A 0.0272 kg arrow is fired with a velocity of 87.3 m/s from a 0.0245 kg bow. Determine the equivalent impulse value imparted on the arrow. (hint: you can also use newton's third law of motion)* A.2.37 Ns B.3.11 Ns C.113.5 Ns D.214.2 Ns​

Answers

Answer 1

Answer:

Explanation:

C. 113.5 Ns


Related Questions

Continue where the red line would would go

Answers

Refraction would cause the red light to bend at the air/glass boundary.

What is refraction?

While the question is unclear, I assume that you are trying to know something about the refraction of the red light across the air/glass boundary. I will tell you something about refraction!

Refraction is a phenomenon of light where it changes direction when it enters a medium with a different refractive index. Refractive index is a measure of how much a medium bends light that passes through it. When light passes from a medium with a lower refractive index to a medium with a higher refractive index, it bends towards the normal (an imaginary line perpendicular to the surface at the point of incidence). On the other hand, when light passes from a medium with a higher refractive index to a medium with a lower refractive index, it bends away from the normal.

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Four capacitors are of the same capacity. If three of them are connected in
parallel and the remaining one is connected in series with this combination, the
resultant capacity is 16.5 μF. Find the capacity of each capacito

Answers

Answer:

bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Explanation:

A positively charged solid conducting sphere is contained within a negatively charged conducting spherical shell as shown. The magnitude of the total charge on each sphere is the same.
1)Which of the following statements best describes the electric field in the region between the spheres?
A.The field points radially outward
B.The field points radially inward
C.The field is zero
2.Which of the following statements best describes the electric field in the region outside the red sphere?
A.The field points radially outward
B.The field points radially inward
C.The field is zero
CAN u give me a explanation.

Answers

1) Statements best describes the electric field in the region between the spheres  field points radially outward.

2) Statements best describes the electric field in the region outside the red sphere The field is zero.

For positive charge, E field lines are projecting outward of positive charge.

For negative charge, E field lines are projecting inward of negative charge.

Then, between the spheres,

because of q, E field lines are projecting outward of q and inward of- q;

and because of- q, E filed lines are projecting outward of q and inward of- q

So, The field points radially outward

2) C still, net charge inside the gaussian face is zero, If we draw a gaussian face outside the spheres.

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(a) A charge of -275e is uniformly distributed along a circular arc of radius 3.85 cm, which subtends an angle of 37°. What is the linear charge density along the arc?
1 C/m
(b) A charge of -275e is uniformly distributed over one face of a circular disk of radius 1.85 cm. What is the surface charge density over that face?
2 C/m2
(c) A charge of -275e is uniformly distributed over the surface of a sphere of radius 1.85 cm. What is the surface charge density over that surface?
3 C/m2
(d) A charge of -275e is uniformly spread through the volume of a sphere of radius 1.85 cm. What is the volume charge density in that sphere?
4 C/m3

Answers

Uniform distribution of charge a) [tex]-1.752 * 10^(-17) C/m[/tex] b) [tex]-4.038 * 10^(-16) C/m^2[/tex] c)  [tex]-6.346 * 10^(-16) C/m^2[/tex] d) [tex]-4.580 * 10^(-13) C/m^3[/tex]

(a) To find the linear charge density along the arc, we divide total charge (-275e) by arc length. Arc length is product of radius (3.85 cm) by the angle (in radians) arc subtends. Convert angle to radians:

[tex]37 degree = (37/360) * 2\pi radians = 0.6435 radians[/tex]

The length of the arc is then:

length = radius x angle = (3.85 cm) x (0.6435) ≈ 2.477 cm

The linear charge density is then:

linear charge density = charge in total / length magnitude = (-275e) / (2.477 cm)

e: elementary charge.

Using charge value:

linear charge density = [tex]-1.752 * 10^(-17) C/m[/tex]

Therefore, linear charge density along the arc is [tex]-1.752 * 10^(-17) C/m.[/tex]

(b) To find the surface charge density over the face of the circular disk, we need to divide the total charge (-275e) by area of disk. Area of face of disk is [tex]\pi[/tex] times radius squared

area =[tex]\pi * (1.85 cm)^2 = 10.78 cm^2[/tex]

The surface charge density is then:

surface charge density = total value of charge / area magnitude = [tex](-275e) / (10.78 cm^2)[/tex]

e: elementary charge.

