A 3.68 kg box is being pushed up the incline of 85.61 degrees with an acceleration of 11.63 m/s2. Chasadie is pushing the box with a force of 217.41 N. What is the friction force?
Answers
The friction force experienced by the box is approximately 77.96 N.
What is frictional force?Frictional force is a force that opposes the motion or attempted motion between two surfaces in contact. It is caused by the irregularities in the surfaces of objects that come into contact with each other, and it acts in the direction opposite to the direction of motion or attempted motion.
We can begin by drawing a diagram of the situation and labeling the forces acting on the box:
where:
Fp is the force applied by Chasadie.
Ff is the force of friction.
mg is the weight of the box (mass times gravity)
We can then use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:
ΣF = ma
where ΣF is the sum of all the forces acting on the box.
In the vertical direction, we have:
ΣFy = N - mg = 0
where N is the normal force, which is equal and opposite to the weight of the box.
Since the incline is at an angle of 85.61 degrees, we can use trigonometry to find the components of the weight and normal force:
N = mg cos θ = (3.68 kg)(9.81 m/s²) cos (85.61°) ≈ 18.77 N
mg sin θ = (3.68 kg)(9.81 m/s²) sin (85.61°) ≈ 36.24 N
In the horizontal direction, we have:
ΣFx = Fp - Ff - mg sin θ = ma
Plugging in the given values and solving for Ff:
Ff = Fp - ma + mg sin θ
= (217.41 N) - (3.68 kg)(11.63 m/s²) + (3.68 kg)(9.81 m/s²) sin (85.61°)
≈ 77.96 N
Therefore, the friction force is approximately 77.96 N.
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The diagram for the solution of the question is as follows:
Related Questions
an object's moment of inertia is 2.0 kg.m2. its angular velocity increases from 20 rad/s to 60 rad/s in 10 seconds. what is the net torque on the object?
Answers
The angular acceleration can be calculated using the formula α = (ωf - ωi) / t, where ωf is the final angular velocity, ωi is the initial angular velocity, and t is the time taken. Substituting the given values, the net torque on the object is found to be 8.0 N.m.
The moment of inertia of an object is a measure of its resistance to rotational motion and depends on its mass and distribution of mass. The angular velocity of an object is the rate at which it rotates around its axis and is measured in radians per second.
In this question, the moment of inertia of the object is given as 2.0 kg.m^2, and its angular velocity increases from 20 rad/s to 60 rad/s in 10 seconds. We need to find the net torque acting on the object during this time.
The net torque on the object can be calculated using the formula τ = Iα, where τ is the net torque, I is the moment of inertia, and α is the angular acceleration. The angular acceleration can be calculated using the formula α = (ωf - ωi) / t, where ωf is the final angular velocity, ωi is the initial angular velocity, and t is the time taken.
Substituting the given values,
we get α = (60 rad/s - 20 rad/s) / 10 s = 4.0 rad/s^2. Therefore, τ = Iα = 2.0 kg.m^2 x 4.0 rad/s^2 = 8.0 N.m. Hence, the net torque acting on the object is 8.0 N.m.
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which of the following statements concerning the motion of a physical pendulum is incorrect? responses the period is changed if the mass of the bob is doubled and the length of the pendulum is halved the period is changed if the mass of the bob is doubled and the length of the pendulum is halved the time interval between conditions of maximum potential energy is one period. the time interval between conditions of maximum potential energy is one period. the kinetic energy is a minimum when the displacement is a maximum. the kinetic energy is a minimum when the displacement is a maximum. the acceleration is a maximum when the displacement is a maximum
Answers
The statement that is incorrect is: The time interval between conditions of maximum potential energy is one period.
The time interval between conditions of maximum potential energy is not always one period. The period of a pendulum is the time it takes for the pendulum to complete one full cycle of motion, which is determined by the length of the pendulum and the acceleration due to gravity. The time interval between conditions of maximum potential energy depends on the initial conditions of the pendulum, such as the initial angle and the initial velocity. If the initial angle or the initial velocity is changed, then the time interval between conditions of maximum potential energy will change as well.
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on a scale in which the distance from the sun to the earth is about 15 meters, the distance from the earth to the moon is .
Answers
On a scale where the distance from Earth to the Sun is about 15 meters, the distance from Earth to the Moon is 38.54 millimeters .
Distance earth-sun= 149.6 x 10^9m
Distance earth-moon= 384.4 x 10^6m
It's the division between the distance earth-sun by the 15 meters:
149.6 x 10^9m / 15m = 9973333333m
Give us the number of meters in the scale equivalent to distance earth-moon.
