In first case speed of fish will be ⅚ m/s.
In the second case the speed of fish ⅙ m/s
Given data :-
Mass of bigger fish ( m₁ ) = 5 kg
Mass of small fish ( m₂ ) = 1 kg.
Speed of large fish ( v₁ ) = 1 m/s
Mass of bigger fish after eating smaller ones = 5 + 1 = 6 kg.
Case - 1
Momentum of bigger fish before eating the smaller fish = m₁* v₁ = 5 * 1 = 5 kg.m/s
Momentum of bigger fish after eating the larger fish = ( m₁ + m₂)*v
v = speed of bigger fish immediately after lunch.
Using the conservation of momentum.
m₁* v₁ = ( m₁ + m₂)*v
5 = 6 * v
v = m/s.
Case -2
Speed of small fish = 4 m/s
Momentum of bigger fish before lunch = 5 kg.m/s
Momentum of smaller fish before lunch = 4*1 = 4 kg.m/s
Net momentum before lunch = 5 - 4 = 1 kg.m/s
Momentum of bigger fish after eating the larger fish = 6 * V
Using the conservation of momentum.
1 = 6 * V
V = m/s.
What is conservation of momentum?
This indicates that a conserved quantity is represented by a variable in an equation that is constant over time. Its value is the same whether an event occurs before or after it.In physics, there are a lot of conserved quantities. For making forecasts in what would otherwise be exceedingly complex situations, they are frequently remarkably useful. There are three fundamental quantities in mechanics that are conserved. These include angular momentum, momentum, and energy. Most often, collisions between objects are described using the principle of conservation of momentum.To know more about conservation of momentum, click the link given below:
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A motorcycle moves according to the velocity-versus-time graph shown in the figure
Find the average acceleration of the motorcycle during segment A of the motion.
(part a)
Find the average acceleration of the motorcycle during segment B of the motion.
(part b)
Find the average acceleration of the motorcycle during segment C of the motion.
(part c)
Average acceleration A = 2 m/s² Average acceleration B = 0 m/s² Average acceleration C = -0.5 m/s²
What is acceleration?The rate of change in velocity over time is called acceleration. The unit of measurement for this vector quantity is meters per second squared (m/s²). Acceleration can be either positive (speeding up) or negative (speeding down). It can also be referred to in terms of direction, such as acceleration to the left or right.
a) V=10m/s
u=0m/s
t= 5 second
a = (v-u)/t
= (10-0)/5
= 2 m/s²
b) The body moves with constant velocity 10m/s , so acceleration is 0m/s
c The velocity is falling , so the body is,
a= (v-u)/t= (5-10)/10
= -5/10
= -0.5 m/s²
Therefore, the Average acceleration of A, B and C are 2 m/s², 0m/s and -0.5 m/s²
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A school bus moves down a road dropping off students after school. The bus slows down from a speed of 15 meters per second (m/s) to a full stop over a distance of 55meters (m) in 11 seconds (s). What is the average speed of the school bus while the bus is slowing down?.
The average speed of the school bus while the bus is slowing down is 5m/s.
Initial velocity, u = 15 m/s.
Distance traveled, d = 55 m.
Time is taken, t = 11 s.
Final velocity, v = 0 m/s.
We know, average velocity is given by :
[tex]v_a_v_g= \frac{distance}{time} = \frac{55}{11} = 5m/s[/tex]
Therefore, the average velocity is 5 m/s.
The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.
In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.
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The experiment began by placing a white rat in front of the infant, who initially had no fear of the animal. watson then produced a loud sound by striking a steel bar with a hammer every time little albert was presented with the rat. after several pairings (the noise and the presentation of the white rat), the boy began to cry and exhibit signs of fear every time the rat appeared in the room. also afraid of similar objects, including other furry animals. watson also created similar conditioned reflexes with other common animals and objects (rabbits, santa beard, etc.) until albert feared them all.
