A 2018 poll of 3612 randomly selected users of a social media site found that 1704 get most of their news about world events on the site. Research done in 2013 found that only 46% of all the site users reported getting their news about world events on this site.
a. Does this sample give evidence that the proportion of site users who get their world news on this site has changed since 2013? Carry out a hypothesis test and use a 0.05 significance level.
b. After conducting the hypothesis test, a further question one might ask is what proportion of all of the site users get most of their news about world events on the site in 2018. Use the sample data to construct a 95% confidence interval for the population proportion. How does your confidence interval support your hypothesis test conclusion?

Answers

Answer 1
a. To test whether the proportion of site users who get their world news on this site has changed since 2013, we can perform a hypothesis test. Let p be the true population proportion of site users who get their world news on this site in 2018. Then the null hypothesis is H0: p = 0.46, and the alternative hypothesis is Ha: p ≠ 0.46. We will use a two-tailed z-test with a 0.05 significance level.

Using the sample data, the sample proportion of site users who get their world news on this site is 1704/3612 = 0.471. The standard error of the sample proportion is sqrt(0.46*0.54/3612) = 0.013. The z-score for the sample proportion is (0.471 - 0.46) / 0.013 = 0.846. The corresponding p-value for this test is P(|Z| > 0.846) = 0.397 > 0.05.

Since the p-value is greater than 0.05, we fail to reject the null hypothesis and conclude that there is not enough evidence to suggest that the proportion of site users who get their world news on this site has changed since 2013.

b. To construct a 95% confidence interval for the population proportion of site users who get their world news on this site in 2018, we can use the sample proportion and the margin of error formula:

Margin of error = z*sqrt(p*(1-p)/n)

where z = 1.96 for a 95% confidence level, p = 0.471, and n = 3612.

Plugging in these values, we get:

Margin of error = 1.96*sqrt(0.471*(1-0.471)/3612) = 0.014

Therefore, the 95% confidence interval for the population proportion is:

0.471 ± 0.014, or (0.457, 0.485)

Since the null hypothesis in part (a) was that the proportion of site users who get their world news on this site is 0.46, and the confidence interval does not contain 0.46, this supports the conclusion of the hypothesis test that there is not enough evidence to suggest that the proportion has changed since 2013.

(If this doesn’t seem right to you make sure you comment!)
Answer 2
a. To test whether the proportion of site users who get their world news on this site has changed since 2013, we can use a hypothesis test with the following hypotheses:

Null hypothesis: The proportion of site users who get their world news on this site is equal to 0.46.
Alternative hypothesis: The proportion of site users who get their world news on this site is greater than 0.46.

We will use a significance level of 0.05.

The sample proportion is 1704/3612 = 0.471. We can assume that the sample is large enough to use a normal distribution. The test statistic is:

z = (0.471 - 0.46) / sqrt(0.46 * 0.54 / 3612) = 3.87

The p-value for this test is P(Z > 3.87) = 0.00005, which is much smaller than the significance level of 0.05. Therefore, we reject the null hypothesis and conclude that the proportion of site users who get their world news on this site has increased since 2013.

b. To construct a 95% confidence interval for the population proportion, we can use the sample proportion and the margin of error formula:

Margin of error = z* * sqrt(p*(1-p)/n)

where z* is the critical value for a 95% confidence level, p is the sample proportion, and n is the sample size.

The critical value for a 95% confidence level is 1.96. Substituting the values, we get:

Margin of error = 1.96 * sqrt(0.471 * 0.529 / 3612) = 0.018

The 95% confidence interval is therefore:

0.471 ± 0.018

or

(0.453, 0.489)

This interval does not include the null hypothesis value of 0.46, which supports our conclusion from the hypothesis test that the proportion of site users who get their world news on this site has increased since 2013.

