A 3 Hz wave has a wavelength of 0.4 m. Calculate the speed of the wave (in m/s).

Answers

Answer 1

The speed of the wave with the given frequency and wavelength is 1.2m/s.

Given the data in the question;

Wavelength of the wave; [tex]\lambda = 0.4m[/tex]Frequency; [tex]f = 3Hz = 3s^{-1}[/tex]Speed of the wave; [tex]v = \ ?[/tex]

Wavelength

Wavelength is  the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.

It is expressed as;

[tex]\lambda = \frac{v}{f}[/tex]

Where v is velocity/speed and f is frequency.

Now, we can easily get the speed of the wave by substituting our given values into the expression above.

[tex]\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s[/tex]

Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.

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Related Questions

A 2.0-kg block slides on a rough horizontal surface. A force (magnitude P = 4.0 N) acting parallel to the surface is applied to the block. The magnitude of the block's acceleration is 1.2 m/s2. If P is increased to 5.0 N, determine the magnitude of the block's

Answers

When the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

Frictional force between the block and the horizontal surface

The frictional force between the block and the horizontal surface is determined by applying Newton's law;

∑F = ma

F - Ff = ma

Ff = F - ma

Ff = 4 - 2(1.2)

Ff = 4 - 2.4

Ff = 1.6 N

When the applied force increases to 5 N, the magnitude of the block's acceleration is calculated as follows;

F - Ff = ma

5 - 1.6 = 2a

3.4 = 2a

a = 3.4/2

a = 1.7 m/s²

Thus, when the applied force increases to 5 N, the magnitude of the block's acceleration is 1.7 m/s².

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at 27 degrees C and 750 mmhg a sample of hydrogen occupies 5.0 L how much space will occupy at STP​

Answers

Answer:

Explanation:

The number of mole of the hydrogen sample at 27 C and 750 mmHg pressure is:

[tex]n=\frac{PV}{RT}=\frac{(0.9898\times 10^{5})(5\times 10^{-3})}{(8.314)(27+273)}\approx 0.0198[/tex] mol

This number of mole will be the same although we change the pressure and temperature. For STP (Temperature = 0 C = 273 K, and Pressure = 760 mmHg = 76 cmHg = 1 Bar = 1.01 x [tex]10^{5}[/tex] Pa):

[tex]P'V'=nRT' \rightarrow V'=\frac{nRT'}{P'}=\frac{0.0198(8.314)(273)}{1.01\times 10^{5}}\approx 44.49 \times 10^{-5}[/tex] in [tex]m^{3}[/tex]. But in L, we find that V' = 0.4449 L

What season would Texas be having at point D?

Answers

Answer:

Almost winter so fall

Explanation:

Hope this helps! Please let me know if you want me to elaborate more or think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!

The force between a pair of charges is 900 newtons. The distance between the charges is 0.01 meters. If one of the charges is 2e-10 C what is the strength of the other charge ?

Answers

Answer:

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

Explanation:

Given:

Force between pair of charges= 900 newtons

The distance between the charges = 0.01 meters

Strength of Charge first q1 = 2e-10 Coulomb

To find:

Strength of Charge second q2 = ____ Coulomb?

Solution:

We know that,

Force between two charges separate by distance r is given by the equation,

[tex]|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb[/tex]

[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]

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Why is gravitational force always towards the center?

Answers

Answer:

i beleave cuz of the Earth is spherical

Explanation:

Because of the definition of gravity, point-mass, and centre of mass, the centre of mass will always be the point at which gravitational forces of the surrounding mass on any opposite sides are exactly equal

A lamp is 15% efficient. How much electrical energy must be supplied to the lamp each second if it produces 30 J of light energy per second? *WILL MARK BRAINLIEST*

Answers

200 Joules should be supplied in the circuit.

Efficiency = output/inupt

Here the output is 30J and input is missing

[tex]\sf \dfrac{30}{I} * 100 = 15[/tex]

multiplied with 100, to covert it into percentage

[tex]\sf 3000 = 15(I)[/tex]

[tex]\sf I = \dfrac{3000 }{15}[/tex]

[tex]\sf I = 200J[/tex]

Let that be X

Efficiency is 15% means the lamp produces 15J of light energy when 100J energy applied.

