Answer:
66 m/s
Explanation:
v=u+at
= 0 + 5.5 * 12
= 66 m/s
A student is sitting at rest in a chair. How does the force that the student exerts
on the chair compare to the force the chair exerts on the student? *
•a larger magnitude but the opposite direction
•a smaller magnitude but the same direction
•the same magnitude but the opposite direction
•the same magnitude and the same direction
Answer:
the same magnitude but the opposite direction
Explanation:
Newton's third law of motion states that there is always an equal and opposite reaction to every action. This means that the amount of force exerted upon an object is equal to the amount of force the object exerts but in an opposite direction.
This is the case in this scenario where a student sits at rest in a chair. The student is supplying the action force being exerted on the chair. According to the third law of Newton, the chair will exert the same size of force back in the student but in an opposite direction.
Hence, the force the chair exerts on the students compare with that of the student in the sense that they are the same magnitude (size) but the opposite directions.
HELLO CAN SOMEONE HELP ME PLS
A car is moving at 35 mph and comes to a stop in 5 seconds.
Find the acceleration of the car.
Answer:
I do believe it's 7
You are walking at 3.75 km per hour across a frozen lake in the snow. You do not realize that with each step you turn 0.350 degrees to your right. If your step length is 74.0 cm what is the diameter, in meters, of the circle that you are inadvertently tracing out?
Answer:
242.27929622673 meters
Starting from rest, a car accelerates at a rate of 7.8m/s^2 for 4.9 seconds. What is it’s velocity at the end of this time?
Answer:
7.8 m/'s = Change of accelerates / time taken =7.8/4.9=
Explanation:
please solve that answer
Use metric conversion factors to solve each of the following problems:a. If a student is 175 cm tall, how tall is the student in meters?b. A cooler has a volume of 5000 mL. What is the capacity of the cooler in liters?c. A hummingbird has a mass of 0.0055 kg. What is the mass, in grams, of the hummingbird?d. A balloon has a volume of 3500 cm3. What is the volume in liters?
Answer:
a) 1.75 m
b) 5 L
c) 5.5 g
d) 3.5 L
Explanation:
a) cm -> m
1 m = 100 cm, so,
1 cm = 1/100 m
175 cm = 175/100 m
175 cm = 1.75 m
b) mL -> L
1 L = 1000 mL, so
1 mL = 1/1000 L
5000 mL = 5000/1000 L
5000 mL = 5 L
c) kg -> g
1 g = 1/1000 kg, so
1 kg = 1000 g
0.0055 kg = 0.0055 * 1000 g
0.0055 kg = 5.5 g
d) cm³ -> L
1 L = 1000 cm³, so
1 cm³ = 1/1000 L
3500 cm³ = 3500/1000 L
3500 cm³ = 3.5 L
therefore, we can conclude that 175 cm is 1.75 m, 5000 mL is 5 L, 0.0055 kg is 5.5g and 3500 cm³ is 3.5 L
Answer:
Explanation:
Answer:
a) 1.75 m
b) 5 L
c) 5.5 g
d) 3.5 L
Explanation:
a) cm -> m
1 m = 100 cm, so,
1 cm = 1/100 m
175 cm = 175/100 m
175 cm = 1.75 m
b) mL -> L
1 L = 1000 mL, so
1 mL = 1/1000 L
5000 mL = 5000/1000 L
5000 mL = 5 L
c) kg -> g
1 g = 1/1000 kg, so
1 kg = 1000 g
0.0055 kg = 0.0055 * 1000 g
0.0055 kg = 5.5 g
d) cm³ -> L
1 L = 1000 cm³, so
1 cm³ = 1/1000 L
3500 cm³ = 3500/1000 L
3500 cm³ = 3.5 L
therefore, we can conclude that 175 cm is 1.75 m, 5000 mL is 5 L, 0.0055 kg is 5.5g and 3500 cm³ is 3.5 L
For an object that experiences constant non-zero acceleration, V f = V i
True or False
Answer:false
Explanation:
Cell phones require powerful batteries in order to work effectively. Which
activity is best described as an engineering endeavor related to cell-phone
batteries?
