Answer:
v = 5.7554 m/s
Explanation:
First of all we need to know if the angle of the vine is measured in the horizontal or vertical.
To do this easier, let's assume the angle is measured with the horizontal. In this case, the innitial height of the monkey will be:
h₀ = h sinα
h₀ = 5.32 sin43° = 3.6282 m
As the monkey is dropping from the innitial point which is the suspension point, is also dropping from 5.32. Then the actual height of the monkey will be:
Δh = 5.32 - 3.63 = 1.69 m
In order to calculate the speed of the monkey we need to understand that the monkey has a potential energy. This energy, because of the gravity, is converted in kinetic energy, and the value will be the same. Therefore we can say that:
Ep = Ek
From here, we can calculate the speed of the monkey.
Ep = mgΔH
Ek = 1/2 mv²
The potential energy is:
Ep = 16.9 * 9.8 * 1.69 = 279.9
Now with the kinetic energy:
1/2 * (16.9) * v² = 279.9
v² = (279.9) * 2 / 16.9
v² = 33.12
v = √33.12
v = 5.7554 m/sHope this helps
A satellite is in orbit 3.117106 m from the center of Earth. The mass of Earth is 5.9821024 kg. Calculate the orbital
period of the satellite.
Answer:
T = 1733.16 s = 28.88 min
Explanation:
The orbital velocity of a satellite about Earth is given as follows:
[tex]v = \sqrt{\frac{GM}{R}}[/tex]
where,
v = orbital speed = ?
G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²
M = Mass of Earth = 5.982 x 10²⁴ kg
R = Orbit Radius = 3.117 x 10⁶ m
Therefore,
[tex]v = \sqrt{\frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(5.982\ x\ 10^{24}\ kg)}{(3.117\ x\ 10^{6}\ m)}}\\\\v = 11.3\ x\ 10^{3}\ m/s[/tex]
but the velocity is given as:
[tex]v = \frac{distance}{time}[/tex]
for distance = circumference = 2πR
time = time period = T = ?
Therefore,
[tex]11.3\ x\ 10^{3}\ m/s = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{T}\\\\T = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{11.3\ x\ 10^{3}\ m/s}\\\\[/tex]
T = 1733.16 s = 28.88 min
Water is entering the prism at a rate of A m^3/hr. The prism is empty at time 0. Express the depth d of the water in meters in terms of A, the length of time t the water has been entering the trough, and the length L of the prism.
This question is incomplete, the complete question is;
The picture shows a triangular prism. The end of prism are equilateral triangles with x meters. the other dimension of the prism is L meters
a) Find the volume V in terms of x and L
b) Water is entering the prism at a rate of A m³/hr. The prism is empty at time 0. Express the depth d of the water in meters in terms of A, the length of time t the water has been entering the trough, and the length L of the prism.
Answer:
a) the volume V in terms of x and L is ((√3/4)x²L) m³
b) required expression is (2/(3)^(1/u))√(At/L)
Explanation:
Given that;
form the question and image below;
triangular prism ends are equilateral triangle
side length = x meter
Dimension of the prism = L meter
Area of the equilateral triangle = √3/4 (side)² = √3/4 (x)² meter
Volume of the triangular prism = Area × height
= √3/4 (x)² × L
V = ((√3/4)x²L) m³
Therefore, the volume V in terms of x and L is ((√3/4)x²L) m³
b)
Rate of water entering = A m³/hr
Depth of water tank = d meter
Time = t
Length of prism = L
now Rate of water entering is A m³/hr
dv/d = A [ V = ((√3/4)x²L) m³ ]
and
dv/dt = √3/4 [2x dx/dt ] L { L is constant }
so
A = √3/4 [2x dx/dt ] L
∫A dt = √3/2 [ Lx dx ] { Integrate both sides}
At = √3/2 × Lx × x²/2
x² = uAt / √3L { we find square root of both sides}
x = √( uAt / √3L )
x = (2/(3)^(1/u))√(At/L)
Therefore; required expression is (2/(3)^(1/u))√(At/L)
You kick a soccer ball with a speed of 12 m/s at an angle of 21. How long does it take the ball to reach the top of its trajectory?
Answer:
Time, t = 0.439 seconds
Explanation:
Given the following data;
Angle, x = 21°
Initial velocity, u = usinx = 12Sin21° = 4.3004m/s
We know that acceleration due to gravity is equal to 9.8m/s
Final velocity = 0m/s since it reached its highest trajectory.