Using charge value:

surface charge density = [tex]-4.038 * 10^(-16) C/m^2[/tex]

Surface charge density over the face of the circular disk is  [tex]-4.038 * 10^(-16) C/m^2[/tex].

(c) To get surface charge density over sphere surface, we divide total charge (-275e) by sphere surface area:

surface area = [tex]4\pi * (radius)^2[/tex]

The surface charge density:

surface charge density = total charge / surface area =[tex](-275e) / [4\pi * (1.85 cm)^2][/tex]

where e is the elementary charge.

Use charge value:

surface charge density ≈ [tex]-6.346 * 10^(-16) C/m^2[/tex]

Surface charge density over sphere is[tex]-6.346 * 10^(-16) C/m^2.[/tex]

(d) To get volume charge density in the sphere, we divide the total charge (-275e) by the volume of the sphere.

volume = [tex](4/3)\pi * (radius)^3[/tex]

The volume charge density is then:

volume charge density = total charge / volume = [tex](-275e) / [(4/3)\pi * (1.85 cm)^3][/tex]

e: elementary charge

Using value of the elementary charge:

volume charge density = [tex]-4.580 * 10^(-13) C/m^3[/tex]

Therefore, the volume charge density in the sphere is [tex]-4.580 * 10^(-13) C/m^3[/tex]

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State any five (5) clinical uses of heat enery .​

Answers

The therapeutic effects of heat include increasing the extensibility of collagen tissues; decreasing joint stiffness; reducing pain; relieving muscle spasms; reducing inflammation, edema, and aids in the post acute phase of healing; and increasing blood flow.

What is the role of heat energy in the body?

In the process of ATP production by cells throughout the body, approximately 60 percent of the energy produced is in the form of heat used to maintain body temperature. Thermoregulation is an example of negative feedback.

Why is heat used as a treatment during health care?

Heat treatments should be used for chronic conditions to help relax and loosen tissues, and to stimulate blood flow to the area. Heat is a great treatment option for chronic conditions caused from old injuries or even arthritis. Heat can be applied before participating in activities to help limber up.

So we can conclude that heat is one of the most important form of energy for our daily life.

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The speed of light in vacuum is 3* 10^8. If the refractive index of a transparent liquid is 4/3, then what is the speed of light in the liquid?

Answers

The speed of light in vacuum is 3 × 10⁸ m/s. If the refractive index of a transparent liquid is 4/3, then the speed of light in water will be 2.25 × 10⁸ m/s.

What is Refractive index?

Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to the speed of light in the second medium of greater density. The refractive index variable is most commonly symbolized by the letter n or n'.

R.I. of water = Speed of light in vacuum / speed of light in water

n' = 4/3

Speed of light in vacuum = 3 × 10⁸

n' = Speed of light in vacuum / speed of light in water

Speed of light in water = Speed of light in vacuum/ n'

Speed of light in water = 3 × 10⁸/ 4/3

Speed of light in water = 2.25 × 10⁸

Therefore, the speed of light in water medium will be 2.25 × 10⁸ m/s.

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A motorist runs out of gas on a level road 210 m from a gas station. The driver pushes the 1,180 kg car to the gas station. If a 140 N force is required to keep the car moving, how much work (in J) does the driver do?

Answers

Answer:

the driver does 29,400 J of work in pushing the car to the gas station.

Explanation:

To find the amount of work done by the driver, we need to know the force applied by the driver and the distance the car is moved.

The force applied by the driver is given as 140 N, and the distance the car is moved is given as 210 m.

Work done can be calculated using the formula:

W = F * d * cos(θ)

where W is the work done, F is the force applied, d is the distance moved, and θ is the angle between the force and the displacement. Since the force and displacement are in the same direction, θ = 0, and the cosine of 0 is 1.

So,

W = F * d * cos(θ) = 140 N * 210 m * 1 = 29,400 J

A spring with a spring constant of 2 N/m is stretched by Laura until extended by 0. 5 m. How much elastic potential energy is stored by the spring?

Answers

The spring stores 0.5 joules of elastic potential energy when stretched by 0.5 meters.

What is Potential Energy?

