9. What is a reactive molecule formed from
three oxygen atoms covalently bonded
together?
A. UV radiation
B. Ozone
C. Coal
D. Chlorofluorocarbon

Answers

Answer 1

Answer:

B. Ozone

Explanation:

Answer 2

Answer: B

Explanation:

Ozone consists of three oxygen atoms covalent bonded together. Ozone is quite reactive.


Related Questions

When a substance is reduced:
A. It is called the oxidizing agent
B. Some other substance must be reduced
C. It loses electrons
D. It is called the reducing agent

Answers

Answer:

Explanation:

Write a balanced chemical equation for each of the following.
Gaseous carbon monoxide reacts with hydrogen gas to form gaseous methane (CH4) and liquid water.
Express your answer as a chemical equation. Identify all of the phases in your answer.

Answers

Answer:

CO+3H2———> CH4+H2O

Explanation:

gavufwvdk if wgbdkiiheh

An Earth scientist is testing how various soil mixtures affect plant growth. She begins with 10 soil types. For each mixture, she combines equal
amounts of 2 soil types.
How many soil mixtures must the scientist create in order to test all possible combinations of the 10 soil types?
You may use the calculator.
OA. 20
OB. 45
OC. 55
OD. 90

Answers

The scientist needs to create 45 soil mixtures in order to test all possible combinations of the 10 soil types. Option B.

Combination problem

To calculate the number of unique soil mixtures, we can use the formula for the number of combinations of n objects taken k at a time, which is given by:

C(n,k) = n! / (k! * (n-k)!)

In this case, we have 10 soil types and we want to take 2 at a time to create unique mixtures. Thus, we substitute n=10 and k=2:

C(10,2) = 10! / (2! * (10-2)!)

= 10! / (2! * 8!)

= (10 x 9) / 2

= 45

In other words, the scientist needs to create 45 soil mixtures in order to test all possible combinations of the 10 soil types.

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In which of the following compounds does sulfur have the highest (i.e most positive) oxidation number? a) CuS b) SO2 c) K2SO3 d) NA2SO4

Answers

Answer:

c) K2SO3

Explanation:

The oxidation number of S in K2SO4 K 2 S O 4 is +6. So, this is the highest oxidation number of S amongst the oxidation number of S in all the given compounds.

b) State two factors that determine the position where the pigments are deposited in the chromatogram from the point of origin. (2mks)

Answers

Two factors that determine the position where pigments are deposited in the chromatogram from the point of origin are polarity and solubility.

Polarity is a measure of the distribution of charge within a molecule. In chromatography, a polar solvent is used to carry the pigments up the chromatography paper.

The pigments with a higher polarity will be more attracted to the polar solvent and will travel up the paper at a faster rate. This means that they will be deposited closer to the point of origin than pigments with lower polarity.

Solubility is another factor that determines the position where pigments are deposited in the chromatogram. Pigments that are more soluble in the solvent will travel further up the paper than pigments that are less soluble. The solubility of pigments is influenced by their molecular structure, size, and polarity.

In summary, the position where pigments are deposited in the chromatogram from the point of origin is determined by the polarity and solubility of the pigments.

Pigments with higher polarity and solubility will travel further up the paper and will be deposited closer to the point of origin, while those with lower polarity and solubility will travel a shorter distance and will be deposited further from the point of origin.

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Calculate the frequency of the =4
line in the Lyman series of hydrogen.

Answers

The frequency of the =4 line in the Lyman series of hydrogen is 3.09 x 10¹⁵ Hz.

What is the frequency of the n = 4 line in the Lyman series of hydrogen?

The energy levels in the Lyman series of hydrogen are given by the formula:

E = -13.6/n²

where

E is the energy of the level and n is an integer representing the level number.

The transition from level n to level 1 produces a photon with a frequency given by:

[tex]v = (E_n - E_1)/h[/tex]

where

v is the frequency of the photon,h is Planck's constant, and [tex]E_n[/tex] and [tex]E_1[/tex] are the energies of levels n and 1, respectively.

