A bakery sold 27 mocha cupcakes in a day, which was 9% of the total number of
cupcakes sold that day. How many total cupcakes did the bakery sell that day?

Answers

Answer 1

Answer:

300 cupcakes

Step-by-step explanation:

[tex]27 = .09c[/tex]

[tex]c = \frac{27}{.09} = \frac{2700}{9} = 300[/tex]

Answer 2

In total, the bakery sold 300 cupcakes on a certain day.

What is the percentage?

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, A bakery sold 27 mocha cupcakes in a day, which was 9% of the total number of cupcakes sold that day.

let, 'x' be the total number of cupcakes sold that day.

Therefore, 9% of 'x' is 27 which is,

(9/100)×x = 27.

0.09x = 27.

x = 27/0.09.

x = 300.

So, The number of cupcakes sold that day is 300.

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Related Questions

In a study of cell phone usage and brain hemispheric​ dominance, an Internet survey was​ e-mailed to 6965 subjects randomly selected from an online group involved with ears. There were 1302 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than​ 20%. Use the​ P-value method and use the normal distribution as an approximation to the binomial distribution

Answers

The hypothesis test shows that we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

What is the claim that the return rate is less than 20% by using a statistical hypothesis method?

The claim that the return rate is less than 20% is p < 0.2. From the given information, we can compute our null hypothesis and alternative hypothesis as:

[tex]\mathbf{H_o :p =0.2}[/tex]

[tex]\mathbf{H_i:p < 0.2}[/tex]

Given that:
Sample size (n) = 6965

Sample proportion [tex]\mathbf{\hat p = \dfrac{x}{n} = \dfrac{1302}{6965} \sim0.1869}[/tex]

The test statistics for this data can be computed as:

[tex]\mathbf{z = \dfrac{\hat p - p}{\sqrt{\dfrac{p(1-p)}{n}}}}[/tex]

[tex]\mathbf{z = \dfrac{0.1869 -0.2}{\sqrt{\dfrac{0.2(1-0.2)}{6965}}}}[/tex]

[tex]\mathbf{z = \dfrac{-0.0131}{0.0047929}}[/tex]

z = -2.73

From the hypothesis testing, since the p < alternative hypothesis, then our test is a left-tailed test(one-tailed.

Hence, the p-value for the test statistics can be computed as:

P-value = P(Z ≤ z)

P-value = P(Z ≤ - 2.73)

By using the Excel function =NORMDIST (-2.73)

P-value = 0.00317

P-value ≅ 0.003

Therefore, we can conclude that since P-value is less than the significance level at ∝ = 0.01, we reject the null hypothesis and there is sufficient evidence to support the claim that the return rate is less than 20%

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Find the slope of the line passing through the points (3,-9) and (2, -3).

Answers

Answer:

The slope of the line passing through is -6.

Need help with this! Brainliest to who answers.

Answers

Answer: K

Step-by-step explanation:

The subtraction with the negatives can cancel out, resulting in a possible positive answer.

Answer:

k

Step-by-step explanation:

K      you CAN get a positive number....

        example  :

     -3   - (-5)   = -3 + 5 = + 2

1/5 (10x+30)-14= - 1/3 (6x-18)

Answers

Answer:

x = 7/2

Step-by-step explanation:

1/5 (10x+30)-14= - 1/3 (6x-18)

10x + 30/5 - 14 = -6x + 18/3

(2*5)x+2*3*5/5-14 = -(2*3)x-2*3^2/3

x = 7/2

S
Which triangle is similar to ABC if sin(A) = cos(A)=√15, and tan(A)=√1
R
5
12
13
T
D
3
12
f
3√15
O
2
K
√15
Σ.
M
O
3
L√6 N
X
6√15
N
O
24
6

Answers

Answer: Option 4

Step-by-step explanation:

Similar triangles have congruent angles, so this means that the sines, cosines, and tangents should be the same.

Thus, the side lengths of the triangle we want to find should be multiples of  [tex]1, \sqrt{15}, 4[/tex].

