \frac{\Delta g }{5}[/tex]

        [tex]k  =  \frac{0.1 }{5}[/tex]

       [tex]k  =  0.02\  g [/tex]

The  uncertainty of  mass of calcium in a single sample is mathematically represent

         [tex]G  =  \frac{0.02 *  40.04}{ 100}[/tex]

          [tex]G  =  0.00801 \  g [/tex]

Generally the average mass of calcium in each sample is  

          [tex]L  =  0.985 \pm 0.00801[/tex]

Answer:

A) 3NH₄ClO₄ + 3Al ---> Al₂O₃ + AlCl₃ + 6H₂O + 3NO

B) 150 g of ammonium perchlorate will produce 43.4 g of aluminum oxide

Explanation:

A)Balanced equation of reaction:

3NH₄ClO₄ + 3Al ---> Al₂O₃ + AlCl₃ + 6H₂O + 3NO

Oxidation states:

Nitrogen, N:  from -3 to +2

Hydrogen, H: from +1 to +1

Chlorine, Cl: From +7 to -1

Oxygen, O: from -2 t0 -2

Aluminum, Al: from 0 to +3.

Oxidizing agent is ammonium perchlorate while the reducing agent is the aluminum powder.

B) molar mass of aluminum oxide = 102 g/mol; molar mass of ammonium perchlorate =117.5 g/mol

From the equation of reaction 3 moles of ammonium perchlorate reacts with 3 moles of aluminum to produce 1 mole of aluminum oxide;

that is 3 * 117.5 g of  ammonium perchlorate reacts with 3 * 27 g of aluminum to produce 102 g/mol of aluminum oxide

150 g of ammonium perchlorate will react with (150 * 3*27) / (3 * 117.5) of aluminum = 34.47 g of Al

Ammonium perchlorate is the limiting reactant.

150 g of ammonium perchlorate will produce (150 * 102)/(3*117.5) g of aluminum oxide = 43.4 g of aluminum oxide

The branch of science that deals with chemicals and bonds are called chemistry. Chemistry deals with the physical and chemical behavior of the element.

The correct answer to the question is [tex]3NH_4ClO_4 + 3Al ---> Al_2O_3 + AlCl_3 + 6H_2O + 3NO[/tex]

B) 150 g of ammonium perchlorate will produce 43.4 g of aluminum oxide

The oxidizing agent is ammonium perchlorate while the reducing agent is the aluminum powder.

B) molar mass of aluminum oxide = 102 g/mol; molar mass of ammonium perchlorate =117.5 g/mol. From the equation of reaction 3 moles of ammonium perchlorate reacts with 3 moles of aluminum to produce 1 mole of aluminum oxide;

That is[tex]3 * 117.5[/tex] g of ammonium perchlorate reacts with [tex]3 * 27[/tex]g of aluminum to produce 102 g/mol of aluminum oxide. 150 g of ammonium perchlorate will react with [tex]\frac{(150 * 3*27) }{ (3 * 117.5)}[/tex] of aluminum = 34.47 g of Al

Ammonium perchlorate is the limiting reactant.

150 g of ammonium perchlorate will produce (150 * 102)/(3*117.5) g of aluminum oxide

= 43.4 g of aluminum oxide.

Hence, the correct answer is 4.34g.

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Answer:

2.59

x

1024

=

C

O

2

=

Explanation:

Answer:

The value is [tex]k =66\%[/tex]

Explanation:

From the question we are told that

The mass of toluene [tex] m_t =0.73 \ g [/tex]

The mass of potassium permanganate is [tex] m =2.0 \ g [/tex]

The volume of potassium hydroxide V = 7.0 mL

The concentration of potassium hydroxide C = 6 M

The mass of benzoic acid is [tex]m_b = 0.633 \ g[/tex]

Generally the % yield of benzoic acid is mathematically represented as

[tex]k = \frac{m_b}{Z} * 100[/tex]

Here Z is the theoretical yield which is mathematically represented as

[tex]Z = \frac{E}{W} * m_t [/tex]

Here W is the molecular weight of product (benzoic acid) with value  

       W  = 92.14 \ g

E is the molecular weight of reactant (toluene)with a constant value  of  

    E =  122.12 g

So

     [tex]Z =  \frac{122.12 }{92.14}  *  0.73 [/tex]

=>    [tex]Z = 0.968 \  g  [/tex]

So

     [tex]k  =  \frac{0.633}{0.968}  * 100[/tex]

=>   [tex]k  =66\%[/tex]

Answer:

The answer is

Explanation:

The Density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} [/tex]

From the question

mass of rock = 12.34 g

volume = final volume of water - initial volume of water

volume = 54.5 mL - 50 mL = 4.5 mL

So the density is

[tex]density = \frac{12.34}{4.5} \\ = 2.744444444...[/tex]

We have the final answer as

Hope this helps you

Answer:

an ion with charge of 2+

Explanation:

proton and electron numbers do not cancel out...

it has 2 more protons than electrons.

since protons carry a positive charge, a charge of 2+ is now carried by the ion.

it is no longer called an atom as the charges do not cancel out.

Answer: An ion with a charge of +2.

Explanation:

The classification of the following elements as a physical or chemical property is shown below

a) iron and oxygen form rust

b)iron is more dense than aluminum

c) magnesium burns brightly when ignited

d)oil and water do not mix

e)mercury melts as -39 C

A. Chemical

B. Physical

C. Chemical

D. Physical

E. Physical

For better understanding let's explain what the statement that

From the above we can therefore say that the answer The classification of the following elements as a physical or chemical property is shown below;

a) iron and oxygen form rust

b)iron is more dense than aluminum

c) magnesium burns brightly when ignited

d)oil and water do not mix

e)mercury melts as -39 C

A. Chemical

B. Physical

C. Chemical

D. Physical

E. Physical

is correct

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Answer:

D

Explanation:

Resonance because the lone pairs undergo resonance due tothe partial bond relationship BTW Carbon - Nitrogen bond so the bond length shortens making the six atoms of peptide bond planar

And positive because The dipole of amide linkage of a peptide bond is as a result of the partially positively charged carbonyl oxygen and partially positively charged amide oxygen.

And the negative because The carboxylic acid group -COOH is an acid donates H+ and -NH2 being a base is H+ so causes a partial negative charge to develop on -COO(-) and partial positive charge to develop on -NH3(+).l

Answer:

The answer to your question is A | Mn

Answer:

Infer and form a hypothesis