6(x/2 + 4) greater than or equal to 9

Answers

Answer 1

Answer:

Greater than 9.

Step-by-step explanation:

[tex]6(x/2 + 4)[/tex]

[tex]3x+24[/tex]


Related Questions

Data on return-to-pay ratios was collected from CEOs of companies within both the low-tech industry and the consumer products industry.

Low-Tech Consumer Products
Sample size 14 12
Sample mean 157 218
Sample Variance 1563 1602
Assume population variances are unequal.

(a) The point estimate of the difference between the means of the two populations is

(b) The standard error for the difference between the two means is

(c) The correct distribution to use is :

t-distribution with 26 degrees of freedom

t-distribution with 23 degrees of freedom

normal distribution

t-distribution with 24 degrees of freedom

Answers

Answer:

Step-by-step explanation:

The confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

Where

x1 = sample mean of low-tech industry

x2 = sample mean of consumer products industry

s1 = sample standard deviation low-tech industry

s2 = sample standard deviation for consumer products industry

n1 = number of samples of low-tech industry

n2 = number of samples of consumer products industry

a) x1 - x2 is the point estimate of the difference between the means of the two populations

Therefore,

Point estimate = 157 - 218 = - 61

b) the formula for standard error is expressed as

√(s1²/n1 + s2²/n2)

Variance = standard deviation²(s²)

s1² = 1563

s2² = 1602

Standard error = √(1563²/14 + 1602²/12) = 623.2

c) Degree of freedom =

(n1 - 1) + (n2 - 1) = (14 - 1) + (12 - 1) = 24

t-distribution with 24 degrees of freedom

According to the data given, we have that:

a) 61

b) 15.65

c) t-distribution with 24 degrees of freedom

Item a:

The point estimate is the difference between the two sample means, hence:

218 - 157 = 61.

Item b:

For each sample, the standard errors are:

[tex]s_l = \sqrt{\frac{1563}{14}} = 10.57[/tex]

[tex]s_h = \sqrt{\frac{1602}{12}} = 11.54[/tex]

For the difference of the two means, it is:

[tex]s = \sqrt{s_l^2 + s_h^2} = \sqrt{10.57^2 + 11.54^2} = 15.65[/tex]

Item c:

Samples of 14 and 12, hence 14 + 12 - 2 = 24 df.

A similar problem is given at https://brainly.com/question/12490448

find five rational numbers between ? explain please

Answers

Answer:

1.5, 6, 24.7, 384, 404.4, 1,980

Step-by-step explanation:

Rational numbers are the result of dividing two integers. Intergers cannot be fractions. So 1.5 is rational but 3/2 is not.

Five rational numbers: 1.5, 6, 24.7, 384, 404.4, 1,980

I'm always happy to help :)

One number is 11 less than the other number. If their sum is increased by 8, the result is 71. Find the numbers.

Answers

First number = [tex]x[/tex]

Second number = [tex]x-11[/tex]

[tex]x+x-11+8=71[/tex]

[tex]2x-3=71[/tex]

[tex]2x=71+3[/tex]

[tex]2x=74[/tex]

[tex]x=37[/tex]

First number = [tex]x=37[/tex]

Second number =  [tex]x-11=37-11=26[/tex]

In a sample of 800 adults, 214 think that most celebrities are good role models. Two us adults are selected from this sample without replacement. find the probability that both adults think most celebrities are good role models

Answers

Answer:

11449/160000

Step-by-step explanation:

The probability of selecting a single adult that thinks most celebrities are good role models is 214/800 = 107/400

The probability that both do is

(107/400)^2 =. 11449/160000

Determine whether the given value is a statistic or a parameter.A homeowner measured the voltage supplied to his home on 42 random days, and the average (mean) value is 127.1 volts.A) The given value is a statistic for the year because the data collected represented a population.
B) The given value is a parameter for the year because the data collected represent a sample.
C) The given value is a parameter for the year because the data collected represent a population.
D) The given value is a statistic for the year because the data collected represent a sample.