This eliminates options (1) and (3).

Between options 2 and 4, we know that the Pythagorean theorem is not satisfied by option (2), thus we should eliminate it.

This leaves us with option (4)

Mr. Harry had 4 daughters, each daughter had a brother. How many Children does Mr. Harry have? ​

Answers

Answer:

Mr. Harry has 5 children.... I know what you were going for...

Help me and i'll help you earn more points if the question is right

Answers

-21x^3 - 8x^3 = -29x^3
-7/4x^(1/2) - 0 = -7/4x^(1/2)
-6x^(1/4)
-12x^(-1/2)
12x^(-1/4)
14x^4

Therefore, the correct option is the 2nd one.

A bag contains Red, Green or Yellow balls. A ball is taken at random from the bag. The probability that it is Red is 0.4 and the probability that it is Green is 0.375.What is the possible number of balls in the bag?

Answers

Answer:

1000 balls

(there are infinitely many solutions to this question; you can scale up 1000, use a different total, etc.)

Step-by-step explanation:

there are, of course, multiple possible numbers,

but the easiest way is to go with 1000, because we can say 375 / 1000 and 400 / 1000

(0.4 + 0.275 + 0.225 = 1)

400 out of 1000 balls are red (400/1000 = 4/10 = 0.4)

375 out of 1000 balls are green (375/1000 = 3.75/10 = 0.375)

225 out of 1000 balls are yellow (225/1000 = 2.25/10 = 0.225)

the question never gave detail as to if the answer should be the lowest number of possible balls, so this value is possible.

So, a possible number of balls in this bag is 1000.

Which table correctly shows all the sample spaces for tossing a coin to get heads and rolling a number on a six-sided number cube?

Answers

Using it's concept, the sample space for the experiment is given as follows:

{(H,1), (H,2), (H,3), (H,4), (H,5), (H,6), (T,1), (T,2), (T,3), (T,4), (T,5), (T,6)}

What is the sample space of an experiment?

The sample space is the set that contains all possible outcomes for an experiment.

In this problem:

For the coin, there are 2 outcomes, H for heads and T for tails.For the number, there are 6 outcomes, which are the 6 numbers.

Hence the sample space is given as follows:
{(H,1), (H,2), (H,3), (H,4), (H,5), (H,6), (T,1), (T,2), (T,3), (T,4), (T,5), (T,6)}

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Algebra 2 point slope form help

Answers

The slope of the line is

[tex]\frac{-1-4}{-1-0}=5[/tex]

So, the equation of the line in point-slope form is [tex]\boxed{y+1=5(x+1)}[/tex]

To find the possible roots of the polynomial 4x3 + x4 – 7x2 – 8x - 8
divide factors of ± __ by factors of ± __ .

Answers

The complete statement is divide factors of ± 8 by factors of ± 1

How to complete the statement?

The polynomial is given as:

4x^3 + x^4 - 7x^2 - 8x - 8

Rewrite properly as:

x^4 + 4x^3 - 7x^2 - 8x - 8

The first term in the above equation is 1 i.e. 1x^4, while the last term is 8

To determine the possible rational roots, we divide the factors of the last term i.e. 8 by the factors of the first term i.e. 1

Hence, the complete statement is divide factors of ± 8 by factors of ± 1

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Given the following equation of a circle in general form, find the equation in standard form by completing the square.
4x² + 8x + 4y² + 32y +52 = 0
Provide your answer below:

Answers

The standard form of the circle equation 4x² + 8x + 4y² + 32y +52 = 0 is (x + 1)² + (y + 4)² = 2²

What is a circle?

