A 3-kg ball is rolling at a speed of 6 m/s. what is the magnitude of the momentum of the ball?

the frequency bandwidth in hz = 70,00,00,000 hz

1GHz = 1000MHz

Bandwidth = 1000mhz - 300mhz

Bandwidth = 700mhz

The frequency in hertz can be converted to hertz by multiplying by 1,000,000.

= 700 × 1000000

= 70,00,00,000 hz

Bandwidth of a channel is referred to as the range of frequencies available for transmission of data through that channel. It is the difference of maximum and minimum frequency contained in the composite signals.

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According to the current, the charge is 818.18 coulombs.

We need to know about current to solve this problem. Current can be defined as the flow rate of charge through the medium. It can be determined as

I = Q / t

where I is current, Q is charge and t is time.

From the question above, we know that

P = 25 W

V = 110 V

h = 1 hour = 3600 second

Calculate the current

P = V . I

25 = 110 . I

I = 0.23 A

By substituting the given parameters, we can calculate the charge

I = Q / t

0.23 = Q / 3600

Q = 818.18 coulombs

Hence, the charge is 818.18 coulombs.

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The tension in the rope which a climber, that has a mass of 60 kg, is hang motionless is 588 N

The tension formula and the procedure we will use is:

T = m * g

Where:

Information of the problem:

Knowing that the body is in equilibrium the tension of the rope is equal to the gravity force. Applying the tension formula and substituting values we have:

T = Fg

Fg = m * g

Fg = 60 kg * 9.8 m/s²

Fg = 588 N

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

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It undermine belief in the Ptolemaic system in the perfect heavens idea of Aristotle because Aristotle's ideal skies and the prolemale model both agreed that the new star was sufficiently remote to be a part of the celestial sphere.

A mathematical model of the universe developed by the Alexandrian astronomer and mathematician Ptolemy in 150 CE and documented by him in his Almagest and Planetary Hypotheses is known as the Ptolemaic system, also known as the geocentric system or geocentric model.

According to the Ptolemaic theory, the Moon, Sun, and planets all revolved around the Earth in a ring-shaped orbit.

The ancient Greeks only knew of five planets, not including the Earth, and they thought they orbited it in a unique motion called an epicycle.

The Earth's position at the center of the universe, or the geocentric model, was Ptolemy's model's most crucial component.

For more than 1,500 years, astronomical and astrological charts were created using Ptolemy's tables because they were so good at forecasting positions in the night sky.

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The all-or-none law is the principle that states, once the threshold has been crossed, the action potential either fires or it does not. there is no half measure.

The all-or-none law: It is a principle which states that the strength of a response of a muscle fiber or nerve cell is not dependent on the  stimulus strength. If the stimulus is above the certain threshold, a muscle fiber or nerve  will fire.

Essentially, there will be either a full response or no response for an individual muscle fiber or neuron. Therefore action potential is essentially a full response.

There is no thing as a strong or weak action potential. Instead, it is always All-or-nothing process.

This will minimize the possibility of information that will be lost in the way.

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a) The velocity when it return to the ground is 9 m/s

b) The total time taken is 1.84 s

c) The highest distance covered is 4.2 m

We have to know that when an object has been projected upwards or downwards that the movement of the objects could be described by the use of the equations of motion under gravity. In that case we have to look at that tennis ball is thrown vertically upward with an initial velocity of +9.0

m/s as an object that is undergoing motion under gravity.

We now have;

The time taken for the ball to reach the starting point;

v = u - gt

At the maximum height the ball is stationary thus v = 0 m/s

t =u/g

t = 9.0 m/s / 9.8 m/s^2

t = 0.92 s

Given that the ball went up and came down the time taken to return to starting point = 2(0.92) = 1.84 s

The highest distance covered by the ball is obtained from;

h = ut - 1/2gt^2

h = 9 * 0.92 - (0.5 * 9.8 * (0.92)^2)

h = 8.3  - 4.1

h = 4.2 m

The highest distance covered is 4.2 m

The balls speed when it returns;

Recall that it now falls from a height thus u = 0 m/s

v = u + gt

v = gt

v = 9.8 * 0.92

v = 9 m/s

The velocity when it return to the ground is 9 m/s

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Answer:

strength or energy as an attribute of physical action or movement.

By ideal gas approximation, the final pressure is 75.76 atm.

We need to know about the ideal gas theory to solve this problem. The ideal gas is assumed that there is no interaction between particles in a gas. It can be determined by the equation

P . V = n . R . T

where P is pressure, V is volume, n is the number of moles gas, R is the ideal gas constant (8.31 J/mol.K) and T is temperature.