Answers

Answer:

[tex] \bar X = \frac{\sum_{i=1}^{42} X_i}{n}[/tex]

And for this case the sample mean is

[tex]\bar X = 127.1[/tex]

And this value is calculated from a sample so then can't represent a population parameter. Then the value 127.1 represent a statistic called the sample mean unbiased for the true population mean since [tex] E(\bar X) =\mu[/tex], and the best option would be:

D) The given value is a statistic for the year because the data collected represent a sample.

Step-by-step explanation:

For this case we know that a homeowner take a random sample of 42 voltage values ina year and he calculate the sample mean with this formula:

[tex] \bar X = \frac{\sum_{i=1}^{42} X_i}{n}[/tex]

And for this case the sample mean is

[tex]\bar X = 127.1[/tex]

And this value is calculated from a sample so then can't represent a population parameter. Then the value 127.1 represent a statistic called the sample mean unbiased for the true population mean since [tex] E(\bar X) =\mu[/tex], and the best option would be:

D) The given value is a statistic for the year because the data collected represent a sample.

HELP! Look at the figure, PQRS. Find the values of ​x and y. a) x = 5, y = 7 b)x = 6, y = 8 c)x = 6, y = 9 d)x = 7, y = 10

Answers

Answer:

  c)  x = 6, y = 9

Step-by-step explanation:

The figure is a parallelogram. The diagonals of a parallelogram bisect each other, so each part of a given diagonal is equal to the other part.

  3x = 2y

  2x = y+3

__

Solving the second equation for y, we have ...

  y = 2x -3

Substituting into the first equation gives ...

  3x = 2(2x -3)

  3x = 4x -6 . . . . simplify

  6 = x . . . . . . . . .add 6 -3x

  y = 2(6) -3 = 9 . . . . use the above expression for y

The values of x and y are (x, y) = (6, 9).

Which table represents a function?

Answers

Answer:

The bottom left table

Step-by-step explanation:

the same x value cannot have different y values

What’s the correct answer for this?

Answers

the answer would be 13.9 kg of gravel used per square meter

Answer:

B.

Step-by-step explanation:

In the attached file

Square A"B"C"D" is the final image after the rule was applied to square ABCD. On a coordinate plane, a square A double-prime B double-prime C double-prime D double-prime has points (negative 5, negative 3), (negative 3, negative 1), (negative 1, negative 3), (negative 3, negative 5). What are the coordinates of vertex A of square ABCD? (–1, –6) (–1, –2) (–1, 6) (–2, 1)

Answers

Answer:

The answer is (-2 , 1 ) or D on Edge

Step-by-step explanation:

The coordinates of vertex A of square ABCD is (-1, -2).

What are coordinates?

Coordinates are two numbers (Cartesian coordinates), or sometimes a letter and a number, that locate a specific point on a grid, known as a coordinate plane.

Given:

A(-5, -3), B(-3, -1), C(-1, -3) and D(-3, -5)

By using the rule

T(-4, -1)

So, the coordinate of Vertex A will be

A( -5 + 4, -3 + 1)

=A(-1, -2)

Learn more about coordinates here:

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whatt is the equation of the line that passes through the points (-3,-3) and (3,1)

Answers

Answer:

[tex] m=\frac{y_2 -y_1}{x_2 -x_1}[/tex]

And replacing we got:

[tex] m=\frac{1-(-3)}{3-(-3)}= \frac{4}{6}=\frac{2}{3}[/tex]

And we can use one of the points in order to find the intercept like this:

[tex] -3= \frac{2}{3} (-3) +b[/tex]

[tex] b =-3 +2=-1[/tex]

And the equation would be given by:

[tex] y= \frac{2}{3}x -1[/tex]

Step-by-step explanation:

We want an equation given by:

[tex] y=mx+b[/tex]

where m i the slope and b the intercept

We have the following two points given:

[tex] (x_1 = -3, y_1 =-3), (x_2=3, y_2 =1)[/tex]

