a 1.120kg car is travelling with a speed of 40m/s find its energy

Answers

Answer 1

Answer:896/10 JOULES.

Explanation:


Related Questions

How fast does the depth of the water change when the water is 10 ft high if the cone leaks water at a rate of 10 ft3/min?.

Answers

Water depth decreases at 128/125π ft ^3/min when the cone leaks water at a rate of 10 ft3/min

The ratio of the radius(r) of the upper surface of the water to the water depth (w) is based on the overall dimensions of the cone r/w = 5/10.

The volume of a cone of water is given by the formula V(w) = (π/12)w^3

After differentiation we get dV/dW = π/4w^2

We are told that dV/dT = -3

dW/dT= (dW/dV)(dV/dT) = 4/πw^2(-3)

When the depth of water is 10 ft we get the rate of fall of water is 128/125π ft ^3/min.

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A wheel and axle on a bicycle are designed with an axle radius of 0. 125 meters and a wheel radius of 0. 5 meters. If a force of 800 newtons is applied to the axle, what is the maximum output force of the bike wheel?.

Answers

The net force of the runner, given the data from the question is 280 N.

What is net force

The net force is the vector sum of forces acting on a particle or object.the net force is a single force that replace the effective of the original forces on the particles motion.

Sol-As per the given question the following data are obtained-

Exerting force = 325 N

Resistance force = 45 N

Net force =?

The net force of the runner can be obtained as illustrated below:

Net force = Exerting force - resistance force

Net force = 325 - 45

Net force = 280 N

From the calculation we can get the runner's net force is 280 N.

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A box is pulled with a force of 27N to produce a displacement of 17m. If the angle between the force and displacement is 30 degrees, Find the work done by the force

Answers

A box is pulled with a force of 27N to produce a displacement of 17m. If the angle between the force and displacement is 30 degrees, the work done by the force is 397.50Joules.

To find the work done, the given data are,

Force =27 N

Displacement = 30 degrees.

What is  Work done?

Work done can be defined as the body that moves with some acceleration and did some work with  a force.

The product of the displacement and the applied force can be also defined as the Work done.

The formula for work done with the angle of the distance or displacement is written as,

W = F × d × cosθ

Substituting all the given data,

W= 27 × 17× cos(30)

= 397.50 joules.

The work done by the force can be calculated as 397.50 joules.

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Which action enhances the effectiveness of levothyroxine for the patient with hypothyroidism?.

Answers

Mechanism of action enhance the effectiveness of  levothyroxine for the patient with hypothyroidism.

What is levothyroxine?

levothyroxine is  also known as L-thyroxine, is a  manufactured from of the thyroid hormone thyroxine. It is used to the  treat thyroihormone deficiency, including a severe from thrle known as myxedema coma. It may also be used to treat and prevent certain types of the thyroid tumors. It is not indicated for the weight loss.

Levothyroxine absorption is the increased by fasting and it is decreased in the  presence of the food and it is the malabsorption syndromes. Dietary fiber to reduces the bioavailability of T4.

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A block of ma 5kg liced down from ret on the inclined plane which incline at an angle 60 degree if the block travel at a ditance 500 ec calculate the frictional force bettwen the block and the plane

Answers

The frictional force between the block and the plane is 25 N.

Friction is the force resisting the relative motion of sturdy surfaces, fluid layers, and material factors sliding towards each specific. There are numerous styles of friction. Dry friction is a strain that opposes the relative lateral movement of two stable surfaces in touch.

Calculation:-

mass = 5 kg

angle of inclination = 60°

distance traveled = 500 m

force = mg cos 60°

          = 5 × 10 × 1/2

          = 25 N

Friction is the shape of contact pressure. It exists between the surfaces that are in touch. The frictional force relies upon the character of the floor in contact. The rougher the ground, the extra friction is involved. The frictional force is proportional to the urgent pressure, which is the burden of the body. it's miles impartial of the place of the touch.

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PLEASE I NEED ANSWERD OF D AND E
d) find the power cunsumption in 22 ohms lamp and 4.5 ohms lamp ?

e) find the power delivered by the battery

Answers

Answer:

2) find the power rating of the given transformer:

the transformer is rated at 250v,50hz, and it is used with a circuit which

consists of a 200v,50hz d.c. source and a rheostat.the rheostat is used to control the current in the primary of the transformer.the maximum readable current in the primary of the transformer is 250mA.the transformer is wired as an autotransformer with the primary winding of 250 turns and the secondary winding of 250 turns.the current in the secondary winding of the transformer is to be kept at 10mA when the load current in the rheostat is 10mA.

