4.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 152. gimol, is burned completely in excess oxygen, and the mass of the products carefully measured:
product mass
carbon dioxide 5.79 g
water 2.84 g
Use this information to find the molecular formula of X.

Answer:Cs2O + H2O —> 2CsOH [2Cs+ + 2OH-]

Explanation: Cs is the most electropositive element, with electron structure [Xe] 6s1.

Answer:

Check the explanation section.

Explanation:

The following steps should be followed orderly.

STEP ONE:

Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.

Where C1 and C2 are the concentration of the stock solution and the diluted solution.

STEP TWO:

Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose

and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.

STEP TWO:

Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.

So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.

Therefore, from STEP ONE ABOVE, we have the dilution equation given as;

C1 × V1 = C2 × V2.

Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.

STEP THREE:

Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.

STEP FOUR:

Using the dilution equation again, Determine the the volume that is needed from 1M SPG.

C1 × V1 = C2 × V2.

V1 = ( 0.1 × 5)/ 1 = 0.5mL.

STEP FIVE:

measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.

STEP SIX:

Now, mix solution X and solution Y together and take the required 5ml

Answer: [tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation when when aqueous solutions of chromium(III) sulfate and calcium nitrate are combined is:

[tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Answer:

Explanation:

The Electronic Configuration of the elements is the arrangement of all electrons of an element in energy levels and sub-levels (orbitals).  

There are 7 energy levels, numbered from 1 to 7, and in which electrons are distributed, logically in order according to their energy level. Electrons with less energy will be spinning at level 1. Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4. These 4 sub-levels are called: s, p, d, f. In the sub-level s there can only be a maximum of 2 electrons, in p there can be a maximum of 6 electrons, in the sub-level d 10 electrons and finally in the sub-level f there can be a maximum of 14 electrons.

In other words, the difference between the sub-levels consists of the number of electrons that it can hold at each level. In each sublevel there are a certain number of orbitals [1 orbital describes the rotation of a maximum of two electrons around the nucleus] that can contain a maximum of 2 electrons each. In this way, the maximum number of electrons that each sublevel admits is: 2 in the s; 6 in the p (2 electrons x 3 orbitals); 10 in the d (2 electrons x 5 orbitals); 14 in the f (2 electrons x 7 orbitals).

Answer:

13.33g/mL is mercury's density

Explanation:

The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of mercury in g/mL:

Grams mercury: 685.0g

Volume = 51.39mL

That means the density of the mercury is:

685.0g / 51.39mL

When NH₃(aq) is added to Cu₂(aq), a precipitate initially forms. Its formula is Cu(NH₃)². The correct option is d.

A chemical formula is a representation of chemical elements and chemical compounds. The chemical letters are used to write the chemical formula. The charges if present is written by charges symbols like plus, minus.

The chemical reaction is

NH₃(aq) + Cu₂(aq) = Cu(NH₃)²

This is called a chemical reaction, which contains reactant on the left side and products on the right side. The precipitate that is formed is copper ammonia whole twice.

Precipitation is the solid crystals' substance that is come out at the surface of the liquid. It is collected in solid form, and it is called a precipitate.

Thus, the correct option is d. Cu(NH₃)².

To learn more about chemical formulas, refer to the link:

https://brainly.com/question/15138610

#SPJ2

Answer:

1. your back

2. false

3. agility

4. hand eye coordination

Explanation:

hope this helps <3

Answer:

1 mole of sodium chloride( NaCl)

=58.4g/mol

1 mole of nitrogen

=14.0g/mol

Answer:

difficult

Explanation:

Answer:

odd

Explanation:

By applying the Nitrogen rule; A molecular ion with odd mass numbers will contain an odd number of a nitrogen atom, however, a molecular ion with an even mass number will contain either an even number of a nitrogen atom or no nitrogen.

So from the given information, the missing word is odd .

Answer:

6 moles of Carbon.

Explanation:

One mole of Carbon is equal to 12 grams of Carbon, so you would divide 72 by 12 and the answer would be 6.

Answer:

the anser is c

Explanation:

no why

anser;

explinaton;

Pretty sure it’s violet

Answer:

c voilet

Explanation:

Answer:

[tex]m_{O_2}=36.3gO_2[/tex]

Explanation:

Hello!

In this case, since the reaction between propane and oxygen is:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Given the 1:5 mole ratio between propane and oxygen, and their molar masses (44.09 g/mol and 32.00 g/mol respectively), we can follow up the shown below stoichiometric setup to compute the required mass of oxygen for the reaction:

[tex]m_{O_2}=10.0gC_3H_8*\frac{1molC_3H_8}{44.09gC_3H_8}*\frac{5molO_2}{1molC_3H_8} *\frac{32.00gO_2}{1molO_2} \\\\m_{O_2}=36.3gO_2[/tex]

Best regards!

Answer:

ummmmm huh?

Explanation:

.......im confused on the question

Answer: 216km

Explanation:

An integer simply refers to a whole number. We should note that fractions and decimals are not integers. Therefore, expressing 2.015×107km as an integer will be:

= 2.015 × 107

= 215.605

= 216

The clay because it has the smallest particles size.