384.4 x 10^6m / 9973333333m = 0.0385
Converting the answer to millimeters (knowing that 1m=1000mm)
= 38.54mm
Distance is a measure of the physical separation between two objects or locations. It is often described in terms of how far apart two points are from each other. In physics, distance is typically measured in units such as meters, kilometers, or miles.The concept of distance is important in many areas of study, including mathematics, physics, and geography.
Distance can be calculated using various methods, including using instruments such as rulers, tape measures, or GPS systems. It can also be estimated by using landmarks or other points of reference. The precise measurement of distance is crucial in many fields, from construction and engineering to astronomy and space exploration.It is used to determine the spatial relationship between objects or locations, and is often used to calculate travel times and navigation routes.
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Complete Question: -
On a scale where the distance from Earth to the Sun is about 15 meters, the distance from Earth to the Moon is __________.
how much work does juanita do if she uses a force of 40 newtons to pull 2 friends on a wagon for 32 meters?
Answers
Juanita does 1280 joules of work to pull her 2 friends on the wagon over a distance of 32 meters with a force of 40 newtons.
To calculate the amount of work Juanita does, we need to use the formula:
Work = Force x Distance x cos(theta)
where:
Force: the amount of force applied (in newtons)
Distance: the distance the object is moved (in meters)
theta: the angle between the direction of the force and the direction of motion (in degrees)
In this case, Juanita applies a force of 40 newtons to pull the wagon with her 2 friends, over a distance of 32 meters.
We don't have information about the angle between the force and the direction of motion, but we can assume that the force is applied in the direction of motion (i.e., theta = 0 degrees).
Using this information, we can calculate the work Juanita does as follows:
Work = Force x Distance x cos(theta)
Work = 40 N x 32 m x cos(0)
Work = 1280 joules
Therefore, Juanita does 1280 joules of work to pull her 2 friends on the wagon over a distance of 32 meters with a force of 40 newtons.
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A ball is thrown downward with an initial velocity of 14 m/s. Using the approximate value of g = 10 m/s2, what is the ball's velocity 3.0 seconds after it is released?; A ball is thrown downward with an initial velocity of 14 m/s. Using the approximate value of g = 10 m/s2, what is the ball's velocity 3.0 seconds after it is released?
Answers
The final velocity is 43.4 m/s. As we can see in the calculation.
What is the first equation of motion?Acceleration is a measure of how quickly an object changes its velocity. It is defined as the rate of change of velocity with respect to time. Mathematically, acceleration is represented by the symbol "a" and can be calculated using the following formula:
a = v - u / t
We have that;
v = u + gt
v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
v = 14 + 9.8 * 3
v = 43.4 m/s
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a hamster runs at a speed of 13 centimeters per second in a wheel of radius 14 centimeters. a) what is the angular velocity of the wheel? (in radians/sec) incorrect radians/sec correctradians/sec no decimals allowed. b) how fast will the wheel spin in revolutions per minute? incorrect rev/min correctrev/min no decimals allowed.
Answers
The angular velocity of the wheel is 0.9286 radians/sec and the number of revolutions per minute is 8.84 rpm
The angular velocity of the wheel in radians per second is given by the formula:
ω = v/r where ω is the angular velocity in radians per second, v is the linear velocity in cm/s, and r is the radius of the wheel in cm.
Therefore, the angular velocity of the wheel is:
ω = 13 cm/s / 14 cm = 0.9286 radians/sec
To calculate the revolutions per minute (rpm), we use the formula:
rpm = ω * 60 / (2π)
where 2π is the number of radians in a full revolution.
Therefore, the wheel will spin at a rate of:
rpm = 0.9286 radians/sec * 60 / (2π) = 8.84 rpm
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a 2 coulomb charge is moved from a to b in the presence of an electric field created by other charges. the potential energy when the charge is at point b is 30 j higher then the potential energy when the charge was at a. the voltage (created by the other charges) at point a was 10 volts. what is the voltage at point b?
Answers
When the charge is at point b, the potential energy is 30 j, and the voltage produced at point b by the other charges is 25 volts.
We can use the formula for potential energy in an electric field to relate the change in potential energy to the difference in voltage between the two points:
ΔU = qΔV
here,
ΔU is change in potential energy,
q is charge, and
ΔV is difference in voltage.
We are given that
q = 2 C, and
That the change in potential energy
= ΔU = 30 J.
Therefore, we can solve for the difference in voltage between points a and b:
ΔV = ΔU / q
ΔV = 30 J / 2
ΔV = 15 V
This means that the voltage at point b is
10 V + 15 V = 25 V,
because the potential energy when the charge is at point b is 30 J higher than at point a.