It is a form of energy that is stored in an object and has the potential to do work. The amount of potential energy depends on the position, shape, and orientation of the object. The most common types of potential energy are gravitational potential energy, elastic potential energy, and chemical potential energy.

The elastic potential energy stored by a spring is given by the formula:

Elastic potential energy = 1/2 * spring constant * (extension)^2

where the spring constant is measured in Newtons per meter (N/m), and the extension is measured in meters (m).

Given that the spring constant is 2 N/m and the extension is 0.5 m, we can plug these values into the formula:

Elastic potential energy = 1/2 * 2 N/m * (0.5 m)^2

= 0.5 J

Therefore, the spring stores 0.5 joules of elastic potential energy when stretched by 0.5 meters.

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A startled deer runs 520 m at 20.0° north of east for half a minute, then turns and runs 380 m at 55.0° north of west for 15.0 seconds and stops. What is the average velocity of the deer during this time?

Answers

Answerbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb

Explanation:

A startled deer runs 520 m at 20.0° north of east for half a minute, then turns and runs 380 m at 55.0° north of west for 15.0 seconds and stops. Therefore, 60m/s is the average velocity of the deer during this time.

What is average velocity?

Motion may be defined using physical quantity concepts such as speed, velocity, duration, displacement, as well as acceleration. Sir Isaac Newton provided the correct explanation of motion.

All of these quantities are explained in terms of a single quantity, time. In this section, we will look at average velocity, its mathematical representation, and its graphical depiction.

average velocity =  520 m+  380 m / 15=60m/s

Therefore, 60m/s is the average velocity of the deer during this time.

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What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?.

Answers

The energy transformation that takes place when using a wind turbine to generate usable energy is mechanical-to-electrical.

This is done by converting the kinetic energy of the wind into mechanical energy, which then turns a generator to produce electrical energy. Then, residences and businesses can be powered by this electrical energy. Wind drives the rotor blades of contemporary wind turbines, which transform kinetic energy into rotational energy. Kinetic energy is a particular kind of power that can be present in a moving object or particle. An object can perform work, which involves the transfer of energy, by applying a net force. The effect is that the object accelerates and acquires kinetic energy. Aerodynamic force is used by the rotor blades of a wind turbine, which function similarly to an aeroplane wing or a helicopter rotor blade, to transform wind energy into electricity. The air pressure drops on one side of the blade as the wind passes across it.

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complete question: What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?

A) friction- electrical

B) kinetic - mechanical - electrical

C) friction - mechanical - electrical

D) mechanical - friction - electrical

who suggested mutation theory​

Answers

Answer:

Hugo de Vries

The mutation Theory of Evolution was proposed by Hugo de Vries.

Answer:

Hugo de Vries

Explanation:

In the history of evolutionary biology, Hugo dr Vries is known as a proponent of the mutation theory of evolution, in which new species are believed to arise by single mutational events.

Which object has the greatest momentum?* A. A sports car driving on the highway.
B. A baseball thrown by a professional pitcher.
C.An 18-wheeler tractor trailer at rest.
D. An average mass person walking.​

Answers

Answer: B

Explanation: The best answer is B. A baseball thrown by a professional pitcher. Momentum is the product of an object's mass and its velocity. Since the baseball has the greatest velocity of all the objects listed, it has the greatest momentum.

A pendulum bob of mass 5 kg is displaced from the vertical until it is 0.25 m above its lowest point. Upon release, it rises to a height of 0.24 m on the other side. How much energy was lost due to friction? Assuming half the total energy loss takes place during the downward swing, with what speed does the bob pass though its lowest point?

Answers

The energy lost due to friction is 0.49 J. And the speed of the bob passing through its lowest point will be 2.19 m/s.

What is the conservation of energy?

The mass is 5 kg and the heights are h₁ 0.25 m and h₂ = 0.24. And the difference in the height is given as,

h₁ - h₂ = 0.25 - 0.24

h₁ - h₂ = 0.01

The energy loss due to friction is given as,

Energy loss = mgh₁ - mgh₂

Energy loss = mg (h₁ - h₂)

Energy loss = 5 x 9.8 x 0.01

Energy loss = 0.49 J

The energy lost due to friction is 0.49 J.

