53% of all the town's residents own a dog and 59% own a cat. Of the dog owners 44% also own a cat. If a town resident is chosen at random find: (round to 4 decimal places where possible)

a. P(Own a Dog) =
.53
Correct

b. P(Own a Cat) =
.59
Correct

c. P(Own a Cat and a Dog) =
.44
Incorrect

d. P(Own a Dog GIVEN Own a Cat) =

53% of all the town's residents own a dog and 59% own a cat. Of the dog owners 44% also own a cat. If a town resident is chosen at random find: (round to 4 decimal places where possible)

a. P(Own a Dog) =
.53
Correct

b. P(Own a Cat) =
.59
Correct

c. P(Own a Cat and a Dog) =
.44
Incorrect

d. P(Own a Dog GIVEN Own a Cat) =

Answers

Answer 1

The probability that the people selected Own a Cat and a Dog would be 0.44.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events.

The probability of all the events occurring need to be 1.

We have been given that 53% of all the town's residents own a dog and 59% own a cat. and the dog owners 44% also own a cat.

If a town resident is chosen at random then, we get;

a. P(Own a Dog) = 0.53

59% own a cat

b. P(Own a Cat) = 0.59

c. P(Own a Cat and a Dog) = 0.44

And the dog owners 44% also own a cat.

d. P(Own a Dog GIVEN Own a Cat) = 0.39

Hence, The probability that the people selected Own a Dog GIVEN Own a Cat would be 0.44.

The probability that the people selected Own a Cat and a Dog would be 0.44.

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Related Questions

Find the domain PLEASE HELP

Answers

The domain of this function is all the real numbers except - 7 / 3 and 23 / 3.

What is the domain of a function?

In accordance with function theory, the domain of a function is a set of x-values such that y-values exist. Herein we find that the given function is a rational function whose denominator includes an absolute value function. The numerator is a linear equation.

Therefore, the domain of the function is all real numbers except those x-values such that denominator is equal to zero. We need to solve the following expression in two cases:

|3 · x - 15| = 8

For x ≥ 5:

3 · x - 15 = 8

3 · x = 23

x = 23 / 3

For x < 5:

- 3 · x + 15 = 8

- 3 · x = - 7

x = - 7 / 3

Then, the domain of this function is all the real numbers except - 7 / 3 and 23 / 3.

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Maria's monthly premium for her car insurance is $ 115.99 $ 115.99 , and her monthly rent is $899.59 $ 899.59 . If the premium and rent are automatically deducted from Maria's bank account every month, how much will be deducted from her account in a year? Enter your answer in the box. Enter your answer using “.” for a decimal point.

Answers

Answer: 12,186.96

Step-by-step explanation:

True or False: If x > y, then |x| < |y|

Answers

Answer:

False

Step-by-step explanation:

This applies perfectly when x and y are negative.

What if both x and y are positive??

x=4, y=3.

4>3 which is true

but |4|<|3| = 4<3 ==> not true.

Hence, the answer is false

I. Resuelve el siguiente sistema por el método de eliminación
(7x - 3y = 27
5x + y = 35

Answers

[tex]5x+y=35 \implies 15x+3y=105 \\ \\ \implies (15x+3y)+(7x-3y)=105+27 \\ \\ 22x=132 \\ \\ \boxed{x=6} \implies 7(6)-3y=27 \\ \\ -3y=-15 \\ \\ \boxed{y=5}[/tex]

When the width of the map on his phone represents an actual distance of 400 feet, the length of Peninsula Park on his phone is 1.2 inches. Joshua changes the zoom on the map so that the width of the map on his phone represents an actual distance of 300 feet instead. What is the length of Peninsula park on his phone, in inches, on the new map?