For the n = 4 line in the Lyman series, the initial level is n = 4 and the final level is n = 1.

The energy of the initial level is:

[tex]E_4[/tex] = -13.6/4²

[tex]E_4[/tex] = -0.85 eV

The energy of the final level is:

[tex]E_1[/tex]= -13.6/1²

[tex]E_1[/tex] = -13.6 eV

The energy difference between the levels is:

[tex]E_4 - E_1[/tex] = -0.85 - (-13.6)

[tex]E_4 - E_1[/tex] = 12.75 eV

Converting to joules:

v = (12.75 x 1.6 x 10⁻¹⁹ J)/6.626 x 10⁻³⁴ J s

v = 3.09 x 10¹⁵ Hz

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The question is in the picture please help thank youuuu!!!

Answers

The missing genotype in the punnett square are as follows:

Bbbb

What is a punnet square?

A punnet square is a graphical representation used in genetics to determine the probability of an offspring expressing a particular genotype.

According to this question, a mother with the genotype 'Bb' (heterozygous) is crossed with a father with genotype 'bb' (homozygous recessive).

The cross between these two parents i.e. Bb × bb, is illustrated in the punnett square above. However, two of the genotype of the offsprings were missing. The possible offsprings' genotype from this cross are as follows:

BbBbbbbb

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whats an example of a low amount of force being applied to an object explain in 1-2 sentences.

Answers

An example of a low amount of force being applied to an object is as follows; a child pushing a barrel that is not moving.

What is force?

Applied force is the force which is applied to an object by another object.

Ideally, a force is a physical quantity that denotes ability to push, pull, twist or accelerate a body. Work is kind of force that causes a body to move.

For example, a person pushing a barrel is an example of applied force. When the person pushes the barrel then there is an applied force acting upon the barrel.

However, when a child pushes against the barrel and it doesn't move, it can be said that a low amount of force is applied.

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The Solubility Product Constant for silver phosphate is 1.3x10^-20 .

The molar solubility of silver phosphate in a 0.223 M sodium phosphate solution is ?M

Answers

The Solubility Product Constant for silver phosphate is 1.3x10^-20 . The molar solubility of silver phosphate in a 0.223 M sodium phosphate solution is 77.51×10M.

A homogenous mixture of one or more solutes in a solvent is referred to as a solution. A typical illustration of a solution is the addition of sugar cubes to a cup of tea or coffee. Solubility is a quality that aids in the dissolution of sugar molecules. Thus, the ability of a substance (solute) to dissolve in a specific solvent can be defined as solubility. Any substance that is dissolved in a solvent and is either solid, liquid, or gas is referred to as a solute.

Ksp = [Ag⁺]³ [PO₄⁻]

1.3×10⁻²⁰=0.256³×s

s=77.51×10M

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When potassium permanganate and glycerol react, the potential energy of the products is
less than the potential energy of the reactants. Which statement about this reaction is
correct? (1 point)
A. The total potential energy of the system is constant.
B. The reaction is exothermic.
C. The activation energy of the system is negative.
D. The reaction is endothermic.

Answers

Regarding this response, the appropriate statement is:.

B. The reaction is exothermic.

Because the potential energy of the products is lower than that of the reactants, energy must be released during the reaction. This indicates that the reaction is exothermic, which means that heat is released as a form of energy. Given that glycerol and potassium permanganate react spontaneously when combined, which suggests that the reaction is energetically advantageous, this is consistent with the fact that the reaction is favorable. The following statements are false in this situation: A. Due to the energy released during the reaction, the total potential energy of the system is not constant. C. The system's activation energy is always positive, so it can never be negative. Since endothermic reactions draw energy from their surroundings, the reaction is not endothermic.

Answer: B

Explanation:

If the potential energy of the products is less than that of the reactants, that must mean that some potential energy was converted into thermal energy during the reaction. Since the reaction released heat, the reaction is exothermic.