To find the time, we would use the first equation of motion;
V = U + gt
0 = 4.3004 + (-9.8)t
0 = 4.3004 - 9.8t
9.8t = 4.3004
t = 4.3004/9.8
t = 0.439 seconds
Therefore, it will take the ball 0.439 seconds to reach the top of its trajectory.
Answer: 0.44 s
Explanation:
that’s what I got correct on my test in physics ;)
An RLC series circuit has an applied voltage of 277 volts. The current through the resistor is 3.5 A. What is the apparent power of the circuit
Answer:
the apparent power of the circuit is 969.5 VA.
Explanation:
Given;
Applied voltage, E = 277 V
current flowing in the circuit, I = 3.5 A
Apparent occurs when the applied voltage and current are out of phase because of reactance. This apparent power of the circuit is calculated as;
[tex]P = EI\\\\P= 277 \ \times \ 3.5 \\\\P = 969.5 \ VA[/tex]
Therefore, the apparent power of the circuit is 969.5 VA.
what color is my socks? :0
A color.......................................................................yeah the color of your socks is a color :}
A 45-year-old man is meeting his doctor for his annual physical. He suffers from Type 2 diabetes and has a family history of coronary disease. Recently his job has become more stressful and he has been eating cookies and drinking soda to cope. What state of change is this man in?
Answer:
The man is on the verge of having a heart attack or a stroke.
Explanation:
If he has a family history of coronary (heart) disease, it means it could normally affect. Normally here means without anything aggravating it. It's already in his lineage so he could have it.
Now, he's past middle age - he's 45. He's past the growing stages of life. His organs are fully developed herefore.
Now also, he suffers from Type 2 diabetes. Although this is sometimes milder than Type 1 diabetes, it increases the risk of having a heart disease or a stroke!
Soda, especially sweetened one, is not to be taken too often because it can cause Diabetes Mellitus. For a diabetes patient, this should be a "no-go-area". Taking this constantly (everyday at work) will now put this 45-year-old man in harm's way.
He is no more at risk of having complications but already on the path to a heart disease or a stroke.
If there is an outlier on your graph, you should ignore it.
O True
O False
Answer:
false
Explanation:
How to detect beta rays
Answer:
For the detection of beta particles, organic scintillators can be used. Pure organic crystals include crystals of anthracene, stilbene, and naphthalene. The decay time of this type of phosphor is approximately 10 nanoseconds. This type of crystal is frequently used in the detection of beta particles.
- Hope this helps!
An inductor, battery, resistance, and ammeter and switch are connected in series. If the switch, initially open, is now closed, what is the current's final value
The question is incomplete. Here is the complete question.
An inductor, battery, resistance and ammeter and switch are connected in series. If the switch, initially open, is now closed, what is the current's final value?
a. zero
b. Battery voltage divided by inductance
c. battery voltage times inductance
d. battery voltage divided by resistance
Answer: d. battery voltage divided by resistance
Explanation: Resistance, voltage and current are related by Ohm's Law, which is explained as the current that passes through a conductor is directly proportional to the applied voltage. The constant of proportionality between them is Resistance.
Ohm's Law is represented by [tex]V=R.I[/tex]
Inductor is a component that stores magnetic energy when electricity is applied to it.
Ammeter is an object constructed to measure electric current of a circuit and it is always connected in serie.
So, in the circuit, when the switch is closed, the "only way" for current to pass through is because of Ohm's Law, which means its magnitude will be:
[tex]I=\frac{V}{R}[/tex]
Then, the correct alternative is d. voltage divided by resistance.
When light bulbs are connected in parallel and you unscrew one light bulb, the other light bulbs will
a. All go out
b. All get dimmer
c. All get brighter
d. All stay on
a. All go out
b. All get dimmer
c. All get brighter
d. All stay on
Is Obesity primarily due to Genetics?
A baseball is hit high into the upper bleachers of left field. Over its entire flight the work done by gravity and the work done by air resistance respectively are:
A. positive; positive
B. positive; negative
C. negative; positive
D. negative; negative
E. unknown since vital information is lacking
Answer:
B. positive; negative.
Explanation:
From the viewpoint of Principle of Energy Conservation and Work-Energy Theorem, we notice that gravity represents a conservative force, associated with gravitational potential energy, whereas air resistance is a non-conservative force, associated with dissipated work. Therefore, the work done by gravity is positive and work done by air resistance is negative. Therefore, the correct answer is B.