The velocity is given as,

KE = mgh₁ - E / 2

(1/2) x 5 x v² = 5 x 9.8 x 0.25 - 0.49 / 2

2.5v² = 12.25 - 0.245

v² = 4.802

v = 2.19 meters per second

The speed of the bob passing through its lowest point will be 2.19 m/s.

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Which sample of water will contain the smallest amount of heat energy?
10 g at 10°C
20 g at 10°C
20 g at 20°C
20 g at 40°C

Answers

Answer:

10 g at 10°C

Explanation:

Answer:

10 g at 10°C

Explanation:

Heat energy is directly proportional to the mass and the temperature of a substance. When comparing two samples of the same substance, the one with higher mass contains more heat energy. Similarly, a substance with higher temperature contains more heat energy compared to the same substance with a lower temperature.

In this case, the smallest amount of heat energy would be in the sample of 10g at 10°C. This is because it has the lowest mass and temperature compared to the other three options.



ALLEN

HELPPPP


i need this done quickly

Answers

Answer:

F(Net) = F(a) + F(g) + F(f) + FN.

A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west..  After they collide, the two interlock and move together.  What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)* A. 11.25 m/s west B. 11.25 m/s east C. 32.6 m/s east D. 32.6 m/s west​

Answers

Answer:cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

Explanation:

Why is copper wire a better conductor of electricity than carbon fiber?(1 point)
Responses

Copper (Cu) has no loose electrons
The electrons in copper (Cu) are loosely bound to the nucleus.
Copper (Cu) is a metal, and only metals can conduct electricity.
Carbon (C) does not have any valence electrons

Answers

The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer

explain about the copper ?

Copper is a chemical element with the symbol Cu and atomic number 29. It is a soft, malleable, and ductile metal with high thermal and electrical conductivity. Copper has been used by humans for thousands of years for various purposes including coinage, electrical wiring, plumbing, and industrial machinery. It is commonly found in nature as copper oxide or copper sulfide, and it can be extracted through mining and refining processes. Copper is also an essential nutrient for all living organisms and plays important roles in biological processes such as the formation of red blood cells and the maintenance of the nervous and immune systems.

The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer. This is because in metals like copper, the outermost electrons of atoms are not tightly bound to their respective nuclei, and can therefore move easily through the material, allowing for efficient conduction of electricity. On the other hand, in non-metal substances like carbon fiber, the electrons are more tightly bound to their respective nuclei, making it less efficient in conducting electricity.

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Answer:

(Question) Why is copper wire a better conductor of electricity than carbon fiber?

(Answer) The electrons in copper (Cu) are loosely bound to the nucleus

(Question) Which of the following best describes a direct current?

(Answer) An electrical current that flows in one direction

(Question) Which of the following substances would allow an electric current to flow through it easily?

(Answer) aluminum (Al)

(Question) Which of the following statements about electrical charges is true?

(Answer) Opposite charges attract one another

(Question) Which of the following statements best describes the relationship between atoms and conductivity?

(Answer) Atoms with a nearly empty valence shell make good conductors

Explanation:

i just finished the quick check

A 65 kg person sits on a 3.6 kg chair. Each leg of the chair makes contact with the floor in a circle that is 1.1 cm in diameter.
Find the pressure exerted on the floor by each leg of the chair, assuming the weight is evenly distributed.!!!!!!!!!!!!!!!!!!!!URGENT!!!!!!!!!!!!!!!!1

Answers

The pressure exerted on the floor by each leg of the chair is [tex]7.080685*10^6M Pa[/tex]

Given :

Mass of person = 65 kg

Mass of chair = 3.6 kg

Diameter of contact point = 1.1 cm = D

Radius of contact point = 1.1/2 = 0.55 cm

The total mass of chair and person = 65 + 3.6 = 68.6 kg = M

Acceleration due to gravity = 9.81 m/s²

Force acting on the floor F

F=mg

F= 68.6 * 9.81

F = 672 .9 N

Area of the contact point

A = [tex]\pi r^2[/tex]

A = [tex]\pi (0.55)^2[/tex]

A = [tex]0.00003025\pi[/tex]

Pressure = force/Area

Pressure = [tex]672.9/0.00003025\pi[/tex]

Pressure =[tex]7.080685*10^6[/tex]

What is pressure in short answer?