A. Designing an investigation that will help determine where the
materials used to make them can be found
B. Performing experiments to explain how different materials used in
batteries store energy
O C. Developing a plan to convince cell-phone companies to use their
batteries
D. Improving their design to make it easier to recycle them when they
are no longer useful
The activity D. Improving their design to make it easier to recycle them when they are best described as an engineering endeavor related to cell phone batteries.
What is an engineering endeavor related to the generation of a product?An engineering endeavor related to the generation of a product can be defined as any type of solution in order to enhance a particular feature of a given product, thereby increasing its utility in order to maximize the process that leads to its use by the clients of such product and or service in the market.
Endeavor engineering generally is based on the combination between extensive discovery and product development in order to solve a particular issue related to the product.
Therefore, with this data, we can see that an engineering endeavor related to the generation of a product is aimed at enhancing a particular feature of such a product.
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PLEASEEEEEE HELP
A jet makes a landing traveling due east with a speed of 120 m/s. If the jet comes to rest in 13.5 s , what’s the magnitude of its average acceleration?
Part B: What is the direction of its average acceleration? (North, south, east, west??)
Answer:
8.89 m/s² west
Explanation:
Assume east is +x. Given:
v₀ = 120 m/s
v = 0 m/s
t = 13.5 s
Find: a
v = at + v₀
0 m/s = a (13.5 s) + 120 m/s
a = -8.89 m/s²
a = 8.89 m/s² west
How does gamma radiation differ from alpha or beta particle radiation?
1) it does not consist of matter
2) it only consists of space
3) it does not consist of energy
4) it only consists of matter
Answer:
1.
Explanation:gamma rays are the most powerful in the electromagnetic spectrum and they are a result of a radioactive atom.they aren't made of matter but just energy as a wave.
A bus is moving at a speed of 20 m/s, when it begins to slow at a constant rate of 5 m/s2 in order to stop at a bus stop. If it comes to rest at the bus stop, how far away was the bus from the stop?
Answer:
u=20m/sec
v=0
a=5m/sec^2
v^2=u^2-2as[ here acceleration is negative]
0=400-2x5xs
-400= -10s
s= 40 metre.
The bus stop is 40 m away from the point at which it starts to slow down at -5 m/s².
State third equation of motion?
The third equation of motion is -
v² - u² = 2aS
Given is a bus moving at a speed of 20 m/s. It begins to slow at a constant rate of 5 m/s² in order to stop at a bus stop.
We can write -
[u] = 20 m/s
[a] = - 5 m/s²
[v] = 0 m/s
Using the third equation of motion -
v² - u² = 2aS
- (20)² = 2 x - 5 x S
- 400 = - 10 S
S = 400/10
S = 40 m
Therefore, the bus stop is 40 m away from the point at which it starts to slow down at -5 m/s²
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A machine carries a 100kg cargo to a boat at a rate of 10m/s2. The distance between the ground to the boat is 50ft. If the machine must transfer the cargo to the boat in 5 minutes, how much power should the machine exert?
Answer:
50.8 watt
Explanation:
we know that P=W÷t
W=F.S S-->distance=50 ft= 15.24 m
F=ma
=100×10=1000 N
SO W= 1000×15.24
=15240 J
NOW
P=W÷t t=5 mints = 5×60=300 sec
P=15240÷300
P=50.8 watt
A train moves from rest to a speed of 25 m/s in 50.0 seconds. What is its acceleration?
Answer:
Wellll. I am assuming the direction of speed is in the same direction as the direction of displacement of the train. (i.e. Velocity is positive)
Acceleration is defined as the rate of change of velocity with respect to time (m^s-2)
Explanation:
A woman on a snowmobile moving with a constant velocity east down the road fires a flare straight upward and the snowmobile continues to move with a constant
velocity as the flare is in the air. Assume no air resistance. Where will the flare land?