Answers

Answer:

.9 inches

Step-by-step explanation:

Set up and solve this proportion:

[tex] \frac{1.2}{400} = \frac{x}{300} [/tex]

[tex]400x = 360[/tex]

[tex]x = .9[/tex]

Use all the non-zero digits (below), but only once each, to make any set of prime numbers:
1 2 3 4 5 6 7 8 9
What is the sum of this set of prime numbers?
Can you get a smaller sum with a different set of primes? (What is the smallest possible sum?)​

Answers

Answer:

Hello,

Answer 207

Step-by-step explanation:

[5, 29, 47, 61, 83, 225]

[5, 29, 41, 67, 83, 225]

[5, 23, 47, 61, 89, 225]

[5, 23, 41, 67, 89, 225]

[2, 5, 7, 43, 61, 89, 207]

[2, 3, 5, 47, 61, 89, 207]

[2, 3, 5, 41, 67, 89, 207]

import sys

#-------------------------------------------------------

def see(txt,arr):

   print (txt,"=",end =" ")

   for i in range(1,10 ):

       if arr[i]:

           print (i,end=" ")

   print ()

#-------------------------------------------------------

def libre(p):

   if p==0:

       return True

   if p<10:

       a=p

       if not(used[a]):

           return True

   else:

       a=p//10

       b=p%10

       if not(used[a]) and not(used[b] ):

           return True

   return False

#-------------------------------------------------------

def store(p):

# on ne stock pas 0

   global used

   #print ("in store ",p)

   if p==0:

       return

   if p<10:

       used[p]=True

   else:

       a=p//10

       b=p%10

       used[a]=True

       used[b]=True

   return            

def isSol():

   global mini,k,mini_set,all_mini_set

   for i in range(1,10):

       if not used[i]:

           return False

   s=i_1+i_2+i_3+i_4+i_5+i_6+i_7+i_8+i_9

   if s <= mini[0]:

       if s < mini[0]:

           k=k+1

           

       mini[0]=s

       mini[1]=i_1

       mini[2]=i_2

       mini[3]=i_3

       mini[4]=i_4

       mini[5]=i_5

       mini[6]=i_6

       mini[7]=i_7

       mini[8]=i_8

       mini[9]=i_9

       

       a_set=sorted(set([i for i in mini if i >0] ))

       if (a_set not in all_mini_set):

           mini_set=a_set.copy()

           all_mini_set.append(a_set)

           print (a_set)

       #print (mini,end="")

   

       """

       see("used ",used)

       see("sav_9",sav_9)

       see("sav_8",sav_8)

       see("sav_7",sav_7)

       see("sav_6",sav_6)

       see("sav_5",sav_5)

       see("sav_4",sav_4)

       see("sav_3",sav_3)

       see("sav_2",sav_2)

       see("sav_1",sav_1)

       """

       #if k>2:

       #    sys.exit(0)

   return True

#-------------------------------------------------------

#╚ 0 : ne pas utiliser

jeu=[

    [],

    [0,13, 17, 19, 31, 41, 61, 71],

    [0,2,23,29],

    [0,3,13,23,31,37,43,53,73,83],

    [0,41,43,47],

    [0,5,53,59],

    [0,61,67],

    [0,7,17,37,47,67,71,73,79,97],

    [0,83,89],

    [0,19,29,59,79,89,97]

    ]

print ("-------------------------------------------")

for i in range(10):

   print (jeu[i])

print ("-------------------------------------------")

mini=[1000]+[0 for i in range(1,10) ]

mini_set={}    

all_mini_set=[]

used=[False for i in range(10 )]

sav_1=used.copy()

k=0

for i_1 in jeu[1]:

   used=sav_1.copy()

   if libre(i_1):

       store(i_1)

       sav_2=used.copy()

     

       for i_2 in jeu[2]:

           used=sav_2.copy()

           if libre(i_2):

               store(i_2)

               sav_3=used.copy()

               for i_3 in jeu[3]:

                   used=sav_3.copy()

                   if libre(i_3):

                       store(i_3)

                       sav_4=used.copy()

                       for i_4 in jeu[4]:

                           used=sav_4.copy()

                           if libre(i_4):

                               store(i_4)

                               sav_5=used.copy()

                               for i_5 in jeu[5]:

                                   used=sav_5.copy()

                                   if libre(i_5):

                                       store(i_5)

