6. A body of density 800 kg/m³ is kept on water. Find out its percentage part remains inside the liquid. ​

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Answer 1

A body of density 800 kg/m³ is kept on water. The percentage of part that remains inside the liquid is 80%.

To discover the proportion of the frame that stays in the liquid, we need to use the method:

Percentage = (Density of body)/(density of liquid) ​× 100.

According to the results, the density of water is ready at 1000kg/m³ at 4°C. The density of the body is given as 800 kg/m³. Plugging those values into the formula, we get:

Percentage = 1000 / 800 ​× 100

Percentage = 125

This means that 125% of the frame remains within the liquid. However, this isn't feasible, as it means that the frame is submerged greater than its own volume. This can simplest happen if the body is hollow or has an air wallet inside it. If the frame is solid and homogeneous, then it'll glide on the water and the handiest part of it will stay within the liquid. In that case, we want to apply some other method:

Percentage = (Volume of the complete body) /             (volume of submerged component​) × 100

To find the quantity of the submerged part, we need to use Archimedes’ principle, which states:

Weight of frame = Weight of the displaced liquid

The weight of the frame is identical to its mass times gravity, and the weight of the displaced liquid is identical to its quantity times density times gravity. Therefore, we will write:

(Mass of frame) × g = (Volume of submerged component) × (Density of liquid) × g

Canceling out g and rearranging, we get:

The volume of submerged element = Density of liquidness of frame​

The mass of the frame is identical to its extent instances density, so we are able to write:

The volume of the submerged part = (Density of liquid) / (volume of body) × (Density of body)​

Now we are able to plug this into the percentage formulation and get:

Percentage = ((Volume of the body) × (density of the body) / (density of the liquid)) / (Volume of the body) ​​× 100

Simplifying, we get:

Percentage = (Density of the body) / (density of liquid) × 100

This is the same method as earlier, however now it applies to a floating frame. Plugging in the given values, we get:

Percentage = (800 / 1000) ​× 100

Percentage = 80

This means that 80% of the frame remains inside the liquid when it floats on water.

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Related Questions

How do the air resistance and the weight of a falling object compare when terminal speed is reached?

Answers

When an object falls through the air, two main forces act upon it: gravity and air resistance. Initially, the force of gravity is greater than the force of air resistance, causing the object to accelerate.

However, as the object falls faster, the air resistance force also increases until it equals the force of gravity. At this point, the object has reached its terminal velocity, or maximum speed.

At terminal velocity, the weight of the object and the air resistance are equal. The object will no longer accelerate, but will continue to fall at a constant speed.

This means that the air resistance force has become strong enough to balance the weight of the object, allowing it to maintain a steady speed.

Therefore, at terminal velocity, the air resistance and weight of the object are equal and opposite forces that cancel each other out.

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rubble pile asteroids are group of answer choices sort of fragile. solid boulder congloms. clearly attached to a central basalt. at a constant zero gravitational force.

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Rubble pile asteroids are indeed a group of fragile, loosely held together boulders. They are not solid, but rather conglomerates of rocks and dust that are only held together by the weak gravitational force that binds them. This makes them very different from other types of asteroids, which are more solid and have a central basalt.
Despite their fragility, rubble pile asteroids can be quite large and can pose a significant threat if they collide with Earth. In fact, scientists believe that many of the craters on our planet were caused by such impacts. These asteroids are also interesting to scientists because they can provide important clues about the early history of our solar system and the processes that formed it.
Overall, rubble pile asteroids are fascinating objects that continue to captivate scientists and stargazers alike. While they may be fragile and seemingly insignificant, they hold important insights into the workings of our universe and the forces that shape it.
Rubble pile asteroids are a group of celestial objects composed of fragments that are loosely bound together by gravitational force. They are not solid boulders nor are they clearly attached to a central basalt. These asteroids can be considered somewhat fragile due to their loosely connected structure, which makes them more susceptible to fragmentation upon impact or other external forces. The gravitational force holding the individual fragments together is relatively weak compared to solid objects, but it is not at a constant zero.

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cylinders that contain corrosive gases should not be stored for more than how many months?

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Cylinders that contain corrosive gases should not be stored for more than 12 months.

