a 1,400-kilogram car is also traveling in a straight line at 10 m/swhat is its momentum

Answers

Answer 1

The velocity of the car is v = 28.6 m/s.

Solution:

v = p/m

v = 40,000 kg x m/s

1,400 kg

v = 28.6 m/s

Average velocity is a measure of total displacement divided by total time. The total displacement is the distance between the start and endpoints. Since the car moves from point A at both the start and end points the total displacement is zero and the average velocity is also zero.

Velocity is the distance traveled per unit of time, the speed of movement. The speed of a car traveling on a smooth, flat section of a highway without traffic congestion is constant and not zero. Acceleration is the rate of change of velocity. The reason is simple. Velocity is the percentage of time an object moves along a path and Velocity is the speed and direction of an object's movement.

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Related Questions

A bullet of mass m and speed v is fired at, hits and passes completely through a pendulum bob of mass M on the end of a stiff rod of negligible mass and length L. The bullet emerges with a speed of v/2 and the pendulum bob just makes it over the top of the trajectory without falling backward in its circular path. Determine an expression (V=?) for the minimum initial speed the bullet must have in order for the pendulum bob to just barely swing through a complete vertical circle. (Use any variable or symbol stated above as necessary.)

Answers

Required value of initial speed of the bullet be ( 4M/m)√(gL).

Given parameters:

Mass of the bullet =m.

Mass of the bob of the pendulum = M.

speed of the bullet before collision = v

Speed of the bullet after collision = v/2.

Length of the pendulum stiff rod = L.

Let speed transmitted to the pendulum be u.

Using principle of conservation of momentum:

mv = Mu + mv/2

⇒ Mu = mv/2

⇒ u = (m/M)v/2

We know that: to make the bob over the top of the trajectory without falling backward in its circular path, required speed be = √(4gL). [ where g = acceleration due to gravity]

To be minimum initial speed the bullet must have in order for the pendulum bob to just barely swing through a complete vertical circle:

u = √(4gL)

⇒  (m/M)v/2 = √(4gL)

⇒ v =( 4M/m)√(gL).

Hence, minimum required  speed of the bullet be ( 4M/m)√(gL).

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Please help with these questions

Answers

3) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4) 90 J work has been done by her

5) 51 J work was done

6) He have done  [tex]10^{4}[/tex] J  of work

7) no work is done

8) no work is done

9) 700 J is the work done on the car

10) 10.68 N  force is applied

3 ) unit of the following are :

a) force = Newton

b) distance = meter

c) work = Joule

4 ) work done = force * displacement

                       = 75 * 1.2 = 90 J

5 )  work done = force * displacement  

                        = 15 * 3.4 = 51 J

6 ) work done = force * displacement  

                        = 100 * 100 = [tex]10^{4}[/tex] J

7) no work is done because no displacement occurred

8)  no work is done because no displacement took place

9) work done = force * displacement

                        = 12.5 * 56 = 700 J

10)  force = work done / displacement

                = 142 / 13.3 = 10.68 N

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After completing a workout/activity, it is best to use this type of stretching.

Answers

After completing a workout/activity, it is best to use Static stretching.

Static stretching is most effective at the quit of your workout. It includes stretches that might be held for a period of time to help extend and unfasten your muscle mass and connective tissue. that is special from a dynamic warmup due to the fact you hold your body nonetheless.

It is a good concept to do dynamic stretching before a workout, and static stretching after a workout, irrespective of what type of exercise you're doing. What you need to differ based on your workout is which muscle groups you are running, on account that it's crucial to warm up the muscle mass you are certainly going to be using.

A dynamic stretching heat-up gets you prepared for something exercising you're approximate to accomplish this is the first-rate form of stretch before an exercising while static stretching is quality for the stop of your workout.

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Which land feature is marked on the map by the $X$ ?
A. valley
B. plain
C. hill
D. mountain

Answers

Mountain is the land feature is marked on the map as x.

What features are shown on a topographic map?Simply described, a topographic map is a two-dimensional depiction of a piece of the earth's three-dimensional surface. Topographic maps are used to depict the land surface since topography is the form of the land surface. Since topographic maps depict how the earth's surface is shaped, they are useful tools in geologic investigations. By utilizing contour lines, cartographers are able to depict the three-dimensional land surface on a flat sheet of paper, making it possible to estimate both horizontal distances and vertical heights from a topographic map.A topographic map is easily recognized by the contour lines that depict the form of the Earth's surface.To unite locations of equal height on the land surface above or below a reference surface, such as mean sea level, contours are imaginary lines.