Pressure is an expression of force exerted on a surface per unit area. if a force F is applied on area A, then pressure P=F/A.

What is the formula for pressure, force, and area?

Pressure is defined as force per unit area. It is expressed as P = F/A, where P is pressure in pascals, F is the force in newtons, and A is the area in square meters.

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Drop Tower NASA operates a 2.2-second drop tower at the Glenn Research Center in Cleveland, Ohio. At this facility, experimental packages are dropped from the top of the tower, on the 8th floor of the building. During their 2.2 seconds of free fall, experiments experience a microgravity environment similar to that of a spacecraft in orbit.
What is the drop distance of a 2.2- s tower?
(part a)
How fast are the experiments traveling when they hit the air bags at the bottom of the tower?
(part b)
If the experimental package comes to rest over a distance of 0.80 m upon hitting the air bags, what is the average stopping acceleration?
(part c)

Answers

The drop distance is 23.7402 m

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Equation of motion

S = ut + ½ at²

S = 0 × t × ½ × 9.81 × 2.2²

S= 23.7402 m

The drop distance is23.7402 m

v = u + at

v = 0 + 9.81 × 2.2

v= 21. 582 m/s

When they hit the airbags at the bottom of the tower the speed of the experiments is 21.582 m/s

The final speed of the fall will be the initial velocity of stopping

v² - u² = 2as

a = v² - u²/ 2s

a= 310.521816 m/s²

The average stopping acceleration is 310.521816 m/s²

What is displacement?

The temporal rate of change of the position vector can also be used to describe velocity. The velocity of P (for example, a point representing the position of a passenger walking on the train) may be referred to as a relative velocity as opposed to an absolute velocity if one considers a moving initial position, or equivalently a moving origin (e.g., an initial position or origin which is fixed to a train waggon which in turn moves on its rail track).

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The following table shows the distance from the sun of some unknown planets of equal mass.

Distance from Sun

Planet Distance from Sun
W 1.5 AU
X 0.723 AU


Which of the following best explains which planet revolves at a faster speed?
Planet X, because the sun pulls it with a greater force
Planet W, because the sun pulls it with a greater force
Planet W, because the gravitational force is weakened by distance
Planet X, because the gravitational force is strengthened by distance


(D was wrong, I'm taking the test again)

Answers

The correct answer is : Planet X, because the sun pulls it with a greater force

The speed at which a planet revolves around the sun is determined by its distance from the sun and the gravitational force between the planet and the sun. The closer a planet is to the sun, the stronger the gravitational force, and the faster it will orbit. Therefore, Planet X, which is closer to the sun than Planet W, will revolve around the sun at a faster speed, assuming that both planets have equal masses. Thus, the correct answer is "Planet X, because the gravitational force is strengthened by distance." The farther a planet is from the sun, the weaker the gravitational force, but this would result in a slower orbital speed, not a faster one.

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Answer: A A A !!!!  

Explanation: just did the test, got it right thx thx!!!

What is the magnitude of velocity of a 900 kg horse that has a momentum of 8000 kgm/s​

A.8.9 m/s
B.0.11 m/s
C.8900 m/s
D.7100 m/s​

Answers

The magnitude of the velocity of the horse will be 8.89 m/s.

Given, the mass of the horse is 900 kg and the momentum of the horse is 8000 Kgm/s.

To calculate, the velocity of the horse from the given values.

Momentum of any body is defined as the product of the mass of the body and the velocity of that body.                                         Momentum(p) = Mass(m) × Velocity(v)

Keeping the provided values in the formula, momentum = mass × velocity to calculate the velocity of the horse

8000 Kgm/s =  900Kg × velocity

velocity = 8000/900 m/s = 8.89 m/s

So, the velocity of the horse is 8.89 m/s.

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what is life? can you explain in please

Answers

Life is a complex phenomenon that is difficult to define or explain in a simple way. It refers to the characteristic that distinguishes living things from non-living things. Some of the defining characteristics of life include the ability to grow and develop, respond to stimuli, maintain homeostasis, produce offspring, and evolve over time.

Life is also often described as a process that involves the consumption of energy and the conversion of matter to maintain and reproduce itself. This process is known as metabolism. Living things are also capable of reproducing and passing on genetic information to their offspring, which allows for the continuation and evolution of life over time.