From the question above, we know that

P1 = 50 atm

T1 = 330 K

T2 = 500 K

When the initial and final volume is the same, we can use the ratio of pressure and temperature as

P1 / P2 = T1 / T2

50 / P2 = 330 / 500

P2 = 50 x 500 / 330

P2 = 75.76 atm

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Explanation:

I hope that this Is the right way to solve the problem

The two risks to company profits they should include in their analysis are less efficient production and unsafe working conditions, therefore the correct answer is options A and E.

Science is the methodical, empirically-based pursuit and application of knowledge and understanding of the natural and social worlds.

As given in the problem If a team of engineers is doing a cost-benefit analysis to determine whether they should develop new technology, then the two risks to company profits they should include in their analysis,

The new technological design could take more time during manufacturing and production which can lead to less efficient production.

Therefore the correct answer is option A and option E.

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It's "possible", but it's very very very rare.  In fact, there are only two known substances that can contract when their temperature increases.

One of them is water.  When water warms from 0°C to 4°C, it contracts.

I can't remember what the other substance is.

Answer:

V = ((179 - 14) + (179 - (-23))) / 94 = 367 / 4 = 3.9 m/s

Question asks for total distance not net distance traveled

The wavelength associated with the particle of mass 1 mg and velocity

1 km/s is 6.63 x [tex]10^{-31}[/tex] m.

We have a particle moving with certain velocity.

We have to calculate the wavelength associated with the particle.

According to de - Broglie, the wavelength of the wave associated with the moving particle is -

λ = h/mv

Where -

h -  Planck's constant

mv - Momentum of particle

According to the question -

Mass = 1 mg =  10⁻⁶ Kg

velocity = 1 Km/s = 1000 m/s

Using the formula for de - Broglie wavelength discussed above -

Momentum = mv = 10⁻⁶ x 10³ = 10⁻³ Kg m/s

now -

λ = h/10⁻³ = 6.63 x 10⁻³⁴/10⁻³ = 6.63 x 10⁻³¹ m

Hence, the wavelength associated with the particle is 6.63 x 10⁻³¹  m.

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The velocity the bullet used in leaving the gun is 586 m/s (Option 1)

We'll begin by obtaining the time taken for the bullet to hit the ground. This is illustrated below::::

h = ½gt²

47 = ½ × 10 × t²

47 = 5 × t²

Divide both side by 5

t² = 47 / 5

Take the square root of both side

t = √(47 / 5)

t = 3.07 s

Finally, we shall determin the the velocity. This is illustrated below:

s = ut

1800 = u × × 3.07

Divide both sides by 3.07

u = 1800 / 3.07

u = 586 m/s

Thus, the velocity the bullet used in leaving the gun is 586 m/s (Option 1)

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The magnitude of cyclist's displacement who has a average velocity of 20 m / s in 5 seconds is 100 meters

v = d / t

v = Velocity

d = Distance

t = Time

v = 20 m / s

t = 5 s

d = v * t

d = 20 * 5

d = 100 m

Velocity of an object is the rate of change of distance by the object in a given amount of time. It is denoted by v.

Therefore, the magnitude of cyclist's displacement who has a average velocity of 20 m / s in 5 seconds is 100 meters

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According to frictional force, the normal force is 3782.61 N.

We need to know about frictional force to solve this problem. The frictional force is the force against the object to move. The magnitude of the frictional force can be determined as

Ff = N . μ

where Ff is the frictional force, N is normal force and μ is coefficient of friction

From the question above, we know that

Ff = 870 N

μ = 0.23

By substituting the given parameters, we can determine the normal force

Ff = N . μ

870 = N . 0.23

N = 870 / 0.23

N = 3782.61 N

Hence, the normal force is 3782.61 N.

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The height of the cliff is [tex]$90.69 \mathrm{~m}$[/tex]

The initial speed of the stone vi = 10m/s

The stone is also moving downward vertically under the effect of the gravitational acceleration [tex]$g=9.81 \mathrm{m} / \mathrm{s}^2$[/tex]

Thus, the stone will have two velocity components while moving. One component is the horizontal speed which will be constant during motion and the other component is the vertical speed which will increase under the effect of gravitational acceleration.