Relationship between uv light and activity of object

Answers

Light and UV radiation can cause irreversible damage to objects (such as fading or weakening of materials). Some items are more sensitive than others, and the intensity and duration of light can have varying effects. Oil paintings and furniture are moderately sensitive.

Consider the balance redox reaction below
K2Cr2O7 + 7H2SO4 + 6KBr ----> 3Br2O + 4K2SO4 + Cr2(SO4)3 + 7H2O

WHich element is oxidized in the reaction?
A.) Br in KBr B.) S in H2S04

C.) H in H2SO4 D.) Cr in K2CR2O7

Answers

In the redox reaction, [tex]K_{2} Cr_{2} O_{7}[/tex] + 7[tex]H_{2} SO_{4}[/tex] + 6KBr → [tex]3Br_{2}O[/tex] + [tex]4K_{2} SO_{4}[/tex] + [tex]Cr_{2} (SO_{4})_{3}[/tex] + [tex]7H_{2}O[/tex], the element that is oxidized is Option A. Br in KBr.

In the given reaction, [tex]K_{2} Cr_{2} O_{7}[/tex], also known as potassium dichromate, is a strong oxidizing agent that causes oxidation of the other reactants. Oxidation refers to the loss of electrons by an atom or molecule. Similarly, reduction refers to the gain of electrons by an atom or molecule.

In [tex]K_{2} Cr_{2} O_{7}[/tex], the oxidation state of chromium (Cr) is +6. In the product, [tex]Cr_{2} (SO_{4})_{3}[/tex], the oxidation state of Cr is +3. Therefore, Cr has been reduced, meaning it has gained electrons and is not oxidized.

On the other hand, [tex]H_{2} SO_{4}[/tex], the oxidation state of sulfur (S) is +6. In the product, [tex]K_{2} SO_{4}[/tex], the oxidation state of S is +6. Therefore, S has not been oxidized or reduced.

Similarly, [tex]H_{2} SO_{4}[/tex], the oxidation state of hydrogen (H) is +1. In the product, [tex]H_{2}O[/tex], the oxidation state of H is 0. Therefore, H has been reduced, meaning it has gained electrons and is not oxidized.

Finally, in KBr, the oxidation state of Br is -1. In the product, [tex]Br_{2}O[/tex], the oxidation state of Br is +1. Therefore, Br has been oxidized, meaning it has lost electrons.

In conclusion, the element that oxidized in the given reaction is Br in KBr (Option A).

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Calculate the molarity of 33.9 g of MgS in 969 mL of solution. ​

Answers

Answer:

0.620M

Explanation:

molarity= moles of solute/volume of solution

molar mass of mgs= 24.3+32= 56.3

moles= 33.9/56.3=0.601

molarity= 0.601/0.969=0.602M

The gas phase reaction between nitric oxide and hydrogen occurs in three elementary steps:

NO + NO <--> N2O2 (fast equilibrium)
N2O2 + H2 --> H2O + N2O (slow)
N2O + H2 --> N2 + H2O (fast)
Based on this mechanism we would expect the rate law to be:

a) Second order in NO, first order in H2, and zero order in H2O
b) Second order in both NO and H2, and zero order in H2O
c) Second order in both NO and H2, and first order in H2O
d) First order in NO, first order in H2, and -1 order in H2O

Answers

The correct option is (b) Second order in both NO and H2, and zero order in H2O.

The rate law for a chemical reaction can be determined from its elementary steps and the rate-determining step (RDS). In this mechanism, the RDS is the second step, which is the slowest step, so the rate law will be based on this step.

According to the second step of the mechanism, the stoichiometry of the reaction is 1:1 for N2O2 and H2. Therefore, the rate law should have a second order dependence on both N2O2 and H2. The rate law should also reflect the stoichiometry of the reaction, so it will be:

Rate = k[N2O2][H2]

The final product is H2O, which is not involved in the RDS, so it will not appear in the rate law.  The correct answer is (b) Second order in both NO and H2, and zero order in H2O. The fast equilibrium step does not affect the overall rate of the reaction, as it simply establishes an equilibrium concentration of N2O2. The rate law only reflects the RDS, which involves the consumption of N2O2 and H2 to form N2 and H2O.