This is because corrosive gases have the ability to eat away at the materials used to construct the cylinder, which can lead to the cylinder weakening and eventually failing. It is also important to note that cylinders that have been in storage for extended periods of time should be inspected before use to ensure their integrity. This can involve checking the cylinder for signs of damage or corrosion, as well as ensuring that the cylinder's valve is functioning properly. Overall, it is important to handle and store cylinders containing corrosive gases with care to ensure the safety of everyone involved.

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x ray tube life may be extended by

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The x-ray tube life may be extended by reducing exposure time, controlling temperature, and ensuring proper maintenance. These measures help in prolonging the tube's performance and minimizing wear.

X-ray tubes are essential components of x-ray machines, and their lifespan plays a crucial role in the efficient functioning of the equipment. Reducing exposure time can significantly decrease the amount of heat generated within the x-ray tube, thus reducing the wear on its components. Using the lowest possible exposure time that still provides adequate image quality is one way to extend the tube's life.

Temperature control is also important in preserving the x-ray tube's lifespan. The tube generates heat during operation, and excessive heat can damage its components. Ensuring that the equipment has adequate cooling mechanisms and is used in a temperature-controlled environment will help minimize heat-related issues and prolong the tube's life.

Lastly, proper maintenance of the x-ray tube is essential in extending its life. This includes regular cleaning and inspection of the tube, as well as following the manufacturer's guidelines for usage and care. By adhering to proper maintenance procedures, potential problems can be detected early, and appropriate measures can be taken to prevent further damage to the tube.

In conclusion, extending the life of an x-ray tube can be achieved through reducing exposure time, controlling temperature, and ensuring proper maintenance. These steps will help maintain the performance and efficiency of the x-ray machine, ultimately benefiting both patients and healthcare providers.

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latent heat is the quantity of heat gained or lost as a substance undergoes a:

Answers

Answer:

"phase change"

I think for water:

Lf (latent heat of fusion) = 80 cal/gm

Lv (latent heat of vaporization) = 540 cal / gm

A transparent dust cloud in space emits electromagnetic radiation in the infrared part of the electromagnetic spectrum. In a vacuum, this infrared light has a wavelength of 2. 20 × 1 0 − 6 m 2. 20×10 −6 m2, point, 20, times, 10, start superscript, minus, 6, end superscript, start text, m, end text and a speed of 3. 00 × 1 0 8 m/s 3. 00×10 8 m/s3, point, 00, times, 10, start superscript, 8, end superscript, start text, m, slash, s, end text

Answers

The Electromagnetic radiation refers to the energy that is propagated through space in the form of electromagnetic waves. Its wavelength of 2.20 × 10−6 m places it within the infrared part of the electromagnetic spectrum.


The transparent dust cloud in space that emits infrared electromagnetic radiation with a given wavelength and speed. To analyze this situation, we can use the information provided to calculate the frequency of the radiation. Wavelength (λ) = 2.20 × 10^-6 m Speed of light in a vacuum (c) = 3.00 × 10^8 m/s We can use the formula relating the speed of light, wavelength, and frequency c = λ × f c = speed of light λ = wavelength f = frequency to find the frequency (f), we can rearrange the formula f = c / λ Now, plug in the given values f = (3.00 × 10^8 m/s) / (2.20 × 10^-6 m) f ≈ 1.36 × 10^14 Hz
So, the frequency of the infrared electromagnetic radiation emitted by the transparent dust cloud in space is approximately 1.36 × 10^14 Hz. In conclusion, the infrared light emitted by the transparent dust cloud in space will travel at the speed of light in a vacuum, and it will not be affected by any particles or objects in its path. Its wavelength of 2.20 × 10−6 m places it within the infrared part of the electromagnetic spectrum.

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why do some scientists think that jupiter's existence may have been critical for life to evolve on earth?

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To give you a long answer, some scientists believe that Jupiter's existence may have been critical for life to evolve on Earth because of its gravitational influence. Jupiter is a massive planet that has a strong gravitational pull, which has helped to protect Earth from asteroid and comet impacts over billions of years. These impacts could have potentially wiped out life on Earth before it had a chance to evolve and develop into the diverse and complex forms we see today.