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

We have an equation that represents the circle:

4x² + 8x + 4y² + 32y +52 = 0

Divide by 4 on both the sides:

x² + 2x + y² + 8y + 13 = 0

x² + 2x + 1 - 1 + y² + 8y + 4² - 4² + 13 = 0

x² + 2x + 1 + y² + 8y + 4² - 1 - 16 + 13

(x + 1)² + (y + 4)² = 4

(x + 1)² + (y + 4)² = 2²

Thus, the standard form of the circle equation 4x² + 8x + 4y² + 32y +52 = 0 is (x + 1)² + (y + 4)² = 2²

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a) Students returning to a secondary school have to pass through a check point at the rate of 50 per though. The average time for checking is 35 seconds. The arrival rate and service rate follow a Poisson distribution. There is a delay and the principal is willing to include another check point to reduce the average time of checking to 28 seconds if the idle time is less than 10% and the average queue length is more than 10 students, check whether the introduction of an extra check point is justifiable

Answers

Answer:

175

Step-by-step explanation:

Average queue length = (arrival rate * service time) / (1 - arrival rate * service time)

For the given problem, the average queue length is:

Average queue length = (50 * 35) / (1 - 50 * 35)

= 175

Step 2 of 2 : Suppose a sample of 782 suspected criminals is drawn. Of these people, 548 were not captured. Using the data, construct the 98% confidence interval for the population proportion of people who are captured after appearing on the 10 Most Wanted list.

Answers

98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list

(0.6625, 0.7388).

What is confidence interval?

A confidence interval is the mean of your estimate plus and minus the variation in that estimate.

Given sample, n= 782

As, 548 were not captured.

x= 548

So, p= 548/ 782

     p = 0.7007

q= 1- 0.7007 = 0.2993

98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list

Now,

α = 1 - 0.98 = 0.02

α/2 = 0.02/2 = 0.01

For confidence level of 98% , z is 2.33

Now,

(0.70007 - 2.33√ (0.7007(0.2993))/782 , 0.70007 + 2.33 √(0.7007(0.2993))/782

= (0.6625, 0.7388)

Hence, 98% of confidence intervals for the Population proportion of people who captured after appearing on the 10 most wanted list

(0.6625, 0.7388).

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a.- Representa el cálculo del porcentaje de cada par de artículos y marca el que es más conveniente comprar.

1 el par de zapatos cuesta $90.Por la compra de dos pares , tienes el 25% del descuento total
2 el par de zapatos cuesta $90.El segundo par de zapatos esta con el 40% de descuento

Answers

El costo en la opción uno es menor que el de la opción dos, asi que la primera es la más conveniente.

¿Cual opción es más conveniente?

En la primera opción, el par de zapatos cuesta $90, y el segundo par tiene un descuento del 25%.

Entonces el costo por 2 pares es:

C = ($90 + $90)*(1 - 25%/100%)

Donde le aplicamos un descuento del 25% al total del costo de los dos zapatos, resolviendo esto obtenemos:

C = ($180)*(0.75) = $135.

En la segunda opcion tenemos que los pares cuestan $90, pero esta vez le aplicamos un descuento del 40% al segundo par.

C = $90 + $90*(1 - 40%/100%) =

C = $90 + $90*(0.6) = $144

Así, vemos que en la primera opción el costo es menor, entonces esa es la mejor opción.

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Can anyone help me solve this? Please and thank you!

Answers

It's the sum of a geometric sequence.

Let's rewrite it a bit:

[tex]\displaystyle\\\sum_{n=1}^{10}8\left(\dfrac{1}{4}\right)^{n-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot \left(\dfrac{1}{4}\right)^{-1}=8\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n\cdot 4=32\sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n[/tex]

And now let's calculate this sum [tex]\displaystyle \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n[/tex]:

[tex]S_n=\dfrac{a(1-r^n)}{1-r}\\\\a=\dfrac{1}{4}\\n=10\\r=\dfrac{1}{4}\\\\S_{10}=\dfrac{\dfrac{1}{4}\cdot\left(1-\left(\dfrac{1}{4}\right)^{10}\right)}{1-\dfrac{1}{4}}=\dfrac{\dfrac{1}{4}\cdot\left(1-\dfrac{1}{1048576}\right)}{\dfrac{3}{4}}=\dfrac{\dfrac{1048575}{1048576}}{3}=\dfrac{1048575}{3145728}=\\=\dfrac{349525}{1048576}[/tex]

Now let's calculate the initial sum:

[tex]\displaystyle 32\cdot \sum_{n=1}^{10}\left(\dfrac{1}{4}\right)^n=32\cdot \dfrac{349525}{1048576}=\dfrac{349525}{32768}\approx10.67[/tex]

50 people sponsor Paula and she raises a total of $180.65 for charity. 28 people sponsor Kate and she raises a total of $135.60 for charity. 45 people sponsor Sam and he raises a total of $169.25 for charity.