                                       sav_6=used.copy()

                                       for i_6 in jeu[6]:

                                           used=sav_6.copy()

                                           if libre(i_6):

                                               store(i_6)

                                               sav_7=used.copy()

                                               for i_7 in jeu[7]:

                                                   used=sav_7.copy()

                                                   if libre(i_7):

                                                       store(i_7)

                                                       sav_8=used.copy()

                                                       for i_8 in jeu[8]:

                                                           used=sav_8.copy()

                                                           if libre(i_8):

                                                               store(i_8)

                                                               sav_9=used.copy()

                                                               for i_9 in jeu[9]:

                                                                   used=sav_9.copy()

                                                                   if libre(i_9):

                                                                       store(i_9)

                                                                       isSol()

                                                               used=sav_9.copy()

                                                                       

Only if you are sure, please :')

Answers

Answer:

Option D) 6.8 × 10⁻²

Answer:

D

Step-by-step explanation:

Rosa has 3 3/5 pounds of dough. She uses 3/4 of a pound for one large roll. How many large rolls could be made from rosa's dough

Answers

The number of large rolls that could be made from Rosa's dough is 4 numbers.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

Let x represent the number of large rolls that can be made from Rosa's dough, hence:

(3/4)x = 3 3/5

(3/4)x = 18/5

x = 4.8

The number of large rolls that could be made from Rosa's dough is 4 numbers.

The inequality that shows the number of shirts that Lisa buys is given as 15x + 35 ≤ 137

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Suppose that a code (similar to a postal code) is of the form LDL DLD, where 'L' is an uppercase letter from A to N (i.e., 14 possible letters) and 'D' is a digit from 0 to 4. Suppose that such a code is randomly generated.

Find the probability that the code either starts with an 'A' or ends with an even digit (note that 0 is even).

Answers

Using the Fundamental Counting Theorem, there is a 0.7143 = 71.43% probability that the code either starts with an 'A' or ends with an even digit.

What is the Fundamental Counting Theorem?

It is a theorem that states that if there are n things, each with [tex]n_1, n_2, \cdots, n_n[/tex] ways to be done, each thing independent of the other, the number of ways they can be done is:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

In this problem, we have that the code has:

3 letters, each with 14 possible outcomes.3 digits, each with 5 possible outcomes.

Hence the number of codes is:

N = 14 x 5 x 14 x 5 x 14 x 5 = 343,000.

The number of codes starting with an A is:

Na = 5 x 14 x 5 x 14 x 5 = 24,500.

The number of codes ending with an even digit(0, 2 or 4) is:

Ne = 14 x 5 x 14 x 5 x 14 x 3 = 205,800.

The number of codes starting with an A and ending with an even digit is:

Nae = 5 x 14 x 5 x 14 x 3 = 14,700.

The number of desired outcomes is:

24500 + 205800 + 14700 = 245,000.

Hence the probability is:

245,000/343,000 = 0.7143.

0.7143 = 71.43% probability that the code either starts with an 'A' or ends with an even digit.

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Find the unit rate.
1¹/2 =
4
[?]
1

Answers

Answer:

[tex]\frac{12}{4} = \frac{3}{1}[/tex]

Step-by-step explanation:

[tex]\frac{12\div4}{4\div4}=\frac{3}{1}[/tex]

Hope this helps!

Answer:

12 = 3

4      1

Step-by-step explanation:

hope the helps

Aubrey has 64 m of fencingEli has 44 m of fencing to build a four-sided fence around a rectangular plot of land. The area of the land is 120 square meters. Solve for the dimensions (length and width) of the field. to build a four-sided fence around a rectangular plot of land. The area of the land is 255 square meters. Solve for the dimensions (length and width) of the field.

Answers

The dimensions of the rectangular field with area 120 square meters is 10 meters by 12 meters.

The measurement that expresses the size of a region on a plane or curved surface is called area. Surface area refers to the area of an open surface or the boundary of a three-dimensional object, whereas the area of a plane region or plane area refers to the area of a form or planar lamina.