Additionally, Jupiter's strong gravity may have also played a role in the formation of Earth itself. It is believed that Jupiter's gravitational influence helped to shape the early solar system, causing debris and gas to come together to form the planets we see today, including Earth.

Finally, some scientists also believe that Jupiter's presence may have influenced the evolution of life on Earth through the process of panspermia. Panspermia is the idea that life may have originated elsewhere in the universe and been transported to Earth via asteroids or comets. Jupiter's gravity could have acted as a barrier, preventing these objects from reaching Earth and potentially bringing life with them.

Overall, there are many factors that could have made Jupiter's existence critical for life to evolve on Earth, and it is an exciting area of research that continues to be explored.


Some scientists believe that Jupiter's existence may have been critical for life to evolve on Earth due to its gravitational influence. Being the largest planet in our solar system, Jupiter's strong gravity helps protect Earth from excessive impacts of comets and asteroids, as it can deflect or capture these celestial objects. This reduces the frequency of large-scale collisions on Earth, allowing life to develop and evolve without frequent major disruptions.

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low-frequency surface waves will be amplified in tall buildings with low frequencies of vibration.
a. ture
b. false

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A. True. Low-frequency surface waves will be amplified in tall buildings with low frequencies of vibration.

This is because tall buildings can act as a resonator, amplifying the vibration frequencies that match their natural frequency of oscillation. This phenomenon is known as resonance, and it can lead to increased vibrations and motion in the building, potentially causing discomfort for occupants and even structural damage in extreme cases.

This is why engineers and architects take resonance into account when designing tall buildings, to ensure that they are able to withstand the forces that can be generated by wind, earthquakes, and other external sources of vibration.

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a 1000-kg car accelerates at 2 m/s2. what is the net force exerted on the car?

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Therefore, the net force exerted on the car is 2000 Newtons. This means that there is a force of 2000 N pushing the car forward, causing it to accelerate at 2 m/s2.


To determine the net force exerted on the car, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration. In this case, the car's mass is 1000 kg, and its acceleration is 2 m/s2. So, we can use the formula:
Net force = mass x acceleration
Net force = 1000 kg x 2 m/s2
Net force = 2000 N
The greater the force exerted on an object, the greater its acceleration will be, provided its mass remains constant. It's important to note that forces can act in different directions and cancel each other out, which can affect an object's overall acceleration.

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a 4000 kg truck travelling at 30 m/s to the right has a head-on collision with a 2000 kg car moving at 15 m/s to the left. during the collision, the two vehicles become stuck together. with what speed does the two-car pair move after the collision? a. -15 m/s b. 30 m/s c. 0 m/s d. 15 m/s

Answers

We need to use the principle of conservation of momentum, which states that the total momentum of a system remains constant unless acted upon by external forces. Therefore, the correct answer is d. 15 m/s. The two-car pair moves to the right at a speed of 15 m/s after the collision.

Initially, the momentum of the truck is (4000 kg) x (30 m/s) = 120000 kg m/s to the right, while the momentum of the car is (2000 kg) x (-15 m/s) = -30000 kg m/s to the left. The total momentum of the system before the collision is therefore 90000 kg m/s to the right.
After the collision, the two vehicles stick together, so they move as a single object. Let's call the velocity of this object v. Since the total momentum of the system is conserved, we can set the initial and final momenta equal to each other:
(4000 kg + 2000 kg) x v = 90000 kg m/s
Simplifying this equation, we get:
v = 90000 kg m/s / 6000 kg
v = 15 m/s to the right

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a ray passes from air into the surface of a lucite block at an angle with the lucite surface of 48.5°. what is the angle of refraction?

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When a ray of light passes from one medium to another, it changes direction due to a change in speed. This phenomenon is known as refraction. The angle of refraction can be determined using Snell's law, which states that the ratio of the sines of the angles of incidence and refraction is equal to the ratio of the speeds of light in the two media.

In this case, the angle of incidence is 48.5 degrees. Assuming the index of refraction of air is 1, the index of refraction of lucite can be found in a table or by using a refractometer. Let's assume it is 1.5. Using Snell's law, we can calculate the angle of refraction to be approximately 32.9 degrees. Therefore, when a ray of light passes from air into the surface of a lucite block at an angle of 48.5 degrees, the angle of refraction is approximately 32.9 degrees.

