A 5kg block is resting on the table. Find the normal force acting on the block.

49 N, up
49 N
5 kg, up
49 N, down

In an elevator going down at constant speed. All these forces are acting on us, except option B. a torque.

Torque is the rotational equivalent of a linear force. In some fields of study, it is also called moment, moment of force, rotational force, or rotational effect. It describes the ability of a force to effect a change in the rotational motion of an object.

Torque is the torque that interacts with the torque of the motor and measures how much of that torque is available when the motor is exerting itself. Torque is present in everyday events. B. Turning a doorknob, opening a soda bottle, using a wrench, pedaling a bicycle.

Constant speed means that the velocity does not change at all for each second of movement. The example of driving a car with cruise control shows constant speed. Constant acceleration means that the velocity increases at the same constant rate every second of his.

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According to Pascal, pressure applied to a fluid is transmitted equally in all directions.

P = F / A

P = Pressure

F = Force

A = Area

Pressure is in Pa ( Pascals ).

Force is in N ( Newtons )

Area is in m² ( Meter² )

Pascal's law states that, pressure applied to an incompressible fluid enclosed in a container is transmitted equally throughout the fluid without any change in magnitude.

Therefore, According to Pascal, pressure applied to a fluid is transmitted equally in all directions.

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The falcon take 14 seconds to reach the pigeon.

A mathematical expression that expresses the location, speed, or acceleration of a body in relation to a specified frame of reference is called as Equation of motion,

By using equation of motion

s = [tex]\frac{1}{2}[/tex]g[tex]t^{2}[/tex]

where, s = total distance travelled by an object = 68.6 m

g = acceleration of gravity = 9.8m/[tex]s^{2}[/tex]

t = time taken to travel the distance = ?

Therefore, t = [tex]\sqrt{2s/g}[/tex]

t = [tex]\sqrt{2*68.6/9.8}[/tex]

t = 14 seconds

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The time taken for the new moon to orbit the earth is √8 times the time taken by the present moon.

According to Kepler's third law,

[tex]T_{m} ^{2}[/tex] = ( 4 π / G [tex]m_{E}[/tex] ) r³

[tex]T_{m}[/tex] = Time taken by the moon

G = Gravitational constant

[tex]m_{E}[/tex] = Mass of Earth

r = Radius of moon

r' = 2 r

r' = Radius of new moon

[tex]T'_{m} ^{2}[/tex] = ( 4 π / G [tex]m_{E}[/tex] ) ( 2 r )³

[tex]T'_{m} ^{2}[/tex] = 8 ( 4 π / G [tex]m_{E}[/tex] ) r³

[tex]T'_{m}[/tex] = √8 [tex]T_{m}[/tex]

Kepler's third law states that square of time period of a planet's orbit is equal to the cube of semi-major axis of the orbit.

Therefore, the time taken for the new moon to orbit the earth is √8 times the time taken by the present moon.

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Answer:

5/2m/s^2

Explanation:

Acceleration is change in velocity divided by change in time. You might have seen it written like this:

ΔV/Δt

in this case, your change in velocity is -10m/s and your change in time is 4s thus your acceleration is -5/2m/s^2

The speed of particle 1 with respect to particle 2 which is moving perpendicular to each other at 2.83 s is 20.89 m / s

a = v / t

v = x / t

[tex]a_{1}[/tex] = 3.37 m / s²

[tex]a_{2}[/tex] = 5.18 m / s²

t = 2.83 s

[tex]v_{1}[/tex] = [tex]a_{1}[/tex] * t

[tex]v_{1}[/tex] = 3.37 * 2.83

[tex]v_{1}[/tex] = d[tex]x_{1}[/tex] / dt = 9.54 m / s

[tex]v_{2}[/tex] = [tex]a_{2}[/tex] * t

[tex]v_{2}[/tex] = 5.18 * 2.83

[tex]v_{2}[/tex] = d[tex]x_{2}[/tex] / dt = 14.66 m / s

[tex]x_{1}[/tex] = [tex]v_{1}[/tex] * t

[tex]x_{1}[/tex] = 9.54 * 2.83

[tex]x_{1}[/tex] = 27 m

[tex]x_{2}[/tex] = [tex]v_{2}[/tex] * t

[tex]x_{2}[/tex] = 14.66 * 2.83

[tex]x_{2}[/tex] = 41.49 m

Since they are moving perpendicular to each other, they make a right angled triangle. According to Pythagoras theorem,