[tex]\\ \rm\Rrightarrow \dfrac{30}{x}(100)=15[/tex]

[tex]\\ \rm\Rrightarrow 3000=15x[/tex]

[tex]\\ \rm\Rrightarrow x=200J[/tex]

stion 3
Define the law of moments. It is applicable to a certain condition of the acting forces.
Name the condition.

Answers

Answer:

algebraic sum of moments of all the forces acting on the body about the axis of rotation is zero, the body is in equilibrium. According to the principle of moments, in equilibrium: Sum of anticlockwise Moments = Sum of clockwise moments.

Condition:

For an object to be in equilibrium, it must be experiencing no acceleration.

Hope it may helpful to you

In the figure below (Figure 1), the upper ball is released from rest, collides with the stationary lower ball, and sticks to it. The strings are both 50.0 cm long. The upper ball has a mass of 2.20 kg and it is initially 10.0 cm higher than the lower ball, which has a mass of 2.70 kg. Find the frequency of the motion after the collision. Find the maximum angular displacement of the motion after the collision.

Answers

(a) The frequency of the motion after the collision is 0.71 Hz.

(b) The maximum angular displacement of the motion after the collision is 16.3⁰.

Speed of the 2.2 kg ball when it collides with 2.7 kg ball

The speed of the 2.2 kg ball which was initially 10 cm higher that 2.7 kg ball is calculated as follows;

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √2gh

v = √(2 x 9.8 x 0.1)

v = 1.4 m/s

Final speed of both balls after collision

The final speed of both balls after the collision is determined from the principle of conservation of linear momentum.

Pi = Pf

m₁v₁ + m₂v₂ = vf(m₁ + m₂)

2.2(1.4) + 2.7(0) = vf(2.2 + 2.7)

3.08 = 4.9vf

vf = 3.08/4.9

vf = 0.63 m/s

Maximum displacement of the balls after the collision

P.E = K.E

[tex]mgh_f = \frac{1}{2} mv_f^2\\\\h_f = \frac{v_f^2}{2g} \\\\h_f = \frac{(0.63)^2}{2(9.8)} \\\\h_f = 0.02 \ m[/tex]

Maximum angular displacement

The maximum angular displacement of the balls after the collision is calculated as follows;

[tex]cos \theta = \frac{L - h_f}{L} \\\\cos\theta = \frac{0.5 - 0.02}{0.5} \\\\cos\theta = 0.96\\\\\theta = cos^{-1}(0.96)\\\\\theta = 16.3 \ ^0[/tex]

Frequency of the motion

[tex]f = \frac{1}{2\pi} \sqrt{\frac{g}{L} } \\\\f = \frac{1}{2\pi } \sqrt{\frac{9.8}{0.5} } \\\\f = 0.71 \ Hz[/tex]

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Which nucleus completes the following equation?

Answers

Answer:

I think that CL IS THE ONLY BEST ANSWER

Explanation:

PLEASE MARK ME BRAINLIEST IF MY ANSWER IS CORRECT PLEASE

Females are theoretically more prone to anxiety disorders due to __________. A. their habit of overreacting to physiological changes B. the high levels of serotonin causing hormone imbalance C. increased levels of norepinephrine causing anxiety sensitivity D. stress levels, life experiences, and friends’ stresses Please select the best answer from the choices provided A B C D

Answers

Answer:

fluctuations in the levels of female reproductive hormones

Explanation:

Women are more prone to anxiety due to a variety of biological, psychological, and cultural factors. Although the exact cause is unknown, recent research suggests that fluctuations in the levels of female reproductive hormones and cycles play an important role in women's enhanced vulnerability to anxiety.

Answer: D. stress levels, life experiences, and friends’ stresses

Explanation:

What would be the potential difference of the capacitor if it is connected to a battery of 3v?

Answers

Answer: 3V

Explanation:

If the capacitor is connected to a 3V battery:

[tex]\bold{V = \frac{Q}{C} }[/tex]

The potential difference is also 3V on the capacitor

At a typical bowling alley the distance from the line where the ball is released (foul line) to the first pin is 60ft. Assume it takes 5.0s for the ball to reach the pins after you release it, if it rolls without slipping and has a constant translational speed. Also assume the ball weights 12lb and has a diameter of 8.5 inches.

