9. a cluster of galaxies is observed to have a recessional velocity of 60,000 km/s. find the distance to the cluster.

Answers

Answer 1

The distance to the cluster is 2.86 billion lightyears. So the correct answer is B. 2.86 billion lightyears.

Distance is a measure of how far apart two objects are from each other. It can be expressed in a variety of units, such as meters, kilometers, miles, or lightyears. In physics and astronomy, distance is often used to describe the separation between two objects in space, such as planets, stars, or galaxies. Distance is an important concept because it helps us understand the size and scale of the universe and how objects within it are related to each other.

To calculate the distance to the cluster of galaxies, we can use the formula:

Distance = (Recessional velocity) / (Hubble constant)

Plugging in the values:

Distance = (60,000 km/s) / (21 km/s/million lightyears)

Distance = 2,857,142.857 million lightyears

Distance = 2.86 billion lightyears

The missing part in the question is shown below.

A cluster of galaxies is observed to have a recessional velocity of 60,000 km/s. find the distance to the cluster. (Assume a hubble constant of 21 km/s per million lightyears).

A. 2.70 billion lightyears

B. 2.86 billion lightyears

C. 1.30 million lightyears

D. 1.26 billion lightyears

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Related Questions

The kinetic friction force between a 55.0 kg and a horizontal surface is 45.N IF THE initial speed of the object is 24.0m/s and a friction is the only force acting on the object what distance will it slide before coming to a stop

Answers

The distance the 55.0 Kg object will slide before coming to rest, given that it was it was initially tracing at 24 m/s is 351.22 m

How do I determine the distance?

First, we shall obtain the deceleration of the object. Details below

Mass (m) = 55.0 KgForce of friction (F) = -45 NDeceleration (a) = ?

F = ma

Divide both sides by m

a = F / m

a = -45 / 55

a = -0.82 m/s²

Finally, we shall determine the distance the object will slide before coming to rest. Details below

Initial velocity (u) = 24 m/sFinal velocity (v) = 0 m/s Deceleration(a) = -0.82 m/s²Distance (s) =?

v² = u² + 2as

0² = 24² + (2 × -0.82 × s)

0 = 576 - 1.64s

Collect like terms

0 - 576 = -1.64s

-576 = -1.64s

Divide both side by -1.64

s = -576 / -1.64

s = 351.22 m

Thus, we can conclude that the distance is 351.22 m

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Organizational commitment has been found to be positively correlated with all of the following except
an employee's age

an employee's time on the job.

an employee's level of education

the current job market.

2 points

QUESTION 2

Shannon is given random bonuses of varying amounts throughout the year based on "how well the company is doing." She is being reinforced using a
fixed ratio schedule.

variable ratio schedule.

fixed interval schedule.

variable interval schedule.

2 points

QUESTION 3

Glass created a computer game experiment whose results indicated that Type A subjects?
Showed a significantly higher physiological stress response rates than the Type B subjects, but recovered back to baseline rates as quickly as the Type Bs.

Showed significantly lower physiological stress response rates than the Type B subjects.

Showed similar physiological stress response rates to the Type B subjects in the game, but had a signficantly higher stress response to the "harrass" condition.

Showed significantly higher stress response rates but beat the game more times than the Type B subjects.

2 points

QUESTION 4

According to goal-setting theory, the key determinants of motivation in the workplace are
job satisfaction and the accomplishment of goals.

monetary incentives associated with meeting goals.

specific, challenging opportunities and commitment to goals.

specific, challenging opportunities and organizational policies directed at goal attainment.

2 points

QUESTION 5

There is a negative correlation between age and voluntary absenteeism.

True
False
1

Answers

1) Current Job Market 2) Variable Ratio Schedule 3) Showed significantly lower physiological stress response rates than the Type B subjects.4) Specific challenging activities and commitment to goals 5) True.

Various research studies have proved that an employee's age, tenure, and level of education positively correlates with organizational commitment. A variable-ratio schedule is a reinforcement where conduct is strengthened after an irregular number of reactions. According to Locke's Goal Setting theory, human actions are purposeful and are directed by conscious goals and the challenging nature of opportunities.

When a behavior is reinforced after a random number of answers, it is said to be on a variable ratio schedule. A high, consistent rate of response is produced by this form of timetable. Because of the chance that the subsequent response will be the one required to get reward, organisms are persistent in responding.