The Little Albert experiment is controversial and ethically questionable by today's standards, as it involved intentionally inducing fear in a child and potentially causing lasting psychological harm
The experiment you are describing is known as the "Little Albert" experiment and was conducted by John B. Watson and his graduate student Rosalie Rayner in 1920. The purpose of the experiment was to demonstrate the principles of classical conditioning, which is a type of learning where an individual learns to associate a neutral stimulus with a meaningful stimulus and responds accordingly.
In the case of Little Albert, the white rat was initially a neutral stimulus that did not elicit any fear or emotional response from him. However, when Watson and Rayner paired the presentation of the rat with a loud, startling noise (the unconditioned stimulus), Little Albert began to associate the two stimuli and developed a fear response (the conditioned response) to the rat alone (the conditioned stimulus).
Watson and Rayner then went on to demonstrate that Little Albert's fear response had generalized to other similar stimuli, such as other furry animals and even a Santa Claus mask. This demonstrated the idea of stimulus generalization, where a conditioned response can be elicited by stimuli that are similar to the original conditioned stimulus.
The true identity of Little Albert was never definitively established, and it is not known what became of him after the experiment.
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A toy car of mass 50g travels down a smooth incline at 30 degrees to
the horizontal. Calculate:
(a) The net force acting on the car as it rolls down the slope, and
(b) The force of the incline on the car as it travels down the slope.
The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.
What is Force?a) F = mg sin θ.
F = 50 * 10−3 9.8 * 1/2
= 0.245 N
If the slope is 30 degrees, the top corner will be 90 30 degrees, and the normal to the vertical force will also be 90 60 degrees, thus we will use mg cos 30 perpendicular to the slope.
b) FN = mg cos θ
= m × g × cos θ
= 50 × 10−3 × 9.8 × cos 30
= 0.43N
Therefore, The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.
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Consider a block of mass 6 kg on a rough plane inclined at 25° to the horizontal A force, F of magnitude 37,173 N is applied to this block to keep it moving at a constant velocity 3.2 6 kg 25° Define a normal force. Draw a force diagram showing ALL the forces acting on this block Calculate the: 3.3.1 component of the weight that is parallel to the inclined plane. 3.3.2 magnitude of the normal force. 3.3.3 magnitude of the frictional force. ▸
Answer:
To calculate the forces acting on the block, we can use the following steps:
Draw a force diagram showing all the forces acting on the block. The forces acting on the block are:
Weight (W), which acts vertically downward with a magnitude of W = m * g, where m is the mass of the block and g is the acceleration due to gravity (g = 9.8 m/s^2)
Normal force (N), which acts vertically upward to balance the weight and prevent the block from sinking into the surface of the plane
Frictional force (f), which acts parallel to the plane in the direction opposite to the motion of the block
Applied force (F), which acts parallel to the plane in the direction of the motion of the block
Calculate the component of the weight that is parallel to the inclined plane. The weight can be resolved into two components, one perpendicular to the plane (Wcosθ) and one parallel to the plane (Wsinθ).
Wcosθ = W * cos(25°) = (6 kg) * (9.8 m/s^2) * cos(25°) = 50.18 N
Wsinθ = W * sin(25°) = (6 kg) * (9.8 m/s^2) * sin(25°) = 59.16 N
Calculate the magnitude of the normal force. The normal force is equal to the component of the weight that is perpendicular to the plane.
N = Wcosθ = 50.18 N
Calculate the magnitude of the frictional force. The frictional force is equal to the magnitude of the applied force minus the component of the weight that is parallel to the plane.
f = |F - Wsinθ| = |37173 N - 59.16 N| = 37113.84 N
Note that the frictional force opposes the motion of the block and its magnitude is limited by the maximum static friction force, which is given by fmax = μN, where μ is the coefficient of friction between the block and the plane. In this case, since the block is moving at a constant velocity, the frictional force must be equal to the applied force, so that f = 37173 N and μ can be calculated as μ = f / N = 37173 N / 50.18 N = 739.
Explanation:
Which of the following statements concerning momentum is true?
Which of the following statements concerning momentum is true?
*
A.) Momentum is a scalar quantity.
B.)The momentum of an object is always positive.
C.)Momentum is a force.
D.) Momentum is a vector
E.)The SI unit of momentum is the Newton.