Related Questions

Posttest
Chiku has a poor track record of completing work assignments. She has been placed on a project with other
co-workers. Her team members will likely view Chiku as:
A) Combative
B) Unreliable
C) Trustworthy
D) Confident

Answers

Answer:

B) Unreliable

Explanation:

Based on the given information, Chiku has a poor track record of completing work assignments. Therefore, her team members are likely to view her as "unreliable".

How does lack of community participation contribute to poor service delivery

Answers

Answer:

In summary, lack of community participation can contribute to poor service delivery by limiting feedback, inadequate needs assessment, limited accountability, and limited resources. Therefore, it is important to involve communities in the planning, implementation, and monitoring of public services to improve service delivery.

Explanation:

Lack of Feedback: If the community is not involved in the planning, implementation, and monitoring of public services, it becomes difficult for authorities to obtain feedback on the effectiveness of the services provided. Without feedback, it is difficult to identify areas that need improvement, and this can result in poor service delivery.

Inadequate Needs Assessment: When community members are not involved in the needs assessment process, it becomes difficult to identify the specific needs of the community. This can result in services that are not tailored to the specific needs of the community, leading to poor service delivery.

Limited Accountability: Community participation provides an avenue for holding service providers accountable for their actions. When community members are not involved in monitoring the delivery of services, it becomes difficult to hold service providers accountable for their actions. This can result in poor service delivery, as service providers may not be held accountable for their shortcomings.

Limited Resources: Community participation can also lead to the identification of additional resources that can be used to support the delivery of public services. When community members are not involved, it becomes difficult to identify additional resources that can be used to support service delivery. This can result in poor service delivery due to limited resources.

who made the state test in 1837-48

Answers

Horace Mann made the state test in 1837-48

Activity 1: Let's Value Directions: Complete the matrix by providing the advantages and disadvantages of the following concepts, then give a brief explanation. Deepen SUBJECT
1. Cloud Computing
2. Mobile Applications
3. Communication Technology
4. World Wide Web
5. E-commerce

write the (POSITIVE IMPACT)( NEGATIVE IMPACT ) (EXPLANATION)​

Answers

Cloud computing is a technology that allows users to access computing resources such as storage, processing power, and applications over the Internet.

How to explain the information

A mobile application or mobile app is a software application designed to run on a mobile device such as a smartphone or tablet.

Tools and systems used to facilitate communication between individuals or groups are called communication technologies.

The World Wide Web, also known as the Web, is an interconnected network of publications and resources accessible via the Internet.  

E-commerce, which stands for electronic commerce, is the purchasing and selling of goods and services on the internet.

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Three ways a community would benefit from participating in campaigns

Answers

The ways in which communities can benefit from participatin in campaings are:

Participating in any campaign addressing a human rights issue has three benefits: taking the initiative, increasing social unity, and improving government standards.

What are campaigns ?

A campaign is a specialized action with the goal of producing outcomes in the short, medium, or long term.

As a result, they are an excellent tool to assess a company's efforts and ensure that the return is beneficial.

There are several sorts of campaigns, each with a distinct goal and target audience.

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Peter earned 40% more money than Albert. Albert earned 20% less than Michael. Petre earned more than michael by
Select one:
a. 25%
b. 20%
c. 12%
d. 10%

Answers

Let's assume Michael earned $100.

Albert earned 20% less than Michael, which is $80.

Peter earned 40% more than Albert, which is $80 + 0.4($80) = $112.

So, Peter earned $112 - $100 = $12 more than Michael.

Therefore, the percentage that Peter earned more than Michael is (12/100) x 100% = 12%.

The answer is c. 12%.

Before the radio and telephone were invented, some groups used patterns of drumbeats to send information to one another.


Which statement ,begin emphasis,best,end emphasis, explains how the patterns of drumbeats transferred information from one group to another?

Answer options with 4 options

A.

The different shapes of the drums produced different sounds.

B.

The pattern of drumbeats represented different words or phrases.

C.

The groups used different drums during different times of the year.