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About how much greater is the gravitational force exerted by the moon on the near side of the earth than on the far side?.

Answers

Difference in Gravity of 7%

The near side of the Earth is 12740 km closer to the Moon than the far side. As a result, the near side experiences a gravitational force that is 7% stronger than the far side.The force that pulls items toward the centre of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.Differential gravitational forces, or gravitational forces that are not equal across a body's finite size, are the fundamental mechanism.

Radius of the earth, r = 6.37*10^6

by solving ((Fn-Ff)/Fn)*100 answer will be of 7%

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What is the most common cause to food born illnesses?

1.Biological hazards (people working while ill, not washing hands, improper temperature control)
2.Chemical hazards (poisonous substances like soaps, sanitizers, or pesticides)
3.Physical hazards (broken glass, jewelry, bandages, or fingernails)

Answers

Option 1. Biological hazards (people working while ill, not washing hands, improper temperature control),  is the most common cause to food born illnesses.

Infectious organisms or their toxins are the maximum commonplace reasons for food poisoning. Food poisoning symptoms may additionally include cramping, nausea, vomiting, or diarrhea. Maximum meal poisoning is slight and resolves without treatment. ensuring ok hydration is the maximum vital element of treatment.

Foodborne infection (food poisoning) is a result of consuming contaminated meals, beverages, or water and may be a diffusion of microorganisms, parasites, viruses, and/or pollution. lots of those pathogens can be received thru extra than simply food, drinks, or water.

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joey is riding in an elevator which is accelerating upwards at 2.0 m/s2. The elevator weighs 300.0 kg, and Joey weighs 60.0 kg. What is the tension in the cable that pulls the elevator upwards?

Answers

Answer:

The tension in the cable is 1800 N.

Explanation:

What do you still wonder about force and motion as it relates to the pod and asteroid collection mission that did not go as planned?.

Answers

To collect the asteroid an equal magnitude of the force in opposite direction is needed.

What is force ?

The motion or speed of an object depends upon the magnitude and the direction of the force.

If the direction of the force is against the direction of motion, then the object will slow down or stop. The two forces of the same magnitude in the opposite direction cancel each other and the collided objects stop each other.

Therefore, to collect the asteroid an equal magnitude of the force in opposite direction is needed.

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A particle leaves the origin with a velocity of 7.2 m/s in the positive y direction and moves in the xy plane with a constant acceleration of (3.0 - 2.0) m/s2. At the instant the particle moves back across the x axis (y = 0), what is the value of its x coordinate?

Answers

When the particle reaches its maximum positive x coordinate, the displacement is 11.62m.

What is acceleration ?

The rate at which speed of velocity change over time is referred to as acceleration. When a point and object speeds or decelerates, it is moving straight ahead. Motion on a circular accelerates even while the speed is constant so because orientation is constantly changing.

Briefing:

The particle's displacement is computed as follows;

v² = u² + 2as

where;

a is acceleration

a = √(3² - 2²)

= 2.23 m/s²

0 = u² + 2as

s = -u²/2a

s = -(7.2²)/(2 x 2.23)

s = -11.62 m

When the particle reaches its maximum positive x coordinate, the displacement is 11.62m.

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Why is the sun not the major factor in the tides?

Answers

Answer: the moon is closer.

Explanation:

The moon is closer to the earth than the sun, which results in a larger gravitational gradient for the moon even though the sun is considerably more massive and has stronger overall gravity than the moon.

Write the slope-intercept form of the given line. Include your work in your final answer.

Answers

The slope intercept form of given line is y = 1x+-1.

Solution:

y = mx+b

m = slope which is 1/1 because it is rise over run (rising 1, running 1)

b = y-intercept form which is -1 because that is where the line meets the y-axis.

The slope is the first number appearing in the equation. The slope is the coefficient of x, regardless of order. The intersection point is the point on the y-axis through which the slope of the line passes. The y-coordinate of the point where the line or curve intersects the y-axis. This is shown by writing the equation for the straight line y = mx+c. where m is the slope and c is the y-intercept.

The slope indicates how much the vertical changes for a given horizontal change. The shape of the slope intercept is actually equal to y plus MX plus b. It's called a slope-intercept shape because it has a slope and an intercept. The slope is defined as the ratio of the vertical change between two points to the horizontal change between the same two points.

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Disclaimer:- Your question is incomplete,please see below for the complete question.