The statement that is true about momentum is as follows: Momentum is a vector (option D).
What is momentum?Momentum is the tendency of a body to maintain its inertial motion. It is the product of its mass and velocity, or the vector sum of the products of its masses and velocities.
Momentum is a vector quantity i.e. it has both magnitude and direction.
Since momentum is a product of mass and velocity, it's S.I unit is kgm/s or N/s.
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Momentum is that momentum is a vector quantity. Therefore, the answer is option D.Momentum is a property of objects that are moving, that is, an object's tendency to stay in motion. Momentum is a measure of an object's motion or its inertia in motion.
An object's momentum is calculated as the product of its mass and its velocity, with the direction of momentum being the same as the direction of velocity.Vector and scalar quantitiesMomentum is a vector quantity because it has both magnitude and direction. A scalar quantity, on the other hand, is a quantity that has only magnitude and no direction.
For example, speed is a scalar quantity because it is defined as distance divided by time and has only magnitude (no direction).In physics, there are two types of quantities: vector quantities and scalar quantities. A vector quantity is a quantity that has both magnitude and direction, whereas a scalar quantity is a quantity that has only magnitude.
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You are fixing the roof of your house when a hammer breaks loose and slides down. The roof makes an angle of 45 ∘ with the horizontal, and the hammer is moving at 4.5 m/s when it reaches the edge. Assume that the hammer is moving from the top of the roof to its right edge.
1. What is the vertical component of the hammer's velocity just as it leaves the roof?
The hammer travels at 3.9 m/s in its horizontal direction. The roof is at an angle with the horizontal when the hammer is dropped from a height of v along it.
Describe a velocity example.The speed with which something travels in a specific direction is known as its velocity. As an illustration, think of the movement of a car driving north on either a highway or the speed at which a rocket takes off.
When does acceleration differ from velocity?The change in displacement is measured in terms of velocity. The speed of change in velocity is known as acceleration. Given that it has both a magnitude and a direction, mass and velocity quantity. Being merely the change in frequency, accelerating is also an vector quantity.
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Wrongly called for a foul, an angry basketball player throws the ball straight down to the floor.
If the ball bounces straight up and returns to the floor 2.9 s after first striking it, what was the ball's greatest height above the floor?
The ball had a maximum height that was 3.0 meters lower than its initial height (h₀).
How can you determine the ball's greatest height?Before being thrown down, let's call the ball's initial height h0. The ball's height after it was thrown down and bounced back up is called h1.
After being thrown, the ball takes half as long to reach its maximum height (h1) as it does to bounce back to the ground (2.9 s divided by 2 = 1.45 s).
Using the following equation for vertical displacement under gravity's constant acceleration:
y = v₀ × t + (1/2) × a × t²
where:
The initial velocity of the ball, v₀, is negative because it was thrown straight down;
a is the acceleration caused by gravity (9.8 m/s²); and
t is the time it takes for the ball to reach its maximum height (1.45 s).
We can use the equation for velocity under constant acceleration to determine the initial velocity of the ball, v₀ :
v = v₀ + a × t
where:
v is the velocity of the ball at time t (0 m/s since it has reached its maximum height)
Combining the two equations:
0 = v₀ + 9.8 m/s² × 1.45 s
v₀ = -9.8 m/s² × 1.45 s
Substituting the values for v₀ and t into the equation for vertical displacement:
h₁ - h₀ = v₀ × t + (1/2) × a × t²
h₁ - h₀ = (-9.8 m/s² × 1.45 s) × 1.45 s + (1/2) × 9.8 m/s² × (1.45 s)²
h₁ - h₀ = -13.8 m + 10.8 m
h₁ - h₀
= -3.0 m
So, the ball's greatest height above the floor was 3.0 m less than its initial height (h₀).
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The Earth is a sphere with a diameter of about 12,800 kilometers. Scientists believe that the Earth first formed
billion years ago and was larger then than it is now.
The Earth was so hot that all the rock was molten, i.e. in the
state.
We think that about 4.4 billion years ago the Earth had cooled down enough to let a
crust form on the surface.