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Label the photomicrograph of compact bone. Osteocyte Central canal Osteon Canaliculus Lacuna Lamella Central canal Cement line Canaliculus Interstitial lamella Osteocyte Osteon

Answers

Labeling the photomicrograph of compact bone is done from right to left anticlockwise:

1) Osteon

2) Central Canal

3)cement Line

4) Lamella

5) Lacuna

6) Canaliculus

7) Interstitial Lamella

8) Osteocyte

Discuss each photomicrograph of compact bone.

1) Osteon: Osteon is the units in the compact tissue. Osteons are cylindrical structures that contain a mineral matrix and living osteocytes connected by canaliculi, which transport blood.

2) Central Canal: The osteon consists of a central canal called the osteonic canal. It is surrounded by concentric rings of the matrix. The osteonic canals contain blood vessels that are parallel to the long axis of the bone.

3) Cement Line: The cement line, is the interface between the fibers and extraosteonal bone matrix. cement line is a region of reduced mineralization that may contain sulfated mucosubstances.

4) Lamella: Each osteon consists of concentric layers, or lamellae, of compact bone tissue that surround a central canal. lamellae are arranged parallel to the surface; these are called circumferential lamellae.

5) Lacuna: Nucleated bone cells and their processes, contained in the bone lacuna and their canaliculi respectively. lacuna is a small space containing an osteocyte in bone or chondrocyte in cartilage.

6) Canaliculus: Canaliculus is the small channels that radiate from the lacunae to the osteonic canal to provide passageways through the hard matrix.

7) Interstitial Lamella: The bone between the osteons is called interstitial lamellae.

8) Osteocyte: Osteocytes occupy spaces (lacuna) in the bone matrix. It maintains the bone matrix. It is at an earlier stage of development that formed the bone matrix.

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on a snowy day, when the coefficient of friction μs between a car's tires and the road is 0.50, the maximum speed that the car can go around a curve is 14 mph.

Answers

The maximum speed that the car can go around a curve is 14 mph is 28.1 mph.

What is speed?

The speed at which an object's location changes in any direction. The distance traveled in relation to the time it took to travel that distance is how speed is defined. Since speed simply has a direction and no magnitude, it is a scalar number.

The force of friction acting on the car provides the centripetal force that keeps the car in circular motion around the curve, so we can write:

[tex]F=\mu m g=m \frac{v^2}{r} \text { (1) }[/tex]

where

[tex]$\mu$[/tex] is the coefficient of friction

[tex]$\mathrm{m}$[/tex] is the mass of the car

[tex]$\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^{\wedge} 2$[/tex]is the acceleration due to gravity

[tex]$\mathrm{V}$[/tex] is the maximum speed of the car

r is the radius of the trajectory

On the snowy day,

[tex]$$\begin{aligned}& \mu=0.50 \\& v=20 \mathrm{mph}=8.9 \mathrm{~m} / \mathrm{s}\end{aligned}$$[/tex]

So the radius of the curve is

[tex]r=\frac{v^2}{\mu g}=\frac{(8.9)^2}{(0.50)(9.8)}=16.1 \mathrm{~m}$$[/tex]

Now we can use this value and re-arrange again the eq. (1) to find the maximum speed of the car on a sunny day, when [tex]$\mu=1.0$[/tex]. We find:

[tex]v=\sqrt{\mu g r}=\sqrt{(1.0)(9.8)(8.9)}=12.6 \mathrm{~m} / \mathrm{s}=28.1 \mathrm{mph}$$[/tex]

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Cigarettes Can Be Used As A Form Of ________. Fiat Money Fake Money Barter
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See Answer
Cigarettes can be used as a form of ________.

fiat money

fake money

barter

Answers

Cash in dollars. Fiat money refers to any forms of currency that are issued by governments or central banks but are not backed by anything.

What types of exchange mechanisms are examples?

When money is used as a medium of exchange, it speeds up transactions between buyers and sellers because it is commonly accepted as payment for goods and services. Although most societies use money, other exchange methods have included tobacco, salt, gold, and stones.

Exactly what qualifies as a medium of exchange?

A medium of exchange is a device or system that acts as a middleman in transactions involving the exchange of goods between parties. Currency serves as the primary means of exchange in modern economies.