A) it will hit the person on the snowmobile who fired the flare
B) Somewhere behind the snowmobile, depends on velocity
C) in front of the snowmobile
D) Impossible to know
E) behind the snowmobile in exactly the same location (relative to the ground) from which it was fired
The velocity of sound is generally greater in solids than in gases at NTP. Why?
Answer:
Because they are so close, than can collide very quickly, i.e. it takes less time for a molecule of the solid to 'bump' into its neighborough. Solids are packed together tighter than liquids and gases, hence sound travels fastest in solids.
Tammy jogged 350 meters at a velocity of 7 m/s. How long did it take her to jog this distance?
Answer:
50 seconds
Explanation:
divide 350 by 7...
add my tik(tok) slapddaddy
3. Will a plant grow higher with more light?
a. Hypothesis + Prediction:
b. Independent Variable (IV):
c. Dependent Variable (DV):
d. Controlling Variable (CV):
e. Experiment:
Answer:
When we analyze the sentence we see that this is a hypotype with the growth of plants must behave and it has a prediction included.
Therefore the correct answer is a
Explanation:
In this exercise you are asked to identify the given sentence with a specific part of the scientific method.
Among the parts of the method we have.
* Independent variable . The controlled variable in research
*Dependent variable. The magnitude measured in the experiment
* Control variable. The magnitude that is not controlled
*Experiment. It is the design of the procedure to evaluate the hypothesis
* Hypothesis. It is the assumption with which scientific work begins
* Prediction. It is a consequence of work if the mortgage is correct.
When we analyze the sentence we see that this is a hypotype with the growth of plants must behave and it has a prediction included.
Therefore the correct answer is a
Joelle is a manager at a construction company, and she is interested in the chemistry behind the materials they use. She has begun studying the materials used to fill walls. She knows that to keep the temperature inside a room steady the material must be a thermal insulator, and she predicts that materials should not be acidic or else they would dissolve too easily in water. Which is most likely a molecule in a wall-filling material? C6H6 Na6Ba6 NeNa HCl
Answer:
C6H6
Explanation:
I just took the test.
The only compound in the given options that is not soluble in water at normal condition is benzene (C₆H₆).
The material used in the wall-filling cannot be acidic or acidic salts. Acids and acidic salts have the tendency to dissolve in water.
An acid salt is a type of salt that can produce an acidic solution when it dissolves in water or other solvents.
In given compounds we can eliminate the possible acids and acid salts or water soluble compounds.
compounds of sodium are soluble in water (eliminate Na₆Ba₆ and NeNa)Hcl is acid which will dissolve in waterThus, the only compound in the given options that is not soluble in water at normal condition is benzene (C₆H₆).
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Is it possible to accelerate and not speed up or slow down?
Answer: No,
explanation: When the object is neither speeding up or slowing down, we can say that its speed is constant.
Hope this helps
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In April 1974, Steve Prefontaine completed a 10.0 km10.0 km race in a time of 27 min27 min , 43.6 s43.6 s . Suppose "Pre" was at the 7.85 km7.85 km mark at a time of 25.0 min25.0 min . If he accelerated for 60 s60 s and then maintained his increased speed for the remainder of the race, calculate his acceleration over the 60 s60 s interval. Assume his instantaneous speed at the 7.85 km7.85 km mark was the same as his overall average speed up to that time.