[tex]x_{3} ^{2}[/tex] = [tex]x_{1} ^{2}[/tex] + [tex]x_{2} ^{2}[/tex]

On differentiating with respect to t,

2[tex]x_{3}[/tex] d[tex]x_{3}[/tex] / dt = 2[tex]x_{1}[/tex] d[tex]x_{1}[/tex] / dt + 2[tex]x_{2}[/tex] d[tex]x_{2}[/tex] / dt

41.49 ( d[tex]x_{3}[/tex] / dt ) = 27 ( 9.57 ) + 41.49 ( 14.66 )

d[tex]x_{3}[/tex] / dt = ( 258.4 + 608.24 ) / 41.49

d[tex]x_{3}[/tex] / dt = [tex]v_{12}[/tex] = 20.89 m / s

Therefore, the speed of particle 1 with respect to particle 2 at 2.83 s is 20.89 m / s

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Answer:

Explanation:

velocity and position

Answer:

A. Velocity and position

Took the test.

The height of the cliff is 88 m.

The initial velocity of the rock, when it is dropped is V(i) = 0 m/s.

The sum of the time taken by the rock to reach the surface of the ocean from the sea cliff and the time taken by the sound of the splash of the rock to the ears of the person who threw the rock is t = 2.7 s.

The speed of sound in air is V(s) = 340 m/s.

The acceleration due to gravity is g = 10 m/s².

The displacement made by the rock during this period will be as follows if we use the kinematic equation for translational motion under gravity and assume that the time it takes the rock to reach the ocean's surface is t₁ :

d = 0 − h = V(i) × t₁ + (1/2) × (− g ) × ( t₁ )²

Since the positions of the rock are taken from the surface of the ocean.

Substituting the values in the equation.

t₁ = √ [ 2h/g ]

( t₁ )² = 2h / g

Since sound moves through the medium at a constant speed, the following is how long it will take for the sound to reach the rock-thrower:

t₂ = h / V(s)

h = V(s) × t₂

Therefore,

( t₁ )² = ( 2 × V(s) × t₂) / g

Now, since t = t₁ + t₂ , therefore, t₂ = t − t₁ .

( t₁ )² = ( 2 × V(s) × ( t - t₁ ) ) / g

( t₁ )² = 2 × ( 340 ) ×( 4.5 − t₁ ) / 10

( t₁ )² = 306 − 68 t₁

Now,

( t₁ )² - 306 + 68t₁ = 0

By using the quadratic formula,

t₁ = { − 68 ± √ [( 68 )² − 4 × ( 1 ) × ( − 306 )] } / 2 × ( 1 )

t₁ = − 68 ± 76.47 / 2

( t₁ = − 68 + 76.47 / 2 = 4.24 s) and;

( t₁ = − 68 − 76.47 / 2 = − 72.24 s )

Since time can't be negative,

t₁ = 4.24 s.

Therefore,

t₂ = t − t₁

t₂ = 4.5 s − 4.24 s

t₂ = 0.26 s

Now,

h = V(s) × t₂

h = ( 340 m / s ) × ( 0.26 s )

h ≈ 88 m

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The correct answer is 4.14456 mi/hour.

The entire distance that an object travels in a given amount of time is the definition of average speed for that object. You can figure it out by dividing the overall distance traveled by the overall journey time.

When an object travels a distance at a variety of speeds, its average speed is the speed at which, if the object moves uniformly, it will travel the same distance in the same amount of time.

average speed= total distance / total time

total distance = 1 mile

The total time = 2 / ( 3 × 3.5 ) = 0.190 hour

time for coming = 1 / (3 × 6.5 ) = 0.05128 hour

Thus the average speed = 1 / ( 0.190 + 0.05128 ) = 1 / 0.24128 = 4.14456 mi/hour.

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Answer: the time for the car to drive directly south is determined as 7.15 s.

Explanation:

The time for the car to drive directly south is determined by applying the concept of slope.

slope = Δy/Δx

a = Δv/Δt

Δt = Δv/a

Δt = (26.8)/(3.75)

Δt = 7.15 s

Thus, the time for the car to drive directly south is determined as 7.15 s.