3) a single phase a.c. supply of 230v,50hz is connected across a series combination of a capacitor and a resistor in parallel with a pure inductor.the resistor and inductor are connected in series with each other.the impedance of the inductor is 100 ohms and the impedance of the capacitor is 60 ohms.the supply current is 10A.

a) find the impedance of the capacitor if the power factor of the circuit is 0.8 lagging.

b

Explanation:

Answer:

Explanation:

Given:

R₁ = 22 Ω

R₂ = 4.5 Ω

U = 45  V

_________

I - ?

P₁ - ?

P₂ - ?

P - ?

Circuit resistance:

R = R₁ + R₂ = 22 + 4.5 = 26.5 Ω

Circuit current:

I = I₁ = I₂ = U / R = 45 / 26.5 ≈ 1.7 А

Lamp voltages:

U₁ = I₁·R₁ = 1.7·22 ≈ 37.40 V

U₂ = I₂·R₂ = 1.7·4.5 ≈ 7.65 V

Power:

P₁ = U₁·I₁ = 37.40·1.7 ≈ 63.6 W

P₂ = U₂·I₂ = 7.65·1.7 ≈ 13.0 W

P = U·I = 45·1.7 ≈ 76.5  W

we can see all three objects clearly in the visible part of the spectrum, even though the peak intensity might lie outside that region. why is this so?

Answers

We an see all three objects clearly in the visible part of the spectrum, even though the peak intensity might lie outside that region because we perceive only what lies in the visible region.

The sun and Sirius A emits light in every part of the electromagnetic spectrum. But our eyes cannot perceive every frequency of light. We see only what can be perceived by a human eye. Just because we cannot see other spectrum does not mean that it is not present.

The visible spectrum of light is 400 nm to 780 nm. The colours are:

Violet - 400 to 420 nmIndigo - 420 to 440 nmBlue - 440 to 490 nm Green - 490 to 570 nmYellow - 570 to 585 nmOrange - 585 to 620 nmRed - 620 to 780 nm

Therefore, we can see all three objects clearly in the visible part of the spectrum, even though the peak intensity might lie outside that region because we perceive only what lies in the visible region.

The given question is incomplete. The complete question is:

Consider three objects - Sirius A, Sun and light bulb. We can see all three objects clearly in the visible part of the spectrum, even though the peak intensity might lie outside that region. why is this so?

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8. (Inelastic) A 10,000 kg truck traveling at 4 m/s runs head-on into a stationary
Ford Pinto mass 1000 kg. How fast will the truck and Pinto be traveling as they
move down the street stuck together?
ans. 3.6 m/s

Answers

Answer:

Explanation:

Given:

m₁ = 10 000 kg

V₁ = 4 m/s

m₂ = 1 000 kg

V₂ = 0 m/s

____________

V - ?

The law of conservation of momentum in inelastic collision:

m₁·V₁ + m₂·V₂ = (m₁ + m₂)·V

V₂ = 0

m₁·V₁  = (m₁ + m₂)·V

V =  m₁·V₁ / (m₁ + m₂)

V = 10 000 · 4 / (10 000 + 1 000) ≈ 3,6 m/s

The pressure at the bottom of a glass filled wlth water (p 1000 kg/m') Is P. The water Is poured out and the glass Is filled wlth ethyl alcohol (p 806 kg/m ). The pressure at the bottom of the glass Is now which of the following? equal to P smaller than P ~indeterminate ~larger than

Answers

Option (a) smaller than P  This is because the pressure (P) at any depth 'd' from the top surface of the water with density (ρ).

P = ρ × g × d

where,

g is the acceleration due to the gravity

thus from the above equation it can be concluded that the pressure at any depth 'd' is directly proportional to the density of the water.

thus,

in the given case the density of the water is lower than that in the first case.

The term "Pressure" refers to the thrust (force) applied to a surface per unit area. It can alternatively be described as the force-to-area ratio (over which the force is acting).