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a block of ice at 0 is sliding on a horizontal surface. the inital speed of the ice is 7.90 and the final speed is 3.80. determine mass of ice that melts

Answers

Given, mass of block 30kg, initital velocity 6.1m/s, final velocity=4.5m/s, change in kinetic energy= mvi^2/2-mvi/2- mvf2/2, KE= 254.4J change in KE= heat generated by friction L=3.4*10^5J/kg, 254.4= m*3.4*10^5, m=0.748gm.

In physics, how do you solve for mass?

There are numerous methods for calculating an object's mass, including:

Mass Equals volume * density (m = V). The mass of an object can be calculated by multiplying its density by its volume because density is a measure of mass per unit of volume. Mass equals force times acceleration (m=F/a). Gravitational acceleration and mass are equal (m=W/g).

What is the center of mass formula?

Center of Mass in a System of Two Particles (m1+m2) rcm equals (m1 r1+m2 r1). The sum of the products of the masses of the two particles and their respective position vectors equals the product of the total mass of the system and the position vector of the center of mass.

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a 50-turn coil has a diameter of '17cm'. the coil is placed in a spatially uniform magnetic field of magnitude so that the face of the coil and the magnetic field are perpendicular. find the magnitude of the emf, , induced in the coil if the magnetic field is reduced to zero uniformly

Answers

The magnitude of the emf induced in the coil is - 1.134 dB/dt. If the initial magnitude of the magnetic field 0.5 T in 0.5 s is reduced to zero uniformly the magnitude of the emf induced in the coil is 1.134 Volt.

The formula to calculate the magnitude of the emf induced in the coil when the magnetic field is perpendicular to the face of the coil

ε = - NA dB/dt

[tex]\epsilon \:=\: - NA \frac{dB}{dt}[/tex]

where

N = the number of turns in the coil = 50A = the surface area of ​​the coil (m²)dB = the change in magnetic induction
dB = B₁ - B₀
B₀ = the initial magnetic induction (Tesla)
B₁ = the final magnetic induction (Tesla) = 0 Tdt = the time interval (s)

The surface area of the coil is a circle A = πr²

d = 17 cmr = 17 ÷ 2 = 8.5 cm = 0.085 mA = 3.14 × 0.085² A = 0.0227 m²

ε = - NA dB/dt

ε = - 50 × 0.0227 × dB/dt

ε = - 1.134 dB/dt

The problem is not complete. It should tell the initial magnitude of the magnetic field and the interval time.

If B₀ = 0.5 T and dt = 0.50 s
[tex]\epsilon \:=\: - 1.134 \frac{0 - 0.5}{0.5}[/tex]
[tex]\epsilon \:=\: - 1.134 \frac{- 0.5}{0.5}[/tex]
ε = 1.134 VoltIf B₀ = 0.5 T and dt = 5.0 s
[tex]\epsilon \:=\: - 1.134 \frac{0 - 0.5}{5.0}[/tex]
[tex]\epsilon \:=\: - 1.134 \frac{- 0.5}{5.0}[/tex]
ε = 0.1134 VoltIf B₀ = 0.5 T and dt = 50 s
[tex]\epsilon \:=\: - 1.134 \frac{0 - 0.5}{50}[/tex]
[tex]\epsilon \:=\: - 1.134 \frac{- 0.5}{50}[/tex]
ε = 0.01134 Volt

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a thin glass rod is submerged in water. part a what is the critical angle for light traveling inside the rod?

Answers

The critical angle is 76.7°

What is the critical angle of light?

The value of this critical angle is given by where n2 is the refractive index of the second medium and n1 is the refractive index of the first medium. When light travels from a medium with a higher refractive index to a medium with a lower refractive index, the critical angle is the angle of incidence above which light is only reflected (no refraction occurs).

The critical angle in this problem is given by because the first medium in it is glass and the second one is oil.

critical angle = arc sin (1.46/ 1.50 )

critical angle = arc sin ( 0.973 )

critical angle = 76.7°

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Which of the following is the unit of coefficient of radiant heat transfer?
a) W/m2
b) W/m K
c) W/m2 K
d) W/K

Answers

Watts per square meter kelvin (W/m2K), the SI values for the heat transfer coefficient, are used. Radiation, convection, and conduction are the three mechanisms by which heat may be transferred.

Describe heat transmission in detail:

Any or all of the several processes known as heat transfer are assumed to act as transporters of energy and entropy from one location to another. The specific mechanisms are also known by the terms convection, heat radiation, and conduction.

How is heat transfer demonstrated?