Answer:
Explanation:
Earth is our home planet. Scientists believe Earth and its moon formed around the same time as the rest of the solar system. They think that was about 4.5 billion years ago. Earth is the fifth-largest planet in the solar system. Its diameter is about 8,000 miles. And Earth is the third-closest planet to the sun. Its average distance from the sun is about 93 million miles. Only Mercury and Venus are closer.
What Are Earth's Different Parts?
Earth consists of land, air, water and life. The land contains mountains, valleys and flat areas. The air is made up of different gases, mainly nitrogen and oxygen. The water includes oceans, lakes, rivers, streams, rain, snow and ice. Life consists of people, animals and plants. There are millions of species, or kinds of life, on Earth. Their sizes range from very tiny to very large.
Below Earth's surface are layers of rock and metal. Temperatures increase with depth, all the way to about 12,000 degrees Fahrenheit at Earth's inner core.
Earth's parts once were seen as largely separate from each other. But now they are viewed together as the "Earth system." Each part connects to and affects each of the other parts. For example:
Clouds in the air drop rain and snow on land.
Water gives life to plants and animals.
Volcanoes on land send gas and dust into the air.
People breathe air and drink water.
Earth system science is the study of interactions between and among Earth's different parts.
A 25kg turkey is fired from a 1.2x10^3 kg turkey launcher. If the horizontal velocity of the turkey is 245m/s east, what is the recoil of the launcher?
A.) 9.38 m/s
B.) 7325 m/s
C.) 4925 m/s
D.) 5.1 m/s
The recoil velocity of the launcher is 5.1 m/s.
option D.
What is the recoil velocity of the launcher?To calculate the recoil velocity of the launcher, we can use the law of conservation of momentum.
According to this law, the total momentum of the system (turkey + launcher) before the launch is equal to the total momentum after the launch.
initial momentum of the turkey = final momentum of the launcher
( 25 kg x 245 m/s ) = 1,200 kg (v)
where;
v is the recoil velocity of the launcherv = ( 6125 kgm/s) / ( 1,200 kg )
v = 5.1 m/s
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Which factors affect the gravitational force between two objects?
distance and velocity
O mass and distance
mass and weight
O acceleration and weight
Answer:
mass and distance
Explanation:
I could explain it but I don't know how to word it xd
Answer:
My best guess is:
B) mass and distance
This is because gravity is affected by the size of objects and the distance between objects.
Explanation:
Hope it helps! =D
Calculate the total work done on a mass m as it moves from position x1 = 0 m to x2 = 40 m
F1 = 5 N F2 = 6 N angle between them 50 degree
F3 = 2 N F4 = 2 N Angle Between them 20 Degree
The total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.
What is Work Done?
Work is a physical quantity that describes the amount of energy transferred when a force acts on an object and causes it to move. When a force acts on an object and causes it to move in the direction of the force, work is said to be done on the object. Mathematically, work is defined as the dot product of force and displacement:
Work = Force x Displacement x cos(theta)
To calculate the total work done on the mass as it moves from position x1 to x2, we need to find the net work done by all the forces on the mass. The net work done by a force is given by the formula:
W = F * d * cos(theta)
where W is the work done, F is the force, d is the displacement of the mass, and theta is the angle between the force and the displacement.
First, we can calculate the work done by each force separately and then add them up to find the total work done.
Work done by F1:
W1 = F1 * (x2 - x1) * cos(0) = 5 N * 40 m * cos(0) = 200 J
Work done by F2:
W2 = F2 * (x2 - x1) * cos(50°) = 6 N * 40 m * cos(50°) ≈ 165.41 J
Work done by F3:
W3 = F3 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J
Work done by F4:
W4 = F4 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J
The total work done on the mass is the sum of the work done by each force:
W_total = W1 + W2 + W3 + W4 ≈ 515.17 J
Therefore, the total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.
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Explain,
A system consists of 55 electrons and 43 protons.