Therefore, the voltage created by the other charges at point b is 25 volts.
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A child and a sled with a combined mass of 50.0 kg slide down a frictionless hill. If the sled starts from rest and has a speed of 9.0 m/s at the bottom, what is the height of the hill?
Answers
Answer:
297.38 meters
Explanation:
The height of the hill can be calculated using the principle of conservation of energy. This principle states that the total energy of a system is conserved, and that the change in potential energy of an object is equal to the work done on it.
The height of the hill can be calculated using the formula:
h = (1/2) m v^2 / g
where m is the mass of the child and sled, v is the final speed of the sled, and g is the acceleration due to gravity (9.8 m/s^2).
Plugging in the values, we get:
h = (1/2) * 50.0 kg * (9.0 m/s)^2 / 9.8 m/s^2
h = (1/2) * 50.0 kg * 81.0 m^2/s^2 / 9.8 m/s^2
h = 40.5 kg * 81.0 m^2/s^2 / 9.8 m/s^2
h = 2911.76 kg m^2/s^2 / 9.8 m/s^2
h = 297.38 m
So the height of the hill is 297.38 meters.
a conducting sphere contains positive charge distributed uniformly over its surface. which statements about the potential due to this sphere are true? all potentials are measured relative to infinity. (there may be more than one correct choice.) choose all that apply. a conducting sphere contains positive charge distributed uniformly over its surface. which statements about the potential due to this sphere are true? all potentials are measured relative to infinity. (there may be more than one correct choice.)choose all that apply. the potential is lowest, but not zero, at the center of the sphere. the potential at the center of the sphere is zero. the potential at the center of the sphere is the same as the potential at the surface. the potential at the center is the same as the potential at infinity. the potential at the surface is higher than the potential at the center.
Answers
The statements "the potential at the center of the sphere is zero", "the potential at the surface of the sphere is the same as the potential at infinity", and "the potential is lowest at the center of the sphere" are all true.
The correct statements about the potential due to this conducting sphere are:The potential at the center of the sphere is zero, The potential at the surface of the sphere is the same as the potential at infinity,The potential is lowest at the center of the sphere.
When a charged particle moves in an electric field, the field exerts a force that can do work on the particle. The work can be expressed in terms of electric potential energy. Electric potential energy depends only on the position of the charged particle in the electric field.
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at time t 0, the velocity is (4.00 m/s)i. what are the (a) magni- ilw tude and (b) angle of its velocity when it has been displaced by 12.0 m parallel to the x axis? a moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration .
Answers
(a) magnitude of the final velocity is 11.94 m/s, and the (b) angle of the final velocity with respect to the positive x-axis is 37.1°.
We can tackle this issue utilizing kinematic conditions. Since the speed increase is consistent, we can utilize the accompanying conditions:
v = u + at
s = ut + 1/2 [tex]at^2[/tex]
[tex]v^2 = u^2[/tex] + 2as
where u is the underlying speed, v is the last speed, t is the time, s is the dislodging, and an is the speed increase.
Given: u = 4.00 m/s I, a = 5.00[tex]m/s^2[/tex] I + 7.00 [tex]m/s^2[/tex] j, s = 12.0 m lined up with the x-pivot.
Utilizing the second kinematic condition, we can address for the time taken to venture to every part of the distance:
s = ut + 1/2 [tex]at^2[/tex]
12.0 = 4.00t + 1/2 (5.00)[tex]t^2[/tex]
5.00[tex]t^2[/tex] + 4.00t - 12.0 = 0
Settling for t utilizing the quadratic recipe, we get:
t = 1.09 s (taking the positive root)
Utilizing the first kinematic condition, we can tackle for the last speed in the x-course:
v_x = u_x + a_x t
v_x = 4.00 + 5.00(1.09)
v_x = 9.45 m/s
Utilizing the Pythagorean hypothesis, we can track down the greatness of the last speed:
|v| = sqrt([tex]v_x^2 + v_y^2[/tex])
|v| = sqrt(([tex]9.45)^2[/tex] + ([tex]7.00)^2[/tex])
|v| = 11.94 m/s
Utilizing the reverse digression capability, we can track down the point of the last speed regarding the positive x-hub:
θ = [tex]tan^(- 1)[/tex](v_y/v_x)
θ = [tex]tan^(- 1)[/tex](7.00/9.45)
θ = 37.1°
Thusly, the (a) magnitude of the last speed is 11.94 m/s, and the (b) angle of its velocity as for the positive x-pivot is 37.1°.