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Circle O is shown. Line segments E O and E O are radii with length 24. Angle D O E is 45 degrees. The area within sector D O E is shaded.
What is the area of the shaded sector?

24π
45π
72π
576π

Answers

In the given circle, the area of the shaded sector is 72π, hence option C is correct.

The region inside the portion of the circle formed by two radii and an arc is known as the area of a sector. It only covers a small portion of the entire circle's surface.

To find the area of the shaded sector, use the formula:

According to the diagram in the question

OE is the radius

The central angel of the sector is 45⁰

A = θ/360 πr²

Put the values in the formula, we get

45 ÷ 60 × π × 24²

1/8 × π × 24 × 24

3 × 24 × π

= 72π

Thus, the area of the shaded sector is 72π.

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During a volcanic eruption, lava flowed at a rate of 37 m/min. At this rate how far in kilometers
can lava travel in 45 minutes?

Answers

Answer:

The lava can travel approximately 1.665 kilometers in 45 minutes.

Explanation:

A 20.0 L helium balloon initially at 25°C and 1.00 atm is heated in the sunlight to a final temperature of 41.6°C. During this process the balloon expands in such a way that the pressure remains constant. What is the change in entropy of the gas during this process? Answer in J/K to three decimal places. R = 8.314 J/mol K = 0.08206 L-atm/mol K

Answers

We can apply the following equation to determine the gas's change in entropy:

S = nR T f /Ti ln

Given: 20.0 L is the initial volume (Vi).

Initial temperature (Ti) = 25 °C, which equals 25 + 273.15 K, or 298.15 K.

Final temperature  = 41.6°C, which is equal to 41.6 + 273.15 K, or 314.75 K.

Pressure does not change (P)

(R) = 8.314 J/mol K for the gas constant.

The ideal gas law must first be used to calculate the quantity of helium gas (n):

PV = nRT

When we rewrite the equation, we get:

n = PV / RT

replacing the specified values:

n is equal to (1.00 atm) x (20.0 L) / (0.08206 L-atm/mol K x 298.15 K).

n ≈ 0.813 mol

Now we can determine the entropy change:

S = ln(314.75 K / 298.15 K) * (0.813 mol) * (8.314 J/mol K)

ΔS ≈ 1.071 J/K

As a result, the gas's entropy changed by about 1.071 J/K during this operation.

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PbI2 is sparingly soluble in water (Ksp = 8.7 x 10-9). Which two of the following statements are true?

- More solid will dissolve when 10 g of PbI2(s) is added to 1.0 L of water than when 5 g of PbI2(s) is added.
- Adding HNO3(aq) to a saturated solution of PbI2(s) will cause more solid to precipitate
- PbI2(s) will be more soluble in pure water than in a solution containing KI(aq)
- PbI2(s) powder will be more soluble in water than large crystals of PbI2(s)
- The solubility product of PbI2(s) will increase with increasing temperature

Answers

Two statements that are true are:

More solid will dissolve when 10 g of PbI2(s) is added to 1.0 L of water than when 5 g of PbI2(s) is added.

The solubility product of PbI2(s) will increase with increasing temperature.

1- More solid will dissolve when 10 g of PbI2(s) is added to 1.0 L of water than when 5 g of PbI2(s) is added.

This statement is true because the solubility of PbI2 is limited by its Ksp value. Therefore, the more solid PbI2 added, the closer the solution gets to being saturated and the more PbI2 will dissolve.

5-The solubility product of PbI2(s) will increase with increasing temperature.

This statement is true because the solubility of most ionic solids increases with increasing temperature. A higher temperature increases the kinetic energy of the solvent molecules, allowing them to better solvate and break apart the solid PbI2. As a result, more ions are available to react and the Ksp value increases.

