The value of delta H° for aniline = 6415 Kj/mol
calculation
Step 1: find heat
Q (heat) = C (specific heat capacity) x ΔT (change in temperature)
C= 4.25 kj/c°
ΔT = 69.8-29.5 = 40.3 c°
Q= 4.25 kj/c x 40.3 c = 171.28 kj
Step 2: find the moles of aniline
moles = mass/molar mass
= 2.49 g/ 93.13 g/mol =0.0267 moles
Step 3: find delta H
171.28 kj/0.0267 mol = 6415 kj/mol
since the reaction is exothermic delta H = 6415 Kj/mol
Answer:
-6.41x10^3
Explanation:
2.49 is 3 significant figures, so your answer should reflect that. Since heat is lost to the surroundings, the reaction is exothermic, and the answer should be negative.
Sort the length measurements in increasing order of magnitude from smallest to largest.
The length measurements in increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.
What is Measurement ?Measurement is the quantification of attributes of an object or event, which can be used to compare with other objects or events.
Measurement is a process of determining how large or small a physical quantity is as compared to a basic reference quantity of the same kind.
Hence, Among the given length measurements, The increasing order of magnitude from smallest to largest is Nanometer, micrometer, centimeter, decimeter, dekameter, kilometer.
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We do not want all staff being able to access all records that we hold. How can you ensure traceability and accessibility to the data stored?
To ensure data traceability and accessibility is to complete a study beginning-to-end on a closed system or platform.
How can you ensure traceability and accessibility to the data stored ? Lean On Self-Service Business Intelligence. Embed Dashboards Into Your Teams' Tools. Facilitate Data Literacy Throughout the Company. Embrace Your Changing Role.Learn more about Data accessibility here ;
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In the laboratory you dissolve 12.2 g of iron(II) iodide in a volumetric flask and add water to a total volume of 500 mL.
What is the molarity of the solution?
M.
What is the concentration of the iron(II) cation?
M.
What is the concentration of the iodide anion?
M.
In the laboratory you dissolve 16.8 g of iron(III) sulfate in a volumetric flask and add water to a total volume of 250 mL.
What is the molarity of the solution?
M.
What is the concentration of the iron(III) cation?
M.
What is the concentration of the sulfate anion?
M.
You wish to make a 0.271 M hydrobromic acid solution from a stock solution of 12.0 M hydrobromic acid. How much concentrated acid must you add to obtain a total volume of 50.0 mL of the dilute solution?
mL
Question 1
1) The formula of iron(II) iodide is [tex]\text{FeI}_{2}[/tex] and has a formula mass of 309.654 g/mol. This means that in 12.2 grams, there are
12.2/309.654 = 0.039398812868557 mol.So, the molarity is (0.039398812868557)/(0.5) = 0.0788 M (to 3 sf)
2) In 0.039398812868557 mol of iron(II) iodide, there are 0.039398812868557 moles of iron(II) iodide cations, and thus the molarity is still 0.0788 M (to 3 sf)
3) In 0.039398812868557 mol of iron(II) iodide, there are
2(0.039398812868557) = 0.078797625737114 moles of iodide anionsThus, the molarity is (0.078797625737114)/(0.5) = 0.158 M (to 3 sf)
Question 2
1) The formula of iron(III) sulfate is [tex]\text{Fe}_{2}\text{(SO}_{4})_{3}[/tex] and has a formula mass of 399.9 g/mol. This means that in 16.8 grams, there are
16.8/399.9 = 0.042010502625656 molSo, the molarity is (0.042010502625656)/(0.25) = 0.168 M (to 3 sf)
2) In 0.042010502625656 moles of iron(III) sulfate, there are 2(0.042010502625656)=0.084021005251312 moles of iron(III) cations, so the molarity is:
0.084021005251312/0.25 = 0.336 M (to 3 sf)3) In 0.042010502625656 moles of iron(III) sulfate, there are 3(0.042010502625656)=0.12603150787697 moles of sulfate anions, so the molarity is:
0.12603150787697/0.25 = 0.504 M (to 3 sf)Question 3
Since we need 50.0 mL of solution at 0.271 M,
0.271 = (moles of HBr)/(0.05) moles of HBr = 0.01355 molSo, we need this from 12.0 M HBr so, meaning that:
12.0 = (0.01355)/(liters of 12.0 M HBr stock solution)liters of 12.0 M HBr stock solution = 0.0011291666666667 L = 1.13 M (to 3 sf)Hybridization of bromine in SF4 and arsenic in SF2
Answer:
The answer is C
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A student runs two experiments with a constant-volume "bomb" calorimeter
containing 1400. g of water (see sketch at right).