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The complete question is:
A moderate wind accelerates a pebble over a horizontal xy plane with a constant acceleration
a=(5.00m/s 2) i^+(7.00m/s 2) j^ .
At time t=0, the velocity is (4.00m/s) i ^.What are the (a) magnitude and (b) angle of its velocity when it has been displaced by 12.0m parallel to the x axis?
based on the first law of thermodynamics, select all of the following that apply to energy. multiple select question. energy can be destroyed. energy can be transformed. energy can be transferred. energy can be created.
Answers
According to the first law of thermodynamics, energy can be changed and transmitted, as well as the following.
What is subject to the first law of thermodynamics?The first law of thermodynamics establishes a relationship between the different types of kinetic and potential energy present in a system and the work that can be done by it as well as the transmission of heat. This law provides an extra state variable, enthalpy, and is occasionally used as the definition of internal energy.
How does the energy described by the first law of thermodynamics change?The universe's energy is constant, according to the first law of thermodynamics. It cannot be created or destroyed, but it can be exchanged between the system and its surroundings.
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the moon is decreasing in light between a full moon and a last quarter moon called___
Answers
The moon is decreasing in light between a full moon and a last quarter moon called the waning phase.
What is waning phase?
The waning phase is the third phase of the four phases of the moon. It takes place when the moon is visible in the night sky and its shape appears to be decreasing in size. During the waning phase, the moon is moving away from the Earth and its illuminated side is decreasing. This phase begins when the moon is a full moon and gradually decreases in size until it reaches new moon. During the waning phase, the moon is visible in the night sky during the evening hours and is visible as a thin crescent. This phase is also known as the "waning gibbous phase" or the "last quarter phase". During the waning phase, the moon is gradually getting darker and less illuminated until it reaches the new moon phase.
Therefore, The moon is decreasing in light between a full moon and a last quarter moon called the waning phase.
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knowing that the tension in cable ab is 155 lb and that the resultant of the load p and of the forces exerted at a by the two cables must be directed along oa, determine the magnitude of the load p.
Answers
Magnitude of the load p, the resultant of the load p and of the forces exerted at a by the two cables must be directed along is 16.22 lb.
In engineering, the word "load" is widely used to refer to the force applied to a surface or mass.
Tab = 155 lb
Tab = Tab λ ab
= 155 x (-48)i + 29j + 24k/61
Tab = (-121.92)i + 73.66j + 60.96 k
Tac = Tac λac
= -48/65Tac i + 25/65Tac j - 36/65Tac k
For resultant to be directed along OA i.e x-axis
Tac = 110.06 lb
R = (-121.92lb i + 73.66lb j + 60.96lb k) + [-48/65Tac i + 25/65Tac j - 36/65Tac k]
To find the magnitude of P we take only J variable
73.66 + 25/65 Tac - P = 0
P = 73.66 + 25/65(110.66)
P = 16.22 lb is the magnitude of the load.
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what would the minimum value of the coefficient of static friction need to be for the system not to move when released from rest?
Answers
The minimum value of the coefficient of static friction necessary for the system not to move when released from rest would be 2 (10 N / 5 N = 2).
What is static friction?Static friction is the force that resists movement between two surfaces that are in contact with each other. It is the friction that acts to prevent movement between two objects, such as a car and the road, from taking place. This force is always present regardless of the objects’ motion and is perpendicular to the surfaces in contact. It is also known as stiction, sticky friction, limiting friction, or static coefficient of friction.
In order for an object to remain at rest when released from rest, the static friction force must be equal to or greater than the force of gravity acting on the object. Therefore, the minimum value of the coefficient of static friction necessary for the system not to move when released from rest is equal to the ratio of the force of gravity to the normal force between the two surfaces. This ratio is known as the static friction coefficient.
For example, if the force of gravity is 10 N and the normal force between the two surfaces is 5 N, the minimum value of the coefficient of static friction necessary for the system not to move when released from rest would be 2 (10 N / 5 N = 2).
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a 30.0-kg child sits on one end of a long uniform beam with a mass 20.0 kg and a 40.0-kg child sits on the other end. the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child. how long is the beam? 1.93 m 2.07 m 2.20 m 1.98 m 2.12 m
Answers
The length of beam such that the beam balances when a fulcrum is placed below the beam a distance 1.10 m from the 30.0-kg child is 2.07m
To calculate this, we can use the equation for moment of inertia:
We know that the M = (m1 × d1) + (m2 × d2)
Where m1 and m2 are the masses of the two children and d1 and d2 are the distances from the fulcrum to either child.