How much money is raised altogether by three of them?
$_____________

Answers

Answer:

485.5

Step-by-step explanation:

180.65+135.60+169.25

Two buses leave a station at the same time and travel in opposite directions. One bus travels12m/hrslower than the other. If the two buses are 765 miles apart after 6 hours, what is the rate of each bus?

Answers

distance = speed * time

the first bus speed = x

second bus = x - 12

the sum of distance = 765 miles

first distance = 6x

second distance = 6 (x -12)

6x + 6(x-12) = 765

x + x -12 = 127.5

2x = 139.5

x = 69.75 mi/h which is the faster bus

the second bus speed = 57.75 mi/h

A local dry cleaner interviewed 17 candidates for the positions of the cashier, washer, salesperson, and delivery driver. How many ways can they fill the 4 positions?


HELP PLSPLSPLS

Answers

Using the permutation formula, it is found that there are 57,120 ways to fill the 4 positions.

There are different roles, hence the order is important, which means that the permutation formula is used.

What is the permutation formula?

The number of possible permutations of x elements from a set of n elements is given by:

[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]

In this problem, 4 roles are chosen from a set of 17, hence the number of ways is given by:

[tex]P_{17,4} = \frac{17!}{13!} = 57120[/tex].

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Math Problem...can you help? (Functions)

Answers

Step-by-step explanation:

[tex]h(x) = \frac{3}{x}\\h(h(x)) = \frac{3}{\frac{3}{x}}\\\\h(h(x)) = \frac{3}{1} * \frac{x}{3}\\h(h(x)) = \frac{3x}{3}\\h(h(x)) = x\\\\\\f(f(x)) = (x^2-3)^2-3\\f(f(x)) = x^4+2(x^2)(-3)+(-3)^2-3\\f(f(x)) =x^4-6x^2+9-3\\f(f(x)) = x^4-6x^2+6\\[/tex]

Solve x2 − 3x = −8. (2 points)


x equals quantity of 3 plus or minus I square root of 29 all over 2
x equals quantity of 3 plus or minus I square root of 23 all over 2
x equals quantity of negative 3 plus or minus I square root of 29 all over 2
x equals quantity of negative 3 plus or minus I square root of 23 all over 2


x equals negative 2 plus or minus 4 I square root of 2
x equals negative 2 plus or minus 2 I square root of 2
x equals negative 1 plus or minus 4 I square root of 2
x equals negative 1 plus or minus 2 I square root of 2

Answers

The value of x equals quantity of (3 ± √23)/2.

What is Quadratic Equations?

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax² + bx + c = 0, where a and b are the coefficients, x is the variable, and c is the constant term.

Here, given equation;

  x² - 3x = -8

    x² - 3x + 8 = 0

 x² - 2 X 3/2 x + 8 = 0

 x² - 2.3/2 x + (3/2)² - (3/2)² + 8 = 0

 (x - 3/2)² - 9/4 + 8 = 0

 (x - 3/2)² + 23/4 = 0

  (x - 1.5)² = -5.75

  x - 1.5 = ±√(-5.75)

 x = 1.5 ± i√(5.75)

  x = (3 ± i√21)/2

Thus, x equals quantity of 3 plus or minus I square root of 23 all over 2.

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Of the three functions in the tables, which represent linear relationships?

Answers

Answer:

D. f and h

Step-by-step explanation:

The function f is a liner function because for every increase in x, there is a proportional increase in f(x). This can be seen when the x value goes from 2 to 4, so a 2 unit increase, the f(x) value increases by 3. Since this is true for every interval of 2 in f(x) -- increase x by 2 results in an increase in 3 of f(x) -- then f(x) is a linear function.