sam....
First, a 5.000 g tablet of benzoic acid (C6H5CO₂H) is put into the "bomb" and
burned completely in an excess of oxygen. (Benzoic acid is known to have a heat of
combustion of 26.454 kJ/g.) The temperature of the water is observed to rise from
13.00 °C to 32.28 °C over a time of 10.7 minutes.
ry Sy...
an Am...
Next, 4.900 g of ethane (C₂H6) are put into the "bomb" and similarly completely
burned in an excess of oxygen. This time the temperature of the water rises from
13.00 °C to 44.56 °C.
Use this information, and any other information you need from the ALEKS Data
resource, to answer the questions below about this reaction:
-
stirrer
Is this reaction exothermic, endothermic, or neither?
ก
thermometer
chemical reaction
"bomb"
A "bomb" calorimeter.
If you said the reaction was exothermic or endothermic, calculate the amount of heat that was
released or absorbed by the reaction in the second experiment.
2C₂H,(g) + 70₂(g) 4CO₂(g) + 6H₂O(g)
Be sure any of your answers that are calculated from measured data are rounded to the correct number of significant digits.
Note for advanced students: it's possible the student did not do these experiments sufficiently carefully, and the values you
calculate may not exactly match published values for this reaction.
exothermic
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How many grams of hydrogen gas are produced from 2.50 mol of water?
__Ca(s) + __H2O(l) → __Ca(OH)2(aq) + __H2(g)
Answer:
2.52 g H₂
Explanation:
To find the mass of hydrogen gas, you need to (1) convert moles H₂O to moles H₂ (via mole-to-mole ratio from reaction coefficient) and then (2) convert moles H₂ to grams H₂ (via molar mass from periodic table values). When multiplying the given value by the mole-to-mole ratio, you need to use the coefficients of the balanced equation. An reaction is balanced once there is an equal amount of each element on both sides.
(Step 1)
The unbalanced equation:
Ca(s) + H₂O(l) ----> Ca(OH)₂(aq) + H₂(g)
Reactants: 1 calcium, 2 hydrogen, 1 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
The balanced equation:
1 Ca(s) + 2 H₂O(l) ----> 1 Ca(OH)₂(aq) + 1 H₂(g)
Reactants: 1 calcium, 4 hydrogen, 2 oxygen
Products: 1 calcium, 4 hydrogen, 2 oxygen
(Step 2)
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
(Step 3)
2.50 moles H₂O 1 mole H₂ 2.016 g
--------------------------- x ------------------------- x ---------------------- = 2.52 g H₂
2 moles H₂O 1 mole
Which of the following is the best example of an isolated system?
OA. A bus at a bus station
B. An astronaut in a spaceship
OC. A car on the freeway
D. A motorcycle in a garage
Answer:
B. An astronaut in a spaceship
Isolated system :-
In an isolated system, there is no transfer of energy or matter between the system and the environment.
Hope it helps!
Calculate the standard enthalpy change associated with this reaction at 25 °C using the
following enthalpies of formation:
CH4 ∆Hf = -62.7 kJ·mol–1, CO2 ∆Hf = -393.5 kJ·mol–1, H2O ∆Hf = -285.8 kJ·mol–1.