Pressure (P) = Thrust/Area is the formula and the unit of pressure

Pascals (Pa) is the SI unit of pressure. 1 Pa = 1N/m2

An illustration would be that a sharp pin is simpler to hammer than a dull pin. This is due to the fact that a blunt pin's end has a lesser area than a sharp pin's end. As a result, there is an increase in pressure, which makes it simpler to hammer the sharp pin.

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Why would placing two very strong magnets in the middle of two separate balloons provide a good model for nuclear fusion?

Answers

Answer:

because the friction in the baloons and the magnetism make it like nuclear fision

Explanation:

The magnetic field and friction between the balloons when placing two very strong magnets in the middle of two separate balloons provide a good model for nuclear fusion.

What is nuclear fusion?

Nuclear fusion is the process through which light elements interact to create heavier elements (up to iron). Significant amounts of energy are released when interacting nuclei are from elements with low atomic numbers, such as hydrogen (atomic number 1) or its isotopes deuterium and tritium.

Thermonuclear weapons, or hydrogen bombs, which were created in the decade immediately following World War II, were the first to utilize the tremendous energy potential of nuclear fusion.

There are two main categories of fusion reactions: those that maintain the ratio of protons to neutrons and those that convert protons to neutrons.

Therefore, the magnetic field and friction in the balloons when placing two very strong magnets in the middle of two separate balloons provide a good model for nuclear fusion.

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2. Draw a free body diagram showing all the forces acting on a box of a dolly pushes the cart with. An applied force of 10N and a frictional force of 5N acts on the cart

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In physics and engineering, a free frame diagram (FBD; also referred to as a force diagram) is a graphical instance used to visualize the applied forces, moments, and ensuing reactions on a frame in a given situation.

A free-body diagram is a sketch of an item of interest with all the surrounding items stripped away and all of the forces acting on the frame shown. The drawing of an unfastened-body diagram is a critical step in the solving of mechanics issues because it helps to visualize all the forces appearing on an unmarried object.

A free-body diagram is a graphic, dematerialized, symbolic representation of the body (structure, element, or segment of an element) wherein all connecting "pieces" have been removed. An FBD is a convenient method to model the structure, structural detail, or phase that is under scrutiny.

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when the rubber band is extended, is the net external work done on the rubber band positive, negative, or zero?

Answers

The elastic energy that is stored in the band starts to affect you as it begins to relax.the net external work done on the rubber band positive.

However, some of this energy, like before, is converted into heat and some into molecular vibrations. You don't get as much work done as you put in due to hysteresis, thus the net work is not zero.When the rubber band is stretched, potential energy increases.

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Please answer now!! correct answer will get brainliest!

Answers

True, false, false, false
Here ya go :)

mechanical efficiency considers the ratio between the energy expenditure of exercise and what other component? group of answer choices energy input energy output movement velocity

Answers

Mechanical efficiency considers the ratio between the energy expenditure of exercise and option B. Energy output.

Mechanical efficiency is an exercising term that describes the ratio of labor output to work input for the duration of the bodily hobby. The more efficaciously you pass with the least quantity of attempt expended, the greater your mechanical efficiency.

Mechanical gain is the ratio of load to attempt, i.e., Output force to enter force. efficiency is the ratio of labor completed by way of a machine to the work completed on the system, i.e., Output paintings to enter work. The extra efficiently you pass with the least amount of effort expended, the extra your mechanical efficiency. A degree of mechanical performance is specifically important to athletes whose purpose is to improve sports overall performance.

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When a piece of sodium metal is dropped into a calorimeter filled with water, hydrogen gas evolves. The temperature of the mixture rises because.

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Hydrogen gas emerges when sodium metal is placed into water. The reaction is therefore 2Na+2H2OH2+2NaOH. Sodium hydroxide is created during the process, and hydrogen gas is also released.

As soon as sodium metal combines with water, sodium hydroxide (NaOH) and hydrogen gas are produced, creating an odorless basic solution (H2). Even after the solution has become fundamental, the reaction still occurs. Because there contains hydroxide in the dissolved state, the final solution is basic. Exothermic is the response. Reversible hydrogen storage could be achieved by using sodium oxide, Na2O, which reversibly absorbs hydrogen, H2, to create sodium hydride, NaH, and sodium hydroxide, NaOH. In the presence of water, sodium metal interacts to form sodium hydroxide and hydrogen gas. when 100.00 g of water and 0.575 g of sodium are combined.