We can find the slope with this formula:

[tex] m=\frac{y_2 -y_1}{x_2 -x_1}[/tex]

And replacing we got:

[tex] m=\frac{1-(-3)}{3-(-3)}= \frac{4}{6}=\frac{2}{3}[/tex]

And we can use one of the points in order to find the intercept like this:

[tex] -3= \frac{2}{3} (-3) +b[/tex]

[tex] b =-3 +2=-1[/tex]

And the equation would be given by:

[tex] y= \frac{2}{3}x -1[/tex]


Directions and Analysis
Task 1: Completing the Square
Look at the quadratic equation below.
2x^2-12x-16=0



This is not an equation that could be easily solved by factoring. Instead, you are going to use the method of completing the square to solve this equation. Follow each step in this task to complete the square and solve the equation.

a. To complete the square, the coefficient of the x2 term must be 1. Divide both sides of the equation by a value and rewrite the equation to meet this criteria.

Type your response here:


b. Rewrite the resulting equation so the constant term is on the right side of the equation and the variable terms are on the left.

Type your response here:


c. Identify the coefficient of the x term in the previous equation. Then divide it by half and square the result. What is the result?

Type your response here:


d. Add the value you identified in part c to both sides of the equation from part b and simplify the right side. Remember that when solving equations, whatever is done to one side of the equation must also be done to the other side the equation: that is why you must add the value to both sides.

Type your response here:


e. Notice that the left side of the equation now represents a perfect square quadratic expression. Use this fact to rewrite the left side of the previous equation as the square of a linear term and create a new equation.

Type your response here:


f. You have now completed the square. Starting with the result from part e, solve the equation for x. Show your work.

Type your response here:


g. Now that you know how to complete the square to solve a quadratic equation, solve the equation 3x^2 – 3x − 6 = 0. Show your work.

Type your response here:



Answers

Answer:

a. [tex]x^2-6x-8=0[/tex]

b. [tex]x^2-6x=8[/tex]

c.

[tex]\frac{1}{2}[/tex] (Coefficient of x) = [tex]\frac{-6}{2}=-3[/tex]

Also, [tex](-3)^2=9[/tex]

d. [tex]x^2-6x+9=17[/tex]

e. [tex](x-3)^2=17[/tex]

f, g. [tex]x=3\pm \sqrt{17}[/tex]

Step-by-step explanation:

Given: [tex]2x^2-12x-16=0[/tex]

To solve: the given equation

Solution:

a.

[tex]2x^2-12x-16=0[/tex]

Coefficient of [tex]x^2=2[/tex]

Divide both sides by 2

[tex]x^2-6x-8=0[/tex]

b.

[tex]x^2-6x=8[/tex]

c.

Coefficient of x = -6

[tex]\frac{1}{2}[/tex] (Coefficient of x) = [tex]\frac{-6}{2}=-3[/tex]

Also, [tex](-3)^2=9[/tex]

d.

Add 9 to both sides of the equation: [tex]x^2-6x=8[/tex]

[tex]x^2-6x+9=8+9\\x^2-6x+9=17[/tex]

e.

[tex]x^2-6x+9=17\\x^2-2(3)x+3^2=17\\(x-3)^2=17\,\,\left \{ \because (a-b)^2=a^2+b^2-2ab \right \}[/tex]

f.

[tex](x-3)^2=17\\x-3=\pm \sqrt{17}\\x=3\pm \sqrt{17}[/tex]

g.

[tex]x=3\pm \sqrt{17}[/tex]

Calculating conditional probability
G
The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom.
Here are the results:
Bride
Groom
29
30
20
1
Given that a randomly selected guest is a friend of the groom, find the probability they are a friend of the bride.
P (bride groom)​

Answers

Complete Question

Calculating conditional probability

The usher at a wedding asked each of the 80 guests whether they were a friend of the bride or of the groom.

Here are the results:

Bride :29

Groom :30

BOTH : 20

Given that a randomly selected guest is a friend of the groom, find the probability they are a friend of the bride.