D.

The drumbeats were so loud that they could be heard from great distances.

Answers

The statement that best explains how patterns of drumbeats transferred information from one group to another is option B: "The pattern of drumbeats represented different words or phrases."

Groups that used drumbeats to communicate developed complex systems of rhythms and patterns that could convey specific meanings, much like a language. Different rhythms and patterns were associated with different words, phrases, or messages.

For example, a certain pattern of beats might represent a warning of danger, while another pattern might indicate the arrival of an important visitor. By varying the rhythm and duration of the beats, and by using different combinations of beats, the drummers could convey a wide range of meanings and messages.

Drum communication was particularly useful for groups that lived in areas with rugged terrain or dense forests, where it was difficult to communicate over long distances using spoken language.

The sound of the drums could carry for miles and was easily distinguishable from other sounds in the environment. In addition, because the drummers could use a code that was known only to their group, they could communicate privately without fear of interception or misinterpretation by outsiders.

In conclusion, the patterns of drumbeats used by certain groups to send information to one another represented different words or phrases. These rhythms and patterns allowed the drummers to convey a wide range of messages over long distances and in difficult terrain.

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5
Select the correct answer from each drop-down menu.
AB
CD is perpendicular to
and passes through point C(5, 12).
If the coordinates of A and B are (-10, -3) and (7, 14), respectively, the x-intercept of CD
is
Reset
Next
The point
lies on
CD

Answers

CD is perpendicular to AB and passes through point C (5,12). If the coordinates of A and B are (-10, -3) and (7, 14), respectively, the x- intercept of CD is: (17, 0)

The point: (-2, 19) lies on CD.

How to explain the information

Since CD is perpendicular to AB and passes through C, we know that CD is parallel to the vector AB and passes through point C. The vector AB is:

AB = <7 - (-10), 14 - (-3)> = <17, 17>

A vector perpendicular to AB is:

n = <-17, 17>

The x- intercept of CD is: (17, 0) and the point: (-2, 19) lies on CD.

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CD is perpendicular to AB and passes through point C (5,12).

If the coordinates of A and B are (-10, -3) and (7, 14), respectively, the x- intercept of CD is:

(12, 0)

(15, 0)

(17, 0)

or (19,0).

The point:

(-5, 24)

(-2, 19)

(7, -10)

or (8, 11)

lies on CD.

2018 poll of 2232 randomly selected U.S. adults found that 40.86% planned to watch at least a "fair amount" of a particular sporting event in 2018.
In 2014, 47% of U.S, adults reported planning to watch at least a "fair amount."
a. Does this sample give evidence that the proportion of U.S. adults who planned to watch the 2018 sporting event was less than the proportion who planned to do so in 2014? Use a 0.05 significance level.
b. After conducting the hypothesis test, a further question one might ask is what proportion of all U.S. adults planned to watch at least a "fair amount" of the sporting event in 2018. Use the sample data to construct a 90% confidence interval for the population proportion. How does your confidence interval support your hypothesis test conclusion?

Answers

a. Let p

1

 be the proportion of U.S. adults who planned to watch at least a "fair amount" of the 2018 sporting event and p

2

 be the proportion of U.S. adults who planned to do so in 2014. We want to test the following hypotheses:

H

0

:p

1

=p

2

H

a

:p

1

<p

2

We will use a significance level of α=0.05.

Our sample size is n=2232 and our sample proportion is  

p

^

=0.4086. The standard error of the sample proportion is:

SE(

p

^

)=

n

p(1−p)

=

2232

0.4086(1−0.4086)

=0.0097

Our test statistic is:

z=

SE(

p

^

)

p

^

−p

0

=

0.0097

0.4086−0.47

=−6.38

Our p-value is P(z<−6.38)=0.000000000002.