Given perimeter of the rectangular plot is 44 meters.

let the length is x , and width = y

Therefore perimeter = 2 (x + y)

or, 2 (x + y) = 44

or, x + y = 22

or, y = 22 - x

Now the area of the field is given as 120 square meters.

Area of the fields in terms of x is given by:

x ( 22 - x ) = 22 x - x²

Therefore  22 x - x² = 120

or,   x² -22x +120 = 0

or,  x² - 10x - 12x + 120 = 0

or, x (x -10) -12(x-10)=0

or, (x-10)(x-12) = 0

Now either the value of x is 10m or the value of x is 12m

Therefore the dimensions of the rectangular field is 10 meters by 12 meters.

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The height of a ball thrown in the air can be described by a parabola. After 3
seconds, the ball reaches the maximum height of 42 feet. If the ball was originally
thrown from a height of 6 feet, find an equation for the height, h(t), of the ball after t
seconds.

Answers

Answer:In his equation height is given by h(t) and t represents time. The shape of this equation is that of a downward facing parabola because the coefficient of the first term is negative. Therefore, the maximum height is found by determining the vertex of the parabola which is given by b/2a or 50/(16*2). Thus after, 1.5625 seconds the ball reaches it maximum height of 44 feet (plug 1.5625 into formula.)

Notice that the formula has a constant of 5 in it meaning that the ball was throw up at a 5 foot starting position above the ground. Thus, for the ball to hit the ground h(t) = -5. So, what is the value of t that gives that value? Here we just use the quadratic formula and find that t = 3.31 seconds. That makes sense doesn't it? 2*1.5625 would get the ball back to the starting position ( 3.125 sec) and the ball needs another .185 sec to fall the last 5 feet. What speed is that in MPH? That would be 5/.185*(3600/5280) = 18.4 MPH. That is a lot slower than a 95 MPH fast ball.

Step-by-step explanation:

Multiply the numbers.

Answers

Answer:

[tex] \: \: \: \: \: { \rm{2 \: \: \: 3 \: \: \: 4}} \\ { \underline{ \times \: \: 0. \: \: 3 \: \: 5}} \\ { \rm{ 1 \: \: 1 \: \: 7\: \: 0}} \\ { \underline{ + 7\: \: 0\: \: 2 \: \: 0 }} \\ { \underline{ \: \boxed{ 8\: \: 1 \: .\: \: 9 \: \: 0}}}[/tex]

Answer: 81.9

If the price of gas was on average $3.20 per gallon, and this was $1.43 cheaper than a year before, what is the percent of decrease in price? (Round to the nearest percent.)​

Answers

Based on the current price of gas per gallon, and the fact that it was cheaper the year before, the percent decrease in price is 31%

How to find the percentage decrease?

First, find the price of gas last year:

=Current price of gas + Decrease in price

= 3.20 + 1.43

= $4.63

The percent of decrease in price can be found by the formula:

= Change in gas price / Price of gas last year x 100%

= 1.43 / 4.63 x 100%

= 0.30885529157667386609071274298056 x 100%

= 31%

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Let f(x) = [tex]3x\sqrt{2-4x}[/tex].

Find the equation of line tangent to the graph of f at x = -2.


Tangent line: y = ?

Answers

the linear equation tangent at x = -2 is:

y = 123.33*x + 226.74

How to find the equation of the tangent line?

To get the slope of the line we need to evaluate the first derivative in x = -2, we get:

f'(x) = 3√(2 - 4x) + (-12/2)*3x*(2 - 4x)^(-1/2)

Evaluating in x = -2 we get:

f'(-2) = 3√(2 - 4*-2) + (-12/2)*3*-2*(2 - 4*-2)^(-1/2) = 123.33

Then the line is something like:

y = 123.33*x + b

And the line must pass through:

f(-2) = 3*(-2)*√(2 - 4*(-2)) = -18.97

So the line must pass through the point (-2,  -18.97)

Replacing that in the linear equation:

-18.97 = 123.33*2 + b

-19.92 + 123.33*2 = b = 226.74

Then we conclude that the linear equation tangent at x = -2 is:

y = 123.33*x + 226.74

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-29/36 - 3/4 equals to what?