P (bride | groom)​

Answer:

The probability is [tex]P(B|G) = \frac{2}{3}[/tex]

Step-by-step explanation:

The sample size is [tex]n = 80[/tex]

The friend of the groom are [tex]G = 30[/tex]

 The friend of the groom are [tex]B = 29[/tex]

 The friend of both bride and groom are [tex]Z = 20[/tex]

The probability that a guest is a friend of the bride is mathematically represented as

      [tex]P(B) = \frac{29}{80}[/tex]

The probability that a guest is a friend of the groom is mathematically represented as

       [tex]P(G) = \frac{30}{80}[/tex]

The probability that a guest is both a friend of the bride and a friend of the groom is mathematically represented as

       [tex]P(B \ n \ G) = \frac{20}{80}[/tex]

Now

    [tex]P(B|G)[/tex] is mathematically represented as

     [tex]P(B|G) = \frac{P(B \ n \ G)}{P(G)}[/tex]

     Substituting values

       [tex]P(B|G) = \frac{\frac{20}{80} }{\frac{30}{80} }[/tex]

      [tex]P(B|G) = \frac{2}{3}[/tex]

     

Answer:

the answer is 3/5

Step-by-step explanation:

on Khan

I want the answer of this question

Answers

[tex]the \: answer \: is \: 10 \\ please \: see \: the \: attached \: picture \: for \\ full \: solution \\ hope \: it \: helps[/tex]

Answer:

10 is the answer for this question.

Complete the point-slope equation of the line through (− 2 ,6 ) ( 1 , 1 )

Answers

Answer:

y=-5/3x+8/3

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(-2,6) and (1,1).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-2,6), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-2 and y1=6.

Also, let's call the second point you gave, (1,1), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=1 and y2=1.

Now, just plug the numbers into the formula for m above, like this:

m=  

1 - 6

1 - -2

or...

m=  

-5

3

or...

m=-5/3

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=-5/3x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-2,6). When x of the line is -2, y of the line must be 6.

(1,1). When x of the line is 1, y of the line must be 1.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=-5/3x+b. b is what we want, the -5/3 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-2,6) and (1,1).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(-2,6). y=mx+b or 6=-5/3 × -2+b, or solving for b: b=6-(-5/3)(-2). b=8/3.

(1,1). y=mx+b or 1=-5/3 × 1+b, or solving for b: b=1-(-5/3)(1). b=8/3.

CAN SOMEONE HELP ME IN THIS INTEGRAL QUESTION PLS
''Find the surface area between the z = 1 and z = 4 planes of z = x ^ 2 + y ^ 2 paraboloid.''

Answers

Due to the symmetry of the paraboloid about the z-axis, you can treat this is a surface of revolution. Consider the curve [tex]y=x^2[/tex], with [tex]1\le x\le2[/tex], and revolve it about the y-axis. The area of the resulting surface is then

[tex]\displaystyle2\pi\int_1^2x\sqrt{1+(y')^2}\,\mathrm dx=2\pi\int_1^2x\sqrt{1+4x^2}\,\mathrm dx=\frac{(17^{3/2}-5^{3/2})\pi}6[/tex]

But perhaps you'd like the surface integral treatment. Parameterize the surface by

[tex]\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+u^2\,\vec k[/tex]

with [tex]1\le u\le2[/tex] and [tex]0\le v\le2\pi[/tex], where the third component follows from

[tex]z=x^2+y^2=(u\cos v)^2+(u\sin v)^2=u^2[/tex]

Take the normal vector to the surface to be

[tex]\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial u}=-2u^2\cos v\,\vec\imath-2u^2\sin v\,\vec\jmath+u\,\vec k[/tex]

The precise order of the partial derivatives doesn't matter, because we're ultimately interested in the magnitude of the cross product:

[tex]\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|=u\sqrt{1+4u^2}[/tex]

Then the area of the surface is

[tex]\displaystyle\int_0^{2\pi}\int_1^2\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv=\int_0^{2\pi}\int_1^2u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv[/tex]

which reduces to the integral used in the surface-of-revolution setup.