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HELP ASAP I WILL GIVE 60 POINTS AND LIKE YOUR Answer PLEASE HELP ME NOWWWWW

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7. Gravitational force is an attractive force that always exists between any two objects with mass. Gravitational fields are usually studied on a macroscopic scale, such as with planets and stars

8. Planets orbit stars because of the gravitational force between them.

9. The strength of an object's gravitational field is determined by its mass and distance from other objects.

What is gravitational force?

Gravitational force  is described as the  force of attraction between any two bodies is directly proportional to the product of their masses and is inversely proportional to the square of the distance between them.

The gravitational force of the star attracts the planet towards it which makes it tp move  in a curved path around the star.

The gravitational force between the planet and the star is the reason why the planet move in an elliptical orbit around the star.

The strength of an object's gravitational field is determined by its mass and the distance between it and other objects, and has an important function of shaping the dynamics and structure of the universe.

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since v = λ f, the speed v of a wave depends on its frequency f. true false

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True. According to the equation v = λ f, the speed of a wave (v) is directly proportional to its frequency (f). This means that as the frequency of a wave increases, so does its speed.

However, it's important to note that this relationship only holds true for waves that are traveling through a homogeneous medium with constant properties. In reality, waves can encounter obstacles or pass through different mediums which can affect their speed and frequency. Additionally, the wavelength (λ) of a wave also plays a role in determining its speed, as longer wavelengths typically travel slower than shorter wavelengths. In summary, the speed of a wave is dependent on both its frequency and wavelength, but for a given medium, an increase in frequency will result in an increase in speed.

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problem 2: estimate the velocity with which you would contact the ground if you jumped from an airplane at an altitude of 5,000 ft and (a) air resistance is negligible, (b) air resistance is important, but you forgot your parachute, or (c) you use a 25 ft diameter parachute.

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a) 176 m/s  air resistance is negligible and b) air resistance is important, but you forgot your parachute, 55 m/s and c)  The parachute would slow you down and reduce your terminal velocity to around 5 m/s, resulting in a much softer landing.

The velocity in these situations will be:
(a) If air resistance is negligible, you would be falling with a constant acceleration of 9.8 m/s^2 due to the force of gravity. The velocity with which you would contact the ground can be calculated using the formula v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity (0 m/s), a is the acceleration (9.8 m/s^2), and s is the displacement (5,000 ft or 1,524 m). Solving for v, we get v = √(2 × 9.8 × 1,524) = 176 m/s.
(b) If air resistance is important but you forgot your parachute, the velocity with which you would contact the ground would be lower than in part (a) due to the force of air resistance. As you fall, the air resistance would increase until it becomes equal to your weight, resulting in a constant velocity called the terminal velocity. The terminal velocity for a human body is around 55 m/s, so this is the velocity with which you would contact the ground.
(c) If you use a 25 ft diameter parachute, the velocity with which you would contact the ground would be much lower than in parts (a) and (b) due to the increased resistance from the parachute. The parachute would slow you down and reduce your terminal velocity to around 5 m/s, resulting in a much softer landing.

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the spring-like property that returns muscle to its original length after a contraction ends is

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The spring-like property that returns a muscle to its original length after a contraction ends is known as muscle elasticity. When a muscle contracts, it generates force and shortens in length. This contraction is achieved by the sliding of actin and myosin filaments within the muscle fibers.

However, once the contraction is over and the force is no longer applied, the muscle has the remarkable ability to return to its original length.

Muscle elasticity is attributed to two main factors: the structural arrangement of proteins within the muscle fibers and the connective tissue surrounding the muscle.

The proteins act as molecular springs that can be stretched and then recoil back to their original position when the force is released. This property allows the muscle to efficiently generate and transmit forces during movement.

Additionally, the connective tissue, such as tendons and fascia, surrounding the muscle acts as a supportive framework. It stores and releases energy during muscle contractions, assisting in the recoil and restoration of the muscle's original length.

Overall, muscle elasticity is essential for the proper functioning of our musculoskeletal system, allowing us to move efficiently and smoothly while maintaining the integrity of our muscles.