One of the strongest emission lines observed from distant galaxies comes from hydrogen and has a wavelength of 122 nm (in the ultraviolet region). (a) How fast must a galaxy be moving away from us in order for that line to be observed in the visible region at 366 nm
Answer:
[tex]v=2.4*10^8m/s[/tex]
Explanation:
From the question we are told that
Wavelength of emission [tex]\lambda=122nm[/tex]
Observation distance [tex]d=366nm[/tex]
Generally the s equation is given as
[tex]f'=f\sqrt{\frac{(1-\frac{v}{c} )}{1+\frac{v}{c} }[/tex]
where
F is inversely proportional to T
[tex]d=\lambda\sqrt{\frac{(1-\frac{v}{c} )}{1+\frac{v}{c} }[/tex]
[tex]\frac{v}{c} =\frac{(1-\frac{\lambda}{d})}{(1+\frac{\lambda}{d}}[/tex]
[tex]\frac{v}{c}=\frac{1-(\frac{122}{366} )^2}{1+(\frac{122}{366})^2}[/tex]
[tex]\frac{v}{c}=\frac{0.8888888889}{1.11111111}[/tex]
[tex]\frac{v}{c}=0.80[/tex]
[tex]v=0.80*3*10^6[/tex]
[tex]v=2.4*10^8m/s[/tex]
A student throws a ball upward with a velocity of 35 m/s. What is the acceleration of the ball as it rises to the top of its arc?
Answer:
The acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
Explanation:
Let suppose that maximum height of the arc is so small in comparison with the radius of the Earth.
Since the ball is launched upwards, then the ball experiments a free-fall motion, that is, an uniform accelerated motion in which the element is accelerated by gravity. Then, the acceleration experimented by the motion remains constant at every instant and position.
Besides, the gravitational acceleration in the Earth and, in consequence, the acceleration of the ball as it rises to the top of its arc equals 9.807 meters per square second.
what types of bodies sink in water
Answer:
Rocks, coins, honey, vegetable oil, diamonds, etc.
Explanation:
Object that are more dense than water.
The charge per unit length on a long, straight filament is 290.0 mC/m. Find the electric field a) 10.0 cm andb) 100 cm from the filament, where distances are measured perpendicular to the length of the filament.
Answer:
Explanation:
given linear charge density λ = 290 x 10⁻³ C / m
Expression for electric field at distance d is given as follow .
E = λ / 2πε₀r
1 / 4πε₀ = 9 x 10⁹
1 / 2πε₀ = 18 x 10⁹
E = λ / 2πε₀r = 290 x 10⁻³ x 18 x 10⁹ / r
= 5220 x 10⁶ / r
For r = 10 x 10⁻² m = .1 m
E = 5220 x 10⁶ / .1
= 5.22 x 10¹⁰ N/m
For r = 100 x 10⁻² m = 1 m
E = 5220 x 10⁶ / 1
= 5.22 x 10⁹ N/m .
A 1210 kg car is driving NE
(at 45.0°) at 15.2 m/s when it is
struck by a moving 1540 kg car.
Afterward, they stick together and
move directly east (at 0°) at 23.3
m/s. What was the x-component
of the second car's initial velocity?
Please help
Answer:
[tex]V_2_X=33.16m/s[/tex]
Explanation:
From the question we are told that
Mass of car [tex]M_1=1210kg \\Angle1=\theta _1 45\textdegree NE[/tex]
Velocity of car [tex]v_1= 15m/s[/tex]
Mass of Truck [tex]M_2= 1540kg \\Angle 2=\theta_2 0\textdegree E[/tex]
Final velocity [tex]v_2= 23.3m/s[/tex]
Generally the the equation of the law of conservation of momentum is mathematically given by
Given the x direction
[tex]m_1v_1cos\theta+m_2v_2=(m_1+m_2)v[/tex]
[tex]1210*15.2cos45+1540*V_2=(1210+1540)*23.3[/tex]
[tex]V_2=\frac{(1210+1540)*23.3}{210*15.2cos45+1540}[/tex]
[tex]V_2=33.16m/s[/tex]
The x-component of the second car's initial velocity is
[tex]V_2_X=33.16m/s[/tex]
what is work??
ASAP who pls
A car has a weight of 10,000 N. What is the mass of the car on Earth (g = 10
N/kg)?
A. 1000 kg
B.1000 N
C. 10,000 kg
D. 10,000N
Given :
Weight of car is, W = 10000 N.
Acceleration due to gravity, g = 10 N/kg.
To Find :
The mass of car on Earth.
Solution :
We know, mass of an object is given by :
[tex]m = \dfrac{W}{g}\\\\m = \dfrac{10000}{10}\ kg\\\\m = 1000\ kg[/tex]
Therefore, mass of the car on Earth is 1000 kg.
A 12 N force and a 21 N force are acting from a single point in opposite directions. What additional force must be
added to produce equilibrium?