Answer:
a system considered of the elements and why protons
Explanation:
no explantion
In the Millikan oil-drop experiment illustrated in the figure below, an atomizer (a sprayer with a fine nozzle) is used to introduce many tiny droplets of oil between two oppositely charged parallel metal plates. Some of the droplets pick up one or more excess electrons. The charge on the plates is adjusted so that the electric force on the excess electrons exactly balances the weight of the droplet. The idea is to look for a droplet that has the smallest electric force and assume it has only one excess electron. Suppose e are using an electric field of 6.45 104 NC. The charge on one electron is l 60 10-19 С. Calculate the radius of an oil dop , de sty 90aa ml for th h its weight could be balanced by the electric force of this field on one electron Oil droplets Pinhole Light Telesxcope with cale in eyepiece um
The radius of the oil droplet in this experiment is approximately 1.11 x 10^-7 meters.
The Millikan oil-drop experiment was designed to determine the fundamental unit of electrical charge, the charge on a single electron, by observing the behavior of charged oil droplets suspended in an electric field. To calculate the radius of an oil droplet given the electric field strength and the charge on one electron, we can use the following formula:
q = mg / E
where q is the charge on the droplet, m is the mass of the droplet, g is the acceleration due to gravity, and E is the electric field strength.
Assuming that the droplet has only one excess electron and that its weight is balanced by the electric force of the field on that electron, we can write:
q = e
where e is the charge on one electron.
Equating these two expressions for q, we can solve for the mass of the droplet:
mg / E = e
m = eE/g
Next, we can use the density of the oil droplet to calculate its volume and then its radius:
[tex]V = (4/3)πr^3 = m/ρ[/tex]
[tex]r = [(3m/4πρ)]^(1/3)[/tex]
where ρ is the density of the oil.
Substituting in the given values, we get:
[tex]m = eE/g = (1.60 x 10^-19 C)(6.45 x 10^4 N/C)/(9.81 m/s^2) = 1.04 x 10^-14 kg[/tex]
ρ = 0.90 g/cm^3 = 900 kg/m^3
[tex]r = [(3m/4πρ)]^(1/3) = [(3(1.04 x 10^-14)/(4π)(900))]^(1/3) = 1.11 x 10^-7 m[/tex]
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Microevolution three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, natural selection bottleneck effect founder effect population gene pool stabilizing, directional and disruptive selection hardy-weinberg equilibrium five conditions that must be met in order for population to be in hardy-weinberg equilibrium adptive evolution relative fitness sexual selection sexual dimorphism intrasexual selection intersexual selection neutral variation balancing selection heterozygote advantage hardy-weinberg problems
Microevolution refers to the evolution occurring at species-level involves three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, and natural selection.
Changes in the environment can affect population gene pools on both a small- and large-scale. Microevolution is the process of population-level changes in allele frequency. Some alterations take place at the species level or lower. There are hence variations in allele frequencies between or within groups.
Natural selection is one of the mechanisms of microevolution. It serves as an editor for allele frequency in populations to determine whether individuals with particular features have a higher or lower chance of surviving and procreating. Populations' gene pools can occasionally shift as a result of individuals leaving or entering the community. This transfer of alleles between populations is referred to as gene flow. Genes can "flow" from one area to another just like water does in a river.
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If two bowling balls were to collide head on stick to one another, with some loss in kinetic energy, the collision would be considered a(n) ___________ collision.
A.Cushy
B .Perfectly Inelastic
C.Reversable
D.Elastic
Which component in the circuit would most likely have the lowest resistance?
A buzzer
A capacitor
A light bulb
A wire
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
A wire should have the least resistance possible, because if there is more resistance in wires, there would be a lot of power loss when current flows through it.
Therefore, wires should have lowest resistance.
Which is an accurate statement about two objects that have the same average kinetic energy?
Each object has the same amount of potential energy.
Each object has the same mass.
Both objects are made of the same material.
Both objects are at the same temperature.