Hence, the final vertical speed when the stone hits the ground is

[tex]$$\begin{aligned}&V_y=V_{y o}+g t \\&V_y=0+9.81(4.3)=42.183 \mathrm{~m} / \mathrm{s}\end{aligned}$$[/tex]

The height of the cliff where the stone is thrown is

[tex]$$\begin{aligned}&h=\frac{\left(V_y\right)^2-\left(V_{y o}\right)^2}{2 g} \\&h=\frac{42.183^2-(0)^2}{2(9.81)} \\&h=90.69 \mathrm{~m}\end{aligned}$$[/tex]

So, the height of the cliff is [tex]$90.69 \mathrm{~m}$[/tex]

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A boost chopper is powered by a 12-V DC power supply.

The output voltage range of this chopper if the duty cycle vary between 20 and 95% will be 15 - 240V

How to calculate the output voltage?

Output voltage can be calculated by the following formula:

[tex]V_0=\frac{V_i}{1-D}[/tex]

Here,

[tex]V_i[/tex] is the initial power supply.

D = Duty cycle

Calculating output voltage for 20%

[tex]V_0=\frac{12}{1-0.20} \\V_0=-\frac{12}{0.8} \\V_0=15[/tex]

Calculating output voltage for 95%

[tex]V_0=\frac{12}{1-0.95} \\V_0=-\frac{12}{0.05} \\V_0=240[/tex]

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The maximum height to which the potato will rise is 13.06 m

From the question given above, the folloing data were obtained:

The maximum height can be obtaibed as illustarted below

v² = u² – 2gh (since the ball is going against gravity)

0² = 16² – (2 × 9.8 × h)

0 = 256 – 19.6h

Collect like terms

0 – 256 = –19.6h

–256 = –19.6h

Divide both side by –19.6

h = –256 / –19.6

h = 13.06 m

Thus, the potato will rise to a height of 13.06 m

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It is frequently necessary to produce volume measurements in quantitative chemistry with an error of 0.1%, or one part per thousand.

Utilizing volumetric glassware with a known capacity down to a few hundredths of a milliliter, or approximately 0.01 mL, is required for this.

Five different types of glassware, including graduated cylinders, beakers, volumetric pipets, burets, and volumetric flasks, are frequently used to measure out precise volumes.

The most exact glassware are volumetric pipets, flasks, and burets; the glassware manufacturers calibrate these to a high degree of accuracy.

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Answer:

C. Hawaiian

Explanation:

Ego's father and all male relatives in his generation have the same kin name. Ego's mother and all female relatives in her generation are referred to by the same kin term.

Similarly, all brothers and male cousins are linked by giving them the same kin term. Sisters and all female cousins are also referred to by the same term.  

d(u, v) = [tex]\sqrt{34}[/tex]

An inner product of a real vector space V is an assignment that for any two vectors u, v ∈ V, there is a real number hu, vi,

d(u, v) = ║u - v║ = [tex]\sqrt{(u_{1} - v_{1} )^{2} + (u_{2} - v_{2} )^{2}[/tex]

<u = v> = 3u₁v₁ + u₂v₂

u = (-3,9)

v = (0,4)

So, d(u, v) = [tex]\sqrt{(-3 0)^{2} + (9 - 4)^{2}[/tex]

                = [tex]\sqrt{9 + 25}[/tex] = [tex]\sqrt{34}[/tex]

d(u, v) = [tex]\sqrt{34}[/tex]

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The  given coefficient of linear expansion of glass is [tex]9 \times 10^{-6}[/tex]/°C.

change in area =[tex]a_1[/tex][tex]\times[/tex]β[tex]\times[/tex]ΔT

where β=2α

so,

[tex]60\times 150\times2\times9\times10^{-6}\times36 = 5.832cm^{2}[/tex]

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Answer:

Group

Explanation:

Within each column, or group, of the table, all the elements have the same number of valence electrons. This explains why all the elements in the same group have very similar chemical properties. For elements in groups 1–2 and 13–18, the number of valence electrons is easy to tell directly from the periodic table.

