(4z+3)+(4z+3)+(4z+3)+(4z+3) solve pls or simplify

Answers

Answer 1

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{16z + 12}}}}}[/tex]

Step-by-step explanation:

[tex] \sf{(4z + 3) + (4z + 3) + (4z + 3) + (4z + 3)}[/tex]

Remove the unnecessary parentheses

[tex] \sf{4z + 3 + 4z + 3 + 4z + 3 + 4z + 3}[/tex]

Collect like terms

Only the coefficients of like terms can be added or subtracted

[tex] \sf{4z + 4z + 4z + 4z + 3 + 3 + 3 + 3}[/tex]

[tex] \sf{16z + 3 + 3 + 3 + 3}[/tex]

Add the numbers

[tex] \sf{16z + 12}[/tex]

Hope I helped!

Best regards! :D


Related Questions

You are going to buy some folders to file
your orders. After doing research, you find
that the most cost-effective price is $7.40
per
box of 100 folders. You have $15 to
spend. How many 100 count boxes can
you buy?

Answers

Two because two boxes would be $14.80 so you wouldn’t have enough for three

State whether the given pairs are complementary or supplementary
1) 75 °, 105 °
2) 62 ° , 28 °
3) 132 ° , 48 °
4) 76 ° , 14 °
5) 118 ° , 62 °
6) 19 ° , 71 °

Answers

I need help on my school work can you help me.

What is 0.63% as a decimal

Answers

Answer:

0.0063

Hope this helps

Plz mark brainliest

Answer:

0.0063

Step-by-step explanation:

move the decimal 2 places to the left

Show work for f(4) = 3x + 2

Answers

F(4)=3x+2
=3(4)+2
F(4)=14

The solution of the given function will be F(4)=14

Since we know that Function is a type of relation, or rule, that maps one input to specific single output.

In mathematics, it is an expression, rule, or law that describes the relationship between one variable (the independent variable) and another variable . In physical sciences, functions are indispensable for formulating physical relationships.

We have been given a function as;

F(x)=3x+2

F(4)=3x+2

WE have to substitute the value of x as 4 then we get;

F(4)=3(4)+2

F(4)=14

Therefore, the value of the given function will be as 14.

Learn more about function here:

https://brainly.com/question/2253924

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-1
0
1
2
3
y = g(x) Average Ratio of
Rate of consecutive
Change outputs
-4.5
-3
-1.5
0
1.5
Determine whether the function is linear, exponential, or neither

Answers

Answer:

  linear

Step-by-step explanation:

First differences of the y-values for the consecutive x-values are ...

  -3 -(-4.5) = 1.5

  -1.5 -(-3) = 1.5

  0 -(-1.5) = 1.5

  1.5 -0 = 1.5

The first differences are constant, so the function is linear.

__

Since we know the function is linear, there's no real point in computing the ratios of successive outputs. In any event, we know it is not constant. The ratio with 0 as a numerator will be 0; the ratio with 0 as a denominator will be undefined.

Polly bought a cracker for $7 and then bought a parrot for $2. By how much did Polly's account change after her transactions?

Answers

Answer:

[tex]Changes = -\$9[/tex]

Step-by-step explanation:

Given

[tex]Cracker = \$7[/tex]

[tex]Parrot = \$2[/tex]

Required

Determine the changes in the account

First, we need to determine the total amount spent;

[tex]Total = Cracker + Parrot[/tex]

[tex]Total = \$7 + \$2[/tex]

[tex]Total = \$9[/tex]

Hence, the changes in her account is a debit of $9 i.e. -$9

A school authority claims that the average height of students is 178 cm. A researcher has taken a well-designed survey and his sample mean is 177.5 cm and the sample standard deviation is 2. The sample size is 25. Which statement is correct?

a) The result of the survey is statistically significant.

b) The sample mean and population mean is the same.

c) The result of the survey is biased.

d) The difference exists due to chance since the test statistic is small

Answers

Answer:

d) The difference exists due to chance since the test statistic is small

Step-by-step explanation:

From the given information:

Population mean = 178 cm

the sample mean = 177.5 cm

the standard deviation = 2

the sample size = 25

The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis:

[tex]H_o: \mu = 178[/tex]

Alternative hypothesis:

[tex]H_1: \mu \neq 178[/tex]

The t-test statistics is determined by using the formula:

[tex]t = \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}}[/tex]