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A 1. 2-kg spring-activated toy bomb slides on a smooth surface along the x-axis with a speed of 0. 50 m/s. At the origin 0, the bomb explodes into two fragments. Fragment 1 has a mass of 0. 40 kg and a speed of 0. 90 m/s along the negative y-axis. In the figure, the energy released by the explosion is closest to.

Answers

Fragment 2's velocity vector is 80.54°, and the x-axis is at 0.075 and the velocity of the y- axis is 0.46m/s.

We are given that,

Mass of the spring = m = 1.2kg

Speed of the spring = v = 0.05 m/s

Mass of the first fragment = m₁ = 40 kg

Initial speed of first fragment =u₁ = 0.9 m/s

m₂ = 0.8 kg

To find the second segment's velocity using the idea of linear momentum conservation,

Locate the x-axis,

m u cos θ = m₁ v₁ cos θ + m₂ v₂ cos θ

1.2 x 0.05 x cos (0) = 0 + 0.8 v₂ cos θ

v₂ cosθ = 0.075

Find the y-axis:

1.2 (0) = -0.4 (0.9) + 0.8 (v₂ sin θ)

v₂ sinθ = 0.36/0.8

v₂ sinθ = 0.45

By solving above two equation we can get ,

tanθ = 6.0

θ = 80.54°

Putting the value of θ in y- axis component then we get,

v₂ sinθ = 0.45

v₂  = 0.45/sinθ

v₂ =  0.46m/s

Therefore , fragment 2's velocity vector is 80.54°, and the x-axis is at 0.075 and the velocity of the y- axis is 0.46m/s.

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how many 75- w lightbulbs, connected to 120 v as in the figure, can be used without blowing a 17 a fuse?(figure 1)

Answers

P=VI,Current drawn by each light bulb Number of bulbs x Current produced by each bulb is 15, Number of bulbs = 17/0.625 = 11 Numbers, I=P/V = 75/120=0.625 Amp, Number of bulbs x Current drawn bulb is 15,.

What is happening right now?

The pace at which charge moves across a location on a circuit is known as current. Multiple coulombs of charge passing over a wire's cross section in a circuit causes a large current to flow. High currents can be produced at low speeds if the charge carriers are tightly packed within the wire.

What exactly are current and electron?

Electron current refers to the movement of electrons. The negative terminal releases electrons into the positive terminal. Traditional current—also known as just current—behaves as though positive charge carriers are the cause of current flow. Normal current moves from the positive electrode to a negative terminal.

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A pilot wants to drop a bomb on a target. His plane is traveling at a speed of 166 m/s horizontallly and is at an altitude of 762.5 meters . How far in front of the target should he let go of the bomb to ensure succes?

Answers

Answer:

2070 m

Explanation:

Find the time to fall from d=  762.5 m to the ground :

   d = 1/2 a t^2     shows t = 12.5 s

Horizontal distance =   166 m/s   * 15.5 s =   2069.7 m =~2070 m

a 1500-kg car accelerates from 0 to 25 m/s in 7.0 s with negligible friction and air resistance. what is the average power delivered by the engine? (1 hp

Answers

Using the concepts of work, power and energy, we got that 90hp is  the average power delivered by the engine for a 1500-kg car accelerates from 0 to 25 m/s in 7.0 s with negligible friction and the air resistance.

we know that,

Work = force x distance

= (ma)x(d)

Similarly, power = energy/time

Initial velocity(V[tex]_i[/tex])=0m/sec

and Final velocity(V[tex]_f[/tex]) = 25 m/s

and t = 7 sec.

We know that acceleration is defined change of velocity in per unit time

Therefore, acceleration =(25-0)/7=3.6m/sec²

and distance(d) = 87.5 meters

Now, we have mass and acceleration, so on putting the values we get

=>F = ma

=>F=1500×3.6

=>F=5400Newton,

Therefore, energy will be equal to=Force × distance

=>Energy=5400×87.5

Energy = 5400×87.5 = 4.7×[tex]10^{5}[/tex] Joules

Therefore, power will be equal to Energy/Time

=>Power= 4.7×[tex]10^{5}[/tex]/7sec

=>Power= 67,500 Watts or 90 hp.

Hence, if a 1500-kg car accelerates from 0 to 25 m/s in 7.0 s with negligible friction and air resistance, the average power delivered by the engine is 90hp.