Andrew invests 79500 for 2 years akd earns 10017 of simple interest. Calculate the interest rate.

Answers

Answer:use mathematic pathway to calualte

Step-by-step explanation:

write (2n^2)^3 without exponents

Answers

Answer:

8n x n x n x n x n x n x n

Step-by-step explanation:

(2n^2)^3 = 8n^ 6

Now just write "n" 6 times and there you go

The given expression without exponents can be written as 8×n×n×n×n×n×n.

The given expression is (2n²)³.

We need to write the given expression without exponents.

What is an exponent?

The exponent of a number shows how many times the number is multiplied by itself. For example, 2×2×2×2 can be written as 24, as 2 is multiplied by itself 4 times.

Now, the given expression can be simplified as follows:

(2n²)³=2³×(n²)³

=2×2×2×[tex]n^{6}[/tex]  (∵[tex](a^{m}) ^{n}=a^{m\times n}[/tex])

=8×n×n×n×n×n×n

Therefore, the given expression without exponents can be written as 8×n×n×n×n×n×n.

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You need to haul a load of patio bricks to a job site. Each brick weighs 4 pounds 14 ounces. Truck can carry a 3/4 - ton load. How many bricks can the truck carry in a full load?

Answers

Answer:

339 bricks.

Step-by-step explanation:

We have the weight of each brick and what the truck can support. Therefore what we must do is pass all to the same unit of measurement to calculate the quantity of bricks.

In this case we will pass everything to pounds.

We have that a 1 pound is 16 ounces, therefore 14 would be:

14 ounces * 1 pound / 16 ounces = 0.875 pounds

In addition we have that 1 ton is 2204.62 pounds, therefore 3/4 would be:

3/4 ton * 2204.62 pounds / 1 ton = 1653.467 pounds

Therefore, in total the brick weighs 4,875 pounds (4 + 0.875) and the truck can support 1653,467 pounds, the number of bricks would be:

1653.467 / 4.875 = 339.17

In other words, it can support about 339 bricks.

Please help me with this question!!

Answers

Answer:

  IV

Step-by-step explanation:

Cosine is positive in quadrants I and IV.

Cosecant (also sine) is negative in quadrants III and IV.

The quadrant where cos > 0 and csc < 0 is quadrant IV.

Graph g(x), where f(x) = 2x − 5 and g(x) = f(x + 1).
A.) a line labeled g(x) that passes through points 0, negative 4 and 2, 0
B.) a line labeled g(x) that passes through points 0, negative 3 and 4, 5
C.) a line labeled g(x) that passes through points negative 5, negative 3 and 0, 7
D.) a line labeled g(x) that passes through points 0, negative 7 and 5, 3

Answers

Answer:

B.) a line labeled g(x) that passes through points 0, negative 3 and 4, 5

Step-by-step explanation:

I graphed both equation on the graph below to find the description of the graph of g(x).

Answer:

b for brakes?

Step-by-step explanation:

A nutritionist wants to determine how much time nationally people spend eating and drinking. Suppose for a random sample of 1082 people age 15 or​ older, the mean amount of time spent eating or drinking per day is 1.53 hours with a standard deviation of 0.71 hour.

a. Determine and interpret a 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day
b. The nutritionist is 95% confident that the amount of time spent eating or drinking per day for any individual is between_________and_________hours.
c. There is a 95% probability that the mean amount of time spent eating or drinking per day is between and hours.
d. The nutritionist is 95% confident that the mean amount of time spent eating or drinking per day is between_______and_____________

Answers

Answer:

a) The 95% confidence interval for the mean amount of time Americans age 15 or older spend eating and drinking each day is (1.49, 1.57).

d) The nutritionist is 95% confident that the mean amount of time spent eating or drinking per day for any individual is between 1.49 and 1.57 hours.

(c and b can not be concluded from the confidence interval)

Step-by-step explanation:

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=1.53.