Answer:
a = 0.161 [tex]$m/s^2$[/tex]
Explanation:
Given :
[tex]$ d_{total}[/tex] = 10 km = 10000 m
[tex]$t_{total} $[/tex] = 27 min 43.6 s
= 1663.6 s
[tex]$d_1$[/tex] = 7.85 km = 7850 m
[tex]$t_1$[/tex] = 25 min = 1500 s
[tex]$t_2$[/tex] = 60 s
Now the initial speed for the distance of 7.85 km is
[tex]$ v_1 = \frac{d_1}{t_1} = \frac{7850}{1500}$[/tex] = 5.23 m/s
The velocity after 60 s after the distance of 7.85 kn is
[tex]$v_2 = v_1 + at_2$[/tex]
= 5.23 + a(60)
The distance traveled for 60 s after the distance of 7.85 km is
[tex]$d_2 = v_1t_2+\frac{1}{2}at_2^2$[/tex]
[tex]$d_2 = (5.23)(60)+\frac{1}{2}a(60)^2$[/tex]
= 313.8 + a(1800)
The time taken for the last journey where the speed is again uniform is
[tex]$t_3 = t_{total}-t_1-t_2 $[/tex]
= 1663.6 - 1500 - 60
= 103.6 s
Therefore, the distance traveled for the time [tex]$t_3$[/tex] is
[tex]$ d_3 = v_2 t_3$[/tex]
= (5.23+60a)(103.6)
= 541.8 + 6216 a
The total distance traveled,
[tex]$ d_{total}= d_1 + d_2 + d_3$[/tex]
Now substituting the values in the above equation for the acceleration a is
10000 = 7850 + (313.6 + 1800a) + (541.8 + 6216a)
10000 = 8706.5 + 8016a
1294.4 = 8016a
a = 0.161 [tex]$m/s^2$[/tex]
As it heats, does fluid rise or compact
s
Answer: The fluid would rise.
An earthquake releases two types of traveling seismic waves, called transverse and longitudinal waves. The average speed of the transverse and longitudinal waves in rock are 8.8 km/s and 5.9 km/s respectively. A seismograph records the arrival of the transverse waves 69 s before that of the longitudinal waves. Assuming the waves travel in straight lines, how far away is the center of the earthquake
Answer:
1239.216 km
Explanation:
The speed of the transverse = 8.8km/s
The speed of the longitudinal = 5.9km/s
distance = speed x time,
8.8km/s x trans_time = 5.9km/s x long_time
8.8 / 5.9 = long_time / trans_time
1.49 = long_time / trans_time
long_time = 1.49 trans_time
the transverse wave was 69s faster than longitudinal,
trans_time - long_time = 69s
trans_time - 1.49trans_time = 69s
0.49 trans_time = 69
trans_time = 69 / 0.49 = 140.82s
long_time = 140.82 - 69 = 71.82s
the distance of the earthquake;
distance = 8.8 x 140.82 = 1239.216 km
A ball is thrown straight upward with a speed of 36 m/s. How long does it take to return to its starting point, assuming negligible air resistance?
Answer:
The time taken for the ball to return to the starting point is is 7.4 s
Explanation:
Given;
initial velocity of the ball, u = 36 m/s
the final vellocity at maximum height, v = 0
let time taken for the ball to reach maxmimum height = t
Time taken for the ball to return to the starting point is known as time of flight, calculated as;
[tex]t = \frac{v-u}{-g} \\\\T = 2t\\\\T = \frac{2(0-u)}{-g}\\\\T = \frac{-2u}{-g}\\\\ T = \frac{2u}{g}[/tex]
T = (2 x 36) / 9.8
T = 7.4 s
Therefore, the time taken for the ball to return to the starting point is is 7.4 s
If a moving clock is ticking half as fast as normal what speed is the clock traveling?
Answer:
Speed of moving clock is
[tex]V2[/tex] =πr/(86400) m/s
Here,
m and s are SI units of distance and time respectively.
Explanation:
If
radius of circular clock= r
than,
total distance covered on clock=S=2πr m
here, m=SI unit of distance
and required time for covering the total distance=t= 86400s
speed of normal clock=[tex]V1[/tex]=S/t
[tex]V1[/tex]=2πr/86400 m/s
As, moving moving clock is ticking half as fast as normal clock so,
speed of moving clock=[tex]V2[/tex]=[tex]V1[/tex]/2
[tex]V2[/tex]=2πr/(86400)*2 m/s
[tex]V2[/tex] =πr/(86400) m/s
What are the benefits of living in a country with a growing population rate?