Answer:
We need to add 9 N in the direction of F(1)
Explanation:
We know that in equilibrium the total force is equal to zero, so we have:
[tex]F_{total}=F_{1}+F_{2}+F_{3}=0[/tex]
F(1) is 12 N
F(2) is 21 N in the opposite direction
F(3) is the additional force.
Then, using these values into the total force equation we have:
[tex]12-21+F_{3}=0[/tex]
[tex]-9+F_{3}=0[/tex]
[tex]F_{3}=9\: N[/tex]
Therefore, we need to add 9 N in the direction of F(1)
I hope it helps you!
Jamie dropped a water bottle from the top of an office building. The water bottle impacted the ground after falling for 5 seconds. Calculate the velocity of the water bottle at impact with the street below.
Answer:
The speed of the water bottle at impact with the street is 49 m/s
Explanation:
Free Fall Motion
A free-falling object falls under the sole influence of gravity. Any object that is being acted upon only by the force of gravity is said to be in a state of free fall. Free-falling objects do not experience air resistance.
If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].
The final velocity of a free-falling object after a time t is given by:
vf=g.t
The water bottle dropped by Jamie takes t=5 seconds to impact the ground, thus its speed at that moment is:
vf= 9.8*5
vf = 49 m/s
The speed of the water bottle at impact with the street is 49 m/s
The speed of sound in steel is 5000 m/s. What is the wavelength of a sound wave of frequency 660 Hz in steel?
Answer:7.58 m
Explanation:
The required wavelength of a sound wave of frequency 660 Hz in steel is approximately 7.58 meters.
What is wavelength?Wavelength is a fundamental property of waves, including electromagnetic waves like light and radio waves, as well as other types of waves, such as sound waves or water waves.
Here,
The wavelength (λ) of a sound wave is given by the formula,
λ = v/f
where v is the speed of sound in the medium and f is the frequency of the wave.
In this case, the speed of sound in steel is v = 5000 m/s, and the frequency of the sound wave is f = 660 Hz. Substituting these values into the formula, we get:
λ = 5000 m/s / 660 Hz
λ = 7.58 meters (rounded to two decimal places)
Therefore, the wavelength of a sound wave of frequency 660 Hz in steel is approximately 7.58 meters.
Learn more about wavelength here:
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The space station in the drawing is rotating to create artificial gravity. The speed of the inner ring is one half that of the outer ring. As an astronaut walks from the inner to the outer ring, what happens to her apparent weight
Answer:
It will double.
Explanation:
Apparent weight is the weight of a physical body affected by a force of gravity different of that of the athmosphere. Thus, the lower the gravity, that is, the lower the attraction of one body to another, the lower the apparent weight of the object on which the gravitational force is exerted; while the opposite occurs if the gravitational force is greater. In other words, the apparent weight of an object is determined by the gravitational force exerted on it: the greater the force, the greater the weight. Therefore, as the outer ring has twice the force of gravity than the inner ring, the apparent weight of the astronaut will double as well.
Lou’s latest invention, aimed at urban dog owners, is the X-R-Leash. It is made of a rubber-like material that exerts a force Fx = (−5.7 N/m) x − (78 N/m2 ) x 2 when it is stretched a distance x. The ad claims, "You’ll never go back to your old dog leash after you’ve had the thrill of an X-R-Leash experience. And you’ll see a new look of respect in the eyes of your proud pooch." Find the work done on a dog by the leash if the person remains stationary, and the dog bounds off, stretching the X-R-Leash from x = 0 m to x = 22 m. Answer in units of kJ.
Answer:
W = 29.06 KJ
Explanation:
The work done while stretching the leash can be calculated by the following formula:
[tex]W = \int\limits^b_a {F_{x}} \, dx \\[/tex]
whee,
W = Work Done = ?
Fₓ = Forcing Function = (-5.7 N/m)x - (78 N/m²)x²
a = starting point of x = 0 m
b = end point of x = 22 m
Therefore,
[tex]W = \int\limits^{22\ m}_{0\ m} {(-(5.7\ N/m)x - (7.8\ N/m^{2})x^{2}}) \, dx \\Integrating\ we\ get:\\W = -\frac{(5.7\ N/m)x^{2}}{2} - \frac{(7.8\ N/m^{2})x^{3}}{3}\\Applying\ limits:\\W = -\frac{(5.7\ N/m)(22\ m)^{2}}{2} - \frac{(7.8\ N/m^{2})(22\ m)^{3}}{3} - 0\\W = - 1379.4\ J - 27684.8\ J\\W = 29064.2\ J[/tex]
W = 29.06 KJ
Carlota does 2000 J of work on a machine. The machine does 500 J of work. What is the efficiency of the
machine?