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a ball of mass m is dropped from rest at a height h and collides elastically with the floor, rebounding to its original height. what is the magnitude of the net impulse on the ball during the collision with the floor? (a) zero (b) mgh
(c) m2gh
(d) m4gh
(e) m8gh

Answers


During an elastic collision, the total momentum of the system is conserved. In this case, the ball is dropped from rest, so its initial momentum is zero. When it collides with the floor, the momentum of the ball is transferred to the floor momentarily, before the ball rebounds back up.

Since the collision is elastic, the ball rebounds to its original height, which means that its final momentum is also zero. Therefore, the net change in momentum of the ball is equal to its initial momentum, which is zero.
According to the impulse-momentum theorem, the net impulse on an object is equal to the change in its momentum. Since the ball's net change in momentum is zero, the magnitude of the net impulse on the ball during the collision with the floor is also zero.
Therefore, options (c), (d), and (e) can be eliminated. Option (a) is incorrect since the ball does experience a force during the collision, even though the net impulse is zero. The correct answer is option (b) mgh, which represents the potential energy of the ball when it was dropped from height h.

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Option (b) mgh. The magnitude of the net impulse on the ball during the collision with the floor can be found using the principle of conservation of energy. Since the collision is elastic, the total mechanical energy of the ball is conserved before and after the collision. Initially, the ball has potential energy mgh and zero kinetic energy.

After colliding with the floor and rebounding to its original height, the ball has zero potential energy and kinetic energy equal to mgh. Thus, the change in kinetic energy of the ball is mgh - 0 = mgh. The net impulse on the ball is equal to the change in momentum, which is mgh/2, since the velocity changes direction during the collision. Therefore, the answer is (b) mgh.

The correct answer is (e) m8gh. When the ball of mass m drops from height h, it gains kinetic energy (KE) before the collision, KE = mgh. During the elastic collision, the ball's velocity changes direction, effectively doubling its change in momentum. The impulse-momentum theorem states that impulse (J) equals the change in momentum (∆p), so J = ∆p. Since the ball rebounds to its original height, the velocity after collision has the same magnitude but opposite direction. Therefore, ∆p = 2mv, where v = √(2gh). So, J = 2m√(2gh) = m8gh.

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material a is tested by brinell hardness test with 500 kg force, and has hardness value 107 bhn. material b is tested by rockwell hardness test, has hardness value 42.5 hra. which material is harder? (use your conversion chart if it is necessary)

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Material a is tested by brinell hardness test with 500 kg force, and has hardness value 107 bhn. Material b is tested by rockwell hardness test, has hardness value 42.5 hra. Material A is harder than material B because the higher the hardness value, the greater the material's resistance to indentation or deformation.

To compare the hardness of materials A and B, we need to convert the Brinell hardness value (BHN) of material A to the Rockwell hardness value (HRA) scale.

Using a conversion chart, we can find that the approximate conversion from BHN to HRA is HRA ≈ (BHN/2) + 10. Thus, for material A:

HRA ≈ (107/2) + 10 ≈ 53.5

Comparing the HRA values, we find that material B has a hardness value of 42.5 HRA, while material A has a hardness value of 53.5 HRA.

Therefore, material A is harder than material B. In this case, material A has a higher HRA value, indicating that it is harder than material B.

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why is it so hard to see the bulge at the middle of the milky way galaxy with visible light?

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It is difficult to see the bulge at the middle of the Milky Way Galaxy with visible light due to several factors. First, the bulge is located far away from us, approximately 27,000 light-years, which means the light has to travel a long distance before reaching our eyes or telescopes.

Second, the Milky Way Galaxy is filled with interstellar dust and gas that absorb and scatter visible light, causing a phenomenon called interstellar extinction. This makes it challenging for the visible light from the bulge to pass through and reach us without significant loss of intensity.
Additionally, our line of sight to the bulge is through the plane of the galaxy, where the concentration of dust and gas is highest. This further exacerbates the problem of interstellar extinction and reduces the visibility of the bulge in visible light.
To overcome these challenges, astronomers rely on other wavelengths of light, such as infrared and radio waves, which are less affected by interstellar dust and gas. By using these wavelengths, we can gain a better understanding of the structure and properties of the Milky Way's central region.