Answer:
The benefits are the place you live in will have more oppurtunities for new jobs as well as growth in residential areas.
Explanation:
A positive and a negative charge are released from rest in vacuum. They move toward each other. As they do: A positive and a negative charge are released from rest in vacuum. They move toward each other. As they do: A negative potential energy becomes less negative. A positive potential energy becomes a negative potential energy. A positive potential energy becomes more positive. A negative potential energy becomes more negative. A positive potential energy becomes less positive. SubmitRequest Answer
Answer:
A negative potential energy becomes more negative
Explanation:
Let the charges be - Q₁ and Q₂ . Let the distance between them be d .
Potential energy = k -Q₁x Q₂ / R
= - KQ₁ Q₂ / R
Now if the magnitude of R decreases , the magnitude of potential energy increases . So we see that the negative potential energy becomes more negative .
Lab reporton motin please help me answer all queastions 1-11 thank you
Answer:
yor welcome
Explanation:
hi
A cue stick has a mass of 0.5 kg. The cue stick hits a ball with a mass of 0.2 kg at a velocity of 2.5 m/s. What is the velocity of the ball after it is hit?
Answer:
1 m/s.
Explanation:
Given that,
Mass of a cue stick, m₁ = 0.5 kg
Mass of a ball, m₂ = 0.2 kg
The cue stick hits a ball with a velocity of 2.5 m/s
We need to find the velocity of the ball after it is hit. Tn this problem, the momentum of the system remains conserved. So,
m₁v₁ = m₂v₂
⇒ [tex]v_1=\dfrac{m_2v_2}{m_1}\\\\v_1=\dfrac{0.2\times 2.5}{0.5}\\\\v_1=1\ m/s[/tex]
So, the velocity of the ball after it is hit is 1 m/s.
Answer:
The moment of impact quick check (connexus academy)
Explanation:
Q.Which mathematical representation correctly identifies impulse?
A.impulse=force×time
Q.In a closed system, a ball with a mass of 3 kg and a momentum of 24 kg·m/s collides into a ball with a mass of 1 kg that is originally at rest. Which statement describes the momentum of the balls and the total momentum?
A.The momentum of each ball changes, and the total momentum stays the same.
Q.In a closed system, three objects have the following momentums: 110 kg⋅m/s, −65 kg⋅m/s, and −100 kg⋅m/s. The objects collide and move together. What is the total momentum after the collision?
A.−55 kg⋅m/s
Q.In a closed system, an object with a mass of 1.5 kg collides with a second object. The two objects then move together at a velocity of 50 m/s. The total momentum of the system is 250 kg⋅m/s. What is the mass of the second object?
A.3.5 kg
Q.A cue stick has a mass of 0.5 kg. The cue stick hits a ball with a mass of 0.2 kg at a velocity of 2.5 m/s. What is the velocity of the ball after it is hit?
A.6.3 m/s
what would the answer be ?
which of the following has the greatest inertia ping pong ball, golf ball, softball, and a bowling ball
Answer:
bowling ball
Explanation:
A bowling ball has more mass than the others, thus having more inertia.
A mass on a string of unknown length oscillates as a pendulum with a period of 1.8 s. What is the period in the following situations? (Parts (a) to (d) are independent questions, each referring to the initial situation.)(a) The mass is doubled?(b) The string length is doubled?(c) The string length is halved?(d) The amplitude is doubled?
Answer:
Using
Period ( P) is given as
P~√(L/g).
a) since mass has no effect on the period of a pendulum. So, the period will remain 1.8seconds
b) using the formula above ,period varies with the square root of the length. Thus , when the length doubles, the period is multiplied by √2. So, the period is 1.8s*√2 = 2.54s
c) in this case, the period is multiplied by √(1/2).
1.8√(1/2)=1.27s.
d) amplitude of the pendulum doesn't affect the period (unless itsvery high, so, the period is still 1.8s