Answer:
both objects are at the same temperature
Explanation:
kinetic energy is not affected or is independent of temperature
a wheel has angular velocity 4.00 rad/s. which of the following is closest to the number of revolutions that the wheel makes in 15.0 s?
a.10 revolutions
b.20 revolutions
c.15revolutions
d.25 revolutions
e. 5 revolutions
f. i dont know yet
Answer:
10 revolutions
Explanation:
By using the equation Δ=Δ, we get that Δ=(4.00rad/s)(15.0s)=60.0rad. Since there are 2 radians per revolution, this angular displacement corresponds to (60.0rad)/(2rad/rev)=9.55rev.
The angular velocity of the wheel is 4 rad/s and the time interval is 15 s. Then the number of rotations in radians is 60 radians. This is equal to 9.5 revolutions.
What is angular velocity ?Angular velocity is a physical quantity that describes the speed of an object in an angular path. It is the rotational o revolutional analogue of of the linear velocity.
The angular velocity of an object is the product of the linear velocity and the radius of the angular path.
Given that, the angular velocity of the wheel = 4 rad/s
time = 15 s
then, number of radians = 4 rad/s × 15 s = 60 radians.
1 revolution = 2π radians.
then 60 radians = 60/2π = 9.5 revolutions.
Therefore, the number of revolutions for the wheel in 15 s is 9.5 revolutions.
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According to the conservation of momentum, the momentum before a collision should be _______ the momentum after the collision.
A.greater than
B.less than
C.double
D.equal to
Answer:
D. equal to
Explanation:
The law of conservation of momentum states that momentum is conserved, so it would stay the same.
A child is sending pulses down a stretched rope at a rate of 2 pulses per second. The distance between the pulses is 5 meters. What is the speed of the wave?.
The speed of the wave that is propagated is 10 meters per second.
A wave is a disturbance or variation that gradually conducts electricity from point to point in a medium and can take the form of elastic deformation or a change in pressure, electric or magnetic intensity, electric potential, or temperature
The speed of a wave is determined by the frequency of the wave and its wavelength. In this case, the child is sending pulses down the rope at a rate of 2 pulses per second, so the frequency is f = 2 Hz.
The distance between the pulses is 5 meters, which is the wavelength of the wave, represented by lambda (λ).
The speed of the wave (v) is given by the formula:
v = f * λ
Substituting the values we have, we get:
v = 2 Hz * 5 m = 10 m/s
Therefore, the speed of the wave is 10 meters per second.
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You are asked to figure out the size of an air bladder (a balloon that inflate and deflate to change the buoyancy of a profiling float) a profiling float should have to be able to profile from 1000m to the surface should be (at least). To figure it out, you look at profiles of density from the region where you will be deploying the float (see attached figure) and compute the maximum difference in density (=1000+sigma_theta) between 1000m and the surface.
Your float is a perfect cylinder with 20cm in diameter and 1.5m in length. Figure out its volume, Figure out the mass it should have, without inflating the bladder, to match the largest density observed at 1000m, so it can be neutrally buoyant at that depth (neither sinking or floating).
Finally, given the above, how big should the air bladder be (in minimum and in ml=cm^3) to that when inflated the float will be buoyant at the surface for all conditions observed at that region?
The minimum size of the air bladder [tex](in ml=cm^3)[/tex] should be[tex]2*σθ * 706.5 cm^3[/tex] to make sure that when inflated, the float will be buoyant at the surface for all conditions observed at that region.
What is air bladder?An air bladder is a sac-like organ that is filled with air and is found in certain aquatic animals, such as fish, amphibians, and certain invertebrates. It is used for buoyancy control, allowing the animal to adjust its position in the water column.
Volume of perfect cylinder =[tex]πr^2h[/tex]
[tex]= 3.14 * (10cm/2)^2 * 1.5m= 706.5 cm^3[/tex]
Mass of the float at 1000m = Density at 1000m * Volume of the float
[tex]= (1000+σθ)* 706.5 cm^3= (1000+σθ) * 706.5 g[/tex]
Air bladder size (minimum) = Mass of the float at 1000m - Mass of the float at surface
[tex]= (1000+σθ) * 706.5 g - (1000-σθ) * 706.5 g= 2*σθ * 706.5 g= 2*σθ * 706.5 cm^3[/tex]
Therefore, the minimum size of the air bladder (in ml=cm^3) should be [tex]2*σθ * 706.5 cm^3[/tex] to make sure that when inflated, the float will be buoyant at the surface for all conditions observed at that region.