The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ
What is Standard Enhalpy change ?The standard enthalpy change of formation of a compound is the enthalpy change which occurs when one mole of the compound is formed from its elements under standard conditions, and with everything in its standard state.
According to the balanced chemical equation ;
CH₄(g) + 2O₂(g) ⟶ CO₂(g) + 2H₂O(l)
Now,
ΔH⁰ = ΔH⁰f(products) − ΔH⁰f(reactants)
= [ΔH⁰(CO₂) +ΔH⁰(H₂O)] − [ΔH⁰(CH₄) + 2ΔH⁰(O₂)]
= [−393.5 + 2 x (−285.8)] − [−62.7 + 2 x 0]
= − 902.4 kJ
Hence, The standard enthalpy change associated with the given reaction at 25 °C using the following enthalpies of formation will be − 902.4 kJ
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BaCl2(aq)+Na2SO4(aq)⟶BaSO4(s)+2NaCl(aq)
Using the balanced chemical equation, determine how many moles of NaCl will be produced, if 0.731 mol of BaCl2 is allowed to react with an excess of Na2SO4.
Answer:
1.46 moles NaCl
Explanation:
To find the moles of NaCl, you need to multiply the given value (0.731 moles BaCl₂) by the mole-to-mole ratio of the two relevant molecules. This ratio is made up of the coefficients in the balanced reaction. The numerator should contain moles NaCl to allow for the cancellation of moles BaCl₂. The final answer should have 3 sig figs to reflect the given value.
1 BaCl₂(aq) + Na₂SO₄(aq) ---> BaSO₄(s) + 2 NaCl(aq)
0.731 mole BaCl₂ 2 moles NaCl
--------------------------- x ------------------------- = 1.46 moles NaCl
1 mole BaCl₂
If 0.731 mol of BaCl₂ is allowed to react with an excess of Na₂SO₄, 1.462 moles of NaCl will be produced.
The balanced chemical equation is:
BaCl₂(aq) + Na₂SO₄(aq) → BaSO₄(s) + 2NaCl(aq)
The mole ratio of BaCl₂ to NaCl is 1:2. This means that 1 mole of BaCl2 will produce 2 moles of NaCl.
Moles of BaCl₂ = 0.731 mol
Mole ratio BaCl₂:NaCl = 1:2
Moles of NaCl = 0.731 mol * 2 = 1.462 mol
If we have 0.731 moles of BaCl₂, then we will produce 2 * 0.731 = 1.462 moles of NaCl.
Therefore, 1.462 moles of NaCl will be produced.
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Pure water boils at 100°C.
What happens to the water particles when water
boils?
A They gain energy and move further apart.
B They gain energy and stay close together.
C They lose energy and move further apart.
D They lose energy and stay close together.
Answer:
A
Explanation:
Which hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine?
Correct Answer is B
Answer:
C.) Csp² - Nsp³
Explanation:
Because the carbon has only 3 unique bonds, the conformation of the carbon should be Csp² (s + p + p). While the nitrogen also has only 3 bonds, making up 3 orbitals, it also has a lone pair of electrons. These electrons also take up one orbital. Therefore, the conformation of nitrogen is Nsp³ (s + p + p + p).
The hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.
What is hybridization?Hybridization is defined as the concept of the mixing of the atomic orbitals for the formation of new hybrid orbitals which are suitable for the pairing of electrons in forming chemical bonds in valence bond theory. And the orbital formed by the hybridization are termed as hybrid orbitals.
Since the carbon atom form one single bond with hydrogen atom and one pi bond with nitrogen bond, so the conformation of carbon atom is Csp2. On the other hand, nitrogen also form one single bond and a pi bond, so it also contribute three hybrid orbital. Since it have one lone pair of nitrogen so they take one orbitals. Therefore, the conformation of nitrogen atom is Nsp3.
Thus, we concluded that the hybrid orbitals overlap to form the sigma bonds between the indicated atoms in xanthine is Csp2 and Nsp3.