Answer:

Доброе утро, ответ 5+5="4

Explanation:

A certain car with an accelerating rate of 0.59 m/s2 will take 5.30 s to go from a speed of 50 mi/h to a speed of 57 mi/h

The formula for Uniformly varied rectilinear motion (UVRM) and procedure we will use to solve this exercise is:

t = (vf - vi) /a

Where:

Information about the problem:

By converting the velocity from mi/h to m/s, we get:

50 mi/h * (1609.34 m / 1 mi) * (1h / 3600 s) = 22.35 m/s

57 mi/h * (1609.34 m / 1 mi) * (1h / 3600 s) = 25.48 m/s

Applying the time formula, we have:

t = (vf - vi) /a

t = ( 25.48 m/s - 22.35 m/s) / 0.59 m/s2

t = 3.13 m/s  /0.59 m/s2

t =  5.30 s

It is a physical quantity that indicates the variation of velocity as a function of time, it is expressed in units of distance per time squared e.g.: m/sec2 ; km/h2

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The distance from equilibrium where the acceleration equal to half its maximum acceleration is;

x=|xocosωt|

=|−xo2|

=xo2

X =Asin(ωt+ϕ)

and the velocity of the oscillating block is given by the equation;

V=dX/dt

=Aωcos(ωt+ϕ)

V=Vmcos(ωt+ϕ)

Where

A is the amplitude

Vm is the maximum velocity

ω is the angular frequency of oscillation.

ϕ is the initial phase

Let

M is the mass of the block attached to the end of the spring.

x is the displacement of the spring at any time t.

Given

The amplitude of the displacement is xoxo

Since given that the displacement is maximum at t = 0 so, the displacement of the body is given by;

x=xocos(ωt) ---------------1

where ω=√k/m and k is the spring constant.

The velocity of the body is;

v=dx/dt

=−xoωsinωt

v=−vosinωt ------------- 2

The acceleration of the body during simple harmonic motion is;

a=dv/dt

=−xoω2cosωt

a=−aocosωt                 Eqn. 3

Given the velocity is half of its maximum velocity;

vo/2=−vosinωt

sinωt=−1/2

So, from equation 1, the distance from equilibrium where the velocity equal to half its maximum velocity is;

x=|xocosωt|

=|-xo/2|

=xo/2

If the acceleration is equal to half of its maximum acceleration:

ao2=−aocosωt

cosωt=−1/2

So, from equation 1, the distance from equilibrium where the acceleration equal to half its maximum acceleration is;

x=|xocosωt|

=|−xo2|

=xo2

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Only traffic trailing the school bus are required to stop when travelling on a highway divided into four traffic lanes.

When a school bus displays its mechanical stop signal or flashing red lights to receive or discharge passengers, the driver of any other vehicle approaching the school bus must stop and not attempt to pass the school bus until the mechanical stop signal is withdrawn, the flashing red lights are turned off, and the bus has begun to move. Highway divided into four or more lanes by a median divider or a centre turning lane: Only traffic trailing the school bus must come to a halt when it stops for passengers. In other words, only cars approaching the back of the bus and moving in the same direction as the bus are permitted.

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It takes 126 s for the sphere to cool by 1K due to its radiation of heat energy and this can be calculated with the help of emissivity formula.

Radiation can be defined as the release of energy in the form of electromagnetic waves or ionizing particles, especially high-energy particles.

This release of energy can be in the form of waves or particles.

Density pf copper = 8900

Radius of sphere = 5cm

emissivity = 1

initial temperature = T=300K

we know [tex]\delta[/tex]t = [tex]\frac{\delta Q}{H}[/tex] = [tex]\frac{mc \delta T}{A \sigma e T^4}[/tex]

We can express it as

m = [tex]\rho V[/tex]

A = 4[tex]R^{2} \pi[/tex]

[tex]\delta t = \frac{\rho Vc \delta T}{4R^2 \pi \sigma e T^4}[/tex]

Volume V = 4/3 [tex]R^{2}\pi[/tex][tex]\delta t = \frac{\rho 4/3 R^3\pi c \delta T}{4R^2\pi \sigma e T^4}[/tex]

[tex]\delta t = \frac{\rho Rc \delta T}{3 \sigma e T^4}[/tex]

[tex]\delta t[/tex] = [tex]\frac{8900*0.05*390*1}{3*5.67*10^{-8}*1*300^4}[/tex]

[tex]\delta t[/tex] = 126s

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This suggests the percentage of those who come lower back on your blog each and every week after their first visit.

As an example, if this week you had one hundred human beings go to your blog and inside the week one column, it suggests seventeen percent. which means of the initial a hundred human beings, seventeen got here returned. underneath week two in case you see eight percent, that means of the preliminary a hundred human beings, eight humans came lower back in two weeks.

This quantity will keep getting smaller, but the goal is to get humans back as often as viable. That increases belief, social shares, and the capability of people to link to you, and it even will increase the odds that the vacationer will convert right into a customer. The Pageviews column tells you ways generally each individual blog published was regarded in the decided on time-frame. The specific Pageviews column simply to the right of it tells you ways a lot of those pageviews were from precise visitors

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