Explanation:

An object's position in a given coordinate system is described by the vector r = t2 i - (3t + 3) j. Assume the object moves without air resistance. What is the object's acceleration at t4 = 5 seconds? Write your answer in component form. just use the formula, if you use formula you will know how to do.

The object's acceleration at t = 5 seconds would be 2 meters/second².

The rate of change of the velocity with respect to time is known as the acceleration of the object.

An object's position in a given coordinate system is described by the vector r = t² i - (3t + 3) j,

assuming the object moves without air resistance.

displacement = t² i - (3t + 3) j

velocity = 2t i -3 j

acceleration = 2i

Thus, the object's acceleration at t = 5 seconds would be 2 meters/second².

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O the dependent variable

The independent variable belongs on the x-axis (horizontal line) of the graph and the dependent variable belongs on the y-axis (vertical line).

Hi,

In general, what goes on the y-axis of a graph?

O the dependent variable

At 10⁻¹⁰ s during the evolution of the universe, quarks formed, which are elementary particles that make up protons and neutrons.

Generally, an atom comprises three (3) distinct subatomic particles and these include the following

Protons can be defined as the positively charged subatomic particles that are found in the nucleus of a chemical element and they have a magnitude of +1. Also, the number of protons in the nucleus of a chemical element always the same as its atomic number.

Quarks can be defined as the elementary particles that make up both protons and neutrons, and they are the basic component of matter. Also, quarks have a charge that's approximately equal to 1.07 × 10⁻¹⁹ Coulomb.

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Complete Question:

At 10⁻¹⁰ s during the evolution of the universe, ________ formed, which are elementary particles that make up protons and neutrons.

Answer:

2 m/s²

Explanation:

To calculate the acceleration of an object, we use the following formula:

[tex]\boxed{a = \frac{v - u}{t}}[/tex],

where:

• a = acceleration

• v = final speed

• u = initial speed, and

• t = time taken

We are told in the question that the final speed of the helicopter is 40 m/s, its initial speed is 30 m/s, and that the time it took to get from 30 m/s to 40 m/s is 5 seconds.

Therefore, using this information, as well as the formula above, we can evaluate the acceleration of the helicopter:

[tex]a = \frac{40 - 30}{5}[/tex]

  [tex]= \frac{10}{5}[/tex]

  [tex]= \bf 2 \: m/s^2[/tex]

So the acceleration of the helicopter is 2 m/s².

The magnitude of the electric field at the given radial distances from the center of the charge distribution is, For the first case electric field=E₁= 1211.37N/C, For the second case electric field =E₂=762.82 N/C, For the third case electric field= E₃= 3276.7 N/C, For the fourth case electric field=E₄=555.04N/C

Electric field is defined in a way that a field is present in a frame. There is two electric source is present that associated with each other and make the field electrified and source of electric. It can be shown in electric per unit area.

The conducting shell carries a total charge of=Q=−11.9 nC=11.9*10⁻⁹C

A sphere of radius=R =0.280m

A uniform charge density of a sphere=ρ₁= 151 nC/m³= 151×10⁻⁹C/m³

A uniform charge density of a spheric shell,

ρ₂=Q/(4/3)π[(4.00R)³−(3.50R)³]

Or,ρ₂=3Q/4πR³[(4.00)³−(3.50)³]

Or,ρ₂=3*11.9*10⁻⁹/4π(0.280)³[(4.00)³−(3.50)³]

Or,ρ₂=6.15*10⁻⁹ C/m³

We know the law of electric field,

E=(1/4πϵ₀)*(q/r²)

(a) r₁=0.76R

The electric field, in this case, can be given as:

E₁=(1/4πϵ₀)*(q₁/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*{(4/3)πr₁³}/r₁²)

Or, E₁=(1/4πϵ₀)*(ρ₁*(4/3)πr₁)

Or, E₁=9*10⁹*( 151×10⁻⁹*(4/3)π*0.76*0.280)

Or, E₁= 1211.37N/C

According to the calculation, The electric field for this case is, E₁= 1211.37N/C

(b) r₂=3.65R

The electric field, in this case, can be given as:

E₂=(1/4πϵ₀)*(q₂/r₂²)

Here, q₂=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₂=88.488*10⁻⁹C

Now, E₂=(1/4πϵ₀)*(q₂/r₂²)

Or, E₂=(1/4πϵ₀)*(88.488*10⁻⁹/(3.65*0.280)²)