The sample size is N=1082.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

[tex]s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.71}{\sqrt{1082}}=\dfrac{0.71}{32.89}=0.022[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=1082-1=1081[/tex]

The t-value for a 95% confidence interval and 1081 degrees of freedom is t=1.962.

The margin of error (MOE) can be calculated as:

[tex]MOE=t\cdot s_M=1.962 \cdot 0.022=0.042[/tex]

Then, the lower and upper bounds of the confidence interval are:

[tex]LL=M-t \cdot s_M = 1.53-0.042=1.49\\\\UL=M+t \cdot s_M = 1.53+0.042=1.57[/tex][tex]LL=M-t \cdot s_M = 1.53-0.042=1.49\\\\UL=M+t \cdot s_M = 1.53+0.042=1.57[/tex]

The 95% confidence interval for the mean is (1.49, 1.57).

A study published in 2010 showed that city dwellers have a higher risk of developing anxiety disorders and a higher risk of developing mood disorders than those who live in the country. A follow-up study published in 2011 used brain scans of city dwellers and country dwellers as they took a difficult math test.1 To increase the stress of the participants, those conducting the study tried to humiliate the participants by telling them how poorly they were doing on the test. The brain scans showed very different levels of activity in stress centers of the brain, with the urban dwellers having greater brain activity than rural dwellers in areas that react to stress.

Required:

a. Is the 2010 study an experiment or an observational study?
i. Experiment
ii. Observational study

b. Can we conclude from the 2010 study that living in a city increases a person's likelihood of developing an anxiety disorder or mood disorder?
i. Yes
ii. No

c. Is the 2011 study an experiment or an observational study?
i. Experiment
ii. Observational study

d. Can we conclude from the 2011 study that living in a city increases activity in stress centers of the brain when a person is under stress?
i. Yes
ii. No

Answers

Step-by-step explanation:

a.It is a controlled experiment because it is clearly seen that an established hypothesis or study is being verified through an experiment, now in this case the hypothesis is tested through an experiment where excessive stress is placed on the Participants during their math exam to effectively verify that people in urban or city areas live with more stress than people in rural areas.

2..As now that the previously established hypothesis has been verified, it is concluded that people who live in the city live with more anxiety and stress than people who live in rural areas.

What is the slope of a line that is perpendicular to the line y = -1/2x + 5?
the answer choices are
-2
-1/2
1/2
2

Answers

Answer:

2

Step-by-step explanation:

as you can see the slope of the line y = -1/2x + 5 is -1/2

the slope m of any line perpendicular to it should verify : -1/2×m = -1

-1/2×m = -1

→ multiply both sides by -2

m = 2

The answer is 2 bc of the equation

Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. They are considering a promotion that involves mailing discount coupons to all their credit card customers. This promotion will be considered a success if more than of those receiving the coupons use them. Before going national with the promotion, coupons were sent to a sample of credit card customers. Click on the datafile logo to reference the data.
a. Develop hypotheses that can be used to test whether the population proportion of those who will use the coupons is sufficient to go national.b. The file Eagle contains the sample data. Develop a point estimate of the population proportion.c. Use αα= .05 to conduct your hypothesis test. Should Eagle go national with the promotion?

Answers

Answer:

Step-by-step explanation:

The question is incomplete. The complete question is:

Eagle Outfitters is a chain of stores specializing in outdoor apparel and camping gear. It is considering a promotion that involves mailing discount coupons to all its credit card customers. This promotion will be considered a success if more than 10% of those receiving the coupons use them. Before going national with the promotion, coupons were sent to a sample of 100 credit card customers. Out of the 100 customers, 13 customers said that they used the discount coupons to make a purchase at a Eagle Outfitters store. Use a 0.05 level of significance. (a) Develop the null and alternative hypotheses that can be used to test whether the population proportion of those who will use the coupons is sufficient to go national. (b) Compute the sample proportion. (c) Compute the test statistic. (d) Compute the critical value. (e) Based on the critical value, do we reject H0 or do we not reject H0? (f) Based on the result of the hypothesis test, should Eagle Outfitter go national with the promotion?