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What is the oxidation number of Boron? (2.2.1)
2+
2-
3+
3-

Answers

on the periodic table it is 3+

Which functional group is within the compound shown below

Answers

The functional group within the compound is ketone.

Ketones are a common functional group in organic chemistry. Ketones have important physiological properties.

Ketones can be named using either the common system or the IUPAC system. In the common system, ketones names are created by naming the groups attached to the carbonyl carbon and then adding the word ketone.

In ketones, the carbonyl group has two hydrocarbon groups attached to it. These can be either aromatic rings or alkyl groups. Ketone does not have a hydrogen atom attached to the carbonyl group.

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how the Sun is responsible for most of the energy on Earth by explaining it's connection to photosynthesis and fossil fuels.

Answers

Answer:

The sun provides most of the energy on earth because it is the earth's (and the solar system's) greatest source of heat and light.

Explanation:

The process of photosynthesis in plants uses the energy from the sun and converts that energy to be used for plants.
The burning of fossil fuels produces greenhouse gases which trap the heat in our earth's atmosphere (causing global warming).

express views on how the law , the citizen and community can proteand support victims of human rights violations?​

Answers

Answer:

On the support of victims of human rights violation, the law should clearly state and express the repercussions of violating human rights. The citizen on the other hand should be well versed with human rights and should report any violator of human rights to the relevant authorities for immediate action to be taken.

Could someone help me solve this

Answers

The mass of CO₂ needed to fill the zip-top bag by converting the moles is 4.4817 g CO₂

How to determine mass?

To determine the mass of CO₂, know the number of moles of CO₂ and its molar mass. The formula to calculate the mass of CO₂ is:

mass of CO₂ = number of moles of CO₂ x molar mass of CO₂

The number of moles of CO₂ can be calculated using the Ideal Gas Law, which relates the number of moles of a gas to its pressure, volume, temperature, and gas constant.

Once calculated the number of moles of CO₂, multiply it by the molar mass of CO₂ to obtain the mass of CO₂. The molar mass of CO₂ is approximately 44 g/mol.

For this case the mass of CO₂ after conversion is 0.102 mol CO₂ x 44.0099 g/mol CO₂ = 4.4817 g CO₂

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Which must be kept in mind when determining if an explanation is correct?

whether people reading the explanation agree
the information that is on the Internet
that there may be more than one way to interpret data
whether a person of authority says it is correct

Answers

There may be more than one way to interpret data.

People need multiple ways to understand the information. This way, they can determine if an explanation is correct in case they don't understand.

Answer:hey ok so the answer is “ that there may be more than one way to interpret date” or just C

Explanation:

I got 100% on the test please give me likes :))))))))

If 4 moles of gaseous nitrogen gas are confined in a 6.0 L container at 1770C and 12.0 atm. Suppose the container isothermally expand to 36.0 L. What is the final pressure experienced by this gas?

Answers

Answer:The initial conditions of the nitrogen gas are:

n = 4 moles

V = 6.0 L

T = 177°C = 450 K

P = 12.0 atm

Using the ideal gas law:

PV = nRT

where R is the universal gas constant (0.08206 L atm/mol K).

We can rearrange the ideal gas law to solve for the final pressure (Pf) at a constant temperature:

Pf = (nRTf) / Vf

where T f and Vf are the final temperature and volume, respectively.

Since the expansion is isothermal, the temperature remains constant at 450 K. The final volume is 36.0 L. Thus:

Pf = (4 mol x 0.08206 L atm/mol K x 450 K) / 36.0 L

Pf = 16.37 atm

Therefore, the final pressure experienced by the nitrogen gas is 16.37 atm.

Explanation:

what is the hyphen notation and nuclear symbol for oxygen

Answers

Answer:

The element name or symbol is followed with a hyphen and the mass number. On the periodic table of elements, oxygen is represented by the symbol O. It has an atomic number of 8 because it has 8 protons in its nucleus

Examples:

Carbon-14 or C-14 (meaning the isotope of carbon that has a mass number of 14)

Calculate the pH of a solution prepared by dissolving 1.30g of sodium acetate, CH3COONa, in 60.5 mL of .20 M acetic acid, CH3COOH(aq). Assume the volume change upon dissolving the sodium acetate is negligible. Ka of CH3COOH is 1.75*10^-5.