The same principle can be applied to h(x), with each 4 unit increase in x, the h(x) value increase by 36.

The function g(x) is not a linear function because for each unit increase of x, there is not a proportional increase (or decrease) in g(x). As seen in the table, g(2)-g(1)= 8-4= 4. For g(x) to be a linear function, every other one unit increase in x should result in a 4 unit increase in g(x0. But this does not occur. g(3)-g(2)= 16-8= 8 , g(4)-g(3)= 32-16= 16, 8 and 16 are not equal to four so g(x) cannot be a linear function.

A florist is making blue and white flower arrangements for the arrangements he places a red ribbon on every third Arrangement and a blue ribbon on every fifth Arrangement which Arrangement will be the first to have a red and blue ribbon

Answers

The Arrangement that will be the first to have a red and blue ribbon is the 15th arrangement.

What is LCM?

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

Given the florist places a red ribbon on every third Arrangement and a blue ribbon on every fifth Arrangement. Therefore, to find the arrangement that will have both a red and a blue ribbon, you need to take the LCM of 3 and 5.

Since the LCM is 15, therefore, the Arrangement that will be the first to have a red and blue ribbon is the 15th arrangement.

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In the standard Normal distribution, 43% of observations lie below which z-score?

Find the z-table here.

–1.08
–0.18
0.18
1.08

Picture posted below

Answers

The answer is -0.18

when you convert 43% to decimal, it is 0.43

And the z-score of 0.43 is closest to -0.18

Hope it helps!

What is the domain of f(x) = 5x – 7?

{x | x > –7}
{x | x < –7}
{x | x > 0}
{x | x is a real number}

Answers

Answer:

all real number {x | x is a real number}

A group of 9 people is going to be formed into committees of 4, 3, and 2 people. How many committees can be formed if no person can serve on more than one committee?

Answers

Answer:

1,260

Step-by-step explanation:

[tex]\implies C(9,4)*C(5,3)*C(2,2)[/tex]

[tex]\implies 9!/4!(9-4)!*5!/3!(5-3)!*2!/2!(2-2)![/tex]

[tex]\implies 9!/4!5!*5/3!2! *2!0![/tex]

[tex]\implies (9 * 8 * 7 * 6 / 4 * 3 * 2 * 1) * (5 * 4 / 2 * 1) * 1[/tex]

[tex]\implies 1260[/tex]

Therefore, 1,260 committees can be formed.

Inga is solving 2x2 + 12x – 3 = 0. Which steps could she use to solve the quadratic equation? Select three options.

2(x2 + 6x + 9) = 3 + 18
2(x2 + 6x) = –3
2(x2 + 6x) = 3
x + 3 = Plus or minus StartRoot StartFraction 21 Over 2 EndFraction EndRoot
2(x2 + 6x + 9) = –3 + 9

Answers

The correct answers are option 1, Option 3 and option 4 which are:-

2(x² + 6x + 9) = 3 + 18

2(x² + 6x) = 3

x+3 = ±√21/√2

What is a quadratic equation?

The polynomial having a degree of two or the maximum power of the variable in a polynomial will be 2 is defined as the quadratic equation and it will cut two intercepts on the graph at the x-axis.

We will check all three options one by one:-

2(x² + 6x + 9) = 3 + 18

2x² +  12x + 18 = 3 + 18

2x² + 12x -3 = 0

We are getting the original equation so it is correct.

