Based on the information provided, the proportion of light bulbs that last more than 500 hours is 36.61%.
How to find the proportion in this case?A proportion refers to the relationship of one variable or element to another. In this case, we need to know the proportion of light bulbs that last more out of the total light bulbs selected. The process is shown below:
Light bulbs that lasted/ total selected
164/448 = 0.3661 x 100 = 36.61%.
Based on this, the point estimate of the proportion of all light bulbs that last more than 500 hours is approximately 0.3661 or 36.61%.
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A die is tossed three times. What is probability that a 6 will show in the upward face at least once?
Answer:
1/216.
Explanation:
The probability of a 6 appearing on any single roll of a fair die is 1/6. Since the rolls are independent, the probability of a 6 appearing on all three rolls is (1/6) x (1/6) x (1/6) = 1/216. Therefore, the probability that a 6 will not appear in any of the three rolls is 1 - 1/216 = 215/216. Finally, the probability that a 6 will appear at least once in the three rolls is 1 - 215/216 = 1/216. Thus, the probability of a 6 appearing in the upward face at least once is 1/216.