Write the slope-intercept form of the given line. Include your work in your final answer.

Line is Y = mx +c

where m=1

c = -1

What causes an object to slowdown or speed up

Answers

Answer:

A force can speed up or slow down an object. A force can change the direction in which an object is moving. A bigger force on an object will produce a bigger change in the motion. A heavier object requires a larger force than a lighter object in order to undergo the same change in motion.

The length of a simple pendulum is 0.80 m and the mass of the "bob" at the end is 0.31 kg. The pendulum is pulled away from equilibrium at an angle of 6.8 degrees and released from rest.

a. What is the angular frequency of the motion?
b. Using the position of the bob at its lowest point as the reference level, determine the total mechanical energy of the pendulum as it swings back and forth.
c. What is the bob's speed as it passes through the lowest point of the swing?

Answers

a) angular frequency of the motion is ω = 3.5s⁻¹

b) total mechanical energy of the bob is T.M.E = 0.029J

c) bob's speed at the lowest point is V= 0.43m/s.

A mechanical device that oscillates or sways is known as a simple pendulum. The gravitational force is primarily responsible for this motion, which takes place in a vertical plane.

Given,

Length of a simple pendulum, L = 0.80m

Mass of the bob, m = 0.31 kg

h= L- LcosΘ = L (1 - cosΘ)

a) Angular frequency, ω = 2π / T

where, T = 2π √(L/g)

ω = 2π / 2π √(g/L)

ω =√(9.8 / 0.80) s⁻¹

ω = 3.5s⁻¹

b) Total mechanical energy, T.M.E = (K.E.)ₐ + (P.E.)ₐ

As (K.E.)ₐ = 0

(P.E.)ₐ =mgh

T.M.E = 0 + mgh, where h = L (1-cosΘ)

T.M.E = ngL (1-cosΘ)

= 0.31*9.8*0.80(1-0.988)

= 0.029J

Thus, T.M.E = 0.029J

c) bob's speed at the lowest position, V

TMEb = 0.029J

(KE)b + (PE)b = 0.029J

1/2mV² + 0 = 0.029J

V =√(2*0.029/m)

V = 0.43m/s

So, the speed at the lowest point is V= 0.43m/s.

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Exercise 2.42
A hot-air balloonist, rising vertically with a constant velocity of magnitude v=5.00 m/s, releases a sandbag at an instant when the balloon is a height h=40.0m above the ground (Figure 1). After it is released, the sandbag is in free fall. For the questions that follow, take the origin of the coordinate system used for measuring displacements to be at the ground, and upward displacements to be positive.
A) Compute the position of the sandbag at a time 0.245 s after its release.
B) Compute the magnitude of the velocity of the sandbag at a time 0.245s after its release.
C) Determine the direction of the velocity of the sandbag at a time 0.245 s after its release.
D) Compute the position of the sandbag at a time 1.15 s after its release.
E) Compute the magnitude of the velocity of the sandbag at a time 1.15 s after its release.
F) Determine the direction of the velocity of the sandbag at a time 1.15 s after its release.

Answers

The position and the velocity of the sandbag at a time 0.245 s after its release is 44.7 m and 2.599 m/s.

The position and the velocity of the sandbag at a time 1.15 s after its release are 38.52 m and -6.25 m/s.

What is the equation of motion?

The equations of motion can describe the relationship between the velocity, time, acceleration, and displacement of a moving object.

The equations of motions can be represented as:

[tex]v = u + at\\S = ut +\frac{1}{2}at^2\\ v^2-u^2=2aS[/tex]

Given, the maximum height of the sandbag, h = 40 m

The velocity of the sandbag moving upward, v = 5 m/s

Calculate the time taken by the ballon:

v = u -gt

0 = 5 -9.8×t

t = 0.51 s

The position of the sandbag at 0.245 s after its release:

[tex]y = h +v_ot-\frac{1}{2}gt^2[/tex]

[tex]y = 40 +5 -0.5\times 9.8\times (0.245)^2[/tex]

y = 44.70 m

The velocity of the sandbag at a time 0.245 s after its release:

v = v₀ - gt

v = 5 - (9.8)(0.245)

v = 2.599 m/s

The position of the sandbag at a time 1.15 s after its release:

[tex]y = h +v_ot-\frac{1}{2}gt^2[/tex]

[tex]y = 40 +5 -0.5\times 9.8\times (1.15)^2[/tex]

y = 38.52 m

The velocity of the sandbag at a time 1.15 s after its release:

v = v₀ - gt

v = 5 - (9.8)(1.15)

v = -6.25 m/s

The velocity is negative so the sandbag is going down.