Since our p-value is less than our significance level of α=0.05, we reject the null hypothesis. There is evidence to suggest that the proportion of U.S. adults who planned to watch the 2018 sporting event was less than the proportion who planned to do so in 2014.

b. A 90% confidence interval for the population proportion is:

CI=(

p

^

−z

1−α/2

⋅SE(

p

^

),

p

^

+z

1−α/2

⋅SE(

p

^

))

CI=(0.4086−1.645⋅0.0097,0.4086+1.645⋅0.0097)

CI=(0.4002,0.4170)

We are 90% confident that the true proportion of U.S. adults who planned to watch at least a "fair amount" of the 2018 sporting event is between 0.4002 and 0.4170.

Our confidence interval does not include 0.47, the proportion of U.S. adults who planned to watch at least a "fair amount" of the sporting event in 2014. This supports our hypothesis test conclusion that the proportion of U.S. adults who planned to watch the 2018 sporting event was less than the proportion who planned to do so in 2014.

Is it true that The earliest evidence of accounting is the double-entry system used in the thirteenth century?

Answers

Answer:

No

Explanation:

No, it is not true. While the double-entry system is an important and widely used method in accounting, there is evidence of accounting practices dating back to ancient civilizations such as the Babylonians and Egyptians. The ancient Greeks and Romans also had various forms of accounting and record-keeping. However, the double-entry system as we know it today was first described by Italian mathematician Luca Pacioli in his book "Summa de Arithmetica, Geometria, Proportioni et Proportionalità" in the 15th century.

can i get the answer

Answers

Sure!what do you need the answe for

When a plant is not strong enough to support its own weight, what is most likely the problem? O A. The plant is producing too many polysaccharides. B. The plant is not producing enough cellulose. C. The plant needs more monosaccharides to add strength. D. The plant does not have enough starch. ✔ Correct




(D) The plant is not producing enough cellulose​

Answers

Yes, you are correct. When a plant is not strong enough to support its own weight, the most likely problem is that the plant is not producing enough cellulose. Cellulose is a complex carbohydrate that provides structural support to plant cell walls. It forms strong fibers that help plants maintain their shape and rigidity. If a plant does not produce enough cellulose, its cell walls may be weak, leading to a lack of structural support and an inability to withstand the weight of the plant.[tex][/tex]

4.The first orange I drew from my bag is red. All oranges in my bag are red. Therefore, the second orange I drawn from my bag will be red, too.

Write the kind of argument?

Answers

Answer:

The first orange I drew from my bag is red. All oranges in my bag are red. Therefore, the second orange I drawn from my bag will be red, too. And so will the third but how many oranges do i have I DON'T KNOW

Explanation:

Question:how old am i

The newly elected president need to decide the remaining eight spots available for cabinet here she is appointing there are 12 eligible candidate for this position where rink matters how many different ways can the member of the cabinet be appointed

Answers

Answer: There are 495 different ways the members of the cabinet can be appointed.

Explanation:

nCr+n! / (r! * (n-r)!)

Where n is the total number of items, and r is the number of items to choose.

In this case, there are 12 eligible candidates for 8 spots. So, we need to find the humber of ways to choose 8 candidates from 12, which is:

12C8 = 12!/ (8! * (12-8)!)+495

How do ocean currents effect the air temperature for Luderitz and Florianopolis?

Answers

Answer:

Ocean currents can have a significant effect on air temperature in coastal areas like Luderitz and Florianopolis.

Luderitz, located on the Atlantic coast of Namibia, is influenced by the cold Benguela Current which flows northward along the coast from Antarctica. This current cools the air above it, resulting in lower air temperatures in Luderitz compared to other locations at a similar latitude.

Florianopolis, on the other hand, is located on the Atlantic coast of Brazil and is influenced by the warm Brazil Current, which flows southward along the coast from the equator. This current warms the air above it, resulting in higher air temperatures in Florianopolis compared to other locations at a similar latitude.

Therefore, in both cases, the ocean currents play a significant role in determining the air temperature of the coastal areas.

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