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Arrange the following elements in order of decreasing atomic radius: Ba , Sn , Cl , Pb , Se .
Rank elements from largest to smallest.
Answer:
Ba, Pb, Sn, Se, Cl
Explanation:
The atomic radius increases when going right to left and top to bottom on the periodic table and decreases going the opposite way so I put it in order based on that.
AICI3 + Pb(NO3)2
I need the answer please
Answer:
2 AlCl₃ + 3 Pb(NO₃)₂ ---> 2 Al(NO₃)₃ + 3 PbCl₂
Explanation:
This is a double-displacement reaction. The general structure of these reactions are:
AB + CD ----> AD + BC
In these reactions, the cation of one molecule is swapped with the cation of another molecule. To find the products, you first need identify the charge on each ion. This is important to know so that you can balance the new molecule via subscripts.
AlCl₃ = Al³⁺ and Cl⁻
Pb(NO₃)₂ = Pb²⁺ and NO₃⁻
Therefore, one of the new products should be a combination of Al³⁺ and NO₃⁻ and the other should be Pb²⁺ and Cl⁻. An easy way to balance the charges in the new molecules is to the make the charge on the cation the subscript of the anion (and vice versa). For instance, since Pb has a +2 charge, the chlorine should have a 2 subscript.
The unbalanced equation:
AlCl₃ + Pb(NO₃)₂ ---> Al(NO₃)₃ + PbCl₂
Reactants: 1 aluminum, 3 chlorine, 1 lead, 2 nitrate
Products: 1 aluminum, 2 chlorine, 1 lead, 3 nitrate
The balanced equation:
2 AlCl₃ + 3 Pb(NO₃)₂ ---> 2 Al(NO₃)₃ + 3 PbCl₂
Reactants: 2 aluminum, 6 chlorine, 3 lead, 6 nitrate
Products: 2 aluminum, 6 chlorine, 3 lead, 6 nitrate
Sunspot populations quickly rise and more slowly fall on an irregular cycle about every 11 years. Significant variations of the 11-year period are known over longer spans of time. For example, from 1900 to the 1960s the solar maxima (the period of greatest activity in the solar cycle of the sun) trend of sunspot count has been upward; from the 1960s to the present, it has diminished somewhat. The Sun is presently at a markedly heightened level of sunspot activity and was last similarly active over 8,000 years ago.
The number of sunspots correlates with the intensity of solar radiation over the period (since 1979) when satellite measurements of absolute radiative flux were available. Since sunspots are darker than the surrounding photosphere it might be expected that more sunspots would lead to less solar radiation and a decreased solar constant. However, the surrounding margins of sunspots are hotter than the average, and so are brighter; overall, more sunspots increase the sun's solar constant or brightness. During the Maunder Minimum in the 17th Century there were hardly any sunspots at all. The Maunder Minimum is the name given to the period roughly from 1645 to 1715, when sunspots became exceedingly rare, as noted by solar observers of the time. It is named after the solar astronomer Edward W. Maunder (1851-1928) who discovered the dearth of sunspots during that period by studying records from those years. During one 30-year period within the Maunder Minimum, for example, astronomers observed only about 50 sunspots, as opposed to a more typical 40,000-50,000 spots. This coincides with a period of cooling known as the Little Ice Age.
1) Which of the following is a true statement?:
A. There were more sunspots in 1965 than in 1701
B. The Little Ice Age had nothing to do with sunspots
C. The Sun is presently at a low level of sunspot activity
D. No one is counting sunspot activity any more
The Sun is presently at a low level of sunspot activity. Hence, option C is correct.
What is solar radiation?Solar radiation is often called the solar resource for the electromagnetic radiation emitted by the sun.
The Sun is presently at a low level of sunspot activity is the correct answer.
Hence, option C is correct.
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For the reaction below determine the ▲H for the reaction and state whether the reaction was endothermic or exothermic. Show your work.