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What is fluid friction

Answers

Fluid friction is an opposition to the ease movement of fluids known as viscosity.

What is fluid friction?

Fluid friction describes the friction between layers of a viscous fluid that are moving relative to each other.

Typically, fluid friction is a type of friction that exist in fluids and it is known as viscosity.

Fluid viscosity can be defined as the type of friction that act on fluid. It can also be defined as the measure of the resistance of a fluid to gradual deformation by shear or tensile stress.

Thus, the fluid friction is equal to fluid viscosity and it is the type of friction that exists only in fluids.

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Check all of the following combinations of elements that could
form a covalent bond.
O and H
Na and Cl
Ca and
N and Cl
C and O

Answers

Following combinations of elements that can form a covalent bond are:

N and Cl

C and O

What are covalent bonds?

Elements with very high ionization energies cannot transfer electrons, and elements with very low electron affinities cannot accept electrons. Atoms of such elements tend to share electrons with atoms of other elements or with other atoms of the same element, and both atoms acquire an octet arrangement in their respective valence shells, achieving stability increase. Such associations by sharing electron pairs between different species or the same species are known as covalent bonds.

Covalent bonds can be achieved in two ways.

By sharing electrons between atoms of the same kind. Formation of H2, Cl2, O2, etc. By sharing electrons between atoms of different types, such as the formation of CH4, H2O, NH3 etc.

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Bumper car A (282 kg) moving +2.82 m/s makes an elastic collision with bumper car B (210 kg) moving +1.72 m/s. What is the velocity of car A after the collision?​

Answers

The velocity of Car B after the collision is 4.856 m/s.

What is elastic collision?

A collision is considered elastic if it does not result in a net decrease in the system's kinetic energy. In an elastic collision, both momentum and kinetic energy are conserved.

In an elastic collision, the kinetic energy is essentially unchanged before and after the contact and is not changed into another type of energy.

Either one dimension or two dimensions are possible. Perfectly elastic collision is not feasible in reality since there will always be some energy exchange, no matter how tiny.

m1v1 + m2v2 = m1u1 + m2u2; where

m1= mass of object 1

m2= mass of object 2

v1= initial velocity object 1

v2= initial velocity object 2

u1= final velocity object 1

u2= final velocity object 2

m1v12/2 + m2v22/2 = m1u12/2 + m2u2/2

281·2.82 - 209·1.72 = 281u1 + 209u2;

281·2.822 + 209·(- 1.72)2 = 281u12 + 209u22;

281u1 + 209u2 = 432.94 and 281u12 + 209u22 = 2852.93

u1 = 1.05407 - 0.74377u2;

u1 = (10.15278 - 0.74377u2)1/2

u2 = 4.856 m/s

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A block is launched with initial speed 2.2 m/s up a 35° frictionless ramp
How far up the ramp does it slide?

Answers

When a block is launched with initial speed 2.2 m/s up a 35° frictionless ramp then ramp slides up to 0.43m.

What is work energy theorem?

The work-energy theorem explains that net work done by the forces on an object is equal to change in its kinetic energy.

We can also say that work done on a body is equal to the net change in its energy.

Given angle = 35°

initial speed = 2.2m/s

Applying work - energy theorem,

Wgravity = KE

-m *g *sin ∅ * S =1/2* (0- 2.2²)

-9.81*sin 35° *S= 1/2 *(0- 2.2² )

S= 0.43m

Ramp slides up to 0.43m.

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You and a friend are astronauts. You push off eachother with a force of 50N. You both have a weight of 0 in space, but your mass is 110kg, and your friend’s is 80kg. Calculate the accelerations of both you and your friend

Answers

The force acting on a body in space is zero, hence the acceleration of the friends in space will be;

acceleration for the  110 kg person is 0.acceleration for the  80 kg person is 0.

What is the acceleration of a body?

The acceleration of a body is the rate of change of the velocity of the body.

The acceleration of a body, the mass of the body, and the force acting on the body are related by the formula below:

Mathematically:

Force = mass * acceleration

Hence,

acceleration = force / mass

The force acting on a body in space = 0 N

For a person having a mass of 110 kg;

acceleration = 0 / 110

Acceleration = 0

For a person having a mass of 110 kg;

acceleration = 0 / 80

Acceleration = 0

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A 50-N applied force(30 degrees to the horizontal) accelerates a 10 kg box across a horizontal sheet of ice. Ben says normal force is 50N, Don says 75N and Warren says 100N who is correct?