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which of the following is true about how waves form and break upon the shore?

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Waves are formed by wind blowing over the surface of the water, which creates a disturbance in the water. The size and shape of the waves depend on factors such as wind speed, wind duration, and the distance over which the wind has blown.

As waves approach the shore, the water depth becomes shallower, causing the bottom of the wave to slow down and the top of the wave to continue moving forward. This causes the wave to become steeper and eventually break, releasing energy onto the shore. The type of break depends on the shape of the coastline and ocean floor. For example, a steep beach may produce a plunging wave break, while a gently sloping beach may produce a spilling wave break.
Waves form and break upon the shore due to the interaction between wind, water, and the ocean floor. As wind blows over the water's surface, it generates friction, creating ripples that eventually transform into waves. The size of the waves depends on factors like wind speed, duration, and the distance it travels (fetch). As waves approach the shore, they encounter shallower depths, causing their speed to decrease while their height increases. This process, called shoaling, leads to wave breaking when the crest topples over, releasing energy onto the shore. Ultimately, wave formation and breaking result from wind energy transfer, water dynamics, and seafloor topography.

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What is the main tenet of the lock-and-key model for drug activity?
A) There is a connection between drug structure and drug shape.
B) Only certain biological keys can unlock the potential of a drug.
C) The key to a drug's success is to keep it locked away from stomach acid.
D) The biological lock of an enzyme can be activated by using certain chemical keys.
E) all of the above

Answers

The main tenet of the lock-and-key model for drug activity is that there is a specific interaction between the drug molecule and the biological target site in the body, such as an enzyme or receptor.

This model proposes that the drug molecule (the "key") must have a complementary shape to the target site (the "lock") in order to exert its therapeutic effect. In other words, the drug molecule must fit into the target site like a key fits into a lock.

This model suggests that the specificity of drug action is due to the complementarity of the shapes of the drug molecule and the target site. It also implies that the drug's activity can be influenced by its chemical structure, and that minor changes to the structure of the drug molecule can have significant effects on its activity.

Therefore, option A is the correct answer: "There is a connection between drug structure and drug shape." The other options are not accurate descriptions of the lock-and-key model.

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Cuando se sumerge una piedra totalmente en un recipiente con agua (cuya densidad es 1g/m) esta experimenta dos fuerzas: su peso y una fuerza de empuje que la hace "más liviana" y que equivale al peso del agua desalojada por la piedra, como se muestra en la siguiente figura

Answers

Cuando se sumerge una piedra en un recipiente con agua, la piedra experimenta dos fuerzas: su peso hacia abajo y una fuerza de empuje hacia arriba que equivale al peso del agua desalojada por la piedra.

Esto se debe al principio de Arquímedes, que establece que un cuerpo sumergido en un fluido experimenta una fuerza de empuje igual al peso del fluido desplazado.

Cuando se sumerge la piedra en el agua, la fuerza de empuje actúa en sentido contrario a la fuerza de gravedad, lo que hace que la piedra parezca "más liviana" en el agua. La magnitud de la fuerza de empuje es igual al peso del agua desplazada por la piedra, según el principio de Arquímedes.

El principio de Arquímedes establece que un cuerpo sumergido en un fluido experimenta una fuerza de empuje dirigida hacia arriba y de magnitud igual al peso del fluido desplazado por el cuerpo. Esto ocurre porque el cuerpo desplaza una cantidad de fluido equivalente a su propio volumen.

En el caso de la piedra sumergida en agua, el volumen del agua desplazada por la piedra es igual al volumen de la piedra. La fuerza de empuje actúa hacia arriba y contrarresta parcialmente la fuerza de gravedad, lo que hace que la piedra parezca "más liviana" en el agua.

Es importante tener en cuenta que la fuerza de empuje depende del volumen del cuerpo y de la densidad del fluido en el que se sumerge. En este caso, al conocer la densidad del agua, podemos determinar la magnitud de la fuerza de empuje como igual al peso del agua desplazada por la piedra.

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Final answer:

Según el principio de Arquímedes, una piedra u otro objeto sumergido en agua experimentará una fuerza de empuje hacia arriba igual al peso del agua que desplaza. Esto hace que el objeto parezca más ligero en el agua que en el aire.