Conduction: When you hold a hot cup of coffee, heat is transferred into your hands. Convection: When the barista "steams" cold milk to produce hot chocolate, heat is transferred. Radiation: Microwave-heating a cold cup of coffee

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consider each of the electric- and magnetic-field orientations given next. in each case, what is the direction of propagation of the wave? (a) es in the x-direction, bs in the y-direction; (b) es in the -y-direction, bs in the x-direction; (c) es in the z-direction, bs in the -x-direction; (d) es in the y-direction, bs in the -z-direction.

Answers

The direction of the propagation of the wave is -x direction.

The direction of the propagation of the wave in each case are:

A) +z direction

B) +z direction

C) -y direction

D) -x direction

\vec Ein is the Electrical field vector and \vec Bin is the Magnetic field vector, because the field vectors are always perpendicular to each other the propagation of the wave is perpendicular to the two vectors. The direction of the propagation of the wave can be found by \vec Ein X \vec Bin (Cross product of two vectors). This can also be done by using the RIGHT HAND RULE.

Cross product can be found by

i x j = k and j x i = - k

j x k=i and k x j = - i  

k x i=j and i x k = - j

where i represents the +x direction, j represents the +y direction and k represents the +z direction

The RIGHT HAND RULE can be used to illustrate the cross product by using the right hand and pointing the index finger in the direction of the first vector and the middle finger along the second vector, the cross product is in the direction of the thumb.

A) \vec Ein the +x direction,\vec Bin the +y direction,

Finding the cross product of the two vectors (i x j = k) would give a vector in the +z direction

B) \vec Ein the -y direction,\vec Bin the +x direction

Finding the cross product of the two vectors (- j x i = k) would give a vector in the +z direction

C) \vec Ein the +z direction,\vec Bin the -x direction

Finding the cross product of the two vectors (k x - i = - j) would give a vector in the -y direction

D) \vec Ein the +y direction,\vec Bin the -z direction

Finding the cross product of the two vectors (j x - k = - i) would give a vector in the -x direction

The direction of the propagation of the wave is -x direction.

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what is the velocity of a 900-kg car initially moving at 3000 cm/s, just after it hits a 150-kg deer initially running at 12000 mm/s in the same direction? assume the deer remains on the car.

Answers

The velocity of car is v= 27.42 m/s.

Given;-

the 900 kg car initially moving at 30 m/s and just after it hits a 150 kg deer initially run at 12 m/s in the same direction are:-

m1 = 900kg

m2= 15okg

v1= 30 m/s

v2= 12 m/s

so, velocity is

v=(900*30 + 150*12)/(900+150)

v= 27.42 m/s.

What happens when two things collide in terms of velocity?

When two objects collide, they are both subject to forces that are equal in strength and directed in opposite directions. Such forces frequently result in the acceleration of one object and the deceleration of the other object (lose momentum).

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(13%) Problem 7: Consider the Lyman series for atomic transitions in hydrogen: 50% Part Calculate the wavelength the first line in the Lyman series, in nanometers 50% Part (b) What type of electromagnetic radiation is it?'

Answers

The wavelength of the first line in the Lyman series of the hydrogen spectrum is equal to 121.6 nm and it will be ultraviolet radiation.

When an electron transitions from its lowest energy state of n = 1 to n = 2 (where n is the main quantum number), the Lyman series, a hydrogen spectral series of transitions and ultraviolet emission lines are produced. The transitions are given Greek letter names, such as Lyman-alpha, which goes from n = 2 to n = 1.

Given Z = atomic number and R = Rydberg's constant (109677 cm-1)

since for the first line of the Lyman series, the electron is de-exited from the excited state (i.e., n2=2) to the ground state (i.e., n1=1).

1/∧ =R(1/n1^2- 1/n2^2)

1/∧= 109677(1/1 - 1/4)= 109677(3/4) = 121.6nm

As a result, we know that the wavelength of the first line in the Lyman series of the hydrogen spectrum is equal to 121.6 nm. As the range of ultraviolet radiation is from 100 nm to 400 nm. So it will be ultraviolet radiation.

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find the magnitude of the acceleration acm of the center of mass of the spherical shell. take the free-fall acceleration to be g = 9.80 m/s2 .

Answers

The acceleration of center of mass of spherical shell = 2.94 [tex]m/s^{2}[/tex]

What is center of mass ?

A position established in relation to an object or set of objects is the center of mass. It is the average location of all the pieces of the system, weighted according to their masses.