[tex]t = \dfrac{177.5 - 178}{\dfrac{2}{\sqrt{25}}}[/tex]

[tex]t = \dfrac{-0.5}{\dfrac{2}{5}}}[/tex]

[tex]\mathbf{t= -1.25}[/tex]

Degree of freedom df = n- 1

Degree of freedom df = 25 - 1

Degree of freedom df = 24

At the level of significance ∝ = 0.05, the critical value  = 2.064

Decision rule: To reject the null hypothesis if the test statistics  is greater than the critical value at 0.05 level of significance

Conclusion: We fail to reject the null hypothesis since the test statistics is lesser than the critical value and we conclude that  the difference exists due to chance since the test statistic is small

Answer:

d. The difference exists due to chance since the test statistic is small

Step-by-step explanation:

With a very small sample size of 25, a difference of 0.5 cm is most likely due to chance.

HELP HELP I NEED HELP PLEASE

Answers

Answer: 76 degrees

Step-by-step explanation:

m<abc = m<1 + m<2

4x+12=(2x-7)+(3x-4)

x=23

180=4x+12+m<3

m<3=76

electricity in a dash power station​

Answers

Answer:

Most of U.S. electricity generation is from electric power plants that use a turbine or similar machine to drive electricity generators. A turbine converts the potential and kinetic energy of a moving fluid (liquid or gas) to mechanical energy.

Step-by-step explanation:

pls mark brainliest

Answer:

most power stations make use of turbines which drives power generators. A turbine converts potential and kinetic of moving fluid to mechanical energy.

A standard working day is 8 hours, if you were to work 125% of a normal day, how many total hours would you work?

Answers

Answer:

10 hours

Step-by-step explanation:

It is given that,

Standard working day is 8 hours

If you were to work 125% of a normal day, then it means that,

[tex]125\%\ \text{of}\ 8\ \text{hours}\\\\=\dfrac{125}{100}\times 8\\\\=10\ \text{hours}[/tex]

Hence, you will work for 10 hours.

2. A motorcycle rider moving with initial velocity of 15.0 m/s uniformly accelerates to a speed of 30.0 m/s in a.

distance of 40.0 m. (a) What is the acceleration? (b) How long does this take

ht

CAUTA

hindi tale to set to this height by How

Answers

Given :

Initial velocity , u = 15 m/s .

Final velocity , v = 30 m/s .

Distance travelled , d = 40 m .

Also , this body is uniformly accelerating .

To Find :

(a) What is the acceleration .

(b) How long does this take .

Solution :

Let , acceleration be a .

By , equation of motion :

[tex]v^2-u^2=2ad\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{30^2-15^2}{2\times 40}\\\\a=8.44\ m/s^2[/tex]

Also , by equation :

[tex]v=u+at\\\\t=\dfrac{v-u}{a}\\\\t=\dfrac{30-15}{8.44}\ s\\\\t=1.78\ s[/tex]

Hence , this is the required solution .

A number is multiplied by three, then five is added to get 19.

Answers

Answer:

5

Step-by-step explanation:

The problem is:

3 x 5 = 15

15 + 4 = 19

Please help with this

Answers

The answer will be C
I believe the answer is C

8(3-z)=4z please help​

Answers

Answer:

z = 2

Step-by-step explanation:

Answer:

z=2

Step-by-step explanation:

8(3-z)=4z

multiply 8 by 3 and 8 by -z

24-8z=4z

subtract 24 from both sides

-8z=4z-24

subtract 4z from both sides

-12z=-24

divide both sides by -12

z=2

Find the distance between the points.
(-5,-1), (0,5)

Answers

Answer:

A. √61

Step-by-step explanation:

The ages of​ Edna, Ellie, and Elsa are consecutive integers. The sum of their ages is 120 .

Answers

Answer:

The answer is 39, 40, and 41

Step-by-step explanation:

You would use the equation x+x+1+x+2=120 to substitute for the ages. x would represent the youngest, then you would add a year to get the middle child (since it is consecutive numbers) then you would add 2 to get the oldest.  And when you get the answer to the equation (which is 39) that is only the age of the youngest (since you solve only for x and that represents the youngest child's age), so you have to add 1 and 2 to the answer to get the ages of the other two.