Solution:

a) We would set up the hypothesis test.

For the null hypothesis,

H0: p ≥ 0.1

For the alternative hypothesis,

Ha: p < 0.1

This is a left tailed test

Considering the population proportion, probability of success, p = 0.1

q = probability of failure = 1 - p

q = 1 - 0.1 = 0.9

b) Considering the sample,

Sample proportion, P = x/n

Where

x = number of success = 13

n = number of samples = 100

p = 13/100 = 0.13

c) We would determine the test statistic which is the z score

z = (P - p)/√pq/n

z = (0.13 - 0.1)/√(0.1 × 0.9)/100 = 1

The calculated test statistic is 1 for the right tail and - 1 for the left tail.

d) Since α = 0.05, the critical value is determined from the normal distribution table.

For the left, α/2 = 0.51/2 = 0.025

The z score for an area to the left of 0.025 is - 1.96

For the right, α/2 = 1 - 0.025 = 0.975

The z score for an area to the right of 0.975 is 1.96

e) In order to reject the null hypothesis, the test statistic must be smaller than - 1.96 or greater than 1.96

Since - 1 > - 1.96 and 1 < 1.96, we would fail to reject the null hypothesis.

Therefore, based on the result of the hypothesis test, the Eagle Outfitter should go national with the promotion

Find the measure of a positive angle and a negative angles that are coterminal with each given angle 400°

Answers

Answer: see below

Step-by-step explanation:

To find a coterminal angle, add or subtract 360° to the given angle as many times as needed to get a positive or negative angle.

I should mention that there are an infinite number of answers!

4) 400°

I can subtract 360° to get a positive angle of 40°

I can subtract another 360° to get a negative angle of -320°

5) -360°

I can subtract 360° to get a negative angle of -720°

I can add 360° twice to get a positive angle of 360°

6) -1010°

I can add 360° to get a negative angle of -650°

I can add 360° another 3 times to get a positive angle of 720°

7) 567°

I can subtract 360° to get a positive angle of 207°

I can subtract another 360° to get a negative angle of -153°

8) -164°

I can subtract 360° to get a negative angle of -524°

I can add 360° to get a positive angle of 194°

9) 358°

I can subtract 360° to get a negative angle of -2°

I can add 360° to get a positive angle of 718°

Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary.
Age (yr) when award was won:
20-24
25-29
30-34
35-39
40-44
45-49
50-54
Frequency:
29
36
15
3
6
2
2

Answers

Answer:

Lower class Limit: 20,25,30,35,40,45,50

Upper class limit: 24,29,34,39,44,49,54

Class width: 4

Class Midpoints : 22,27,32,37,42,47,52

Class Boundries : 19.5,24.5,29.5,34,5,39.5,44.5,49.5,54.5

Total Individuals: 93

Step-by-step explanation:

Lower class limit is the lowest value of a class e.g in the first class, the lowest value is 20. Similarly find lower class limit of othere classes.

Upper class limit is the highest value of a class e.g in the first class, the highest value is 24. Similarly find upper class limit of othere classes.

Class width is the difference between highest and lowest value of a class e.g 24-20=4

Class Midpoints can be found by adding lowest and highest value of a class and dividing it by 2 e.g (20+24)/2 = 22

Class boundaries are the halfway point which seperates the classes e.g for first classes, clasee boundry is (19.5,24.5)

Total individuals are founf by adding all the frequencies.

8,36 : 1,6



pleaseeeeeeeeee

Answers

Answer:

  209 : 40  or  5.225 : 1

Step-by-step explanation:

Your calculator can tell you the ratio 8.36/1.60 is 5.225. Writing that decimal as a fraction, you can factor out 25 to get ...