C2H5OH + 3 O2 → 2 CO2 + 3H2O
C-C = 83 kcal; C-H = 99 kcal; C-O = 84 kcal; O-H = 111 kcal; C=O 192 kcal; O=O = 119 kcal
I got stuck on this and need help please, thank you so much!
Answer:exothermice
Explanation: it is relaeing heat not keeping it in
|
Dilution
A chemist makes 620. ml. of zinc nitrate • (Zn(NO3)₂) working solution by adding distilled water to 210. mL of a 4.93 M stock solution of zinc nitrate in water.
Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.
1.66 M is the concentration of the chemist's working solution.
What is molarity?Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.
In this case, we have a solution of Zn(NO₃)₂.
The chemist wants to prepare a dilute solution of this reactant.
The stock solution of the nitrate has a concentration of 4.93 M, and he wants to prepare 620 mL of a more dilute concentration of the same solution. He adds 210 mL of the stock and completes it with water until it reaches 620 mL.
We want to know the concentration of this diluted solution.
As we are working with the same solution, we can assume that the moles of the stock solution will be conserved in the diluted solution so:
[tex]n_1[/tex]= [tex]n_2[/tex] (1)
and we also know that:
n = M x [tex]V_2[/tex]
If we replace this expression in (1) we have:
[tex]M_1[/tex] x [tex]V_1[/tex]= [tex]M_2[/tex] x [tex]V_2[/tex]
Where 1, would be the stock solution and 2, the solution we want to prepare.
So, we already know the concentration and volume used of the stock solution and the desired volume of the diluted one, therefore, all we have to do is replace the given data in (2) and solve for the concentration which is [tex]M_2[/tex]:
4.93 x 210 = 620 x[tex]M_2[/tex]
[tex]M_2[/tex] = 1.66 M
This is the concentration of the solution prepared.
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Which are the product(s) of this chemical reaction? FeCl 3 + 3NH 4OH ->
a. 3NH4Fe + Cl3OH
b. 3FeCl3NH4OH
c. 3NH4Cl + 3FeOH
d. Fe(OH)3 + 3NH4Cl
Calculate the mass of pure sodium chloride will yield enough hydrogen chloride gas to tralize 25 cm² of 0.5 M potassium trioxo- bonate(IV) solution. NACI=58.5, HC1 = 36.5, K,CO, = 138)
1. Write the reaction rate expressions for the following reactions in terms of the disappearance of the reactants and the appearance of products: 1-(aq)+ OCI-(aq)-CI-(aq)+OI-(aq)
In terms of the disappearance of the reactants, the rate equations are R= -kd[I-]/dt and -kd[OCl-]/dt.
What is an ionic reaction?The term ionic reaction refers to the reaction that takes place between two ions. In this case, the ionic reaction is; I-(aq) + OCl-(aq) -------> Cl-(aq) + OI-(aq).
The rate equations in terms of the disappearance of the reactants is;
R= -kd[I-]/dt
And
R = -kd[OCl-]/dt
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Need ASAP please and thank you
The empirical formula would be [tex]C_2H_3O_2[/tex] and the molecular formula would be [tex]C_4 H_6 O_4[/tex]
Empirical and molecular formulaFrom the illustration:
C = 40.6 g H = 5.1 g O = 54.2 g
Divide each element by its molar weight:
C = 40.6/12 = 3.4 H = 5.1/1 = 5.1 O = 54.2/16 = 3.4
Divide by the smallest:
C = 3.4/3.4 = 1 H = 5.1/3.4 = 1.5 O = 3.4/3.4 = 1
Thus, the empirical formula is [tex]C_2H_3O_2[/tex]
To find the molecular formula:
[ [tex]C_2H_3O_2[/tex]]n = molecular formula
where n = molar mass/empirical formula mass
Empirical formula mass = 24 + 3 + 32 = 59
n = 118.084/59 = 2
Thus, the molecular formula is [tex]C_4 H_6 O_4[/tex] which is more or less the same as the empirical formula.