Hope this helped :)

Answer:

Edna = 39 years

Ellie = 40 years

Elsa = 41 years

Step-by-step explanation:

Edna = n

Ellie = n + 1

Elsa = Ellie + 1 = (n + 1) + 1 = n + 2

Edna + Ellie + Elsa = 120

replace

n + (n + 1) + (n + 2) = 120

3n + 3 = 120

3n = 120 - 3

3n = 117

n = 117 : 3

n = 39

Edna = n = 39 years

Ellie = n + 1 = 39 + 1 = 40 years

Elsa = n + 2 = 39 + 2 = 41 years

Which equation represents the data shown in the table below?
x
y
2
5
moll
6
7.
5
8
O A. y = 2x
B. y = x + 3
O C. y = 3x
D. y = x + 1

Answers

Answer:

the answer will be y=2x

Step-by-step explanation:

1/2 ( 4h +8 ) =3h + 6
Solve pls

Answers

Answer:

1/2 ( 4h + 8 ) = 3h + 6

2h + 4 = 3h + 6

2h - 3h = 6 - 4

- h = 2

h = -2

I hope this helped. Let me know if it did. Can you mark me brainliest? Please.

Find two consecutive whole numbers that 141 lies between

Answers

Answer:

140 and 142?

Step-by-step explanation:

Solve the LP problem. If no optimal solution exists, indicate whether the feasible region is empty or the objective function is unbounded.

Maximize p=x+ysubject to

x+3y≤4

3x+y≤4

x≤0

y≤0

Answers

Answer:

P = 4

Step-by-step explanation:

The LP is:

Maximize p = x+y

x+3y≤4

3x+y≤4

x ≥ 0

y ≥ 0

Solving graphically using the geogebra graphing calculator which is attached, the points are A(0, 4), B(0, 1.33), C(1.33, 0), D(4, 0) and E(1, 1)

The maximum objective is:

For point A(0, 4):  Maximize p = x + y = 0 + 4 = 4

For point B(0, 1.33):  Maximize p = x + y = 0 + 1.33 = 1.33

For point C(1.33, 0):  Maximize p = x + y = 1.33 + 0 = 1.33

For point D(4, 0):  Maximize p = x + y = 4 + 0 = 4

For point E(1, 1):  Maximize p = x + y = 1 + 1 = 2

Hence, the maximum point is at A(0, 4) which gives P = 4

Solve the following inequality:

4x^2-25<0

I will give the person who answers this correctly brainiest.

Answers

Answer:

−2.5<x<2.5

Step-by-step explanation:

Let's find the critical points of the inequality.

4x2−25=0

4x2−25+25=0+25(Add 25 to both sides)

4x2=25

4x24=25/4(Divide both sides by 4)

x2=25/4

x=±√254(Take square root)

x=2.5,−2.5

Check intervals in between critical points. (Test values in the intervals to see if they work.)

x<−2.5(Doesn't work in original inequality)

−2.5<x<2.5(Works in original inequality)

x>2.5(Doesn't work in original inequality)

The model represents an equation. What value of X makes the equation true?
Answers are: -15
-3
15
3
Please help.

Answers

Answer:

D. 3

Step-by-step explanation:

Assuming the model represents an equation, the following can be deduced:

On the left side of the equation, the model shows we have 3 "x's", and 6 "1's". Let this represent:

3x + 6

On the right side of the equation, we have 2 "x's" and 9 "1's". Let this represent:

2x + 9.

The model would represent the equation below:

[tex] 3x + 6 = 2x + 9 [/tex]

Solve for x

[tex] 3x + 6 - 2x = 2x + 9 - 2x [/tex] (Subtracting 2x from both sides of the equation)

[tex] x + 6 = 9 [/tex]

[tex] x + 6 - 6 = 9 - 6 [/tex] (subtracting 6 from both sides of the equation)

[tex] x = 3 [/tex]

The janitor found that it was leaking at a rate of 23 fl oz per hour . How fast was the pipe leaking in gallons per day ?

Answers

Answer:

4.3 gallons per day

Step-by-step explanation:

23 fl oz converted to gallons is 0.179688

0.179688 x 24 = 4.312512 and i rounded it to the nearest tenth

When the system is executed, the system crashes with probability 0.05 if only Module A fails. The system crashes with probability 0.12 if only Module B fails. The system crashes with probability 0.60 if both Module A and Module B fail. The system crashes with probability 0.01 if neither fails. (a) When the system is executed, what is the probability the system will crash

Answers

Answer:

P (system will crash) = 0.101528

P(A and B jails / System crash) = 0.5390

Step-by-step explanation:

The complete question is as stated below

"Suppose a system has two modules, A and B , that function independently. Module A fails with probability 0.24 and Module B fails with probability 0.38 ,when the system is executed.  When the system is executed, the system crashes with probability 0.05 if only Module A fails. The system crashes with probability 0.12 if only Module B fails. The system crashes with probability 0.60 if both Module A and Module B fail. The system crashes with probability 0.01 if neither fails.