A- Calculate the rotation rate of the ball in rev/s

B- What is the total kinetic energy in pound-feet? Ignore the finger holes and treat the bowling ball as a uniform sphere

Answers

A) The rotation rate of the ball in rev/secs is ;  10.79 rev/secs

B) The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet

Given data :

mass of ball = 12 Ib

diameter of ball = 8.5 inches

Radius = 4.25 inches = 0.10795 m

Time = 5 secs

distance travelled = 60 ft  = 18.288 m

A) Determine the rotation rate of the ball

First step : calculate the velocity of ball

V = distance / time

  = 18.288 / 5 = 3.66 m/s

Next step :

angular velocity ( w ) = V / r  

                                  = 3.66 / ( 0.10795 ) = 33.90 rad/sec

convert to rev/sec = 33.90 / π

                               = 10.79 rev/secs

B) Determine the total kinetic energy

given that ball rolls without slipping

Vcon = Rw

Total K.E = 1/2 IW² + 1/2 mv²

               = 7/10 MR²W²

Total K.E = 7/10 *  5.44 * ( 0.10795 )² * 33.90²

               = 50.99 ≈ 51 J

convert to pound-feet = 37.6157 pound-feet

Hence we can conclude that The rotation rate of the ball in rev/secs is ;  10.79 rev/secs  and The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet.

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What is electrical power and how is it measured?

Answers

Answer:

power is measured in watts and its the messure of work over time.

Explanation:

✓ 4.) A certain molecule has an energy-level diagram for its vibrational energy in
which two levels are 0.0141eV apart. Find the wavelength of the emitted
line for the molecule as it falls from one of these levels to the other. [h
6.63 x 10-34 kgm s-?, C = 3 x 108ms-1, lev = 1.602 x 10^-19j

Answers

Answer:

Explanation:

You can use [tex]\Delta E=\frac{\hbar c}{\lambda} \rightarrow \lambda =\frac{\hbar c}{E} = \frac{1240 eV.nm}{0.0141 eV} \approx 87943.26[/tex] in nm.

Here the hc = 1240 eV.nm in eV and nanometer unit.

An example of a natural electric field is thunder or lightning

Answers

An example of natural electric field is Lightning

Answer:

Lightning

Explanation:

Lightning during a thunderstorm is an example of electrical energy. It is the visible discharge of atmospheric electricity. As lightning heats the air, it creates a shock wave that causes the sound of thunder.

hope this helps :)

• (-/1 Points) DETAILS OSCOLPHYS2016 9.5.WA.040.
MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER
A supertanker uses a windlass (a type of winch) like the one shown in the figure below to hoist its 21,200-kg anchor. Determine the force that must be exerted on the
outside wheel to lift the anchor at constant speed, neglecting friction and assuming the anchor is out of the water.
IN
doorg
-0.45 m
- 1.5m

Answers

The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

Force exerted outside the wheel

The force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.

∑τ = 0

Let the distance traveled by the load = 1.5 mLet the radius of the wheel or position of the force = 0.45 m

∑τ = R(mg) - r(F)

rF = R(mg)

0.45F = 1.5(21,200 x 9.8)

F = 6.925 x 10⁵ N.

Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.

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All machines are less than 100% efficient. True False​

Answers

Answer:

false

Explanation:

because no machines have 100% efficient

What is one benefit of smart meters?

Answers

Answer:

 You get up-to-date readings 

Explanation:

Is water Wet or Dry. Explain.

Answers

Explanation:

Water is wet, in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together.

Answer:

Liquid water is not itself wet, but can make other solid materials wet.

Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.

Whether an object is wet or dry depends on a balance between cohesive and adhesive forces. Cohesive forces are attractive forces within the liquid that cause the molecules in the liquid to prefer to stick together. Cohesive forces are also responsible for surface tension. If the cohesive forces are very strong, then the liquid molecules really like to stay close together and they won't spread out on the surface of an object very much. On the contrary, adhesive forces are the attractive forces between the liquid and the surface of the material. If the adhesive forces are strong, then the liquid will try and spread out onto the surface as much as possible. So how wet a surface is depends on the balance between these two forces. If the adhesive forces (liquid-solid) are bigger than the cohesive forces (liquid-liquid), we say the material becomes wet, and the liquid tends to spread out to maximize contact with the surface. On the other hand, if the adhesive forces (liquid-solid) are smaller than the cohesive forces (liquid-liquid), we say the material is dry, and the liquid tends to bead-up into a spherical drop and tries to minimize the contact with the surface.