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Two blocks are attached to either end of a light rope that passes over a light, frictionless pulley suspended from the ceiling. One block has mass 8. 00 kg , and the other has mass 6. 00 kg. The blocks are released from rest.
Two blocks are attached to either end of a light rope that passes over a light, the change in gravitational PE is 11.76, -15.68j, 0.2T, -0.2T and speed is 0.7483 m/s.
partA] change in gravitational PE :
U6 = m1gh = 6*9.8*0.2 = 11.76 J
U8 = -m2gh = -8*9.8*0.2 = -15.68 J
ANSWER = 11.76, -15.68
partB] W6 = T*0.2 = 0.2T
W8 = T*-0.2 = -0.2T
answer = 0.2T, -0.2T
partC] WT = 0.2T-0.2T = 0
deltaUg = 11.76-15.68 = -3.92 J
increase in KE = 3.92J
speed v = sqrt(2KE/(m1+m2))= sqrt(2*3.92/14) = 0.7483 m/s
answer = 0,-3.92, 0.7483
The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.
In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.
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How can scientists determine whether an extinct animal gave birth on land or underwater?.
The correct option is C. Position of the head of the fetus of an extinct animal that gave birth on land or underwater.
In human prenatal development, fetal development starts offevolved from the 9th week after fertilization (or eleventh week gestational age) and maintains till birth.
Prenatal improvement is a continuum, with no clear defining characteristic distinguishing an embryo from a fetus. however, a fetus is characterized by the presence of all the most important body organs, though they will now not yet be completely advanced and practical and some not but situated in their very last anatomical vicinity. An unborn offspring develops and grows within the uterus (womb) of humans and different mammals. In human beings, the fetal duration begins at 9 weeks after fertilization of an egg by using sperm and ends at the time of delivery.
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Complete Question:
1. How can scientists determine whether an extinct animal gave birth on land or underwater?
a. Location of the hind limbs of the fetus
b. Position of the nostrils
c. Position of the head of the fetus
d. Location of the fossils
The graph depicts the motion of two objects. Which statement BEST describes the acceleration of the two objects?
Responses
A Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.Acceleration 1 - no acceleration. Acceleration 2 - speeds up and slows down.
B Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - no acceleration. Acceleration 2 - negative acceleration.
C Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.Acceleration 1 - positive acceleration. Acceleration 2 - negative acceleration.
D Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration.
Acceleration 1 - constant acceleration. Acceleration 2 - varied acceleration. The correct option is D.
What is acceleration?Acceleration of any object is defined as the variation in the speed of the object with the variation of time. Acceleration is a vector term and to define it we require both the magnitude and the direction. The unit of acceleration can be m / sec², miles / sec², etc.
In a velocity-time graph, the acceleration corresponds to the slope of the curve.
In fact, acceleration is defined as the ratio between the change in velocity and the time interval:
a = Δv / Δt
However, in a velocity-time graph, corresponds to the y-variable increment (), while corresponds to the x-variable increment (). (). As a result, acceleration can also be expressed as,
a = Δy / Δx
For object 1, the slope is constant: this means that the acceleration is constant.
For object 2, the slope varies: this means that the acceleration varies as well.
The missing graph is attached with the answer below.
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The mechanical energy of a bicycle at the top of a hill is 6000 j. The bicycle stops at the bottom of the hill by applying the brakes. If the gravitational potential energy of the bicycle-earth system is 2000 j at the bottom of the hill, how much mechanical energy was converted into thermal energy?.
Answer:
Explanation: POTENTIAL ENERGY is stored energy, energy ready to go. A race car at the starting line of a race, a bicycle on top of a hill, and students waiting to go home from school are all examples of potential energy.
A moving bicycle has mechanical energy. When you apply the brakes, the bicycle's mechanical energy is not destroyed. The mechanical energy is transformed into thermal energy. Friction between the brake pad of a car and the moving wheel transforms mechanical energy into thermal energy (heat).