(a) When the system is executed, what is the probability the system will crash?

(b) If the system crashes, what is the probability that both modules A and B crashed?"

Solution

P(A fails) = 0.24

P(B fails) = 0.38

P(A ∩ B) = P (A) * P (B) = 0.24 * 0.38 = 0.0912

P(only A fails) = P(A) - P(A ∩ B) =0.24 - 0.24*0.38 = 0.1488

P(only A fails) =P(B) - P(B ∩ A) = 0.38 - 0.24*0.38 = 0.2888

P(Both fails) = P(A) * P(B) = 0.24*0.38 = 0.0912

P(Neither fails) = P(A) * P(B) =1-(0.24+0.38-0.0912) = 0.4712

P(Add to 1)

a) P (system will crash) = 0.1488*0.05+0.2888*0.12+0.0912*0.6+0.4712*0.01 P (system will crash) = 0.101528

b) P(A and B jails / System crash) = 0.0912*0.6 / 0.101528

P(A and B jails / System crash) = 0.5390

The formula=A+2lh+2wh gives surface area a. Of a rectangler solid with length, width, and height, L,W, and H, respectively solve the formula for L


Answers

Answer:

[tex]l= \frac{A}{2h} -w[/tex]

Step-by-step explanation:

The question is not correct (particularly the expression for the area)

 A=2lh+2wh

Now we are expected to solve for l, that is we are going to make l subject of the formula, we have

let us take the second term on the RHS to the LHS

[tex]A-2wh= 2lh[/tex]

we can now divide both sides by 2h we have

[tex]\frac{A-2wh}{2h} = l\\\\l=\frac{A}{2h} -\frac{2wh}{2h} \\\\l= \frac{A}{2h} -w[/tex]

hence the expression for the length is  [tex]l= \frac{A}{2h} -w[/tex]

The perimeter of a rectangle is 92 cm. If the length is 16 cm, how wide is the rectangle?

Answers

Answer:

30cm

Step-by-step explanation:

2w+2L=Perimeter of rectangle

2w+2*16=92

2w+32=92

2w=92-32

2w=60

w=30

check : 16 +16 +30 +30 =92cm

A cheetah can run at top speed for only about 20 seconds

Answers

im pretty sure this is false they can run fro 30 seconds not 20

Answer:

A cheetah can run at top speed for only about 20 seconds. If an antelope is too far away for a cheetah to catch it in 20 seconds, the antelope is probably safe. Your friend claims an antelope running 60 feet per second will not be safe if the cheetah running at 90 feet per second is 650 feet behind it.

Please leave a review and feel free to give me brainiest.

Solve for x:
2/3+1/3x=2x

Answers

2/3+1/3x=2x
2+1x=6x
x-6x=-2
-5x=-2
x=2/5

A car travel 300 miles on 10 gallons of gas,whats the ratio

Answers

Answer:

30/1

Step-by-step explanation:

300 miles per 10 gallons or 300/10.

simplify by dividing both numbers by the greatest common denominator. which in this case is 10. so divide 300 and 10 by ten and you get 30/1. it can't be simplified any more so thats the final simplified ratio.

If C is the part of the circle (x/5)^2 + (y/5)^2 = 1 in the first quadrant, find the following line integral with respect to arc length. integral_c (8x - 3y)ds = _______.

Answers

Convert to polar coordinates, in which the circle's equation becomes

[tex]\left(\dfrac x5\right)^2+\left(\dfrac y5\right)^2=1\implies x^2+y^2=5^2\implies r^2=5^2\implies r=5[/tex]

where [tex]x=5\cos\theta[/tex] and [tex]y=5\sin\theta[/tex], and we get the part of the circle in the first quadrant with [tex]0\le \theta\le\frac\pi2[/tex].