Answers

-29 3 -29 3•9 -29 - 27 -56 -14
—— - — = —- - —— = ————- = -— = -—
36 4 36 4•9 36 36 9

Help me am I correct?

Answers

Answer: Yes

Step-by-step explanation:

All you had/have to do is 19-11 and get 8

Answer:

Yes, you're correct.

Step-by-step explanation:

Because since the bases are the same you can set the exponents equal. Then move the constant to the right hand side and it changes the sign. Then you calculate the difference. Finally you change the signs on both sides of the equation. x = 8

please help


please hurry

Answers

Answer:

-22 I arrived as fast as I could

Simplify the expression
(-3m to the 2) x (-5m to the 7)
Explain your process and justify each step by naming the appropriate property.

Answers

Answer:

15m⁹

Step-by-step explanation:

-3m² × -5m⁷ multiply bases (-3×-5=15). when multiplying bases you add exponents (2+7=9)

= 15m⁹

find the measures of the labeled angles :)

3x =
second answer =
simplified =
please help im struggling !! this is my last question :) ill mark brainliest

Answers

Answer: 54

Step-by-step explanation:

3x=72-x       ==> 3x and 72-x are both congruent angles, so they're equal

3x+x=72-x+x

4x=72

x=18

3x=

3(18)=54 degrees

please help with geometry problem

Answers

The value of the x in the given geometry figure is  108° .

When 2 lines ran into one another, then the other angles, shaped thanks to intersection are referred to as vertical angles or vertically opposite angles. A try of vertically opposite angles are invariably capable one another. Also, a angle and its adjacent angle are supplementary angles, i.e., they add up to one hundred eighty degrees.When 2 lines ran into, four angles are shaped. There are 2 pairs of distant angles. These pairs are referred to as vertical angles.Vertical angles are a try of non-adjacent angles shaped by the intersection of 2 straight lines. In straightforward words, vertical angles are set across from each other within the corners of the "X" shaped by 2 straight lines. they're conjointly referred to as vertically opposite angles as they're settled opposite to every alternative.

The labelled diagram of the figure is given below.

From the figure , we can see that ∠OEA = ∠BOF as they are vertically opposite angles .

Hence ∠BOF = x

∠OFT and ∠BOF are linear pair , so on adding them , we will get sum 180°

∠OFT + ∠BOF = 180°

 72° + x = 180°

        x = 108°

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Answer:

  x° = 22°

Step-by-step explanation:

You want the measure of the angle marked x° in the figure with two parallel lines and a "bent" transversal.

Remote interior angles

Extending the upward-sloping line in the figure as shown in the attachment results in a triangle against the top horizontal line.

The angle on the right side of that triangle corresponds to the one marked 50°, so has the same measure. It is one of two "remote interior angles" whose sum is the measure of the exterior angle marked 72°. The other "remote interior angle" making up that sum is the vertical angle to the one marked x°.

So, we have ...

  x° +50° = 72°

  x° = 22° . . . . . . . . subtract 50°

__

Additional comment

You can do a "sanity check" on this answer by considering some extreme cases. If the 72° angle is reduced to 50°, the top leg of the "72°" angle would be horizontal. That would effectively reduce x to 0. Similarly, if the 72° angle were made to be 180°, then the value of x would be supplementary to the 50° angle. In other words, x is the difference between the one marked 72° and 50°, or 22°.

−13,9,9,−13,5,−13,9


Calculate the value of the sample standard deviation. Round your answer to one decimal place.

Answers

Step-by-step explanation:

first we need the mean value. this is the sum of all data points divided by the number of data points :

(3×9 + 5 - 3×13)/7 = -7/7 = -1

next, for the standard deviation, we need to sum the squares of the differences of the data points to the mean value, divide that by the number of data points again, and then pull the square root :

(3(-13 - -1)² + 3(9 - -1)² + (5 - -1)²)/7 =

= (3×196 + 3×100 + 36)/7 = (588 + 300 + 36)/7 =

= 924/7 = 132

the standard deviation is now the square root of 132 :

sqrt(132) = 11.48912529... ≈ 11.5

so, yes, as we can see, the numbers vary/deviate rather strongly from the mean value.