Or, E₂=762.82 N/C

According to the calculation, The electric field for this case is, E₂=762.82 N/C

(c) r₃=2.30R

The electric field, in this case, can be given as:

E₃=(1/4πϵ₀)*(q₃/r₃²)

In this case, electric charge enclosed by the Gaussian surface is given by: q₃=151×10⁻⁹C/m³

Now, E₃=(1/4πϵ₀)*(q₃/r₃²)

Or, E₃=(1/4πϵ₀)*(151×10⁻⁹/(2.30*0.280)²)

Or, E₃= 3276.7 N/C

According to the calculation, The electric field for this case is,  E₃= 3276.7 N/C

(d) r₄=4.50R

Here, q₄=Q+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=11.9*10⁻⁹+(4/3)π[(4.00)³−(3.50)³]

Or, q₄=88.488*10⁻⁹C

Now, E₄=(1/4πϵ₀)*(q₄/r₄²)

Or, E₄=(1/4πϵ₀)*(88.488*10⁻⁹/(4.50*0.280)²)

Or, E₄=555.04N/C

According to the calculation, The electric field for this case is, E₄=555.04N/C

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The frequency of a 1.77-Angstrom x-ray photon is 1.694×10^18hz.

AS, we can see, the wavelength given of x ray photon

[tex]\lambda[/tex]=1.77-Angstrom = 1.77×10^-10

we know the relationship betwee frequency and lambda

c=λν

ν=c/[tex]\lambda[/tex]

ν is frequency , [tex]\lambda[/tex] is wavelength, and c is speed of light

c= 3×10^8m/s

now put the value in equation:

ν= 3×10^8m/s÷1.77×10^-10

ν=1.694×10^18hz

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The moment of the force about point A found using the moments formula, [tex]|M| = |F| \cdot \: d \perp[/tex] is 67.695 ft–lb.

The moment of a force is the turning effect of the force about a point.

The moment of the force is given by the formula;

[tex]|M| = |F| \cdot \: d \perp[/tex]

Where;

d = The perpendicular distance from the point to the line of action of the force.

The length of the sides of ∆ABC are;

AB = √(20.5²+4.38²) ≈ 20.9626907

BC = √(17.2²+7.62²) ≈ 18.812347

AC = √((7.62+4.38)²+(20.5-17.2)²) ≈ 12.4454811

The semi–perimeter of triangle ABC = (20.9626907 + 18.812347 + 12.4454811)/2 ≈ 26.1102594

The area, A, of triangle ∆ABC found using Heron's formula is therefore;

A = √((26.1102594×(26.1102594-20.9626907)×(26.1102594-18.812347)×(26.1102594-12.4454811)) ≈ 115.773

The perpendicular distance, d, from point A to BC is therefore;

d = A/(BC)

Which gives;

d = 115.773/18.812347 ≈ 6.15409696

The magnitude of the moment about point A is therefore;

M = 132 lb × 0.51284138 ft. ≈ 67.695 ft.–lb

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The time interval between one frame and the next is 1/60 second and it needs to be slowed down by a factor of 2.5.

The unitary method's formula is to identify the value of a single unit, then multiply that value by the number of units to obtain the required value.

The frame rate of a high-speed video while recording sporting events is 60 frames per second.

Let's say the time interval between one frame and the next is x.

Using the unitary method,

60 frames → 1 sec

1 frame → x second

So, x = 1/ 60 second

Now, in continuous motion, we can see 24 frames per second.

60 frames per second need to be slowed down to 24 frames per second.

Therefore the factor will be:

= ( 60/24 ) = ( 15/6 ) = ( 5/2 ) = 2.5

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Answer:

N1 Sin θ1 = N2 sin θ2        Snell's equation

Sin θ2 = 1 / 1.33 * Sin 40

Sin θ2 = .752 * .643 = .483

θ2 = 28.9 deg

Answer:

2538263

Explanation:

when I divide it this is the answer I got

Answer:

pp

Explanation:

hahahahhahahhahahahahahaahhahaha..  tbh

The resultant displacement is  (- 145 i - 130 j )m and the angle made by the resultant is 46° west of the South, this can be found using the polygon law of vector addition.

Physical quantity that has both magnitude as well as direction a vector is represented by a line ending with an arrow head where the length of the line represents the magnitude of the vector and the direction of the arrowhead represents the direction of the vector.