Answers

The normal force on the 10 Kg box is 50 N. The one with the correct statement is Ben.

Howdo I determin the normal force?

We know that normal force acting on an object is given as:

N = mg

Where angle projection is involve, it is written as:

N = mgSineθ

Where

N is the normal force m is the massg is the acceleration due to gravityθ is the angle

Now, we shall calculate the normal force, to see who is right amongst the boys. This is shown below:

Mass (m) = 10 KgAngle (θ) = 30 degreesAcceleration due to gravity (g) = 10 m/s²Normal force (N) =?

N = mgSineθ

N = 10 × 10 × Sine30

N = 100 × 0.5

N = 50 N

Thus, the normal force is 50 N. Therefore, Ben is correct!

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A person throws a ball up into the air, and the ball falls back toward Earth. At which point would the kinetic energy be the lowest?(1 point)
Responses

at a point before the ball hits the ground
at a point before the ball hits the ground

when the ball is at its highest point
when the ball is at its highest point

when the ball leaves the person’s hand
when the ball leaves the person’s hand

at a point when the ball is still rising
at a point when the ball is still rising

Answers

Answer:

highest point

Explanation:

at highest point , ball stops moving, velocity = 0

KE = 1/2 m v^2

     = 1/2 m ( 0)^2 = 0    at highest point

What is a Cuticle?

20 POINTS

Answers

Answer:

a protective and waxy or hard layer covering the epidermis of a plant, invertebrate, or shell.

Answer:

The cuticles for animals are a thin layer of clear dead skin around the nail bed on fingers and toes. As the nail grows, it naturally pushes and damages the underside of the skin around the base of the nails, called the eponychium. The space between the eponychium and the bottom of the nail is where the cuticle is located.  

The cuticle definition related to plants is a protective and waxy or hard layer covering the epidermis. The plant cuticle is an extracellular hydrophobic layer that covers the aerial epidermis.

Explanation:

Luka Doncic throws a ball from a 3-point line distance (6.75 m). The basket is at height
3.05 m. The ball leaves his hands at height 2.80 m at an angle of 45◦ and velocity 8.3 m/s.
Will he score the 3 points?

Answers

Luka Doncic will score the 3 points if he throws a ball from a 3-point line distance (6.75 m) and if the basket is at height of 3.05 m.

Resolving u into its vertical and horizontal components

ux = u cos θ

ux = 8.3 cos 45°

ux = 5.9 m / s

uy = u sin θ

uy = 8.3 sin 45°

uy = 5.9 m / s

H = 3.05 - 2.8

H = 0.25 m

T = uy + √ uy² - 2 g H / g

T = 5.9 + √ 5.9² - ( 2 * 9.8 * 0.25 ) / 9.8

T = 5.9 + √ 34.81 - 4.9 / 9.8

T = 5.9 + 5.47 / 9.8

T = 11.37 / 9.8

T = 1.16 s

R = ux T

R = 5.9 * 1.16

R = 6.8 m

Distance of three point line from the basket = 6.75 m = 6.8 m = R

Therefore, Luka Doncic will score the 3 points

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The gravitational force between two objects that are 2.1x10‐1 m apart is 3.2x10‐6 N. If the mass of one
object is 55 kg what is the mass of the other object? What will be their acceleration if they are released
from their position?

Answers

The mass of the other object is 18.11 kg and their acceleration  will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².

Given parameter:

The gravitational force between two objects : F = 3.2×10⁻⁶ N.

Distance between two objects : r =  2.1x10⁻¹ m.

The mass of one object m₁ = 55 kg.

The mass of other object m₂ =?

From universal gravitational law, we know that, force acting between two objects of mass m₁ and m₂ separated by a distance r is:

F = G m₁ m₂ / r²

Where, G = universal gravitational constant = 6.67 × 10⁻¹¹ N m⁻² kg⁻².

So, we can write,

 3.2×10⁻⁶ N = (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg) m₂/( 2.1x10⁻¹ m)

⇒ m₂ = (3.2×10⁻⁶ N ×  2.1x10⁻¹ m )/ { (6.67 × 10⁻¹¹ N m⁻² kg⁻²) (55 kg)}

= 18.11 kg.

Hence, the mass of the other object is 18.11 kg.

So, acceleration of the object of mass 55 kg is:

a₁ = F/m₁ = 3.2×10⁻⁶/55  m/s² = 5.8 × 10⁻⁸ m/s².