According the given information

Two forces act along the line of motion. Gravity down the slope,

m g sin([tex]\alpha[/tex]), and friction up the slope, F. They provide the linear acceleration and F also provides the torque about the Center of mass. This gives the equations of motion:

m a = m g sin([tex]\alpha[/tex]) - F

I dV/dt = F R

A spherical shell of mass m has moment of inertia I = 2/3 m R^2. Furthermore a pure rolling relates dV/dt and a through a = R dV/dt. So the two equations become

m a = m g sin([tex]\alpha[/tex]) - F

2/3 m a = F

These we solve for a and F:

Substituting F from the second equation gives

m a = m g sin([tex]\alpha[/tex]) - 2/3 m a

a = 3/5 g sin([tex]\alpha[/tex])

a = 3/5 × 9.80m/s^2 sin(30.0) = 2.94 [tex]m/s^{2}[/tex]

The acceleration of center of mass of spherical shell = 2.94 [tex]m/s^{2}[/tex]

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Describe specific heat and explain one way that this is important to humans.

Answers

Water has a high specific heat, thus it takes a lot of heat to raise its temperature. This keeps the surroundings from getting overly hot or chilly.

Why is specific heat crucial for the human body?A substance can absorb more heat energy before changing when it has a high specific heat. 70% of the human body is made up of water. Thus, the high specific heat of water ensures that the body's temperature is maintained. Additionally, it functions as a heat energy regulator.Water has a high specific heat, thus it takes a lot of heat to raise its temperature. This keeps the surroundings from getting overly hot or chilly. Humans contain around 66% water, so this feature of water also aids in the regulation of our body temperature.    

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calculate the force of earth's gravity on a spacecraft 2.50 earth radii above the earth's surface if its mass is 1200 kg .

Answers

Determine the gravitational pull of the Earth on a spaceship. If its mass is 1850 kg, it is 2.00 Earth radii above the surface of the planet. A spacecraft experiences gravity at a force equal to its weight.

The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. The height of the spacecraft is 2.00 earth radii. Consequently, the gravitational force equation is given by, The spacecraft is three times as far from the Earth's centre since it is 2.00 Earth radii above the planet's surface. There are spacecraft at a height of.

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the command module of the apollo spacecraft can be modelled as a truncated cone with a base diameter of 3.90 meters, a diameter at the upper (apex) end of 1.30 meters, and a length of 3.50 meters. the magnitude and direction of the earth's magnetic field do not vary significantly over a distance the size of the spacecraft. if the spacecraft is oriented while in orbit so that its long axis is parallel to the earth's magnetic field, which has a magnitude of 0.500 x 10-4 t, what is the amount of magnetic flux which passes through the sloping sides of the spacecraft (that is, excluding the base and top surface)?

Answers

The amount of magnetic flux which passes through the sloping sides of the spacecraft=28.57×10^-4Tm^2.

Amount of magnetic flux  is given by

                   Ф=B.Acosθ

since , the magnetic  field is parallel to area(sloping area) so, θ=0

                     Ф=B.Acos0=BA

       Hence,   B=1.0×10^-4T

                       A=π(R+r)h=3.14×(3.90+1.3)/2×35

                       A=28.57m^2

        so , magnetic flux

                                Ф=1.0×10^-4×28.57=28.57×10^-4Tm^2

   Magnetic Flux :

Specifically in electromagnetism, the magnetic flux through a surface is the integral of the normal component of the magnetic field B across that surface. Usually displayed as Φ or ΦB. The SI unit of magnetic flux is Weber and the CGS unit is Maxwell.

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superposition of waves can produce a) a larger wave. b) a smaller wave. c) no wave. d) all the above

Answers

The superposition of two waves can produce a smaller wave, a larger wave and no wave as well.

When any two waves travel along the same medium and they overlaps each other, there amplitude overlaps each other, this phenomena is known as superposition of two waves.

When any two waves interferes with each other they can form a wave of greater amplitude, smaller amplitude or even of equal magnitude.

Whether there will be a wave of larger or smaller amplitude it depends totally on the kind of interference taking place.

If the interference is constructive the wave amplitude it supposed to be larger but if the wave interferences destructive than the amplitude of the wave is supposed to be smaller.

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what should you point out on a demonstration drive when depressing 2023 versa throttle three-quarters of the way to the floor

Answers

You should emphasize during a test drive that the 2021 Versa's CVT replicates shifts like an ordinary automatic transmission by depressing the accelerator approximately 75% of the way to the floor.