Water actually has pretty high cohesive forces due to hydrogen bonding, and so is not as good at wetting surfaces as some liquids such as acetone or alcohols. However, water does wet certain surfaces like glass for example. Adding detergents can make water better at wetting by lowering the cohesive forces . Water resistant materials such as Gore-tex fabric is made of material that is hydrophobic (water repellent) and so the cohesive forces within the water (liquid-liquid) are much stronger than the adhesive force (liquid-solid) and water tends to bead-up on the outside of the material and you stay dry.

A toy car, with mass of 6 Kg, is pushed with a force of 10 N. If the toy car is in the grass with a coefficient of friction of 0.1 then what is the acceleration?

How far does it get pushed in 10 s?

Answers

Fy=ma

Fn-mg=ma
Fn-6(10)=6a
Fn=6a+60

Fx=ma

10-Ff=ma
10-(Fn)(0.1)=6a
0.1Fn=-6a+10
Fn=-6a+10/0.1

(substitute)
-6a+10/0.1=6a+60
-6a+10=0.6a+6
-6.6a=-4
a≈0.61m/s^2

Use Kinematics to find x in 10s

x=Vt+1/2at^2
x=0+1/2(0.61)(10)^2
x≈30.3m

I hate physics :p hope this is accurate

a car 150m to the east then backtracks 30m to the west. Describe the mathematical operation you will use to determine the net movement of the car

Answers

Answer:

Total displacement will be 120m

Explanation:

Since displacement is shortest distance travelled

Td= 150m east - 30m west ( Since they are opposite in direction)

Td= 120m East

Find the magnitude of the sum of these two vectors:​

Answers

Answer:

Explanation:

You can decompose those vectors into their components in x and y direction. For the first vector:

[tex]\vec{r}_{1}=r_{1}\cos 30\hat{i}+r_{1}\sin 30\hat{j}=3.14(\frac{1}{2}\sqrt{3}\hat{i}+\frac{1}{2}\hat{j})=1.57\sqrt{3}\hat{i}+1.57\hat{j}[/tex]

For the second vector:

[tex]\vec{r}_{2}=r_{2}\cos 60\hat{i}-r_{2}\sin60 \hat{j}=1.355\hat{i}-1.355\sqrt{3}\hat{j}[/tex]

The sum of two vectors will be:

[tex]\vec{r}=\vec{r}_{1}+\vec{r}_{2}=(1.57\sqrt{3}+1.355)\hat{i}+(1.57-1.355\sqrt{3})\hat{j}\approx 4.0711\hat{i}-0.77415\hat{j}[/tex]

The magnitude of the sum of two vectors is:

[tex]r=\sqrt{(4.0711)^{2}+(-0.77415)^{2}}\approx 4.14[/tex] meter

Answer:

4.14m

Explanation:

You are pushing a 30 crate along a rough surface by applying a horizontal force. The coefficients of
frictions between the surface and the crate are 0.3 and 0.6. Sketch the situation and create a Free Body diagram
from it, then Calculate:
a. The normal force on the crate by the floor.
b. The force required to get the crate to move.
c. Determine the kinetic friction force that the floor applies on the object.
d. Determine the acceleration of the crate.

Answers

Answer:

ill say math too!

Explanation:

A 2 kg solid disk with a radius of 0.22 m has a tangential force of 300N applied to it.
a) What is the torque acting on the disk?
b) What is the moment of inertia of the disk?
c) What angular acceleration is produced by the torque?
d) If the disk starts from rest and the acceleration is constant for 3.0s, what is the angular velocity of the disk at the end of 3.0s?
e) Through what angle in radians has the disk rotated during this time?

Answers

(a) The torque acting on the disk is 66 Nm.

(b) The moment of inertia of the disk is 0.05 kgm².

(c) The angular acceleration is produced by the torque is 1,320 rad/s².

(d) The final angular velocity of the disk is  3,960 rad/s.

(e) The angle of rotation of the disk is 5,940 rad.