Explanation:

En física, el fenómeno que describes se llama el principio de Arquímedes. Este principio establece que un objeto sumergido en un fluido experimenta una fuerza de empuje hacia arriba que es igual al peso del fluido que desplaza. En este caso, la piedra sumergida en el agua experimentará una disminución en su peso debido a esta fuerza de empuje. Supongamos que la piedra tiene una densidad mucho mayor que el agua, por lo que se hundirá. Sin embargo, sentirá menos peso que en el aire porque el agua empuja hacia arriba contra ella con una fuerza igual al peso del agua que ha desplazado. Este efecto es por el cual los objetos parecen más ligeros cuando están en el agua.

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how does a mirror affect the path of light? responses light rays are scattered by mirrors. light rays are scattered by mirrors. light rays are reflected by mirrors. light rays are reflected by mirrors. light rays pass through mirrors at an angle. light rays pass through mirrors at an angle. light rays are interrupted by mirrors. light rays are interrupted by mirrors.

Answers

Explanation:

light rays are reflected by mirrors.    <====that is why when you look in a mirror you see your 'reflection'

question. in last jedi, luke projected a hologram of himself to fight kylo ren. how did his hologram kiss leia?

Answers

Luke's hologram in "The Last Jedi" projected a lifelike image and had the ability to engage in physical contact, like kissing Leia, as a deliberate expression of their bond.

How Luke able to display physical affection like kissing Leia through his hologram projection in "The Last Jedi"?

Luke's hologram in "The Last Jedi" possessed an astonishing ability to manifest a convincing physical presence, enabling him to interact seamlessly with his environment. In a heartfelt moment with Leia, the hologram projection exhibited a remarkable lifelike appearance, even going so far as to engage in physical contact, including a tender kiss. This deliberate decision by Luke allowed him to express his deep affection and forge a lasting emotional connection with his sister before bidding her farewell.

The scene demonstrated the extraordinary potential of holographic technology within the Star Wars universe, blurring the line between reality and illusion in a poignant and unforgettable manner.

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what is the resistance of a 1300 w (120 v) hair dryer?

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The values back into the formula for resistance: R = V/I. With a voltage of 120V and a current of 10.83A, the resistance (R) is approximately 11.08 ohms.


We need to understand what resistance is. Resistance is the measure of how much a device or material opposes the flow of electrical current. The unit of measurement for resistance is ohms (Ω). We can use Ohm's Law to calculate the resistance of the hair dryer. Ohm's Law states that resistance (R) is equal to voltage (V) divided by current (I): R = V/I. In this case, we know that the hair dryer has a power of 1300 watts and a voltage of 120 volts. Using the equation P = VI, we can calculate the current as I = P/V = 1300/120 = 10.83 amps. Then, we can use Ohm's Law to calculate the resistance as R = V/I = 120/10.83 = 11.07 Ω.  It's important to note that the resistance of the hair dryer may not remain constant throughout its use. As the hair dryer heats up, its resistance may increase due to the change in temperature and the behavior of the material inside the device. However, for the initial calculation, we can use the resistance of 11.07 Ω as an approximate value.

The resistance of a 1300 W (120 V) hair dryer is approximately 11.07 Ω. To determine the resistance of a 1300W (120V) hair dryer, we can use Ohm's Law, which states that voltage (V) equals current (I) times resistance (R). The formula is V = IR. We can rearrange the formula to solve for resistance: R = V/I. We need to find the current (I). We can do this by using the formula for power (P), which is P = VI. By rearranging the formula, we can find the current: I = P/V. In this case, the power (P) is 1300W, and the voltage (V) is 120V, so I = 1300/120 = 10.83A.

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a group of friends are playing football in the park. one of the players is hit in the chest and falls to the ground. he gets up holding his right chest area with his arm. which injury would be most likely?

Answers

Based on the description, the player most likely suffered a rib injury or a chest wall contusion. When the chest is hit with significant force, it can cause bruising or contusions of the muscles and tissues, resulting in pain and discomfort. Rib injuries are also common in such scenarios, as the ribs can fracture or bruise, causing sharp pain and difficulty breathing.