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The Empirical formula will be C₂H₃O₂ and the Molecular formula would be C₄H₆O₄
What is Empirical and Molecular Formula ?Empirical formula is a formula giving the proportions of the elements present in a compound but not the actual numbers or arrangement of atoms.
Molecular formula is a chemical formula that gives the total number of atoms of each element in each molecule of a substance.
Given ;
C = 40.6 gH = 5.1 gO = 54.2 gDivide each element by its molar weight:
C = 40.6 / 12 = 3.4H = 5.1 / 1 = 5.1 O = 54.2 / 16 = 3.4Divide by the smallest Value:
C = 3.4/3.4 = 1H = 5.1/3.4 = 1.5 O = 3.4/3.4 = 1Thus, the Empirical formula is C₂H₃O₂
Now, to find the molecular formula ;
[C₂H₃O₂ ]n = molecular formula
where n = molar mass / empirical formula mass
Empirical formula mass = 24 + 3 + 32 = 59
n = 118.084 / 59 = 2
[C₂H₃O₂ ]n = molecular formula
[C₂H₃O₂ ]2 = C₄H₆O₄
Thus, the Molecular formula is C₂H₃O₂
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The average speed of a diatomic fluorine molecule at 25 ∘C is 442.4 m⋅s−1 . What is the average wavelength of a fluorine molecule at this temperature? Assume that the molecule acts as a single particle
The average wavelength of the fluorine molecule will be 2.36 × 10⁻¹¹ metres.
Fluorine Molecule's Speed = 442.4 m/s
The Molar Mass of the F₂ = 38 g/mol
Now as we know that any molecule's
1 mole contain = 6.022 × 10²³ Molecule
So, 1 Fluorine molecule mass =
Fluorine's Molar mass / Number of Fluorine molecule in 1 mole
So, 1 Fluorine molecule mass = 38 / ( 6.022 × 10²³ )
1 Fluorine molecule mass = 6.31 × 10⁻²³ g
1 Fluorine molecule mass = 6.31 × 10⁻²⁶ Kg
So molecule's momentum = Molecule's mass × Molecule's Velocity
So molecule's momentum = ( 6.31 × 10⁻²⁶ ) × 442.4
So molecule's momentum = 2.8 × 10⁻²³ Kg.m/s
Now wavelength of Fluorine molecule = λ = planks constant / momentum
wavelength of Fluorine molecule = λ = ( 6.626 × 10⁻³⁴ ) / ( 2.8 × 10⁻²³ )
wavelength of Fluorine molecule = λ = 2.36 × 10⁻¹¹ metre
So the wavelength of the diatomic fluorine molecule came out to be 2.36 × 10⁻¹¹ metres after applying all the concepts and formulas.
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A sample of 0.0084 mol of HCl is dissolved in water to make a 1500 mL solution. Calculate the molarity of the HCl solution, the [H3O+] and the pH. For a strong acid such as HCl, the [H3O+] is the same as the molarity of the HCl solution.
A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a Molarity of HCl of 5.6 × 10⁻³ M, a Molarity of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.
What is Molarity ?Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solutionA solution is prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution. The molarity of HCl is:
[HCl] = 0.0084 moles / 1.5 L
= 5.6 × 10⁻³ M
HCl is a strong acid according to the following equation.
HCl(aq) + H₂O(l) ⇒ Cl⁻(aq) + H₃O⁺(aq)
Thus, the concentration of H₃O⁺ will be equal to the initial concentration of HCl, 5.6 × 10⁻³ M.
Now, we will calculate the pH of the solution using its Formula ;
pH = - log[H₃O⁺]
= - log [5.6 × 10⁻³]
= 2.3
Hence, A solution prepared by dissolving 0.0084 moles of HCl in 1500 mL of solution has a Molarity of HCl of 5.6 × 10⁻³ M, a Molarity of H₃O⁺ of 5.6 × 10⁻³ M and a pH of 2.3.