4%
O 25%
O 75%
O 400%
Answer:
25%
Explanation:
500 J out of 2000 J is 25%
PLEASE HELP!! THIS IS DUE RN!!
Answer:
know on car wright now
Explanation:
A ballet dancer spins with 2.4 rev/s with her arms outstretched,when the moment of inertia about axis of rotation is 1 .With her arms folded,the moment of inertia about the same axis becomes 0.61 . calculate the new rate of spin.
Correct question is;
A ballet dancer spins with 2.4 rev/s with her arms outstretched,when the moment of inertia about axis of rotation is I. With her arms folded,the moment of inertia about the same axis becomes 0.6I about the same axis. Calculate the new rate of spin.
Answer:
4 rev/s
Explanation:
We are given;
Initial Angular velocity; ω_i = 2.4 rev/s
Initial moment of inertia; I_i = I
Final moment of inertia; I_f = 0.6I
From conservation of angular momentum, we have;
I_i × ω_i = I_f × ω_f
Where ω_f is the new rate of spin.
Thus, let's make it the subject to get;
ω_f = (I_i × ω_i/I_f)
Plugging in relevant values, we have;
ω_f = (I × 2.4/0.6I)
I will cancel out to give;
ω_f = 2.4/0.6
ω_f = 4 rev/s
Suppose you have a total charge qtot that you can split in any manner. Once split, the separation distance is fixed. How do you split the charge to achieve the greatest force
Answer:
Answer is explained in the explanation section below.
Explanation:
Solution:
We know from the Coulomb's Law that, Coulomb's force is directly proportional to the product of two charges q1 and q2 and inversely proportional to the square of the radius between them.
So,
F = [tex]\frac{Kq1q2}{r^{2} }[/tex]
Now, we are asked to get the greatest force. So, in order to do that, product of the charges must be greatest because the force and product of charges are directly proportional.
Let's suppose, q1 = q
So,
if q1 = q
then
q2 = Q-q
Product of Charges = q1 x q2
Now, it is:
Product of Charges = q x (Q-q)
So,
Product of Charges = qQ - [tex]q^{2}[/tex]
And the expression qQ - [tex]q^{2}[/tex] is clearly a quadratic expression. And clearly its roots are 0 and Q.
So, the highest value of the quadratic equation will be surely at mid-point between the two roots 0 and Q.
So, the midpoint is:
q = [tex]\frac{Q + 0}{2}[/tex]
q = Q/2 and it is the highest value of each charge in order to get the greatest force.
Two cars collide and then stick together in an accident.
Car A has a mass of 1000. kg and is moving 5.00 m/s east, and
car B has a mass of 2000. kg and is moving 2.00 m/s west.
What is the speed of the cars after the collision?
b. 1.53m/s
c. 2.43m/s
a. 0.33m/s
d. 3.93m/s
What’s the answer
Answer:
Option A. 0.33 m/s
Explanation:
From the question given above, the following data were obtained:
Mass of A (mₐ) = 1000 kg
Velocity of A (uₐ) = 5 m/s
Mass of B (m₆) = 2000 kg
Velocity of B (u₆) = 2 m/s
Velocity (v) after collision =?
mₐuₐ – m₆u₆ = v (mₐ + m₆)
(1000 × 5) – (2000 × 2) = v (1000 + 2000)
5000 – 4000 = 3000v
1000 = 3000v
Divide both side by 3000
v = 1000 / 3000
v = 0.33 m/s
Thus, the speed of the cars after collision is 0.33 m/s
The speed of the cars after the collision is 0.33 m/s.
The right option is a. 0.33 m/s
To calculate the speed of the cars after the collision, we use the formula below.
Formula:
mu+m'u' = V(m+m')............... Equation 1Where:
m = mass of car Am' = mass of car Bu = initial velocity of car Au' = initial velocity of car BV = Speed of the cars after the collision.make V the subject of the equation
V = (mu+m'u')/(m+m').............. Equation 2From the question,
Given:
m = 1000 kgm' = 2000 kgu = 5 m/s eastu' = -2 m/s westSubstitute these values into equation 2
V = [(1000×5)+(2000×(-2))]/(1000+2000)V = (5000-4000)/(3000)V = 1000/3000V = 0.33 m/sHence, The speed of the cars after the collision is 0.33 m/s.
The right option is a. 0.33 m/s
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PLEASE HELPPPPPP!!!!
Answer:
b
Explanation:
i just did that question