In addition to these biological definitions, the concept of life also has cultural, spiritual, and philosophical dimensions. Different cultures and belief systems have their own interpretations of what life is and what it means.

In general, life is a complex and multifaceted concept that encompasses many different aspects of our existence, from the physical and biological, to the cultural and philosophical.

A simple circuit contains a 10 V battery connected with wires to a small bulb. If the power dissipated by the bulb is 0.5 W, what is the resistance of the bulb?

Group of answer choices

200 ohms

100 ohms

5 ohms

20 ohms

Answers

The resistance (slope of a curve) is about 490 so when bulb is lit. According to this model, the resistance was inversely proportional to temperature for materials (such this tungsten filament).200 ohms

LED lights have how many ohms?

The datasheet for such LED will include this information as well as the forward dc voltage. LEDs typically demand 10 to 20mA. For instance, a 9V battery powered ultra-bright blue LED has a forwards voltage or 3.2V and a typical current is 20mA. Thus, the resistor must be 290 ohms and as close to that value as is feasible.

Are batteries highly resistant?

Due to their relatively high resistance, alkaline, carbon-zinc, and the majority of primary batteries can only be used in low-current devices like flashlights, remotes, portable entertainment systems, and kitchen clocks. The resistance gets worse when these batteries run out of power.

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aInfinite Sheets of Charge | 1|2 In both cases shown below, the colored lines represent positive (blue) and negative (red) charged planes. The magnitudes of the charge per unit area on each plane is the same. Case A Case B 1) In which case is the magnitude of the electric field at point P bigger? Case A Case B They are the same Submit (Survey Question) 2) Explain your reasoning Submit

Answers

Because the charge densities per unit area on every plane are equal. Hence, the strength of the electric field around point P is the same in situations A and B.

Explain the electric filed due to infinite line of charge?

Gauss' law can be used to determine the electric field of such an infinite line charge with such a uniform linear charge density.

The electric field is of equal strength at each point of a cylinder and thus is pointed outward when a Gaussian surface with radius r is modeled as a cylinder.

We discovered that electric field is radially oriented away as from line charge and that its strength decreases in inverse proportion to its distance.

The colored lines in the two instances below denote the positive (blue) and negative (red) charged planes, respectively.Because the charge densities per unit area on every plane are equal.

Hence, the strength of the electric field around point P is the same in situations A and B.

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Blood flows through a major artery at 1.2 m/s over a distance of 0.50m then at 0.70 m/s for another 0.50 m through a smaller artery.
Is the average speed of the blood 0.95 m/s greater than 0.95 m/s or less than 0.95 m/s (part a)
Verify your answer to Part A by calculating the average speed.
(part b)

Answers

The average speed of the blood is less than 0.95 m/s and the average speed is 0.884 m/s.

What is average speed?

Average speed is a measure of the rate of change in position of an object over a certain period of time. It is calculated by dividing the total distance traveled by the total time taken. In other words, it is the rate at which an object covers a given distance. Average speed is useful in determining the efficiency of a vehicle, or of a person, in covering a particular distance. For example, if a person drives for 2 hours and travels a total distance of 200 kilometers, the average speed of the body is 100 km/hr (200km / 2 hrs).

The average speed is,

[tex]V_{avg} = \frac{d_{1}+ d_{2} }{\frac{d_{1} }{V_{1} }+ \frac{d_{2} }{V_{2} } }[/tex]

        [tex]= \frac{0.50m + 0.50m}{\frac{0.50m}{1.2m/s}+\frac{0.50m}{0.70m/s} }[/tex]

       = 0.884 m/s

Due to the average speed is 0.884 m/s the average speed of the blood becomes less than 0.95 m/s.

Therefore, the average speed of the blood is less than 0.95 m/s and the average speed is 0.884 m/s.

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Identify the correct sequence of events from this passage.

A. Martin Cooper invented the first cell phone.
B. AT&T discussed the concept of a wireless phone.
C. The FDA ruled that the health risks of cell phones were small.
D. Cell phone became the most common electronic device.