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in order for LeBron James to score a slam-dunk what must he exert?

Answers

His hand and gastrocnemius

stone has energy when it is lifted at a height. Why?​

Answers

Answer:

Explanation:

Comment

The question really means, what kind of energy? It immediately takes on the energy associated with the height.  

Potential Energy = mgh

m is the mass of the stoneg = 9.81 in the metric systemh = the height measured where the stone is.

Now if you are the one holding the stone, and you let go then immediately the stone takes on both Potential Energy (which is going down in value because the height is going down) and Kinetic Energy (because the stone is moving faster as it falls).

Kinetic Energy = 1/2 mv^2

So there cannot be Kinetic energy until the stone is released from a certain height. Until it is released, the stone has energy because when released, it will pick up energy because of increasing velocity.

A 2.50 kg book is placed on a flat desk. suppose the coefficient of static friction between the book and the desk is 0.448 and the coefficient of kinetic friction is 0.373. how much force is needed to begin moving the book?

Answers

Answer:

11 N

Explanation:

You will need enough force to overcome the static friction

Fn = 2.50 kg * 9.81 m/s^2

F of static friction =  Fn * coeff static =  2.50 * 9.81 * .448 =~ 11 N

Two ice skaters suddenly push off against one another starting from a stationary position. The 45-kg skater acquires a speed of 0. 375 m/s moving to the right. What speed does the 60-kg skater acquire?.

Answers

The speed is v = 0.281 m/s speed does the 60-kg skater acquire.

From law of conservation of momentum.

[tex]p_{i}[/tex] = [tex]p_{f}[/tex]

([tex]m_{1}[/tex]+[tex]m_{2}[/tex])v = [tex]m_{1}v_{1}[/tex] + [tex]m_{2}v_{2}[/tex]

(45+60)kg × 0m/s = 45×0.375 +60[tex]v_{2}[/tex]

0=45×0.375 +60[tex]v_{2}[/tex]

60[tex]v_{2}[/tex] = -45×0.375

[tex]v_{2}[/tex] = -0.28125 m/s

∴ v= 0.281m/s

In Newtonian mechanics, an object's mass and velocity are combined to form momentum, more precisely linear momentum or translational momentum. It has both a magnitude and a direction, making it a vector quantity. If an object has mass (m) and velocity (v), both of which are vector quantities, then its momentum (p) is: p= mv.

The kilogram meter per second (kg m/s), or newton-second in the International System of Units (SI), is the unit used to measure momentum.

The rate of change of a body's momentum is equal to the net force acting on it, according to Newton's second law of motion.

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a sign painted no a store window is reversed when viewed from inside the store if a person inside the store views the reversed sign in a plane mirror does the sign appear as itwould when viewed from outside the store

Answers

If a sign painted on a store window is reversed when viewed from inside the store and if a person inside the store views the reversed sign in a plane mirror it would appear as it would when viewed from outside the store.

A mirror typically reverses the image when seen from our point of view. Here the sign is initially reversed when seen from inside the store. If the sign is viewed in a mirror from inside the store, the sign would once again be reversed.

Since the sign is reversed from the reversed sign, it would appear normally as viewed from outside the store.  

Therefore, if a sign painted on a store window is reversed when viewed from inside the store and if a person inside the store views the reversed sign in a plane mirror it would appear as it would when viewed from outside the store.

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total internal reflection only occurs when the index of refraction of the outside material is material the light is in.

Answers

From a medium with a high index of refraction, light moves to one with a low index of refraction.

What is total internal reflection?

Total internal reflection is the complete reflection of a light ray from the surrounding surfaces back into a medium, such as glass or water, in physics. If the incidence angle exceeds a specific limiting angle known as the critical angle, the phenomenon will manifest.

A ray of light in a medium with a higher index of refraction typically causes total internal reflection at the border between two transparent media when it approaches the other medium at an angle of incidence larger than the critical angle.

The essential angle for a water-air surface is 48.5°. The critical angle (and thus the angle of total internal reflection) will vary significantly with wavelength and, therefore, with color since indices of refraction depend on wavelength. Both refraction and reflection take place in different amounts at all angles smaller than the critical angle.

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How enzymes are working out of the living cells?.

Answers

Enzymes are working out of the living cells by binding to reactant molecules.