Explain the term demonstration drive?A test drive is indeed the act of operating a motor vehicle to evaluate its general operational condition, drivability, and roadworthiness. A test driver is a person who tests cars for a living, whether for an automaker, the automotive press for reviews, or a racing team.

You should emphasize during a test drive that the 2021 Versa's CVT replicates shifts like an ordinary automatic transmission by depressing the accelerator approximately 75% of the way to the floor.

Engine noise that would usually result from continuous acceleration at high revs is reducedAnother more linear acceleration sensation is present.

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why can't you get all the dust off your car by just squirting water from a hose onto it? why can't you simply remove dust just by blowing across a surface? why does dust cling to a fast rotating fan? how can a leaf stay on a car moving at high speed?

Answers

It all happens because of the law of Inertia.

The Newton's first law which is also called the law of inertia states that when a body is moving or at rest, it tends to be in the same state state until an external force is applied to it.

The dust particles can't be removed just by squirting water as the water may become stagnant and the dust particles will get mixed up with water by making a heterogenous mixture and they can remain there. Thus, a large pressure should be applied with a large amount of force which can remove the particles.

The same goes with other dust particles, they can't be removed until an external force is applied so that they leave the surface and fall off. Here, newton's first and second law works.

The leaf remains on the car because the force applied by the air on the opposite is more to make the leaf stay or sometimes they get stuck in a part of a car from where it can't be flown until a great amount of force is applied. Here, Newton's third law works.

Therefore, everything is controlled by the Newton's laws of motion.

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on a violin, a correctly tuned string has a frequency of 460 hz. if the string produces a sound at 510 hz when under a tension of 25.0 n, what should the tension be to produce the correct frequency?

Answers

The tension be to produce the correct frequency is 306N

What is the frequency?

The frequency of a repeated event is its number of instances per unit of time. It differs from angular frequency and is sometimes referred to as temporal frequency for clarification. One event occurs per second when measuring frequency in hertz.

f= 1/2L[tex]\sqrt[/tex] μT

so

fα[tex]\sqrt[/tex] T

∴ f 1/f 2 = [tex]\sqrt[/tex]T 1/T 2

In our example, f 1 = 460 Hz, and T 1 =?

​and for f = 510 Hz, T 2 = 255.

510/460  = [tex]\sqrt[/tex]T 1/255.

∴T 1 =( 510/510 )=306N.

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when the outer layers of a star like the sun expand, and it becomes a giant, which way does it move on the h-r diagram?

Answers

When a star's outer layers, which are similar to the sun's, expand, the star travels upward and becomes cooler and more bright than the sun.

What is a star ?

Most galaxies have stars distributed throughout them that are born within dust clouds. The Orion Nebula is a well-known illustration of a dust cloud of this type. Even though stars are not alive, we refer to their beginnings and endings as "birth and death." It's a useful, though fantastical, approach to explain the star's ultimately disastrous interaction with matter and energy.

The outer layers start to enlarge, chill, and lose some of their radiance. The name "Red Giant" now refers to the growing star. Convection moves the energy from the shell-burning zone to the star's outer layers. The brilliance of the star eventually rises by a factor of 1000 or so. On the HR diagram, the star will move up and to the right along the Red Giant Branch during this phase of growth.

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you are attempting to create a standing wave with n = 7 in a pipe .50m in length and filled with air. the top of the pipe is open to the ait and the bottom of the pipe is barely submerged in water and thus closed. draw the diagram for this standing wave with the proper nodes and antinodes for this open- closed pipe. what is the frequency?

Answers

The top of the pipe is open to the air and the bottom of the pipe is barely submerged in water and thus closed is 1200.5Hz

[tex]Wavelength =[/tex] λ = [tex]\frac{4L}{7}[/tex]

[tex]Frequency =[/tex] v× 1/λ = 343 ×[tex]\frac{1}{4l/7}[/tex]

[tex]f[/tex] = [tex]\frac{7*343}{4L}[/tex] = [tex]\frac{7*343}{4*0.5}[/tex] = [tex]f = 1200.5Hz[/tex]

In physics, the wavelength is the spatial length of a periodic wave—the distance over which the wave's form repeats. it is the space between consecutive corresponding factors of the same section on the wave, consisting of adjoining crests, troughs, or 0 crossings, and is a characteristic of both visiting waves and standing waves, in addition to other spatial wave patterns. The inverse of the wavelength is known as the spatial frequency. Wavelength is generally particular via the Greek letter lambda (λ). The time period wavelength is likewise once in a while applied to modulated waves, and to the sinusoidal envelopes of modulated waves or waves shaped by means of interference of several sinusoids.