Torque acting on the disk

The torque acting on the disk is calculated as follows;

τ = Fr

τ = 300 x 0.22

τ = 66 Nm

Moment of inertia

The moment of inertia of a solid disk is calculated as follows;

I = ¹/₂MR²

I = ¹/₂ x 2 x (0.22)²

I = 0.05 kgm²

Angular acceleration of the disk

The angular acceleration of the disk is calculated as follows;

τ = Iα

[tex]\alpha = \frac{\tau }{I} \\\\\alpha = \frac{66}{0.05} \\\\\alpha = 1,320 \ rad/s^2[/tex]

Angular velocity of the disk after 3 s

ωf = ωi + αt

ωf = 0 + (1320 x 3)

ωf = 3,960 rad/s

Angle of rotation of the disk

ωf² = ωi²+ 2αθ

(3,960)² = 0 + 2(1320)θ

θ = (3,960²) / (2 x 1320)

θ = 5,940 rad

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Which best illustrates projectile motion?

A pictorial diagram showing a hot air balloon in four different positions, each the same height from the ground and equally spaced.
A pictorial diagram with a rocket launched straight upward. The first three positions of the rocket are shown with equal spacing between them.
A pictorial diagram with a person swimming and position shown in equal time intervals and equally spaced.
A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground.

Answers

The pictorial diagram with a rocket launched straight upward, showing the first three positions of the rocket with equal spacing between them, best illustrates projectile motion. In this case, the rocket is projected upward into the air, and its path follows a parabolic trajectory due to the influence of gravity.

What is projectile motion?

Projectile motion refers to the motion of an object that is thrown, launched or otherwise projected into the air and then moves under the influence of gravity alone. In this type of motion, the object moves along a curved path, called a parabola, due to the combined effect of its initial velocity and the force of gravity acting on it.

When a rocket is launched straight upward, it experiences a projectile motion. The rocket's initial velocity is upwards, but gravity causes it to decelerate until it eventually stops at the highest point of its trajectory. The rocket then starts to fall back down, accelerating due to gravity until it reaches the ground. If we take three equal intervals of time, we can show the rocket's positions at those times. Initially, the rocket will be moving upwards with a decreasing velocity, then it will reach its maximum height before falling back down with an increasing velocity.

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#SPJ1

Answer: I believe it should be the final answer,

A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground

Explanation:

Friction helps your vehicle stop quickly.
A. TRUE
B. FALSE

Answers

Answer:

true

Explanation:

Friction helps your vehicle stop quickly. this statement ids true. Hence option A us correct. A vehicle can stop more rapidly because to friction. The brake pads rub on the turning braking discs or drums when the brakes are applied.

The friction slows the moving vehicle down and eventually causes it to halt by converting its kinetic energy into heat energy.  The effectiveness of the braking action will increase with the level of friction between the brake parts. For rapid stops, friction between the tyre and the road is also important.

The vehicle's forward motion is opposed by friction created by the tyres' gripping action on the road surface, which helps in stopping and decelerating. Rapid vehicle stopping would be incredibly difficult and risky without friction.

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How Does a Broken Bone Heal? Interactivity. Please i need the answer soon.

Answers

Answer:

The body develops a blood clot over the fractured bone in the first few days of a fracture to protect it and deliver the requisite cells for healing. Then, around the fractured bone, a field of healing tissue grows. This is referred to as a callus.

Explanation:

Answer:

Bone heals by making cartilage to temporarily plug the hole created by the break. This is then replaced by new bone. Many people think of bones as being solid, rigid, and structural. Bone is, of course, key to keeping our bodies upright, but it is also a highly dynamic and active organ

Explanation:

A wheel rotates at 24 revolutions every 3 minutes. This is equivalent to

Answers

8 revolutions every minute

Which angle is the angle of refraction?

Answers

Explanation:

[tex]\longmapsto\: \red{ hello \: mate}[/tex]

OPTION (C) 3

is the angle of refraction

Answer:

Option C. 3

Explanation:

Refraction is the change in direction of light passing from one medium to another. Angle 1 and 2 are reflection due to the bouncing of light.

Which statement is true about a wave that is created by causing vibrations in
particles of matter?
A. It can travel through empty space.
B. It is not an electromagnetic wave.
C. It does not need a medium.
D. It moves through a magnetic or electric field.

Answers

Answer:

A

Explanation:

A. it can travel through empty space

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