If two or more vectors are joined head to tail then the polygon law of vector addition states that the resultant of such a vector will be given by the vector addition of all the vectors present in the polygon.

Given:

Magnitude of vector 1 pointing south = 40m

Magnitude of vector 2 pointing south = 230 m

Magnitude of vector 3 pointing south of west = 110m

Magnitude of vector 4 pointing north of west = 180 m

Using the polygon law of vector addition we get,

The resultant displacement = vector 1 + vector 2 + vector 3 + vector 4

The resultant displacement = 40 i - 230 j - 110 × cos 30 i - 110 × sin 30 j- 180 × sin 60 j + 180 × cos 60

The resultant displacement = 40 i - 230 j - 95 i - 55 j + 155 j - 90 i

The resultant displacement = ( - 145 i - 130 j )m

To find the angle of the resultant vector we will use tangent trigonometric ratio.

Tan x = (-145)/(-130)

Tan x = (145)/(130)

x = 46° to west of South

Where,

x is the angle made by resultant vector with the vertical axis.

Therefore, the resultant displacement is  ( - 145 i - 130 j )m and the angle made by the resultant is 46° to the west of the South.

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A line of best fit is a straight line drawn through the most points on a scatter plot, with an equal number of points above and below the line. It is used to investigate the nature of the relationship between two variables. The correct option is d.

A straight line with the best fit is one that minimizes the distance between it and some data.

In a scatter plot of varying data points, the line of best fit is used to express a relationship. It is a result of regression analysis and can be used to forecast indicators and price movements.

It is important to note that your line does not need to pass through any of the points on the plot; it only needs to bisect the area that contains the data points.

Thus, none of the options are correct, the correct one is d.

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The speed of the ball have in falling 3.6 s is 35.5 m/s.

The speed of the ball is calculated using the equation of a body falling under the influence of gravity or velocity of free fall.

The equation of the motion of the body is given as follows:

v = u - gt

where;

u is the initial velocity

g = acceleration due to gravity

t = time

v = final velocity

Assuming u = 0 m/s, g = 9.8 m/s², t = 3.6 s

v = 0 - 9.8 * 3.6

v = 35.5 m/s

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The motion of the person on a velocity time graph would show a flat portion which indicates that there is no change in the speed.

If the person moves at constant velocity, it implies that the velocity is not changing with time. This implies that the person does not change speed and that the acceleration of  the person is zero.

Accordingly, the motion of the person on a velocity time graph would show a flat portion which indicates that there is no change in the speed of the object with time as the person moves.

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A vector is a physical quantity that has both magnitude and direction

A two dimensional vector represented by r = xi + yj has the magnitude r = √(x² + y²) where

Also, a three dimensional vector represented by r = xi + yj + zk has the magnitude r = √(x² + y² + z²) where

Given a vector r = 3i + 4j, we find its magnitude thus r = √(x² + y²) where

So, r = √(x² + y²)

r = √(3² + 4²)

r = √(9 + 16)

r = √25

r = 25 units

Also, given a vector r = 3i + 4j + 5k, we find its magnitude thus r = √(x² + y² + z²) where

So, r = √(x² + y² + z²)

r = √(3² + 4² + 5²)

r = √(9 + 16 + 25)

r = √(25 + 25)

r = √50

r = 5√2 units

So,

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Answer:

As an object moves away from us, the sound or light waves emitted by the object are stretched out, which makes them have a lower pitch and moves them towards the red end of the electromagnetic spectrum, where light has a longer wavelength.

Explanation:

Doppler shift example: Sound waves from a police car siren. The car is driving forwards. The sound waves in front of the car get bunched up and the sound waves behind the car get stretched out.

In the case of light waves, this is called redshift

Answer:

Third law of motion

Explanation:

because his third law states that for every action (force) in nature there is an equal and opposite reaction. so when the wagon is empty you only have to give a less power

please make my answer as brainelist

The length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

Cells are the basic building blocks of all living things, including humans. The human body is composed of trillions of cells with  average cell diameter of 1 x 10⁻⁵ m.

The length of the total cells in the human body when all the cells are stretched out is calculated as follows;

total length of the cells = average diameter of a cell x number of cells

total length of the cells = 1 x 10⁻⁵ m x 7.5 x 10¹³

total length of the cells = 7.5 x 10⁸ m

Thus, the length of the total cells in the human body when all the cells are stretched out is 7.5 x 10⁸ m.

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