Enzymes work by binding to reactant molecules and holding them in such a way that the chemical bond-breaking and bond-forming processes take place more readily. Reaction coordinate diagram showing the course of a reaction with and without a catalyst. With the catalyst, the activation energy is lower than without.

Enzymes help with the chemical reactions that keep a person alive and well. For example, they perform a necessary function for metabolism, the process of breaking down food and drink into energy. Enzymes speed up (catalyze) chemical reactions in cells.

Therefore, enzymes are working out of the living cells by binding to reactant molecules.

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Find the moment of inertia ix of particle a with respect to the x axis (that is, if the x axis is the axis of rotation), the moment of inertia iy of particle a with respect to the y axis, and the moment of inertia iz of particle a with respect to the z axis (the axis that passes through the origin perpendicular to both the x and y axes).

Answers

The definition of moment of interia allows to find the results for the moment of inertia with respect to each axis are:

1-Iₓ = m r²

2-Iy=9m r²

3-Iz=10m r².

What is moment interia?

The moment of interia is a scalar quantity is obtained by the expression.

Sol-

I =∫ r² dm

Where I is the moment of inertia, m the mass of the body and r the distance from the axis of rotation.

In the case of point particles, the expression reduces to

    I = m r²

In this case we calculate with respect to each coordinate axis.

a) With respect to the x axis the distance is x = r, the moment of inertia is

      Iₓ = m r²

with respect to the y-axis, indicate that the distance is y = 3 r.

We calculate

        I_y = m (3r) ²

        I_y = 9 m r²

c) Regarding the z-axis.

We look for the distance.

         z =√x^2+y^2

         z = √ 1^2+3^2

We calculate the moment of interia  Iz = m (10r²)

        Iz = 10 m r²

In conclusion using the definition of moment of inertia we can look for the results of the moment of interia for each axis are:

  a) Iₓ = m r²

  b) I_y = 9 m r²

  c) I_z = 10 m r²

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how much force must be applied to accelerate a 2 kg object at 10 m/s2 if friction exerts a force of 1 N

Answers

The force applied is 21N

According to Newton's second law, acceleration and net external force are directly proportional, while acceleration and mass are inversely proportional. Newton's second law of motion states, "Force is equal to the rate of change of momentum." For a constant mass, force equals mass multiplied by acceleration.

Given

Mass = 2kg

Acceleration = 10 m/s2

Friction force = 1

We have to determine the force

By using newtons second law formula

F - f  = ma

F -1 = 2 x 10

F – 1 = 20

F = 20 + 1

F = 21

Therefore the force applied is 21N

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The three types of meteorites come from different parts of their parent bodies. Stony-iron meteorites are rare because.

Answers

The three different types of meteorites originate from various locations on their parent bodies. Because only a small portion of a parent body contains both stone and iron, stony-iron meteorites are uncommon.

What makes stony-iron meteorites uncommon?

Pallasites were most likely formed in a relatively small area within these differentiated asteroids, which may account for their scarcity. Only about 45 known pallsites exist among the many thousands of identified meteorites.

More than 95% of meteorites that are seen to crash to Earth are made of stone. The two types of them are chondrites and achondrites. The majority of both types also contain metallic iron in small, dispersed grains, but silicate minerals make up the majority of both.

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a small ball of mass 23 g is suspended from a string of length 27 cm and whirled in a circle lying in the horizontal plane. If the string makes an angle of 31◦ with the
vertical, find the centripetal force experienced
by the ball. The acceleration of gravity is
9.8 m/s
2
.
Answer in units of N

Answers

The centripetal force experienced by the small ball of mass 23 g suspended from the string is 0.1354 N.

Given in the question,

Mass of the ball = 23 g

Length of the string = 27 cm

Angle made with the verticle = 31◦

Let  m is the mass of ball

       g is the gravitational force.

       T is the tension applied on the string,

The horizontal force acting on the small ball is,

Σ Fx = T cosθ - mg

       = 0

T = mg / cosθ

The centripetal force acting on the small ball is,

Fc = T sinθ

T = Fc / sinθ

Comparing T and equating both the equations, we have

mg / cosθ = Fc / sinθ

Fc = mg tanθ

Putting the values given , we have,

Fc = 0.023 x 9.8 x tan 31◦

    = 0.2254 x 0.60086

    = 0.1354 N

Hence, the centripetal force experienced by the small ball of mass 23 g suspended from the string is 0.1354 N.

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