2(x² + 6x) = 3

2x² + 12x = 3

2x² + 12x - 3 = 0

This is also right.

x+3 = ±√21/√2

Squaring on both the sides:-

( x + 3 )² = 21 / 2

x² + 6x + 9 = 21 / 2

2x² + 12x + 18 = 21

2x² + 12x = 21 - 18

2x² + 12x -3 = 0

This is also right

Therefore the correct answers are option 1, Option 3 and option 4 which are:-

2(x² + 6x + 9) = 3 + 18

2(x² + 6x) = 3

x+3 = ±√21/√2

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Answer:

A, C, D

A: 2(x2 + 6x + 9) = 3 + 18

C: 2(x2 + 6x) = 3

D: x + 3 = Plus or minus StartRoot StartFraction 21 Over 2 EndFraction EndRoot

Step-by-step explanation:

Got 100% on quiz

A study of the amount of time it takes a mechanic to rebuild the transmission for a 1992 Chevrolet Cavalier shows that the mean is 8.4 hours and the standard deviation is 1.77 hours. Assume that a random sample of 40 mechanics is selected and the mean rebuild time of the sample is computed. Assuming the rebuilding times are normally distributed, what percentage of sample means is greater than 8.8 hours? Express your answer as a percent rounded to hundredths of a percent.

Answers

Using the normal distribution, it is found that 7.64% of of sample means are greater than 8.8 hours.

Normal Probability Distribution

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The z-score measures how many standard deviations the measure is above or below the mean. Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

The parameters are given as follows:

[tex]\mu = 8.4, \sigma = 1.77, n = 40, s = \frac{1.77}{\sqrt{40}} = 0.2799[/tex]

The proportion of sample means greater than 8.8 hours is one subtracted by the p-value of Z when X = 8.8, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{8.8 - 8.4}{0.2799}[/tex]

Z = 1.43

Z = 1.43 has a p-value of 0.9236.

1 - 0.9236 = 0.0764.

7.64% of of sample means are greater than 8.8 hours.

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3(x-5)² +14(x-5)-24

Answers

Answer:

3x^{2} -16x-19

Step-by-step explanation:

If we are going to be simplying this problem, then we need to take it step by step.

Start off by using the distributive property, and then combining like terms. Keep in mind the square, and make sure that gets sorted out correctly.

Answer:

(3x - 19) • (x + 1)

Step-by-step explanation:

STEP

1

:

Equation at the end of step 1

((3•((x-5)2))+14•(x-5))-24

STEP

2

:

Equation at the end of step 2

(3 • (x - 5)2 + 14 • (x - 5)) - 24

STEP

3

:

Trying to factor by splitting the middle term

Factoring 3x2-16x-19

The first term is, 3x2 its coefficient is 3 .

The middle term is, -16x its coefficient is -16 .

The last term, "the constant", is -19

Step-1 : Multiply the coefficient of the first term by the constant 3 • -19 = -57

Step-2 : Find two factors of -57 whose sum equals the coefficient of the middle term, which is -16 .

-57 + 1 = -56

-19 + 3 = -16 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -19 and 3

3x2 - 19x + 3x - 19

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (3x-19)

Add up the last 2 terms, pulling out common factors :

1 • (3x-19)

Step-5 : Add up the four terms of step 4 :

(x+1) • (3x-19)

Which is the desired factorization

Mountain Climbing Gym has a gym registration fee of $30 and then charges $55 per month for all access climbing.

Susie wanted to model what she has spent in total on the climbing gym at any given month in the future.

Fill in the blanks for the equation if C = total Cost and m = number of months.

Answers

Answer:

C=55m + 30

Step-by-step explanation:

You would multiply 55 by the number of months so you'd get 55m, and since 30 is a one time fee you would just add 30 to your monthly payment.

Other Questions
What distinguishes folk art from outsider art? Preparation of Adjusting Entries Bartow Photographic Services takes wedding and graduation photographs. At December 31, the end of Bartow's accounting period, the following information is available: All wedding photographs are paid for in advance, and all cash collected for them is credited to Unearned Service Revenue. Except for a year end adjusting entry, no other entries are made for service revenue from wedding photographs. During the year, Bartow received $42,600 for wedding photographs. At year end, $37,480 of services had been performed. The beginning-of-the-year balance of Unearned Service Revenue was zero. During December, Bartow photographed 228 members of the next year's graduating class of Shaw High School. The school has asked Bartow to print one copy of a photograph of each student for the school files. Bartow delivers these photographs on December 28 and will bill the school $5.00 per student in January of next year. 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