Answers

Answer:

The correct sequence of events is:

A. Martin Cooper invented the first cell phone.

B. AT&T discussed the concept of a wireless phone.

C. Cell phone became the most common electronic device.

D. The FDA ruled that the health risks of cell phones were small.

What is the mass density of a liquid that exerts a pressure of 180 kPa at a depth of 41 m?

Answers

Answer: no answer

Explanation:

Find the moment of inertia for the following objects:
A. A uniform disc of mass M and radius R rotating about its axis. Replace the sum in 3.31 by the appropriate integral and do the integral in polar coordinates.
B. A uniform solid sphere rotating about a diameter. Replace the sum in 3.31 by the appropriate integral and do the integral in spherical coordinates.

Answers

The moment of inertia of a uniform disc of mass M and radius R rotating about its axis is [tex](1/2) MR^2[/tex].

The moment of inertia of a uniform solid sphere of mass M and radius R rotating about a diameter is [tex](8/5) MR^2[/tex].

The moment of inertia of a uniform disc of mass M and radius R rotating about its axis can be found by integrating the moment of inertia of small elements of mass dm located at a distance r from the axis of rotation.

Using polar coordinates, we can write dm = (M/πR^2)rdrdθ, where r ranges from 0 to R and θ ranges from 0 to 2π.

The moment of inertia of each element is given by dI = dm r^2. Therefore, we have:

I = ∫dI

= ∫[tex]r^2 dm[/tex]

= ∫₀²π ∫₀ᴿ (M/πR^2)r³drdθ

= (M/πR^2) ∫₀²π [∫₀ᴿ r³dr] dθ

= (M/πR^2) ∫₀²π [(1/4)R^4] dθ

= (M/πR^2) (1/4)R^4 (2π)

= [tex](1/2) MR^2[/tex]

The moment of inertia of a uniform solid sphere of mass M and radius R rotating about a diameter can be found by integrating the moment of inertia of small elements of mass dm located at a distance r from the diameter. Using spherical coordinates, we can write dm = (M/4πR^3)r^2sinθdrdθdφ, where r ranges from 0 to R, θ ranges from 0 to π, and φ ranges from 0 to 2π. The moment of inertia of each element is given by dI = dm r^2sin^2θ. Therefore, we have:

I = ∫dI = ∫r^2sin^2θ dm = ∫₀²π ∫₀ᴾ ∫₀ᴿ (M/4πR^3)r^4sin^3θdrdθdφ

= (M/4πR^3) ∫₀²π ∫₀ᴾ [∫₀ᴿ r^4sin^3θdr] dθdφ

= (M/4πR^3) ∫₀²π ∫₀ᴾ [(2/5)R^5sin^3θ] dθdφ

= (2/5) MR^2 ∫₀²π [∫₀ᴾ sin^3θ dθ] dφ

= (2/5) MR^2 ∫₀²π [(-cosθ + (3/2)cos^3θ/3)|₀ᴾ] dφ

= (8/15) MR^2 ∫₀²π dφ

= (8/15) MR^2 (2π)

= (8/5) MR^2

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Landing with a speed of 71.4 m/s and traveling due south, a jet comes to rest in 939 m
Assuming the jet slows with constant acceleration, find the magnitude of its acceleration.
(part a)
Assuming the jet slows with constant acceleration, find the direction of its acceleration.
(part b)

Answers

The acceleration is 2.7 m/s^2.

What is the acceleration?

Acceleration is a measure of the rate at which an object changes its velocity. It is defined as the change in velocity per unit time and has units of meters per second squared (m/s^2). Acceleration can be positive (when an object is speeding up), negative (when it is slowing down), or zero (when its velocity is constant).

We can get the acceleration;

v^2 = u^2 - 2as

v = final velocity

u = initial velocity

a = acceleration

s = distance

Thus we have that;

v = 0 m/s thus;

u^2 = 2as

a = u^2/2s

a = (71.4)^2/2 * 939

a = 5097.96/1878

a = 2.7 m/s^2

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A car driving at a constant speed of 20 m/s (meters per
second) turns right, down a street.
1. Is the car accelerating during the turn? Why or why not?
2. Would you feel any of the movement during this event?
Why or why not?
EXTRA HELP
What is changing as the car turns? What changes qualify as
an acceleration? How can you feel acceleration?

Answers

Answer:

it is accelerating because it is at constant speed.

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