  8.36 : 1.6 = 5.225 : 1 = 5225 : 1000 = (25)(209) : (25)(40) = 209 : 40

CAN SOMEONE HELP ME IN THIS INTEGRAND QUESTION PLS PLS PLS PLS
''Find the surface area between the z = 1 and z = 4 planes of z = x ^ 2 + y ^ 2 paraboloid.''

Answers

Answer:

Step-by-step explanation:

Answer:

S = ⅙ π (65^³/₂ − 5^³/₂)

Step-by-step explanation:

z = x² + y², 1 < z < 4

Surface area is:

S = ∫∫√(1 + (fₓ)² + (fᵧ)²) dA

where fₓ and fᵧ are the partial derivatives of f(x,y) with respect to x and y, respectively.

fₓ = 2x, fᵧ = 2y

S = ∫∫√(1 + (2x)² + (2y)²) dA

S = ∫∫√(1 + 4x² + 4y²) dA

For ease, convert to polar coordinates.

S = ∫∫√(1 + 4r²) dA

S = ∫∫√(1 + 4r²) r dr dθ

At z = 1, r = 1.  At z = 4, r = 4.

So 1 < r < 4, and 0 < θ < 2π.  These are the limits of the integral.

S = ∫₀²ᵖⁱ∫₁⁴√(1 + 4r²) r dr dθ

To integrate, use u-substitution.

u = 1 + 4r²

du = 8r dr

⅛ du = r dr

When r = 1, u = 5.  When r = 4, u = 65.

S = ∫₀²ᵖⁱ∫₅⁶⁵√u (⅛ du) dθ

S = ∫₀²ᵖⁱ (⅛ ∫₅⁶⁵√u du) dθ

S = ∫₀²ᵖⁱ (¹/₁₂ u^³/₂ |₅⁶⁵) dθ

S = ∫₀²ᵖⁱ (¹/₁₂ (65^³/₂ − 5^³/₂)) dθ

S = (¹/₁₂ (65^³/₂ − 5^³/₂)) θ |₀²ᵖⁱ

S = (¹/₁₂ (65^³/₂ − 5^³/₂)) (2π)

S = ⅙ π (65^³/₂ − 5^³/₂)

Please answer this correctly

Answers

Answer:

Band: 30%

Chorus: 18%

Painting: 21%

Robotics: 14%

Coding: 17%

Write the equation of the line. Slope = -4, passing through (- 1, 5)

Answers

Answer:

y=-4x+1

Step-by-step explanation:

You want to find the equation for a line that passes through the point (-1,5) and has a slope of -4.

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

To start, you know what m is; it's just the slope, which you said was -4. So you can right away fill in the equation for a line somewhat to read:

y=-4x+b.

Now, what about b, the y-intercept?

To find b, think about what your (x,y) point means:

(-1,5). When x of the line is -1, y of the line must be 5.

Because you said the line passes through this point, right?

Now, look at our line's equation so far: . b is what we want, the -4 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the the point (-1,5).

So, why not plug in for x the number -1 and for y the number 5? This will allow us to solve for b for the particular line that passes through the point you gave!.

(-1,5). y=mx+b or 5=-4 × -1+b, or solving for b: b=5-(-4)(-1). b=1.

The equation of line passes through the point (-1, 5) will be;

⇒ y = - 4x - 2

The equation of line in point-slope form passing through the points

(x₁ , y₁) and (x₂, y₂) with slope m is defined as;

⇒ y - y₁ = m (x - x₁)

Where, m = (y₂ - y₁) / (x₂ - x₁)

Given that;

The point on the line are (-1, 5).

And, The slope of line is,

⇒ m = - 4

Now,

Since, The equation of line passes through the point (- 1, 5).

And, Slope of the line is,

m = - 4

Thus, The equation of line with slope - 4 is,

⇒ y - 5 = - 4 (x - (-1))

⇒ y - 2 = - 4 (x + 1)

⇒ y - 2 = - 4x - 4

⇒ y = - 4x - 4 + 2

⇒ y = - 4x - 2

Learn more about the equation of line visit:

https://brainly.com/question/18831322

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