During braking, 60% of the kinetic energy of the bicycle and rider is converted to thermal energy in the brake blocks.
An FM radio station broadcasts at 9.23x10^7 Hz. Given that the radio waves travel at 3.00x10^8 m/s, what is the wavelength of these waves?
If a radio station broadcasts at 9.23 x 10⁷Hz and the velocity of the waves is 3 x 10⁸m/s, the wavelength of these waves is 3.25m.
How to find the wavelength of radio waves?According to the question,
Frequency of the FM radio = 9.23 x 10⁷Hz
Velocity of the waves = 3 x 10⁸m/s
The wavelength of the wave =?
To find the wavelength of the wave, we conclude the velocity equation;
Velocity = frequency x wavelength.
Since to find unknown is the wavelength, we have to solve for it:
3 x 10⁸ = 9.23 x 10⁷ x wavelength
wavelength = 3 x 10⁸/ 9.23 x 10⁷
wavelength = 3.25m
Therefore, the wavelength of these waves is 3.25m.
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By changing the current in the wire, you can change the ____ of an electromagnet.
An electromagnet experiences a direct current (DC) voltage that travels from the positive to the negative end of the DC circuit. This produces a magnetic field with a north and south magnetic pole.
What is the impact of polarity on electromagnet?Due to the inverse relationship between the resistance of the circuit and cross-sectional area, the thickness of the wire has an impact on the electromagnet's strength.
if the current increases, more current will flow through the electromagnet. The strength of the electromagnet is so increased by the wire's thickness.
Increasing the current through the wire. The magnetic field is produced by the current that is flowing through the wire. Stronger magnetic fields and, hence, stronger electromagnets result from larger current flow.
Therefore, an electromagnet's polarity can be altered by reversing the flow of electricity through its coil.
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Two equal charges are placed at a separation of 1.0m. What should be the magnitude of the charges so that the force between them equals the weight of a 50 kg person?
The magnitude of the charges must be 1.67 x 10⁻⁵ C in order for the force exerted by them to be comparable to the weight of a 50 kilogram individual.
The force of attraction between two point charges Q1 and Q2 separated by a distance r is given by Coulomb's law:
[tex]F = k * (Q1 * Q2) / r^2[/tex]
here,
k is Coulomb constant, value is [tex]9.0 * 10^9 Nm^2/C^2[/tex].
To find the magnitude of the charges such that the force between them equals the weight of a 50 kg person, we need to set the force equal to the weight of the person:
F = m * g
here,
m is mass of the person and
g is the acceleration gravity, value [tex]9.81 m/s^2[/tex].
Reserving values:-
[tex]m * g = k * (Q1 * Q2) / r^2[/tex]
We know that Q1 and Q2 are equal, so we can write Q1 = Q2 = Q. Reserving equation above:-
[tex]m * g = k * Q^2 / r^2[/tex]
Solving for Q:-
[tex]Q = \sqrt{[(m * g * r^2) / k]}[/tex]
Reserving values:-
[tex]Q = \sqrt{x} \sqrt{[(50 kg * 9.81 m/s^2 * (1.0 m)^2) / (9.0 x 10^9 Nm^2/C^2)]}[/tex]
Simplifying and evaluating:-
[tex]Q = 1.67 * 10^-^5 C[/tex]
Therefore, the magnitude of each of the charges should be approximately [tex]1.67 * 10^-^5 C[/tex].
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Unit 3
The Flow of Energy in Systems
EVIDENCE NOTEBOOK
11. How could the surfaces and structures in an urban area be related to the
urban heat island effect? Record your evidence
Answer:
The surfaces and structures in an urban area can have a significant influence on the urban heat island effect. For example, paved surfaces like roads and buildings absorb more heat than surfaces covered in vegetation, and structures like high-rise buildings can trap and reflect heat, resulting in higher temperatures in the urban area. Additionally, urban areas usually have less vegetation than their rural counterparts, meaning there is less vegetation to absorb heat from the sun and provide shade, further contributing to the urban heat island effect. Evidence of this can be seen in research at louisvilleky.gov/government/sustainability/urban-heat-island-project.