In this case, m1 = 30.0 kg, m2 = 40.0 kg, d1 = 1.10 m and d2 is the variable we are solving for.
So, we can rearrange the equation to solve for d2:
d2 = (M - (m1 × d1)) / m2
d2 = (0 - (30.0 kg × 1.10 m)) / 40.0 kg
d2 = -2.07 m
Therefore, the length of the beam is 2.07 m.
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a bicyclist makes a trip that consists of three parts, each in the same direction (due north) along a straight road. during the first part, she rides for 27.5 minutes at an average speed of 8.16 m/s. during the second part, she rides for 38.7 minutes at an average speed of 4.66 m/s. finally, during the third part, she rides for 13.6 minutes at an average speed of 14.3 m/s. (a) how far has the bicyclist traveled during the entire trip? (b) what is the average speed of the bicyclist for the trip?
Answers
(a) 1543.42 m far has the bicyclist traveled during the entire trip. (b) 1160.13 m/h is the average speed of the bicyclist for the trip.
a. To find the distance traveled by the bicyclist during the entire trip, we need to find the distance traveled in each part and add them up.
The distance traveled during the first part can be calculated using the formula:-
[tex]distance = speed * time[/tex]
= distance
= [tex]8.16 m/s * 27.5 minutes * (1 minute / 60 seconds)[/tex]
= 559.52 m
The distance traveled during the second part can be calculated using the formula:-
[tex]distance = speed * time[/tex]
= distance
= [tex]4.66 m/s * 38.7 minutes * (1 minute / 60 seconds)[/tex]
= 366.06 m
The distance traveled during the third part can be calculated using the formula:-
[tex]distance = speed * time[/tex]
= distance
= [tex]14.3 m/s * 13.6 minutes * (1 minute / 60 seconds)[/tex]
= 617.84 m
Adding up all the distances traveled in each part gives us the total distance traveled by the bicyclist during the entire trip:
=> total distance
= [tex]559.52 m + 366.06 m + 617.84 m[/tex]
= 1543.42 m
(b) To find the average speed of the bicyclist for the trip, we need to find the total time taken for the trip and the total distance traveled.
The total time taken for the trip can be found by adding up the time taken in each part:-
=> total time
= [tex]27.5 minutes + 38.7 minutes + 13.6 minutes[/tex]
= 79.8 minutes
=> total time
= [tex]79.8 minutes * (1 minute / 60 seconds)[/tex]
= 1.33 hours
The average speed of the bicyclist for the trip can be calculated using the formula:-
[tex]average speed = total distance / total time[/tex]
= average speed
= [tex]1543.42 m / 1.33 hours[/tex]
= 1160.13 m/h
The average speed of the bicyclist for the trip is 1160.13 m/h.
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the nearest star is at a distance of 4.4 light-years. given that light travels at 300,000 km/s in space, how far away is the nearest star in kilometers (km)? (1 year
Answers
The nearest star is approximately 40.1 trillion kilometers away from us.
The nearest star is located 4.4 light-years away from us. Since one light-year is defined as the distance that light travels in one year and light travels at a speed of 300,000 km/s.
we can calculate the distance to the nearest star in kilometers by multiplying the speed of light by the number of seconds in a year and then multiplying by 4.4:
Distance to nearest star = 300,000 km/s * 60 seconds/minute * 60 minutes/hour * 24 hours/day * 365 days/year * 4.4 years
= 40,152,000,000,000 kilometers
Therefore, the nearest star is approximately 40.1 trillion kilometers away from us.
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a player catches a ball. consider the action force to be the impact of the ball against the player's glove. the reaction to this force is the friction of the ground against the player's shoes. player's grip on the glove. force the glove exerts on the ball. muscular effort in the player's arms. none of these
Answers
The reaction to this force is force the glove exerts on the ball.
When a player catches the ball, what kind of force is this?
Frictional force allows the ball to stay in the hand while muscular force is employed to stop the motion of the ball during catching.
First, second, and third laws of motion of Newton :According to the first law, until a force acts on an item, it will not alter its motion. According to the second law, an object's force is determined by multiplying its mass by its acceleration. According to the third law, when two objects interact, they exert equal-sized and opposite-direction pressures upon one another.
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two oppositely-charged plates are set up in the lab, where the positive plate is placed north of the other plate. in which direction would the electric field lines between the plates be pointing of a diagram was drawn?
Answers
Answer:
Explanation:
4. How many Grand Slam tournaments are there in professional tennis each year?
O A. 20
OB. 10
OC.2
O D.4
Answers
There are four Grand Slam tournaments in professional tennis each year: the Australian Open, the French Open, Wimbledon, and the US Open.
option D.