So the integral is

[tex]\displaystyle\int_C(8x-3y)\,\mathrm ds=\int_0^{\frac\pi2}(8x(\theta)-3y(\theta))\sqrt{\left(\dfrac{\mathrm dx}{\mathrm d\theta}\right)^2+\left(\dfrac{\mathrm dy}{\mathrm d\theta}\right)^2}\,\mathrm d\theta[/tex]

[tex]=\displaystyle\int_0^{\frac\pi2}(40\cos\theta-15\sin\theta)\sqrt{25\cos^2\theta+25\sin^2\theta}\,\mathrm d\theta[/tex]

[tex]=\displaystyle25\int_0^{\frac\pi2}(8\cos\theta-3\sin\theta)\,\mathrm d\theta[/tex]

[tex]=25(8\sin\theta+3\cos\theta)\bigg|_0^{\frac\pi2}=200-75=\boxed{125}[/tex]

Line integral involves integrating a function along a curve

The value of the line integral is 125

The equation is given as:

[tex]\mathbf{(\frac{x}{5})^2 + (\frac{y}{5})^2 = 1}[/tex]

Expand

[tex]\mathbf{\frac{x^2}{5^2} + \frac{y^2}{5^2} = 1}[/tex]

Multiply through by 5^2

[tex]\mathbf{x^2 + y^2 = 5^2}[/tex]

The equation of a circle is represented as:

[tex]\mathbf{(x - a)^2 + (y - b)^2 = r^2}[/tex]

So, by comparison

[tex]\mathbf{r^2 = 5^2}[/tex]

[tex]\mathbf{r = 5}[/tex]

Where:

[tex]\mathbf{x = rcos\theta}[/tex]

[tex]\mathbf{y = rsin\theta}[/tex]

So, we have:

[tex]\mathbf{\int_c (8x - 3y)ds}[/tex]

Because it is in the first quadrant (i.e. 0 to pi/2), the integrand becomes

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_0 (8x - 3y)rd\theta}[/tex]

Convert to polar forms

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_0 (8x - 3y)\sqrt{x^2 + y^2}d\theta}[/tex]

Substitute [tex]\mathbf{x = rcos\theta}[/tex] and [tex]\mathbf{y = rsin\theta}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_c (8rcos(\theta) - 3rsin(\theta))\sqrt{(rcos(\theta))^2 + ( rsin(\theta))^2}d\theta}[/tex]

Substitute 5 for r

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_c (40cos(\theta) - 15sin(\theta))\sqrt{25cos^2\theta + 25sin^2\theta}\ d\theta}[/tex]

Factor out 5

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_c 5(8cos(\theta) - 3sin(\theta))\sqrt{25cos^2\theta + 25sin^2\theta}\ d\theta}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_c 5(8cos(\theta) - 3sin(\theta))\sqrt{25(cos^2\theta + sin^2\theta)}\ d\theta}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_c 5(8cos(\theta) - 3sin(\theta))5\sqrt{(cos^2\theta + sin^2\theta)}\ d\theta}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds = \int\limits^{\frac{\pi}{2}}_c 25(8cos(\theta) - 3sin(\theta))\sqrt{(cos^2\theta + sin^2\theta)}\ d\theta}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds =25 \int\limits^{\frac{\pi}{2}}_c (8cos(\theta) - 3sin(\theta))\sqrt{(cos^2\theta + sin^2\theta)}\ d\theta}[/tex]

In trigonometry

[tex]\mathbf{cos^2\theta + sin^2\theta = 1}[/tex]

So, we have:

[tex]\mathbf{\int_c (8x - 3y)ds =25 \int\limits^{\frac{\pi}{2}}_c (8cos(\theta) - 3sin(\theta))\sqrt{1}\ d\theta}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds =25 \int\limits^{\frac{\pi}{2}}_0 (8cos(\theta) - 3sin(\theta))\ d\theta}[/tex]

Integrate

[tex]\mathbf{\int_c (8x - 3y)ds =25 \times [ (8sin(\theta) + 3cos(\theta))\ } ]|\limits^{\frac{\pi}{2}}_0}[/tex]

Expand

[tex]\mathbf{\int_c (8x - 3y)ds =25 \times ([ 8sin(\frac{\pi}{2}) + 3cos(\frac{\pi}{2})] - ([ (8sin(0) + 3cos(0)])}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds =25 \times ([ 8\times 1 + 3\times 0)] - ([ (8\times 0 + 3\times 1])}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds =25 \times ([ 8] - [ 3])}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds =25 \times 5}[/tex]

[tex]\mathbf{\int_c (8x - 3y)ds =125}[/tex]

Hence, the value of the line integral is 125

Read more about line integrals at:

https://brainly.com/question/16571667

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