Assuming a sinusoidal wave transferring at a hard and fast wave velocity, the wavelength is inversely proportional to the frequency of the wave: waves with better frequencies have shorter wavelengths, and lower frequencies have longer wavelengths.

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what is the number n of the highest harmonic that could be heard by a person who is capable of hearing frequencies up to f

Answers

The 24th harmonic is the highest that could be heard  by a person.

A wave or signal that is harmonic has a frequency that is an integral (whole number) multiple of the frequency of the source signal or wave that it is being compared to. The frequency of such a signal or wave relative to the frequency of the reference signal or wave is also referred to as a component of the harmonic series by the word. The first harmonic is sometimes referred to as the basic frequency or initial wave. Higher harmonics are the next harmonics in the series. In addition to the total number of harmonics being periodic at that particular frequency, the fundamental frequency of all harmonics is also.

The word "harmonic" is used in a variety of industries, including music, radio, and all other wave-based technologies.

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different masses are hung on a spring scale calibrated in newtons. the force exerted by gravity on 1.0 kg is shown in the image below in newtons. an image of a spring scale with a 1 kilogram weight attached. the scale reads 9.8 n. what would be the force exerted by gravity on 9.0 kg? 9.0 n 9.8 n 81 n 88 n

Answers

The force exerted by gravity on a mass of 6.5 kg will be equal to 64 N. Hence, option A is correct.

What is Force?

Any operation that has the ability to alter, maintain, or modify a body's motion is considered a force in mechanics. Isaac Newton's Principia Mathematica has three laws of motion that are usually used to demonstrate the idea of force (1687). A body at rest or consistently moving in a straight path is said to remain in that state before a power is applied to it, according to Newton's first law.

Now, let's find out the force exerted by gravity,

Given,

Mass, m = 6.5 kg

Use the value of acceleration due to gravity (g) as 9.8 m/s².

f = 6.5 × 9.8

f = 63.7 or,

f = 64 N.

Therefore, the force exerted by the gravity will be equal to 64 N.

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22. two slits, each 0.80 mm wide, are 2.6 mm apart: when light is shone through them onto a screen how many interference maxima are there between the first diffraction minimum on the left side and the first diffraction minimum on the right side? a 1 b. 3 c.5 d. 7 e.9

Answers

Option (D) is the correct answer

Given data:  width of each slit, a = 0.80 mm.        

distance between the slits, d = 2.6 mm

If the wavelength of light is \lambda then,

2.6 ) = 2 x (0.8) = 6.5 r=2x

x = 7 ( taking the next higher integer of 6.5)

The wavelength of a wave describes how lengthy the wave is. The distance from the "crest" (top) of 1 wave to the crest of the following wave is the wavelength.

Alternately, we can degree from the "trough" (bottom) of 1 wave to the trough of the subsequent wave and get the equal price for the wavelength.

SI unit of wavelength is metre . At the same time as measuring wavelength the multiples or fractions of a metre is also used. Extensively, exponential powers of 10 are used whilst wavelengths are of a huge assets.

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A motorbike undergoes a constant acceleration from rest and travels a distance
of 60 m in 6.0 s.
What is the acceleration of the motorbike?

Answers

Acceleration equals velocity/time. We have time, 6 seconds; but need to find velocity. Using kinematic equations we know velocity equals distance/time. Our distance is 60m and our time is 6s. Giving us a velocity of 60m/6s = 10m/s. Now we input our velocity and our time values into our acceleration equation.
a = v/t. 10m/s / 6s = 60m/s.

if the spring constant of a simple harmonic oscillator is quadrupled, by what factor will the mass of the system need to change in order for the frequency of the motion to remain the same?

Answers

the mass of the system must be quadrupled

here,

the initial spring constant is K0

the final spring constant , K = 4 * K0

when the frequency remains the same

(1/2*pi) * sqrt(K/m) = (1/2*pi) * sqrt(K0/m0)

K/m = K0 /m0

4 * K0 /m = K0 /m0

m = 4 * m0

the mass of the system must be quadrupled

In classical mechanics, a harmonic oscillator is a system that, when displaced from its equilibrium position, experiences a restoring force F proportional to the displacement x:

where k is a positive constant. If the only force acting on a

system is F, the system is called a simple harmonic oscillator, and it oscillates simply. Sinusoidal oscillation of constant amplitude and constant frequency (independent of amplitude) around the equilibrium point.