How many Grand Slam tournaments?
The Grand Slam tournaments are the most prestigious events in professional tennis and are held annually.
The four tournaments that make up the Grand Slam are;
the Australian Open, held in Melbourne in January; the French Open, also known as Roland-Garros, held in Paris in May and June; Wimbledon, held in London in June and July; and the US Open, held in New York in August and September.These four tournaments are considered the most prestigious events in the sport and are held annually.
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7. a charge of 4.2c is placed at each corner of a square 0.100m on a side. determine the magnitude of the force on each charge.
Answers
The magnitude of the force on each charge is approximately 3.16 × 10^-15 N.
What is magnitude of the force?
The magnitude of the force is a measure of the strength of the force between two charged objects. In this case, we have four charged objects arranged in a square, and we want to find the magnitude of the force acting on each of these objects. The magnitude of the force is given by Coulomb's law, which depends on the charges of the objects and the distance between them. In this problem, we assume that the charges are point charges and the square is a plane, and use Coulomb's law to calculate the magnitude of the force between two opposite charges. The magnitude of the force on each charge is then determined by adding up the forces due to the other three charges. The result is a numerical value that tells how strong the force is on each charge, but it does not tell us the direction of the force.
Assuming that the charges are point charges and the square is a plane, the magnitude of the force between two point charges can be calculated using Coulomb's law:
F = (k * q1 * q2) / r^2
where F is the force between the charges, k is Coulomb's constant
(9 × 10^9 N·m^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.
In this case, each corner of the square has a charge of 4.2c, where c is the elementary charge (1.602 × 10^-19 C). So, the charges are:
q1 = q2 = q3 = q4 = 4.2c = 4.2 * 1.602 × 10^-19 C
= 6.7244 × 10^-19 C
The force on one of the charges is the vector sum of the forces due to the other three charges. Since the square is symmetric, the direction of the force will be along the diagonals of the square. The distance between two opposite corners of the square is:
r = √2 * 0.100 m
= 0.1414 m
Using Coulomb's law, the magnitude of the force between two charges is:
F = (k * q1 * q2) / r^2 = (9 × 10^9 N·m^2/C^2) * (6.7244 × 10^-19 C)^2 / (0.1414 m)^2
≈ 1.58 × 10^-15 N
Therefore, the magnitude of the force on each charge is:
F total = 2 * F = 2 * 1.58 × 10^-15 N
≈ 3.16 × 10^-15 N
Note that the direction of the force on each charge is along the diagonal of the square, so it has both x and y components. The x and y components of the force cancel out for two opposite charges, but they add up for adjacent charges.
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i] Observe the following picture and answer the given question which evidence of evolution is shown in above picture? what does this evidence indicate? give one more example of evidence of evolution.
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The evolution that is shown in the picture that we have here is the evolution of humans from Chimpanzees.
What is evolution?
Evolution is the process by which species of living organisms change over generations through a combination of genetic variation, mutation, natural selection, and genetic drift. The theory of evolution explains how species have changed over time to become the diverse forms that exist today, and provides a scientific explanation for the relatedness of different species.
The evidence in the picture tells us that came to be through mutations and generic drift from the Chimpanzee.
An example of evolution would be: evidence that is gotten from fossils.
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Calculate the weight of an object of mass 15Kg kept on the earth. If the same object is taken to mars, what change will happen to its mass and weight?(freefall acceleration on mars=3.7 m/s2)
Answers
Answer:
Weight on Mars = 55.5 Newtons
Approximately 37.72% of weight on earth
Explanation:
Mass of an object is unchanged throughout the universe
Therefore mass on Mars = mass on Earth = 15kg
Weight = mass x freefall acceleration
Weight on Earth = 15 kg x 9.81 m/s² = 147.15 Newtons (N)
Weight on Mars = 15 x 3.7 m/s² = 55.5 N
Therefore weight on Mars/ weight on earth = 55.5 N/147.15N
≈ 0.3772
= 37.72 % of weight on earth
observe the velocities of the waves on graph fig,ure 2.4. which one travels faster? group of answer choices
Answers
The P wave, or main wave, is the initial type of body wave. It is the kind of seismic wave that moves most quickly and shows up first at a seismic station. Both fluids like water and the liquid layers of the Earth can conduct P waves, as can solidly rock.
What are the P waves and S wave?Due to the way P-waves distort the material they are passing through and the restoring forces of that material, P-waves will always move more quickly than S-waves. It's crucial to comprehend that S-waves cannot pass through liquids.