Input
0
1
6
Output = Input x Itself + (-5) Output
95
59
76

Answers

We are given a table for input and output values and the relation between them.

Consider the table,

Input           Output = Input × itself + (-5)           Output

0                                        

1

6    

                                                                              95

                                                                              59

                                                                              76

For Input = 0 :

Output = Input × itself + (-5)

Output = 0 × 0 - 5

Output = -5

Now, for Input = 1,

Output = Input x Itself + (-5)

Output = (1) × 1 + (-5)

Output = 1 - 5

Output = - 4

For Input = 6,

Output = Input x Itself + (-5)

Output = (6) × 6 + (-5)

Output = 36 - 5

Output = 31

For Output = 95,

Output = Input x Itself + (-5)

95 = (Input)²+ (-5)

95 + 5 = (Input)²

(Input)² = 100

Input = √100

Input = 10

For Output = 59,

Output = Input x Itself + (-5)

59 = (Input)²+ (-5)

59 + 5 = (Input)²

(Input)² = 64

Input = √64

Input = 8

For Output = 76,

Output = Input x Itself + (-5)

76 = (Input)²+ (-5)

76 + 5 = (Input)²

(Input)² = 81

Input = √81

Input = 9

Therefore the complete table will be:

Input           Output = Input × itself + (-5)              Output

0                     Output = 0 × 0 + (-5)                          -5

1                      Output = 1 × 1 + (-5)                             -4

6                     Output = 6 × 6 + (-5)                          31

10                  95 = Input × itself + (-5)                      95

8                    59 = Input x Itself + (-5)                      59

9                    76 = Input x Itself + (-5)                      76

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A triangle has a perimeter of 13. If it has
sides of x/2,( x – 5), and (x - 2) lengths,
then:
a) find the value of x
b)find the length of the longest side

Answers

[tex]\stackrel{\textit{\LARGE sides}}{\cfrac{x}{2}+(x-5)+(x-2)~}~ = ~~13\implies \cfrac{x}{2}+2x-7=13 \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left( \cfrac{x}{2}+2x-7 \right)=2(13)}\implies x+4x-14=26\implies 5x-14=26 \\\\\\ 5x=40\implies x=\cfrac{40}{5}\implies \boxed{x=8} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(8)}{2}\implies 4\hspace{5em}(8)-5\implies 3\hspace{5em}\underset{Longest}{(8)-2\implies 6}[/tex]

Louisa made a purchase at her local convenience store for $6.65. She wanted to use up her change so she used
quarters and dimes to pay the clerk. If she used a total of 29 coins, how many fewer dimes than quarters did she
use?
Louisa used Number
fewer dimes.

Answers

Answer:

25 quarters and 4 dimes. Louisa used 21 more quarters than she did dimes.

Step-by-step explanation:

q=number of quarters

d=number of dimes

6.65=.25q+.10d   6.65 (the total) is equivalent to the amount of quarters times .25 (the value of a quarter) plus the amount of dimes times .10 (the value of a dime)

Now divide 6.65 by .25.

26 quarters can be used.

26 times .25 = 6.50

26 quarters is $6.50

29-26=3

3 times .10 = .30

.30+6.50=6.80

This is too much. Let's try taking off one quarter.

Now we have 25 quarters. .25 times 25 = 6.25

29-25=4 (This means there will be 4 dimes if she used 25 quarters, but let's see)

4 times .10 = .40

.40 + 6.25=6.65

6.65 is the total amount she had to pay, so we did it. Solving this showed us that she used 25 quarters and 4 dimes. This equals $6.65, the amount she paid, uses only quarters and dimes, and uses a total of 29 coins.

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describe a real world situation where you can apply finding the unit rate

Answers

The unit rate problem is discussed above and the unit rate of speed according to problem is 50 kilometers per hour.