Holding the chest with the arm is a natural response to the pain and discomfort felt in the chest area. It is essential to seek medical attention if such an injury occurs to rule out any serious complications.

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a) calculate the kinetic energy of a 3-kg toy cart that moves at 4 m/s.
b) calculate the kinetic energy of the same cart at twice the speed.

Answers

a) the kinetic energy of the 3-kg toy cart that moves at 4 m/s is 24 J.

b) The kinetic energy of the same cart at twice the speed is 96 J.

a) The kinetic energy of an object is given by:

KE = 1/2 * m * v^2

where m is the mass of the object and v is its velocity. Plugging in the given values, we get:

KE = 1/2 * 3 kg * (4 m/s)^2 = 24 J

Therefore, the kinetic energy of the 3-kg toy cart that moves at 4 m/s is 24 J.

b) If the speed of the cart is doubled to 8 m/s, the kinetic energy increases four times because the kinetic energy is proportional to the square of the velocity. Therefore, we have:

KE' = 1/2 * 3 kg * (8 m/s)^2 = 96 J

Therefore, the kinetic energy of the same cart at twice the speed is 96 J.

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What three factors affect electric force? Choose all that apply a whether the charge is positive or negative b amount of charge c the distance between two charged objects d potential kinetics of two objects

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This is a secondary factor and is generally only significant at high speeds or in certain specialized circumstances.

The electric force between two charged objects is determined by the amount of charge on each object and the distance between them. These are the two primary factors that affect the electric force.

Firstly, the amount of charge on each object determines the strength of the electric force between them. Like charges (both positive or both negative) repel each other, while opposite charges (positive and negative) attract each other. The greater the amount of charge on the objects, the stronger the electric force between them.

Secondly, the distance between the charged objects also affects the electric force. The electric force decreases as the distance between the objects increases. This is because the electric field created by one charged object diminishes as it spreads out over a larger area.

In addition to these two primary factors, the potential kinetic energy of the two charged objects can also affect the electric force. If one or both objects are in motion, their kinetic energy can contribute to the overall energy of the system and affect the electric force.

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a cyclist cycles 15 km west and then 15 km north. what is the magnitude of her displacement vector?

Answers

Answer:

21.2 km

Explanation:

You're basically solving for the hypotenuse of a right triangle with legs of 15 and 15.  Use the pythagorean theorem:

d =  displacement vector

d² = 15² + 15² = 450

d = √450 = 21.2 km

Show how The Archimedes principle may be used in determine the relative density of a liquid

Answers

Archimedes principle can be used to determine the relative density of a liquid by measuring the buoyant force acting on an object submerged in the liquid.

The buoyant force is equal to the weight of the liquid displaced by the object. By comparing the buoyant force on the object in the liquid to its weight in air, we can calculate the relative density of the liquid.

According to the Archimedes principle, when an object is submerged in a fluid, it experiences an upward buoyant force equal to the weight of the fluid displaced by the object. To determine the relative density of a liquid, we can follow these steps:

Measure the weight of the object in air using a scale. Let's call this weight W.

Immerse the object completely in the liquid and measure the apparent weight of the object in the liquid using the scale. Let's call this apparent weight W'.

The difference between the weight in air and the apparent weight in the liquid is the buoyant force acting on the object. This buoyant force is equal to the weight of the liquid displaced by the object.

Calculate the density of the liquid using the formula ρ = W / (W - W'), where ρ is the relative density of the liquid.

By following this procedure, we can determine the relative density of a liquid using the Archimedes principle and the measurements of weight in air and apparent weight in the liquid.

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if you want to find a radius value for most stars, what must you first measure about the star?

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To find the radius value of a star, you must first measure its apparent brightness and its distance from Earth.

These two measurements are essential because they help astronomers calculate the star's luminosity, which is the total amount of energy it emits per second. Once the luminosity is known, scientists can use a mathematical equation called the Stefan-Boltzmann law to determine the star's surface temperature. Finally, by combining the temperature with the luminosity, astronomers can calculate the star's radius. This process is essential for understanding a star's physical properties and can provide valuable insights into its life cycle and behavior. Overall, measuring the apparent brightness and distance of a star is critical for determining its radius value and unlocking many other mysteries about these fascinating celestial objects.

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