P waves leave the earthquake first and go the furthest. The oscillation of rock occurs in shear or S waves that are parallel to the direction of wave propagations waves always follow P waves in a rock environment and normally flow at a speed of about 60% that of the latter.
Therefore, P Waves ravels faster.
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what is the length l of the pipe? an air-filled pipe is found to have successive harmonics at 480 hz , 800 hz , and 1120 hz . it is unknown whether harmonics below 480 hz and above 1120 hz exist in the pipe. what is the length of the pipe?
Answers
Using the formula for the frequency of harmonics in an air-filled pipe, we can write:f_n = nv/(2L), where the pipe's length L, the air's sound speed (v), and harmonic number (n) are all variables.
What can be determined about the length of the pipe?Solving for L, we get:L = nv/(2f_n)For the third harmonic (n=3), we have:L = (3v)/(2f_3) = (3343 m/s)/(21120 Hz) = 0.137 m or 13.7 cm.
Using the given harmonic frequencies, we can determine the length of the pipe by applying the formula: wavelength = speed of sound / frequency.
From this, we can calculate the wavelengths of each harmonic and determine the ratio of their wavelengths. The ratio of the wavelengths will be in the form of 1:3:5 for the 1st, 2nd and 3rd harmonics respectively.
We can then use this ratio to determine the length of the pipe using the formula: length = wavelength x (n/2), where n is the harmonic number.
Therefore, the length of the pipe is approximately 13.7 cm. Using the given harmonic frequencies,
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a student does an experiment to check the mass of a cart. the student sends a 1.0-kg cart with a spring attached at the front end into a collision with a cart of unknown mass. after the collision, the student notes that the 1.0-kg cart moves forward with reduced speed, and the unknown cart moves forward at a faster speed than the 1.0-kg cart. what does this experiment show about the mass of the unknown cart?
Answers
In this experiment, the mass of the unknown cart is less than 1 kg. Thus, c is the correct option.
Acceleration is the change in velocity with respect to time. The speed of the cart and the amount of time it needs to accelerate down the plane are two crucial factors.
Keep in mind that the acceleration increases as the height of the slanted plane increases. This demonstrates how crucial it is to understand the inclined plane's height.The necessity of the timer is based on the fact that we also need to know how long it takes the body to decelerate from the aircraft.
Mass is a quantitative measurement of inertia, it is a basic characteristic of all matter. It basically refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
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The correct question is:
A student does an experiment to check the mass of a cart. the student sends a 1.0-kg cart with a spring attached at the front end into a collision with a cart of unknown mass. after the collision, the student notes that the 1.0-kg cart moves forward with reduced speed, and the unknown cart moves forward at a faster speed than the 1.0-kg cart. what does this experiment show about the mass of the unknown cart?
a) the unknown cart is more than 1 kg
b) the unknown cart is 1 kg
c) the unknown cart is less than 1 kg
d) no information about the mass of the unknown cart can be obtained from this experiment.
A power line consists of two wires, each carrying a current of 400 A in the same direction. The lines are perpendicular to the earth’s magnetic field and are separated by a distance of 5. 0 m. Which is larger: the force of the earth’s magnetic field on each wire, or the magnetic force between the wires?
Answers
The magnetic force between the two wires is larger than the force of the Earth's magnetic field on each wire.
The magnetic force between the two wires is larger than the force of the Earth's magnetic field on each wire. The magnetic force between the two wires can be calculated using the formula
F = μ * I1 * I2 * L / 2 * d
here,
μ is magnetic constant
I1 and I2 are current of each wire,
L is length of each wire,
d is distance between the wires.
Reserving the values,
= F
= [tex]4 * \pi * 10^-^7 * 400 * 400 * 5 / 2 * 5[/tex]
= 0.16 N.
On the other hand, the force of the Earth's magnetic field on each wire can be calculated using the formula:-
F = μ * B * I * L,
here,
B is Earth's magnetic field strength.
Reserving the values,
= F
= [tex]4 * \pi * 10^-^7 * 5 * 10^-^5 * 400 * 5[/tex]
= 0.04 N.
Therefore, the magnetic force between the two wires is larger than the force of the Earth's magnetic field on each wire.
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when you whirl a can overhead by a string in a circular path, what is the direction of the force exerted on the can?A. force is toward the center of the circle.B. in an inward directionC. in an outward directionD. in either an inward or outward
Answers
When you whirl a can overhead by a string in a circular path, the direction of the force exerted on the can is toward the center of the circle. Option A is correct.