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An imaginary element, Y, has two different isotopes.
y has a percentage abundance of 25% and 29y has a percentage abundance of
75%.
Which of the following is the relative atomic mass of Y?
26
25
27
28
Answer:
kliujhygfdsalikumjyhbtgvf
Explanation:
The answer is:
28
I just got this answer so I don't know how to work it out but i hope it helps.
Data are often arranged to highlight particular patterns. What other ways might you arrange the data shown in the Sample of Elements table?
The data shown in the Sample of Elements table can be arranged on basis of physical and chemical properties , atomic number , atomic weight , etc .
The data shown in the Sample of Elements table can be arranged in various ways :
On basis of similarity among physical and chemical properties of several groups of three elements , as done by Johann Dobereiner in early 1800’s .On basis of increasing atomic wieghts , as done by A.E.B. de Chancourtois in 1862 and english chemist, John Alexander Newlands in 1865.On basis of the physical properties such as atomic volume, melting point and boiling point against atomic weight as done by Lothar Meyer .On basis of atomic no. as done by the English physicist, Henry Moseley in 1913.Learn more about Sample of Elements table here https://brainly.com/question/15987580
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If 44.7 g of KCI (MM = 74.55 g/mol) are added to a 500.0 mL volumetric flask, and water is added to fill the flask, what is the concentration of KCI in the resulting solution?
1.199 M is the concentration of KCI in the resulting solution.
What are moles?A mole is defined as 6.02214076 × [tex]10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.
No.of moles of KCI
[tex]Moles = \frac{mass}{molar \;mass}[/tex]
[tex]Moles = \frac{44.7 g}{74.5513 g/mol}[/tex]
= 0.599 moles
Vol.of the solution,V= 500 ml
= 0.5 liter
Molarity
[tex]Molality = \frac{Moles \;solute}{Volume \;of \;solution \;in \;litre}[/tex]
[tex]Molality = \frac{0.599 moles}{0.5 liter}[/tex]
= 1.199 M
Hence, 1.199 M is the concentration of KCI in the resulting solution.
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question is hard an di do not how to satrt thank you if you can help
The number of moles of N₂ contained in the flask will be 0.607.
What is Boyle's law?According to Boyle's law, the pressure of a gas tends to drop as the capacity of the container increases. The ideal gas equation is formed from the Boyles and Charles law.
Given data,
Pressure,P= 2.86 ATM
Volume,V = 5.00 L
Universal gas constant,R= 0.08206 L atm/mol K
Temperature,T= 13.86 °C = 286.8 K
From the ideal gas equation;
PV=nRT
2.86 × 5 = n × 0.08206 × 286.8
n = 0.607 moles
Hence the number of moles of N₂ contained in the flask will be 0.607.
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Determine how many kilojoules are absorbed when 341 g of Ca(OH)2 reacts via the following reaction:
Ca(OH)2(s)→CaO(s)+H2O(l),ΔH=+65.3kJ
305.6KJ are absorbed when 341 g of [tex]Ca(OH)_2[/tex]reacts via the following reaction.
What is enthalpy?The sum of the internal energy and the product of the pressure and volume of a thermodynamic system.
Given data:
[tex]Ca(OH)_2[/tex] (s) → [tex]CaO(s)+H_2O(l)[/tex], ΔH=+65.3kJ
Moles of [tex]Ca(OH)_2[/tex]= [tex]\frac{mass}{molar \;mass}[/tex]
Moles of [tex]Ca(OH)_2[/tex] = [tex]\frac{341 g }{74g/mol}[/tex] =4.68 moles
Since, 1 mol [tex]Ca(OH)_2[/tex] absorbs 65.3kJ.
Therefore, 4.68 moles [tex]Ca(OH)_2[/tex] produce energy = 65.3kJ X 4.68 moles
=305.6KJ
Hence, 305.6KJ are absorbed when 341 g of [tex]Ca(OH)_2[/tex] reacts via the following reaction.