Answer:

Pebbles

Explanation:

The faster a stream flows, the larger the particles it can carry. When the current slows down the largest particles will be deposited first, which in this case are the pebbles. If the stream continues to slow down the sand will be deposited next, followed by the silt and clay. (Clay is only deposited when the water is nearly still.)

Answer:

0.56 g

Explanation:

A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.

Step 1: Given data

Moles of nitrogen gas (n): 0.020 mol

Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

We will use the following expression.

m = n × M

m = 0.020 mol × 28.02 g/mol

m = 0.56 g

Answer:

In this Lewis equation it can be seen how oxygen and hydrogen have a dative union, that is, there is a proton that is temporarily "borrowed"

Explanation:

This molecule is the same as water but with one more hydrogen, that is why the general charge of the molecule is positive

Answer:

[tex]\boxed {\boxed {\sf D. \ 64 \ grams }}[/tex]

Explanation:

Given the moles, we are asked to find the mass of a sample.

We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.

[tex]\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]

Multiply by the given number of moles, which is 2.0

[tex]2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]

The moles of methanol will cancel each other out.

[tex]2.0 \ *\frac{32 \ g \ CH_3OH}{1 }[/tex]

The denominator of 1 can be ignored.

[tex]2.0 * 32 \ g\ CH_3OH[/tex]

Multiply.

[tex]64 \ g \ CH_3OH[/tex]

There are 64 grams of methanol in the sample.

The answer is 64 grams, or:

Answer:

Explanation:

Given that:

2H₂(g) + 2NO(g) → 2H₂O(g) + N₂(g)

Experiment      [H₂] (M)       [NO]   (M)      Initial Rate  (M/s)

1                        0.010          0.025          2.4 × 10⁻⁶

2                       0.0050       0.025          1.2  × 10⁻⁶

3                       0.010          0.0125         0.60 × 10⁻⁶

The general formula for rate law is:

[tex]rate = k[H_2]_x [NO]_y[/tex]

From (1) and (2), it is obvious that the concentration of NO looks constant unlike that of H₂ which has decreased by 1/2. Similarly, the initial rate also reduced by 1/2. Hence, the initial rate is proportional to the concentration of H₂. So, x = 1

Also;

From (1) and (3), it is obvious that the concentration of H₂ looks constant unlike that of NO which has decreased by 1/2. Similarly, the initial rate also reduced by 1/4. Hence, the initial rate is proportional to the concentration of NO. So, y = 2

∴

The overall rate law is: [tex]rate = k[H_2][NO]_2[/tex]

[tex]Order \ of \ reaction = 1 + 2 = 3[/tex]

(b)

From (1)

The rate constant is:

[tex]rate = k[H_2][NO]_2[/tex]

∴

[tex]k = \dfrac{rate}{ [H_2] [NO]^2}[/tex]

[tex]k = \dfrac{2.4 \times 10^{-6} \ M/s}{(0.010 \ M)(0.025 \ M)^2 }[/tex]

k = 0.38 / M².s

(c)

From the rate law, it is pertinent to understand that the slow step in the reaction includes one molecule of H₂ and two molecules of NO, where O atoms serve as an intermediary.

SO;

H₂ + 2NO → N₂ + H₂O + O        slow step

O + H₂  →   H₂O                         fast step

                                                  2H₂ + 2NO → 2H₂O + N₂

Answer:

Oxygen is a pure element. Water, however, is a compound molecule containing oxygen. Water also contains hydrogen, In an H2O molecule, the two hydrogen molecules and the oxygen molecules are chemically bonded together.

Answer:

Water is 1% oxygen and it is a compound

While oxygen is a Pure element that means it forms with only oxygen molecules

Explanation:

Answer:

2 × 10⁻²² g

Explanation:

Step 1: Given data

Atoms of oxygen: 9 atoms

Step 2: Calculate the moles corresponding to 9 atoms of O

We will use Avogadro's number: there are 6.02 × 10²³ atoms of O in 1 mole of atoms of O.

9 atom × 1 mol/6.02 × 10²³ atom = 1 × 10⁻²³ mol

Step 3: Calculate the mass corresponding to 1 × 10⁻²³ moles of O

The molar mass of O is 16.00 g/mol.

1 × 10⁻²³ mol × 16.00 g/mol = 2 × 10⁻²² g

Answer:

Explanation:

We define lattice energy as "the change in internal energy that accompanies the formation of one mole of the solid from its constituent gas phase ions." (Housecroeft and Sharpe, 2012).

Also, lattice energy depends on the size of the ions. In this case, the anion is the same so we consider the relative sizes of the cations. The smaller the size of the cation, the greater the quantitative value of the lattice energy.

Since Ca^2+ is smaller than K^+, the quantitative value for the lattice enthalpy of calcium bromide is larger than the value for the lattice enthalpy of potassium bromide.

Answer:

its has to be AAAAAAAAAA

Answer:

The answer is A

Explanation:

Answer:

Explanation:

In an aqueous solution of potassium sulfate (K₂SO₄), the solute is K₂SO₄ and the solvent is water. The percentage by mass describes the grams of solute there are dissolved per 100 grams of solution. It can be calculated as:

mass percentage = (mass of solute/total mass of solution) x 100%

For example, in an aqueous solution which is 2% by mass of K₂SO₄, there are 2 grams of K₂SO₄ per 100 g of solution.