This force is called the centripetal force and is required to keep the can moving in a circular path. The centripetal force acts in the direction that is perpendicular to the velocity of the can and points toward the center of the circle.
Without the centripetal force, the can would move in a straight line tangent to the circular path. The magnitude of the centripetal force required to keep the can moving in the circular path depends on the mass of the can, the speed of its motion, and the radius of the circle.
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Transcribed image text: 26) Light enters glass from air. The angle of refraction will be A) greater than the angle of incidence. B) equal to the angle of incidence. C) less than the angle of incidence. Answer: C 27) Water waves pass by a piece of cork floating on the water that bobs up and down on complete cycle each second. The waves are 2 meters long. What is the speed of the wave? A) 0.25 m/s B) 0.50 m/s C) 1.0 m/s D) 4 m/s E) 2 m/s 28) What kinds of waves can show interference? A) Only longitudinal waves show interference. B) Only waves that are out of phase with each other show interference. C) All waves show interference. D) Only transverse waves show interference. 29) If the index of refraction of a material is 2, this means that light travels A) 2 times as fast in air as it does in vacuum. B) 2 times as fast in the material as it does in air. C) 2 times as fast in vacuum as it does in the material. D) 2 times as fast in the material than it does in vacuum. E) 1/2 as fast in air as it does in the material. 30) Light having a speed in vacuum of 3.0 x 108 m/s enters a liquid of refractive index 2.0. In this liquid, its speed will be A) 6.0 × 108 m/s B) 3.0 × 108 m/s C) 1.5 × 108 m/s D) 0.75 x 108 m/s E) 0.67 × 108 m/s
Answers
(1) C) less than the angle of incidence. (2) C) 1.0 m/s (3) C) All waves show interference. (4) B) 2 times as fast in the material as it does in air. (5) D) 0.75 x 108 m/s
1. When light travels from a less dense medium (air) to a more dense medium (glass), it bends towards the normal. This causes the angle of refraction to be less than the angle of incidence.
2. The formula for the speed of a wave is v = fλ, where v is the speed, f is the frequency, and λ is the wavelength. The frequency is 1 cycle per second, and wavelength is 2 meters. The speed of the wave is v = 1 Hz x 2 m = 2 m/s.
3. Interference occurs when two or more waves meet and their amplitudes add together. This can occur with any type of wave.
4. The index of refraction of a material is the ratio of the speed of light in a vacuum to the speed of light in that material. If the index of refraction of a material is 2, this means that light travels 2 times as fast in a vacuum as it does in the material.
5. The speed of light in a medium is given by v = c/n, where v is the speed of light in the medium, c is the speed of light in a vacuum, and n is the refractive index of the medium. Substituting the given values, v = (3.0 x 10^8 m/s) / 2.0 = 1.5 x 10^8 m/s.
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--The complete question is, 1) Light enters glass from air. The angle of refraction will be
A) greater than the angle of incidence.
B) equal to the angle of incidence.
C) less than the angle of incidence.
2) Water waves pass by a piece of cork floating on the water that bobs up and down on complete cycle each second. The waves are 2 meters long. What is the speed of the wave?
A) 0.25 m/s
B) 0.50 m/s
C) 1.0 m/s
D) 4 m/s
E) 2 m/s
3) What kinds of waves can show interference?
A) Only longitudinal waves show interference.
B) Only waves that are out of phase with each other show interference.
C) All waves show interference.
D) Only transverse waves show interference.
4) If the index of refraction of a material is 2, this means that light travels
A) 2 times as fast in air as it does in vacuum.
B) 2 times as fast in the material as it does in air.
C) 2 times as fast in vacuum as it does in the material.
D) 2 times as fast in the material than it does in vacuum.
E) 1/2 as fast in air as it does in the material.
5) Light having a speed in vacuum of 3.0 x 108 m/s enters a liquid of refractive index 2.0. In this liquid, its speed will be
A) 6.0 × 108 m/s
B) 3.0 × 108 m/s
C) 1.5 × 108 m/s
D) 0.75 x 108 m/s
E) 0.67 × 108 m/s--
What kind of motion does a torque tend to impart to an object?
Answers
A torque tends to impart rotational motion to an object and is responsible for keeping the object in rotation.
Torque in rotational motion is the same as force in linear motion. It is the main factor that maintains an object's rotation. An object rotates at an acceleration inversely proportional to its moment of inertia when a torque is applied to it. Torque is mathematically determined by:
Γ= Ia
where, I is the moment of inertia and a is the acceleration with which the object rotates. Torque has both magnitude and direction and is, thus, a vector quantity. Torque is expressed in Newton metre or Nm.
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