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How does temperature affect Keq of a reaction
In an endothermic reaction, Keq increases as the temperature increases and vice versa.
In an exothermic reaction, Keq decreases as the temperature increases and vice versa.
Keq is the equilibrium constant of a reaction. The equilibrium constant is independent of the concentrations of the reactants and productsThe only factor that the equilibrium constant depends on is the temperature of the system of reactionIn an endothermic reaction, energy is gainedSo a higher temperature is more favourable in an endothermic reactionAs a result, more products are formed at a higher temperature, leading to a higher value of KeqIn an exothermic reaction, energy is releasedSo a lower temperature is more favourable in an exothermic reactionAs a result, fewer products are formed at a higher temperature, leading to a lower value of KeqTherefore, the temperature is the only factor that affects the equilibrium constant of a reaction.
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What information does a net ionic equation give that the complete ionic equation does not show?
A complete ionic equation shows ions formed from each of the species. It also show the charge on each of the ions.It also shows all reactants as compounds or elements. The ions formed and their charges can only be inferred from this equation.
What is a Net Ionic equation ?The net ionic equation shows the chemical species involve in chemical reaction while the complete ionic equation also involve the spectator ions.
What are Spectator ions ?These ions are same in both side of chemical reaction and thus cancels out each other.
Their presence can not effect the equilibrium of reaction that's why these ions are omitted in net ionic equation.
The net ionic equation state that whether precipitation is occur or not.
If the chemical reaction have no net ionic equation it means all are in aqueous from not precipitation occur.
Consider the following example:Balanced Chemical equation:
HClO₂(aq) + NaOH(aq) → H₂O(l) + NaClO₂ (aq)
Ionic equation:
H⁺(aq) + ClO₂⁻(aq) + Na⁺(aq) + OH⁻(aq) → H₂O(l) + Na⁺(aq) + ClO₂⁻ (aq)
Net ionic equation:
H⁺(aq) + OH⁻(aq) → H₂O(l)
The ClO₂⁻(aq) and Na⁺ (aq) are spectator ions that's why these are not written in net ionic equation.
The water can not be splitted into ions because it is present in liquid form.
Hence, The net ionic equation shows the chemical species involve in chemical reaction while the complete ionic equation also involve the spectator ions.
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In the reaction of 675.9 grams of barium chloride and excess silver(I) nitrate, how many grams of silver(I) chloride should get formed?
i dont understand, show work pls ty
Taking into account the reaction stoichiometry, the mass of silver(I) chloride formed is 930.37 grams.
Reaction stoichiometryIn first place, the balanced reaction is:
2 AgNO₃ + BaCl₂ → 2 AgCl + Ba(NO₃)₂
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
AgNO₃: 2 moles BaCl₂: 1 moleAgCl: 2 molesBa(NO₃)₂: 1 moleThe molar mass of the compounds is:
AgNO₃: 169.87 g/moleBaCl₂: 208.24 g/moleAgCl: 143.32 g/moleBa(NO₃)₂: 261.34 g/moleThen, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
AgNO₃: 2 moles ×169.87 g/mole= 339.74 grams
BaCl₂: 1 mole ×208.24 g/mole= 208.24 grams
AgCl: 2 moles ×143.32 g/mole= 286.64 grams
Ba(NO₃)₂: 1 mole×261.34 g/mole= 261.34 grams
Mass of silver(I) chloride formedThe following rule of three can be applied: if by reaction stoichiometry 208.24 grams of barium chloride form 286.64 grams of silver(I) chloride, 675.9 grams of barium chloride form how much mass of silver(I) chloride?
[tex]mass of silver(I) chloride=\frac{675.9 grams of barium chloride x286.64 grams of silver(I) chloride }{208.24 grams of barium chloride}[/tex]
mass of silver(I) chloride= 930.37 grams
Finally, the mass of silver(I) chloride formed is 930.37 grams.
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