A harmonic oscillator is called a damped oscillator if there is also a frictional force (damping) proportional to velocity. Depending on the coefficient of friction, the system can:

Oscillates at a lower frequency than undamped and decreases in amplitude over time (underdamped oscillator). The

damps to its equilibrium position without oscillation (overdamped oscillator).

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93. High biological value proteins are classified as A_ complete proteins. B_ plant-based proteins C essential amino acids_ D free-form amino acids_

Answers

Option C;  High biological value proteins are classified as Essential amino acids

When a proteins contains the essential amino acid in right proportion required by human being it is high biological value.

An obligatory amino acid, also known as an essential amino acid, is one that the body cannot produce quickly enough to meet its needs from scratch, necessitating dietary intake. Nine amino acids—phenylalanine, valine, threonine, tryptophan, methionine, leucine, isoleucine, lysine, and histidine—of the 21 essential amino acids for all living things cannot be produced by humans.

Six additional amino acids are classified as conditionally necessary in the human diet, which means that their synthesis may be restricted in certain pathophysiological situations, such as in infants who are premature or people who are experiencing acute catabolic distress. Arginine, cysteine, glycine, glutamine, proline, and tyrosine are the six amino acids in question. Humans can generate sufficient amounts of six amino acids that are non-essential (dispensable), meaning they are not required.

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what is the acceleration due to gravity at the surface of titania?

Answers

12.4) to the earth and to Titania. The acceleration due to gravity at the surface of Titania is given by g₁ = Gm/R2, where m is its mass and R is its radius.
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The acceleration due to gravity on the surface of earth is lower than that at earth. The g value for titania is 0.037 m/s².

What is acceleration due to gravity?

Acceleration due to gravity is the acceleration by the force of gravitation by an object. The g value can be obtained from the mass, radius or distance and universal gravitational constant G as written below:

g = G m/r²

The acceleration due to gravity for earth is 9.8 m/s². The mass of titania is 1/1700 of the mass of earth and its radius is 1/8 times that of earth. The acceleration due to gravity for titania is:

g = G (Me/1700)/ (Re/8)²

 = 64/1700  G Me/Re²

Where Me and Re be the mass and radius of earth. The g value for earth is 9.8 m/s².

Acceleration due to gravity for titania = 9.8 m/s² × 64/1700 = 0.0377m/s²

Therefore, the acceleration due to gravity of titania is 0.0377m/s².

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A toy car having mass
m = 1.45 kg
collides inelastically with a toy train of mass
M = 3.55 kg.
Before the collision, the toy train is moving in the positive x-direction with a velocity of
Vi = 2.35 m/s
and the toy car is also moving in the positive x-direction with a velocity of
vi = 4.80 m/s.
Immediately after the collision, the toy car is observed moving in the positive x-direction with a velocity of
1.90 m/s.
b) Determine the change ΔKE in the total kinetic energy. Assume friction and therotation of the wheels are not important so that they do not affect ΔKE.

Answers

The change in the total kinetic energy (ΔKE) is determined as -1.77 J.

What is the final speed of the toy train?

The final speed of the train is calculated by applying the principle of conservation of linear momentum for elastic collision.

Note:

for elastic collision, both objects will have different speed after collision.for inelastic collision both objects will have the same speed after the collision.

The final speed of the toy train is calculated as;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

m₁ is the mass of the toy caru₁ is the initial speed of the toy carm₂ is the mass of the toy trainu₂ is the initial speed of the toy trainv₁ is the final speed of the toy carv₂ is the final speed of the toy train

(1.45 x 4.8) + (3.55 x 2.35) = (1.45 x 1.9) + (3.55v₂)

15.30 = 2.755 + 3.55v₂

15.30 - 2.755 = 3.55v₂

3.55v₂ = 12.545

v₂ = 3.53 m/s

The change in the kinetic energy is calculated as follows;

ΔK.E = ¹/₂m₂(v₂² - u₂²) +  ¹/₂m₁(v₁² - u₁²)

ΔK.E = ¹/₂(3.55)(3.53² - 2.35²) +  ¹/₂(1.45)(1.9² - 4.8²)

ΔK.E = 12.32 J - 14.08 J

ΔK.E = -1.77 J

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