Answers

The pH of the solution prepared by dissolving 1.30g of sodium acetate in 60.5 mL of 0.20 M acetic acid is approximately 3.34.

To calculate the pH of the solution, we need to consider the equilibrium between the acetic acid (CH3COOH) and its conjugate base, acetate ion (CH3COO-), using the Ka value provided. We will also take into account the presence of sodium acetate (CH3COONa), which will provide additional acetate ions.

First, let's determine the moles of acetic acid present in the solution:

Moles of acetic acid = concentration x volume

Moles of acetic acid = 0.20 M x 60.5 mL x (1 L / 1000 mL)

Moles of acetic acid = 0.0121 mol

Next, let's determine the moles of sodium acetate:

Moles of sodium acetate = mass / molar mass

Moles of sodium acetate = 1.30 g / 82.03 g/mol

Moles of sodium acetate = 0.0158 mol

Since sodium acetate dissociates completely, the concentration of acetate ions (CH3COO-) will be equal to the moles of sodium acetate divided by the total volume of the solution:

Concentration of acetate ions = moles of sodium acetate / total volume

Concentration of acetate ions = 0.0158 mol / 60.5 mL x (1 L / 1000 mL)

Concentration of acetate ions = 0.260 M

Now, we can set up an ICE (Initial, Change, Equilibrium) table to calculate the concentrations of acetic acid and acetate ions at equilibrium:

CH3COOH(aq) + H2O(l) ⇌ CH3COO-(aq) + H3O+(aq)

Initial: 0.0121 M 0 M 0 M

Change: -x +x +x

Equilibrium: 0.0121 - x x x

The Ka expression for acetic acid is:

Ka = [CH3COO-][H3O+] / [CH3COOH]

Using the given Ka value, we can set up the equation:

1.75 x 10^-5 = (x)(x) / (0.0121 - x)

Since x is expected to be small compared to 0.0121, we can approximate the denominator as 0.0121:

1.75 x 10^-5 = x^2 / 0.0121

Simplifying the equation:

x^2 = 1.75 x 10^-5 x 0.0121

x^2 = 2.1175 x 10^-7

x ≈ 4.6 x 10^-4

Now, we can calculate the concentration of H3O+ ions:

[H3O+] = x = 4.6 x 10^-4 M

Finally, we can calculate the pH using the formula:

pH = -log[H3O+]

pH = -log(4.6 x 10^-4)

pH ≈ 3.34

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as the mass of salt increased, what happened to the temperature at which the ice cube melted.

Answers

Therefore, if we add salt into a mixture of ice and water, the melting/freezing point of the mixture decreases and the ice begins to melt. In order for a phase change to occur, the ice draws the heat of fusion from its surroundings, which allows the temperature to decrease.

define tetragonal unit cell​

Answers

Answer:

The tetragonal unit cell is distinguished by an axis of fourfold symmetry, about which a rotation of the cell through an angle of 90° brings the atoms into coincidence with their initial positions. The elements boron and tin can crystallize in tetragonal form, as can some minerals such as zircon.

Explanation:

How many µg of mercury are contained in 27.2 mL of a 14.10 ppm solution?

Answers

To calculate the amount of mercury in µg (micrograms), we need to use the following formula:

mass (in µg) = volume (in mL) x concentration (in ppm) x atomic mass (in g/mol) / 1000

The atomic mass of mercury (Hg) is 200.59 g/mol.

Substituting the given values into the formula, we get:

mass = 27.2 mL x 14.10 ppm x 200.59 g/mol / 1000

mass = 76.9 µg

Therefore, there are 76.9 µg of mercury in 27.2 mL of a 14.10 ppm solution.
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