What is the unit rate method ?

The unit rate method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

The real world situation can be as follows ;

A police officer who believes you were speeding stops you. You say that it took you exactly seven hours to travel 350 kilometers across the state. To determine if you were over speeding, the policeman must perform the necessary calculations. He requires to find out the unit rate.

Let's solve it to find out that at what unit rate of speed you were travelling.

We know that unit rate meant we need to find out the distance we have travelled in 1 hour.

So,

Unit speed = 350 / 7 km per hour

or

Unit speed = 50 kilometers per hour

Police man will check with the limit of speed and if he find that you were not over speeding , then he would allow you to go further.

Therefore , the unit rate problem is discussed above and the unit rate of speed according to problem is 50 kilometers per hour.

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The scale factor for a toy animal is 1:30. The toy animal is 5 inches tall. How tall is the actual animal?

Answers

The animal is 150 inches tall .

Scale Factor = ( scale / actual )

Given : Scale Factor = ( 1 / 30 )

To find : the actual height of animal .

Let t be the actual height of animal .

Therefore Scale Factor comes out to be ( 5 / t ) .

Equating both the scale factors and hence finding the value of t ,

( 1 / 30 ) = ( 5 / t )

t = 150 inches .

Therefore , the animal is 150 inches tall .

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Four brothers have ages that are consecutive even integers. From youngest to oldest, their names are Matt, Pat, Dave, and Dan. If Dan's age is 36 years less than twice Pat's age, then what are the ages of all four brothers?

Answers

Answer:

Matt is 38, Pat is 40, Dave is 42 and Dan is 44.

Step-by-step explanation:

Let Matt's age be x.

Then Pat is x + 2, Dave is x + 4 and Dan is x + 6.

Dan's age is 36 years less than twice Pat's age:

x + 6 = 2(x + 2) - 36

Solve it for x:

x + 6 = 2x + 4 - 36x + 6 = 2x - 322x - x= 6 + 32x = 38

So Matt is 38, Pat is 40, Dave is 42 and Dan is 44.

The distribution of the weights of a sample of 1,400 cargo containers is symmetric and bell-shaped. (need help asap)

A. According to the Empirical Rule, what percent of the weights will lie between X−3s and X+3s ? (Round your answer to 2 decimal places.)


B. According to the Empirical Rule, what percent of the weights will lie between X and X+ 3s (Round your answer to 2 decimal places.)


C. According to the Empirical Rule, what percent of the weights will lie below X−3s ? (Round your answer to 2 decimal places.)




C.

Answers

Using the Empirical Rule, the percentages are given as follows:

a) 99.7%.

b) 49.85%.

c) 0.15%.

What does the Empirical Rule state?

It states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.Approximately 95% of the measures are within 2 standard deviations of  the mean.Approximately 99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

In item a, the bounds are within 3 standard deviations of the mean, hence the percentage is of 99.7%.In item b, the bounds are within the mean and 3 standard deviations above the mean. Considering the symmetry of the normal distribution, the percentage is of 49.85%, as 99.7/2 = 49.85%.For item c, we have that 0.3% of the measures are more than 3 standard deviations of the mean. Considering the symmetry, we have that 0.3%/2 = 0.15% are below 3 standard deviations below the mean, that is, below X - 3s.

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The difference of four times a number and seven is ten more than the number

Answers

The number is 5.67

Let the number be 'x'

The difference of four times a number and seven = 4x - 7

Ten more than the number = 10 + x

According to the condition given in the question,

The difference between four times a number and seven is equal to ten more than the number.

4x - 7 = 10 + x

4x - x = 10 + 7

3x = 17

x = 17/3 = 5.67

We can verify the answer,

Consider the LHS,

=> 4x - 7 = 4(5.67) - 7 = 22.68 - 7 = 15.68

Consider the RHS,

=> 10 + x = 5.67 + 10 = 15.67

Both LHS and RHS are equal.

Therefore the number that satisfies the given condition is 5.67

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