The acceleration of the object of mass 18.11 kg is:

a₂ = F/m₂ = 3.2×10⁻⁶/18.11 m/s² =  17.66× 10⁻⁸ m/s².

Hence, their acceleration if they are released from their position will be respectively 5.8 × 10⁻⁸ m/s² and 17.66× 10⁻⁸ m/s².

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Jay has a small marble that is very dense.
Which of the following accurately describes
the mass and volume of the marble?
small marble
A. large mass; little
volume
C. little weight; large
volume
B. little mass; large
volume
D. mass and volume
are equal

Answers

Answer:

c

xExplanation:

The gas exchange in humans occurs in the alveoli where oxygen enters the blood stream and carbon dioxide enters the lungs for
exhalation. What major organ are alveoli located in?
O the heart
O the lungs
O the bronchi
O the brain

Answers

Answer: the lungs

Explanation: During gas exchange oxygen moves from the lungs to the bloodstream. At the same time carbon dioxide passes from the blood to the lungs. This happens in the lungs between the alveoli and a network of tiny blood vessels called capillaries, which are located in the walls of the alveoli.

With an average acceleration of -0.50 m/s^2, how long will it take a cyclist to bring a bicycle with an initial speed of 13.5 m/s to a complete stop?

Answers

The time taken for the bicycle to come to a complete stop with an initial velocity of 13.5 m/s is 27 seconds.

What is time?

Time can be defined as the calculable measure of motion with respect to before and afterness.

To calculate the time it takes the cyclist to bring the bicycle to complete stop, we use the formula below.

Formula:

t = (v-u)/a.......... Equation 1

Where:

t = Timev = Final velocityu = Initial velocitya = Acceleration

From the question,

Given:

v = 0 m/s (to stop)u = 13.5 m/sa = -0.5 m/s²

Substitute these values into equation 1

t = (0-13.5)/-0.5t = -13.5/-0.5t = 27 seconds.

Hence the time taken for the bicycle to stop completely is 27 seconds.

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A block with an unknown mass is on a smooth tabletop attached to a string that is attached to a hanging block of mass of 3.6kg. If the blocks accelerate at 2.1 m/s^2 What is the mass of the block on the table? What is the Tension in the rope?

Answers

The mass of the block on the table is 2.33 kg.

The Tension in the rope is 4.9 N.

What is the mass of the block on the table?

The mass of the block on the table is calculated by applying Newton's second law of motion.

Newton's second law of motion states that the force applied on an object is directly proportional to the product of mass and acceleration of the object.

F = ma

where;

m is the mass of the blocka is the acceleration of the block

F(net) = ma

m₂g - m₁g = a(m₁ + m₂)

where;

m₂ is the mass of the hanging blocka is the acceleration of the blockm₁ is the mass of the block on table

m₂g - m₁g = m₁a + m₂a

m₂g  - m₂a = m₁a  + m₁g

m₂g  - m₂a = m₁(a + g)

3.6(9.8) - 3.6(2.1) = m₁(2.1 + 9.8)

27.72 = 11.9m₁

m₁ = 27.72 / 11.9

m₁ = 2.33 kg

The tension in the rope is calculated as follows;

T = m₁a

T = 2.33 kg x 2.1 m/s²

T = 4.9 N

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A 5 kg body rests on a horizontal plane where it is missing frictional force. A force of 10N is applied at the angle of 37 ° over the plan, for a time of 5 s. How far does the body move during this time?

Answers

Answer:

the formula of acceleration

Water is stored in an artificial lake created by a dam (the figure below). The water depth is 41 m at the dam, and a steady flow rate of 35 m3/s is maintained through hydroelectric turbines installed near the base of the dam.
a) How much electrical power can be produced?

Answers

When the water level at the dam is 41 m, 1435J of electrical power can be generated if hydroelectric turbines are placed close to the base of the dam and a constant flow rate of 35 m3/s is maintained.

What different forms of electricity are there?

There are two kinds of electricity, including: DC power is created by DC sources like generators, batteries, battery storage, etc. and is defined as the result of voltage and current. AC power is a term used to describe a charge flow that periodically changes its direction.

What is referred to as electricity?

The pace at which work is completed or energy is changed inside an electrical circuit is known as the electric power definition. It is a way to quantify how much energy is consumed over a certain period of time. Electrical power is the term used in physics to describe the rate at which an electrical circuit transfers electrical energy per unit of time.

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