A bag contains 5 red marbles, 8 blue marbles and 4 green marbles. If three marbles are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that all three marbles drawn will be red?

Answers

Answer 1

Without replacement, the probability that all three marbles drawn will be red is 0.01.

What is the probability?

Probabiliy is used to determine the likelihood of an event happening. The probability that the event would occur lies between 0 and 1.

Probability of drawing three red marbles = (number of red marbles / total number of marbles) x (number of red marbles / total number of marbles - 1) x (number of red marbles / total number of marbles - 1)

5/17 x 4/16 x 3/15 = 0.01

Answer 2

The probability, to the nearest 10th of a percent, that all three marbles drawn will be red; 1.5%

How to calculate probability?

We are given;

Number of red marbles = 5

Number of blue marbles = 8

Number of Green marbles = 4

Total number of marbles = 5 + 8 + 4

Total number of marbles = 17

Probability of first being red = 5/17

Probability of second being red = 4/16

Probability of third being red = 3/15

Thus;

P(all three marbles drawn are red) = (5/17) * (4/16) * (3/15)

P(all three marbles drawn are red) = 0.0147

Approximating to nearest tenth of a percent = 0.015 = 1.5%

Read more about Probability at; https://brainly.com/question/251701

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Answer:

she started with 32 apples and ended with 28

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Step-by-step explanation:

The cylinder shown here has a height of 7 centimeters and a radius of 4 centimeters.
Part A. What is the area of the base of the cylinder? Express your answer in terms of π. options are: 15 pi cm, 14 pi cm, 16 pi cm, 17 pi cm.

Part B: How many cubic centimeters of fluid can fill this cylinder? Express your answer in terms of π. options are: 112 pi cm, 110 pi cm, 113 pi cm, 107 pi cm.

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Answers

Answer:

A: 16[tex]\pi[/tex][tex]cm^{2}[/tex]

B: 112[tex]\pi[/tex][tex]cm^{3}[/tex]

C: 351.68[tex]cm^{2}[/tex]

Step-by-step explanation:

The cubic inches that can fill the cylinder is [tex]112\pi[/tex] and the decimal approximation 351.68 cm^3

The given parameters are:

Radius (r) = 4 cm

Height (h) = 7 cm

The area of the base

The area of the base is:

[tex]A = \pi r^2[/tex]

So, we have:

[tex]A = \pi *4^2[/tex]

[tex]A = 16\pi[/tex]

Hence, the area of the base is [tex]16\pi[/tex]

The cubic inches that can fill the cylinder

This is the volume of the cylinder.

So, we have:

[tex]V = \pi r^2h[/tex]

Substitute known values

[tex]V = \pi * 4^2 * 7[/tex]

[tex]V = 112\pi[/tex]

Hence, the cubic inches that can fill the cylinder is [tex]112\pi[/tex]

The decimal approximation

We have:

[tex]V = 112\pi[/tex]

Expand

[tex]V = 112 * 3.14[/tex]

Evaluate the product

[tex]V = 351.68[/tex]

Hence, the cubic inches that can fill the cylinder is 351.68 cm^3

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